I need help on this problem, i checked some that I think might be right, could I get some help on it?

The probability that a point chosen at random in the square is in the blue region is given by: Option D: 0.75

When probability is in terms of area or volume or length etc geometric amounts (when infinite points are there), we can use this definition:

Then:

[tex]P(E) = \dfrac{A(E)}{A(S)}[/tex]

where A(E) is the area/volume/length for event E, and similar for A(S).

For this case, we're given that:

The favorable space is the blue shaded region.

The total sample space is the area of the considered square.

Let we take:

E = event of choosing point in the blue shaded region

Now, we have:

Area of blue region = Area of triangle with base = height = 8 inches + Area of right sided triangle which has base of 4 inch (look it upside down), and height of 8 inches

Area of blue region = [tex]\dfrac{1}{2} \times (8 \times 8 + 4 \times 8) = 48 \: \rm in^2[/tex]

Area of the square of sized 8 inches = 64 sq. inches.

Thus, we get:

[tex]P(E) = \dfrac{A(E)}{A(S)} = \dfrac{48}{64} = \dfrac{3}{4} = 0.75[/tex]

Thus, the probability that a point chosen at random in the square is in the blue region is given by: Option D: 0.75

Learn more about geometric probability here:

https://brainly.com/question/24701316

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Perpendicular lines have slopes that are opposite reciprocals.

This means we take a number, flop it over, and change its sign.

In this case, we take [tex]\boxed{-3}[/tex], change its sign:

[tex]\boxed{3}[/tex]

3 can also be written as

[tex]\boxed{\frac{3}{1} }[/tex]

Now the numerator & denominator switch places:

[tex]\boxed{\frac{1}{3}}[/tex]

So that's the slope of the new line.

Now, let's write the equation in point-slope form:-

[tex]\bigstar{\underline{\boxed{\pmb{y-y_1=m(x-1)}}}[/tex]

Where

y₁  is the y-coordinate of the point (in this case, y₁ = 3)

m = slope (1/3)

x₁= the x-coordinate of the point (in this case, it's -2)

Plug in the values:-

[tex]\bigstar{\boxed{\pmb{y-3=\frac{1}{3}(x-(-2)}}[/tex]

[tex]\bigstar{\boxed{\pmb{y-3=\frac{1}{3}(x+2)} }\longleftarrow\sf{Point-Slope~Formula:)}}[/tex]

===============================================

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)

The expression of [tex]\sqrt{[/tex](16a^4x^6) is an algebraic expression

The equivalent expression of [tex]\sqrt{[/tex](16a^4x^6) is 4a^2x^3

The expression is given as:

[tex]\sqrt{[/tex](16a^4x^6)

Expresss 16 as the square of 4

[tex]\sqrt{[/tex](16a^4x^6) = [tex]\sqrt{[/tex](4^2a^4x^6)

Evaluate the square root of each factor in the expression

[tex]\sqrt{[/tex](16a^4x^6) = 4a^2x^3

Hence, the equivalent expression of [tex]\sqrt{[/tex](16a^4x^6) is 4a^2x^3

Read more about equivalent expressions at:

https://brainly.com/question/2972832

Answer: (1) and (4)

Step-by-step explanation:

The parts listed in the ciongruence statements don't correspond, so they aren't necessarily congruent.

Answer:

10 feet

Step-by-step explanation:

Drawing obviously not to scale but... Red segment is the ruler, at least the part between 5 and 6 inches, 1 inch long. Brown segment is the pole, ground to the top. Leftmost point is the eye, green line is the horizontal. The triangles are similar (AAA, the vertical lines are parallel), the ratio of the side is the same as the ratio of the heights. The height of the larger triangle (measured across the green line is

[tex]40 yd \times 3\frac{ft}{yd} \times 12\frac{in}{ft}= 1440''[/tex].

Ratio of the height is then [tex]1440\div24 = 60[/tex].

At this point the height of the pole is 60 times the length of the measure on the ruler, or 60 inches, that is 5 feet. Add the 5 feet the pole was starting from, it's 10 feet.

Answer: 240 minutes

Step-by-step

60 times 4 hour = 240 minutes

Answer: w=8.5

Step-by-step explanation:

Just did it.

Answer: Yes

Step-by-step explanation:

Step #1: Lacey has 2 3/4 yards of wrapping paper remaining. She has six boxes to wrap, each of which requires 3/8 of a yard of paper. First, you must find the total number of yards of wrapping paper needed for six boxes.

Number of boxes * Number of wrapping paper required for each box

6 x 3/8 = 9/4

Step #2: Subtract the number of yards of wrapping paper remaining by the total number of wrapping for 6 boxes.

2 3/4 - 9/4 = 1/2

Step #3: Determine and solve whether Lacey will have enough wrapping paper left to also wrap a book that requires 1/2 yard of paper. To solve, subtract the remaining amount of wrapping paper by the amount of wrapping required for a book.

1/2 - 1/2 = 0

So, yes Lacey will have just enough wrapping paper to also wrap a book that requires 1/2 yard of paper.

Answer:

8x+3y=-6

Step-by-step explanation:

Answer:

the answer is 1323. i took the quiz on k12 and this was the answer

Step-by-step explanation:

hi

1323

bye (disco lovely_jinni #2028

Answer:

below

Step-by-step explanation:

the law of indices:

a) x⁵

b) x¹⁷

c) -18s⁹

d) -60x²

Answer:

Third option: An infinite geometric series converges if −1<r<1 is true.

Step-by-step explanation:

An infinite geometric series contains an infinite number of terms. A convergent infinite geometric series can go to infinity on a graph. An infinite geometric series can converge if the ratio "r" is true in the equation " –1 < r < 1".

Answer:

yes she can

Step-by-step explanation:

yes she can because $20 is great than $18.50

Answer:

21,42/2,-(42/-2)

Step-by-step explanation:

please mark me as brainlest

Answer:

[tex] {3}^{2} = 9 \\ \\ 81 = 9[/tex]

Answers:

Choice A) 0

Choice B) 0.5

=======================================================

Explanation:

Matia claims that [tex]x^2 > x[/tex]

However, the claim isn't true when 0 ≤ x ≤ 1.

For example, x = 0 leads to [tex]x^2 = 0^2 = 0[/tex]

Meaning that [tex]x^2 > x[/tex] would update to [tex]0 > 0[/tex] which is false.

------------------

Similarly, if x = 0.5, then

[tex]x^2 > x\\\\0.5^2 > 0.5\\\\0.25 > 0.5 \ \text{which is also false}\\\\[/tex]

Because the last inequality is false, the first inequality must also be false for x = 0.5

-------------------

Those last two previous sections showed that x = 0 and x = 0.5 are counter-examples to Matia's claim to thereby prove it false.

Answer:

Part A: [tex]x^2-30x+224\geq 0[/tex]

Part B: Jessica has at least 2 cookies more than Martha

Step-by-step explanation:

Since there are 2 question-

Let,

How many more cookies will Jessica have than Martha?If x represents the number of cookies Jessica started with, complete the statements below. Be Part A:

Let,

The inequality that describes the relationship between the number of cookies each one of them has is x^2- _ x + 224 ≥ 0 Jessica has at least _ cookies more than Martha.

Be Part B:

Hint:

J=Jessica

30-J=Martha

(J-6)*((30-J)-6)<=80

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Solve:

Starting with Part A: Find the inequality that describes the relationship between the number of cookies each one of them has

Let,

"x" be the number of cookies when Jessica started

"30-x" be the number of cookies when Martha started

Given us that:

Each of them ate 6 cookies from their bag

Therefore,  

Cookie left in each bag are:

(x-6) which is - Jessica

30 - x - 6 = (24 - x) - Martha

Solution - (x-6)(24-x)

The product of the number of cookies left in each bag is not more than 80.

Thus,

[tex](x-6)(24-x\leq 80[/tex]

[tex]24x-x^2-144+6x\leq 80[/tex]

[tex]-x^2+30x-144-80\leq 0[/tex]

[tex]-x^2+30x-244\leq 0[/tex]

[tex]\mathrm{Multiply\;by\;-1\;both\;sides}[/tex]

[tex]x^2-30x+224\leq 0[/tex]

Hence, Answer = [tex]x^2-30x+224\leq 0[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Solve:

Part B: Solve the quadratic equation:

[tex]\begin{bmatrix}\mathrm{Solution:}\:&\:14\le \:x\le \:16\:\\ \:\mathrm{Interval\:Notation:}&\:\left[14,\:16\right]\end{bmatrix}[/tex]

[tex]\left(x-14\right)\left(x-16\right)\le \:0[/tex]

[tex]14\le \:x\le \:16[/tex]

The solution is x=16 cookies

Thus, (30-x)=30-16=14 cookies

Now we know that;

The number of cookies when Jessica started was 16 cookies

The number of cookies when Martha started was 14 cookies

So,

The number of cookies left in each bag  is equal to

Jessica:

16-6=10 cookies

Martha:

14-6=8 cookies

10 > 8

As a result, Jessica has at least 2 cookies more than Martha.

Fill in blank for:

The inequality that describes the relationship between the number of cookies each one of them has is x^2 - __30__ x +224 >= 0.

Jessica has at least __2__ cookies more than Martha.​

~Lenvy~

Answer:

106

Step-by-step explanation:

a foot is 12 inches so 8x12 would be 96 and if you add the other 10 inches that would be 106

Answer:

5a - 4b

Step-by-step explanation:

= 8a - 6b - 3a +2b

= 8a - 3a - 6b + 2b

= 5a - 4b

Hope it helps :)

Answer:

5a - 4b

Step-by-step explanation:

Answer: (-√(3) /2, 1/2)

Step-by-step explanation:

The triangle created is a 30 60 90 triangle, and thus the opposite side of the angle equals the y-coordinate which equals 1/2, and the adjacent side of the angle equals the x-coordinate which equals -√(3) /2

Answer:

B. y = 5x-1

Step-by-step explanation:

B. y = 5x-1 is not an exponential function.

Answer:

[tex]10.67\pi[/tex] OR [tex]33.49[/tex]

Step-by-step explanation:

Volume of a Sphere: [tex]\frac{4}{3} *\pi*r^3[/tex]

Radius = 2

[tex]\frac{4}{3} *\pi*r^3[/tex]

[tex]\frac{4}{3} *\pi*2^3[/tex]

[tex]\frac{4}{3} *\pi*8[/tex]

[tex]10.67\pi[/tex]

OR

[tex]\frac{4}{3} *\pi*r^3[/tex]

[tex]\frac{4}{3} *3.14*2^3[/tex]

[tex]\frac{4}{3} *3.14*8[/tex]

[tex]\frac{4}{3} *25.12[/tex]

[tex]33.49[/tex]

Hope this helps!

Answer:

30,976

Step-by-step explanation:

=}.

[tex](11 {}^{3} \times 4 { }^{2} \binom{}{11 {}^{2} } ) {}^{2} [/tex]

=}.

[tex](11 \times 4 {}^{2} ) {}^{2} [/tex]

=}.

[tex]121 \times (4 {}^{2} ) {}^{2} [/tex]

=}.

[tex]121 \times 256[/tex]

=}. 30,976

Answer:

Answer given above

Step-by-step explanation:

11^2 * 4^4

Answer:

[tex]\huge\boxed{\sf \$ 3,114}[/tex]

Step-by-step explanation:

Annual Income of Sam = $37,368

To find the monthly income (given that he earns an equal amount of money every month), we can divide the annual income by 12. (Each year has 12 months)

Monthly Income:

= $37,368 / 12

= $3,114

[tex]\rule[225]{225}{2}[/tex]

When trapezoidal prism undergoes a dilation, the size of the prism changes

The height of the image is 52.2 meters

The given parameters are:

A1 = 35 m²

A2 = 315 m²

H1 = 5.8 m

To calculate the height of the image, we make use of the following equivalent ratio

A1 : H1 = A2 : H2

So, we have:

35 : 5.8 = 315 : H

Express as fractions

35/5.8 = 315/H

Make H the subject

H = 315 * 5.8/35

Evaluate the product

H = 52.2

Hence, the height of the image is 52.2 meters

Read more about dilation at:

https://brainly.com/question/3457976

Answer:

17.4

Step-by-step explanation:

The length of the other dimension rectangular portion of the garden is 12 feet.

Area is the amount of space occupied by a two dimensional shape or object.

The area of each semicircle = (1/4) * π * radius² = (1/4) * π * 4² = 12.56 ft²

Let x represent the other side of the rectangle, hence:

Area of garden = 2(12.56) + 4x = 4x + 25.12

Hence:

73.12 = 4x + 25.12

x = 12 feet

The length of the other dimension rectangular portion of the garden is 12 feet.

Find out more on area at: https://brainly.com/question/25292087

Answer:

3:30 is the answer

What is it?

The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), ​first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

How do you find IQR?

Step 1: Put the numbers in order. ...

Step 2: Find the median. ...

Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...

Step 4: Find Q1 and Q3. ...

Step 5: Subtract Q1 from Q3 to find the interquartile range.

Answer:

The answer to this quesion is a measure of statistical dispersion, the spread of data or observations, first you need to get the data find the median calculate the median from both lower and upper half of the data and the iqr is the diffrence between the lower and upper.

Step-by-step explanation:

I Hope This Helps You!

-Justin:)