Help picture below problem 11

Answer:

The total compound interest is $1,047,130.76.

Step-by-step explanation:

The amount of the money received after 1 year is $31384283.7672.

Compound interest is the interest on savings calculated on both the initial principal and the accumulated interest from previous periods.

The formula used to find the compound interest = [tex]A=P(1+\frac{r}{100})^{nt}[/tex].

Given that, principal = $10,000,000, rate of interest =10% and time period = 1 year

Here, A=10,000,000(1+10/100)¹²

= 10,000,000(1.1)¹²

= $31384283.7672

Therefore, the amount of the money received after 1 year is $31384283.7672.

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Answer:

C

Step-by-step explanation:Only one that makes sence just look at the graph

Answer:

C

Step-by-step explanation:

Answer:

Step-by-step explanation:

Final Answer: 19.5%

The total percentage 19.5% increase in the investor's stock account

A ratio or value that may be stated as a fraction of 100 is called a percentage. And it is represented by the symbol '%'.

Given:

An investor has an account with stock from two different companies. Last year, his stock in Company A was worth $5900 and his stock in Company B was worth $1850.

The total worth is $5900 + $1850 = $7750

The stock in Company A has increased 20% since last year.

So,

20% of 5900,

= 20 x 5900 /100

= $1180

And the stock in Company B has increased 18%.

So,

18% of 1850,

= 18 x 1850/100

= $333

The total increased amount,

= $333 + $1180

= $1513

The increased percentage,

1513 = n x 7750/100

n = 1513 x 100/7750

n = 19.522

n = 19.5% to the nearest tenth.

Therefore, 19.5% is the required percentage.

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Using the normal distribution and the central limit theorem, we have that:

a) The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

b) There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

c) There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem:

Item a:

The mean and the standard error are given by:

[tex]\mu = p = 0.22[/tex]

[tex]s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.22(0.78)}{150}} = 0.0338[/tex]

The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

Item b:

The probability is one subtracted by the p-value of Z when X = 0.25, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.25 - 0.22}{0.0338}[/tex]

Z = 0.89

Z = 0.89 has a p-value of 0.8133.

1 - 0.8133 = 0.1867.

There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

Item c:

The probability is the p-value of Z when X = 0.2 subtracted by the p-value of Z when X = 0.15, hence:

X = 0.2:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.2 - 0.22}{0.0338}[/tex]

Z = -0.59

Z = -0.59 has a p-value of 0.2776.

X = 0.15:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.15 - 0.22}{0.0338}[/tex]

Z = -2.07

Z = -2.07 has a p-value of 0.0192.

0.2776 - 0.0192 = 0.2584.

There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

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The total cost of producing Q units of a given product is given by TC = 500+ 4Q2-12Q. Compute Marginal cost and average cost

Step-by-step explanation:

Answer:

The elapsed time is 2 hours and 5 minutes. Example 4. The movie started at 7:30 pm and ended at 10:20 pm. 

Step-by-step explanation:

Elapsed time is the amount of time that has passed between two events. You can calculate the elapsed time by figuring out the difference between the start and stop time.Here is an elapsed time problem.Soccer practice begins at 3:15 p.m. and ends at 4:45 p.m. Determine how long soccer practice lasts.To solve this problem, set up a subtraction problem that could be used to find the number of hours and minutes that pass between those two times.Subtract the starting time from the stopping time. Remember that both times represent the number of hours and minutes past noon. 

5 : 40 PM

Explanation:

   11 : 05 P.M

(-)  5 : 25

--------------

5 : 40 PM

Answer:

B

Step-by-step explanation:

-6x + 6 = 2x - 9

-6x + 15 = 2x

15 = 8x

x = 15/8

Using proportions, we have that:

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

The scale is of 1 inch = 8 feet. What is the height for 2.5 inches? The rule of three is given by:

1 inch - 8 feet.

2.5 inches - x feet

Applying cross multiplication, the height in feet of the final building is given by:

x = 8 x 2.5 = 20 feet.

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The height of the building is calculated by representing 1 inch as 8 feet. The final building has a height of 20 feet.

Scaling is the increase or decrease in the height of an object by a scale factor k.

Given that the scale used is:

1 inch = 8 feet. Hence:

Since the height of the building is 2.5 in, hence:

Height of the final building = 2.5 in * 8 ft per 1 in = 20 feet

The height of the final building is 20 feet.

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19.99 + 15= 34.99

40-34.99 = 12.51

Jenny received $5.01 change.

Answer:

tkm

Step-by-step explanation:

First T the middle k and at last m

The probability that Shayla will select two red marbles from the bag is 1/16.

Probability determines the odds that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

The probability that Shayla will select two red marbles  = (number of red marbles / total number of marbles) x (number of red marbles / total number of marbles)

5/20 x 5/20 = 1/16

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Answer:

387-141=246

Step-by-step explanation:

    387

   - 141

-------------

     246

Answer:

144

Step-by-step explanation:

[tex]x^2+24x +144\\\\=x^2 + 2\cdot 12x +12^2\\\\=(x+12)^2[/tex]

Answer:

[tex]y = \dfrac{3}{2} x + 9[/tex]

Step-by-step explanation:

We would like to write the given equation in slope intercept form of the line .

[tex]\longrightarrow 6x - 4y = -36 [/tex]

The slope intercept form of the line is [tex] y = mx + c [/tex] , where

we can rewrite the given equation as ,

[tex]\longrightarrow 6x - 4y = -36 \\ [/tex]

[tex]\longrightarrow -4y = -36 -6x \\ [/tex]

[tex]\longrightarrow -4y = -6( x + 6)\\[/tex]

[tex]\longrightarrow y =\dfrac{-6}{-4}(x + 6)\\[/tex]

[tex]\longrightarrow y = \dfrac{3}{2}(x+6)\\ [/tex]

[tex]\longrightarrow y = \dfrac{3}{2}x +\dfrac{3}{2}\times 6\\[/tex]

[tex]\longrightarrow \underline{\underline{\pmb{ y =\dfrac{3}{2}x +9}}}{}[/tex]

This is the required equation of line in slope intercept form , with ;

Answer:

Refer to the attachment

Answer: -43010000.

Step-by-step explanation: 3.99 million is 3,990,000. From there, you subtract 47,000,000 from 3,990,000. The answer is -43010000.

Have a great day! :)

Answer:

3x>18

Step-by-step explanation:

Three times the number x will be called 3x. If an expression is more or greater than a number, we use the greater symbol: >

So, we can write,

3x>18

Answer:

-1/2 or -5/2

Step-by-step explanation:

| | means the absolute value (distance from 0), so there is going to be a positive case and a negative case (distance from the negatives and distance from the positives).

POSITIVE CASE

[tex]2x+3=2\\2x=-1\\x=-\frac{1}{2}[/tex]

NEGATIVE CASE

[tex]-(2x+3)=2\\-2x-3=2\\-2x=5\\x=-\frac{5}{2}[/tex]

So, your answer would be -1/2 or -5/2.

Step-by-step explanation:

after 4x^2+12x+5

do sum and product but I solved it directly through calculator

hope it helps

Answer:

-9

Step-by-step explanation:

225 ÷ -25 = -9

Answer: (-6x - 5) • (2x + 3)

Step-by-step explanation:

((0 -  (22•3x2)) -  28x) -  15

Pull out like factors :

-12x2 - 28x - 15  =   -1 • (12x2 + 28x + 15)

Trying to factor by splitting the middle term

3.2     Factoring  12x2 + 28x + 15

The first term is,  12x2  its coefficient is  12 .

The middle term is,  +28x  its coefficient is  28 .

The last term, "the constant", is  +15

Step-1 : Multiply the coefficient of the first term by the constant   12 • 15 = 180

Step-2 : Find two factors of  180  whose sum equals the coefficient of the middle term, which is   28 .

     -180    +    -1    =    -181

     -90    +    -2    =    -92

     -60    +    -3    =    -63

     -45    +    -4    =    -49

     -36    +    -5    =    -41

     -30    +    -6    =    -36

     -20    +    -9    =    -29

     -18    +    -10    =    -28

     -15    +    -12    =    -27

     -12    +    -15    =    -27

     -10    +    -18    =    -28

     -9    +    -20    =    -29

     -6    +    -30    =    -36

     -5    +    -36    =    -41

     -4    +    -45    =    -49

     -3    +    -60    =    -63

     -2    +    -90    =    -92

     -1    +    -180    =    -181

     1    +    180    =    181

     2    +    90    =    92

     3    +    60    =    63

     4    +    45    =    49

     5    +    36    =    41

     6    +    30    =    36

     9    +    20    =    29

     10    +    18    =    28    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  10  and  18

                    12x2 + 10x + 18x + 15

Step-4 : Add up the first 2 terms, pulling out like factors :

                   2x • (6x+5)

             Add up the last 2 terms, pulling out common factors :

                   3 • (6x+5)

Step-5 : Add up the four terms of step 4 :

                   (2x+3)  •  (6x+5)

            Which is the desired factorization

Answer: (-6x - 5) • (2x + 3)

Answer:

Given:

[tex] \\ {\tt{A = \left [ \: \begin{array}{ c c c} \: \: \: \: 2 & -3 & - 5 \\ - 1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1& - 3 & - 4\end{array} \: \: \: \right] \: and \: B = \left[\begin{array}{c c c} \: \: \: \: 2 & - 2 & - 4 \\ - 1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & - 2 & - 3\end{array} \right]}}[/tex]

Matrix A is of order 3 × 3 and Matrix B is of order 3 × 3

To Show:

Formula Used:

[tex]\\ { \rm{ \left[ \begin{array}{c c c} a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33}\end{array} \right] \times \left[ \begin{array}{c c c} b_{11} & b_{12} & b_{13} \\ b_{21} & b_{22} & b_{23} \\ b_{31} & b_{32} & b_{33} \end{array} \right] = \: \left[ \begin{array}{c c c} \: \: a_{11}b_{11} + a_{12}b_{21} + a_{13}b_{31} & a_{11}b_{12} + a_{12}b_{22} + a_{13}b_{32} & a_{11}b_{13} + a_{12}b_{23} + a_{13}b_{33} \\ \: \: a_{21}b_{11} + a_{22}b_{21} + a_{23}b_{31} & a_{21}b_{12} + a_{22}b_{22} + a_{23}b_{32}&a_{21}b_{13} + a_{22}b_{23} + a_{23}b_{33} \\ \: \: a_{31}b_{11} + a_{32}b_{21} + a_{33}b_{31}&a_{31}b_{12} + a_{32}b_{22} + a_{33}b_{32} & a_{31}b_{13} + a_{32}b_{23} + a_{33}b_{33}\end{array} \right]}}[/tex]

If A is a matrix of order a×b and B is a matrix of order c×d , then matrix AB exits and is of order a×d , if and only if b = c.

[tex] \: \: [/tex]

If A is a matrix of order a×b and B is a matrix of order c×d , then matrix BA exits and is of order c×b , if and only if d = a.

[tex] \: \: [/tex]

For Matrix AB, a = 3, b = c = 3, d = 3 , thus Matrix AB is of order 3×3

[tex]\\ { \rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right] \times \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] = \left[\begin{array}{c c c} \: \: \: \: 2(2)-3(-1)-5(1) & \: \: \: \: 2(-2)-3(3)-5(-2) & \: \: \: \: 2(-4)-3(4)-5(-3) \\ -1(2)+4(-1)+5(1) & -1(-2)+4(3)+5(-2) & -1(-4)+4(4)+5(-3)\\ \: \: \: \: 1(2)-3(-1)-4(1) & \: \: \: \: 1(-2)-3(3)-4(-2) & \: \: \: \: 1(-4)-3(4)-4(-3) \end{array} \right]}}[/tex]

[tex]\\ {\rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 4 + 3 - 5 & \: \: \: -4 -9 + 10 & \: \: -8 - 12 + 15 \\ -2 - 4 + 5 & \: \: \: \: \: \: + 2 + 12 - 10 & \: \: \: \: \: 4 + 16 - 15 \\ \: \: \: \: \: 2 + 3 - 4 & \: \: -2 - 9 + 8 & -4 - 12 + 12 \end{array} \right] = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right]}}[/tex]

[tex]\\ {\rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right] = Matrix \: A}}[/tex]

For Matrix BA, a = 3, b = c = 3, d = 3 , thus Matrix BA is of order 3 × 3

[tex]\\ {\rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] \times \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: \: 1 & -3 & -4 \end{array} \right]}}= \left[ \begin{array}{c c c} \: \: \: \: \: 2(2) -2(-1) -4(1) & \: \: \: \: 2(-3) -2(4) -4(-3) & \: \: \: \: 2(-5) -2(5) -4(-4) \\ \: -1(2) + 3(-1) + 4(1) & -1(-3) + 3(4) +4(-3) & -1(-5) + 3(5) + 4(-4) \\ \: \: \: \: \: 1(2) -2(-1) -3(1) & \: \: \: \: 1(-3) -2(4) -3(-3) & \: \: \: \: 1(-5) -2(5) -3(-4) \end{array} \right][/tex]

[tex]\\{ \rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 4 + 2 - 4 & \: \: \: -6 -8 + 12 & \: \: -10 - 10 + 16 \\ -2 - 3 + 4 & \: \: \: \: \: \: +3 + 12 - 12 & \: \: \: \: \: + 5 + 15 - 16 \\ \: \: \: \: \: 2 + 2 - 3 & \: -3 -8 +9 & \: \: \: \: \: -5 -10 + 12 \end{array} \right] = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right]}}[/tex]

[tex]\\{ \rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] = Matrix \: B}}[/tex]

Step-by-step explanation:

width is 6 units

P=2(l+w)

p=2(l+6)

l+6=p/2

l= (p/2)-6

The length of the reactangle with a width of 6 units and perimeter p units is (P/2)-6 units.

A perimeter is a closed route that surrounds, outlines, or embraces a rectangle. The perimeter of a rectangle is given by the formula,

[tex]\rm Perimeter= 2(Length +width)[/tex]

As it is given that the width of the rectangle is 6 units, while the perimeter of the rectangle is P. Now if we write about the perimeter of the rectangle, it can be written as,

[tex]\rm Perimeter= 2(Length +width)[/tex]

[tex]P = 2(l+6)\\\\\dfrac{P}{2} = (l+6)\\\\l = \dfrac{P}{2}-6[/tex]

Hence, the length of the reactangle with a width of 6 units and perimeter p units is (P/2)-6 units.

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Answer:

x = 3

Step-by-step explanation:

These angles are actually equal to each other

This is because when two lines intersect, the two opposite angles are the same.

Since they are the same, you can set them equal to each other

Like so:

6x - 7 = 4x - 1

Then solve:

6x - 7 = 4x - 1

6x = 4x +6

2x = 6

x = 3

Using the Central Limit Theorem, it is found that the values of the population standard deviation [tex]\sigma[/tex] needed are given by:

a) [tex]\sigma = 32[/tex]

b) [tex]\sigma = 16[/tex]

c) [tex]\sigma = 4[/tex]

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard error [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

In this problem, we have that n = 16.

Item a:

s = 8, hence:

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]8 = \frac{\sigma}{\sqrt{16}}[/tex]

[tex]\sigma = 32[/tex]

Item b:

s = 4, hence:

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]4 = \frac{\sigma}{\sqrt{16}}[/tex]

[tex]\sigma = 16[/tex]

Item c:

s = 1, hence:

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]1 = \frac{\sigma}{\sqrt{16}}[/tex]

[tex]\sigma = 4[/tex]

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Answer: Its 1,110

Step-by-step explanation:

Answer:

142 meters.

Step-by-step explanation:

Area can be found by multiplying length*width.  This means that if you have an area, but no width, you can divide the area by the length, or vice versa.  To get the answer, you divide 852/6 to get 142.

Answer:

D. Two hours exercising and eight hours cleaning

Step-by-step explanation:

Rob works part time at the Fallbrook Riding Stable. He makes $5 an hour exercising horses and $10 an hour cleaning stalls. Because Rob is a full-time student, he can work no more than 12 hours per week. However, he must make at least $60 per week.

x = hrs. exercising horses

y = hrs. cleaning stalls

Equations:

Hours he can work per week:

x + y ≤ 12

Amount of money he can make per week:

5x + 10y ≥ 60

Now, graph your equations into desmos.

As you can see in the graph, the correct answer is D (2, 8)

Check your answer by hand:

x + y ≤ 12

2 + 8 ≤ 12

10 ≤ 12

This statement is correct

5x + 10y ≥ 60

5(2) + 10(8) ≥ 60

10 + 80 ≥ 60

90 ≥ 60

This statement is correct

Therefore, the correct answer is D

Hope this helps!

The inequality that represent the number of students in the class is x ≤ 24. They could be 20 students

An inequality is an expression that shows the non equal comparison of two or more numbers and variables.

Let x represent the number of students in the class, hence:

x ≤ 6(4)

x ≤ 24

If each team has at least 2 students:

x ≥ 6(2)

x ≥ 12 and x ≤ 24

The inequality that represent the number of students in the class is x ≤ 24. They could be 20 students

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Answer:

$600,000

Step-by-step explanation:

GIven;

Alex had $750,000 he lost 80%

To Find;

How many dollars did he lose ​

Solve;

$750,000 * 80% = 600,000

Hence, Alex lost $600,000.

~Learn with Lenvy~

Answer:75,000

Step-by-step explanation:he has 750,000 but he loses 80% so he has 75,000 about.