Identify the vertex of the function below.f(x) - 4= (x + 1)2-onSelect one:O a. (-4,1)O b.(1,-4)O c. (-1,-4)O d.(-1,4)

Answers

Answer 1

The standard equation of a vertex is given by:

[tex]f(x)=a(x-h)^2+k[/tex]

where (h,k) is the vertex.

Comparing with the given equation after re-arranging:

[tex]f(x)=(x+1)^2+4[/tex]

The vertex of the function is (-1, 4)


Related Questions

Write a relation consisting of five ordered pairs that satisfies the following conditions. The relation is a function. Switching the x- and y-coordinates of each ordered pair results in a relation that is not a function.

Answers

Answer:

Step-by-step explanation:

If each value of x only has one corresponding value of y, it is a function. You can test this just by eye or by graphing and doing the vertical line test by rolling a pencil or other straight object across to make sure only one point is on the line at a time

Area of a sector A sector with a radius of \maroonD{8\,\text{cm}}8cmstart color #ca337c, 8, start text, c, m, end text, end color #ca337c has an area of \goldE{56\pi\,\text{cm}^2}56πcm

Answers

To find the angle of the sector, follow the steps below.

Step 01: Find the total area of the circle.

The area (A) of a circle with radius r is:

[tex]A=\pi r^2[/tex]

Knowing that r = 8 cm, then the area is:

[tex]\begin{gathered} A=8^2\pi \\ A=64\pi\text{ cm}^2 \end{gathered}[/tex]

Step 02: Find the central angle.

To find the angle, use proportions.

Knowing that:

When angle = 2π, A = 64π,

Then when angle is x, A = 56π

[tex]\begin{gathered} \frac{x}{2\pi}=\frac{56\pi}{64\pi} \\ \\ \text{ Multiplying both sides by 2}\pi: \\ \frac{x}{2\pi}*2\pi=\frac{56\pi}{64\pi}*2\pi \\ x=\frac{56*2}{64}\pi \\ x=\frac{112}{64}\pi \\ \\ \text{ Dividing both the numerator and the denominator by 16:} \\ x=\frac{\frac{112}{16}}{\frac{64}{16}}\pi \\ x=\frac{7\pi}{4} \end{gathered}[/tex]

Answer: The central angle measure is:

[tex]\frac{7\pi}{4}[/tex]

Solve by using a proportion. Round answers to the nearest hundredth if necessary. 1. You jog 3.6 miles in 30 minutes. At that rate, how long will it take you to jog 4.8 miles? 2. You earn $33 in 8 hours. At that rate, how much would you earn in 5 hours?

Answers

EXPLANATION

Let's see the facts:

rate ---> 3.6 miles / 30 minutes

The unit rate is:

Unit rate = 0.12 miles/minute

Now, dividing the needed 4.8 miles by the unit rate will give us our desired number:

Time= 4.8 miles/ 0.12miles/minute = 40 minutes

The answer is 40 minutes.

List the angle measures of △VWX in order from smallest to largest. Assume that t is a positive number.

Answers

Explanation

To begin with, we will first have to obtain the length of side VX

[tex]VX^2=WX^2+VW^2-2\times WX\times VWcosw[/tex]

In our case

[tex]\begin{gathered} WX=28t \\ VW=95t \\ w=94^0 \end{gathered}[/tex]

Thus

[tex]\begin{gathered} VX^2=(28t)^2+(95t)^2-2\times(28t\times95t)cos94 \\ \\ VX^2=784+9025+371.104 \\ VX^2=100180.10 \\ \\ VX=100.90t \end{gathered}[/tex]

Next, we will determine the angles at V and X

using sine rule

[tex]\begin{gathered} \frac{sin94}{100.9t}=\frac{sinV}{28t} \\ \\ sinV=\frac{28t\times sin94}{100.9t} \\ \\ sinV=0.27683 \\ \\ V=16.07^0 \\ \end{gathered}[/tex]

Then, we will get the measure at X

[tex]180^0-16.07^0-94=69.93^0[/tex]

Therefore, the order from smallest to largest angles will be

m

OR

m

2. Graph the image of Parallelogram WXYZ under a translation 4 units to the left and 6 units up

Answers

Translation 4 units to the left transforms the point (x, y) into (x-4, y). Applying this rule to the parallelogram WXYZ, we get:

W(0, -2) → (0-4, -2) →W'(-4, -2)

X(2, -2) → (2-4, -2) → X'(-2, -2)

Y(2, -5) → (2-4, -5) → Y'(-2, -5)

Z(0, -5) → (0-4, -5) → Z'(-4, -5)

Translation 6 units up transforms the point (x, y) into (x, y+6). Applying this rule to the parallelogram W'X'Y'Z', we get:

W'(-4, -2) → (-4, -2+6) → W''(-4, 4)

X'(-2, -2) → (-2, -2+6) → X''(-2, 4)

Y'(-2, -5) → (-2, -5+6) → Y''(-2, 1)

Z'(-4, -5) → (-4, -5+6) → Z''(-4, 1)

Where the parallelogram W''X''Y''Z'' is the image of Parallelogram WXYZ translated 4 units to the left and 6 units up, as can be seen in the next graph:

hector recorded the amount of rainfall in the desert each month over a period of two years. the list shows the number of inches fell for each month for year 1 and year 2 year 1: 2,2,0,0,0,1,2,2,3,2,2,2year 2:1,1,0,0,0,0,2,2,2,1,2,1 whats the difference in rain fall between the mean of the rain fall in two years hurry its a test

Answers

ANSWER

The difference is 0.5

EXPLANATION

We have to find the mean of the rain fall for each year. To do this we have to add all the data and then divide by the total number of data.

Year 1: number of data = 12:

[tex]\bar{x_1}=\frac{2+2+0+0+0+1+2+2+3+2+2+2}{12}=\frac{18}{12}=\frac{3}{2}=1.5[/tex]

Year 2: number of data = 12:

[tex]\bar{x_2}=\frac{1+1+0+0+0+0+2+2+2+1+2+1}{12}=\frac{12}{12}=1[/tex]

The difference is:

[tex]\bar{x}_1-\bar{x}_2=1.5-1=0.5[/tex]

Use the graph of 'f' in the figure below to answer the following questions. 1. State the domain and range of 'f'.2. Find the average rate of change of 'f' over the interval [0,6].

Answers

The domain of the given function corresponds to:

[tex]\lbrack-4,-2)\cup(-2,6)[/tex]

And the range of the function is:

[tex](-2,6)[/tex]

The average rate of change of f over the interval [0,6] is:

[tex]\frac{5.5-(-2)}{0-6}=\frac{7.5}{-6}=-\frac{5}{4}=-1.25[/tex]

hello I just need help with these no need to explain just the answers please

Answers

The two pairs of angles are supplementary

Here, we want to complete the given sentence

We want to find the relationship between two parallel lines which are cut by a transversal

A figure showing the described relationship is given below;

Now, we want to find the relationship between the two marked angles

From what we have, the two marked angles are supplementary

What this mean is that both angles add up to 180 degrees

Ashley‘s Internet service is terribly unreliable in fact on any given day there’s a 60% chance that her Internet‘s connection will be lost at some point that day what is the probability that her Internet service is not broken for seven days in a row inner a fraction or round your answer to four decimal places if necessary.

Answers

Let the event that her internet will be broken be A

The event that her internet will not be broken be B

Therefore:

[tex]\begin{gathered} P(A)=60\%=0.60 \\ P(B)=1-0.60=0.4 \end{gathered}[/tex]

Thus, the probability that her internet is not broken for 7 days in a row:

[tex]P(B\text{ for 7 days\rparen=P\lparen B\rparen}\times\text{P\lparen B\rparen}\times\text{P\lparen B\rparen}\times\text{P\lparen B\rparen}\times\text{P\lparen B\rparen}\times\text{P\lparen B\rparen}\times\text{P\lparen B\rparen}[/tex]

Substitute the value:

[tex]P(B\text{ for 7 days\rparen=0.4}\times\text{0.4}\times\text{0.4}\times\text{0.4}\times\text{0.4}\times\text{0.4}\times\text{0.4=0.001634}[/tex]

Round to four decimal places is 0.0016

Answer: 0.0016

Given that events A and B are independent with P(A) = 0.08 and P(B) = 0.25,determine the value of P(A and B), rounding to the nearest thousandth, ifnecessary.

Answers

To find: P(AandB)

P(AandB)=P(A)*P(B)

P(AandB)=0.08*0.25

P(AandB)=0.02

Thus the required answer is 0.02

What is 13.496 rounded to the nearest tenth?A.13B.13.4C.13.5D.14

Answers

[tex]C)13.5[/tex]

1) When we need to round up or down to the nearest tenth, it's necessary to consider the hundredth's place.

2) Note this number:

We can see that 13.496 is greater than 13.45 so it is closer to 14 than 13, then we can round it off to the nearest greater number than 4.

3) Thus, we can round it off to:

[tex]13.5[/tex]

Part 1: Factorial! 3. What are the pros and cons to using the factorial function on your calculator in terms of understanding and/or thecalculation itself?

Answers

Explanation

We are required to determine the pros and cons of using the factorial function on the calculator.

Hence, the answers are:

- Pros

• It makes calculation easier.

,

• It makes calculations to be done in an efficient manner.

,

• It helps students to solve complicated questions seamlessly.

- Cons

• It cannot help with large numbers as the calculator has limited space for answer preview.

,

• It does not help to understand better how the calculation is done.

* The functions f(x) and g(x) are both linear. f(2) = 4 and f(3) = -1, while g(2) = 6 and g(-3) = 7. Are these lines parallel, perpendicular, or neither? Show your work algebraically.

Answers

Solution

f(2) = 4 and f(3) = -1

g(2) = 6 and g(-3) = 7

From the info given we can see this :

x = 2 f(2) = 4 , g(2)= 6

x= 3 f(3)= -1 , g(3)= 7

And we can calculate the slope with the following formula:

[tex]m=\frac{-1-4}{3-2}=-5[/tex][tex]m=\frac{7-6}{3-2}=1[/tex]

And for this case we can conclude that the lines are neither

Since m1 is different from m2

And m1*m2 is not -1

have $100 to spend on Halloween candy. A pack of M&Ms cost $3.50. 15 Twix bars cost $7.00. 9 Hershey Bars cost $3.00. If I need 15 M&M packs, 17 Twix bars and 9 Hershey bars how much will it cost? How much money will I have left?

Answers

Answer:

Assuming this is rounding to the nearest cent, $36.51

Step-by-step explanation:

    1 ) Find the cost of each individual candy.

M&Ms are given at $3.50 per pack.

To find the cost of one Twix bar, divide $7.00 by 15. This makes Twix equal $0.47 per bar.

You don't need to find the individual price of the Hershey's bars because 9 bars cost $3.00 and you need 9 bars in the equation.

    2 ) Now that you have the prices you need, multiply.

For M&Ms 15 x $3.50 = $52.50

For Twix 17 x $0.47 = $7.99

For Hershey's, it is given that 9 bars are $3.00

    3 ) Add all of these up to get the total spent on candy.

$52.50 + $7.99 + $3.00 = $63.49

    4 ) Subtract this from the budget to get the total amount left over.

$100 - $63.49 = $36.51

y = (x+3)^3 find the zeros of each function

Answers

Given,

[tex]y=(x+3)^3[/tex]

We have,

[tex]y=0[/tex]

when,

[tex]\begin{gathered} x+3=0 \\ \Rightarrow x=-3 \end{gathered}[/tex]

The zeros of the function are x=-3,-3,-3

A pool is filled to 3/4 of its capacity 1/9 of water in the pool, evaporates. If the pool can hold 24,000 gallons when it is full, how many gallons of water will have to be added in order to fill the pool?A. 6,000B. 8,000C.12,000D.16,000

Answers

First, the pool was filled to 3/4 of its capacity, which is equal to:

[tex]24000\cdot\frac{3}{4}gal=18000gal.[/tex]

Then, 1/9 of the water evaporated remaining 8/9 of the 18000 gal:

[tex]18000\text{gal}\frac{8}{9}=16000gal.[/tex]

Therefore, to fill the pool we need to add:

[tex]24000-16000[/tex]

gallons of water.

Answer: B. 8000.

Kuta Sotware - Infinite Algebra 2 Solving Inequalities Solve each inequality and graphite 10 > Kuin Software - Infinite Algebra 2 Graphing Linear Inequalities Sketch the graph of each linear inequality. Name Samante 1) yz-2x-2 Y-2-2 2). ys - !

Answers

Could you please send a picture of the inequality you are asked to solve?

I'll be closing the session now if you cannot do it. Please ask your question again, and send the image in the question itself to avoid this problem of your uploaded images and messages not getting to me.

Thank you, and please re-submit your question request.

The half-life of a radioactive kind of iodine is 21 hours. How much will be left after 42 hours,if you start with 19,296 grams of it?In grams

Answers

The half-life of a radioactive material is the time that it takes to reduce to half

In this case, the half-life is 21 hs, and since 42hs is twice the half-life, the material will reduce to half after 21 hours and then to half again.

one half of one half is:

[tex]\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{4}[/tex]

Then we multiply by the initial amount:

[tex]19,296\cdot\frac{1}{4}=4824gr[/tex]

The amount left after 42 hours is 4824 grams.

Find the tangent of the angle whose measure is pi/2....pi divided by 2.

Answers

We have the following:

[tex]\begin{gathered} \tan \theta=x \\ \tan \frac{\pi}{2}=x \end{gathered}[/tex]

the value of pi / 2 is not defined

Help me pls on math homework!!!!!

Answers

He sold 28 watermelons on Friday.

How to find the number of watermelons sold on Friday?

The number of watermelons sold during the entire week is of 60, hence we find the daily amounts and add them, and this has to reach 60. The daily amounts are given as follows:

Monday: x.Tuesday: 2x. (twice as many as Monday).Wednesday: 0.5x. (half as many as Monday).Thursday: 18.Friday: 6x + 4. (four more than twice the amount sold on Monday).

Hence the following equation is built, and we can solve for the unknown variable x as follows:

x + 2x + 0.5x + 18 + 6x + 4 = 60.

9.5x = 38

x = 38/9.5

x = 4

Then the amount sold on Friday is calculated as follows:

Friday = 6x + 4 = 6(4) + 4 = 24 + 4 = 28 watermelons.

More can be learned about equations at https://brainly.com/question/24808124

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He sold 28 watermelons on Friday

What is the number of watermelons he sold on Friday?

The total number of watermelons sold for the whole summer week is 60

He sold x watermelons on Monday

On Tuesday, he sold twice the numbers sold on Monday: 2x

On Wednesday, he sold half the numbers sold on Monday: x/2

On Thursday, he sold 18

On Friday, he sold:

= 2(x+2x) + 4 = 2(3x) + 4 = 6x + 4

And we know that the total number of watermelons is 60. Therefore:

x + 2x + x/2 + 18  + 6x+4 = 60

9.5x + 22 = 60

9.5x = 60 - 22

9.5x = 38

x = 4

since the amount sold on Friday is  6x+4:

= 6 x 4 +  4

= 24 + 4 = 28

Therefore, he sold 28 watermelons on Friday

Learn more about word problems on:

https://brainly.com/question/13818690

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You invent a game that is played on a perfect 12 foot by 12 foot square. What is the longest distance between any two points on the square? A. 12 feetB. 15 feetC. 17 feetD. None of the aboveI will really appreciate the help on this problem.

Answers

The given figure is a square that measures 12 foot by 12 foot. please see illustration below;

The square in the sketch above shows the longest distance between two opposite diagonals, and that is the hypotenuse, labelled as a.

In the triangle ADC, using Pythagoras' theorem;

[tex]\begin{gathered} AD^2+DC^2=AC^2 \\ 12^2+12^2=a^2 \\ 144+144=a^2 \\ 288=a^2 \\ \sqrt[]{288}=a \\ a=16.97 \end{gathered}[/tex]

The longest distance which is a (that is AC) is approximately 17 ft as shown above (16.97 ft).

use the generic rectangle 3x-8)² and -7x⁴(3x-2) what's the product and sum?

Answers

In this case the answer is very simple .

Step 01:

Data:

eq1. (3x - 8)²

eq2. -7x⁴(3x-2)

Step 02:

Sum.

eq.1 + eq.2

(3x - 8)² + (-7x⁴(3x-2))

(9x² - 2*3x*8 - 64) + (-21x⁴ - 14x⁴)

9x² -

Which phrase represents the algebraic expression for n-4.A) The quotient of a number and 4. B) 4 less than a number. C) 4 minus a number. D) 4 more than a number.

Answers

B) 4 less than a number.

Solve the following logarithmic equation.  Select the correct choice below and, if necessary, fill in the answer box to complete your choice.(Simplify your answer. Type an exact answer. Use a comma to separate answers as needed.)

Answers

Hello

We are given a log funtion to solve and see if it have a solution.

[tex]\log _2(x+2)=\log _2(15)[/tex]

Step 1

we apply log rules

[tex]\begin{gathered} \log _2(x+2)=\log _215 \\ x+2=15 \end{gathered}[/tex]

Step 2

Solve for x

[tex]\begin{gathered} x+2=15 \\ x=15-2 \\ x=13 \end{gathered}[/tex]

From the calculation above, the solution of the set is 13; i.e x = 13

students at a local school were asked about how many hours do you spend on homework each week? the table shows the results of the survey classify the statement below as a true or false more students study for 3 to 4 hours than for 5 to 6 hours the statement is (true or false) because.... students study for 3 to 4 hours and..... students study for 5 to 6 hours.

Answers

The total of students that study for 3 to 4 h is 147

The total of students that study for 5 to 6 h is 107

Then, the statement: "more students study for 3 to 4 hours than for 5 to 6 hours" is true because 147 students study for 3 to 4 hours and 107 students study for 5 to 6 hours.

can you explain this to me what you are supposed to do this

Answers

Solution

If we see the two tirangles given BAC and A'B'C' we can conclude that we have the following congruent angles

< CAB = < C'A'B'

< BCA = < B'C'A'

< ABC = < A'B'C'

Compute the area of each triangle. Round to the nearest tenth.

Answers

The triangle ΔDEF has the following coordinates

[tex]\lbrace D(-1,6),E(-4,-6),F(3,-5)\rbrace[/tex]

To find the area of a triangle in coordinate geometry, we have a formula. Given 3 vertices A(x1, y1), B(x2,y2) and C(x3,y3), the area of this triangle is given by

[tex]Area(\Delta ABC)=\frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|[/tex]

Using this formula for our problem, we have

[tex]Area_{\Delta DEF}=\frac{1}{2}|(-1)((-6)-(-5))+(-4)((-5)-6)+3(6_{}-(-6))|[/tex]

Solving this equation, we have

[tex]\begin{gathered} Area_{\Delta DEF}=\frac{1}{2}|(-1)((-6)-(-5))+(-4)((-5)-6)+3(6_{}-(-6))| \\ =\frac{1}{2}|(-1)((-6+5)+(-4)(-5-6)+3(6_{}+6)| \\ =\frac{1}{2}|(-1)(-1)+(-4)(-11)+3(12)| \\ =\frac{1}{2}|1+44+36| \\ =\frac{1}{2}|81| \\ =\frac{81}{2} \\ =40.5 \end{gathered}[/tex]

And this is our answer Area(ΔDEF) = 40.5

Match each step with the correct expression to factor s2 + 78 + 6 by using the decomposition method.

Answers

We have the following:

[tex]s^2+7s+6[/tex]

solving:

[tex]\begin{gathered} \text{step 1} \\ s^2+s+6s+6 \\ \text{step 2} \\ s\mleft(s+1\mright)+6\mleft(s+1\mright) \\ \text{step 3} \\ (s+1)(s+6) \end{gathered}[/tex]

In which of the following triangles does m

Answers

Okay let's analyze each triangle

In triangles A, B, and D the angle

Suppose that the velocity v (t) (in meters per second) of a sky diver falling near the Earth’s surface is given by the following exponential function, where time t is the time after diving measured in seconds.

Answers

The equation of the velocity is given by the exponential:

[tex]v(t)=53-53e^{-0.24t}[/tex]

Let us say that the sky driver's velocity will be 47 m/s at t₁. Then, using the expression above:

[tex]\begin{gathered} v(t_1)=47 \\ 53-53e^{-0.24t_1}=47 \end{gathered}[/tex]

Solving for t₁:

[tex]\begin{gathered} \frac{53-47}{53}=e^{-0.24t_1} \\ \ln (\frac{6}{53})=-0.24t_1 \\ t_1=9.1s \end{gathered}[/tex]

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