Helppppppp pleaseeeee

Answer:

0.8 km per day

Step-by-step explanation:

5 3/5 is the same as 5.6, so

5.6/7

= 0.8 km per day

Hey there!

k - 10/2 = -7

k - 5 = -7

ADD 5 to BOTH SIDES

k - 5 + 5 = -7 + 5

CANCEL out: -5 + 5 because that gives you 0

KEEP: -7 + 5 because it helps solve for the k-value

NEW EQUATION: k = -5 + 7

SIMPLIFY IT & YOU HAVE YOUR ANSWER!

k = -2

Therefore, your answer is: k = -2

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

I believe the answer will be 27/3

Answer:

2^9=512

5.9*10^2=590

9^3=729

5^4=625

6.81*10=68.1

6.81 × 10¹, 2⁹, 5.9 × 10²,  5⁴, 9³

Answer: -1/6

You can multiply 2/6 by 2 to get 4/12 which you can subtract from 6/12.

4/12 - 6/12 = -2/12 which you can simplify further to get -1/6

Answer:

No solution

Step-by-step explanation:

How should I kow how much he drove? I need at least one distance. Either your fooling me, or the person who gave you this question is. There is no solution.

Answer:

122.4 i think

Step-by-step explanation:

Answer:

2×2=4

9x+2=11x

1-6x=4x

x²-4=16

=16¹⁵x

Answer:

im 11  and

Step-by-step explanation:

i just need points i have -32

Answer:

r= 5/12 h

Step-by-step explanation:

r/h = 1/2.4

r =[tex]\frac{10}{24}[/tex]h

r=[tex]\frac{5}{12}[/tex]h

Answer:

[tex]x=-10-8 = -18[/tex]

Step-by-step explanation:

Answer:

x=-10-8=18

Step-by-step explanation:

Answer:

N = 34

Step-by-step explanation:

METHOD I

(hit and trial)

The given two ratios have to be equal.

This means, 24 : N must break down to 12 : 17 after dividing it by some common factor.

The common factor here is 2.

Since,

12 × 2 = 24

17 × 2 = 34

[tex] \boxed{\mathsf{ \underline{N \: must \: be \: 34}}}[/tex]

(after dividing the first ratio by 2(common factor) we get the second ratio. Meaning that they become equivalent as required by the question).

METHOD II

(mathematical approach)

Ratios can be written in form of fractions as:

[tex] \boxed{ \mathsf{ \frac{24}{N} = \frac{12}{17} }}[/tex]

Cross multiplying:

[tex] \implies \mathsf{24 \times 17 = 12 \times N }[/tex]

taking 12 to the denominator:

[tex] \implies \mathsf{ \frac{24 \times 17 }{12} = N }[/tex]

24 and 12 gets canceled and 2 takes up their spot

(why?

=> 24 ÷ 12 = 2)

[tex] \implies \mathsf{2 \times 17 = N } [/tex]

[tex] \implies \mathsf{2 \times 17 = N } [/tex]

[tex] \implies \mathsf{ N = 34 } [/tex]

[tex] \implies \mathsf{ N = 34} [/tex]

Answer:

Any number smaller than 2

Step-by-step explanation:

You would graph this by wrighting a solid, filled in circle with an arrow point toward the negative numbers, because those numbers are smaller than 2

Answer:

36

Step-by-step explanation:

6:8

27/6 = 4.5

8 · 4.5 = 36

Answer:

Around 19 rows

Step-by-step explanation:603/31= 19.40 so I'm not too sure

Answer:

Step-by-step explanation:

Conclusion:

Therefore:

Hoped this helped.

[tex]GeniusUser[/tex]

Answer:

4860

Step-by-step explanation:

Get the product of twenty and three, then multiply that to three again, repeat this for three more times.

Answer:

7.8 or 8

Step-by-step explanation: To get the hypotenuse of a right triangle we must square each part.

5^2 is 25 and 6^2 is 36

Now you add the two squared parts, which equals 61. 61 squared isn't a perfectly squared. This means the answer is 7.8 or rounded to the nearest tenth the answer will be 8.

Recall that

(a + b)² = a² + 2ab + b²

Then

(a + b)² = 25 + 2•12 = 49

Step-by-step explanation:

i think is this the answer

5×-4=-20

-20+2=18

Answer:

y=15

Step-by-step explanation:

Answer:

  1. 125 cm³; 88.8 cm³; 1650 cm³; 0.11 m³

  2. about 1.47 kg

  3. can't tell what the volume of 1 jar is

Step-by-step explanation:

The relationship between volume, mass, and density is ...

  mass = volume × density

Solving for volume, we find ...

  volume = mass ÷ density

__

(a) 50 g/(0.4 g/cm³) = 125 cm³

(b) 770 g/(8.67 g/cm³) ≈ 88.8 cm³ . . . (rounded to 3 significant figures)

(c) 4000 g/(2.42 g/cm³) ≈ 1650 cm³ . . . (rounded to 3 significant figures)

(d) 80 kg/(720 kg/m³) ≈ 0.11 m³ . . . (rounded to 2 significant figures)

_____

The volume of the cylinder is ...

  V = πr²h

  V = π(4 cm)²(15 cm) = 240π cm³ ≈ 754.0 cm³

Using the above relation, we find the mass to be ...

  mass = (754.0 cm³)(1.95 g/cm³) ≈ 1470 g = 1.47 kg

_____

We cannot tell if the volume of each jar is 360 liters, or if that is the total volume of all 6 jars. Either way, we suspect a units problem, as the jars would have to be extremely large and unusually thin relative to what we usually think of as a jar for jam (0.77 m diameter; 0.2 mm thick). The density of the jam would be roughly 10 times the density of air, if that is the volume of all 6 jars. The problem would be more sensible if the units of volume were mm³, and the given volume is that of one jar.

The mass of jam in one jar is (5400/6 -200) = 700 g. Divide that by what you think the volume of one jar is in cm³ to find the density in g/cm³. (For comparison, the density of air is about 0.0012 g/cm³.)

_____

Additional comment

We have rounded the answers to 2 or 3 significant figures. In most cases, this is more than would be justified by the number of significant figures in the given measurements. For purposes of ongoing calculations, it is useful to keep intermediate results to at least 1 more significant figure than required for the answer.

in order:

y=6

y=16

y=26

y=31

The length of the line segment GD is 10.5

To get the length of the line segment GD, we will use similarity theorems of triangles to have:

ED/FD = GD/DH

Substitute the given sides to have:

6+GD/(8+14) = GD/14

6+GD/22 = GD/14

Cross multiply

22GD = 14(6+GD)

22GD = 84 + 14GD

22GD - 14GD = 84

8GD = 84

GD = 84/8

GD = 10.5

Hence the length of the line segment GD is 10.5

Learn more on similarity theorems of triangle here: https://brainly.com/question/8242716

Answer:

[tex] - (6 - 4x) = - 6 + 4x[/tex]

Answer:

[tex]-6+4x[/tex]

Step-by-step explanation:

[tex]-(6-4x)[/tex]

[tex]\mathrm{Distribute\:parentheses}[/tex]

[tex]=-\left(6\right)-\left(-4x\right)[/tex]

[tex]\mathrm{Apply\:minus-plus\:rules}[/tex]

[tex]-\left(-a\right)=a,\:\:\:-\left(a\right)=-a[/tex]

[tex]=-6+4x[/tex]