Houa is driving to a concert and needs to pay for parking. There is an
automatic fee of $8 just to enter the parking lot, and when she leaves the lot, she will have to pay an additional $2 for every hour she had her car in the lot. How much total money would Houa have to pay for
parking if she left her car in the lot for 3 hours? How much total money would Houa have to pay if she left her car in the lot for 3 hours? How much would Houa have to pay if she left her car in the lot for t hours?

Cost of parking for 3 hours:
I
Cost of parking for t hours:

Answer:

$20,000

Step-by-step explanation:

20,000 / 0.07 = 1400

Check the picture below.

The value of f(x) at x=4 is 2.

A function is an expression, rule, or law in mathematics that describes a relationship between one variable (the independent variable) and another variable (the dependent variable). Functions are common in mathematics and are required for the formulation of physical relationships in the sciences.

We have to find the value of function for x=4.

This means that from the figure we have to find the value of y when x= 4.

Now, looking into the figure we have

f(4)= 2

f(0)= -2

f(-1)= -1

f(3)= 4

So, the required value is 2.

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Answer:

5x + 6 = 0

5x = - 6

x = - 6/5

-6/5 is the answer

Answer:

x=sqrt(7)

Step-by-step explanation:

Since this is a right triangle, we can use the pythagorean theorem

a^2 + b^2 =c^2  where a and b are the legs and c is the hypotenuse

x^2 + ( sqrt(7))^2 = (sqrt(14))^2

x^2+7 = 14

x^2 = 14-7

x^2 = 7

Take the square root of each side

sqrt(x^2) = sqrt(7)

x=sqrt(7)

Answer:

ANSWER: Yes. They have enough to pay their bill: 21 dollars times 1.06 = 22 dollars and 26 cents and 22 dollars and 26 cents times 1.15 = 25 dollars and 60 cents.

Step-by-step explanation:

convert all % to decimals

0.06 x 21 = $1.26 tax

0.15 x 21 = $3.15 tip

1.26 + 3.15 = $4.41 added payment

4.41 + 21 = = $25.41 total bill

(yes i am aware i did the method differently since i learned it another way but the answer should till be correct.)

Answer:

Yes. They have enough to pay their bill: 21 dollars times 1.06 = 22 dollars and 26 cents and 22 dollars and 26 cents times 1.15 = 25 dollars and 60 cents. Otherwise B.

Answer:

x=28°

Step-by-step explanation:

supplementary angles equal 180°

So:

3x+2x+x+12=180°

6x+12=180

6x=168

x=28°

Therefore:

3x:

3(28)=84°

2x:

2(28)=26°

x+12:

28+12=40°

Answer:

Step-by-step explanation:

The progression of sums is ...

  1, 5, 15, 34, 65, ...

So, first differences are ...

  4, 10, 19, 31

Second differences are ...

  6, 9, 12, ...

Third differences are constant:

  3, 3, ...

This means the expression for Sn will be a cubic expression. If dn is the first of the n-th differences, then the equation can be written as ...

  Sn = S1 +(n -1)(d1 +(n -2)/2(d2 +(n -3)/3(d3)))

And this simplifies a little bit to ...

  Sn = 1 +(n -1)(4 +(n -2)(n +3)/2)

In simpler form, we have ...

  Sn = 1/2(n³ +n)

Then the two terms we're interested in are ...

  S7 = (1/2)(7³ +7) = 175

  S17 = (1/2)(17³ +17) = 2465

Each term Sₙ consists of the sum of a triangular number of terms, which are given by

[tex]T_n = \displaystyle \sum_{k=1}^n k = 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}2[/tex]

The triangular numbers are given recursively for n ≥ 1 by

[tex]T_n = T_{n-1} + n[/tex]

starting with T₀ = 0.

For example,

• S₁ = 1 and

[tex]\displaystyle S_1 = \sum_{k=T_0+1}^{T_1} k = \sum_{k=1}^1 k = 1[/tex]

• S₂ = 2 + 3 and

[tex]\displaystyle S_2 = \sum_{k=T_1+1}^{T_2} k = \sum_{k=2}^3 k = 2 + 3[/tex]

• S₃ = 4 + 5 + 6 and

[tex]\displaystyle S_3 = \sum_{k=T_2+1}^{T_3} k = \sum_{k=4}^6 k = 4 + 5 + 6[/tex]

Then the n-th term of the sequence we're considering is

[tex]S_n = \displaystyle \sum_{k=T_{n-1}+1}^{T_n} k = \sum_{k=T_{n-1}+1}^{T_{n-1}+n} k[/tex]

Expanding this sum, we have

[tex]S_n = \left(T_{n-1}+1\right) + \left(T_{n-1}+2\right) + \left(T_{n-1}+3\right) + \cdots + \left(T_{n-1}+n\right)[/tex]

There are n terms on the right side, and hence n copies of [tex]T_{n-1}[/tex], and the rest of the terms make up the next triangular number [tex]T_n[/tex] :

[tex]S_n = nT_{n-1} + 1 + 2 + 3 + \cdots + n[/tex]

[tex]S_n = nT_{n-1} + \displaystyle \sum_{k=1}^n k[/tex]

[tex]S_n = nT_{n-1} + T_n[/tex]

We have a closed form for [tex]T_n[/tex], so we end up with

[tex]S_n = n \cdot \dfrac{(n-1)n}2 + \dfrac{n(n+1)}2 \implies \boxed{S_n=\dfrac{n^3+n}2}[/tex]

From here it's easy to find S₇ and S₁₇.

[tex]S_7 = \dfrac{7^3+7}2 \implies \boxed{S_7 = 175}[/tex]

[tex]S_{17} = \dfrac{17^3+17}2 \implies \boxed{S_{17} = 2465}[/tex]

2b + 21 < 22

b is the unknown number so multiply it by 2 to get 2b then add 21, bring the less than sign and write the 22 after the less than sign

22/3 sorry I accidentally deleted steps

Answer:

7½ cups of sugar

Step-by-step explanation:

2 cups of flour needs 3 cups of sugar

1 cups of flour needs 3/2=1.5 cups of sugar

1×5 cups of flour needs 1.5×5=7.5 cups of sugar=7½ cups of sugar ANS

Answer:

9, 12

Step-by-step explanation:

the rule is +3 for each step in the sequence

Answer:

Hello There!

According to the question,

Base=6

And

Height =4

Let's know the formula

[tex] \frac{1}{2} \times base \times height \\ so \\ \frac{1}{2} \times 6 \times 4 \\ [/tex]

simplify 2 with 6 then it will look like this

[tex] \frac{1}{1} \times3 \times 4 \\ \\ [/tex]

1 has no value so

[tex]3 \times 4 = 12 {ft}^{2} \\ [/tex]

So third option

[tex]a = 12 {ft}^{2} [/tex]

is correct.

[tex]\Large\textsf{Hope \: It \: Helped}[/tex]

Answer:

Area = 12 sq ft

Step-by-step explanation:

The formula to find the area of a triangle is

1/2 bh so we will replace the letters with their number value

1/2 (6x4)

1/2 x 24 = 12

So, 12 is your answer!

Answer:

7=4m +c( y intercept)

Step-by-step explanation:

use the formula y= mx +c

Answer:

your grade will be an 76

Step-by-step explanation:

Answer:

630

Step-by-step explanation:

the value of 7 in the tenths place is 70

the value of 7 in the hundredths place is 700

compare 700 and 70

So 700-70 = 630

Answer:

Click the picture and u will see the answer.

#CarryOnLearning

The summation of the given function from 1 to 4 is 10.5x³.

The given parameters:

[tex]\Sigma \ x^3 \times \Delta x, \ \ \ \Delta x = 2 + \frac{i}{4} \\\\[/tex]

The summation of the given function from i = 1, to i = 4, is calculated as follows;

[tex]\Sigma \ x^3 \times \Delta x = x ^3 (2 + \frac{1}{4} ) + x ^3 (2 + \frac{2}{4} ) + x ^3 (2 + \frac{3}{4} ) + x ^3 (2 + \frac{4}{4} )\\\\= x^3(10\frac{1}{2} )\\\\=\frac{21}{2} x^3\\\\= 10.5x^3[/tex]

Thus, the summation of the given function from 1 to 4 is 10.5x³.

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Answer:

Step-by-step explanation:

The rule when you divide two values with the same base is to subtract the exponents.

Answer:

[tex]-\frac{1}{4}(\sqrt{2}+\sqrt{6})[/tex]

Step-by-step explanation:

[tex]cos(\frac{11\pi}{12})[/tex]

[tex]cos(\frac{2\pi}{3}+\frac{\pi}{4})[/tex]

[tex]cos(\frac{2\pi}{3})cos(\frac{\pi}{4})-sin(\frac{2\pi}{3})sin(\frac{\pi}{4})[/tex]

[tex](-\frac{1}{2})(\frac{\sqrt{2}}{2})-(\frac{\sqrt{3}}{2})(\frac{\sqrt{2}}{2})[/tex]

[tex]-\frac{\sqrt{2}}{4}- \frac{\sqrt{6}}{4}[/tex]

[tex]-\frac{1}{4}(\sqrt{2}+\sqrt{6})[/tex]

Helpful Tips:

Sum Identity: [tex]cos(\alpha+\beta)=cos(\alpha)cos(\beta)-sin(\alpha)sin(\beta)[/tex]

Answer:

It's 48.

Hope that helped? Also, if you need anymore answers feel free to ask me as I had that assignment on Mathswatch.

Step-by-step explanation:

Answer:

i think it's 48 if i'm wrong i'm sorry

Answer:

4 tenths or 4/10

Step-by-step explanation:

Answer:

16:1

Step-by-step explanation:

Since there are 85 total people and 80 are students that means 5 are chaperones.(85-5) Therefore the ratio of students to chaperones is 80:5 or simplified 16:1.

[tex]\text{Given that,}\\\\f(x) = 4x+5,~~~g(x) = \dfrac 2x\\\\\\f(3) = 4(3) +5 = 12 +5 = 17\\\\\\(g\circ f)(3)=g(f(3))=g(17)=\dfrac 2{17}[/tex]

Answer:

The answer is 2/17

Step-by-step explanation: Can I get brainliest again my answer was deletedee

Answer:

4

Step-by-step explanation:

-4+3=-1

-1+5=4

Answer:

DC

Step-by-step explanation:

If we rotate a segment around a point 360 degrees, we have rotated it around to its original point. Similarly, if we rotate it 180 degrees, we have rotated it to the side opposite of where it once was relative to the point.

What we can do is see how much 144 degrees is of 360 and use that to determine how far around we rotate AE around F.

144/360

divide by 12 because that is a common factor of both the numerator and denominator

12 / 30

divide by 2 because that is a common factor

6/15

divide by 3 because that is a common factor

2/5

Therefore, 144/360 = 2/5. This means that we rotate segment AE 2/5 of the way around point F. We have 5 sides in the polygon ABCDE, and each represents 1/5 of the way around. Going counterclockwise, ED represents 1/5, DC represents 2/5, and so on. We are looking for 2/5, so DC is our answer

Answers:

=========================================================

Explanation:

For equation A, I'll transform the right hand side into a similar form as the left side. Throughout the steps below, the left hand side stays the same.

[tex]\sqrt{448x^c} = 8x^3\sqrt{7x}\\\\\sqrt{448x^c} = \sqrt{(8x^3)^2}\sqrt{7x}\\\\\sqrt{448x^c} = \sqrt{64x^{3*2}}\sqrt{7x}\\\\\sqrt{448x^c} = \sqrt{64x^{6}}\sqrt{7x}\\\\\sqrt{448x^c} = \sqrt{64x^{6}*7x}\\\\\sqrt{448x^c} = \sqrt{64*7x^{6+1}}\\\\\sqrt{448x^c} = \sqrt{448x^{7}}\\\\[/tex]

Therefore, c = 7

Notice that 7/2 = 3 remainder 1. The quotient 3 is the exponent for the term outside the root for [tex]8x^3\sqrt{7x}[/tex] while the remainder 1 is the exponent for the x term inside the root.

---------------------------------------

We do the same idea for equation B.

[tex]\sqrt[3]{576x^{d}} = 4x\sqrt[3]{9x^{2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{(4x)^3}\sqrt[3]{9x^{2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{64x^3}\sqrt[3]{9x^{2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{64x^3*9x^{2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{64*9x^{3+2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{576x^{5}}\\\\[/tex]

This must mean d = 5

Note: 5/3 = 1 remainder 2, which means [tex]\sqrt[3]{x^5} = x^1\sqrt[3]{x^2} = x\sqrt[3]{x^2}[/tex]