The values of a and C using Law of sines is: a = 23.2 and C = 94°
How to use Law of sine?You can use the Law of Cosines, if only one of which is missing: three sides and one angle. Hence, if the known properties of the triangle is SSS(side-side-side) or SAS (side-angle-side), this law is applicable.
You can use the Law of Sines if you want to equate the ratio of the sine of an angle and its opposite side. This can be used if the known properties of the triangle is ASA(angle-side-angle) or SAS.
We are given the parameters as:
A = 39°, B = 47°, and b = 27
a/sin A = b/sin B
Thus:
a = (27 * sin 39)/sin 47
a = 23.2
Sum of angles in a triangle is 180 degrees. Thus:
C = 180 - (47 + 39)
C = 94°
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Which of the following combinations of side lengths would NOT form a triangle with vertices X, Y, and Z? A. XY = 11 mm , YZ = 12 mm , XZ = 18 mm B. XY = 16 mm , YZ = 12 mm , XZ = 23 mm C. XY = 16 mm , YZ = 17 mm , XZ = 18 mm D. XY = 11 mm , YZ = 12 mm , XZ = 28 mm
the answer is (D) XY = 11 mm, YZ = 12 mm, XZ = 28 mm would NOT form a triangle with vertices X, Y, and Z.
How to solve the question?
To determine whether a triangle can be formed using the given side lengths, we need to apply the Triangle Inequality Theorem, which states that the sum of any two sides of a triangle must be greater than the third side.
Let's check each option:
A. XY = 11 mm, YZ = 12 mm, XZ = 18 mm
To form a triangle, we need to check whether the sum of any two sides is greater than the third side. Let's check:
XY + YZ = 11 mm + 12 mm = 23 mm > XZ = 18 mm
YZ + XZ = 12 mm + 18 mm = 30 mm > XY = 11 mm
XY + XZ = 11 mm + 18 mm = 29 mm > YZ = 12 mm
All the combinations are greater than the third side, so a triangle can be formed with these side lengths.
B. XY = 16 mm, YZ = 12 mm, XZ = 23 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 16 mm + 12 mm = 28 mm > XZ = 23 mm
YZ + XZ = 12 mm + 23 mm = 35 mm > XY = 16 mm
XY + XZ = 16 mm + 23 mm = 39 mm > YZ = 12 mm
Again, all the combinations are greater than the third side, so a triangle can be formed with these side lengths.
C. XY = 16 mm, YZ = 17 mm, XZ = 18 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 16 mm + 17 mm = 33 mm > XZ = 18 mm
YZ + XZ = 17 mm + 18 mm = 35 mm > XY = 16 mm
XY + XZ = 16 mm + 18 mm = 34 mm > YZ = 17 mm
All the combinations are greater than the third side, so a triangle can be formed with these side lengths.
D. XY = 11 mm, YZ = 12 mm, XZ = 28 mm
Let's check whether the sum of any two sides is greater than the third side:
XY + YZ = 11 mm + 12 mm = 23 mm < XZ = 28 mm
YZ + XZ = 12 mm + 28 mm = 40 mm > XY = 11 mm
XY + XZ = 11 mm + 28 mm = 39 mm > YZ = 12 mm
The first combination is less than the third side, so a triangle cannot be formed with these side lengths.
Therefore, the answer is (D) XY = 11 mm, YZ = 12 mm, XZ = 28 mm would NOT form a triangle with vertices X, Y, and Z.
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If quadrilateral PQRS is a parallelogram, line segment QR is ≅ to line segment QT, and m∠TQR=60°, which angles are congruent to ∠S? Select all that apply.
a.) ∠P
b.) ∠PQR
c.) ∠RQT
d.) ∠QRT
e.) ∠SRQ
f.) ∠TQR
From the given information, you can deduce that triangle QTR is equilateral and equiangular (all angles are 60 degrees)
b, c, d, and f are true
The opposite angles of a parallelogram are congruent (b)
If 2 parallel lines are cut by a transversal, then the corresponding angles are congruent (d)
Angle RQT is congruent to angle QRT, and angle QRT is congruent to angle S. By the transitive property, angle RQT is congruent to angle S (c)
Transitive property, like c (f)
Which equation is perpendicular to y= -2/7x - 5 and passes through (2,4)?
micah wants to know the most common style of surfboard used at rhe breakers point. He surverys surfers at breakers point between 8:00 am and 12:00 pm.
solve for x please
Choices are..
6
20
140
90
Answer:
Answer is 20
Step-by-step explanation:
When two lines intersect each other as a result of that, every opposite angles are equal
so,
6x+20 = 140
6x = 120
x = 120/6
x = 20
Answer:
x = 20
Step-by-step explanation:
Vertically opposite are equal
therefore
6x + 20 = 140
6x = 140-20
6x = 120
6x/6 = 120/6
x = 20
ing walk at
e, in miles, to the
ter x hours is
t 8:00 AM,
minutes
5 miles
5 mile
st office.
graph of the
.5x + 2 is shown.
12. Peter opens an
$600 deposit that earns 8% simple
interest annually. He makes no
other deposits or withdrawals.
Complete the sentences.
This situation can be modeled by a
quadratic
linear
$12
$48
After 4 years, Peter will have
$48
$192
grows
function that
earned
each year.
in interest.
Answer:
Peter opens an account with a $600 deposit that earns 8% simple interest annually. He makes no other deposits or withdrawals.
Complete the sentences:
This situation can be modeled by a linear function that grows in interest.
Peter will earn $48 in interest each year.
Explanation:
Simple interest is calculated as a percentage of the principal amount and does not compound over time. Therefore, the amount of interest earned each year is constant, and the growth of the account is linear.
To calculate the amount of interest earned each year, we multiply the initial deposit by the interest rate:
$600 x 0.08 = $48
Therefore, Peter will earn $48 in interest each year. After four years, he will have earned:
4 x $48 = $192
So his total balance will be:
$600 + $192 = $792
Since the growth of the account is linear, we can model it with a linear function of the form:
y = mx + b
Where y is the total balance, x is the number of years, m is the slope (or rate of growth), and b is the initial balance.
In this case, the slope is the amount of interest earned each year, which is $48, and the initial balance is $600. So the linear function that models this situation is:
y = 48x + 600
Find the measure of the line segment indicated, assume that lines which appear tangent, are tangent.
Find FS
Possible answers —>
A. 17
B. 21
C. None of the other answers are correct
D. 18
E. 45
The value of x for the intersecting chords is derived to be 1.9 and the segment FS is equal to 18
What is the properties of intersecting chordsThe property of intersecting chords states that in a circle, if two chords intersect, the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord.
UF × FS = VF × FT
8(10x - 1) = 9 × 16
80x - 8 = 144
80x = 144 + 8 {collect like terms}
80x = 152
x = 152/80 {divide through by 80}
x = 1.9
FS = 10(1.9) - 1 = 18
Therefore, the value of x for the intersecting chords is derived to be 1.9 and the segment FS is equal to 18
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the following are percentages of fat found in 5 samples of each of two brands of ice cream: a 5.7 4.5 6.2 6.3 7.3 b 6.3 5.7 5.9 6.4 5.1 which of the following procedures is appropriate to test the hypothesis of equal average fat content in the two types of ice cream? a paired t test with 5 df. b . two-sample t test with 4 df. c paired t test with 4 df. d two-sample t test with 9 df. e two-proportion z test
with 4 df.
The correct answer is d. Two-sample t test with 9 df.
11. Jessica is focusing on wrestling this semester. What category does this sport fall into?
The Correct Answer Is: High-strength sports.
explanation:
Because for wrestling you have to use, you're strength. (And I just did the exam and I got it wrong for choosing the wrong answer, so I believe it's my answer. !!so, it's not high-power sports)
I hope it helps you!
:)
please help me find these 2!! it’s due tmmr and it would help a lot!!
Answer:
the outlier is 37 but for 43 are they asking for the upper and lower quartiles or the lowest and highest number
Jada said: I know that 55 is less than 62, so -55 is also less than -62.this means it was colder on Mars.do you agree?
Answer:
I cannot agree or disagree with this statement without more information.
The fact that -55 is less than -62 is correct, and it does suggest that the temperature on Mars may have been colder than the temperature on Earth (assuming that the comparison is being made between temperatures measured in the same units). However, it's important to note that comparing just two temperatures (even if they are in different units) is not enough to draw conclusions about the overall climate or temperature patterns on Mars or Earth.
In addition, it's unclear what evidence Jada is using to make this comparison. Without more context or information about the source of this statement, it's difficult to evaluate its accuracy or validity.
the mean iq of the population of osu students is 100. a random sample of 5 students will be taken from the population, but the first student scored 150. what do expect the average to be for the 5 students?
Even though the first student scored 150, the expected average IQ score for the remaining four students is still 100.
Explain average
The average is a statistical measure that represents the central tendency of a set of values. It is calculated by adding up all the values and dividing them by the total number of values. The average provides a single value that represents the typical value in the set and is often used to compare different sets of data or to summarize large amounts of data.
According to the given information
Let X be the random variable representing the IQ score of an individual student. Then, the sample mean of the five students, denoted by Y, can be expressed as:
Y = (X1 + X2 + X3 + X4 + X5) / 5
Given that the first student scored 150, the expected value of the sample mean of the remaining four students, denoted by E(Y|X1=150), can be calculated as follows:
E(Y|X1=150) = E((X2 + X3 + X4 + X5) / 4 | X1 = 150)
Since X1 = 150 is an observed value, we can treat it as a constant and apply the linearity of expectation:
E((X2 + X3 + X4 + X5) / 4 | X1 = 150) = (E(X2 | X1 = 150) + E(X3 | X1 = 150) + E(X4 | X1 = 150) + E(X5 | X1 = 150)) / 4
Now, since the sample is random, the remaining four IQ scores are also independent and identically distributed as X, with the same mean of 100. Therefore, we have:
E(X2 | X1 = 150) = E(X3 | X1 = 150) = E(X4 | X1 = 150) = E(X5 | X1 = 150) = E(X)
Thus, we can simplify the expression as:
E(Y|X1=150) = (4E(X) / 4) = E(X) = 100
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Is the triangle equilateral, isoscele, or scalene?
Answer: This triangle is isoscele
Step-by-step explanation:
subtract (c-3d-e) from the sum of (4c+d-e) and (2c-3d+2e)
To subtract (c-3d-e) from the sum of (4c+d-e) and (2c-3d+2e), we can first find the sum of the two polynomials, which is (4c+d-e) + (2c-3d+2e) = 6c - 2d + e. Then, we can subtract (c-3d-e) from this sum by changing the signs of the terms in (c-3d-e) and adding the resulting polynomial to 6c - 2d + e. This gives us:
(4c+d-e) + (2c-3d+2e) - (c-3d-e) = 5c + d + 4e
Therefore, the answer is 5c + d + 4e.
If I mean absolute division is close to 0 then what does that mean about the data set
Answer:
If the mean absolute deviation of a data set is close to 0, it means that the data values in the set are very close to the mean of the set. In other words, the data points are clustered tightly around the average value, indicating that there is little variation or dispersion in the data.
This can be useful information in analyzing the data, as it suggests that the data is relatively homogeneous and consistent. On the other hand, if the mean absolute deviation is large, it suggests that the data is widely spread out and may have significant variability, which may require further investigation or analysis.
In how many ways can a committee of two men and one women be formed from a group of ten men and eight women?
Out of a group of ten men & eight women, there are 1320 possible ways to form a committee of two men and one woman.
What is number?Numbers are mathematical units of measurement and labelling. It is a sign or collection of symbols that are used to represent a quantity, usually a real or integer number.
Out of a group of ten men & eight women, there are 1320 possible ways to form a committee of two men and one woman. The idea of combination can be used to arrive to this number.
Calculating the number of possible combinations of a given number of things is done mathematically using the concept of combination. C(n,r) = n! / (r! (n - r)!), where n is the total number of items and r is the number of things to be picked at a time, is the formula used to compute it. In this instance, r is the number of persons to be picked, which is 3, and n is the total number of people to be chosen from the group, which is 18, consisting of 10 males and 8 women.
As a result, there are a total of 10 ways for men and 8 ways for women to form a committee of two men and one woman C(18,3) = 18! / (3! (18 - 3)!) = 18! / (3! 15!) = 1320.
Thus, there are 1320 different methods to create a committee of two men and one woman out of a group of ten men and eight women.
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May anyone help with this question
Rounding to the nearest hundredth, the arc length of one slice is approximately 53.67 feet.
What is arc length?Arc length is the distance along the curved line or arc of a circle, measured in linear units such as centimeters, feet, or meters. It is calculated as the product of the radius of the circle and the angle subtended by the arc at the center of the circle, expressed in radians.
Here,
Since the circle is divided into eight equal slices, each slice is 360/8 = 45 degrees. The arc length of one slice can be calculated using the formula:
Arc length = (angle/360) x 2πr
where angle is the central angle in degrees, r is the radius of the circle, and π is the constant pi.
In this case, the diameter of the circle is 137 feet, so the radius is half of that, or 68.5 feet.
Substituting the given values into the formula, we get:
Arc length = (45/360) x 2 x 3.14 x 68.5
Arc length = 0.125 x 2 x 3.14 x 68.5
Arc length = 0.785 x 68.5
Arc length = 53.67 feet
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Graph the solution of the inequality.
3.5
Project Option 1
For this option, you will work individually.
Instructions
For this option, you will work individually.
You’ve worked hard in this module to become a pro at equations! Now, you’ll put your skills to the test. Your job is to create an equations portfolio. The format is up to you. Be creative! You may use a slideshow, document, video, etc. As long as all of the parts of the project are addressed, the delivery is up to you.
Your portfolio must include a minimum of the following five types of equations and solutions:
Two one-step equations
Two equations that contains fractions
One equation with distributive property
One equation with decimals
One real-world problem that is solved by an equation
Remember that each equation must include at least one variable. Once you have created each equation, you will solve it and show your work. Pretend that you are teaching the equations to a new pre-algebra student. Or you can actually teach them to a sibling or friend!
This is a total of 7 equations and solutions.
Equations are used to solve different types of problems in mathematics and in the real world.The five types of equation are 2x = 8,2y/2 = 8/2, (1/2)x + 2 = 3,3(x+4)= 21,0.4x + 1.2 = 2.6.
What is Equations Portfolio?
Equations are an essential part of mathematics and have various applications in real-world problems. In this portfolio, we will cover different types of equations and solve them step by step. This portfolio will cover one-step equations, equations with fractions, equations with the distributive property, and equations with decimals.
One-step equations are equations that can be solved in one step. For example, if we have the equation 2x = 8, we can solve it by dividing both sides by 2. Let's solve two one-step equations,
3x = 15
Dividing both sides by 3
3x/3 = 15/3
x = 5
Again,
2y = 8
Dividing both sides by 2
2y/2 = 8/2
y = 4
Equations with fractions are equations that contain fractions. To solve these equations, we need to clear the fractions by multiplying both sides of the equation by the least common multiple (LCM) of the denominators. Let's solve two equations with fractions:
(1/2)x + 2 = 3
Subtracting 2 from both sides
(1/2)x = 1
Multiplying both sides by 2 (LCM of 1/2)
(1/2)x × 2 = 1 × 2
x = 2
(2/3)y - 1 = 3
Adding 1 to both sides
(2/3)y = 4
Multiplying both sides by 3 (LCM of 2/3)
(2/3)y × 3 = 4 × 3
y = 6
Equations with distributive property are equations that involve distributing a number or a variable to the terms inside the parentheses. Let's solve an equation with the distributive property,
3(x + 4) = 21
Distributing 3 to (x + 4)
3x + 12 = 21
Subtracting 12 from both sides
3x = 9
Dividing both sides by 3
x = 3
Equations with decimals are equations that contain decimal numbers. To solve these equations, we need to clear the decimals by multiplying both sides of the equation by a power of 10. Let's solve an equation with decimals,
0.4x + 1.2 = 2.6
Subtracting 1.2 from both sides
0.4x = 1.4
Multiplying both sides by 10 (power of 10 for one decimal place)
0.4x × 10 = 1.4 × 10
4x = 14
Dividing both sides by 4
x = 3.5
Now let's solve a real-world problem using an equation,
Sarah has $500 in her bank account. She wants to buy a dress for $120 and save the rest of the money. How much money will Sarah save?
Let x be the amount of money Sarah saves.
Total money = $500
Money spent on the dress = $120
Money saved = Total money - Money spent on the dress
x = 500 - 120
x = 380
Therefore, Sarah will save $380.
In conclusion, equations are used to solve different types of problems in mathematics and in the real world.
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The five types of equation are 2x = 8,2y/2 = 8/2,(1/2)x + 2 = 3,3(x + 4) = 21,0.4x + 1.2 = 2.6.
What is Equations Portfolio?Equations are an essential part of mathematics and have various applications in real-world problems. In this portfolio, we will cover different types of equations and solve them step by step. This portfolio will cover one-step equations, equations with fractions, equations with the distributive property, and equations with decimals.
One-step equations are equations that can be solved in one step. For example, if we have the equation 2x = 8, we can solve it by dividing both sides by 2. Let's solve two one-step equations,
3x = 15
Dividing both sides by 3
3x/3 = 15/3
x = 5
Again,
2y = 8
Dividing both sides by 2
2y/2 = 8/2
y = 4
Equations with fractions are equations that contain fractions. To solve these equations, we need to clear the fractions by multiplying both sides of the equation by the least common multiple (LCM) of the denominators. Let's solve two equations with fractions:
(1/2)x + 2 = 3
Subtracting 2 from both sides
(1/2)x = 1
Multiplying both sides by 2 (LCM of 1/2)
(1/2)x × 2 = 1 × 2
x = 2
(2/3)y - 1 = 3
Adding 1 to both sides
(2/3)y = 4
Multiplying both sides by 3 (LCM of 2/3)
(2/3)y × 3 = 4 × 3
y = 6
Equations with distributive property are equations that involve distributing a number or a variable to the terms inside the parentheses. Let's solve an equation with the distributive property,
3(x + 4) = 21
Distributing 3 to (x + 4)
3x + 12 = 21
Subtracting 12 from both sides
3x = 9
Dividing both sides by 3
x = 3
Equations with decimals are equations that contain decimal numbers. To solve these equations, we need to clear the decimals by multiplying both sides of the equation by a power of 10. Let's solve an equation with decimals,
0.4x + 1.2 = 2.6
Subtracting 1.2 from both sides
0.4x = 1.4
Multiplying both sides by 10 (power of 10 for one decimal place)
0.4x × 10 = 1.4 × 10
4x = 14
Dividing both sides by 4
x = 3.5
Now let's solve a real-world problem using an equation,
Sarah has $500 in her bank account. She wants to buy a dress for $120 and save the rest of the money. How much money will Sarah save?
Let x be the amount of money Sarah saves.
Total money = $500
Money spent on the dress = $120
Money saved = Total money - Money spent on the dress
x = 500 - 120
x = 380
Therefore, Sarah will save $380.
In conclusion, equations are used to solve different types of problems in mathematics and in the real world.
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1. Calculate the perimeter, area and volume a) Classroom with Length=10m, breadth=8m and height=3m b) Box with Length=40cm, breadth=25cm and height=30cm c) Cabinet with length=80cm, breadth=70cm and height=2m Area Volume 26 a b C Perimeter
a) Classroom:
Perimeter = 2(length + breadth) = 2(10m + 8m) = 36m
Area = length x breadth = 10m x 8m = 80m^2
Volume = length x breadth x height = 10m x 8m x 3m = 240m^3
What is the perimeter, area and volume?b) Box:
Perimeter = 2(length + breadth) = 2(40cm + 25cm) = 130cm
Area = 2(length x breadth + length x height + breadth x height) = 2(40cm x 25cm + 40cm x 30cm + 25cm x 30cm) = 41500cm^2
Volume = length x breadth x height = 40cm x 25cm x 30cm = 30000cm^3
c) Cabinet:
Perimeter = 2(length + breadth) = 2(80cm + 70cm) = 300cm
Area = 2(length x breadth + length x height + breadth x height) = 2(80cm x 70cm + 80cm x 2m + 70cm x 2m) = 12640cm^2
Volume = length x breadth x height = 80cm x 70cm x 2m = 112000cm^3
Note: It's important to use consistent units in calculations. In this case, I converted the dimensions to a common unit (meters or centimeters) before performing the calculations.
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lee had scored the following points in his first 8 games 12,14,14,15,8,10,3,15 enter the number of points lee needs to score in the nest game to increase his keam score to 13 points PLS ANSER FASTE
Find the measure of the missing side.
1. 8.2
2. 9.9
3. 7.4
4. 10.9
Answer:
1
Step-by-step explanation:
First of all we use the "law of sines"
to get the measure/length we need the opposing angle of it of the side, now in this case the missing side is x
and its opposing angle is missing so using common sense, the sum of angles in the triangle is 180°
180°=70°+51°+ x
x = 180°-121°
=59°
Using law of sines:
(sides are represented by small letters/capital letters are the angles)
a/sinA= b/sinB= c/sinC
We have one given side which is "9"
so,
9/sin70= x/sin59
doing the criss-cross method,
9×sin59=sin70×x
9×sin59/sin70=x
x=8.2 (answer 1)
I hope this was helpful <3
3 out of 7 questions. PLEASE help me.
Translate the solid circle 2 units to the left and 2 units down and dilate the solid circle by a scale factor of 2. and the circles are similar
Transforming the circles(a) To move the solid circle exactly onto the dashed circle, we need to perform the following transformations:
Translate the solid circle 2 units to the left and 2 units down.Dilate the solid circle by a scale factor of 2.Therefore, the blank spaces should be filled as follows:
Translate the solid circle 2 units to the left and 2 units down.
Dilate the solid circle by a scale factor of 2.
(b) Yes, the original solid circle and the dashed circle are not similar, because they have different radii.
This is because all circles are similar
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Which comparison is not correct?
A. 1 > -9
B. 3 < 6
C. -8 > -6
D. -3 < 4
Answer:
The comparison that is not correct is:
C. -8 > -6
This is not correct because -8 is actually less than -6. Therefore, the correct comparison would be -8 < -6.
The other comparisons are correct:
A. 1 > -9 (true, because 1 is greater than -9)
B. 3 < 6 (true, because 3 is less than 6)
D. -3 < 4 (true, because -3 is less than 4)
ASAP I really need help doing a two column proof for this please.
The two column proof is written as follows
Statement Reason
MA = XR given (opposite sides of rectangle)
MK = AR given (opposite sides of rectangle)
arc MA = arc RK Equal chords have equal arcs
arc MK = arc AK Equal chords have equal arcs
Equal chords have equal arcsAn arc is a portion of the circumference of a circle, and a chord is a line segment that connects two points on the circumference.
If two chords in a circle are equal in length, then they will cut off equal arcs on the circumference. This is because the arcs that the chords cut off are subtended by the same central angle.
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Gia made a garden stone shaped like a regular octagon with the dimensions shown. Find the area of the octagon.
5.5 in.
4.6 in
The area of the garden which is same as the shape of an octagon would be = 101.2in².
How to calculate the area of an octagon?To calculate the area of an octagon the formula that can be used is given below;
Area of an octagon = (number of sides × length of one side × apothem)/2
For an octagon = 8 sides
apothem = 5.5in
Length of one side = 4.6in
Area = 8×4.6×5.5/2
= 202.4/2
= 101.2in²
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Which graph shows the solution to this system of linear inequalities?
Answer: A. Graph D
Step-by-step explanation: Graph D shows the solution to the system of linear inequalities because it includes all the points that satisfy both inequalities. The shaded region in graph D is where the two shaded regions from the other graphs overlap, which means that it is the only region that satisfies both inequalities simultaneously.
29. The area of a rectangle is given by the expression +7x² + 11x + 2) in². The length of the rectangle is given by the expression (x + 2) in. What is an expression for the width of the rectangle?
To find an expression for the width of the rectangle, we can use the formula for the area of a rectangle, which is:
Area = length x width
What is an expression for the width of the rectangle?In this case, we know that the area is given by the expression +7x² + 11x + 2 and the length is given by the expression (x + 2). So we can substitute these values into the formula and solve for the width:
+7x² + 11x + 2 = (x + 2) x width
Expanding the right-hand side, we get:
+7x² + 11x + 2 = xwidth + 2width
Rearranging terms, we get:
+7x² + 11x + 2 - xwidth - 2width = 0
Factoring out the width, we get:
width*(x - 2) + 2*(x - 1) = 0
Dividing both sides by (x - 2), we get:
width = -2*(x - 1)/(x - 2)
Therefore, an expression for the width of the rectangle is:
width = -2*(x - 1)/(x - 2)
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What is the exact area of the trapezoid?
Answer:
135.07 mm2
Step-by-step explanation:
height = 10.39 mm
area = 135.07 mm2
The line plot displays the number of roses purchased per day at a grocery store.
A horizontal line starting at 1 with tick marks every one unit up to 10. The line is labeled Number of Rose Bouquets, and the graph is titled Roses Purchased Per Day. There is one dot above 1 and 2. There are two dots above 8. There are three dots above 6, 7, and 9.
Which of the following is the best measure of variability for the data, and what is its value?
The range is the best measure of variability, and it equals 8.
The range is the best measure of variability, and it equals 2.5.
The IQR is the best measure of variability, and it equals 8.
The IQR is the best measure of variability, and it equals 2.5.
The range is the best measure of variability for this data, and it equals 8.
What is range?In statistics, the range is a measure of variability that describes the difference between the largest and smallest values in a dataset. It is the simplest measure of variability and is calculated by subtracting the smallest value in the dataset from the largest value.
According to given information:The range is a measure of variability that tells us the spread of the data, i.e., how far apart the minimum and maximum values are. It is calculated by subtracting the smallest value in the dataset from the largest value.
In the given line plot, the horizontal axis represents the number of rose bouquets purchased per day, and the vertical axis represents the frequency (i.e., how many times that particular number of rose bouquets was purchased). Based on the plot, we can see that the lowest number of rose bouquets purchased in a day is 1, and the highest number is 9. Therefore, the range is 9 - 1 = 8.
In contrast, the IQR (interquartile range) is a measure of variability that gives us an idea of how spread out the middle 50% of the data is. It is calculated by subtracting the 25th percentile (Q1) from the 75th percentile (Q3). Since we do not have the values for Q1 and Q3, we cannot calculate the IQR for this dataset.
Therefore, the range is the best measure of variability for this data, and it equals 8.
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