How do I deposit more money into my bank account

Answers

Answer 1
Answer:

When you deposit cash at a bank or credit union, you typically need to use a deposit slip. That's simply a slip of paper that tells the teller where to put the money. Write your name and account number on the deposit slip (deposit slips are usually available at the lobby or drive-throug).


Related Questions

If Bill hiked 6.5 miles at a rate of 10.4 mph, how long did it take him to complete his hike?

Answers

Answer:

I think it depends how far bill wants to hike..

Step-by-step explanation:

Took him 0.625 hours
OR
37 minutes and 30 seconds

What is the expanded form of 8,609?
A 8,000+600+ 90
8,000+60+9
8,000 +900+ 6
8,000+600 +9

Answers

The last one 8,000 + 600 + 9

It’s the last one 8,000+600+9

pls help me loves :((

Answers

Answer:

609 m²

Step-by-step explanation:

Area of unshaded:

(6 x 18) + ((13-6) x 7) = 157

Area of overall rectangle:

36 x 28 = 1008

Area of the chunck of rectangle not included:

11 x 22 = 242

Area of shaded:

1008 - 157 - 242 = 609

Please help soon- The weight of oranges growing in an orchard is normally distributed with a mean
weight of 6 oz. and a standard deviation of 1 oz. From a batch of 2500 oranges, how
many would be expected to weight less than 4 oz., to the nearest whole number?

Answers

5 oz. Hope this helped!

Can someone help me please?

Answers

Slope : -2

y - intercept : 3

Equation : y = -2x+3

Answer:

Step-by-step explanation:

Slope: -0.5

Y-Intercept: 3

y = -0.5x+3

I need this please help me

Answers

Answer:

A. Right 6, Down 5

Step-by-step explanation:

I don't know how to explain this

Find the exact value of sin A in simplest radical form.

Answers

Using the sine rule,

[tex] \frac{a}{sin(a)} = \frac{b}{sin(b)} = \frac{c}{sin(c)} [/tex]

Here we are going to use the values of A and C,

[tex] \frac{12}{sin(a)} = \frac{14}{sin(90)} \\ \frac{12}{sin(a)} = \frac{14}{1} \\ sin(a) = 12 \div 14 \\ sin(a) = 0.8571[/tex]

So sin(A) = 12/14 = 6/7 = 0.8571, but since the question says in its simplest radical form, I think the closest answer to it should be

[tex] \frac{ \sqrt{3} }{2} [/tex]

Find the perimeter of a rectangle with a base of 12 ft and a height of 5 ft.

Answers

Answer:

P=34ft

Step-by-step explanation:

Solution

P=2(l+w)=2·(12+5)=34ft

can someone help me :(

Answers

Answer:

A is the correct answer

.......................

Answer:

A. y+116+30=180

Step-by-step explanation:

A straight angle is 180°.

all the given angles make up a straight angle, so they add to 180°.

Is the line a good fit for the data points plotted in the scatter plot below?

Answers

It would be A. Because the line is close to the points which makes it a good fit!

Type the integer in the box.
Solve:: t/2 + 10 =-40

Answers

Answer:

t = -100

Step-by-step explanation:

Simplify to isolate t:

[tex]\frac{t}{2}+10-10=-40-10[/tex]

[tex]\frac{t}{2} * \frac{2}{1} = -50 * 2[/tex]

[tex]t = -100[/tex]

What is the volume of a sphere with a radius of 3.1 cm, rounded to the nearest tenth
of a cubic centimeter?

Answers

The answer is 124.79 centimeters
Rounded to the nearest tenth It’s 124.8

How much is three times two

Answers

Answer:

the answer is 6.

Step-by-step explanation:

Answer:

6.

Step-by-step explanation:

3+3=6 = 2×3=6

you can do draw 3 circles 2 times and add it all together.


There are 50 pennies in a roll. If you have 150 rolls of pennies, how many pennies do you have?

Answers

Answer: 7500

Step-by-step explanation:

multiply 150 by 50

Identify a second of transformations that maps triangle ABC onto triangle A"B"C in the image below.

Answers

Answer: The answer is B because the triangle rotated a 90 degrees counterclockwise then got a reduction.

Step-by-step explanation:

which best describes a rectangle with diagonals that are perpendicular

Answers

Answer: If a parallelogram has diagonals that are perpendicular, it is a rhombus. … This definition can also be stated as: A square is a quadrilateral that is also a rectangle and a rhombus.

Step-by-step explanation:

Simran has a bag containing white and yellow marbles. Simran randomly selects one marble from the bag,

records the result, and returns the marble to the bag. The results of the first 65 selections are shown below.

A white marble was selected 41 times.

A yellow marble was selected 24 times.

Based on these results, what is the probability that the next marble Simran selects, rounded to the nearest

Answers

Answer:

d. 63%

Step-by-step explanation:

percent, will be white?

A41% b50% c59% d63%

The probability of white = P (w) = 41/65= 0.63

The  probability of yellow = P (y)= 24/65= 0.369=0.37

The probability of choosing white is 0.63 . When rounded to  nearest percent gives

0.63*100/100

=0.63*100 percent

= 63 percent

= 63%

the probability of getting   the next marble white is the same as the probability of getting a white.

Find the area of the triangle

Answers

Answer:

About 292.72

Step-by-step explanation:

We can imagine a circle circumscribed around the triangle, then solve it as we normally do using the apothem. By dividing 360 by the number of sides (3) we know that the central angle constructed by the apothem and radiuses would be 120. Divided by 2 (because we are using a right triangle to solve it) is 60. Now with this you can either use trig ratios (sin, cos, or tan) or use special right triangles (30-60-90 or 45-45-90). I used special rights. With this I know my apothem is [tex]\frac{13\sqrt{3} }{3}[/tex]. Perimeter is 26 times 3 which is 78. The formula for area of regular polygons is 1/2(perimeter times apothem). When we plug our values in the answer is about 292.72. You are lucky that I just had my test on this, I hope it helps.

Here is my work since this is very visual for me:

The scale on a map is 55 cm : 88 km.

If the distance between two cities is 5656 km, how far apart in cm are the two cities on the map?

Answers

Answer:

look at the picture i have sent

Answer:

The cities are 35 cm apart in map.

The scale on a map is 5 cm : 8 km.

Step-by-step explanation:

mrk me brainliest please

The times that a cashier spends processing individual customers' orders are independent random variables with mean 3.5 minutes and standard deviation 3 minutes. Find the number of customers n such that the probability that the orders of all n customers can be processed in less than 2 hours, is approximately 0.1. (Round your answer to the nearest integer.)

Answers

Answer:

26 customers

Step-by-step explanation:

First:  determine the z score from standard normal probability table with an indicative area of 0.1

Z-score from probability table  = - 1.28

mean   = 3.5 minutes

std  = 3 minutes

next determine the Z-score based on the information given in the question

Z = ( std -  mean )  / processing time

  = ( 3 - 3.5 ) / 2 = -0.25

Finally determine the number of customers

N = [tex](\frac{-1.28}{-0.25} )^2[/tex]  = 1.6384 / 0.0625 = 26.21 ≈ 26 customers  

5% equals what fraction, in lowest terms?

Answers

Answer:

1/20

Step-by-step explanation:

According to G0ogle 5 percent equals 1/20 in lowest terms.

Answer:

5% equals 5/100 which is 1/20 in lowest terms.

Step-by-step explanation:

5% is basically equivalent to 5/100. 5/100 in lowest terms is 1/20 since you divide the numerator and denominator by 5.

I hope this helps, have a nice day.

PLSSSSSSSSSSS ASAP!!!!! Find the area of the figure shown below.

Answers

Answer:

54 square ft

Step-by-step explanation:

Find missing sides:

8+6 = 14

9-6 = 3

Find area of full rectangle:

9×8 = 72

Find the area of the missing part of the full rectangle

3×6 = 18

Find the area of the actual shape:

72-18 = 54

Area = 54 square ft

1+1 why does my dog not love me?

Answers

Answer:

2

Step-by-step explanation:

your dog doesn't love you because it saw what you did. it knows. be cautious around your dog from now on. it knows more than you think and sees all. I'm warning you

The scatter chart below displays the residuals verses the dependent variable, x. Which of the following conclusions can be drawn based upon this scatter chart? a. The residuals are normally distributed. b. The model over predicts the value of the dependent variable for small values and large values of the independent variable. c. The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship. d. The residuals have a constant variance.

Answers

Answer: Hello the scatter plot related to your question is missing attached below is the scatter plot

answer :  The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship ( C )

Step-by-step explanation:

The conclusion that can be drawn based upon the scatter chart is that The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship

A scatter plot helps in observing the relationship within different numeric variables but the scatter plot attached fails in the showing the actual relationship

a cylinder has a diameter of 12 and height of 12. the volume of the cylinder is:

A. 1728π cubic units
B. 288π cubic units
C. 144π cubic units
D. 432π cubic units

Answers

D which means you add 12 plus 12

Mona has a bag containing 4 red marbles, 12 green marbles, and 8 black marbles. Without looking, she pulls out one marble from the bag and places it in an empty jar. She then pulls a second marble from the bag and places it in the jar. WHat is the probability that she will have 2 green marbles in the jar?


A. 12/24 x 11/23

B. 12/24 x 12/24

C. 1/12 x 1/11

D. 12/24 x 12/23​

Answers

Answer is b hope this helps

Caroline has a rock stuck in her Jeep’s tire

Answers

Answer:

oh no

Step-by-step explanation:

sorry about that I guess

Consider the initial value problem my''+cy'+ky=F(t), y(0)=0, y'(0)=0, modeling the motion of a spring mass dashpot system initially at rest and subjected to an applied force F(t), where the unit of force is the Newton (N). Assume that m=2 kilograms, c=8 kilograms per second, k=80 Newtons per meter, and F(t)=20 sin(6t) Newtons.
1. Solve the initial value problem. y(t)=?
2. Determine the long term behavior of the system. Is lim as t goes to infinity of y(t)=0? If it is, enter zero. If not, enter a function that approximates y(t) for very large positive values of t. For very large positive values of t, y(t) is approximately.. ?

Answers

Answer:

Hence, the [tex]y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t))\end{array}[/tex] and approximately value of [tex]y(t)[/tex] is [tex]-0.844[/tex].

Given :

 [tex]my''+cy'+ky=F(t), y(0)=0, y'(0)=0,[/tex]

Where  [tex]m=2[/tex] kilograms

           [tex]c=8[/tex] kilograms per second

           [tex]k=80[/tex] Newtons per meter

          [tex]F(t)=20\sin (6t)[/tex] Newtons

Explanation :

(1)

Solve the initial value problem. [tex]y(t)[/tex]

   [tex]my''+cy'+ky=F(t), y(0)=0, y'(0)=0,[/tex]

[tex]\Rightarrow 2y''+8y'+80y=20\sin (6t)[/tex]

[tex]\Rightarrow y''+4y'+40y=10\sin (6t)[/tex]

Auxilary equations :[tex]F(t)=0[/tex]

[tex]\Rightarrow r^2+4r+40=0[/tex]

[tex]\Rightarrow r=\frac{-4\pm\sqrt{4^2-4\times 1\times 40}}{2\times 1}[/tex]

[tex]\Rightarrow r=\frac{-4\pm\sqrt{16-160}}{2}[/tex]

[tex]\Rightarrow r=\frac{-4\pm\sqrt{-144}}{2}[/tex]

[tex]\Rightarrow r=\frac{-4\pm12i}{2}[/tex]

[tex]\Rightarrow r=-2\pm6i[/tex]

The complementary solution is [tex]y_c=e^{-2t}\left(c_1\cos 6t+c_2\sin 6t\right)[/tex]

The particular Integral, [tex]y_p=\frac{1}{f(D)}F(t)[/tex]

[tex]y_{y} &=\frac{1}{D^{2}+4 D+40} 25 \sin (6 t) \\\\ y_{y} &=\frac{25}{-6^{2}+4 D+40} \sin (6 t) \quad\left(D^{2} \text { is replaced with }-6^{2}=-36\right) \\\\y_{y} &=\frac{25}{4 D+4} \sin (6 t) \\\\y_{y} &=\frac{25}{4(D+1)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4(D+1)(D-1)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4\left(D^{2}-1\right)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4(-36-1)} \sin (6 t) \\\\y_{y} &=-\frac{25}{148}(D-1) \sin (6 t) \\y_{y} &=-\frac{25}{148}\left(\frac{d}{d t} \sin (6 t)-\sin (6[/tex]

Hence the general solution is :[tex]y=y_c+y_p=e^{-2t}(c_1\cos 6t+c_2\sin 6t)-\frac{25}{148}(6\cos 6t-\sin 6t)[/tex]

Now we use given initial condition.

[tex]y(t) &=e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\\y(0) &=e^{-\alpha 0)}\left(c_{1} \cos (0)+c_{2} \sin (0)\right)-\frac{25}{148}(6 \cos (0)-\sin (0)) \\\\0 &=\left(c_{1}\right)-\frac{25}{148}(6) \\\\c_{1} &=\frac{75}{74} \\\\y(t) &=e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\[/tex]

[tex]y^{\prime}(t)=-2 e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)+e^{-2 t}\left(-6 c_{1} \sin 6 t+6 c_{2} \cos 6 t\right)-\frac{25}{148}(-36 \sin (6 t)-6 \cos (6 t)) \\\\y^{\prime}(0)=-2 e^{0}\left(c_{1} \cos 0+c_{2} \sin 0\right)+e^{0}\left(-6 c_{1} \sin 0+6 c_{2} \cos 0\right)-\frac{25}{148}(-36 \sin 0-6 \cos 0) \\\\0=-2\left(c_{1}\right)+\left(6 c_{2}\right)-\frac{25}{148}(-6) \\\\0=-2 c_{1}+6 c_{2}+\frac{75}{74} \\\\0=-2\left(\frac{75}{74}\right)+6 c_{2}+\frac{75}{74} \\\\[/tex][tex]\begin{array}{l}0=-\frac{150}{74}+6 c_{2}+\frac{75}{74} \\\\\frac{150}{74}-\frac{75}{74}=6 c_{2}\end{array}[/tex]

[tex]\begin{array}{l}c_{2}=\frac{25}{148}\\\\\text { Substitute } c_{1} \text { and } c_{2} \text { in } y(t) \text { . Then }\\\\y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t))\end{array}[/tex]

(2)

[tex]y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\y(t)=\left(\frac{75}{74} e^{-2 t} \cos 6 t+\frac{75}{148} e^{-2 t} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\y(t)=\frac{75}{74}\left(e^{-2 t}-1\right) \cos 6 t+\frac{25}{148}\left(3 e^{-2 t}+1\right) \sin 6 t \\\\|y(t)| \leq \frac{75}{74} e^{-2 t}-1|\cos 6 t|+\frac{25}{148}\left|3 e^{-2 t}+1\right||\sin 6 t| \\\\[/tex]

[tex]|y(t)| \leq \frac{75}{74}\left|e^{-2 t}-1\right|+\frac{25}{148}\left|3 e^{-2 t}+1\right| \\\\\lim _{t \rightarrow \infty} y(t) \leq \lim _{t \rightarrow \infty}\left\{\frac{75}{74}\left|e^{-2 t}-1\right|+\frac{25}{148}\left|3 e^{-2 t}+1\right|\right\} \\\\\lim _{t \rightarrow \infty} y(t)=\left\{\frac{75}{74}\left|\lim _{t \rightarrow \infty}\left(e^{-2 t}-1\right)\right|+\frac{25}{148}\left|\lim _{t \rightarrow \infty}\left(3 e^{-2 t}+1\right)\right|\right\} \\[/tex]

[tex]\lim _{t \rightarrow \infty} y(t)=\left\{\frac{75}{74}(-1)+\frac{25}{148}(1)\right\}=-\frac{75}{74}+\frac{25}{148}=-\frac{-150+25}{148}=-\frac{125}{148} \approx-0.844[/tex]

PLEASE HELP FAST WILL MARK BRAINLIEST PLEASEEE

Answers

Answer:

[tex]\frac{8x^{18} }{y^{2} }[/tex]

Step-by-step explanation:

Which statement describes whether the function is continuous at x = 2?
O The function is continuous at x = 2 because f(2) exists.
O The function is continuous at x = 2 because lim f(x) exists.
X-2
The function is not continuous at x = 2 because f(2) does not exist.
The function is not continuous at x = 2 because lim f(x) does not equal f(2).
X-2

Answers

Answer: (b)

Step-by-step explanation:

Given

The function is given as

[tex]f(x)=\dfrac{x^2-12x+20}{x-2}[/tex]

Solving the function

[tex]f(x)=\dfrac{x^2-2x-10x+20}{x-2}\\\\f(x)=\dfrac{(x-2)(x-10)}{(x-2)}\\\\f(x)=x-10[/tex]

for [tex]x=2[/tex]

[tex]f(2)=2-10\\f(2)=-8[/tex]

The function is continuous at [tex]x=2[/tex] because [tex]\lim_{x \to 2} f(x)[/tex] exists.

If the limit exists at a point, then the function is continuous.  

Answer:

on edge its fs not b or c

Step-by-step explanation:

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