The value of the side labelled x is equal to 3.8 to the nearest tenth using the trigonometric ratio of sine.
What is trigonometric ratios?The trigonometric ratios is concerned with the relationship of an angle of a right-angled triangle to ratios of two side lengths.
The basic trigonometric ratios includes;
sine, cosine and tangent.
Considering the sine of angle 41°
sin 41° = 2.5/x {opposite/hypotenuse}
x = 2.5/sin 41° {cross multiplication}
x = 3.8106
Therefore, the value of the side labelled x is equal to 3.8 to the nearest tenth using the trigonometric ratio of sine.
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6. Kibo is a Japanese laboratory on the
International Space Station. It is a cylinder
11.2 meters long with a radius of 2.2 meters.
Compare its volume to the volumes of Destiny
and Columbus.
Based on the provided information, we can say that Kibo has a volume of approximately 54.01 cubic meters.
To compare the volume of Kibo, Destiny, and Columbus, we need to calculate the volumes of each module.
The volume of a chamber can be determined utilizing the equation V = πr^2h, where r is the span and h is the level (or length for this situation) of the chamber.
For Kibo:
Radius (r) = 2.2 meters
Length (h) = 11.2 meters
V_kibo = π * (2.2^2) * 11.2
= 4.84 * 11.2
≈ 54.01 cubic meters
For Destiny and Columbus, we would need their respective dimensions to calculate their volumes using the same formula.
Destiny is a U.S. laboratory module on the International Space Station. It is a multi-sided module, so we would need the measurements of each side to calculate its volume.
Columbus is a European laboratory module, which is also multi-sided.
Without the specific dimensions of Destiny and Columbus, we cannot accurately compare their volumes to Kibo. However, based on the provided information, we can say that Kibo has a volume of approximately 54.01 cubic meters.
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Is the following a statistical question?
) How many yards are in one mile?
yes
No
Hello!
Answer:
No
Explanation:
A statistical question is answered by collecting data that exhibits variability
[tex]\Huge \fbox{Answer = No}[/tex]
[tex]\Huge \fbox{Step-by-step explanation:}[/tex]What are statistical questions?Statistical questions are open ended questions that are created to gather information or data about a population or a sample. Depending on the population or sample being investigated, they often involve variability and can have a variety of possible responses.
Why is the question not statistical?Because it is a straightforward factual question that can be answered with a single value, the question being asked is not a statistical one.
There are 1,760 yards in a mile, hence the answer to this question is an exact number. There is no variability or data gathering involved with this response. As a result, the question is not a statistical question.
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[(3/4) is to -6 / (3/4) is to 3]is to x = (3/4) is to -9
The value of x in the proportion is -9.
How to determine the value of xTo solve the proportion [(3/4) is to -6] is to [(3/4) is to 3] is to x = [(3/4) is to -9], we can cross-multiply and solve for x.
Starting with the left side of the proportion:
[(3/4) is to -6] is to [(3/4) is to 3]
Cross-multiplying:
(3/4) * 3 = (3/4) * (-6)
Simplifying:
9/4 = -18/4
Now, moving to the right side of the proportion:
[(3/4) is to -9]
Cross-multiplying:
x * (3/4) = (3/4) * (-9)
Simplifying:
(3/4) * x = -27/4
To solve for x, we can multiply both sides of the equation by the reciprocal of (3/4), which is 4/3:
(4/3) * [(3/4) * x] = (4/3) * (-27/4)
Simplifying:
x = -9
Therefore, the value of x in the proportion is -9.
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Complete the statement below to explain how this model shows that 12÷23=34.
Answer:
Hope this helps :)
Step-by-step explanation:
[tex]\frac{1}{2}[/tex] ÷ [tex]\frac{2}{3}[/tex]
When dividing by a fraction, we just have to multiply by the reciprocal, making the equation:
[tex]\frac{1}{2}[/tex] × [tex]\frac{3}{2}[/tex]
Then we multiply and end up with:
[tex]\frac{1}{2}[/tex] × [tex]\frac{3}{2}[/tex] [tex]=\frac{3}{4}[/tex]
Psychology: Ethical guidelines are established to help professional psychologists maintain
A. Objectivity
B. Scientific method
C. Professional behavior
D. Continuing education
Ethical guidelines are established to help professional psychologists maintain Professional behavior.
Professional behavior refers to the conduct and standards expected of psychologists in their professional practice. Ethical guidelines provide a framework that outlines the principles, values, and standards that psychologists should follow in their interactions with clients, colleagues, and the broader community.
These guidelines promote ethical behavior by setting expectations for confidentiality, informed consent, competence, integrity, and avoiding conflicts of interest, among other aspects. They ensure that psychologists prioritize the well-being and rights of their clients, maintain professional boundaries, and uphold ethical standards in research and practice.
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How many miles are there in 76 kilometers?
Answer:
There are 47.2242 miles in 76 kilometers.
1.6 km = 1 mile
76 km = 76/1.6 = 47.5 mile
There are 47.5 miles in 76 kilometers.
solve question 5 please
The value of all the expression which have x = 5 asymptotes are,
⇒ g (x) = 3 log (x - 5)
⇒ g (x) = log₁₀ (- x + 5) - 4
⇒ f (x) = (3x + 20) / (x - 5)
We have to given that,
All the expressions are,
⇒ g (x) = 3 log (x - 5)
⇒ f (x) = √(x - 5) + 2
⇒ h (x)= eˣ⁻⁵
⇒ g (x) = log₁₀ (- x + 5) - 4
⇒ h (x) = - ∛(x - 5) + 1
⇒ f (x) = (3x + 20) / (x - 5)
Now, We can check all the expressions for which have x = 5 asymptotes.
Hence, We can substitute x = 5 in each expression and check all expression as which are not defined at x = 5,
⇒ g (x) = 3 log (x - 5)
Substitute x = 5;
⇒ g (x) = 3 log (5 - 5)
⇒ g (x) = 3 log (0)
Which is undefined.
⇒ f (x) = √(x - 5) + 2
Substitute x = 5;
⇒ f (x) = √(5 - 5) + 2
⇒ f (x) = 2
Which is defined.
⇒ h (x)= eˣ⁻⁵
Substitute x = 5;
⇒ h (x)= e⁻⁵
Which is defined.
⇒ g (x) = log₁₀ (- x + 5) - 4
Substitute x = 5;
⇒ g (x) = log₁₀ (- 5 + 5) - 4
⇒ g (x) = log₁₀ (0) - 4
Which is undefined.
⇒ h (x) = - ∛(x - 5) + 1
Substitute x = 5;
⇒ h (x) = - ∛(5 - 5) + 1
⇒ h (x) = 1
Which is defined.
⇒ f (x) = (3x + 20) / (x - 5)
Substitute x = 5;
⇒ f (x) = (3x + 20) / (5 - 5)
⇒ f (x) = (15 + 20) / (0)
Which is undefined.
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what is the quotient (6x 10
Answer:60
Step-by-step explanation: because I Maltiply 6 by 6 times
50 Points! Multiple choice algebra question. Photo attached. Thank you!
The value of x, applying the trigonometric ratios, is given by the following option:
B) 8.0.
What are the trigonometric ratios?The three trigonometric ratios are the sine, the cosine and the tangent, and they are obtained according to the rules presented as follows:
Sine of angle = opposite side/hypotenuse.Cosine of angle = adjacent side/hypotenuse.Tangent of angle = opposite side/adjacent side = sine/cosine.For this problem, we have that side x is opposite to the angle of 28º, while the hypotenuse has a length of 17.
Hence the length x is obtained as follows:
sin(28º) = x/17
x = 17 x sine of 28 degrees
x = 8.
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100 Points! Algebra question. Use the given key features to sketch a nonlinear graph. Photo attached. Thank you!
The non-linear graph of the function y = -(x - 1)² + 1. is given by the image presented at the end of the answer.
When a function is positive and when it is negative?We have to look at the graph of the function relative to the x-axis, as follows:
A function is positive when it is above the x-axis.A function is negative when it is below the x-axis.The function has a maximum point at (1,1), meaning that:
The function is increasing for x > 1.The function is decreasing for x < 1.Considering the end behavior of the function, that it goes to negative infinity at both tails of the graph, a function that satisfies these features is given as follows:
y = -(x - 1)² + 1.
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4. For each babysitting job. Adam charges a fee for his bus fare plus an hourly rate. The graph shows how he calculates the cost of a babysitting job. Write a linear function in the form
y = mx + b to represent the situation.
Ay = 3x+2
B. y = 3x+1
C. y = 6x +2
D. y =-6x+2
The equation of the graph is,
⇒ y = 6x + 2
Since, The equation of line in point-slope form passing through the points
(x₁ , y₁) and (x₂, y₂) with slope m is defined as;
⇒ y - y₁ = m (x - x₁)
Where, m = (y₂ - y₁) / (x₂ - x₁)
We have to given that;
For each by sitting job. Adam charges a fee for his bus fare plus an hourly rate.
And, The graph shows how he calculates the cost of a babysitting job.
Now, By graph;
Two points on the line are (1, 8) and (2, 14).
Now,
Since, The equation of line passes through the points (1, 8) and (2, 14).
So, We need to find the slope of the line.
Hence, Slope of the line is,
m = (y₂ - y₁) / (x₂ - x₁)
m = (14 - 8)) / (2 - 1)
m = 6 / 1
m = 6
Thus, The equation of line with slope 6 is,
⇒ y - 8 = 6 (x - 1)
⇒ y - 8 = 6x - 6
⇒ y = 6x + 2
Therefore, The equation of line will be;
⇒ y = 6x + 2
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What postulate or theorem allows you to state that angle DEF is congruent to angle GHJ
Then you can state that angle DEF is congruent to angle GHJ.
The postulate or theorem that allows you to state that angle DEF is congruent to angle GHJ is the Angle-Angle (AA) Postulate.
This postulate states that if two angles of one triangle are congruent to two angles of another triangle, then the third pair of angles must also be congruent.
In this case, if you have two triangles, one with angles DEF and the other with angles GHJ, and
you know that angle D is congruent to angle G and angle E is congruent to angle H, then by the AA Postulate, you can conclude that angle F is congruent to angle J.
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Which measure would you describe the center of the data?
The choice of measure depends on the characteristics of the data and the purpose of the analysis.
The measure commonly used to describe the center of the data is the arithmetic mean or average. The arithmetic mean is calculated by summing all the data points and dividing the sum by the total number of data points. It provides a representative value that balances the contributions of all the data points.
Another measure of center is the median, which represents the middle value when the data is arranged in ascending or descending order. Unlike the mean, the median is not affected by extreme values or outliers, making it a robust measure of central tendency.
Additionally, there is the mode, which represents the most frequently occurring value in the dataset. It can be useful in cases where identifying the most common observation is important.
Each measure has its strengths and limitations, and researchers need to consider the nature of the data and the research question at hand to determine the most appropriate measure of center
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What is the probability that either event will occur?
25
A
5
B
15
5
P(A or B)=P(A) + P(B) - P(A and B)
P(A or B) = [?]
Enter as a decimal rounded to the nearest hundredth.
Enter
If the events A and B are mutually exclusive, meaning they cannot occur simultaneously, then the probability of both events occurring together is zero. In this case, the formula simplifies to P(A or B) = P(A) + P(B).
The probability that either event A or event B will occur can be calculated using the addition rule of probability. According to this rule, the probability of either event A or event B occurring is equal to the sum of the individual probabilities of each event minus the probability of both events occurring together.
In other words, P(A or B) = P(A) + P(B) - P(A and B)
However, if the events A and B are not mutually exclusive, then the probability of both events occurring together needs to be subtracted from the sum of their individual probabilities to avoid double-counting.
So, the final answer to the question "What is the probability that either event will occur?" depends on the specific probabilities of events A and B and whether they are mutually exclusive or not.
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HELP ME ASAP
An object is launched at 39.2 meters per second (m/s) from a 42.3-meter tall platform. The equation for the object's height s at time t seconds after launch is s(t) = -4.9t^2 +39.2t + 42.3t, where s is in meters.
Create a table of values and graph the function.
Approximately when will the object hit the ground?
SHOW YOUR WORK
A. A table of values and graph of the function is shown below.
B. The object would hit the ground at approximately 8.963 seconds.
How to create a table of values and graph the function?Based on the information provided, we can logically deduce that the height (s) in meters, of this object above the ground is related to time by the following quadratic function:
s(t) = -4.9t² +39.2t + 42.3
When t = 0, s(t) is given by;
s(0) = -4.9(0)² +39.2(0) + 42.3
s(0) = 42.3
When t = 1, s(t) is given by;
s(1) = -4.9(1)² +39.2(1) + 42.3
s(1) = 76.6
When t = 2, s(t) is given by;
s(2) = -4.9(2)² +39.2(2) + 42.3
s(2) = 101.1
Therefore, the table can be created as follows;
Time (t) Height s(t)
0 43.3
1 76.6
2 101.1
3 115.8
4 120.7
5 115.8
Part B.
Generally speaking, the height of this object would be equal to zero (0) when it hits the ground. By critically observing the graph (see attachment), we can logically deduce that the object would hit the ground at approximately 8.963 seconds.
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Find the slope of the line that passes through the given points4,7) and (4, -6).
Answer:
undefined
Step-by-step explanation:
To find the slope of the line passing through the points (4, 7) and (4, -6), we can use the slope formula:
m = (y₂ - y₁) / (x₂ - x₁)
Substituting the coordinates of the points (4, 7) and (4, -6) into the formula:
m = (-6 - 7) / (4 - 4)
m = (-13) / (0)
The denominator is zero, which means the line is vertical and parallel to the y-axis. When the denominator is zero, the slope is undefined.
Therefore, the line passing through the points (4, 7) and (4, -6) has an undefined slope.
In the diagram below of triangle BCD, E is the midpoint of BD and Fis
the midpoint of CD. If EF = -9x + 82, and BC = 80 - 6x, what is
the measure of BC?
The measure of BC is 48x - 168.
In the given diagram of triangle BCD, we are told that E is the midpoint of BD and F is the midpoint of CD. Let's denote the measure of BC as y.
Since E is the midpoint of BD, we can say that BE = ED. Similarly, F is the midpoint of CD, so CF = FD.
Using the information given, we can write the equation EF = -9x + 82. Since F is the midpoint of CD, we can substitute FD for EF, so FD = -9x + 82.
Also, we know that BC = 80 - 6x.
In triangle BCD, we can write the equation BC = BE + EF + FD.
Substituting the given values, we have:
80 - 6x = (BE) + (-9x + 82) + (-9x + 82).
Simplifying the equation:
80 - 6x = BE - 9x + 82 - 9x + 82.
Combining like terms:
80 - 6x = BE - 18x + 164.
Moving the variables to one side and constants to the other side:
6x - BE + 18x = 164 - 80.
Combining like terms:
24x - BE = 84.
Rearranging the equation:
BE = 24x - 84.
Since E is the midpoint of BD, we can write:
BE = BD/2.
Substituting the value of BE:
BD/2 = 24x - 84.
Simplifying the equation:
BD = 48x - 168.
We are required to find the measure of BC, which is y. From the equation BC = BD, we have:
y = 48x - 168.
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HELP PLS!
Scott had 1 ten dollar bill, 2 Five dollar bill and 6 one dollar bills in his wallet. He pulled out one bill at random. What is the probability that it was an five dollar bill
Answer:
B: 2/9
Step-by-step explanation:
There are a total of 9 bills in Scott's pocket, and he has 2 five dollar bills.
This means that the probability of pulling out a 5 dollar bill is 2/9.
12. The map shows three bus stations at points A, B and C. A tour from station A to the Zoo and the Port and back to A is 10 km long. A tour from station B to the Park and the Zoo and back to B is 12 km long. A tour from station C to the Port and the Park and back to C is 13 km long. Also. A tour from the Zoo to the Park and the Port and back to the Zoo is 15 km long. How long is the shortest tour from A to B to Cand back to A? (A) 18 km (B) 20 km (C) 25 km (D) 35 km (6) 50 km
The shortest tour from A to B to C and back to A is 50 km.
We have,
A to Zoo and Port and back to A: 10 km
B to Park and Zoo and back to B: 12 km
C to Port and Park and back to C: 13 km
Zoo to Park and Port and back to Zoo: 15 km
To calculate the shortest tour from A to B to C and back to A, we can add up the distances between each pair of stations:
A to Zoo and Port and back to A (10 km)
Zoo to Park and Port and back to Zoo (15 km)
B to Park and Zoo and back to B (12 km)
C to Port and Park and back to C (13 km)
So, Total distance: 10 + 15 + 12 + 13 = 50 km
Therefore, the shortest tour from A to B to C and back to A is 50 km.
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Suppose a copy machine is set to reduce a picture that's 8.5 inches by 11 inches to picture dimensions that are one-half the original size. What proportion shows this reduction?
A) 8.5∕11 = 5.5∕4.25
B) 8.5∕11 = 2.125∕2.75
C) 8.5∕11 = 17∕22
D) 8.5∕11 = 4.25∕5.5
Answer:
D
Step-by-step explanation:
To reach this, you would divide both by half.
8.5 ÷ 2= 4.25
11 ÷ 2= 5.5
therefore, D
The carrying capacity of a drain pipe is directly proportional to the area of its cross- section. If a cylindrical drain pipe can carry 36 litres per second, determine the percentage increase in the diameter of the drain pipe necessary to enable it to carry 60 litres per second.
Step-by-step explanation:
Let's start by using the formula for the volume of a cylinder:
V = πr^2h
where V is the volume of the cylinder, r is the radius of the cylinder, h is the height of the cylinder, and π is a mathematical constant (approximately equal to 3.14).
Since we are dealing with a drain pipe, we can assume that the height of the cylinder is fixed and does not change. Therefore, we can rewrite the formula as:
V = πr^2h = Ah
where A is the cross-sectional area of the cylinder.
Now, let's use the given information that the drain pipe can carry 36 litres per second. We know that the volume of water that passes through the pipe in one second is equal to 36 litres. We can therefore write:
36 = Ahv
where v is the velocity of the water flowing through the pipe. Since we are assuming that the height of the cylinder is fixed, we can simplify this equation to:
36 = Av
Now we need to determine the percentage increase in the diameter of the drain pipe necessary to enable it to carry 60 litres per second. Let's call the new diameter d2 and the old diameter d1. We can set up a proportion to solve for d2:
A1/A2 = d1^2/d2^2
We know that A1 and A2 are proportional to the volumes of water the pipe can carry, so we can write:
A1/A2 = 36/60
Simplifying this equation, we get:
A1/A2 = 3/5
Substituting in the formula for the cross-sectional area of a cylinder, we get:
πd1^2/4 / πd2^2/4 = 3/5
Simplifying further, we get:
d1^2/d2^2 = 3/5
Taking the square root of both sides, we get:
d1/d2 = sqrt(3/5)
Now we can solve for d2:
d2 = d1 / sqrt(3/5)
We want to know the percentage increase in the diameter, which we can find using the formula:
% Increase = (New Value - Old Value) / Old Value x 100%
Substituting in our values, we get:
% Increase = (d1 / sqrt(3/5) - d1) / d1 x 100%
Simplifying, we get:
% Increase = (1 / sqrt(3/5) - 1) x 100%
Using a calculator, we get:
% Increase ≈ 34.64%
Therefore, the percentage increase in the diameter of the drain pipe necessary to enable it to carry 60 litres per second is approximately 34.64%.
4. For each babysitting job, Adam charges a fee for his bus fare plus an hourly rate. The graph shows how he calculates the cost of a babysitting job. Write a linear function in the form
y = mx + b to represent the situation.
Ay = 3x+2
B. y = 3x+1
C. y = 6x+2
D. y = -6× + 2
y = 6x + 2 is the function which Adam charges a rate of $6 per hour and an additional fee of $2 for the bus fare.
The linear function in the form y = mx + b represents the situation where y represents the cost of the babysitting job
x represents the number of hours, "m" represents the hourly rate, and "b" represents the additional fee (bus fare).
y = 3x + 2 represents an hourly rate of 3 and an additional fee of 2.
y = 3x + 1 represents an hourly rate of 3 and an additional fee of 1.
y = 6x + 2 represents an hourly rate of 6 and an additional fee of 2.
y = -6x + 2 represents a negative hourly rate of -6 and an additional fee of 2.
Hence, y = 6x + 2 is the which Adam charges a rate of $6 per hour and an additional fee of $2 for the bus fare.
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Given that q-5 is a solution of the equation 2(3+x)=3q-3+5x, find the value of q and of x.
Answer:
[tex]q=4, x=-1[/tex]
Step-by-step explanation:
The given equation is:
[tex]2(3+x)=3q-3+5x---(1)[/tex]
Since [tex]x=q-5[/tex] is a solution of the equation above, so substitute x=q-5 into (1) as follows:
[tex]2(3+q-5)=3q-3+5(q-5)\\2(q-2)=3q-3+5q-25\\2(q-2)=8q-28\\q-2=4q-14\\4q-q=-2+14\\3q=12\\q=4[/tex]
Then, it follows:
[tex]x=q-5\\\therefore x=4-5=-1[/tex]
[tex]f(x)=\sqrt[3]{2x-1}[/tex]
The function [tex]f(x) = \sqrt[3]{2x-1}[/tex] is a cubic root function with a linear transformation applied.
How to solveThe expression inside the root, 2x-1, is a linear function that scales and shifts the input x. The cubic root function then takes the cube root of the result.
This function is defined for all real numbers x, as the cubic root can be calculated for any real number.
Its graph is a transformed version of the standard cubic root function, skewed and shifted depending on the coefficients in the linear function. The function increases monotonically as x increases, and it is continuous and differentiable everywhere.
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The Complete Question
[tex] f(x)=\sqrt[3]{2x-1}[/tex]
Identify this function and solve
Select the correct comparison symbol from the drop-down box.
The correct comparison symbol from the drop-down box is,
⇒ 0.67 = 0.670
Since, Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
We have to given that;
To compare between 0.67 and 0.670
Now, We know that;
The value of zero after any number in decimal expression has neglect.
So, By definition of decimal numbers, we get;
The correct comparison symbol from the drop-down box is,
⇒ 0.67 = 0.670
Hence, The correct comparison symbol from the drop-down box is,
⇒ 0.67 = 0.670
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Evaluate the expression.
log4 (x-7)=3
X= 71
X= 19
x = 57
Answer:
x = 71
Step-by-step explanation:
using the rule of logarithms
[tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex]
then
[tex]log_{4}[/tex] (x - 7) = 3 , then
x - 7 = 4³ = 64 ( add 7 to both sides )
x = 71
solve for C using law of cosine tuned to the nearest tenth
The value of angle C is calculated by applying cosine rule as 50.67 ⁰.
What is the value of C?The value of angle C is calculated by applying cosine rule as shown below;
c² = a² + b² - 2ab cosC
The given parameters in the diagram;
length a = 22
length b = 18
c = 20
The value of angle C is calculated as;
20² = 22² + 18² - (2 x 22 x 18) cos C
792 cos C = 502
cos C = 502/792
cos C = 0.6334
C = arc cos (0.6334)
C = 50.67 ⁰
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vector v has components of 9,6 determine the angle, Ф, in degrees , that vector v makes with the x-axis
The angle the vector v, that has components of 9,6 makes with the x- axis is 33.7°
What is the angle of a vector?The angle of a vector with x and y components (x,y) is given by
Ф = tan⁻¹(y/x)
Given that vector v has components of 9,6. To determine the angle, Ф, in degrees , that vector v makes with the x-axis, we proceed as follows.
We know that the components of the vector are (9,6) which means that
x - component, x = 9 andy - component, y = 6So, we have that
x = 9 andy = 6So, substituting the values of the variables into the equation, we have that
Ф = tan⁻¹(y/x)
Ф = tan⁻¹(6/9)
Ф = tan⁻¹(2/3)
Ф = tan⁻¹(0.6667)
Ф = 33.69°
Ф ≅ 33.7°
So, the angle is 33.7°
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100 Points! Algebra question. Photo attached. Please show as much work as possible. Photo attached. Thank you!
A. A graph of the function is shown in the image below.
B. The illumination in foot-candles that the object receives at a distance of 20-feet from the light source is
C. In the context of the problem, a meaningful domain is {x | x ≤ 0} and a meaningful range is {y | y ≥ 0}.
How to construct and plot the function on a graph?In this exercise, we would plot the illumination on the y-axis (y-coordinates) of a graph while the square of the distance would be plotted on the x-axis (x-coordinate) of a graph on a coordinate plane.
Part B.
The illumination in foot-candles that this object would receive at a distance of 20-feet from the light source can be calculated by substituting the value of d, which is 20 feet into the function as follows;
I(d) = 4500/d²
I(20) = 4500/20²
I(20) = 4500/400
I(20) = 11.25 foot-candles.
Part C.
By critically observing the graph shown in the image attached below, we can reasonably and logically deduce the following domain and range:
Domain = [-∞, 0] ∪ [0, ∞] or {x | x ≤ 0}.
Range = [0, ∞] or {y | y ≥ 0}
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A ball will be thrown upward from a height of 20 meters above the ground, with an initial velocity of 15 meters per second. Its distance from the ground, d, is a function of the time in seconds since the ball was thrown, t. This function is graphed below. How many seconds after the ball is thrown will it be 20 meters from the ground again ?
From the graph, we can calculate that 6 seconds after the ball is thrown, it will be 20 meters from the ground again.
How do we calculate?The equation is as follows:
d = d0 + v0 * t - (1/2) * g * t²
d = distance from the ground
d0 = the initial height
v0 = initial velocity
g = acceleration due to gravity = 9.8 m/s²
t= time
20 = 20 + 15 * t - (1/2) * 9.8 * t^2
We simplify as follows:
0 = -4.9 * t² + 15 * t
We then go ahead to solve this quadratic equation to find the values of t when the ball is 20 meters from the ground again.
t * (-4.9t + 15) = 0
t = 0 or
-4.9t + 15 = 0.
-4.9t + 15 = 0
-4.9t = -15
t = 3.06 seconds
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