I need help with this quadratic function… I thought I knew the answer, but obviously I don’t

I Need Help With This Quadratic Function I Thought I Knew The Answer, But Obviously I Dont

Answers

Answer 1

Let us start with the following quadratic function:

[tex]f(x)=x^2-x-12[/tex]

the X-intercepts are the collection of values to X which makes f(x) = 0, and it can be calculated by the Bhaskara formula:

[tex]x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

where the values a, b, and c are given by:

[tex]f(x)=ax^2+bx+c[/tex]

Substituting the values from the proposed equation, we have:

[tex]\begin{gathered} x_{1,2}=\frac{1\pm\sqrt{1^2-4*1*(-12)}}{2*1} \\ x_{1,2}=\frac{1\pm\sqrt{1+48}}{2}=\frac{1\pm\sqrt{49}}{2} \\ x_{1,2}=\frac{1\pm7}{2} \\ \\ x_1=\frac{1+7}{2}=\frac{8}{2}=4 \\ x_2=\frac{1-7}{2}=-\frac{6}{2}=-3 \end{gathered}[/tex]

From the above-developed solution, we are able to conclude that the solution for the first box is:

(-3,0) ,(4,0)

Now, the y-intercept, is just the value of y when x = 0, which can be calculated as follows:

[tex]\begin{gathered} f(0)=0^2-0-12=-12 \\ f(0)=-12 \end{gathered}[/tex]

From this, we are able to conclude that the solution for the second box is:

(0, -12)

Now, the vertex is the value of minimum, or maximum, in the quadratic equation, and use to be calculated as follows:

[tex]\begin{gathered} Vertex \\ x=-\frac{b}{2a} \\ y=\frac{4ac-b^2}{2a} \end{gathered}[/tex]

substituting the values, we have:

[tex]\begin{gathered} x=-\frac{-1}{2*1}=\frac{1}{2} \\ y=\frac{4*1*(-12)-(-1)^2}{4*1}=\frac{-48-1}{4}=\frac{-49}{4} \end{gathered}[/tex]

which means that the solution for the thirst box is:

(1/2, -49/4) (just as in the photo)

Now, the line of symmetry equation of a quadratic function is a vertical line that passes through the vertex, which was calculated to be in the point: (1/2, -49,4).

Because this is a vertical line, it is represented as follows:

[tex]x=\frac{1}{2}[/tex]


Related Questions

Brenda is preparing food for a picnic. She must make at least 6 sandwiches and at least 3 dozen cookies. It takes her 4 minutes to make a sandwich

Answers

For 6 sandwiches and 3 dozen cookies, the total time taken by Brenda would be 33 minutes.

What is a mathematical function, equation and expression?function : In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.expression : A mathematical expression is made up of terms (constants and variables) separated by mathematical operators.equation : A mathematical equation is used to equate two expressions.equation modelling : Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis and results of the given problem

Given is Brenda who must make at least 6 sandwiches and at least 3 dozen cookies. It takes her 4 minutes to make a sandwich, and 45 minutes to make a dozen cookies.

If she makes [x] sandwiches and [y] dozen cookies, then the total time she would take to make them can be written as -

t = 4x + 3y

For 6 sandwiches and 3 dozen cookies, we can write -

t(6, 3) = 4 x 6 + 3 x 3 = 24 + 9 = 33 minutes

t(6, 3) = 33 minutes

Therefore, for 6 sandwiches and 3 dozen cookies, the total time taken by Brenda would be 33 minutes.

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{Complete question is given below -

She must make at least 6 sandwiches and at least 3 dozen cookies. It takes her 4 minutes to make a sandwich, x, and 45 minutes to make a dozen cookies, y.}

Find the equation of the line with slope = 5 and passing through (-7,-29). Write your equation in the form
y = mz+b.

Answers

Answer:

[tex]y =5x+6[/tex]

Step-by-step explanation:

In the equation, [tex]y=mx+b[/tex], the "m" represents the slope, and the b represents the y-intercept.

We know the slope is 5, so we already know part of the equation: [tex]y=5x+b[/tex]

To solve for the "b" part or y-intercept, we can simply plug in a known point on the line, which was given to be (-7, -29)

This gives us the following equation:

[tex]-29 = 5(-7) + b\\\text{simplify}\\-29 = -35 + b\\\text{add 35 to both sides}\\6=b[/tex]

Answer: y = 5x + 6

Step-by-step explanation:

1. Do point-slope formula {(y - y1) = m(x - x1})

(y - 29) = 5(x - 7)

Distribute

(y - 29) = 5x - 35

Subtract 29 on both sides

Cancel out y - 29 - 29

y = 5x + 6

I will give brainliest. By the way, two people need to answer for someone to give brainliest.


For the direct variation equation y=223x, what is the constant of proportionality?

A: 2

B: 2 2/3

C: 2/3

D: 3

The equation y=7x gives the relationship between the number of road projects, x, and the number of weeks it takes a crew of workers to complete all the projects, y. What is the constant of proportionality? What does it mean in this context?

A: The constant of proportionality is 7. It takes the crew of workers 7 weeks to complete 1 road project.

B: The constant of proportionality is 7. It takes the crew of workers 7 days to complete all of their road projects.

C: The constant of proportionality is 7. It takes the crew of workers 7 days to complete 1 road project.

D: The constant of proportionality is 7. It takes the crew of workers 7 weeks to complete all of their road projects.

Write a direct variation equation to find the number of miles a jet travels in 3 hours if it is flying at a rate of 600 mph.

A: 600 = 3x

B: 3 = 600x

C: y = 600/3

D: y = 600 x 3

Jamal earns $125,000 a year as a systems analyst. He wants to know how much he will earn if he continues at the same rate of pay for 7 years. Which equation will help him find this amount?

A: x = 125,000/5

B:125,000 = 7x

C:125,000 = 7/x

D: y = 125,000 x 7

Answers

Answer: I think B and for the second one I think C

Step-by-step explanation: The constant of proportionality is 7. It takes the crew of workers 7 days to complete 1 road project. That means they have to take at least 7 days which is correct.

Assume that Jim Bruce and Valerie are 3 of the 17 members of the​ class, and that of the class members will be chosen randomly to deliver their reports during the next class meeting. What is the probability that Jim Bruce and Valerie are selected in that​ order?

Answers

The probability that Jim, Bruce and Valerie are selected in that​ order is P = 1/680

Given,

Number of students in a class = 17

Jim, Bruce and Valerie are 3 of the 17.

Three of students from the class are randomly chosen to deliver their reports during the next class meet.

We have to find the probability that Jim, Bruce and Valerie are selected in that​ order;

Here,

The total number of possible selection;

S = ⁿCr

Where, n = 17 and r = 3

Then,

S = ¹⁷C₃

S = 17! / 14! x 3!

S = 680

Therefore,

The probability that Jim, Bruce and Valerie are selected in that​ order is P = 1/680

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to find the height of a tree, a group of students devised the following method. A girl walks toward the tree along it's shadow until the shadow of the top of her head coincide with the shadow of the top of the tree. if the girl is 150 cm tall, her distance to the foot of the tree is 13 meters, and the length of her shadow is 3 m, how tall is the tree?

Answers

Answer: 8m

Explanation:

Given:

To find the height(h) of the tree, we can use ratio since they are similar triangles.

Triangle 1

Triangle 2

So,

[tex]\begin{gathered} \frac{1.5}{3}\text{ = }\frac{h}{16} \\ \text{Simplify and rearrange} \\ h=\text{ }\frac{1.5}{3}(16) \\ \text{Calculate} \\ h=\text{ 8 m} \end{gathered}[/tex]

Therefore, the height of the tree is 8m.

two ships leave a port at the same time. the first ship sails on a bearing of 55° at 12 knots (natural miles per hour) and the second on a bearing of 145° at 22 knots. how far apart are they after 1.5 hours (round to the nearest nautical mile)

Answers

Given that one of the ships travels at 12 nautical miles per hour, then after 1.5 hours, it will travel 12*1.5 = 18 miles

The other ship will travel 22*1.5 = 33 miles

The angle of 145° is measured with respect to the positive x-axis. Then, respect the negative x-axis, its measure is 180° - 145° = 35°

We have to use trigonometric functions to find x1, y1, x2, and y2, as follows:

sin(55°) = y1/18

sin(55°) *18 = y1

14.7 = y1

cos(55°) = x1/18

cos(55°)*18 = x1

10.3 = x1

sin(35°) = y2/33

sin(35°)*33 = y2

18.9 = y2

cos(35°) = x2/33

cos(35°)*33 = x

-27 = x2 (the minus sign comes from the graph)

The distance between two points (x1, y1) and (x2, y2) is computed as follows:

[tex]d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Substituting with the values found,

[tex]\begin{gathered} d=\sqrt[]{(-27-10.3)^2+(18.9-14.7)^2} \\ d=\sqrt[]{(-37.3)^2+4.2^2} \\ d=\sqrt[]{1391.29+17.64} \\ d\approx38\text{ miles} \end{gathered}[/tex]

i have test tomorrow i will love you to help me with thisClassify the following as a monomial, binomial, trinomial, or polynomial andstate the degree.a) 7^5b) 5^7 + 7^2c) 7^3 + 11^2 − 13 + 112d) + 2 + 3^2e) 11^3 − 7^3

Answers

Answer:

a) degree 5; monomial

b) degree 7; polynomial

c) degree 3; polynomial

d) degree 2; polynomial

e) degree 3 polynomial

Explanation.

A polynomial is a mathematical expression containing coefficients and variables.

An example of a polynomial is 42x^5 + 23 x^3 - 2x.

A monomial is a polynomial that contains only one term. For example, x^4, 34x^5, 2x, etc.

Having that in mind, we go through the expressions and place them in one of either category.

a) 7^5

This contains only one term, meaning it is monomial; its highest exponent is 5, meaning it is of degree 5.

b) 5^7 + 7^2

This contains two terms, meaning it is a polynomial; its highest exponent is 7, meaning its degree is 7.

c) 7^3 + 11^2 − 13 + 112

This expression contains four terms - it is a polynomial; its highest exponent is 3, meaning its degree is 3.

d) + 2 + 3^2

This contains three terms, meaning it is a polynomial; its highest exponent is 2, meaning its degree is 2.

e) 11^3 − 7^3

This contains 2 terms, meaning it is a polynomial; its highest exponent is 3, meaning it is of degree 2.

The equation for a straight line (deterministic model) is y = Bo + B,X.If the line passes through the point ( - 10,3), then x = - 10, y = 3 must satisfy the equation; that is, 3 = Bo + B1(-10).Similarly, if the line passes through the point (11,4), then x = 11, y = 4 must satisfy the equation; that is, 4 = Bo+B1(11).Use these two equations to solve for Bo and By; then find the equation of the line that passes through the points (-10,3) and (11,4)...Find Bo and B,B1 =Bo(Simplify your answers. Type integers or simplified fractions.)

Answers

To find the equation of the line we just need to find the beta constants. In order to do this we have (they provided us with) the following system of equations:

[tex]\begin{cases}3=\beta_0+\beta_1(-10) \\ 4=\beta_0+\beta_1(11)\end{cases}[/tex]

Let us subtract the second equation to the first one:

This implies that

[tex]\beta_1=\frac{-1}{-21}=\frac{1}{21}[/tex]

Now, let us replace this value we just got into the second equation to find beta_0:

[tex]\begin{gathered} 4=\beta_0+\frac{1}{21}\cdot11, \\ 4=\beta_0+\frac{11}{21}, \\ \beta_0=4-\frac{11}{21}=\frac{4\cdot21}{21}-\frac{11}{21}=\frac{84-11}{21}=\frac{73}{21} \end{gathered}[/tex]

At last,

[tex]\beta_1=\frac{1}{21},\beta_0=\frac{73}{21}[/tex]

Then, the equation of the line is just

[tex]y=\frac{73}{21}+\frac{1}{21}x[/tex]

#Classify each number as a natural number, a whole number, or an integer.
If a number belongs to more than one set, list all possible sets it belongs to.
a) 1
b) -20
c) -3

Answers

(a) Whole number and integer

(b) Negative integer

(c) Negative integer

What are whole numbers an integers?

Positive, negative, and zero numbers all fall under the category of integers. The word "integer" is a Latin word that signifies "whole" or "intact." Therefore, fractions and decimals are not considered to be integers. A number line is a graphic representation of positive and negative integers. The use of integers on a number line facilitates mathematical procedures. The right-side number is always greater than the left-side number. Due to the fact that they are greater than 0, positive numbers are positioned to the right of zero. All natural numbers and 0 are included in a group of numbers known as whole numbers. They belong to the category of real numbers, which excludes fractions, decimals, and negative numbers. Numbers used for counting are also regarded as whole numbers.

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can you explain what the 8th question is asking then answer it please

Answers

Answer:

Options A and C

Explanation:

We want to find out which arithmetic sequence(s) contain the term 34.

For an arithmetic sequence to contain the term, 34, the corresponding n-value must be an integer.

Option A

Set tn = 34

[tex]\begin{gathered} t_n=6+(n-1)4 \\ 34=6+(n-1)4 \end{gathered}[/tex]

Solve for n:

[tex]\begin{gathered} 34-6=4n-4 \\ 28=4(n-1) \\ n-1=\frac{28}{4}=7 \\ n-1=7 \\ n=7+1 \\ n=8 \end{gathered}[/tex]

The 8th term of this sequence is 34.

Option B

[tex]\begin{gathered} t_n=3n-1 \\ 34=3n-1 \\ 34+1=3n \\ 35=3n \\ n=\frac{35}{3}=11\frac{2}{3} \end{gathered}[/tex]

A sequence cannot have a decimal nth term, therefore, the sequence does not contain 34.

Option C

T1 = 12, d=5.5

[tex]\begin{gathered} 12+5.5(n-1)=34 \\ 5.5(n-1)=34-12 \\ 5.5(n-1)=22 \\ n-1=\frac{22}{5.5} \\ n=4+1 \\ n=5 \end{gathered}[/tex]

The 5th term of this sequence is 34, therefore, it contains the term 34.

Option D

3,7,11,...

[tex]\begin{gathered} t_1=3 \\ d=7-3=4 \end{gathered}[/tex]

Using the nth term of an arithmetic sequence formula:

[tex]\begin{gathered} t_n=t_1+(n-1)d \\ 34=3+4(n-1) \\ 34-3=4(n-1) \\ 31=4(n-1) \\ n-1=\frac{31}{4} \\ n-1=7\frac{3}{4} \\ n=8\frac{3}{4} \end{gathered}[/tex]

A sequence cannot have a decimal nth term, therefore, the sequence does not contain 34.

The sequences in Options A and C contain the term 34.

Find the sum of the first 39 terms of the following series, to the nearest integer.2,7, 12,...

Answers

The sequence 2,7,12,... given is an arithmetic progression. This is because it has a common difference.

Given:

first term, a = 2

common difference, d = second term - first term = 7 - 2 = 5

d = 5

n = 38

The sum of an arithmetic progression is given by;

[tex]\begin{gathered} S_n=\frac{n}{2}\lbrack2a+(n-1)d\rbrack \\ S_{38}=\frac{38}{2}\lbrack2(2)+(38-1)5\rbrack \\ S_{38}=19\lbrack4+37(5)\rbrack \\ S_{38}=19\lbrack4+185\rbrack \\ S_{38}=19(189) \\ S_{38}=3591 \end{gathered}[/tex]

Therefore, the sum of the first 39 terms of the series is 3,591

it's Hamilton path and Hamilton circuitweighted graph / graph theoryyou have to add each angle up and find the answer for each row 12 grade math

Answers

What you need to do in order to solve this is add the values that are defined by the begining and end points declared in there:

[tex]A\text{ B D E C A}[/tex]

that means the distance defined by AB, BD, DE, EC & CA:

[tex]4+8+11+10+8\text{ = 41}[/tex]

And in the same manner all of the other series of distances.


L1 : y=−4x+3L2 : y=4x−1


Answers

Answer:

Assuming you're trying to find where the lines intersect (their solution), the point where they intersect is (1/2 , 1).

Step-by-step explanation:

When you are trying to find the point where two lines intersect, you have to find the x and y values of that point. To do that, just set the lines equal to each other.

First, since y must equal y:

y = y

-4x + 3 = 4x - 1

Now solve for x:

-8x + 3 = -4

-8x = -4

8x = 4

x = 1/2

We just found the x value of the shared point. Now we need to find the y value of that point. Again, since the two lines share this point, plugging in the x value will result in the same y value for both lines.

So just plug in x to any of the equations: (I think y=4x-1 is easier)

y(1/2) = 4(1/2) - 1     or      y = 4(1/2) - 1  (it doesn't matter how you write it)

y(1/2) = 2 - 1           or      y = 2 - 1

y(1/2) = 1

So the point is:

(1/2 , 1)

To check you can plug in the y value you find, 1 in this case, and solve for x. If you get the same x value as before, everything is correct.

So:

(1) = -4x + 3

-2 = -4x

1/2 = x    or    x = 1/2

Great! Everything is correct.

This may seem like a very long process, but it is very easy. Just find the x and y values that the lines share by setting the lines equal to each other.

I need help please quickly I need help

10(2 + 3) - 8 · 3.​

Answers

20+50-8 times 3

70 -24

46 is answer

Answer:

10(5)-24 ----) 50-24 -----) 26

Step-by-step explanation:

answe is 26

Determine if the correlation between the two given variables is likely to be positive or negative, or if they are not likely to display a linear relationship.A child’s age and the number of hours spent napping-positive-negative-no correlation

Answers

We know that a a childresn spend more hours napping when they are youngers therefore we have a negative correlation

Leila runs at 12 mph find the number of miles she can travel if she runs for 2 hours
20 POINTS ANSWER I WILL MARK BRAINLIEST!!!!!!!!!!

Answers

Answer: 24 mph

Step-by-step explanation:

If she can run 12 mph/ 12 miles per hour

She runs for 2 hours

12 · 2 = 24

can you please help me on e. f. and g.

Answers

His temperature was 100.1 degree farad initially which is around 6 pm. At 7 pm it became 101 degree farad.

[tex]\begin{gathered} \text{slope = }\frac{y_2-y_1}{x_2-x_1}=\frac{101-100.1}{7-6}=\frac{0.9}{1}=0.9 \\ m=0.9 \end{gathered}[/tex]

y = mx + b

where

m = slope

b = y - intercept

let find the y intercept

[tex]\begin{gathered} 101=0.9(7)+b \\ 101-6.3=b \\ b=94.7 \end{gathered}[/tex]

Therefore, the equation is

[tex]y=0.9x+94.7[/tex]

e. let us draw a graph

His temperature will be critical above 22 minutes past 9 pm.

f . He should go to emergency room.

g.

[tex]\begin{gathered} y=0.9x+94.7 \\ 98.6=0.9x+94.7 \\ 98.6-94.7=0.9x \\ 3.9=0.9x \\ x=\frac{3.9}{0.9} \\ x=4.33333333333 \end{gathered}[/tex]

His temperature will be normal around past 4 pm which is 98.6 degree farad.

A collection of dimes and quarters has a value of $1.35. List all possible combinations of dimes and quarters. Remember to write a let statement

Answers

3 combinations:

3 quarters and 6 dimes

5 quarters and 1 dime

1 quarter and 11 dimes

1) Remember that a dime corresponds to $0.10 and a quarter to $0.25. And the value we want to find is $1.35

2) As we can see the last digit on $1.35 is 5 then we can infer that we're going to need an odd number of quarters ($0.25). Also, notice that we need whole numbers for the quantities of each coin. In other words, multiples of 0.10 and 0.25 whose sum yields to $1.35. So let's do it step by step:

So, we can write out the following list of combinations:

q (quarter) 3 q = 3 x 0.25 = $ 0.75

d (dimes) 6 d = 6 x 0.10 = $ 0.60

0.60 + 0.75 = 1.35

2.2) Another possible combination:

q (quarter) 5 q = 5 x 0.25 = $ 1.25

d (dimes) 1 d = 1 x 0.10 = $ 0.10

0.10+1.25= 1.35

2.3)

q (quarter) 1 q = 1 x 0.25 = $ 0.25

d (dimes) 11 d = 11x 0.10 = $ 1.10

0.25+1.10 = 1.35

3) Hence, considering that we need to combine dimes and quarters and their sum must be lesser than $1.35 We have three combinations with whole numbers of dimes and quarters:

3 quarters and 6 dimes

5 quarters and 1 dime

1 quarter and 11 dimes

The figure ABCD is a rectangle. AB = 2 units, AD = 4 units, and AE = FC = 1 unit.Find the area of triangle ABE.

Answers

Area of triangle ABE can be calculated using the formula 1/2 x b xh

From the question,

base b = AE = 1

height h =AB = 2

substitute the values into the formula

[tex]A=\frac{1}{2}\times1\times2[/tex]

Area = 1 square unit

f(x) = -2x² + 2x
Find f(-8)

Answers

Answer:

f(-8)= -112

Step-by-step explanation:

-2(-8)^2 + 2(-8)

-2(-64) + 16

-128 + 16

= -112

hope this helped

have a good day :)

7) The water park is a popular field trip destination. This year the senior class at High School A and thesenior class at High School B both planned trips there. The senior class at High School A rented andfilled 1 van and 14 buses with 309 students. High School B rented and filled 4 vans and 14 buseswith 354 students. Each van and each bus carried the same number of students. Find the number ofstudents in each van and in each bus.C) Van: 19 Bus: 29 D) Van: 15, Bus: 21

Answers

Given

The water park is a popular field trip destination. This year the senior class at High School A and the senior class at High School B both planned trips there. The senior class at High School A rented and filled 1 van and 14 buses with 309 students. High School B rented and filled 4 vans and 14 buses with 354 students. Each van and each bus carried the same number of students.

Answer

Let students in Van be x

And students in bus be y

A/Q

x + 14y = 309 (1)

4x + 14y = 354 (2)

Subtracting (1) and (2)

3x = 45

x = 15

Put in eq (1)

15 + 14 y = 309

14y = 309 - 15

14 y = 294

y = 21

St

Which of the following is a solution to the equation c + ( 4 -3c) - 2 = 0?A. -1B. 0C. 1D. 2

Answers

Given data:

The given equation is c+(4-3c)-2=0

The given equation can be written as,

c+4-3c-2=0

-2c+2=0

-2c=-2

c=1

Thus, the value of c is 1, so option C) is correct.

Metric area unit conversion with decimal valuesTammy has a rectangular poster. The poster is 1.2 meters long and 0.9 meters wide. What is the area of the poster in square centimeters? Do not round youranswer.cmcm²cm³

Answers

We are asked to find the final area in square centimeters.

We must first convert the measurements of the poster into centimeters:

1.2m = 120cm

0.9m = 90cm

Area = length * width

= 120*90

= 10800 square centimeters.

A businesswoman buys a new computer for $4000. For each year that she uses it the value depreciates by $400. The equation y=-400x+4000 gives the value y of the computer after x years. What does the x-intercept mean in this situation ? Find the x-intercept. After how many years will the value of the computer be $2000 ?

Answers

We have the following:

The intersection with the x-axis is when the value of y is 0, that is, the computer already has a value of 0 and has no commercial value.

we found it like this

[tex]\begin{gathered} 0=-400x+4000 \\ 400x=4000 \\ x=\frac{4000}{400} \\ x=10 \end{gathered}[/tex]

which means that in 10 years, the computer does not represent a commercial value

to calculate the number of years that have passed when the computer has a value of 2000, y = 2000, therefore we replace

[tex]\begin{gathered} 2000=-400x+4000 \\ 400x=4000-2000 \\ x=\frac{2000}{400} \\ x=5 \end{gathered}[/tex]

This means that in a total of 5 years the value of the computer will be $ 2000

Find extreme values of function f(x) = x³ - (3/2)x² on interval [- 1,2]

Answers

we have the function

[tex]f(x)=x^3-\frac{3}{2}x^2[/tex]

Find out the first derivative of the given function

[tex]f^{\prime}(x)=3x^2-3x[/tex]

Equate to zero the first derivative

[tex]\begin{gathered} 3x^2-3x=0 \\ 3x(x-1)=0 \end{gathered}[/tex]

The values of x are

x=0 and x=1

we have the intervals

(-infinite,0) (0,1) (1,infinite)

Interval (-infinite,0) -----> f'(x) is positive

interval (0,1) ---------> f'(x) is negative

interval (1,infinite) -----> f'(x) is positive

that means

x=0 is a local maximum

x=1 is a local minimum

Find out the y-coordinates of the extreme values

For x=0 -----> substitute in the function f(x) ---------> f(x)=0

For x=1 ------> substitute in the function f(x) ------> f(x)=-0.5

therefore

The extreme values are

local maximum at (0,0)local minimum at (1,-0.5)

-2 decimal 3/% because if you divide the principal in half its 1% of 3

Identify the augmented matrix for the system of equations and the solution using row operations.

Answers

Given:

The system of equation is given as,

[tex]\begin{gathered} 7x-4y=28 \\ 5x-2y=17 \end{gathered}[/tex]

The objective is identify the augmented matrix for the system of equations and the solution using row operations.

Explanation:

The required augmented matrix will be,

Performing the Gauss-Jordan elimination with the following operation,

[tex]R_2=R_2-\frac{5R_1}{7}[/tex]

By applying the operation to the augmented matrix,

To find y :

On equating the second row of the matrix,

[tex]\begin{gathered} \frac{6y}{7}=-3 \\ y=\frac{-3}{\frac{6}{7}} \\ y=\frac{-3\times7}{6} \\ y=\frac{-7}{2} \end{gathered}[/tex]

To find x :

On equating the first row of the matrix,

[tex]\begin{gathered} 7x-4y=28 \\ 7x=28+4y \\ x=\frac{28+4y}{7} \end{gathered}[/tex]

Substitute the value of y in the above equation.

[tex]\begin{gathered} x=\frac{28+4(\frac{-7}{2})}{7} \\ x=\frac{28-14}{7} \\ x=\frac{14}{7} \\ x=2 \end{gathered}[/tex]

Thus the value of solutions are,

[tex]\begin{gathered} x=2 \\ y=-\frac{7}{2}=-3.5 \end{gathered}[/tex]

Hence, option (3) is the correct answer.

y=x-6y=x+2 how to solve this problem

Answers

No solutions

Explanation

[tex]\begin{gathered} y=x+6\text{ Eq(1)} \\ y=x+2\text{ Eq(2)} \end{gathered}[/tex]

Step 1

replace Eq(1) in Eq (2)

[tex]\begin{gathered} y=x+2\text{ Eq(2)} \\ x+6=x+2 \\ \end{gathered}[/tex]

Step 2

subtract x in both sides

[tex]\begin{gathered} x+6=x+2 \\ x+6-x=x+2-x \\ 6=2 \end{gathered}[/tex]

6=2 is false, it means there is not solution for both equations,

Gary is saving money to buy a ticket to a New York Jets game that costs $225. Healready has saved $18. What is the least amount of money Gary must save each week, sothat at the end of 9 weeks he has enough money to buy the ticket? (Only an algebraic- solution will be accepted.)

Answers

lillyvong13, this is the solution:

Cost of the ticket to a New York Jets game = $ 225

Savings up to now = $ 18

Difference = 225-18 = 207

Number of weeks = 9

Let x to represent the amount of money Gary must save each week for buying the ticket, as follows:

x = 207/9

x = 23

Gary must save $ 23 at the end of 9 weeks to have enough money to buy the ticket

Divide the polynomial by the binomial. (Simplify your answer completely.)
(q² + 5q + 20) / (q + 8)

Answers

Answer:

It's already in its simplest form.

Step-by-step explanation:

Factorising Quadratics

I'm writing a book/document on this topic but it's not finished. I suspect there is an error in this question because it's practically impossible to factorise it into integers.

The quadratic polynomial in the numerator has imaginary roots because 5 squared is less than 20 times 4.

ax² + bx + c;

if ( b² < 4ac ) { 'solution is imaginary' }

The quadratic equation will explain the above.

Derek has $20 to spend on used books, but he can not spend all $20.Hardcover books cost $5 each and paperbacks cost $2 each. Create aninequality which determines the number (x) of hardcover books and the number(y) of paperback books he can buy.

Answers

Given:

The amount to spend on books, T=$20.

The cost of a handcoverbook, m=$5.

The cost of a paperback, n=$2.

Let x be the number of handcover books and y be the number of paperback books.

It is said that the complete amount of $20 cannot be spend.

So, the inequality to determine x and y can be written as,

[tex]\begin{gathered} T>mx+ny \\ 20>5x+2y \end{gathered}[/tex]

So, the inequality is 20>5x+2y.

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