how do I find the perimeter of a quadrilateral on a graph?

Answers

Answer 1

The perimeter of a figure is always the sum of the lengths of the sides.

If we have the coordinates of the vertices of the quadrilateral, we can calculate the length of each side as the distance between the vertices.

For example, the length of a side AB will be the distance between the points A and B:

[tex]d=\sqrt[]{(x_b-x_a)^2+\mleft(y_b-y_a\mright)^2}[/tex]

Adding the length of the four sides will give the perimeter of the quadrilateral.


Related Questions

First use the Pythagorean theorem to find the exact length of the missing side. Then find the exact values of the six trigonometric functions for angle 0.

Answers

The trigonometric functions are given by the following formulas:

[tex]\begin{gathered} \sin \theta=\frac{a}{h} \\ \cos \theta=\frac{b}{h} \\ \tan \theta=\frac{a}{b} \\ \cot \theta=\frac{b}{a} \\ \sec \theta=\frac{h}{b} \\ \csc \theta=\frac{h}{a} \end{gathered}[/tex]

Where we call a to the opposite leg to the angle θ (the side whose measure equals 20), b is the adjacent leg to angle θ (the side whose measure equals 21) and we call h to the hypotenuse (the larger side, whose measure equals 29).

By replacing 20 for a, 21 for b and 29 for h into the above formulas, we get:

[tex]\begin{gathered} \sin \theta=\frac{20}{29} \\ \cos \theta=\frac{21}{29} \\ \tan \theta=\frac{20}{21} \\ \csc \theta=\frac{29}{20} \\ \sec \theta=\frac{29}{21} \\ \cot \theta=\frac{21}{20} \end{gathered}[/tex]

An athlete runs at a speed of 9 miles per hour. If one lap is 349 yards, how many laps does he run in 22 minutes

Answers

The athlete will cover 17 yards in 22 minutes of his running.

What is unitary method?

The unitary method is a method in which you find the value of a single unit and then the value of a required number of units.

Given is an athlete who runs at a speed of 9 miles per hour and one lap is 349 yards.

We will use the unit conversions to solve the given problem.

The speed of the athlete is 9 mph. We can write it as -

9 mph = (9 x 1760) yards per hour = 15840 yards per hour.

15840 yards per hour = (15840/60) yards per minute = 264 yards per min.

Total yards covered in 22 minutes = 22 x 264 = 5808 yards

one lap is equivalent to 349 yards.

1 yard is equivalent to (1/349) laps

5808 yards are equivalent to (5808/349) or 16.6 yards or approximately 17 yards.

Therefore, the athlete will cover 17 yards in 22 minutes of his running.

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8) Remus earns $.15 per unit for the work he does. For all units heproduces in a week, over 1,000, he receives $.20. What were his weeklyearnings if he produced 1,420 units?

Answers

You have the following information:

- Remus earns $.15 per unit

- For units he produced over 1,000 he receives $.20

- He produced 1,420 units

In order to determine what were the weekly earnings, you first take into account the earnings for the first 1,000 units:

0.15 x 1,000 = 150

Next, you calculate the earnings for the units over 1,000, which are 420:

0.20 x 420 = 84

Next, you sum both contributions:

150 + 84 = 234

Hence, the weekly earning os Ramus were of $234

Can You Teach Me How To Multiple Fractions ?

Answers

Let's suppose we are given two fractions:

[tex]\frac{a}{b},\frac{c}{d}[/tex]

In order to multiply them we simply multiply the numerators and denominators, like this:

[tex]\frac{a}{b}\times\frac{c}{d}=\frac{a\times c}{b\times d}[/tex]

For example, let's say we are given the following fractions:

[tex]\frac{1}{2},\frac{3}{5}[/tex]

We can multiply them following the previous rule:

[tex]\frac{1}{2}\times\frac{3}{5}=\frac{1\times3}{2\times5}=\frac{3}{10}[/tex]

Solve the system of linear equations by substitution:x - y = -2 and 3x - y = 2

Answers

To solve the system by substitution, isolate one variable from one equation and substitute the expression obtained for that variable into the other equation.

[tex]\begin{gathered} x-y=-2 \\ 3x-y=2 \end{gathered}[/tex]

Isolate x from the first equation:

[tex]\begin{gathered} x-y=-2 \\ \Rightarrow x=y-2 \end{gathered}[/tex]

Substitute x=y-2 into the second equation:

[tex]\begin{gathered} 3x-y=2 \\ \Rightarrow3(y-2)-y=2 \end{gathered}[/tex]

Solve for y:

[tex]\begin{gathered} \Rightarrow3y-6-y=2 \\ \Rightarrow2y-6=2 \\ \Rightarrow2y=2+6 \\ \Rightarrow2y=8 \\ \Rightarrow y=\frac{8}{2} \\ \Rightarrow y=4 \end{gathered}[/tex]

Substitute y=4 into the expression of x to find its value:

[tex]\begin{gathered} x=y-2 \\ \Rightarrow x=4-2 \\ \Rightarrow x=2 \end{gathered}[/tex]

Therefore, the solution to the given system is:

[tex]\begin{gathered} x=2 \\ y=4 \end{gathered}[/tex]

Which of the following is not a valid way of starting the process of factoring60x² +84x +49?Choose the inappropriate beginning below.O A. (x )(60)OB. (2x (30%)O C. (6x X10x)OD. (2x (5x )

Answers

Given the equation:

60x^2 + 84x + 49

We are to determine among the options which is not a process of factorizing.

In factorizing, you get factors of the given numbers of the equation that when they are being multiplied or added, they give the numbers in the equation.

So, looking at the options, the only option that does not satisfies the requirement for starting a factorization process is B, which is (2x (30%)

Therefore, the inappropriate process of starting factorization among the option is option B which is (2x (30%).

write an equation in slope -intercept form for the line with y- intercept -1 and slope -3/2

Answers

The line equation in the slope -intercept form can be written as,

[tex]y=mx+b[/tex]

Here, m is the slope and b is the y intercept.

Given,

m = -3/2 and b = -1, therefore we can write the equation as,

[tex]y=-\frac{3}{2}x-1[/tex]

The equation is, y =(-3/2)x-1.

What’s the correct answer answer asap for brainlist please

Answers

Answer:

A.it can't be endeavor.

What is the value of x if x + 15 = 38 ? Enter answer below

Answers

x=23

1) Evaluating x +15=38

x +15=38 Subtract 15 from both sides

x+15-15 = 38 -15

x=23

2) So the quantity of x = 23

x=23

1) Evaluating x +15=38

x +15=38 Subtract 15 from both sides

x+15-15 = 38 -15

x=23

2) So the quantity of x = 23

Simplify 6+ √-80.
06+16√5i
06+4√5
06+16/ √5
06+4√ √5i

Answers

Answer:

6 + 4[tex]\sqrt{5}[/tex]i

Step-by-step explanation:

The prime factorization of 80 is 2x2x2x2x5

6 + [tex]\sqrt{-2x2x2x2x5}[/tex]  We can take out 2 pairs of 2 which would be 4 and [tex]\sqrt{-1}[/tex] is i

6 + 4[tex]\sqrt{5}[/tex] i

F(x)=x+1 and g(x)=x^3 -1Find (fg)(5)

Answers

Solution

[tex](fg)(x)=f(x)\times g(x)[/tex]

So

[tex]\begin{gathered} f(5)=5+1=6 \\ g(5)=5^3-1=125-1=124 \end{gathered}[/tex]

and

[tex]\begin{gathered} (fg)(5)=f(5)\times g(5) \\ (fg)(5)=6\times124=744 \end{gathered}[/tex]

Answer: (fg)(5) = 744

Type the correct answer in each box use numerals instead of words What are the values of the function

Answers

Given the following function:

[tex]h(x)=\begin{cases}{3x-4;x<0} \\ {2x^2-3x+10;0\leq x<4} \\ {2^x};x\ge4\end{cases}[/tex]

We will find the value of the function when x = 0 and when x = 4

First, when x = 0, the function will be equal to the second deifinition

So, h(0) will be as follows:

[tex]h(0)=2(0)^2-3(0)+10=10[/tex]

Second, when x = 4, the function will be equal to the third definition

So, h(4) will be as follows:

[tex]h(4)=2^4=16[/tex]

So, the answer will be:

[tex]\begin{gathered} h(0)=10 \\ h(4)=16 \end{gathered}[/tex]

Find the y-coordinate of point P that lies 1/3 along segment CD, closer to C, where C (6, -5) and D (-3, 4).

Answers

SOLUTION:

The given ratio is:

[tex]1:3[/tex]

• The given points are ,C(6, -5) and D (-3, 4).

Using the section formula, the coordinate of P is:

[tex]\begin{gathered} P=(\frac{1(-3)+3(6)}{1+3},\frac{1(4)+3(-5)}{1+3}) \\ P=(\frac{-3+18}{4},\frac{4-15}{4}) \\ P=(\frac{15}{4},\frac{-11}{4}) \end{gathered}[/tex]

Therefore the coordiantes of P

[tex]P=(\frac{15}{4},\frac{-11}{4})[/tex]

An extrasolar planet is observed at a distance of 4.2 x 10° kilometers away. A group of scientists has designed a spaceship that can travel at the speed of 7 x 108 kilometers per year. How many years will the spaceship take to reach the extrasolar planet?

Answers

Speed is the time rate at which an object is moving along a path. Then 0.6×10-8 years will the spaceship take to reach the extrasolar planet.

What is Speed?

Speed is the time rate at which an object is moving along a path.

The formula for speed is distance/time

Given that

An extrasolar planet is observed at a distance of 4.2 x 10° kilometers away.

Distance= 4.2 x 10°

A group of scientists has designed a spaceship that can travel at the speed of 7 x 10⁸ kilometers per year

Speed = 7 x 10⁸

Time we need to calculate

Time =Distance/speed

Time = 4.2 x 10°/7 x 10⁸

=0.6×10⁻⁸

Hence 0.6×10-8 years will the spaceship take to reach the extrasolar planet.

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The equation of a line that is perpindicular to y=10x but passes through (1, -3)

Answers

The equation of line is y = -x/10 + -29/10.

Given,

The equation of a line that is perpendicular to y = 10x

and, passes through the (1, -3)

To find the equation of line.

Now, According to the question:

Find the slope of the line that is perpendicular to y = 10x;

m = - 1/10

We know that, Slope of line is ;

y = mx + c

m = -1/10

x = 1

y = -3

Substitute and calculate

- 3 = -1/10 + b

b = -29/10

Now, y = mx + b

Substitute all the values in above slope equation:

y = -x/10 + -29/10

Hence, The equation of line is y = -x/10 + -29/10.

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Find the component form of the sum of u and v with direction angles u and v.

Answers

We will have the following:

[tex]\begin{gathered} U_x=14cos(45) \\ \\ U_y=14sin(45) \\ \\ V_x=80cos(180) \\ \\ V_y=80sin(180) \end{gathered}[/tex]

Then:

[tex]\begin{gathered} \sum_x=\frac{14\sqrt{2}}{2}+(-80)\Rightarrow\sum=7\sqrt{2}-80 \\ \\ \sum_y=\frac{14\sqrt{2}}{2}+(0)\Rightarrow\sum=7\sqrt{2} \end{gathered}[/tex]

So, the component form for the sum of the vectors will be:

[tex]u+v=(7\sqrt{2}-80)i+(7\sqrt{2})j[/tex]

Christine is a software saleswoman. Let y represent her total pay (in dollars). Let x represent the number of copies of Math is Fun she sells. Suppose that x and y are related by the equation 70x + 1700= y.Answer the questions below. Note that a change can be an increase or a decrease. For an increase, use a positive number. For a decrease, use a negative number. What is the change in Christine’s total pay for each copy of Math is Fun she sells? What is Christine’s total pay if she doesn’t sell any copies of Math is Fun?

Answers

From the information given, the equation relating her total pay (in dollars), y to the number of copies of Math is Fun she sells, x is expressed as

y = 70x + 1700

This is a linear equation. The slope intercept form of a linear equation is expressed as

y = mx + b

where

m = slope or rate of change

b = y intercept of the value of y when x = 0

By comparing both equations,

m = 70

b = 1700

a) Thus, the change in Christine’s total pay for each copy of Math is Fun she sells 70 dollars per copy

b) Christine’s total pay if she doesn’t sell any copies of Math is Fun is the value of y when x = 0. thus,

Christine’s total pay if she doesn’t sell any copies of Math is Fun = $1700

Cindy eats 12 oz of candy in 4 days how long will it take her to eat 1 pound of candy

Answers

We should know that:

1 pound = 16 oz

given Cindy eats 12 oz in 4 days

She will eat 1 pound in x days

So, we need to find the number of days to eat 1 pound which is equal to 16 oz

Using the ratio and proportion

12 : 4 = 16 : x

[tex]\begin{gathered} 12\colon4=16\colon x \\ \frac{12}{4}=\frac{16}{x} \\ x=\frac{4\cdot16}{12}=\frac{16}{3}=5\frac{1}{3} \end{gathered}[/tex]

so, the number of days = 5 1/3

Rewrite the fallowing as an exponential expression in simplest form.

Answers

SOLUTION

[tex]\begin{gathered} 5x\sqrt[]{x} \\ 5x\times\sqrt[]{x} \\ 5x^1\times x^{\frac{1}{2}} \\ 5x^{1+\frac{1}{2}} \\ 5x^{\frac{3}{2}} \\ \end{gathered}[/tex]

3. If you ordered a pizza to share with others, which of the following sets ofnumbers would best describe the part of the pizza you ate.a. Integerb. WholeC. Naturald. Rational

Answers

rational, because you've split the pizza

So for example if you cut the pizza into 12 pieces to one of your friends you gave 1/12

find the equation of the circle with the given center and radius:center (-1,-6), and radius = 6

Answers

ANSWER:

[tex](x+1)^2+(y+6)^2=36^{}[/tex]

STEP-BY-STEP EXPLANATION:

We have that the equation of the circle is given as follows:

[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \text{where (h, k) is the center and r is the radius } \end{gathered}[/tex]

Replacing:

[tex]\begin{gathered} (x-(-1))^2+(y-(-6))^2=6^2 \\ (x+1)^2+(y+6)^2=36^{} \end{gathered}[/tex]

Find the annual fixed expense for car insurance if John makes

six payments in a year at $174.45 each?

Answers

The annual fixed expense for car insurance is  $ 1,046.70.

It is given in the question that John makes six payments in a year at $174.45 each.

We have to find the annual fixed expense for car insurance.

We know that,

The annual fixed expense for the car insurance will be 6 times the individual payment given in the question.

Hence, by simple multiplication, we can write,

Annual fixed expense for the car insurance = 6*174.45 = $ 1,046.70

Car insurance

Car insurance is a type of financial protection that covers the cost of another driver’s medical bills and repairs if you cause an accident with your car, or in case your car is stolen or damaged some other way.

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i inserted a picture of the question, could you please take the short way.

Answers

Recall the following property of exponents:

[tex](a\cdot b)^x=a^x\cdot b^x\text{.}[/tex]

Therefore:

[tex](14\cdot(-58))^{16}=14^{16}\cdot(-58)^{16}\text{.}[/tex]

Answer: Option A.

If triangle ABC with C =90°,if C = 31MM & B equals 57° then a equals

Answers

SOLUTION

Step1; Draw the Triangle and locate the angles

We are to obtain the value of a that is the side |BC|

Applying trigonometry ratios we have

[tex]\begin{gathered} \text{hypotenuse}=c=31 \\ \text{Adjacent}=a \\ \theta=57^0 \end{gathered}[/tex][tex]\begin{gathered} \cos \theta=\frac{adjacent}{Hypotenuse} \\ \cos 57^0=\frac{a}{31}\ldots.\text{ cross multiply} \\ a=31\times cos57^0 \end{gathered}[/tex][tex]\begin{gathered} a=31\times0.8999 \\ a=27.89 \end{gathered}[/tex]

Then the value of a = 28mm to the nearest whole number

A radio announcer asked her listeners which type of music they preferred. The results are below. which answer choice lists the results from greatest to least perefence?F. 0.10, 25%, 0.20, 45/100G. 25%, 45/100, 0.20, 0.10H. 0.10, 0.20, 25%, 45/100J. 45/100, 25%, 0.20, 0.10

Answers

To compare the preferences is best to express them using the same form, for example, express all values as decimal values:

To express 25% as a decimal value you have to divide it by 100:

[tex]\frac{25}{100}=0.25[/tex]

To express the fraction 45/100 as a decimal value you have to divide 45 by 100

[tex]45\div100=0.45[/tex]

So, the observations expressed as decimal values are:

Rap 0.25

Norteno 0.45

Kazz 0.20

Tejano 0.10

Now that all numbers are on the same form you can order them from greatest to least. To do so, you have to compare the digit on the first decimal place, if the first digit is equal, you have to compare the digit on the second decimal place.

The number with the greatest decimal value is 0.45

Then you have 0.20 and 0.25 both have the same first digit, so you have to compare the second digits. "0" is less than "5" so, 0.20 is less than 0.25.

The least value is 0.10.

So ordered from greatest to least the values are:

[tex]\begin{gathered} 0.45;0.25;0.20;0.10= \\ \frac{45}{100};25\%,0.20;0.10 \end{gathered}[/tex]

The correct option is J.

Solve the following inequality for t. Write your answer in the simplest form.6t + 3 < 7t + 10

Answers

[tex]\begin{gathered} \text{Given} \\ 6t+3<7t+10 \end{gathered}[/tex]

[tex]\begin{gathered} \text{Subtract both sides by }10 \\ 6t+3<7t+10 \\ 6t+3-10<7t+10-10 \\ 6t-7<7t\cancel{+10-10} \\ 6t-7<7t \\ \\ \text{Then subtract both sides by }6t \\ 6t-7<7t \\ 6t-6t-7<7t-6t \\ \cancel{6t-6t}-7-7 \end{gathered}[/tex]

Therefore, the solution is t > -7.

A boutique in Lanberry specializes in leather goods for men. Last month, the company sold 56 wallets and 63 belts, for a total of $3,920. This month, they sold 94 wallets and 22 belts, for a total of $3,230. How much does the boutique charge for each item?

Answers

Let w represent the cost of each wallet.

Let b represent the cost of each belt.

Last month, the company sold 56 wallets and 63 belts, for a total of $3,920. This means that

56w + 63b = 3920

This month, they sold 94 wallets and 22 belts, for a total of $3,230. This means that

94w + 22b = 3230

We would solve the equations by applying the method of elimination. To eliminate w, we would multiply the first equation by 94 and the second equation by 56. The new equations would be

5264w + 5922b = 368480

5264w + 1232b = 180880

Subtracting the second equation from the first, we have

5264w - 5264w + 5922b - 1232b = 368480 - 180880

4690b = 187600

b = 187600/4690

b = 40

Substituting b = 40 into 56w + 63b = 3920, we have

56w + 63(40) = 3920

56w + 2520 = 3920

56w = 3920 - 2520 = 1400

w = 1400/56

w = 25

Thus, the boutique charges $25 for each wallet and $40 for each belt

A board game that normally costs $30 is on sale for 25 percent off. What is the sale price of the game?
$22.50
$27.50
$32.50
$37.50

Answers

$22.50

30.00 times 0.25= 7.5
30.00-7.50=22.50

In ACDE, J is the centroid. If JG=21 find CG. D F G C E H

Answers

Let's begin by identifying key information given to us:

We have triangle CDE

J is the centroid

[tex]\begin{gathered} JG=21 \\ \text{The centroid of a triangle divides }\frac{2}{3\text{ }}\text{the distance from}verte\text{x to midpoint of the sides} \\ \Rightarrow JG=\frac{2}{3}CG \\ \Rightarrow21=\frac{2}{3}CG=\frac{63}{2} \\ \therefore CG=\frac{63}{2}=31.5 \end{gathered}[/tex]

Y=1/3x+2 standard form

Answers

3y - x = 6 is standard form for the given equation

What is standard form of linear equation ?The typical form for linear equations with two variables is Ax+By=C.For instance, the linear equation 2x+3y=5 is in standard form. Finding both intercepts of an equation in this style is quite easy (x and y).This form is also very useful when trying to solve systems of two linear equations.Calculation

y = 1/3x + 2

3y = x + 6

3y - x = 6 is standard form

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