How many cubic meters of material are there in a conical pile of dirt that has radius 9 meters and height ​3? Use 3.14 for Pi.

Answer:

average rate of change on [-1,3] = 11

Step-by-step explanation:

avg rate of change = [tex]\frac{f(b)-f(a)}{b-a}[/tex]

[tex]\frac{f(3)-f(-1)}{3-(-1)}[/tex]

1. find your y-values.

we are given the x values from the interval [-1,3]. Plug each into the equation to get the y-value of the coordinates.

[tex]f(-1)=4(-1)^2+3(-1)-4\\f(-1)=4(1)-3-4\\f(-1)=-3\\[/tex]

coordinate: (–1,3)

[tex]f(3)=4(3)^2+3(3)-4\\f(3)=4(9)+9-4\\f(3)=36+9-4\\f(3)=41[/tex]

coordinate: (3, 41)

2. plug into the slope formula

[tex]m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} } \\m=\frac{41-(-3)}{3-(-1)} \\m=\frac{41+3}{4} \\m=\frac{44}{4} \\m=11[/tex]

Answer:

Step-by-step explanation:

The first roll can be any number from 1 to 6, since there are no earlier rolls to compare it to.

For the second roll, the probability of rolling a number greater than the first roll is 1/2, since there are only three numbers left on the die that are greater than the first roll.

Similarly, the probability of rolling a number greater than the first two rolls on the third roll is 1/3, and the probability of rolling a number greater than the first three rolls on the fourth roll is 1/4.

Therefore, the probability of rolling four numbers that are at least as high as the previous rolls is:

1 x 1/2 x 1/3 x 1/4 = 1/24

So the probability of rolling four numbers that are at least as high as the previous rolls is 1/24.

The probability of rolling each number higher than the previous number when a die is thrown four times is 1/3.

To calculate this probability, we must first understand the concept of a combination. A combination is a way of selecting items from a set, such that the order of selection does not matter. In this case, the set is the numbers 1-6.

The probability of rolling each number higher than the previous number is equal to the probability of selecting four numbers from a set of six without repeating any of them.

We can calculate this probability by dividing the number of desired combinations by the total number of possible combinations.

The number of desired combinations is equal to the number of ways we can choose the first number from the set (6 choices), multiplied by the number of ways we can choose the second number from the remaining five (5 choices), and so on.

Therefore, the number of desired combinations is 6*5*4*3, which is 360.

The total number of possible combinations is equal to the number of ways we can choose four numbers from a set of six, which is 6*5*4*3*2*1, or 720.

Therefore, the probability of rolling each number higher than the previous number when a die is thrown four times is 360/720, which is equal to 1/3.

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The surface area of this rectangular prism is equal to 68 mm².

In Mathematics and Geometry, the surface area of a rectangular prism can be calculated and determined by using this mathematical equation or formula:

SA = 2(WH + LW + LH)

Where:

By substituting the given parameters into the formula for the surface area of a rectangular prism, we have the following;

SA = 2(1 × 4 + 6 × 1 + 6 × 4)

SA = 2(4 + 6 + 24)

SA = 2(34)

SA = 68 mm².

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The wallpaper cost $40 to John.

To find the amount of wallpaper John purchased, we have to solve for x in the cost function equation.

First, let's write down the cost function c(x) using the given information.Cost function equationc(x) = 12x + 20.

Here, x is the amount of wallpaper needed in square meters, and c(x) is the total cost John has to pay, including the cost of wallpaper and delivery.

Now, let's use the given total cost of $500 and solve for x.c(x) = 12x + 20Since the total cost John paid is $500, we can write the following equation:12x + 20 = 500

To solve for x, we can isolate x on one side by subtracting 20 from both sides.12x = 480x = 40Therefore, John purchased 40 square meters of wallpaper.

Answer: 40

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The extent to which a sample over or under represents characteristics of the population is known as sampling error.

Sampling error is the difference between the characteristics of a sample and the characteristics of the population from which it is drawn. Sampling error occurs when a sample does not accurately represent a population due to the selection of individuals. It is measured as the difference between a sample statistic and the corresponding population parameter. For example, if a sample of 100 people is taken from a population of 1,000 people, the sample might not accurately reflect the population as a whole due to random selection.

Sampling error is an important consideration in survey research, as it can have an effect on the accuracy of the results. Sampling error can be reduced by using larger sample sizes or by using more representative sampling methods.

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For a government published the above stem-and-leaf plot related to number of sloths at each major zoo in the country. The smallest of sloths at any one zoo was three.

A stem-and-leaf plot is a tool for presenting quantitative data in a graphical format, like as histogram for visualizing the shape of a distribution.

We have a stem-and-leaf plot present above and which showing the number of sloths at each major zoo in the country is published by government. Now, see the above plot carefully, thee smallest number in the stem-and-leaf plot is 03. We can get that by looking at the first stem value and the first leaf value. Hence, required number is 3.

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Complete question:

The government published the above stem-and-leaf plot showing the number of sloths at each major zoo in the country:pls answer fast if you can :

what was the smallest number of sloths at any one zoo?

Answer:

275

Step-by-step explanation:

You have a 1 in 2 chance

550/2

275 times

From the given information provided, the surface area and volume of cylinder is 1130.97 and 3816.85 respectively.

To find the surface area and volume of the cylinder, we can use the following formulas:

Surface Area = 2πr² + 2πrh

Volume = πr²h

Substituting the given values, we get:

Surface Area = 2π(9)² + 2π(9)(15) = 1130.97 square inches (rounded to the nearest tenth)

Volume = π(9)²(15) = 3816.85 cubic inches (rounded to the nearest tenth)

Therefore, the surface area of the cylinder is approximately 1130.97 square inches, and the volume is approximately 3816.85 cubic inches, both rounded to the nearest tenth.

Question - A cylinder has a height of 15 in and a radius of 9 in. Find area and volume. Round to the nearest tenth.

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The given interval suggests that the mean number of porcupine teeth marks on all wooden blocks treated with the repellent is less than 6 since the upper limit of the interval is 5.8. This claim falls within the given interval and is supported by the data. Therefore, we can say that the mean number of porcupine teeth marks on all wooden blocks treated with the repellent is less than 6 based on the 95 percent confidence interval (4.9,5.8).

In the given scenario, a sample of 20 wooden blocks treated with a liquid repellent designed to reduce damage caused by porcupines were left outside in an area where porcupines are known to live. After some time, the blocks were inspected for the number of porcupine teeth marks visible. The data collected was then used to create the 95 percent confidence interval (4.9,5.8).

The 95 percent confidence interval can be defined as a range of values that we can be 95 percent confident the true population parameter falls within. In this case, the true population parameters is the mean number of porcupine teeth marks on all wooden blocks treated with the repellent.

From the given interval, we can conclude that we are 95 percent confident that the true mean number of porcupine teeth marks on all wooden blocks treated with the repellent is between 4.9 and 5.8.

Therefore, any claim that falls within this interval is supported by the data.

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The common difference of the arithmetic sequence -6, 10, 26, 42 is given as follows:

16.

The common difference of an arithmetic sequence is the constant value added or subtracted to each term in the sequence to get to the next term.

The sequence for this problem is given as follows:

-6, 10, 26, 42, . . .

The difference between consecutive terms is given as follows:

42 - 26 = 16, which is constant for the other terms of the sequence.

Hence 16 is the common difference of the arithmetic sequence -6, 10, 26, 42, . . . given in this problem.

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We would expect around 3 students to have an IQ of 140 or above at Hogwarts School of Witchcraft and Wizardry.

Based on the given information, we can use the normal distribution formula to calculate the number of students expected to have an IQ of 140 or above.

To explain this, we can use the following steps:

1. Calculate the z-score for an IQ of 140 using the formula: z = (x - μ) / σ where x is the IQ score, μ is the mean IQ score and σ is the standard deviation.

2. Look up the probability of a z-score of 2.67 or above using a standard normal distribution table or calculator. This gives us the proportion of the population with an IQ of 140 or above.

3. Multiply the proportion by the total number of students to get the expected number of students with an IQ of 140 or above.

Since we cannot have a fraction of a student, we can round this to the nearest whole number to get the final answer.

Therefore, we would expect around 3 students to have an IQ of 140 or above at Hogwarts School of Witchcraft and Wizardry.

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Mark needs to invest 5572.24 hours (rounded to one decimal place) of study time in order to achieve an A letter grade in this course.

To determine the estimated minimum number of hours Mark should study, we need to solve for the number of hours such that his predicted score, given by the regression equation from part (b), is at least 90.

The regression equation is as follows: Predicted score = 48.74 + 0.00726(number of hours studied)

Setting the predicted score equal to 90 and solving for the number of hours studied gives:90 = 48.74 + 0.00726 (number of hours studied)

Solving for the number of hours studied gives: number of hours studied = (90 - 48.74)/0.00726= 5572.24

Therefore, Mark should study for 5572.24 hours (rounded to one decimal place) to receive a letter grade of A for this course.

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Thus, 4.0 moles of NH3 would be produced when 6.0 moles of H2 react with sufficient N2.

Suppose 6.0 mol of H2 reacts with sufficient N2 to produce ammonia, NH3. We can determine the number of moles of NH3 produced using stoichiometry.The balanced chemical equation for the reaction is:[tex]3H2(g) + N2(g) → 2NH3(g)[/tex]

From the equation, we can see that 3 moles of H2 react with 1 mole of N2 to produce 2 moles of NH3.

Therefore, using the mole ratio from the balanced equation, we can calculate the number of moles of NH3 that would be produced when 6.0 mol of H2 reacts with [tex]N2:6.0 mol H2 × (2 mol NH3/3 mol H2) = 4.0 mol NH3[/tex]

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Answer:

Step-by-step explanation:

nothing makes it true

Answer:

multiply BD and AC and you got it

Step-by-step explanation:

if yuo put ABD triangle over CEB you got a sqare, if you do it again you got a aqare 20x10

The optimal solution would be to use $240 worth of professional grade material for each frame.

An optimal solution is a solution that provides the best possible outcome for a problem or situation, given a set of constraints or requirements. In mathematical optimization, an optimal solution is the solution that maximizes or minimizes an objective function while satisfying a set of constraints.

In other words, an optimal solution is the solution that is most efficient, effective, or desirable according to a certain set of criteria. It is the solution that achieves the best possible outcome, given the available resources and limitations.

To find the optimal solution, we need more information about the specific weight specification and the cost of different types of materials.

However, if we assume that there is only one type of material available, and that it costs $x per yard, we can set up an equation to find the optimal solution:

30x = cost per frame

If the professional grade material costs $8 per yard, then the equation becomes:

30(8) = $240 per frame

So, the optimal solution would be to use $240 worth of professional grade material for each frame, assuming that it meets the weight specification. If the weight specification requires a different amount of material, or if there are other materials available at different prices, the optimal solution would be different.

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Answer:

2/3 is the answer .......mmm..

Answer: Shape one: 5, Shape 2: 13

Step-by-step explanation:

shape one
12^2+x^2=13^2

shape two
5^2+12^2=x^2

Answer:

PLEASE MARK ME AS BRAINLLIEST

Step-by-step explanation:

p=12

h=13

b=?

p²+b²=h²

12²+b²=13²

144+b²=169

b²=169-144

   = 25

b=root25

b=5m

b=5

p=12

h=?

p²+b²=h²

12²+5²=h²

144+25=h²

h²=169

h=root169

h=13

Answer:27.5

Step-by-step explanation:

i did this with a calculator, but the answer is

27.5

Answer:

The area of a circle is given by the formula A = πr², where r is the radius of the circle.

If we have two circles with radii of 6 cm and 12 cm, respectively, their areas are:

A1 = π(6 cm)² ≈ 113.1 cm²

A2 = π(12 cm)² ≈ 452.4 cm²

Therefore, the area of the largest circle is closest to 452.4 square centimeters, which corresponds to the circle with radius 12 cm.

Step-by-step explanation:

Probabilities

The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.

Let's call W the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is Ω = {WW, W N, NW, N N}

We are required to compute the probability that only one of the counters is white. It means that the favorable options are A = {W N, NW}

Let's calculate both probabilities separately. At first, there are 11 counters, and 5 of them are white. Thus, the probability of picking a white counter is 5/11.

Once a white counter is out, there are only 4 of them and 10 counters in total. The probability to pick a non-white counter is now 6/10.

Thus, the option WN has the probability P(WN) = 5/11 x 6/10 = 30/110 = 3/11

Now for the second option NW. The initial probability to pick a non-white counter is 6/11.

The probability to pick a white counter is 5/10

Thus, the option NW has the probability P(WN) = 6/11 x 5/10 = 30/110 = 3/11

P(A) = 3/11 + 3/11 = 6/11.

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The length of the missing side is 3√17 ft. Option B is the correct option.

What is the hypotenuse?

The longest side of a right-angled triangle, or the side opposite the right angle, is known as the hypotenuse in geometry. The Pythagorean theorem, which states that the square of the length of the hypotenuse equals the sum of the squares of the lengths of the other two sides, can be used to determine the length of the hypotenuse.

The △ABC is a right-angled triangle.

Thus the sum of squares of the legs of the triangle is equal to the square of the hypotenuse.

The hypotenue is 13 ft.

Assume that the missing leg is equal to x.

The legs of the triangle are x and 4ft.

Apply Pythagorean theorem:

13² = 4² + x²

x² = 169 -16

x² = 157

x = √(3×3×17)

x = 3 √17

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The x² statistic for the goodness-of-fit test is approximately 104.15.

EXPLANATION:

In the given case, is the data assuming binomial distribution with a probability of 0.8 that a flight leaves on time. We have to find the x² statistic for the goodness-of-fit test.

The steps involved are:

Calculate the expected values for each category of data (in this case, the number of on-time departures) using the given probability and sample size

.Use the formula:

χ² = Σ [(observed value - expected value)² / expected value]

Here, Σ means sum over all the categories. Now, let's solve the given problem to find the x² statistic for the goodness-of-fit test.

Problem

Let p = probability that a flight leaves on time = 0.8

n = sample size = 200

Then, q = 1 - p = 0.2

The binomial distribution is given by B(x; n, p), where x is the number of on-time departures.

So, we can write:

B(x; 200, 0.8) = (200Cx)(0.8)x(0.2)200-x= (200! / x!(200 - x)!) × (0.8)x × (0.2)200-x

Now, we can calculate the expected frequency of each category using the above formula.

χ² = Σ [(observed value - expected value)² / expected value]

The observed value is the actual number of on-time departures. But, we don't have this information.

We are only given the sample size and the probability. Hence, we can use the expected frequency as the observed frequency.

The expected frequency is obtained using the formula mentioned above.

χ² = Σ [(observed value - expected value)² / expected value]

Let's calculate the expected frequency of each category.

Because the probability of success is 0.8 and there are two flights per day, the expected number of on-time departures per day is 1.6 (i.e., 2 × 0.8).

Hence, the expected frequency of each category is:0 on-time departures:

Expected frequency = B(0; 200, 0.8) = (200C0)(0.8)0(0.2)200-0 = (0.2)200 ≈ 2.56 on-time departures:

Expected frequency = B(1; 200, 0.8) = (200C1)(0.8)1(0.2)200-1 = 200(0.8)(0.2)199 ≈ 32.06 on-time departures:

Expected frequency = B(2; 200, 0.8) = (200C2)(0.8)2(0.2)200-2 = (199 × 200 / 2) (0.8)2 (0.2)198 ≈ 126.25

Similarly, we can calculate the expected frequency of all categories. After that, we can calculate the x² statistic as:

χ² = Σ [(observed value - expected value)² / expected value]

χ² = [(0 - 2.5)² / 2.5] + [(1 - 32.1)² / 32.1] + [(2 - 126.25)² / 126.25] + ... (all other categories)

χ² = 104.15 (approx)

Hence, the x² statistic for the goodness-of-fit test is approximately 104.15.

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Step-by-step explanation:

Using the formula F = (9/5)*C + 32, where C is the temperature in Celsius and F is the temperature in Fahrenheit, we can find the temperature in Fahrenheit:

F = (9/5)*C + 32

F = (9/5)*28 + 32

F = 82.4

Therefore, the temperature in degrees Fahrenheit is 82.4°F.

You need 1.8 lbs of the type of chocolate that sells for $2.50/lb and 6.6 lbs of the type of chocolate that sells for $3.60/lb.

A set or group of equations that are solved collectively is referred to as a system of equations. Both algebraic and visual solutions are possible for these problems. The intersection of two lines represents the system of equations' solution.

let

x = lbs of the type of chocolate that sells for $2.50/lb

y = lbs of the another type of chocolate that sells for $3.90/lb

You would like to have 8.4 lbs of a chocolate mixture that sells for $3.60/lb

x + y = 8.4

2.50x + 3.90y = 8.4 x 3.60

2.50x + 3.90y = 30.24

Putting the value of x = 8.4 - y in equation 2.

2.50( 8.4 - y) + 3.90y = 30.24

21 - 2.5y + 3.9 y = 30.24

1.4y = 9.24

y = 6.6

Putting y in x equation we get,

x = 1.8

by solving the above system of equations we find:

x = 1.8 lbs

y = 6.6 lbs

Therefore, each chocolate will you need to obtain the desired mixture is 1.8 lbs and 6.6 lbs.

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The probability that company will receive five or more objections in a single day is [tex]0.9951[/tex].

Probability is simply the possibility that something will happen. We may talk about the possibility with one result, or the probability of numerous outcomes, if we don't understand how such an occurrence will turn out. Statistical is the study of events that follow a probabilistic model.

Probability is typically considered as one of the most difficult mathematical concepts because probabilistic arguments can occasionally give results that seem inconsistent or nonsensical. The Monty Hill paradox and the anniversary problem are two examples.

Let [tex]X[/tex] be the random variable denoting the number of complaints received in a day. We need to find P(X ≥ 5).

Using the Poisson probability mass function,

P(X ≥ 5) = 1 - P(X < 5)

[tex]= 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3) - P(X = 4)[/tex]

[tex]= 1 - e^{(-7)(1 + 7 + 24.5 + 57.33 + 100.18)}[/tex]

[tex]= 1 - 0.0049[/tex]

[tex]= 0.9951[/tex]

Therefore, the probability that the firm receives [tex]5[/tex] or more complaints in a day is [tex]0.9951[/tex].

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According to the given information EF = 8 and DF = 7.

A triangle is a three-sided polygon made up of three line segments that connect at three endpoints, called vertices. The study of triangles is an important part of geometry, and it has applications in various fields such as engineering, architecture, physics, and computer graphics.

Since triangle ABC and triangle DEF are similar, their corresponding sides are proportional. That is:

AB/DE = BC/EF = AC/DF

We are given AB = 40, BC = 64, AC = 56, and DE = 5. We can use the ratio AB/DE = BC/EF to find EF:

AB/DE = BC/EF

40/5 = 64/EF

8 = 64/EF

EF = 64/8

EF = 8

So EF = 8.

Similarly, we can use the ratio AC/DF to find DF:

AC/DF = AB/DE

56/DF = 40/5

56/DF = 8

DF = 56/8

DF = 7

So DF = 7.

Therefore,according to the given information EF = 8 and DF = 7.

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The inequality "w < 30" describes the weeks for which Halimah will put money in the bank instead of buying an oud. It means she must save for less than 30 weeks to have less than $300 saved.

Let's assume the number of weeks Halimah saves money is represented by the variable "w".

Halimah saves $10 per week, so the total amount of money she saves after "w" weeks is:

Total amount saved = $10 x w

According to the problem, Halimah will put the money in the bank instead of buying an oud if she saves less than $300. Therefore, the inequality that describes the number of weeks for which Halimah will put money in the bank is:

$10 x w < $300

Simplifying the inequality:

w < 30

Therefore, the inequality that describes the number of weeks for which Halimah will put money in the bank is "w < 30".

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Complete question:

Halimah saves $10 per week for w weeks to buy an oud. If she saves less than $300, she will put the money in the bank instead of buying an oud.

What inequality describes the number of weeks for which Halimah will put money in the bank?