How many customers spent less than $20? I couldn't include a pic of a histogram.

Answer: Problems Involving FractionsIn solving word problems, first, identify what is asked. Then, look for the given facts. Establish the number sentence and the operation/s to be used. Make sure that the operation/s used will bring out the correct answer. Check the answer using the number sentence and see if it will satisfy the given condition.

Step-by-step explanation: Learning Task 2:Answers:16 1/4 square meters₱322,362.50Step-by-step explanation:Solutions:1. Given: 6 1/2 square meters - area which Ruben can paint in an hour

The probability of exponential random variables that your job will be ready before 10:01 is approximately 0.0693, or about 6.93%.

We can use the cumulative distribution function (CDF) of the exponential distribution to solve this problem. Let X be the random variable representing the time it takes to print a job. Then, X follows an exponential distribution with parameter λ = 1/12, since the expectation of X is 12 seconds.

The probability that your job will be ready before 10:01 is equal to the probability that the printer finishes the first two jobs in less than 1 minute since your job is third in line.

Let Y be the random variable representing the time it takes to print the first job. Then, Y also follows an exponential distribution with parameter λ = 1/12.

The probability that the first job is finished before 10:01 is given by:

P(Y < 60) = 1 - [tex]$e^{(-\lambda t)}$[/tex] = 1 - [tex]e^{(-(1/12)(60))}[/tex] = 0.3935

Similarly, the probability that the second job is finished before 10:01 is also 0.3935, since it is also an exponential random variable with the same parameter. Therefore, the probability that your job will be ready before 10:01 is:

P(X < 60) = P(Y < 60) × P(Y < 60) × P(X < 60) = 0.3935² × (1 - [tex]$e^{(-\lambda t)}$[/tex]) = 0.0693

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the Cartesian coordinates of the point represented by the polar coordinates (6, -π/3) are (3, -3√3).

What is a fraction?

A fraction represents a part of a number or any number of equal parts. There is a fraction, containing numerator and denominator.

To convert these polar coordinates to Cartesian coordinates (x, y), we use the following formulas:

x = r cos(θ)

y = r sin(θ)

Substituting the given values, we get:

x = 6 cos(-π/3) = 6 × (1/2) = 3

y = 6 sin(-π/3) = 6 × (-√3/2) = -3√3

Therefore, the Cartesian coordinates of the point represented by the polar coordinates (6, -π/3) are (3, -3√3).

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For a general junk food has collected data on the last 10,000 boxes,

a) The average weight of a box of their cereal is "= Average ( A:10, A : 10010)."

b) The standard deviation of the weight of their boxes of cereal "= STD ( A:10, A : 10010)."

c)

We have a general junk food has collected data on the last 10,000 boxes of cereal they produced. We have no information about the data points related to 10000 boxes of cereal produced by general junkfoods. But we can use Excel function, Let the 10000 boxes values be lie in Excel sheet from row 10 to 10010.

a) the average weight of a box of their cereal is calculated by the following excel function, " = average ( range)"

that is ' = Average ( A:10, A : 10010)'

b) For standard deviations the weight of their boxes of cereal is calculated by the following excel function , "= STD ( A:10, A : 10010)."

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Complete question:

1. Using excel, answer the following questions. Write down the Excel formulas used at each step.1. General Junkfoods has collected data on the last 10,000 boxes of cereal they produced.a. What is the average weight of a box of their cereal

b. what is the standard deviation of the weight of their boxes of cereal? c. what are 1 sigma, 2 sigma and 3 sigma values for this data? d. draw a bell graph showing these sigma values (av 1sigma, av 2sigma, av 3sigma) and the usl and lsl.

The mean number of people with the genetic mutation in a randomly selected group of 600 people is 24.

Given that about 4% of the population has a particular genetic mutation, the probability that a randomly selected individual has the mutation is

P(mutation) = 0.04

The number of people with the mutation in a group of 600 individuals follows a binomial distribution, where the number of trials is 600 and the probability of success is 0.04.

The mean of a binomial distribution is given by the formula:

mean = n × p

where n is the number of trials and p is the probability of success.

Substituting the values, we get:

mean = 600 × 0.04

mean = 24

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Euler's method with step size [tex]$h = 0.2$[/tex], we estimate [tex]$y(1.4) \approx 0.32$[/tex].

Euler's method with step size[tex]$h = 0.1$[/tex], we estimate [tex]$y(1.4) \approx 0.343$[/tex].

Euler's method to approximate the solution of the initial-value problem:

[tex]y \prime =x - xy,y(1)=0[/tex]

with step size [tex]$h = 0.2$[/tex]and [tex]$h =0.1[/tex]

Euler's method with step size [tex]$h = 0.2$[/tex], we have:

[tex]x_0 &= 1 \y_0 &= 0 \x_1 &= 1 + h = 1.2 \y_1 &= y_0 + hf(x_0, y_0) = 0 + 0.2(1-1\cdot 0) = 0.2 \x_2 &= 1.2 + h = 1.4 \y_2 &= y_1 + hf(x_1, y_1) = 0.2 + 0.2(1.2 - 1.2\cdot 0.2) = 0.32 \[/tex]

Euler's method with step size [tex]$h = 0.2$[/tex], we estimate.

[tex]$y(1.4) \approx 0.32$[/tex].

Euler's method with step size[tex]$h = 0.1$[/tex], we have:

[tex]x_0 &= 1[/tex]

[tex]y_0 &= 0[/tex]

[tex]x_1 &= 1 + h = 1.1[/tex]

[tex]y_1 &= y_0 + hf(x_0, y_0) = 0 + 0.1(1-1\cdot 0) = 0.1[/tex]

[tex]x_2 &= 1.1 + h = 1.2[/tex]

[tex]y_2 &= y_1 + hf(x_1, y_1) = 0.1 + 0.1(1.1 - 1.1\cdot 0.1) = 0.19[/tex]

[tex]x_3 &= 1.2 + h = 1.3[/tex]

[tex]y_3 &= y_2 + hf(x_2, y_2) = 0.19 + 0.1(1.2 - 1.2\cdot 0.19) = 0.266[/tex]

[tex]x_4 &= 1.3 + h = 1.4[/tex]

[tex]y_4 &= y_3 + hf(x_3, y_3) = 0.266 + 0.1(1.3 - 1.3\cdot 0.266) = 0.343 \\end {align}[/tex]

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Answer: We can use a proportion to estimate the total number of fur seal pups in Rookery A. Let x be the total number of fur seal pups in Rookery A. Then we have:

6269/x = 221/1100

Cross-multiplying, we get:

221x = 6269 * 1100

Dividing both sides by 221, we get:

x = 6269 * 1100 / 221

Simplifying, we get:

x = 31,245.25

Rounding to the nearest whole number, we get:

x ≈ 31,245

Therefore, the estimated total number of fur seal pups in Rookery A is 31,245.

Step-by-step explanation:

Two consecutive integers in algebraic language would be 7 and 8

Let's call the first integer "X" then the next consecutive integer would be "x+1".

so if the sum of the two integers is 15, we can write the following expression.

x + (x+1) = 15

Solving for x  we get  
2x + 1 = 15
2x =14
x = 7

Hence, the two consecutive integers in this case are 7 and 8.

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Translation:

Two consecutive integers in algebraic language

Answer: C

Step-by-step explanation:

Answer:

Parallelogram

Step-by-step explanation:

given that the opposite sides are parallel, then

the figure is a parallelogram

Answer: 213.75

Step-by-step explanation:

Add a zero to the hundredths place of 345.5 making it 345.50, then subtract as you would normally.

The volume of the solid is 4,503.22 in³.

What is volume?

A volume is simply defined as the amount of space occupied by any three-dimensional solid. These solids can be a cube, a cuboid, a cone, a cylinder, or a sphere. Different shapes have different volumes

The volume of a solid with a hollow cylinder can be calculated by subtracting the volume of the inner cylinder from the volume of the outer cylinder.

Assuming the dimensions in the figure are in inches, the outer cylinder has a height of 17 inches and a radius of 9 inches, so its volume is:

[tex]V_{outer} = \pi * r^2 * h[/tex]

= π × 9² × 17 ≈ 4,842.51 in³

The inner cylinder has a height of 12 inches and a radius of 3 inches, so its volume is:

[tex]V_{inner} = \pi * r^2 * h[/tex] = π × 3² × 12 ≈ 339.29 in³

To find the volume of the solid, we need to subtract the volume of the inner cylinder from the volume of the outer cylinder:

[tex]V_{solid }= V_{outer} - V_{inner}[/tex]

≈ 4,842.51 - 339.29 ≈ 4,503.22 in³

Hence, the volume of the solid is 4,503.22 in³.

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Segment CP is tangent to circle C at point B.

How to prove that the line is tangent to a circle?

Draw circle C with center at point A and radius AD = CD = DE.

Draw point P outside the circle C.

Draw segment AP and extend it to intersect the circle at point B.

Draw segment BD.

Draw segment CP.

Note that triangle BCD is isosceles, since CD = BD. Therefore, angle BDC = angle CBD.

Since angle BDC is an inscribed angle that intercepts arc BC, and angle CBD is an angle that intercepts the same arc, then angle BDC = angle CBD = 1/2(arc BC).

Since CD = DE, then angle CED = angle CDE. Therefore, angle DCE = 1/2(arc BC).

Since angles BDC and DCE are equal, then angles BDC and CBD are also equal, and triangle BPC is isosceles. Therefore, segment BP = segment PC.

Since BP = PC, then segment CP is perpendicular to segment BD, by the Converse of the Perpendicular Bisector Theorem.

Therefore, segment CP is tangent to circle C at point B.

Hence, the proof is complete.

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Answer:

The two data sets that have equal standard deviations are:

Data set A: 40, 50, 60, 60, 70, 80

Data set C: 50, 55, 60, 65, 70

To see this, we can calculate the standard deviation for each data set using a formula or a calculator. Alternatively, we can observe that data sets A and C have similar ranges and distributions, which suggests that they may have similar standard deviations. In contrast, data sets B and D have different ranges and distributions, which suggests that their standard deviations may be different.

The graph that  represents the sum w1 + w2 is: b. A line goes from (0, 0) to point (3, negative 1). On a coordinate plane, the y-axis is labeled imaginary and the x-axis is labeled real.

To find the sum of w1 and w2, we simply add their real and imaginary parts separately:

w1 + w2 = (4 + 2i) + (-1 - 3i) = 3 - i

So the real part of the sum is 3, and the imaginary part is -1. Therefore, the sum w1 + w2 corresponds to the point (3, -1) on the coordinate plane.

The graph that represents this point is option (b), where a line goes from (0, 0) to point (3, -1) on a coordinate plane with the y-axis labeled imaginary and the x-axis labeled real. The other options do not represent the correct point or are not lines passing through the origin.

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Answer:

We don't have enough information to answer this question because we don't know the relationship between the functions f(x) and j(x). The fact that the minimum graph of y = j(x) is (-1,-2) only tells us about the behavior of j(x), not f(x).

If we had more information about the relationship between the two functions, we might be able to use the fact that the minimum graph of y = j(x) is (-1,-2) to make some inferences about the minimum point on the graph of y = f(x) + 7. However, without additional information, we cannot provide a specific answer to this question.

Answer: Let's say we want to find out how many red Skittles we need to add to the bag to have the same ratio of red Skittles as in the original bag.

Suppose the original bag contains x red Skittles. Then, the ratio of red Skittles to the total number of Skittles in the bag is x/100.

Let's say we add y red Skittles to the bag, so the total number of red Skittles in the bag becomes x + y. The total number of Skittles in the bag becomes 100 + y, since we only added red Skittles.

For the ratio of red Skittles to be the same as in the original bag, we need:

(x + y) / (100 + y) = x / 100

Cross-multiplying, we get:

100(x + y) = x(100 + y)

Simplifying and rearranging, we get:

y = 100x / (100 - x)

So, we need to add 100x / (100 - x) red Skittles to the bag to have the same ratio of red Skittles as in the original bag. For example, if the original bag has 20 red Skittles, we need to add:

y = 100(20) / (100 - 20) = 25

So, we need to add 25 red Skittles to the bag to have the same ratio of red Skittles as in the original bag.

Step-by-step explanation:

The variance of the area of the circle is [tex]\pi^2\theta^{4/45}[/tex].

The mean area of the circle is [tex]\pi\theta^{2/3}.[/tex]

Let X be the radius of the circle, uniformly distributed on [0, θ].

The probability density function of X is given by:

[tex]f(x) = 1/\theta, for 0 \leq x \leq θ[/tex]

= 0, otherwise

Let Y be the area of the circle. Then[tex]Y = \pi X^2.[/tex] We want to find the mean and variance of Y.

Mean of Y:

By the law of the unconscious statistician, the mean of Y is given by:

[tex]E(Y) = E(\pi X^2) = \pi E(X^2)[/tex]

[tex]E(X^2)[/tex] using the formula for the variance of X:

[tex]Var(X) = E(X^2) - [E(X)]^2[/tex]

Since X is uniformly distributed on [0, θ], we have:

[tex]E(X) = (0 + \theta)/2 = \theta/2[/tex]

[tex]Var(X) = [(\theta - 0)^2]/12 = \theta^{2/12}[/tex]

Solving for [tex]E(X^2)[/tex], we get:

[tex]E(X^2) = Var(X) + [E(X)]^2 = \theta^2/12 + (\theta/2)^2 = \theta^{2/3}[/tex]

Substituting this into the expression for E(Y), we get:

[tex]E(Y) = \pi E(X^2) = \pi (\theta ^{2/3}) = \pi \theta^{2/3}[/tex]

Variance of Y:

To find the variance of Y, we can use the formula for the variance of a function of a random variable:

[tex]Var(Y) = E(Y^2) - [E(Y)]^2[/tex]

We can find[tex]E(Y^2)[/tex] using the law of the unconscious statistician:

[tex]E(Y^2) = E[(\pi X^2)^2] = \pi^2E(X^4)[/tex]

To find [tex]E(X^4)[/tex], we can use the formula for the fourth moment of a uniform distribution:

[tex]E(X^4) = (\theta^4 + 2\theta^2)/5[/tex]

Substituting this into the expression for[tex]E(Y^2)[/tex], we get:

[tex]E(Y^2) = \pi^2E(X^4) = \pi^2[(\theta^4 + 2\theta^2)/5] = \pi^2\theta^{4/5} + 2\pi^2\theta^{2/5}[/tex]

Substituting this and the expression for E(Y) into the formula for the variance of Y, we get:

[tex]Var(Y) = E(Y^2) - [E(Y)]^2[/tex]

[tex]= \pi^2\theta^{4/5} + 2\pi^2\theta^{2/5} - (\pi\theta^2/3)^2[/tex]

[tex]= \pi^2\theta^4/45[/tex]

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The total length of fences needed to surround the parks is 1500 feet. The length is calculated by adding up the lengths of all sides of both parks.

To find the total length of fences needed to surround the parks, we need to add up the lengths of all the sides of both parks.

For park RST, the total length of the fences needed is

RS + ST + RT = 230 + 350 + 230 = 810 ft

For park XYZ, since YX is congruent to XYZ, we can label YX as YZ for simplicity. The total length of the fences needed for park XYZ is

XY + YZ + XZ = YZ + YZ + 230 = 2YZ + 230

To find YZ, we can use the fact that park RST is congruent to park XYZ, so the corresponding sides are equal in length. This means YZ = RT = 230 ft.

Substituting this value, we get

2YZ + 230 = 2(230) + 230 = 690 ft

Therefore, the total length of fences needs to surround two parks with dimensions ARST XYZ and YX YZ is

810 + 690 = 1500 ft.

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--The given question is incomplete, the complete question is given

" The figure shows the dimensions of two city parks, where RST is congruent to XYZ and YX is congruent to XYZ. A city

employee wants to order new fences to surround both parks. What is the total length of the fences

required to surround the parks?

ST is 350 ft., XZ is 230 ft.

The total length of fences needed to surround the parks is ______

feet."--

The least to the greatest of the amount of gas bought each day last week are Tuesday, Thursday, Friday, Wednesday and Monday.

Chaz kept a record of how many gallons of gas he purchase everyday last week.

Therefore, the correct order of the least amount of gas purchased to the greatest amount of gas purchased can be represented as follows:

Therefore,

Tuesday = 3.7

Thursday = 3.73

Friday = 4.253

Wednesday = 4.256

Monday = 4.6

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For the given diagram, the square ABCD is transformed into square A'B'C'D' by the dilation using the scale factor of 5.

On a map, scales are frequently present. The scale factor in geography usually applies to how accurately the scale depicted on the map reflects actual distance. Find the corresponding sides upon that two figures before obtaining the scale factor.

Then, divide the new figure's measurement by the old figure's measurement. Your scale factor, i.e., how many times bigger or less than your new image is in comparison to the old, is the consequence.

From the diagram:

coordinate of A = (1,1)

coordinate of A' = (5,5)

Thus, the coordinates of A is multiplied by 5 to get the coordinates of A'

Same applies with the coordinates of B, C and D.

Thus, for the given diagram, the square ABCD is transformed into square A'B'C'D' by the dilation using the scale factor of 5.

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Answer: spinner: yellow, die: 1

Step-by-step explanation:

        We will look at the table given and select the answer option that correctly lines up with what we're looking for based on the given context, see attached.

        The spinner must be on yellow and the die must be on 1 or 4, this leads us to the 3rd answer option;

               spinner: yellow, die: 1

Answer:

13.416407865

Step-by-step explanation:

You wouldn't use soh cah toa

There is no angle given. Instead you should do 6²+12²=180

And then you would square root 180=13.416407865

Therefore the answer is 13.416407865

The surface area of this solid would be; 127.

To Find the surface area of the composite solid, we have;

Sides (a) area

4 * 3 = 12

12 * 2 = 24

Now Sides (b) area

7 * 3 = 21

21 * 3 = 63

Then Face (c) area

3 * 4 / 2 = 6

6 * 2 = 12

Base area

4 * 7 = 28

Total surface area

To calculate the total surface area we have to add the value of each face :

28 + 12 + 63 + 24 = 127

Thus, the surface area of this solid is 127.

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The total amount of interest paid over the life of the loan is $1863.45.

The present value of the loan.

Since there are 12 months in a year, and the loan has n-years, there are 12n monthly payments.

Let's use the formula for the present value of an annuity due:

[tex]PV = PMT \times ((1 - (1 + r) ^(-n)) / r) \times (1 + r)[/tex]

PV is the present value of the loan, PMT is the monthly payment, r is the monthly interest rate, and n is the number of months.

Substituting the given values, we get:

[tex]PV = \$800 \times ((1 - (1 + 0.12/12) ^(-12n)) / (0.12/12)) \times (1 + 0.12/12)[/tex]

[tex]PV = \$800 \times ((1 - (1.01)^(-12n)) / 0.01) \times 1.01[/tex]

[tex]PV = \$800 \times ((1 - 1.01^(-12n)) / 0.01) \times 1.01[/tex]

[tex]PV = \$800 \times ((1 - 0.887^(-n)) / 0.01) \times 1.01[/tex]

The formula for the interest paid in any given month of an annuity due:

[tex]I = PV \times r \times (1 + r) ^(m - 1)[/tex]

I is the interest paid in the 45th month, PV is the present value of the loan, r is the monthly interest rate, and m is the month.

Substituting the given values for the 45th month, we get:

[tex]\$424.45 = PV \times 0.01 \times (1 + 0.01 )^(45 - 1)[/tex]

[tex]\$424.45 = PV \times 0.01 \times (1.01)^4^4[/tex]

[tex]PV = \$424.45 / (0.01 \times (1.01)^4^4)[/tex]

PV =[tex]\$75799.45[/tex]

Now that we know the present value of the loan, we can calculate the total amount of interest paid over the life of the loan.

Let's use the formula for the total interest paid in an annuity due:

[tex]Total interest = (PMT \times n \times (n + 1) / 2) - PV[/tex]

Substituting the given values, we get:

Total interest = [tex](\$800 \times 12n \times (12n + 1) / 2) - \$75799.45[/tex]

Total interest = [tex]\$9600n^2 + \$4800n - \$75799.45[/tex]

We can solve for n by using the fact that the interest paid in the 45th month is $424.45:

[tex]\$424.45 = \$800 \times (n \times 12 - 44) \times 0.01 \times (1 + 0.01)^(45 - 1)[/tex]

[tex]\$424.45 = \$800 \times (n \times 12 - 44) \times 0.01 \times (1.01)^4^4[/tex]

n = 4.5

Substituting n = 4.5 into the formula for total interest, we get:

Total interest =[tex]\$9600 \times (4.5)^2 + \$4800 \times 4.5 - \$75799.45[/tex]

Total interest = $1863.45

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The radius of convergence is 4.

To find the radius of convergence, R, of the collection, we can use the ratio test:

[tex]lim_n→∞ |(a_(n+1)/[/tex][tex]a_n)|[/tex]

[tex]lim_n→∞ |(a_{(n+1})/[/tex]

[tex]= lim_n→∞ |(x+8) / 4| * |ln(n+1) / ln(n)|[/tex]

For the series to converge, this limit need to be less than 1. therefore, we've:

[tex]|(x+8) / 4| * lim_n→∞ |ln(n+1) / ln(n)| < 1[/tex]

For the reason that[tex]lim_n→∞ |ln(n+1) / ln(n)| = 1[/tex], we will simplify this to:

|(x+8) / 4| < 1

Taking the absolute cost under consideration, we have cases:

Case 1: (x+8)/4 < 1

In this case, we have x < -4.

Case 2: (x+8)/4 > -1

In this case, we have x > -12.

Consequently, the radius of convergence is the distance from the center of the collection (x = -8) to the closest endpoint of the c language (-12 on the left and -4 at the right):

R = min{8, 4} = 4

So, 4 is the radius of convergence.

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The condition that speaks to the circumstance is 194.99 + 2p = 284.97 where p represents the price of one game.

Let's begin by setting up the condition based on the data given.

Serena paid $194.99 for the amusement framework and two diversions that took a toll at the same cost, let's call it "p".

The whole sum that went through Serena was $284.97.

So able to set up the condition as:

194.99 + 2p = 284.97

The left-hand side of the condition represents the whole sum that went through the amusement framework and two diversions. The right-hand side speaks to the whole sum went through by Serena.

therefore, the equation that speaks to the circumstance is:

194.99 + 2p = 284.97 .

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Therefore, the solution to the system of equation is (x, y) = (-5, 9).

An equation is a mathematical statement that shows that two expressions are equal. It consists of two sides, the left-hand side and the right-hand side, separated by an equals sign (=). An equation can contain variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division.

Here,

To solve the system using linear combination, we want to eliminate one of the variables by adding the two equations together.

{3x + 4y = 21

{5x + 4y = 11

Notice that if we subtract the first equation from the second, we get:

(5x + 4y) - (3x + 4y) = 11 - 21

2x = -10

x = -5

Now we can substitute x = -5 into either of the original equations and solve for y:

3x + 4y = 21

3(-5) + 4y = 21

-15 + 4y = 21

4y = 36

y = 9

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It will take approximately 29 days for the ant population to drop below 250.

The logarithmic function to the base e is called the natural logarithmic function and it is denoted by loge.

f(x) = loge x

To find out how many days it will take for the ant population to drop below 250, we need to solve for the value of t in the equation:

A(t) = [tex]45000*(0.271)^t[/tex]< 250

We can start by simplifying the equation:

[tex]45000*(0.271)^t[/tex]< 250

[tex](0.271)^t[/tex] < 250/45000

[tex](0.271)^t[/tex]< 0.00555556

Next, we can take the natural logarithm of both sides to isolate t:

ln[[tex](0.271)^t][/tex] < ln(0.00555556)

t*ln(0.271) < ln(0.00555556)

t > ln(0.00555556) / ln(0.271)

t > 28.32

Therefore, it will take approximately 29 days for the ant population to drop below 250.

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