How do I solve this?

Answer:

Step-by-step explanation:

We can use the standard normal distribution to solve this problem by standardizing the score.

z = (x - mu) / sigma

Where:

x = 70 (score we are interested in)

mu = 60 (mean score)

sigma = 7 (standard deviation)

z = (70 - 60) / 7 = 1.43

Using a standard normal distribution table or calculator, we can find the probability that z is greater than 1.43. The probability is approximately 0.0764.

Therefore, the probability that a randomly selected student scored more than 70 on the exam is 0.0764 (or about 7.64%).

The expression or equation that correctly represents the situation given is y = 2x.

Based on the table, for each package of cashews 2 cans of peanuts are required. Here are some examples:

Based on this relationship and assuming y represents the cans of peanuts and x represents the packages of cashews a possible equation to represent this situation would be y = 2x.

Note: This question is incomplete; below I attach the missing information:

Write an equation to represent this relationship:

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Answer:

area=36.5

Step-by-step explanation:

8×4=32

8-5=3 for the base of the triangle

7-4=3 for the height of the triangle

3×3=9

9÷2=4.5

4.5+32=36.5

area=36.5

Answer: 37.5

Step-by-step explanation:

Answer:

slope of 3/4 = line C

undefined slope = line A

Step-by-step explanation:

remember that slope is [tex]\frac{rise}{run}[/tex]. Pick any two points on the graph and count up and over to find the rise/run.

OR

use the slope formula [tex]m=\frac{y_{2} -y_{1} }{x_{2}-x_{1} }[/tex] to plug the two points into and find the slope.

- vertical lines are always undefined.

- horizontal lines have a slope of 0

The value of angle x in the right triangle KJI is approximately 63.4 degrees.

What is trigonometric ratios ?

Trigonometric ratios are mathematical functions that relate the angles of a right triangle to the lengths of its sides. The three primary trigonometric ratios are sine, cosine, and tangent, which are abbreviated as sin, cos, and tan, respectively.

These ratios are defined as follows:

Sine (sin) of an angle is the ratio of the length of the side opposite to the angle to the length of the hypotenuse.

Cosine (cos) of an angle is the ratio of the length of the adjacent side to the angle to the length of the hypotenuse.

Tangent (tan) of an angle is the ratio of the length of the side opposite to the angle to the length of the adjacent side.

Finding the value of x :

We can use the trigonometric ratios to find the value of angle x in the right triangle KJI.

First, we can use the Pythagorean theorem to find the length of the hypotenuse KI:

[tex]KI^2 = KJ^2 + JI^2[/tex]

[tex]KI^2 = 27^2 + 48^2[/tex]

[tex]KI^2 = 729 + 2304[/tex]

[tex]KI^2 = 3033[/tex]

[tex]KI =\sqrt{3033}[/tex]

Next, we can use the sine function to find the value of angle I:

[tex]sin(I) = JI / KI[/tex]

[tex]sin(I) = 48 / \sqrt{3033}[/tex]

[tex]I = sin^-1(48 / \sqrt{3033})[/tex]

[tex]I = 63.4[/tex] degrees

Therefore, the value of angle x in the right triangle KJI is approximately 63.4 degrees.

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Answer:

153

Step-by-step explanation:

The relationship in the row is below

4³ +2³ +1³ =64 + 8 +1 = 72

1³ + 2³ +6³= 1 + 8 + 216

3³ + 1³ + 5³ = 27 +1 +125 = 153

All numbers below the first level are raised to power 3 and added together

The equation of the circle is with the diameter given is x² + y² = 9.

The standard form of the equation of a circle is (x - h)² + (y - k)² = r², where (h,k) is the center of the circle.

We can quickly determine the circle's centre and radius thanks to this form. We must first square the x and y terms before rearranging the components in order to transform a circular equation into standard form.

The endpoints of the diameter is (-3,0) and (3,0).

Now, using the section formula the coordinates of radius are:

((-3+3)/2, (0+0)/2) = (0,0

The standard form of the equation of a circle is (x - h)² + (y - k)² = r², where (h,k) is the center of the circle.

Substituting the values:

(x - 0)² + (y - 0)² = 3²

Hence, the equation of the circle is x² + y² = 9.

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The gorilla has a heart rate that is four times faster than the chimpanzee's when they are resting.

Expression in math is a combination of numbers, variables, operations and/or symbols that represent a value, quantity or an equation. It can either be a single term, or several terms connected by mathematical operations such as addition, subtraction, multiplication and division. Expressions are typically used in equations, formulas and problems to help solve them.

To calculate the heart rate of the gorilla, we use the power function given: H(m) = 240m. Substituting in m = 200, we get H(200) = 240(200) = 48,000 beats per minute.

To calculate the heart rate of the chimpanzee, we use the same power function: H(m) = 240m. Substituting in m = 50, we get H(50) = 240(50) = 12,000 beats per minute.

Therefore, the gorilla has a heart rate that is four times faster than the chimpanzees when they are resting.

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Step-by-step explanation:

2 pictures are attached

sin waves are used in many medical devices like to measure heart beats

Equation:

89.50=2.35c+5.50d

If theres 22 dogs and cats in total you can plug in number less than 22 for c(# of cats) and d(# of dogs).

So we try pats numbers 8 cats and 14 dogs so

89.50=2.35(8)+5.50(14)

89.50=18.8+77

89.50=95.8

So pats numbers were wrong so we try different numbers

So i started pluging in numbers from under 22 so i got c is 10 and d is 12 lets try it with the equation

89.50=2.35(10)+5.50(12)

89.50=23.5+66

89.50=89.50 so it works the answer to how many number of dogs and cats is 12 dogs and 10 cats

As per integration, the height of the water in the barrel at time = 2 hours is 1.672 feet (option C).

The formula is r(t) = 47-15, where t is the time in hours since the rain began. This formula tells us how fast the water level is changing at any given time t.

In this case, we're asked to find the height of the water in the barrel at t = 2 hours, given that the height at t = 1 hour is 0.75 feet. To solve this problem, we'll integrate the rate formula from t = 1 to t = 2, and add the starting height of 0.75 feet.

∫(47-15)dt from t=1 to t=2 = [47t-15t] from t=1 to t=2 = 0.922

So the total increase in height from t=1 to t=2 is 0.922 feet. Adding this to the starting height of 0.75 feet, we get the height of the water at t=2:

0.75 + 0.922 = 1.672 feet

Therefore, the correct option is (C).

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Answer:

For problem a: 0,4 0,5 0,6

For Problem B: 1,0 2,0 3,0

Step-by-step explanation:

Graph each equation on a graph Figure out either solid or dotted line. Then depending on <=,<,>,>= is whre you shade on your graph. The spot where both lines meet when shaded is your solution area and you pick any spot on that. You can check your answer by plugging in ordered pairs for your X,Y values in the system.

The percentage change in the visit of total number of customers in the second week as compare to first week is equal to 16.67%.

Total number of customers visited the store in the first week = 360

Total number of customers visited the store in the second week = 300

Percentage Change = (|First week - second week / First week) x 100%

Substitute the value of the number of customers in different weeks in the formula we get,

Percentage Change

= (|300 - 360| / 360) x 100

= (60 / 360) x 100

=( 100 / 6 )

= 16.66666%

= 16.67%

Therefore, the percentage change in the number of customers that visited the store from the first week to the second week is a decrease of 16.67%.

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The above question is incomplete, the complete question is:

Mr. Davies opened a new retail store. During the first week, 360 customers visited the store. During the second week, 300 customers visited the store.

What is the percentage change of the number of customers that visited the store in the first week to the number of customers that visited the store in the second week?

Probability that exactly four workers carpool to work is 0.214990847, or approximately 21.5%.

We must apply the binomial distribution formula to resolve this issue. The number of successes in a certain number of independent trials that all have the same chance of success are described by the binomial distribution, which is a type of probability distribution. In this scenario, the number of successes is the number of workers who carpool, and the probability of success is 0.1.

The binomial distribution's formula is:

[tex]P(X=k) = to (n pick k) * p*k*1-p (n-k)[/tex]

Where n is the total number of trials (in this case, 8), p is the success probability (0.1), and (n choose k) is the binomial coefficient, which is equal to [tex]n! / (k! * (n-k)![/tex] and P(X=k) is the probability of obtaining exactly k successes.

This formula can be used to determine the likelihood that four employees will carpool to work:

[tex]P(X=4) = (8 pick 4) * 0.14 * 0.94 * 0.214 = 0.214990847.[/tex]

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Answer:

75°

Step-by-step explanation:

The angle in the given figure is 90°.

x + 15 = 90

x = 90 - 15

x = 75°

The sequence follows a pattern of adding 7 to the previous term, and its formula is 7n - 3. The sum of the first 100 terms of the sequence is 35,350, which was found using the formula for the sum of an arithmetic series.

The next term in the sequence can be found by adding 7 to the previous term, so the next term is 25.

To find a formula for the nth term of the sequence, we can observe that each term is 7 more than a multiple of 7. In other words, the nth term is given by the formula 7n - 3.

To find the sum of the first 100 terms of the sequence, we can use the formula for the sum of an arithmetic series:

S = (n/2)(a1 + an)

where S is the sum of the first n terms, a1 is the first term, and an is the nth term. Substituting n = 100, a1 = 4, and an = 703, we get:

S = (100/2)(4 + 703) = 35,350

Therefore, the sum of the first 100 terms of the sequence is 35,350.

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To estimate the number of new subscribers in Charlottesville and Albemarle County, we'll use the given joint probability density function (pdf) f(x,y).

Here's a step-by-step explanation:
1. Identify the random variables: In this case, X represents the number of new subscribers (in thousands) in Charlottesville, and Y represents the number of new subscribers (in thousands) in Albemarle County outside of Charlottesville.
2. Understand the joint probability density function (pdf): The function f(x,y) describes the probability of having a specific number of new subscribers in both areas. The joint pdf is used to find the probability of a particular combination of X and Y values.
3. Determine the desired outcome: In this case, you want to estimate the number of new subscribers in both Charlottesville (X) and Albemarle County (Y) next year.
4. Calculate the probabilities: To find the probability of a specific combination of X and Y values, you'll need to evaluate the joint pdf f(x,y) at those values.
5. Analyze the results: Based on the probabilities you've calculated using the joint pdf, you can make informed estimates about the number of new subscribers in both areas next year.
By following these steps and using the joint probability density function f(x,y), you can estimate the number of new subscribers for F XYZ finity Cable in Charlottesville and Albemarle County next year.

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The probability that it rains at least one day this weekend is [tex]$\frac{a}{b}$[/tex],  so the value of a+b is given as 107.

Calculating the likelihood of experiments happening is one of the branches of mathematics known as probability. We can determine everything from the likelihood of receiving heads or tails when tossing a coin to the likelihood of making a research blunder, for instance, using a probability.

Let x be the probability that it rains on Sunday given that it doesn't rain on Saturday then we have,

3/5x + 2/5(2x) = 3/10

7/5x = 3/10

x = 3/14.

Therefore, the probability that it doesn't rain on either day is,

[tex]$\left(1-\dfrac{3}{14}\right)\left(\dfrac{3}{5}\right)=\dfrac{33}{70}$[/tex]

Therefore, the probability that rains on at least one of the days is

[tex]$1-\dfrac{33}{70}=\dfrac{37}{70}$[/tex],

so adding up the 2 numbers, we have,

37 + 70 = 107.

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Complete question;

There is a 40% chance of rain on Saturday and a 30% chance of rain on Sunday. However, it is twice as likely to rain on Sunday if it rains on Saturday than if it does not rain on Saturday. The probability that it rains at least one day this weekend is [tex]$\frac{a}{b}$[/tex], where a and b are relatively prime positive integers. Find a+b.

The sum of the first $20$ terms of the arithmetic sequence is $420$.

In an arithmetic sequence, the sum of the second and eighth terms is $5$, and the product of the fourth and fifth terms is also $5$. The sum of the first $20$ terms of this sequence can be calculated using the following formula:

Sum of the first $20$ terms = $20$/2($a_1 + a_{20})$, where $a_1$ is the first term of the sequence and $a_{20}$ is the twentieth term of the sequence.

Therefore, we need to find the first term of the sequence and the twentieth term of the sequence. To find the first term, we use the following equation:

$5 = a_2 + a_8$, where $a_2$ is the second term and $a_8$ is the eighth term.

To find the twentieth term, we use the following equation:

$5 = a_4 \times a_5$, where $a_4$ is the fourth term and $a_5$ is the fifth term.

Solving both equations, we get $a_2 = 1$ and $a_{20} = 40$. Then, we can calculate the sum of the first $20$ terms of the sequence:

Sum of the first $20$ terms = $20$/2($1 + 40$) = $420$.

Therefore, the sum of the first $20$ terms of the arithmetic sequence is $420$.

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The system of linear inequalities to model the number of hours that you could work at each location in a week is:

x ≥ 4

x + y ≤ 15

What is system of linear inequality?

A system of linear inequalities is a set of two or more linear inequalities with the same variables. It describes a region in the coordinate plane that satisfies all of the inequalities in the system.

In this case, we are trying to model the number of hours that someone could work at two different jobs.

The first inequality given is that the person must work at least 4 hours per week at the trampoline park. Let x be the number of hours worked at the trampoline park. This can be represented as:

x ≥ 4

The second inequality given is that the total number of hours worked at both jobs cannot be greater than 15. Let y be the number of hours worked at the landscaping company. Then, the total number of hours worked can be represented as:

x + y ≤ 15

Together, these two inequalities form a system of linear inequalities that model the possible number of hours that the person can work at each job in a given week.

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Answer:

10 + 2x

also,

2x + 10

Step-by-step explanation:

"a number value" is the unknown, so use a variable (letter) I used x, but could be almost any letter (avoid e and i, they have other math meanings)

"10 more than" means to add on 10. You can do that up front or at the end. Order is way more important for subtracting, so no worries here.

"product" means multiplying. So the "product of 2 and a number" is 2x.

So to translate this word phrase into an algebraic expression, you get:

10 + 2x

but also 2x + 10 is the same thing.

The probability of getting 0 toppings when ordering a hamburger with a choice of up to 6 toppings is 0.0154, rounded to four decimal places.

The total number of ways to choose 6 toppings out of a possible 6 is given by the combination formula:

[tex]$${ \choose 6} = \frac{6!}{6!(6-6)!} = 1$$[/tex]

This is the total number of possible outcomes.

To get 0 toppings, we need to choose 0 toppings out of 6. The number of ways to do this is:

[tex]{6_{0} =[/tex] [tex]\frac{6!}{0!(6-0)!} = 1$$[/tex]

So the probability of getting 0 toppings is:

[tex]$$P(\text{0 toppings}) =[/tex]  [tex]\frac{number of ways to get 0 toppings}{total number of possible outcomes} $$[/tex] [tex]\frac{1}{1} = 1$$[/tex]

However, this is assuming that the cashier chooses the toppings randomly and without replacement. If the cashier has some bias or preference towards certain toppings, this probability may be different.

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The probability that the number of phone calls between 2:00 pm and 2:10 pm is exactly 25 is 1/110,592,893.

To calculate this probability, use the Poisson distribution formula: P(x) = (e^-λ * λ^x) / x!, where λ = 3 x 10 = 30. Therefore, P(25) = (e^-30 * 30^25) / 25! = 1/110,592,893.

The probability that the number of phone calls between 2:00 pm and 2:10 pm is more than 25 is the sum of probabilities of all calls more than 25. That is, the probability is 1 - (e^-30 * (30^0 + 30^1 + 30^2 + ... + 30^25)) / (0! + 1! + 2! + ... + 25!).

By using the same Poisson distribution formula, the probability is 1 - 0.99988822 = 0.00011178.

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b + 2p = 10 ,we have an equation that relates the number of bracelets to the number of purses and the total cost of the purchase. if Evelyn buys two purses, she also buys six bracelets.

Let's start by defining our variables. We'll let "b" represent the number of bracelets that Evelyn buys and "p" represent the number of purses she buys.

We know that each bracelet costs $6 and each purse costs $12. We also know that her total purchase is $60.

Using this information, we can create an equation:

6b + 12p = 60

Now we want to solve for "b", which represents the number of bracelets. To do this, we need to isolate "b" on one side of the equation. We can start by simplifying the equation by dividing both sides by 6:

b + 2p = 10

Now we have an equation that relates the number of bracelets to the number of purses and the total cost of the purchase. We can use this equation to find the value of "b" given any value of "p". For example, if Evelyn buys two purses, we can substitute "p = 2" into the equation and solve for "b":

b + 2(2) = 10

b + 4 = 10

b = 6    

So if Evelyn buys two purses, she also buys six bracelets.

In general, we can see that the equation tells us that for every two purses that Evelyn buys, she buys one less bracelet. This makes sense because purses are more expensive than bracelets, so as she buys more purses, she can afford fewer bracelets.

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Method 1: Graphing

Graphing is best when the both equations are shown in slope-intercept form. For example:

[tex]y=\frac{1}{2} x+2\\y=-\frac{1}{2} x+4[/tex]

[tex](2,3)[/tex]

You can easily graph this system of equations and find the intersecting point. The graph is displayed below. This may not always be the case, however and you may get complicated fractions in your answer. In this case, substitution or elimination may be better.

Method 2: Substitution

Substitution is a good method to solve a system of equations when one of the equations can be rearranged to isolate one variable, or the equation already solves for a variable. This isolated expression can then be substituted into the other equation(s) to create a new equation(s) with only one variable.

For example, consider the system of equations:

[tex]y=x-2\\2x-5y=1[/tex]

Since y is much easier to substitute, we can choose y to substitute into the other equation:

[tex]2x-5(x-2)=1[/tex]

We can then simplify the equation:

[tex]2x-5x+10=1\\-3x=-9\\x=3[/tex]

Then you can substitute x into the original equation:

[tex]y=3-2\\y=1[/tex]

Solution: [tex](3,1)[/tex]

Substitution can be a useful method when the system involves two or three variables and one equation can be easily rearranged to isolate a variable. However, it can become more difficult or time-consuming when the system involves more variables or when the equations are not solving for a variable or can be easily solved. In these cases, other methods such as elimination is more efficient.

Method 3: Elimination

Elimination is a good method to solve a system of equations when the equations can be added or subtracted in a way that eliminates one of the variables.

For example, consider the system of equations:

[tex]x+y=90\\x-y=18[/tex]

We can cancel out the variable y and add the other numerals and variables:

[tex]2x=108[/tex]

This simplifies to:

[tex]x=54[/tex]

We can then solve for y:

[tex]54+y=90\\y=36[/tex]

Solution: [tex](54, 36)[/tex]

Once we have the value of x, we can substitute it back into one of the original equations to solve for y.

Although elimination is slightly more complicated, it is the most efficient method out of all of the three methods I have shown here.

Hope this helped you :)

(This took like 30 minutes ;-;)

Answer:

The answer to your problem is, [tex]16cm^{2}[/tex]

Step-by-step explanation:

Sophie has a small cube shaped box.

Volume of the box is [tex]64cm^{3}[/tex]

We have to find the area of one face of the box.

Let one side of the box is x

Then volume = [tex]x^{3}[/tex] = 64

x³ = 4³

= 4

Now area of one face of the cube = x²

then area = 4² = 16 cm²

Thus the answer to your problem is, [tex]16cm^{2}[/tex]

We can see here that the figures that have the same area are: A. Figures I and II.

Area is a measure of the size of a two-dimensional surface or shape. It refers to the amount of space inside the boundaries of a flat object, such as a rectangle, triangle, or circle. Area is typically measured in square units, such as square meters, square feet, or square centimeters.

The area of Figure I which is a rectangle is = l × b = 2cm × 5.8cm = 11.6cm².

The area of Figure II which is a parallelogram is = b × h = 4cm × 2.9cm = 11.6cm².

Thus, Figures I and II have the same area.

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Factor  72 + 32 in the form of a ( b + c)  with A having gcf is 72 + 32 is 8(9 + 4).

To factor 72 + 32, we first need to find the greatest common factor (GCF) of 72 and 32.

The prime factorization of 72 is 2³ x 3², and the prime factorization of 32 is 2⁵.

The common factors of 72 and 32 are 1, 2, 4, 8, and 16. The greatest common factor is 8, since it is the largest factor that they both share.

So, we can write 72 + 32 as:

72 + 32 = 8 x (9 + 4)

Therefore, the factored form of 72 + 32 is 8(9 + 4).

To factor 72 + 32, we need to find the greatest common factor (GCF) of 72 and 32, which is 8. We can then use this GCF to write 72 + 32 in factored form as 8(9 + 4). This expression can also be simplified as 8(13), which equals 104. This means that 72 + 32 can be written as the product of 8 and 13, where 8 is the GCF of 72 and 32, and 13 is the sum of the quotients of 72 and 32 when divided by 8. Factoring expressions is an important skill in algebra and is used in many areas of mathematics and science.

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