Hudson is a waiter at a restaurant. Each day he works, Hudson will make a guaranteed wage of $30, however the additional amount that Hudson earns from tips depends on the number of tables he waits on that day. From past experience, Hudson noticed that he will get about $13 in tips for each table he waits on. How much would Hudson expect to earn in a day on which he waits on 18 tables? How much would Hudson expect to make in a day when waiting on t tables?

Answer: y-98

Step-by-step explanation:

Consequently, in this rhombus-shaped skating rink, the longest distance that may be covered without changing directions is 40 metres.

The total distance encircling a two-dimensional shape's perimeter is known as its perimeter. It represents the total length of the shape's sides. The perimeter of a rectangle, for instance, can be determined by combining the lengths of its four sides: A rectangle's perimeter equals 2 x (length + width). Other shapes, such triangles, circles, and polygons, can have their perimeters determined using the appropriate formulas.

given

The formula for the perimeter of a rhombus, which is the sum of the lengths of its four sides, can be used to determine the greatest distance that can be covered in a rhombus-shaped skating rink without changing direction.

Given that the sides are each 26 metres long, the rhombus's perimeter would be:

Perimeter: (4 x 26) = 104 metres

But, we must consider that the smaller diagonal of the skating rink measures 40 metres in order to determine the most distance that may be traversed without changing directions. This means that the skater is limited to a 40-meter radius before having to change directions.

Consequently, in this rhombus-shaped skating rink, the longest distance that may be covered without changing directions is 40 metres.

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The complete question is:- 3.- What is the maximum distance that can be traveled without changing direction in a rhombus-shaped skating rink, if each side measures 26 meters and the smaller diagonal is 40 meters?

The correct option- The perpendicular bisector of AB has the slope -1/3.

The difference between the change in y-values and the change in x-values is known as the slope of a line. This figure represents the slope of a line.

Formula for slope m = (y2 - y1)/(x2 - x1)

Line segment AB coordinates :

A (1,5) and B (9,17).

Slope m1 = (17 - 5)/(9 - 5)

m1 = 12/4

m1 = 3

The line perpendicular to AB.

Let the slope of m2.

The relation between the slopes of perpendicular lines:

m1 x m2 = -1

3 x m2 = -1

m2 = -1/3.

Thus, the slope of the line perpendicular to the given line AB is found as:  -1/3.

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Complete question:

AB in the coordinate plane has endpoints with coordinates A (1,5) and B (9,17). Which of the following is true?

The perpendicular bisector of  AB has slope 3/2.

The perpendicular bisector of AB has slope -2/3.

The perpendicular bisector of AB  has slope -2/3.

The perpendicular bisector of AB has slope -1/3.

Answer:

The number cube has 6 equally likely outcomes, so the probability of rolling a 1 or a 6 on any given roll is 2/6 = 1/3.

If Kenya rolls the number cube 90 times, we can use the expected value formula to find the expected number of times that a 1 or a 6 will land face up:

Expected number of 1's or 6's = (number of rolls) x (probability of rolling a 1 or a 6)

Expected number of 1's or 6's = 90 x (1/3)

Expected number of 1's or 6's = 30

Therefore, a reasonable prediction for the number of times that a 1 or a 6 will land face up is 30.

Answer: the answer would be 122

Step-by-step explanation:

To find the surface area you need to find the area of each face and add them together

2 (W L+H L+H W) = surface area  

2·(4·7+3·7+3·4)=122

Answer:

Step-by-step explanation:

Given dimensions of the rectangular prism ,

4"×3"×7"

We know, Total surface area of a cuboid= 2(lb+bh+hl)

where, l=length of the cuboid

 b= breadth " " "

 h= height " " "

Since, a rectangular prism holds the shape of a cuboid, therefore it's surface area should also be 2(lb+bh+hl)

Now, surface area of the rectangular prism = 2(4×3+3×7+7×4)

 =2(12+21+28)

 =2×61

 =122 square inches.

Therefore, the number of ways to choose a committee of size 10 with at least 2 men is: 961379655

We are to find the number of ways to choose a committee of size 10 with at least 2 men if there are 30 women in the club and 20 men in the club using set difference. We can use the following formulas: (1) A set difference B = {elements of A that are not in B} (2) The number of ways to choose k elements from n elements is represented by nCk.

(3) The complement of an event E is the set of all outcomes in the sample space that are not included in the outcome of E.(4) If E is an event, then P(E) represents the probability of E happening.(5) P(E') + P(E) = 1 (where E' is the complement of E).

To choose a committee of size 10 with at least 2 men, we can first find the total number of committees possible (which includes committees with 0, 1 or 2 men) and then subtract the committees that do not have at least 2 men. So, the total number of ways to choose a committee of size 10 is 50C10. Using the formula nCk = n!/k!(n-k)!, we can write it as follows: 50C10 = 50! / 10!40! = 10272278170.

The number of ways to choose a committee of size 10 with no men is 30C10.Using the formula nCk = n!/k!(n-k)!, we can write it as follows:30C10 = 30! / 10!20! = 30045015. The number of ways to choose a committee of size 10 with exactly 1 man is (20C1) * (30C9).Using the formula nCk = n!/k!(n-k)!, we can write it as follows:(20C1) * (30C9) = 20! / 1!19! * 30! / 9!21! = 47152200.

The number of ways to choose a committee of size 10 with exactly 2 men is (20C2) * (30C8). Using the formula nCk = n!/k!(n-k)!, we can write it as follows:(20C2) * (30C8) = 20! / 2!18! * 30! / 8!22! = 47502000. Therefore, the number of ways to choose a committee of size 10 with at least 2 men is:50C10 - 30C10 - (20C1) * (30C9) - (20C2) * (30C8)10272278170 - 30045015 - 47152200 - 47502000 = 961379655  Ways.

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ANSWERS:
A ) x^2 + 5/6x + 25/144 = (x + 5/12)^2

B ) x^2 - 11x + 121/4 = (x - 11/2)^2

EXPLANATION:

a. To complete the square for the equation x^2 + 5/6x + ___,

first divide the coefficient of the linear term (5/6) by 2,

which gives you 5/12.

Then, square the result:

(5/12)^2 = 25/144.

So, the equation becomes:
x^2 + 5/6x + 25/144 = (x + 5/12)^2

b. To complete the square for the equation x^2 - 11x + ___,

first divide the coefficient of the linear term (-11) by 2,

which gives you -11/2.

Then, square the result:

(-11/2)^2 = 121/4.

So, the equation becomes:

x^2 - 11x + 121/4 = (x - 11/2)^2

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The larger number if the difference of the numbers is 52 is 65.

A number is five times a smaller number. Let's find the larger number when their difference is 52.

Therefore,

let

x = smaller number

larger number = 5x

There difference is 52. Hence,

5x - x = 52

4x = 52

divide both sides of the equation by 4

x = 52 / 4

x = 13

Therefore,

larger number = 5(13) = 65

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Answer:

The first one...............

Answer: B

Step-by-step explanation:

because I did it and it was right lol

8 Cans of mandarin oranges are needed to serve a part of 200 people if each person is to receive a 3-ounce serving and each can weights 5 pounds 10 oz (9 ounces of that as liquid which you will discard).

Given that each can of mandarin oranges weighs 5 pounds 10 oz (9 ounces of that as liquid which you will discard).We are to find out how many cans of mandarin oranges are needed to serve a part of 200 people if each person is to receive a 3-ounce serving.

Convert 3 ounces into pounds and ounces

3 ounces = 3/16 pound (1 pound = 16 ounces)

Amount of mandarin oranges required by one person = 3/16 pound

Amount of mandarin oranges required by 200 people = 200 * (3/16) pound

Amount of mandarin oranges required by 200 people = 37.5 pound

Convert the amount of mandarin oranges required into cans

Weight of one can of mandarin oranges = 5 pounds 10 oz = (5*16 + 10) ounce = 90 ounce

Weight of mandarin oranges only in one can = 90 ounce - 9 ounce = 81 ounce (9 ounce is liquid which you will discard)

Number of cans required = (total weight required) / (weight of one can)Number of cans required = (37.5 * 16) / 81 Number of cans required = 7.4 cans

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We should expect the lahar to arrive at your location at 3:30 pm if we travel down the sandy river at 40 miles an hour.

The given data is as follows:

Length of river = 20 miles

Time = 3 pm

Speed = 40 miles an hour

To calculate the time, we need to use the formula,

Time required = (distance/speed)

It is given that the distance between Mount Hood and your location is 20 river miles, and the speed of the lahar is 40 miles per hour. Therefore, the time it will take for the lahar to arrive is calculated as:

Time required = distance/speed

Time required = 20 miles / 40 miles per hour

Time required = 0.5 hours = 30 min

to determine the expected arrival time at your location,

Total time required = 3.00 + 0.30  =  3.30 pm.

Therefore we can conclude that we should expect the lahar to arrive at your location at 3:30 pm.

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When the tank is tilted, the water level reaches the midpoint of the 60 cm side, which is 30 cm from the bottom of the tank. This means that the height of the water is 30 cm.

To find the depth of the water when the tank is returned to its horizontal position, we need to use the concept of similar triangles. The two triangles formed by the water level and the sides of the tank are similar, because they have the same angles.

Let x be the depth of the water in centimeters when the tank is returned to its horizontal position. Then we have:

(40 - x) / 60 = 30 / 50

Simplifying this equation, we get:

40 - x = 36

x = 4

Therefore, the depth of the water in the fish tank when it is returned to its horizontal position is 4 cm.

There are 1960 different ways to distribute 8 identical pieces of candy to the five children, where the twins get an equal amount of candy.

First, distribute the candy to the twins.

Split the 8 pieces of candy into two equal parts for the twins using combinations:

C(8, 4)

This means selecting 4 pieces of candy from the 8 identical pieces for one twin, and the remaining 4 pieces will automatically go to the other twin.

C(8, 4) is calculated as:

[tex]^8C_4 = \dfrac{8!}{4!(8-4)!}[/tex]

     = 8! / (4! * 4!)

     = (8 * 7 * 6 * 5) / (4 * 3 * 2 * 1)

     = 70

Now, you have distributed 4 pieces of candy to each of the twins. Y

In this case, you have 6 pieces of candy to distribute among 3 children, and you can use two dividers (bars) to separate the candy for each child.

This can be represented as:

OO|OO|OO

The two bars split the 6 pieces of candy into three sections for the three children.

So, you have C(6 + 2, 2) ways to distribute the remaining candy:

[tex]^{6+2}C_2 = \dfrac{8!}{2!(8-2)!}[/tex]

         = 8! / (2!(8 - 2)!)

         = 8! / (2! * 6!)

         = (8 * 7) / (2 * 1)

         = 28

Now, the total number of ways to distribute the candy

Total ways = C(8, 4) * C(8, 2) = 70 * 28 = 1960

So, there are 1960 different ways to distribute.

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The probability of consuming at least one insect fragment in more than one bar is 0.3011.

Given that you consumed seven 28.35-gram (one-ounce) bars this week from a brand at the mean contamination level. The probability of finding one or more insect fragments in a 28.35-gram chocolate bar that is produced with the mean level of contamination is 0.4875.

The probability that you consume one or more insect fragments in a single bar is 0.4875The probability that you will not consume an insect fragment in a single bar is 0.5125

The probability that you will not consume an insect fragment in any of the seven bars is 0.5125⁷ = 0.0236The probability that you consume one or more insect fragments in more than one bar is 1 - 0.0236 = 0.9764The probability that you consume one or more insect fragments in more than one bar is 0.9764.

The probability that you consume one or more insect fragments in more than one bar is 0.3011.

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The probability that a bat does not consume any mosquitoes in a 30-second interval is 0.0067379 or 0.67%.

In this case, the average rate of mosquitoes consumed by a bat is 10 per minute.

To find the rate for a 30-second interval, calculate the rate for 1 minute and then adjust it for the 30-second interval:

Average rate for 1 minute = 10 mosquitoes

Rate for 30 seconds = [tex]\dfrac{10 \,mosquitoes}{1 \,minute} \times \dfrac{1}{2}[/tex]

                                  = 5 mosquitoes

The Poisson distribution probability mass function is given by:

[tex]\[ P(X = k) = \dfrac{e^{-\lambda} \cdot \lambda^k}{k!} \][/tex]

Where:

[tex]\(\lambda\)[/tex] is the average rate of events.

In this case, to find the probability that k = 0.

So, let's plug in the values:

[tex]\(\lambda = 5\)[/tex]

[tex]\(k = 0\)[/tex], back to the formula as

[tex]\[ P(X = 0) = \dfrac{e^{-5} \cdot 5^0}{0!} \][/tex]

Calculating the probability as

[tex]\[ P(X = 0) = e^{-5}[/tex]

                [tex]= 0.0067379[/tex]

Therefore, the probability is 0.0067379 or 0.67%.

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Answer:

Hey Sweetheart!

z=4

4x4x4= 64

Hope this Helps!!!

can we see a picture or equation

There are 4 different weekly plans that meet the condition

If Tycho wants to go for a run on the same weekdays every week, there are 7 choices for the first day of the week, 6 choices for the second day of the week, and 5 choices for the third day of the week (since he can't run on two consecutive days).

However, we have to be careful not to overcount the number of plans that meet the conditions. For example, if Tycho chooses Monday and Tuesday as his running days, that's the same as choosing Tuesday and Monday.

To avoid overcounting, let's first count the total number of possible plans, regardless of whether they meet the conditions or not. We can choose any two days of the week for Tycho to run, which can be done in 7 choose 2 ways (or C(7,2) ways), since order doesn't matter.

C(7,2) = 7!/(2!(7-2)!) = 21

So there are 21 possible plans, regardless of whether they meet the conditions or not.

Now let's count the number of plans that meet the conditions. Since Tycho wants to run on two days a week and not on consecutive days, there are only two possible patterns: (1) run on Monday and Thursday, or (2) run on Tuesday and Friday.

Each pattern can be done in 2 ways: either run on Monday and Thursday, or run on Thursday and Monday. Similarly, either run on Tuesday and Friday, or run on Friday and Tuesday.

So there are 4 plans that meet the conditions: (Monday, Thursday), (Thursday, Monday), (Tuesday, Friday), and (Friday, Tuesday).

Therefore, there are 4 different weekly plans that meet the condition

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The statement "Cleanups may be carried out by the Environmental Protection Agency or private parties" is true of the Comprehensive Environmental Response, Compensation, and Liability Act (CERCLA), also known as Superfund.

What is the Comprehensive Environmental Response, Compensation, and Liability Act (CERCLA)?

The Comprehensive Environmental Response, Compensation, and Liability Act (CERCLA), commonly known as Superfund, is a United States federal law aimed at cleaning up sites contaminated with hazardous substances as well as preventing future hazardous waste site contamination.

CERCLA was passed by the United States Congress in December 1980 as a means of counteracting the increasing risk of hazardous waste sites in the United States.

What does CERCLA cover?

CERCLA was enacted to offer a federal "Superfund" to clean up uncontrolled or abandoned hazardous waste sites, as well as responding to oil spills, chemical disasters, and other emergencies that present a threat to the public health and the environment.

Cleanups may be carried out by the Environmental Protection Agency or private parties.

When it comes to financing these cleanups, the law mandates that those responsible for the contamination pay for the cleanup or those who do not take responsibility for the pollution.

The legislation was enacted to provide for the cleanup of the country's most hazardous waste sites and to ensure that businesses that generate hazardous waste are held responsible for their toxic contributions to the environment.

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The height of the given cylinder with radius 1.6 meters is 11.81 meters.

A cylinder is a solid made up of two congruent circles in parallel planes, respective interiors, and all the parallel line segments with ends on the circular regions that are perpendicular to the took the shape the centers of both circles.

A three-dimensional solid's volume is the amount of room it occupies up. When calculating the volume, make sure that each of the quantities belong to the same unit.

Radius r =  1.6 meters.

Volume of cylinder V = 95 cubic meters

Formulae for volume of cylinder = πr²h

Height = ?

V = πr²h

95 = 3.14  * 1.6² * h

h = 95 /(3.14  * 1.6²)

h = 11.81

Thus, the height of the given cylinder with radius 1.6 meters is 11.81 meters.

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Answer:

Rewrite the expression using the negative exponent rule b−n=1bn b - n = 1 b n . 1y98 1 y 9 8.

Step-by-step explanation:

The percentage of 65 out of 140 will be 46.428%.

The amount of any product is given as though it was a proportion of a hundred. The ratio can be expressed as a quarter of 100. The phrase % translates to one hundred percent. It is symbolized by the character '%'.

The percentage is given as,

[tex]\text{Percentage (P) = [Final value - Initial value] / Initial value x 100}[/tex]

The whole numbers are 65 and 140.

Then the percentage is written as,

[tex]P = (65 \div 140) \times 100[/tex]

[tex]P=0.46428 \times 100[/tex]

[tex]P=46.428\%[/tex]

The percentage of 65 out of 140 will be 46.428%.

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To enlarge Shape A by a scale factor of 1.5 with the center of enlargement (0, 0), we have to multiply every length by 1.5.

Enlargement of Shape A

Enlargement of a shape is when it is either stretched or shrunk in one or both directions. The original shape is called the pre-image, while the new shape is called the image. What is the centre of enlargement?

The center of an enlargement is the point about which all of the points of the pre-image are scaled to obtain the image. When the scale factor is greater than 1, the image of the pre-image is an enlargement. When the scale factor is between 0 and 1, the image of the pre-image is a reduction.In an enlargement, each point on the pre-image is mapped onto a corresponding point on the image along a straight line which goes through the centre of enlargement.

The new shape has a larger size than the original shape. To expand shape A by a scale factor of 1.5, you need to multiply each length by 1.5. You have to create new points. It's easy to use a scale ruler to make sure each length is multiplied by 1.5.

A Centre of enlargement is a point in the coordinate plane that enlarges or shrinks a figure by some scale factor. In the problem, the center of enlargement is (0, 0).

Thus, we have to extend every length of Shape A by 1.5, and our scale factor is 1.5. We get Shape B by doing so. Now, we can conclude that to enlarge Shape A by a scale factor of 1.5 with the center of enlargement (0, 0), we have to multiply every length by 1.5.

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The equation representing the situation is 4x = y - 1, where x is the number of households with one pet and y is the total number of households. This can be answered by the concept of Simple equation.

Let's assume that there are x households with a single pet. The number of households with no pets is given as one-fourth of the number of households with multiple pets, which means there are 4 times as many households with multiple pets as there are households with no pets. Let's represent the total number of households as y.

Therefore, we can say that the number of households with no pets is (y - x)/4, and the number of households with multiple pets is 3(y - x)/4 since there are 4 times as many households with multiple pets as there are households with no pets.

Now, we can use the given information that the number of households with no pets is one-fourth of the number of households with multiple pets to write the equation:

(y - x)/4 = x/3

Solving for y, we get:

y = 4x + 3x/4 = 16x/4 + 3x/4 = 19x/4

But we are given that the total number of households y includes the households with one pet, so we can write:

y = x + (y - x)/4 + 3(y - x)/4 = x + y/4

Substituting the value of y from the previous equation, we get:

19x/4 = x + 19x/16

Solving for x, we get:

x = 16/3

Therefore, the equation representing the situation is 4x = y - 1, where x = 16/3 and y = 19x/4, which simplifies to:

4(16/3) = y - 1

y = 21

Therefore, there are 16 households with one pet and 5 households without any pets.

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The given image is trapezoid and to obtain the image there are two different ways: 1. Plotting the points 2. Transformations

What is trapezoid?

In geometry, a trapezoid is a four-sided polygon that has at least one pair of parallel sides. The parallel sides of a trapezoid are called bases, while the non-parallel sides are called legs.

The image below appears to be a trapezoid with vertices at A(2,2), B(4,5), C(6,5), and D(8,2). There are several ways to obtain this image, but here are two possible methods:

Method 1: Plotting the Points

One way to obtain the image is to plot the points A, B, C, and D on a coordinate plane, and then connect them in the correct order to form the trapezoid. Here are the steps:

Draw a coordinate plane with x and y axes.

Plot the point A at (2,2).

Plot the point B at (4,5).

Plot the point C at (6,5).

Plot the point D at (8,2).

Connect the points A, B, C, and D in the order ABDC to form the trapezoid.

Method 2: Transformations

Another way to obtain the image is to start with a reference trapezoid with known vertices, and then apply a sequence of transformations to obtain the desired trapezoid. Here are the steps:

Start with a reference trapezoid with vertices at (0,0), (2,3), (4,3), and (6,0). This trapezoid has the same shape as the desired trapezoid, but is located in a different position on the coordinate plane.

Translate the reference trapezoid 2 units to the right and 2 units up by adding (2,2) to each vertex. This results in a trapezoid with vertices at (2,2), (4,5), (6,5), and (8,2), which is the desired trapezoid.

(Optional) Rotate or reflect the trapezoid as desired to obtain different orientations or symmetries.

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The ladder reaches the height of approximately 16.03 feet up the wall. (Rounded to the nearest hundredth of a foot)

We can use trigonometry to solve this problem. Let h be the height up the wall that the ladder reaches, and let θ be the angle that the ladder makes with the ground. We know that the length of the ladder (hypotenuse) is 16 feet and the angle θ is 78 degrees.

We can use the trigonometric function tangent (tan) to find the height h:

tan(θ) = opposite/adjacent

In this case, the opposite side is the height h, the adjacent side is the distance from the ladder to the wall (which is the same as the distance from the wall to Lauren), and the angle θ is 78 degrees. So we have:

tan(78°) = h/x

where x is the distance from the ladder to the wall. Solving for h, we get:

h = x * tan(78°)

We don't know the value of x, but we can use the fact that the ladder is 16 feet long to find it. Using the Pythagorean theorem, we have:

x^2 + h^2 = 16^2

Substituting h = x * tan(78°), we get:

x^2 + (x * tan(78°))^2 = 16^2

Simplifying, we get:

x = 16 / √(1 + tan^2(78°))

x ≈ 3.83 feet

Finally, we can substitute x into our equation for h:

h = x * tan(78°)

h ≈ 16.03 feet

Therefore, the ladder reaches approximately 16.03 feet up the wall. Rounded to the nearest hundredth of a foot, the answer is 16.03 feet.

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Answer:yes it is a triangle

Step-by-step explanation:

let's assume this triangle's sides are a,b and c.

we know this equation: [tex]a+b > c > |a-b|\\c+b > a > |c-b|\\a+c > b > |a-c|\\a=6\\b=7\\c=9\\13 > 9 > 1--- > which is true\\16 > 6 > 2----- > which is true as well\\15 > 7 > 3------ > it is true,too\\all of this equations are true so, this is a triangle[/tex]

Answer: B $2,251.80

Step-by-step explanation:

:)

6. f(x)g(x)+h(x) = 20x3-4x. This answer is arrived at by using the rules of algebra and the values of the given functions.

7. f(x)g(x) = -15x2 - 18x - 15

Polynomials are algebraic expressions consisting of variables and coefficients that are combined through addition, subtraction, multiplication and division operations. For example, the polynomial 4x² + 3x - 5 can be written as the sum of 4x², 3x and -5.

6. In order to calculate f(x) g(x)+h(x), it is necessary to first multiply f(x) and g(x). Since f(x)=4x and g(x) = 5x2-4, it follows that f(x)g(x)=20x3-4x. Next, it is necessary to add h(x) to this product. Since h(x) = 9x, it follows that f(x)g(x)+h(x) = 20x3-4x+9x = 20x3-4x. Since each coefficient is correctly represented in the answer, it follows that the correct answer is 20x3-4x.

Multiplying f(x) and g(x) gives the product of 20x3-4x, and adding h(x) to this product gives the sum of 20x3-4x. As each coefficient is correctly represented in the answer, the correct answer is 20x3-4x.

7. The product of two polynomials is found by multiplying each term of one polynomial by each term of the other polynomial. This is known as the FOIL method (First, Outer, Inner, Last).

The first term is the product of the first terms of each polynomial, which is 3x x 4x = 12x2.

The second term is the product of the outer terms, which is 3x x -5x = -15x2.

The third term is the product of the inner terms, which is 5 x -5x = -25x.

Finally, the fourth term is the product of the last terms of each polynomial, which is 5 x -3 = -15.

We can now combine the terms to get the product of the two polynomials, which is:

f(x)g(x) = -15x2 - 18x - 15.

Therefore, the correct coefficient for each term is -15x2 for the first term, -18x for the second term, and -15 for the third term.

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