How many volts would it take to push 1 amp through a resistance of 1 ohm?

Answers

Answer 1
V=I x R so V= 1 x 1 =1V
Answer 2

Answer:

[tex]1\; \rm V[/tex].

Explanation:

Ohm's Law give the following relationship between the potential [tex]V[/tex] across a conductor, the electrical resistance [tex]R[/tex] of that conductor, and the current [tex]I[/tex] through that conductor:

[tex]V = I \, R[/tex].

It is given that the current through this conductor is [tex]I = 1\; {\rm A}[/tex], and that the electrical resistance of this conductor is [tex]R = 1\; \rm \Omega[/tex].

Note, that the unit of electrical resistance Ohm is a composite unit; [tex]1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}[/tex] (volts per ampere.)

Substitute the value of [tex]I[/tex] and [tex]R[/tex] into the equation [tex]V = I \, R[/tex] from Ohm's Law to find the potential across this conductor:

[tex]\begin{aligned}V &= I \, R \\ &= 1\; {\rm A} \times 1\; {\rm \Omega} \\ &= 1\; {\rm A} \times 1\; {\rm V \cdot A^{-1}} \\ &= 1\; {\rm V}\end{aligned}[/tex].


Related Questions

how to prove sand is not a fluid even if it takes the shape of a container

Answers

Solids can be any size or shape. Sand is a solid that has the ability to be poured like a liquid and take the shape of its container. It is still a solid, as each individual grain of sand has a shape of its own and keeps that shape.

Your friend has a rubber band stretched between two fingers. When you pluck the rubber band, it vibrates and makes sound. What would you have to do to make the sound a higher pitch?

To make a higher pitch, stretch the rubber band more.


To make a higher pitch, pluck the rubber band less hard.


To make a higher pitch, stretch the rubber band less.


To make a higher pitch, pluck the rubber band harder.

Answers

Answer:

I think it is   To make a higher pitch, stretch the rubber band more

Explanation:

I'm not too sure. Sry if u got it wrong

Answer:

To make a higher pitch ,pluck the rubber band more

A ball is kicked at an angel of 37° to a goalkeeper who is 24m away. What was the initial velocity of the ball?

Answers

The initial velocity of the ball when it was projected is 15.64 m/s.

The given parameters:

Angle of the projection, θ = 37⁰The range of the projectile, R = 24 m

The initial velocity of the ball is calculated by applying formula for range of projectile as follows;

[tex]R = \frac{u^2 sin(2\theta)}{g} \\\\u^2 = \frac{Rg}{sin(2\theta)} \\\\u = \sqrt{\frac{Rg}{sin(2\theta)} } \\\\u =\sqrt{\frac{24 \times 9.8}{sin(2\times 37)} } \\\\u = 15.64 \ m/s[/tex]

Thus, the initial velocity of the ball when it was projected is 15.64 m/s.

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The gravitational force on Mars is about 38% of Earth. What would a cat weighing 15 pounds on Earth weigh on Mars?

Answers

Answer: 5.7

Explanation: 38% of 15.

The weight we experience ourselves and the ability to stand in the ground is due to the gravitational pull of earth. If this pull is lower we feel weight loss. So the cat will have a weight of 5.7 pounds or 2.58 kg in mars where the gravitation is about 38% of earth.

What is gravitational force?

Gravitational force is a kind force by which a body attracts other objects into its centre of mass. Earth have strong gravitational effect on objects and thus we are all standing on the surface and everything falling from a height hits the ground.

As the mass of the object increases, gravitational effect also increases. The weight experienced by a body is the product of its mass and gravity. Thus massive body have greater weight.

Our mass is constant everywhere but weight will change according a change in gravity. Mars  have only 38% of gravity of earth. Thus the cat weighing 15 pounds on earth will loss its weight in mars by 38%.

Thus, 15 × 38/100= 5.7 pounds will be the weight of the cat in mars.

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Find the gravitational force between Earth (5.97 x 1024 kg) and the Sun (1.99 x 1030 kg) knowing they are 1.48 x 1011 m apart.

Answers

Using the gravitational force of F= G(m1*m2/r^2)

m1= 5.97 x 10^24 kg (Earth)

m2= 1.99 x 10^30 kg (Sun)

r= 1.48 x 10^11 m

G is a known value, it is 6.672 x 10^-11

All units are proper. Therefore plug in the values and you get 3.16 x 10^22 N.

Let me know if I calculated this wrong and it is something else so I can delete this. Thank you. I don't want to make other students put down the wrong answer.

Answer:

[tex]\boxed {\boxed {\sf F_g \approx 3.62 *10^{22} \ N}}[/tex]

Explanation:

We are asked to find the gravitational force between Earth and the Sun. Use the following formula:

[tex]F_g= \frac{Gm_1m_2}{r^2}[/tex]

G is the universal gravitational constant. One mass (m₁) is the Earth and the other (m₂) is the Sun. r is the distance between the planets.

G= 6.67 * 10⁻¹¹ N*m²/kg²m₁ = 5.97 * 10²⁴ kg m₂= 1.99 * 10³⁰ kg r= 1.48 *10¹¹ m

Substitute the values into the formula.

[tex]F_g = \frac{ (6.67*10^{-11} N*m^2/kg^2)(5.97*10^{24} \ kg)(1.99*10^{30} \ kg) }{ (1.48 *10^{11} \ m)^2}}[/tex]

Multiply the numerator. The units of kilograms cancel.

[tex]F_g = \frac {7.9241601 *10^{44} \ N*m^2}{ (1.48 *10^{11} \ m)^2 }[/tex]

Solve the exponent in the denominator.

[tex]F_g= \frac {7.9241601 *10^{44} \ N*m^2}{ 2.1904*10^{22} \ m^2}[/tex]

Divide. The units of meters squared cancel.

[tex]F_g=3.61767718 *10^{22} \ N[/tex]

The original values all have 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 7 in the thousandth place tells us to round the 1 up to a 2.

[tex]F_g \approx 3.62 *10^{22} \ N[/tex]

The gravitational force between Earth and the Sun is approximately 3.62 *10²² Newtons.

An object’s mechanical energy is

a
its energy of motion.
b
the sum of its potential (position) energy and kinetic (motion) energy.
c
the waste energy it produces by friction.
d
not related to the object’s mass.

Answers

Explanation:

the sum of its potential (position) energy and kinetic (motion) energy.

An object, moving with a constant velocity, travels 400 m in 25 s. What is its velocity?

Answers

v = d/t

= 400/25

= 16 m/s

I'm not sure though

A student lifts a backpack straight up with a force of 53.5 N for a distance of 0.65 m. How much work is done on the backpack?

Happy Christmas Eve!!

Answers

The answer is 34.775j because w=Fd (53.5N)(0.65m)=34.775j

Answer:

W = 34.775J

Explanation:

W = F × d

W = 53.5N × 0.65m

W = 34.775J

W = work = unknown

f = force = 53.5N

d = distance = 0.65m

please help quick
How much work is done by the people in raising the load 3 meters if the combined pulling force of the men on the rope is 700 newtons?
A.233 N·m
B. 703 N·m
C. 2,100 N·m
D. 400 N·m

Answers

Answer:

C is the right answer for the question

How many neutrons are in an atom of Carbon-13 or (613C)?

Answers

Answer: 6 OR 7

Explanation:



Tom pulls a muscle. He has to stop working to get an ice pack. Claudia continues to work and soon finishes her pile.
Power is the rate of doing work. It's calculated by dividing work by time (power = work = time). Who had more power in
this scenario? Why?

Answers

Answer:

Tom

Explanation:

if for example both their work is 40 and Tom stops working after 2 hours but Claudia continues and stops after 3 hours when you divide their work by their time Claudia will get a lower number of power.

(in your explanation maybe use different numbers based on you book or notes)

Answer:

Claudia had more power. She did more work than Tom, and she did it in less time.

Explanation:

sample answer on edmentum. maybe change it up. hope this helps:)


A racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction). It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/a to the left (-x direction).what is the magnitude of the racquetball's change in momentum?

Answers

The magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Given that a racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction).

mass m  = 42g = 42/1000 = 0.042kg

initial velocity before collision u = 7 m/s

It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/s to the left (-x direction). That is,

velocity after collision v = 7 m/s

To calculate the magnitude of the racquetball's change in momentum, we will use the formula below

Change in momentum = Mv - Mu

Since momentum is a vector quantity, we will consider the direction.

Change in momentum = 0.042 x 7 - ( 0.042 x - 7)

Change in momentum = 0.294 + 0.294

Change in momentum = 0.588 kgm/s

Therefore, the magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Learn more on momentum here: https://brainly.com/question/402617

Drag each tile to the correct location.
Match each process to where it occurs in the carbon cycle.
Ingestion
fossilization
decomposition
combustion
light
energy
oxygen
carbon
dicadde
- sugar
minerak
water
All rights reserved

Answers

The order of the location of each process in the carbon cycle are as follows;

Ingestion → Decomposition → Fossilization → Combustion

Reasons:

Ingestion; During the ingestion process, the products of the direct Sunlight and photosynthesis, which

are energy rich chemical substances are ingested by herbivores.

Decomposition; The plants and animals die and undergo decomposition.

Fossilization; A long period the decomposed plants and animals manifest

into hard petrified materials, with their parts transformed to fossils.

Combustion; The remains of plants and animals, subjected to heat and

pressure due to compression, as when as bacteria decomposition that

removes several other elements, leaving a carbon and hydrogen rich

sludge that can be processed into fuel used for combustion. The

combustion process produces carbon dioxide which restarts the cycle.

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Choose all the answers that apply.

Light _____.
A. cannot travel through a vacuum
B. slows down when traveling through denser substances
C. speeds up when traveling through more dense substances
D. travels in transverse waves
E. can be absorbed and transformed into heat

Answers

Answer:

B

Explanation:

A car moving at 60 mph slams on its brakes to stop before hitting a deer. Another identical car traveling at 60 mph slows to a stop at a stop sign. Who experiences the greatest impulse during the stop

Answers

Happy Holidays!

Recall that:

Impulse = Change in Momentum = mass × change in velocity

Since both cars are identical and have the same initial velocity of 60 mph, them breaking to a stop means that they both experience the same change in velocity.

Thus, both of the cars' impulses are equal.

12. A lathe mounted on wooden skids is to be slid down a pair of planks placed against the back of a truck.
(a) If the coefficient of friction is 0.28, what angle should the planks make with the ground in order for the lathe to slide down at constant velocity?
(b) When the planks are at this angle, will the lathe start to slide down of its own accord?

Answers

(a) The angle the planks make with the ground in order for the lathe to slide down at constant velocity is 90⁰.

(b) Yes, at this angle the lathe will start sliding at constant velocity because of the sharp steepness.

The given parameters:

coefficient of friction, μ = 0.28

The net force on the wooden skids is calculated as follows;

[tex]\Sigma F = 0\\\\F - \mu mg cos\theta = 0\\\\ma - \mu mg cos\theta = 0\\\\ma = \mu mg cos \theta \\\\a = \mu g cos\theta\\\\at \ constant \ velocity , \ a = 0\\\\0 = \mu g cos \theta\\\\cos \theta = 0\\\\\theta = 90 ^0[/tex]

Yes, at this angle the lathe will start sliding at constant velocity because of the sharp steepness.

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a flashlight operates with a current of 3.0 a and a power of 4.5 W. what is the voltage of the flashlights battery?

Answers

Answer:

V=1.5V

Explanation:

p=I×V

4.5=3×V

[tex]v = \frac{4.5}{3} [/tex]

[tex]v = \frac{3}{2} [/tex]

v=1.5

Suppose two objects are gravitationally attracted to each other with some force F. If the mass of object 1 is multiplied by a factor of five and the mass of object 2 is multiplied by a factor of two, what will the new gravitational force be between the objects?

A. F2

B. 1/2F

C. 0.1F

D. 2F/5

E. 5F

J. 10F

Please help will mark brainliest

Answers

If F = Gm₁m₂/d², and we change m₁ to 5m₁ and m₂ to 2m₂, then the new magnitude of the gravitational force is

F' = G (5m₁) (2m₂) / d²

F' = 10  Gm₁m₂ / d²

but this is really just F' = 10F. So J is the correct choice.

Hi there!

Using Newton's Law of Universal Gravitation:

[tex]\large\boxed{F_g = G\frac{m_1m_2}{d^2}}[/tex]

Fg = Force of gravity (N)

G = Gravitational Constant

m₁ = mass of object 1 (kg)

m₂ = mass of object 2 (kg)

d = distance between the objects (m)

There is a direct relationship between the masses of the objects and the resulting force of gravity, so we can plug new values in:

[tex]F_g = G\frac{5m_12m_2}{d^2}} = 10G\frac{m_1m_2}{d^2}} = 10F_g[/tex]

Thus, the correct answer is J. 10Fg.

Using techniques similar to the aluminum foil lab, how could you do an experiment to determine the volume of the filled soda bottle? What factors might limit the accuracy of your experiment?

Answers

Answer:

applications of density measurements. The densities of brass and aluminum will be calculated from mass and volume measurements.

Explanation:

draw the following vector quantity Using the coordinate system.
a. 190 newton east
b. 120km/hr, 250 north of east
c. 60 meters southwest​

Answers

The given vectors quantities can be described by their properties of both

magnitude and direction.

a. The drawing of the vector extending from point (0, 0) to (190, 0) on the coordinate plane is attached.b. The velocity vector extending from  (0, 0) to (108.76, 50.714) on the coordinate plane is attached.c. The displacement vector extending from (0, 0) to (30·√2, 30·√2) is attached.

Reasons:

a. The magnitude of the vector = 190 N

The direction in which the vector acts = East

Therefore, in vector form, we have;

[tex]\vec{F}[/tex] = 190 × cos(0)·i + 190 × sin(0)·j = 190·i

The vector can be represented by an horizontal line, 190 units long

Coordinate points on the vector = (0, 0) and (190, 0)

The drawing of the vector with the above points using MS Excel is attached.

b. Magnitude of the velocity vector = 120 km/hr. 25° North of east

Solution;

The vector form of the velocity is; [tex]\vec{v}[/tex] = 120 × cos(25)·i + 120×sin(25)·j, which gives;

[tex]\vec{v}[/tex] = 120 × cos(25)·i + 120×sin(25)·j ≈ 108.76·i + 50.714·j

[tex]\vec{v}[/tex] ≈ 108.76·i + 50.714·j

Therefore, points that define the vector are; (0, 0) and (108.76, 50.714)

The drawing of the vector is attached

c. The magnitude of the vector = 60 m

The direction of the vector is southwest = West 45° south

The vector form of the displacement is [tex]\vec{d}[/tex] = 60 × cos(45°)·i + 60 × sin(45°)·j

Which gives;

[tex]\vec{d}[/tex] = 30·√2·i + 30·√2·j

Points on the vector are therefore; (0, 0), and (30·√2, 30·√2)

The drawing of the vector is attached

Learn more about vectors here:

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give answer or fight me

Answers

The answer is that they are translucent

Answer:

translucent

Explanation:

Hope this helps! Pls give brainliest! Also, please sub to Kgirl633 on yt.

"true wisdom is knowing what you don't know"

Reader's Response/explanation


(Y'all I need help) ​

Answers

Answer:

“The only true wisdom is in knowing you know nothing.” ― Socrates. Socrates had it right. Remain humble and appreciate the fact that you don't know everything. ... Thankfully, one's search for knowledge has no end as there is always something new to learn, giving one's life meaning and purpose.

Explanation:

Answer:

knowing wisdom cool

Explanation:

lol

If Force = 200 N and Mass = 20 kg, what is acceleration?

Answers

[tex]\text{Given that,}\\\\\text{Force, F =200 N}\\\\\text{Mass, m = 20 kg}\\\\\text{Using Newton's second law,}\\\\F = ma \\\\\implies a = \dfrac{F}{m} = \dfrac{200}{20}= 10 ~ \text{ m s}^{-2}\\\\\text{The acceleration is 10 m s}^{-2}.[/tex]

A payload of mass m, where m

Answers

Answer:

where m < M is delivered to the space station. Soon after, the space station's orbit is adjusted so that it is 50 km ...

A payload of mass m, where m<M, is delivered to the space station.

What is payload?

The maximum mass that the vehicle is capable of moving is referred to as the mass's payload. The carrying capacity of a packet or other transmission data unit is referred to as a payload.

The phrase, which has military roots, is frequently used in relation to malicious code that can be executed and cause harm. A payload is a section of code that runs when hackers take advantage of a weakness. In other words, it's a module for an exploit.

It typically consists of a few commands that will execute on the targeted operating system in order to steal data and carry out other malicious deeds (such as keyloggers).

Therefore, A payload of mass m is sent to the space station, where m<M.

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The bulb in the circuit shown below does not glow. Which of following labelled parts is responsible for this?

Answers

Answer:

answer to this question is c

Answer:

3

Explanation:

because the battery's power is not functioning well

What is chemical reaction? Give an example of each of exothermic and endothermic reaction​

Answers

Answer:

A chemical reaction is a process that occurs when two or more molecules interact to form a new product(s).

Endothermic reactions are chemical reactions in which the reactants absorb heat energy from the surroundings to form products.

Example:

A popular example of an endothermic chemical reaction is photosynthesis. During this process, plants absorb energy from the Sun and convert it into carbon dioxide and water into glucose and oxygen.

An exothermic reaction releases energy into the surrounding of the system.

Example:

the chemical reaction between sodium and chlorine results in the formation of sodium chloride (also known as common salt).

The magnitude of acceleration due to gravity is

Select one:
a. 9.8 m/s

b. 8.9 m/s2

c. 4.6 m/s

Answers

Answer:

The magnitude of a gravity is always 9.8 which is later approximated to 10m/s.

Answer:

a. 9.8

Explanation:

The magnitude of acceleration due to gravity is 9.8

Why do magnets move objects in different ways?

Answers

Answer:

Magnets have two poles, called north and south. The like poles are attracted to unlike poles, but like poles repel each other. For example, the north pole of one magnet is attracted to the south pole of another. ... To make objects move with a magnet attach a piece of metal, or another magnet, to it.

A stone is thrown horizontally from the top of an inclined plane (angle of inclination θ). How would I find the initial speed of the stone if it hit the plane a distance L down the slope from the point of launch?

Answers

Answer:

S = V t     where S is the horizontal distance traveled

1/2 g t^2 = H       where H is the vertical distance traveled

t^2 = 2 H / g

V^2 = S^2 / t^2 = S^2 g / (2 H) combining equations

tan theta = H / S

V^2 = S g / (2 tan theta)

Using S = L cos theta

V^2 = L g cos theta / (2 tan theta)

Giving V in terms of L and theta

Preston goes on a camel safari. There, he travels 5 km north, then 3 km east.

Answers

7777Answer:

Explanation:

Ok but what’s the question?
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