How can you best use the word protrude in an art related sentence?
A. A shelf protrudes into a wall
B. A gravestone protrudes from the ground.
C. The wires from the computer protrude behind the desk.
D. A lollipop stick protrudes into your mouth.

Answer:

D. 100

Step-by-step explanation:

Mean = Sum of all numbers divided by the count of all numbers

Mean = 50

Let say that the sum of all numbers = X

50 = X / 4

200 = X

X = (20+30+50) + The 4th Value

200 = 100 + 4th Value

The 4th Value = 100

Answer:

  0.772 seconds; 9.228 seconds

Step-by-step explanation:

The given projectile formula with the given numbers filled in is ...

  [tex]\displaystyle h=-16t^2+v_0t+h_0\\\\114=-16t^2+160t[/tex]

We can "complete the square" to solve this for t, the times at which the height is 114 feet.

  16(t² -10t) = -16(7.125) . . . . . rearrange, showing factor of 16

  t² -10t +25 = -7.125 +25 . . . . divide by 16, add 25 to complete the square

  t = 5 ±√17.875 ≈ 5 ± 4.228 . . . . take the square root, add 5

  t ∈ {0.772, 9.228}

The arrow is 114 feet high after 0.772 seconds and again after 9.228 seconds.

Answer:

10 miles

Step-by-step explanation:

He could run 2 miles.

Now he can run 5 times as far.

Now he can run 5 times 2 miles.

5 × 2 miles = 10 miles

The situation IS NOT represented by the tape diagram.

The situation can be represented by the equation:

s + s + s + s + s + 6 = 106

5s + 6 = 106

5s = 106 - 6

5s = 100

s = 100/5

s = 20

Therefore, the amount Noah earned each time he walked the dog is $20

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#1

Paved area:-

#b

Let's see

Answer:

(a)  121 miles

(b)  7 days

Step-by-step explanation:

Given function:

[tex]\sf L(d)=205-7d[/tex]

Question (a)

When d = 12:

[tex]\sf \implies L(12)=205-7(12)[/tex]

                [tex]\sf =205-84[/tex]

                [tex]\sf =121 \ miles[/tex]

Therefore, the crew has 121 miles left to pave after 12 days.

Question (b)

When L(d) = 156

[tex]\sf \implies 156=205-7d[/tex]

[tex]\sf \implies 7d=205-156[/tex]

[tex]\sf \implies 7d=49[/tex]

[tex]\sf \implies d=\pm\sqrt{49}[/tex]

[tex]\sf \implies d=\pm7[/tex]

As distance is positive, [tex]\sf d=7[/tex] only

Therefore, the crew has been paving the the road for 7 days.

Answer:

A=lw+l(w

2)2+h2+w(l

2)2+h2=30·20+30·(20

2)2+282+20·(30

2)2+282≈2127.25933

Your answer is 2127.259

I think it will help you

If "s" represents the slant height in the rectangular pyramid with dimensions l = 30, w = 20, and h = 28, then the length of "s" is approximately 29.75 units.

To find the length of "s" in the rectangular pyramid, we first need to understand the terminology used to describe the different dimensions of a pyramid.

In a rectangular pyramid, "l" usually represents the length of the base, "w" represents the width of the base, and "h" represents the height of the pyramid (the perpendicular distance from the base to the apex or top vertex of the pyramid).

However, there is no standard notation for the length of the slant height (s) in a rectangular pyramid. In this context, the term "s" could represent either the slant height or some other unknown dimension of the pyramid.

If "s" represents the slant height of the pyramid, we can use the Pythagorean theorem to find its value. The slant height, "s," is the hypotenuse of a right triangle formed by one of the triangular faces of the pyramid and the height and half the width of the base.

Using the given dimensions:

l = 30 (length of the base)

w = 20 (width of the base)

h = 28 (height of the pyramid)

Let's find the value of "s" using the Pythagorean theorem:

[tex]s^2 = h^2 + (w/2)^2\\s^2 = 28^2 + (20/2)^2\\s^2 = 28^2 + 10^2\\s^2 = 784 + 100\\s^2 = 884\\[/tex]

Now, take the square root of both sides to find the value of "s":

s ≈ √884

s ≈ 29.75 (rounded to two decimal places)

So, if "s" represents the slant height in the rectangular pyramid with dimensions l = 30, w = 20, and h = 28, then the length of "s" is approximately 29.75 units.

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Answer:

3.64% (when rounded to the nearest hundredth)

Step-by-step explanation:

I'm assuming by 5700 you actually mean 57,000.

Calculate the percent change:

(57,000-55,000)/55,000 *100

(2000/55000)x100

0.036363x100

3.6363 rounded to the nearest hundredth is 3.64

[tex]\sf\large\underline{Given:-}[/tex]

Speed of the train = 20km / 1hr.

[tex]\rightarrow[/tex] 1 hour = 60 minutes.

So, speed of the train = 20km/60min.

[tex]\sf\large\underline{To\: Find:-}[/tex]

[tex]\rightarrow[/tex]Distance covered by train in 1min.

[tex]\sf\large\underline{Solution:-}[/tex]

Let the distance covered by train in 1 min be [tex]\sf{x}[/tex] m.

So, if train covers 20 km in 60min then it covers [tex]\sf{x}[/tex] m in 1 min.

It can be written as,

[tex]\rightarrow[/tex] [tex]\sf{\frac{20}{60}}[/tex] [tex]\sf{=\frac{x}{1}}[/tex](by cross multiplication)

[tex]\rightarrow[/tex][tex]\sf{20\: = \: 60x}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{\frac{20}{60}= x}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{\frac{1}{3}= x}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{0.33= x}[/tex](approx)

Therefore, distance covered by train in 1 min= 0.33km (approx).

_______________________________

Hope it helps you:)

Step-by-step explanation:

hope it helps, I have chegg and they seem to have more answers and a lot of topics. you can scan your books bar code and get end of chapter questions

Answer:

9

Step-by-step explanation:

He would need to by 9 boxes. There might be some left over pencils.

The value of x determined algebraically given the total area of the rectangle is 1.5 inches

Initial dimensions:

Length = 14 inches

Width = 10 inches

New dimensions:

Length = 14 + x

Width = 10 + x

Area = 320 square inches

Area of a rectangle = Length × Width

320 = (14 + x) × (10 + x)

320 = 14x × 10x

320 = 140x²

x² = 320/140

x² = 2.28571428571428

x = √2.28571428571428

x = 1.511857892036908908858066144936720243

Approximately,

x = 1.5

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Answer:

85 dogs have signed up to compete

Step-by-step explanation:

its 85 small dogs because 49+36=85

The computation of the equation illustrates that the number will be 46.4.

Let the number be represented as x.

Therefore, the the difference of 3 / 4 and 1 / 6 of a number is 7 will be computed as follows:

(1/6 × x) - 3/4 = 7

0.167x = 7 + 3/4

0.167x = 7.75

x = 7.75/0.167

x = 46.4

Therefore, the number is 46.4.

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Answer:

no

Step-by-step explanation:

because mindy has already saved $20 and is putting $8 which is more than the amount georgette is putting (monthly) and plus georgette has no money saved so basically mindy will have more money saved

The faster speed is the cruising speed on the flight from Philadelphia to Barcelona.

Average speed is the total distance travelled per time. It is used to determine how fast an object is moving with respect to time.

Average speed = total distance / total time

Average speed on the flight back home = 530 / 1 = 530 mph

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Answer:

135 square yards

Step-by-step explanation:

9 yd   *   15 yd   =  (9 * 15) yd^2 = 135 yd^2

Answer:

B. 3

Step-by-step explanation:

we know 2x3 = 6 soo just add 2 zeros = 600

Answer:

Your answer is D, 11

Step-by-step explanation:

PEMDAS, first you divide, 21/3 is 7

7+8 is 15

15 - 4 is 11

Hope this helps! :)

Answer:

[tex]\boxed{\sf{11}}[/tex]

Step-by-step explanation:

Solving this problem requires an order of operations.

PEMDAS stands for:

First, divide.

[tex]\sf{21\div3+8-4}[/tex]

[tex]\sf{21\div3=7}[/tex]

Then rewrite the problem.

[tex]\sf{7+8-4}[/tex]

Add.

[tex]\sf{7+8=15}[/tex]

Subtract.

[tex]\sf{15-4=\boxed{\sf{11}}[/tex]

11

Therefore, the correct answer is 11.

I hope this helps you! Let me know if my answer is wrong or not.

Answer: x=20

Step-by-step explanation:

(6x-10)=(3x+50) (subtract both sides by 3x)

3x-10=50(add ten to both sides)

3x=60(divide both sides by 3)

x=20

Answer:

1/8

Step-by-step explanation:

Answer:

8(x+4)=3

Step-by-step explanation:

the answer is this!

Answer: 64 inches

Step-by-step explanation:

The distance between two cars comes to be 4412.06 feet.

Find the attached diagram to visualize it better.

From the attached diagram

The Distance between two cars is x+y

The angle of elevation for the first car = 22 degrees

The angle of elevation for the second car = 65 degrees.

Height of the Goodyear blimp = 1500 feet

The tangent of an angle is the ratio of the opposite side to the adjacent side of that angle.

So, tan 22° = 1500/x

So, x= 1500/tan 22°

x = 3712.63 feet

tan 65° = 1500/y

So, y = 1500/tan 65°

y = 699.46 feet

x+y = 4412.06 feet

So, the distance between two cars =  4412.06 feet

Therefore, the distance between two cars comes to be 4412.06 feet.

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Answer:

D

Step-by-step explanation:

When you look for (f+g)(x), we are in essence say that we're looking for f(x)+g(x)

=(2x+1)+(x^2-7).        (substitute for f(x) and g(x))

=2x+1+x^2-7.            (remove the brackets by substituting positive 1 into g(x))

=2x+x^2-6                (add like terms- in this case 1-7=6)

=x^2+2x-6                 (rearrange the equation)

The rate of interest required to achieve the conditions set forth is 7.1773%.

The interest rate is the rate at which the investment increases. The formula that can be used to determine interest rate is:

g = (FV / PV)^(1/N) - 1

Where:

4^(1/20) - 1 = 7.1773%

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Answers are in bold

S1 = 1

S2 = 0.5

S3 = 0.6667

S4 = 0.625

S5 = 0.6333

=========================================================

Explanation:

Let [tex]f(n) = \frac{(-1)^{n+1}}{n!}[/tex]

The summation given to us represents the following

[tex]\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=\sum_{n=1}^{\infty} f(n)\\\\\\\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=f(1) + f(2)+f(3)+\ldots\\\\[/tex]

There are infinitely many terms to be added.

-------------------

The partial sums only care about adding a finite amount of terms.

The partial sum [tex]S_1[/tex] is the sum of the first term and nothing else. Technically it's not really a sum because it doesn't have any other thing to add to. So we simply say [tex]S_1 = f(1) = 1[/tex]

I'm skipping the steps to compute f(1) since you already have done so.

-------------------

The second partial sum is when things get a bit more interesting.

We add the first two terms.

[tex]S_2 = f(1)+f(2)\\\\S_2 = 1+(-\frac{1}{2})\\\\S_2 = \frac{1}{2}\\\\S_2 = 0.5\\\\\\[/tex]

The scratch work for computing f(2) is shown in the diagram below.

-------------------

We do the same type of steps for the third partial sum.

[tex]S_3 = f(1)+f(2)+f(3)\\\\S_3 = 1+(-\frac{1}{2})+\frac{1}{6}\\\\S_3 = \frac{2}{3}\\\\S_3 \approx 0.6667\\\\\\[/tex]

The scratch work for computing f(3) is shown in the diagram below.

-------------------

Now add the first four terms to get the fourth partial sum.

[tex]S_4 = f(1)+f(2)+f(3)+f(4)\\\\S_4 = 1+(-\frac{1}{2})+\frac{1}{6}-\frac{1}{24}\\\\S_4 = \frac{5}{8}\\\\S_4 \approx 0.625\\\\\\[/tex]

As before, the scratch work for f(4) is shown below.

I'm sure you can notice by now, but the partial sums are recursive. Each new partial sum builds upon what is already added up so far.

This means something like [tex]S_3 = S_2 + f(3)[/tex] and [tex]S_4 = S_3 + f(4)[/tex]

In general, [tex]S_{n+1} = S_{n} + f(n+1)[/tex] so you don't have to add up all the first n terms. Simply add the last term to the previous partial sum.

-------------------

Let's use that recursive trick to find [tex]S_5[/tex]

[tex]S_5 = [f(1)+f(2)+f(3)+f(4)]+f(5)\\\\S_5 = S_4 + f(5)\\\\S_5 = \frac{5}{8} + \frac{1}{120}\\\\S_5 = \frac{19}{30}\\\\S_5 \approx 0.6333[/tex]

The scratch work for f(5) is shown below.

Volume:-