identify each described physical separation technique. a liquid is carefully poured out, leaving the solid behind in the container

Lipids the compound present in food with formula C₄₄h₈₆O₈NP

The compound with a formula C₄₄H₈₆O₈NP is understood as phosphatidylethanolamine. it's the second most abudant phospholipid in animal and plant lipid, after phosphotidylcholine. It is present in many foods. Also a main lipid component of microbial membranes. it's found in all living cells and compose of 25% of all phospholipids.

What is the role of lipids in food?

They are important in the diet as energy sources and as sources of essential fatty acids and fat-soluble vitamins, which tend to accompany fats. They also contribute satiety, flavor, and palatability to the diet.Dietary lipids are primarily oils (liquid) and fats (solid). Commonly consumed oils are canola, corn, olive, peanut, safflower, soy, and sunflower-seed oil . Foods rich in oils include dressing , olives, avocados, spread , nuts, seeds, and a few fish. Fats are found in animal meat, dairy products, and cocoa butter

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From highest to lowest according to the percentages of greenhouse gases they emit.

What are greenhouse gases?

The main greenhouse gases in Earth's atmosphere are water vapour (H2O), carbon dioxide (CO2), methane (CH4), nitrous oxide (N2O), and ozone. A greenhouse gas (GHG or GhG) is a gas that absorbs and emits radiant energy in the thermal infrared range (O3). Without greenhouse gases, the average surface temperature of the Earth would be closer to 18 °C (0 °F) than it is today, which is 15 °C (59 °F). Additionally, greenhouse gases are found in the atmospheres of Venus, Mars, and Titan.

Thus the correct order goes as:

Forestry, agriculture, transportation, residential and commercial buildings

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The following value to the ordinary numbers:

a - 5.5 × 10⁻⁶ = 0.0000055

b - 2.9 ×10² = 2900

c - 1.115 × 10⁴ = 11150

d - 1.412 × 10⁻³ = 0.001412

e - 7.2 × 10¹ = 72

To convert standard form numbers to regular form: Give a regular number a power of 10. It is necessary to multiply the decimal number by this power of 10. You should type your number like a regular number.

A decimal is one of the number types in mathematics that has a fractional component and a complete integer split by a decimal point. The point that appears between the components of a whole integer and a fraction is known as the decimal point. 34.5 is an example of a decimal number.

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There are 0.96 moles of toluene are in the solution of toluene (C₇H₈) in 301 g of cyclohexane (C₆H₁₂) having a boiling point of 90.30°C.

Given data -

Boiling point of cyclohexane = 90.30°C

Mass of cyclohexane = 301 g

Kb of cyclohexane = 2.92°C/m

Tb of cyclohexane = 80.90°C

Using the equation,

           m = ∆Tb

                   Kb

where,

m is molality of the solution,

∆Tb is the change in boiling point of cyclohexane -

          90.30 ° C - 80.90 °C = 9.40 °C

Kb is the boiling point elevation constant of cyclohexane, 2.92 °C/m

          Molality (m) =  9.40 = 3.22 mol/kg

                                   2.92

Number of moles of toluene = molality x mass of cyclohexane (in kg)

                                                = 3.22 x 301  

                                                               1000

Number of moles of toluene = 0.96 mol

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The ph of a 0.10 m monoprotic acid ha is measured to be 3.5. The ka value of this acid is 10^(-6).

What is pH?

The hydrogen ion concentration is measured using the pH scale. The pH values, which range from 0 to 14, are assigned to it. Therefore, we may say that the pH value is a number that represents how acidic or basic a solution is.

A solution with a pH below 7 is referred to as acidic, and one with a pH over 7 is referred to as basic, or alkaline.

HA⇌H+ + A−

ka= [H +][A −]/[HA]

For weak acids, [H+] = [A-]

[H+] = 10^(-pH)

Thus, Ka = {10^(-3.5)}^2/0.10 = 10^(-6)

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The energy is released upon emission is E =  1.7 x 10⁵ J/mol.

The formula of energy is

      E = hv

Here,

      v = c / λ

c = speed of light

  = 3 × 10^8

λ = 660 nm

  = 660 × 10^-9

       v = c / λ

          = 3 × 10^8 / 660 × 10^-9

       v = 4.5 × 10^14

Value of h = 6.626 x 10^-34 Js

      E = hv

      E = 6.626 × 10^-34 Js ×  4.5 × 10^14

      E = 2.9 × 10^-19 J/ photon

The amount of energy we receive is one photon's worth. To find the solution to this question, we must thus multiply this result by Avogadro's number.

E = 2.9  x 10 ⁻¹⁹ J/ photon x 6.022 x 10 ²³photon/mol

E =  1.7 x 10⁵ J/mol

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If we consider a structure in which a carbon is bonded to two three carbon chains and a branched alkane then the branched alkane is a 2 carbon chain with a  ethyl on Carbon 1 then the correct name of the structure is 4-(isopropyl)heptane.

The two three carbon chains bonded to the carbon atom will form the parent chain of this structure and this chain will have 7 carbon atoms in it.

Since this chain is that of an alkane and it has no functional group attached so the root name will be heptane.

Now, we have to add a prefix by naming the branched alkyl chain. The branched chain has 3 carbon atoms in it with a methyl group on carbon 1.

So, this name of this group will be propyl.

The position of this propyl group is 4th on the parent chain so the full name of the structure will be 4-(isopropyl)heptane.

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boiling malt kinling are two of the most energy-demanding operations in the malthouse and brewery.

What is malthouse and brewery?

A facility where cereal grain is turned into malt by soaking it in water, allowing it to sprout, and then drying it to inhibit further growth is known as a malt house, malt barn, or maltings. The malt is utilised in the production of beer, whisky, and some meals. During the 20th century, traditional malt houses were mainly replaced by more automated production. A music hall has been made of many former malt houses, including Snape Maltings in England.

Approximately 60% of the primary energy consumed by the malt beverage sector is made up of natural gas and coal (Energy Information Administration (EIA), 1997; National Petroleum Council (NPC), 2003). These fuels are typically utilised as inputs into boilers to provide steam for different processes and for the generation of on-site electricity.

One of the most energy-intensive processes in the malthouse and brewery is the boiling of malt kinling.

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The best reducing agent is Na2S.

A chemical species known as a reducing agent in chemistry "donates" an electron to an electron acceptor. The Earth metals, formic acid, oxalic acid, and sulfite compounds are a few examples of chemicals that are frequently used as reducing agents.

A material that induces oxidation by receiving electrons becomes reduced when it acts as an oxidising agent. A chemical that reduces something by gaining electrons is said to be an oxidising agent. There are examples of how to recognise oxidising and reducing agents.

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Gold is fcc and has a lattice constant of 0.40788 nm . The value for the atomic radius of a gold atom in nanometers is 0.14421 nm. .

A gold atom touches another along the diagonal on each face of the unit cell of a fcc lattice, which has right angles. Typically, the diagonal is shown as extending from the center of one atom to the center of a second atom and to the center of a third atom. As a result, one can construct a right triangle whose hypotenuse is 4r, where r is the radius of a gold atom, and whose legs both have lengths of a = 0.40788 nm. By applying the Pythagorean theorem,

a^2 +  a^2  = ( 4r )^2,

2 a^2 + = (16r^2) ,

and r = (21/2/4)a,

where an is the stated covalent atomic radius of gold and r is 0.14421 nm.

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The half-life gets longer as the initial concentration increases in zero-order reaction.

The amount of time it takes for the concentration of a given reactant to reach 50% of its initial concentration is known as the half-life of a chemical reaction (i.e. the time taken for the reactant concentration to reach half of its initial value).

For zero order reaction:

The half-life is given as:

[tex]t_{1/2}=\frac{[A]_{0}}{2k}[/tex] where k is the rate constant of the reaction and [tex][A]_{0}[/tex] is the initial concentration.

As we can see that the half-life is directly proportional to the initial concentration. Therefore, when the initial concentration increases the half-life gets longer.

For the first-order reaction,

The half-life is given as:

[tex]t_{1/2}=\frac{\ln 2}{k}=\frac{0.693}{k}[/tex]

A first-order reaction's half-life is independent of the initial concentration.

For a second-order reaction,

The half-life is:

[tex]t_{\frac{1}{2} }=\frac{1}{k[A]_{0}}[/tex]

The initial concentration is inversely proportional to the half-life, so when the initial concentration increases the half-life will get shorter.

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Answer:

Probably the most common use is the first-order decay law, which describes everything from radioactive decay to the metabolism of drugs.

Much of the power of logarithms is their usefulness in solving exponential equations. Some examples of this include sound (decibel measures), earthquakes (Richter scale), the brightness of stars, and chemistry (pH balance, a measure of acidity and alkalinity)

Explanation:

The  initial and final pressures are 9 bar and 5 bar and work transfer is 12.5916 kJ.

To find initial and final pressure, we will keep the value of initial and final volume in the given formula.

For the case of initial pressure -

p = AV⁻¹+B

p = (0.06÷0.01)+3

p = 6+3

p = 9 bar

For the case of final pressure -

p = (0.06÷0.03)+3

p = 2+3

p = 5 bar

Now, calculating the work transfer -

The formula to be used here is -

[tex]W = \int\limits^1_2 {p} \, dV[/tex]

Keep the values in formula to find the value of work transfer -

W = [tex]\int\limits^2_1 {(\frac{0.06}{V} +3)} \, dV[/tex]

W = 0.06 (ln 0.03÷0.01)+3(0.03-0.01)

On solving the integration we get -

W = 12.5916 kJ

Hence, the initial and final pressures are 9 bar and 5 bar and work transfer is 12.5916 kJ.

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The complete question is -

Oxygen (O₂) gas within a piston-cylinder assembly undergoes an expansion from a volume V₁ = 0.01 m³ to a volume V₂ = 0.03 m³. The relationship between pressure and volume during the process is p = AV⁻¹+B, where A = 0.06 bar-m³ and B = 3.0 bar. For the O₂, determine the following:

(a) the initial and final pressures, each in bar

(b) the work, in kJ

The IUPAC name of the compound is (r)-3-bromo-3-methyl-1-hexene.

Or  (r)-3-bromo-3-methyl-1-hexene.

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The value of Ka is 2.25 × 10⁻³.

A dissociation constant is a particular kind of equilibrium constant used in chemistry, biochemistry, and pharmacology to measure an object's propensity to break down into its component parts, such as when a complex disintegrates into its component molecules or a salt disintegrates into its component ions.

K is a constant that depends on the equilibrium between ions and non-ionized molecules in a solution or liquid. – also known as the dissociation constant.

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0.19264 × 10^23 molecules of NH4Br are there in 3.166g of NH4Br.

Given

Mass = 3.166g

Molecular mass of NH4Br = 97.94

Moles = Given mass / molar mass

Moles = 3.166 / 97.94

Moles = 0.032

To get number of molecules

Molecules = Moles × 6.02 × 10^23

                = 0.032 × 6.02 × 10^23

Molecules = 0.19264 × 10^23

Depending on the context, the term may or may not include ions that fit this condition. A molecule is a collection of two or more atoms held together by the attractive forces known as chemical bonds.

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The thickness of a sheet of aluminum (al) foil is t = 0.015 mm.

The definition of density is the mass of a material per unit of volume. The Latin letter D may also be used, however the sign is most usually employed to denote density. The mathematical definition of density is mass divided by volume.

row = m/V

where is the density, m is the mass, and V is the volume.

The connection between a substance's mass and the amount of space it occupies is known as its density (volume). The density of a substance is determined by the mass, size, and arrangement of its atoms. Density (D) is defined as the product of a substance's mass and volume.

V = mass/ Density

V = 3.736/2.699

V = 1.3842 cm³

area = 1.00 ft²

as we know,

1ft = (0.305m)²

    = 0.093m²

   = 0.093 * 10⁶ mm²

so, the thickness will be,

t = 1384.2/ 0.093 * 10⁶ mm²

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The net ionic equation is: 2H⁺(aq) + S²⁻(aq) → H₂S(g)

A net ionic equation is an ionic equation which does not indicate the ions which remains in the solution as ions at the end of the reaction but only the ions which form the products are shown in  a net ionic equation.

The ions that remain in solution are known as spectator ions.

The ionic equation of the given reaction is given below:

Mn²⁺S²⁻(aq) + 2H⁺SO₄²⁻ (aq) → Mn²⁺SO₄²⁻ (aq) + H₂S(g)

The net ionic equation is: 2H⁺(aq) + S²⁻(aq) → H₂S(g)

In conclusion, a net ionic equation only shows ions that form products.

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The average atomic mass of silver is 107.8682 amu. The fractional abundance of the lighter of the two isotopes is 0.5185.

The metal has always been in perfect plenty. Both heavier and lighter particles have a combined abundance of 1.

Assume that a is the heavier particle's abundance.

The lighter particle will have an abundance of = 1-a.

Calculations for the element's atomic mass with isotopes go like this:

Average atomic mass equals the sum of the abundance of isotope 1 and isotope 2 masses.

107.8682 amu is the specified average atomic mass.

Lighter isotope 1 has a mass of 106.90509 amu.

The heavier isotope has a mass of 108.9047 amu.

putting the values :

107.8682 = 106.90509 (1 - a) + 108.9047a

107.8682 =  106.90509 - 106.90509a + 108.9047a

107.8682 -  106.90509 = 1.99961a

0.96311 = 1.99961a

a = 0.48

Thus, 0.48 is the heavier particle abundance.

Lighter particle abundance = 1 - a

The density of lighter particles is equal to 1 - 0.48.

Lighter particle abundance = 0.518

The lighter particle has a percent abundance of 51.8%.

The lighter of the two isotopes has a fractional abundance of 0.5185.

Question:

Silver has two naturally occurring isotopes with the following isotopic masses: 10747Ag 10947Ag 106.90509 108.9047 The average atomic mass of silver is 107.8682 amu. The fractional abundance of the lighter of the two isotopes is ________. Silver has two naturally occurring isotopes with the following isotopic masses: Ag Ag 106.90509 108.9047 The average atomic mass of silver is 107.8682 amu. The fractional abundance of the lighter of the two isotopes is ________. 0.24221 0.48168 0.75783 0.90474 0.51835

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A baseball’s resultant velocity is 17.23 m/s, at 26.02° from the level ground then the  horizontal component of the baseball’s velocity is 15.4835m/s

Velocity means the direction of the movement of the body or the object here given data is velocity =17.23 m/s, at angle= 26.02° and we have to find  horizontal component of the baseball’s velocity=?

So, Horizontal distance can be expressed as x=V × t

Cos26.02°=x/17.23 for vector component, this means that the

17.23cos26.02°= x horizontal component is the hypotenuse length

x=15.4835m/s is the horizontal component of the baseball’s velocity

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The sample most likely to be a protein .

Amino acids, which are smaller building blocks of proteins, are linked together in lengthy chains to form proteins. To create a protein, 20 distinct kinds of amino acids can be mixed. Each protein's precise function and distinctive 3-dimensional structure are determined by the order of the amino acids.

Combinations of three DNA building units (nucleotides), which are dictated by the order of genes, are used to code for amino acids.

The main functions of the proteins are determined below:-

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Answer:

106.119 calories

Explanation:

Hope this helps! If you need a step-by-step explanation feel free to ask and I'd be happy to give it to you <33

The pressure of gas will increase by a factor of 4.

When absolute temperature of a gas is increased 4 times while maintaining constant volume, The pressure of the gas is increased by a factor of 4.

This can be explained by Gay-Lussac Law, which states that at any constant volume, the pressure of the gas will be directly proportional to the temperature for a given gas.  
PV=nRT  ,

Gay-Lussac law explains  the relationship between temperature and pressure at constant volume. 

P ∝ T  =>  P1 / T1 = P2 / T2

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Enolate synthesis, nucleophilic addition, and elimination are the three basic steps in the mechanism of a Claisen reaction.

What is Nucleophilic addition reaction?

A chemical molecule having an electrophilic double or triple bond combines with a nucleophile in a nucleophilic addition reaction, breaking the double or triple bond.

A nucleophile attacking the electrophile's location in the reactant molecule and displacing it to generate a product is known as nucleophilic substitution. An electrophile, which is an electron-deficient species that accepts electrons, is present in an electrophilic addition reaction.

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Answer:

2

Explanation:i had this same question

120 KJ of heat is absorbed in this reaction.

As we know

Where W is the provided mass of carbon, which is 30g, n=W/M

M is the carbon molar mass. 30 / 12 = 2.5 moles at 12g/mol.

As a result, the heat absorbed by 2.5 moles of carbon is equal to 120 kJ, or half the heat absorbed by 5 moles of carbon, or 239.9 kJ.

The heat evolved (either emitted or absorbed) during a process that runs at constant pressure is equivalent to the change in enthalpy. The internal energy (U) and pressure-volume product (PV), are both supplied by the equation:

H=U+PV

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Elution sequence for chemicals, from the fastest to the slowest is hydrocarbons, olefins, ethers, halocarbons, aromatics, ketones, aldehydes, esters, alcohols, amines and acids.

What is Elution sequence ?

No matter how polar the compounds are, the more polar the solvent, the faster the chemicals elute. Therefore, altering the polarity of the solvent will not alter the order in which the compounds elute off a TLC or column. This may seem counterintuitive because a polar solvent would seem to carry polar compounds farther than nonpolar compounds.

Consider that chemicals and solvents will fight for locations on the stationary phase in order to help you visualize this idea. Slow elution will be caused by molecules remaining attached to the stationary phase due to a less polar solvent's poor ability to compete. Molecules and a polar solvent will successfully contend for locations on the stationary phase.

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pH of the buffer solution is 1.76.

Chemical dissociation of formic acid in the water:

HCOOH(aq) ⇄ HCOO⁻(aq) + H⁺(aq)

The solution of formic acid and formate ions is a buffer.

[HCOO⁻] = 0.015 M; equilibrium concentration of formate ions

[HCOOH] + [HCOO⁻] = 1.45 M; sum of concentration of formic acid and formate

[HCOOH] = 1.45 M - 0.015 M

[HCOOH] = 1.435 M; equilibrium concentration of formic acid

pKa = -logKa

pKa = -log 1.8×10⁻⁴ M

pKa = 3.74

Henderson–Hasselbalch equation: pH = pKa + log(cs/ck)

pH = 3.74 + log (0.015 M/1.435 M)

pH = 3.74 - 1.98

pH = 1.76

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When we treated 1-pentyne with 2 equivalent of HBr, the formation of 2-Bromo-1-pentene takes place. This reaction follows Markonikov's rule, which states that incoming nucleophile is added to the carbon atom, which has less hydrogen.

When we treated 1-pentyne with 2 equivalent of HBr, the formation of 2-Bromo-1-pentene takes place. This reaction follows Markonikov's rule, which states that incoming nucleophile is added to the carbon atom, which has less hydrogen.

1-bromo-1-pentene.

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