How are earthquake epicenters active volcanoes and mountain ranges distributed on the map?

Answers

Answer 1

Answer:

Volcanoes and earthquakes are not randomly distributed around the globe.

Explanation:

Instead they tend to occur along limited zones or belts. With the understanding of plate tectonics, scientists recognized that these belts occur along plate boundaries.


Related Questions

3.9 determine the current i in the circuit of fig. 3.21 after first replacing the four sources with a single equivalent source.

Answers

The current I in the circuit after first replacing the four sources with a single equivalent source is calculated as 50mA. The circuit can be seen in the attached diagram.

Series combination

If we have to combine the voltage sources, they must be in series. In the question since it is given that same current flows through each, thus it means it is in series.

If we start from the bottom and proceed clockwise in the circuit, we have

-3-9-5+1 = -16V

The four voltage equivalent sources are to be replaced with a single 16V source.

so, then when KVL is mixed with the Ohm's law, we have

-16 + 100i +220i = 0

⇒ i = 16/320 = 50mA

The circuit described in the given question is also equivalent

For the diagram pertaining to the circuit, it is attached below.

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this observation indicated that the rays thomson observed that the nature of the cathode rays was identical whether iron or any other material was used to construct the cathode. are embedded in a sea of positive charge. carry a negative charge. are fundamental to all matter. have mass.

Answers

In the Cathode ray experiments, JJ Thomson observed that cathode rays were produced high voltage was applied to an anode and cathode in an evacuated tube.

What is the cathode ray experiment?

Thomson surrounded the cathode ray with two electric plates that were charged in opposition to test the qualities of the particles. The negatively charged electric plate was avoided in favor of the positively charged plate, deflecting the cathode ray. This demonstrated the presence of negatively charged particles in the cathode ray.

JJ Thomson discovered during the cathode ray tests that cathode rays were generated when a high voltage was supplied to the anode and cathode inside of an evacuated tube. Cathode rays were deflected away from a negative charge and towards a positive charge, which allowed Thomson to conclude that they were negative particles. It was later determined that these particles were electrons, not cathode rays.

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Which of the following is the source of wealth for a nation in a mercantilism system?
a. religion
B. population
c. natural resources
D. land​

Answers

Answer:

c. natural resources

Explanation:

mercantilism is an economic practice by which governments use their economies

so economies in this mean their natural resources

if am ryt

Answer:

C. natural resources

Explanation:

Mercantilism is based on the concept of a nation's power being directly related to its wealth. A nation's goal under mercantilism was to obtain as much gold and silver as possible and to export more goods than it imported from other nations. Gold and Silver are natural resources.

a very large thin plate is centered in a gap of width 0.06 m with different oils of unknown viscosities above and below; one viscosity is twice the other. when the plate is pulled at a velocity of 0 3 m s, the resulting force on one square meter of plate due to the viscous shear on both sides is 29 n. assuming viscous flow and neglecting all end effects, calculate the viscositie

Answers

μ1 = 0.97 and μ2 = 1.93 (viscosities of fluid below and above plate respectively.)

We have to find the viscosities above and below the plate

Let us take the viscosities above the plate = μ1 ,and below the plate =μ2

Now the force applied due to top layer of the fluid

Т1 = μ (Δu / Δv )

Here Δu and Δv are the velocity of plate and gap between the plate and upper surface respectively.

Where Δu= 0.3

          Δv = 0.03

So,

   T1 = μ( 0.3/0.03)

        =10μ

Now we have to find the force on plate due to bottom of the fluid

T2 = μ2 ×( Δu / Δv)

T2 = μ2 × (0.3/0.03)

T2= 10μ2

Total force per unit is = T1 + T2

i.e., the sum of two  viscous shear .

F/ A = T1 + T2

It is given that sum of two viscous sheer is 29N.

So

T1 + T2 = 29

10μ1 + 10 μ2 = 29

10(μ1 + μ2) = 29

μ1 + μ2 = 2.9  

μ2= 2μ1

Hence we get

μ1 + 2μ2 =2.9

3μ1=2.9

μ1 = 2.9/3

    0.9667≈ 0.967

 μ2 = 2μ1

       =  2 × 0.9667

       =1.9333 ≈1.93

Therefore the viscosities above and below the plate due to the top layer of the fluid are 0.967 and 1.93 respectively.

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What is the core ram clock speed for ram with a ddr2 speed rating of ddr2-800 and a pc speed rating of pc2-6400?

Answers

Answer:

400 MHz

Explanation:

voodoo$ knows all

A train running at 30 m/s is slowed uniformly to a stop in 44 seconds. Find (a) the acceleration and (b) the stopping distance.

Answers

A. The acceleration of the train is –0.68 m/s²

B. The stopping distance is 660 m

What is acceleration?

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a is the acceleration v is the final velocity u is the initial velocity t is the time

A. How to determine the acceleration Initial velocity (u) = 30 m/sFinal velocity (v) = 0 m/sTime (t) = 44 sAcceleration (a) =?

a = (v – u) / t

a = (0 – 30) / 44

a = –0.68 m/s²

B. How to determine the distanceInitial velocity (u) = 30 m/sFinal velocity (v) = 0 m/sTime (t) = 44 sDistance (s) =?

s = (v + u)t / 2

s = [(0 + 30) × 44]/ 2

s = (30 × 44) / 2

s = 1320 / 2

s = 660 m

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radio frequency (rf) signals are also called electromagnetic (em) signals. optical signals are based upon photons and not electromagnetic waves, therefore optical signals are not part of the em spectrum

Answers

The statements are true that radio frequency signals are also called electromagnetic signals and optical signals are based upon photons and not electromagnetic waves, that's why optical signals are not part of the electromagnetic spectrum.

What is an Electromagnetic Spectrum?

The complete spread of electromagnetic radiation by wavelength or frequency. Although all electromagnetic waves have a wide range of frequencies, wavelengths, and photon energies, they all move at the speed of light in a vacuum.

The range of all electromagnetic radiation is represented by the electromagnetic spectrum, which also includes numerous subranges, often known as parts, such as visible light and ultraviolet radiation. The various parts have different names depending on variations in the emission, transmission, and absorption of the associated waves as well as on the many practical uses for which they are put to use.

All radio waves (such as commercial radio and television, microwaves, and radar), infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays are all included in the entire electromagnetic spectrum, which ranges in frequency from the lowest to the highest (longest to shortest wavelength). Spectroscopy may make use of almost all electromagnetic radiation's frequencies and wavelengths.

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What is the gravitational acceleration close to the surface of a planet what a mass of 3m?

Answers

The gravitational acceleration close to the surface of a planet then a mass of 3m will be

Gravitational force is directly related to the mass of a body.

As the mass increases the gravitational force increases.The force which is exerted by an body to attract another body towards itself is known is gravitational force.Let us suppose that the mass of a body is m.So, if the mass of the body is increased 3 times then the effect of gravity is also increased by three times.The formulae to calculate gravity is = [tex]\frac{m_{1}m_{2} }{r^{2} }[/tex]  where [tex]m_{1}[/tex] and [tex]m_{2}[/tex] are the masses of two bodies to which gravity is being calculated and r is the distance between the two bodies.

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I need answers to these physics problems. (See picture). Also, i'm not sure if the one's I circled are correct

Answers

The length of the vector is proportional to the size of the force.

The wheelchair is not accelerating, so the forces on it are balanced.

In a free-body diagram of the wheelchair, force due to gravity points down,  normal force points up, force pushing the wheelchair points forward, friction resisting the motion points backward.

For the force diagram:

In picture 1: F gravity points down; F normal points upIn picture 2: F gravity points down; F tension points upIn picture 3: F gravity points down; F spring points up.

What are forces?

Forces are a push or pull agents that causes a change in the state of a body when they are applied to the body.

Unbalanced forces cause acceleration of a body.

In a free-body diagram, the mass (force) on an object is represented by a vector.

The length of the vector is proportional to the size of the force. Suppose you push a wheelchair forward at constant velocity. The wheelchair is not accelerating, so the forces on it are balanced. In a free-body diagram of the wheelchair, the vector for the force due to gravity points down, the vector for the normal force points up, the vector for your force pushing the wheelchair points forward, and the vector for the force of friction resisting the motion points backward.

Considering the picture visual representation of the forces between many interacting objects or the force diagram:

In picture 1: F gravity points down; F normal points up

In picture 2: F gravity points down; F tension points up

In picture 3: F gravity points down; F spring points up.

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what did classical physics predict would happen to the light given off by an object as its temperature increased?

Answers

Answer:

Classical physics predicted that the light given off by an object as its temperature increased is that the energy of the light would increase from visible light into the ultraviolet range

Explanation:

The phenomena are referred to as Black body radiation. When a substance heats up, its electrons become excited. An electron will occasionally descend to a lower state and produce a photon. The frequency of emitted light increases with increasing temperature.

This is also how incandescent light bulbs operate. The majority of the light we see from stars is caused by black body radiation, and we may deduce the temperature of a star based on its hue. Plank's Law is the equation that gives the energy emitted as a function of frequency and temperature.

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an automobile accelerates from 55.0 km/h to 85.0 km/h in 8.70 s. what is its acceleration in m/s2? recall 1 km

Answers

The acceleration can be found as 3.44× 10³  m/s².

To find the acceleration, the given values are,

Initial velocity = 55 km/hr

Final velocity = 85 km/hr

time t = 8.70 seconds.

What is acceleration?Acceleration is a rate of change of velocity with respect to time with respect to direction and speed.A point or an object moving in a straight line is accelerated if it speeds up or slows down.Acceleration formula can be written as,

                   a = (v - u ) / t m/s²

where, a - acceleration m/s²

v - Initial velocity km/hr

u - final velocity km/hr

t - time

Acceleration is a vector quantity.

Substituting the values in the acceleration formula,

 a = ( 85 × 10³ - 55 ×10³ ) / 8.70

    = 30 × 10³/ 8.70

    = 3.44 × 10³ m/s².

The acceleration of the automobile can be found as 3.44 × 10³  m/s².

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(a)
The skateboard moves backwards as the skateboarder jumps forwards. Explain,
using the idea of momentum, why the skateboard moves backwards.

Answers

The amount of momentum before and after a jump is equal. Prior to jumping, neither the skateboarder nor the skateboard had any momentum. Following a jump, the skateboarder gains forward momentum, thus the skateboard must also gain reverse momentum

In the hippie jump, a skateboarder travels at a specific speed Vh along a flat, horizontal surface. Then, without touching the board horizontally, he jumps straight up. He may now soar through the air at a speed equal to that of the board (also moving at Vh). As a result, he can land on top of the board because it is still right underneath him. this is how the momentum involved.

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What is the energy of each of the two photons produced in proton antiproton annihilation?

Answers

The minimum energy is released, and hence the minimum frequency photons are produced, when the proton and antiproton are at rest once they annihilate.

Energy = 2.27 × 10²³Hz

That is, E=E₀ and K=0. To conserve momentum, each photon must have the identical magnitude of momentum, and p = E/C, so each photon must take away one-half the energy

[tex]E_{min} = \frac{E_{0} }{2}[/tex] = E₀ = 938.3MeV = [tex]hf_{min}[/tex]

[tex]f_{min} =\frac{(938.3MeV) (1.602 * 10^{-13} J/MeV}{6.626 *10^{-34}Js } = 2.27 * 10^{23} Hz[/tex]

How much energy is required to produce a proton-antiproton pair?

The process of creating a particle-antiparticle pair is called pair production. to supply this pair, you would like a boson with sufficient energy. The Mass-Energy of both a proton and an anti-proton is about 938 Mev/c². Translated into Joules, this mean you would like about 27 MJ to do so

How is annihilation energy calculated?

The amount of energy (E) produced by annihilation is equal to the mass (m) that disappears multiplied by the square of the speed of light in a vacuum (c)—i.e., E = mc²

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A motorcycle, starting from rest, has an acceleration of +2.6 m/s². After the motorcycle has traveled a distance of 120 m, it slows down with an acceleration of -1.5 m/s² until its velocity is +12 m/s. a. Calculate the final velocity of the motorcycle after the first 120 m interval.

Answers

The velocity of the motorcycle after the first 120 m is 24.97 m/s and the total displacement of the motorcycle is 280 m.

The acceleration of the motorcycle starting from rest is 2.6 m/s².

The acceleration of the motorcycle after traveling a distance of 120 m id -1.5 m/s² and the velocity is 12 m/s.

The initial velocity of the motorcycle, u = 0 m/s

The acceleration of the motorcycle, a = 2.6 m/s²

Therefore, the final velocity of the motorcycle after d = 120m is:

v² - u² = 2as

v² = u² + 2as

v² = (0)² + 2 × 2.6 × 120

v² =  624

v = √624

v = 24.97 m/s

Now, the motorcycle slows down to -1.5 m/s² and a velocity of 12 m/s.

So, the initial velocity is u = √624 m/s and final velocity is v = - 12 m/s.

So,

v² - u² = 2as

( - 12)² - (√624)² = 2 × -1.5 × d

144 - 624 = - 3 × d

- 480 = - 3d

d = 480 / 3 = 160 m

Therefore, the total displacement of the motorcycle is 120 m + 160 m = 280 m.

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Help :))))))))))))))))))))))

Answers

Answer:

1) 00.5

2) 400

3) 0.0601

4) 10900

Explanation:

goggle it

a fan is to accelerate quiescent air to a velocity of 5 m/s at a rate of 5 m^3/s. find the minimum power required for the fan if the air density is 1.2 kg/m^3.

Answers

The minimum power that is required for the fan is 75W.

Calculation

It is given that:

ρ = 1.2 kg/m³, density of air

v = 5 m/s, flow velocity

Q = 5 m³/s, volumetric flow rate

So the minimum power required at 100% efficiency can be known by

P= 1/2 [tex]v^{2}[/tex][tex]\rho[/tex]Q

=1/2 x [tex]5^{2}[/tex] x 1.2 x 5

=75 W

The minimum power to be supplied is 75W

Power

Power is defined as the amount of energy that is transferred or converted per unit time. Watt can be defined as the unit of Power which is one joule per second.

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is it nessesary to have a break in a swiming pool after you eat?

Answers

Answer:

yes

Explanation:

because you have to eat so that you can have strength of swimming again

10.A person drives 6 km in a car and sees a sign for Burger King. He turns around
and drives back 1 km to get some food.
a. What is his distance?
b. Displacement?

Answers

The distance covered by man is 7 km and displacement will be 5 km.

What are distance and displacement?

Distance is defined as the total path covered between two points. It is a scalar quantity.

Displacement is defined as the shortest path between two points. It is a vector quantity.

Distance is either always greater or equal to displacement. The distance can never be smaller than displacement.

According to the question, a person drives 6 km in the car, and he comes back 1 km to get some food means the distance traveled by him is 7 km.

However, the distance travelled will only be 5 kilometers if he travels straight to Burger King. Displacement is, after all, the shortest route between two places.

Hence, the distance will be 7 km and displacement will be 5 km respectively.

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a security guard walks at a steady pace, traveling 120 mm in one trip around the perimeter of a building. it takes him 250 ss to make this trip.

Answers

The security guard make the trip of 120 m of distance in a time of 250 s with a speed of: 0.48 m/s

The formula and procedure we will use to solve this exercise is:

v = x /t

Where:

x = distancet = timev = velocity

Information about the problem:

t = 250 sx= 120 mv = ?

Applying the velocity formula we have that:

v = x /t

v = 120 m /250 s

v = 0.48 m/s

What is velocity?

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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What constant acceleration (in m/s2 ) will bring haley to this lower speed in the distance available?

Answers

The value of constant acceleration is 0.29m/s

Given that Haley is driving down a straight highway at 73 mph. A construction sign warns that the speed limit will drop to 55 mph in 0.50 mi.

we have to  find out constant acceleration (in ) that will bring Haley to this lower speed in the distance available

we know that,

1mile= 1.609km

1 km/h = 5/18m/s

Initial Speed of Haley(u)=  73mph=73×1.609×(5÷18) =32.63m/s

Final Speed of Haley(v)=  55 mph=55×1.609×(5÷18)=24.58m/s

The distance to be travelled  while lowering the speed(S)= 0.5mile=0.805km=805m

according to third equation of motion,v²-u²=2as

as speed is lowering down the acceleration will be in the opposite direction of motion, hence acceleration will be negative, equation will become u²-v²=2as

putting values,(32.63)²-(24.58)²=2a×805

a=(460.55÷1610)

a≅0.29m/s²

the constant acceleration  that will drop speed to  is 0.29m/s².

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___ electrification occurs any time two objects with different levels of charge make physical contact.

Answers

Contact electrification occurs any time two objects with different levels of charge make physical contact.

Contact electrification is a word that describes a phenomenon wherein surfaces end up electrically charged, thru a number of viable mechanisms, while  or greater objects come within near proximity of one another.

Static electricity is created while effective and bad costs aren't balanced. Protons and neutrons do not circulate around tons, however electrons love to jump all around the place. Whilst an item has greater electrons, it has a poor price.

Static electricity is an imbalance of electrical costs with in or at the surface of a material. The rate stays till it could pass away by an electric powered current or electric discharge.

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A race car is one lap behind the lead race car when the lead car has 52 laps to go in a race. If the speed of the lead car is 56.3 m/s, what must be the average speed of the second car to catch the lead car just before the end of the race, assume 1 lap is 1.34km

Answers

The speed of the car is 55.2 m/s.

What is the average speed?

We can define speed as the ratio of distance to time. We know that the question states the car is one lap behind the lead race car when the lead car has 52 laps to go in a race.

If 1 lap =  1.34km or 1340 m

Distance covered =   1340 m * 52 = 69680 m

Time = 69680 m/ 56.3 m/s

= 1237.7 s

Given that the second car is one lap behind;

51 *  1340 m = 68340 m

Speed =  68340 m/1237.7 s

= 55.2 m/s

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Two identical containers at the same pressure contain the same gas. if container a contains half as much gas as container b, which container has the lower temperature?

Answers

Container A has a higher temperature than container B according to the ideal gas approximation.

What is an ideal gas?

Multiple randomly moving point particles with no interparticle interactions make create an ideal gas in theory. The ideal gas notion is useful because it complies with the ideal gas law, has a condensed equation of state, and can be studied using statistical mechanics.

An ideal gas is a fictitious gas that, because of its tiny size and lack of interactions, perfectly complies with the gas laws. Ideal gas is a gas that abides by all gas laws at all pressures and temperatures.

Ideal gases' internal energy and enthalpy are solely dependent on temperature; neither volume nor pressure play a role.

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What is Newton's third law of motion?​

Answers

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also exerts an equal and opposite force on object A. In other words, forces result from interactions

Explanation:

Newton’s Third Law: Action & Reaction

Whenever one object exerts a force on a second object, the second object exerts an equal and opposite force on the first.

His third law states that for every action (force) in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also exerts an equal and opposite force on object A. In other words, forces result from interactions.

Examples of action and reaction involving aerodynamics:

   The motion of lift from an airfoil, the air is deflected downward by the airfoil’s action, and in reaction, the wing is pushed upward.    The motion of a spinning ball, the air is deflected to one side, and the ball reacts by moving in the opposite    The motion of a jet engine produces thrust and hot exhaust gases flow out the back of the engine, and a thrusting force is produced in the opposite direction

----------------

HOPE THIS HELPS <3

Answer :

Newton's Third law of motion states :

" Every action has an equal and opposite reaction "

i.e If a force is applied by an object A on another object B then that object B also exerts a foce on object A, that is of same magnitude and opposite direction to the force applied by object A.

Ex - A book on a table exerts gravitational force on the table and table exerts back a normal force on the book.

A cannonball is shot horizontally off a 10.5 m high castle wall at 47.4 m/s. How far from the base of the wall does the cannonball land?

Answers

Answer:

69.8 m  (nearest tenth)

Explanation:

Constant Acceleration Equations (SUVAT)

[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Consider the horizontal and vertical motion of the projectile separately.

Resolving vertically

As the projectile is fired horizontally, the vertical component of its initial velocity is zero.

Acceleration due to gravity = 9.8 ms⁻²

Resolving vertically, taking ↓ as positive:

[tex]s=10.5 \quad u=0 \quad a=9.8[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s&=ut+\dfrac{1}{2}at^2:\\\\10.5&=(0)t+\dfrac{1}{2}(9.8)t^2\\10.5&=4.9t^2\\t^2&=\dfrac{15}{7}\\t&=\sqrt{\dfrac{15}{7}}\end{aligned}[/tex]

Resolving horizontally

The horizontal component of velocity is constant, as there is no acceleration horizontally.

Resolving horizontally, using the value of t found previously:

[tex]u=47.7 \quad v=47.7 \quad a=0 \quad t=\sqrt{\dfrac{15}{7}}[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s&=ut+\dfrac{1}{2}at^2:\\\\s&=47.7\left(\sqrt{\dfrac{15}{7}}\right)+\dfrac{1}{2}(0)\left(\sqrt{\dfrac{15}{7}}\right)^2\\s&=47.7\left(\sqrt{\dfrac{15}{7}}\right)\\s&=69.82565022...\end{aligned}[/tex]

Therefore, the cannonball lands 69.8 m from the base of the wall.

A 60-kg woman with a density of 980 kg/m^3 stands on a bathroom scale. Determine the reduction of the scale reading due to air. (The answer is 0.774 N)

Answers

Answer:

The woman displaces a volume of air equivalent to her own volume; VV; V=\dfrac{m}{\rho_{\text{woman}}}=\dfrac{60}{980}=0.0612\mathrm{\ m^3}V= ρ woman m = 98060 =0.0612 m 3

Explanation:

What is Inverse Distance Weighting?​

Answers

Answer: LOL Hello! for the third time! the answer is Inverse distance weighting (IDW) is a type of deterministic method for multivariate interpolation with a known scattered set of points. The assigned values to unknown points are calculated with a weighted average of the values available at the known points.

Explanation: ^^ Up there have a good day and hope this helps you!

Question: Hello: ) ✨What is Inverse Distance Weighting?​

Answer: a method of interpolation that estimates cell values by averaging the values of sample data points in the neighborhood of each processing cell. The closer a point is to the center of the cell being estimated, the more influence, or weight, it has in the averaging process.Inverse Distance Weighting (IDW) interpolation estimates unknown values with specifying search distance, closest points, power setting & barriers.”

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a student is calculating the gravitational force between the earth and the sun. she knows that mass of the earth is 5.972 x 10245.972 x 1024 kg, the mass of the sun is 1.989 x 10301.989 x 1030 kg, and the distance between the earth and the sun is 1.496 x 10121.496 x 1012 meters. what piece of information is she missing to be able to find the gravitational force?

Answers

The gravitational force is 3.54 x 10²⁰ N

We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses objects. The magnitude of gravitational force can be determined as

F = G.m1.m2 / R²

where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.

From the question above, we know that

m1 = 5.972 x 10²⁴ kg

m2 = 1.989 x 10³⁰ kg

R = 1.496 x 10¹² m

By substituting the following parameters, we get

F = G.m1.m2 / R²

F = 6.674 × 10¯¹¹  . 5.972 x 10²⁴ . 1.989 x 10³⁰ / (1.496 x 10¹²)²

F = 3.54 x 10²⁰ N

Hence, the gravitational force is 3.54 x 10²⁰ N

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An open rectangular box with volume 8 m3 has a square base. express the surface area sa of the box as a function of the length of a side of the base, x. sa = incorrect: your answer is incorrect. m2

Answers

By rectangular box formula,  the surface area is 8/h

We need to know about rectangular box volume to solve this problem. The volume of the rectangular box can be calculated by multiplying the base area by height. It can be written

V = SA . h

where V is volume, SA is base area and h is height

From the question above, we know that

SA = square

V = 8 m³

Hence, the surface area is

SA = x²

where x is side of the base length

Substitute to rectangular box volume equation

V = SA . h

8 = x².h

h = 8/x²

x = √(8/h) ...... (1)

Substitute (1) to find surface area function

SA = x²

SA = (√(8/h))²

SA = 8/h

Hence, the surface area is 8/h

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neither the operator nor anyone else should ever stand directly in front of the wheel of an abrasive power tool as it accelerates to full operating speed. why? a. because it could throw off remnants of debris from the last job, putting a fragment in someone’s eye b. because if it is not secured tightly enough to the spindle, it could roll off and right into the operator c. because there is always the chance that the wheel wasn’t sound and could disintegrate or explode d. none of the above

Answers

There is always a potential that an abrasive power tool's wheel wasn't sound and may burst or disintegrate, thus neither the operator nor anyone else should ever stand in front of the wheel as it accelerates to full operational speed. So, C is the best choice.

Before mounting, all abrasive wheels must undergo a thorough inspection and ring test to make sure there are no fractures or other flaws. The spindle's grinding wheels must easily fit on it without being pressed in.

The spindle nut should only be tightened enough to secure the wheel. The following are a few recommendations for using abrasive wheels: The spindle end, nut, and flange projection guards on abrasive wheel tools must be covered. Keep the wheel in the right alignment. Never use more force than the fastenings can handle.

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