The time taken by the runner to do the work is 1.42 seconds.
Given the data in the question;
Work done; [tex]W = 457J[/tex]Power; [tex]P = 321W[/tex]Time elapsed; [tex]t = \ ?[/tex]PowerPower can be simply referred to as the quantity of energy transferred per unit time.
It is expressed as;
[tex]P = \frac{W}{t}[/tex]
Where W is work done and t is time elapsed.
To determine the time it took the runner to do the work, we substitute our given values into the expression above.
[tex]P = \frac{W}{t} \\\\t = \frac{W}{P} \\\\t = \frac{457J}{321W} \\\\t = \frac{457 kgm^2/s^2}{321 kgm^2/s^3}\\\\t = 1.42s[/tex]
Therefore, the time taken by the runner to do the work is 1.42 seconds.
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Why does the final electron energy not depend on the focusing cylinder voltage?
The electron energy does not depend on the focusing cylinder voltage because the magnetic field runs perpendicular to the electron's direction of movement.
What is a magnetic field?A magnetic field is produced by moving negatively electric charges (electrons) which generate magnetic forces that are observable.
The negative electrons that orbit around atoms in a molecule generate small magnetic fields around such atoms.
According to Fleming's left-hand rule, the direction of a magnetic force acting on a current is perpendicular to the direction of the electric current and magnetic field.
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Because it exerts a force that's also parallel to the horizontal fields instead of in opposition to it, the final electron energy is unchanged by the focusing cylinder voltage.
What is electron energy?An electron's energy is on the same scale (in the same range) as that of light. The lines in an element's spectrum represent changes in the energy of electrons within the element's atoms. Scientists have reached numerous conclusions regarding the behavior of electrons in atoms by studying these spectra.
Negative electrons orbiting around atoms in a molecule produce modest magnetic fields surrounding them.
The vector of a magnetic force that acts on a current is opposite to the axis of the electric current and magnetic fields, as per Fleming's left-hand rule.
Thus, because it exerts a force that's also parallel to the horizontal fields instead of in opposition to it, the final electron energy is unchanged by the focusing cylinder voltage.
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1. A hockey puck has a mass of 0.115-kg and strikes the pole of the net at (37 m/s)x. It bounces off in the opposite direction at (-25 m/s)x +(5 m/s)y. (A) What is the impulse on the puck? (B) If the collision takes .005s what is the force acted on the puck?
(a) The impulse on the puck is 1.323 kgm/s.
(b) The magnitude of the force that acted on the puck is 264.5 N.
Impulse of the puckThe impulse on the puck is equal to the change in momentum of the puck.
The change in th momentum of the puck is calculated as follows;
ΔP = m(u - v)
where;
v is the final velocity = (-25x + 5y) m/su is the initial velocity = 37 m/sMagnitude of the final velocity
|v| = √[(-25)² + (5)²] = 25.5 m/s
ΔP = 0.115(37 - 25.5)
ΔP = 1.323 kgm/s
Thus, the impulse on the puck is 1.323 kgm/s.
Force on the puckThe magnitude of the force that acted on the puck is calculated as follows;
F = ΔP/t
F = 1.323/0.005
F =264.5 N
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Different Betweens in Current Source And Voltage Source.
[tex] \\ \\ \\ \\ \\ \\ \\ [/tex]
Thanks:')
Answer:
Voltage and current sources are two different sorts of sources that may be found in an electrical network. A voltage source has an emf forcing function, whereas a current source has a current forcing function.
☆ ------ ☆ ------ ☆ ------ ☆ ------ ☆
How much work is done in lifting 30 kg of bricks to a height of 20 m?
Answer:
5,886 Joules or 5.886 KJ.
Explanation:
FORMULA IN FINDING WORK is
W = F x D
Where W is working;
F is force; and
D is distance
However, let us first discuss what work is.
When there is an object being moved by a force through a certain distance, the measure of energy transfer is what we call WORK.
One of the most common units used in work is JOULES (commonly used as a unit of energy). It is the work by which 1 Newton (1N = 1 kg.m/sec²) of force is used/expended through a distance of 1 meter (1m).
Refer to the problem.
It is said that the 30 kg set of bricks is to be raised to a height of 20 meters. As we see, there is no force given. But recall that force (F) is the product of the mass (m) of an object and its acceleration (a)
F = ma
However, in the formula, (g = 9.81 m/s²) or acceleration due to gravity is used in replacement of (a) because the object is moving upward.
So now we have
F = mg
Thus, we have the new work formula as
W = (mg)(D)
Substituting the given values, we have
W = (mg)(D)
W = (30kg)(9.81 m/s²)(20m)
W = 5,886 kg.m²/sec² or W = 5,886 Joules
The work done in lifting the bricks is 5,886 Joules or 5.886 KJ.
~hope this helps~
Suppose that it takes a simple pendulum 1.2 seconds to swing from its leftmost point to its rightmost point. what is the period of the pendulum
The time period of the simple pendulum is 2.4 seconds.
Given the data in the question;
Time taken to swing from leftmost point to rightmost point; [tex]t = 1.2s[/tex]Period of the pendulum; [tex]T = \ ?[/tex]What is Period?Period is the time needed for a complete cycle of vibration to pass a given point.
Period of a pendulum is the of time needed for it to complete one full back-and-forth motion. It is the time required to for the pendulum to swing from leftmost point to rightmost point and back to leftmost point.
Now, if it took the pendulum [tex]1.2s[/tex] to swing from leftmost point to rightmost point, it will also take the pendulum [tex]1.2s[/tex] to swing back to its original position( leftmost point )
Hence,
[tex]T[/tex] = time taken to swing from leftmost to rightmost + time taken to swing from rightmost point to leftmost point.
[tex]T = 1.2s + 1.2s\\\\T = 2.4s[/tex]
Therefore, the time period of the simple pendulum is 2.4 seconds.
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Which claim do scientists use to describe electromagnetic radiation?
(1 point)
Electromagnetic radiation exhibits properties of particles only.
Electromagnetic radiation exhibits properties of both particles and waves.
Electromagnetic radiation doesn't exhibit properties of either particles or waves.
Electromagnetic radiation exhibits properties of waves only.
Answer:c
Explanation: I took the identifying claims quick check and the answers are 1.yes it can be 2. No because it is an opinion 3.claims 4.it is prediction 5.both particles and waves 6.a wave model is most useful
Scientists use to describe electromagnetic radiation as It exhibits properties of both particles and waves. The correct option is B.
What is an electromagnetic wave?An electromagnetic wave is a type of wave that consists of oscillating electric and magnetic fields that travel through space at the speed of light.
Electromagnetic waves are produced by the movement of charged particles and are characterized by their frequency, wavelength, and amplitude.
Electromagnetic waves include a wide range of frequencies, which together form the electromagnetic spectrum. The spectrum includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Each of these types of electromagnetic waves has a different frequency and wavelength, which determines its properties and how it interacts with matter.
Here in the question,
Scientists describe electromagnetic radiation as exhibiting properties of both particles and waves.
This is known as the wave-particle duality of electromagnetic radiation, which means that electromagnetic radiation can exhibit both wave-like and particle-like behavior depending on how it is observed or measured.
The wave-like behavior is described by its frequency, wavelength, and amplitude, while the particle-like behavior is described by its energy, momentum, and photons.
Therefore, The electromagnetic wave shows duality i.e both particle and wave properties.
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Mass m1 on the frictionless table of the figure is connected by a string through a hole in the table to a hanging mass m2
For a mass m1 on the frictionless table, the speed m1 must rotate a with radius r if m2 is to remain hanging at rest is mathematically given as
[tex]v=\sqrt{m1/m2*xg}[/tex]
What speed must m1 rotate in a circle of radius r if m2 is to remain hanging at rest?Generally, the equation for the Force is mathematically given as
Fc=Fw
Therefore
[tex]\frac{m1v1}{x}=m2g[/tex]
[tex]v=\sqrt{m1/m2*xg}[/tex]
In conclusion, if m2 is to remain hanging at rest the speed of ratio of m1 is calcuylated using
[tex]v=\sqrt{m1/m2*xg}[/tex]
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The value of the velocity for the mass m₁ on the frictionless table will be [tex]\rm v = \sqrt{\frac{m_1}{m_2 xg} }[/tex]. Velocity is a time-based component. Its unit is m/sec.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity.
The given data in the problem is
m is the mass
g is the acceleration of free fall =10m/sec²
v is the velocity
From the balancing equation of force the centripetal force is equal to the weight;
[tex]\rm F_c= m_2 g \\\\ \rm \frac{m_1v_1^2}{x} = m_2 g \\\\ v= \sqrt{\frac{m_1}{m_2xg} } \\\\[/tex]
Hence the value of the velocity for the mass m₁ on the frictionless table will be [tex]\rm v = \sqrt{\frac{m_1}{m_2 xg} }[/tex].
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where is A what is the answer?
A car is traveling in a race. The car went from the initial velocity of 35 m/s to the final velocity of 65 m/s in 5 seconds
What is the acceleration?
- 13 m/s
-6m/s
6 m/s
13 m/s
Answer:
C
Explanation:
65-35 = 30
30 divided by 5 = 6
The answer will be 6 m/s
Explanation:
c............ ......
...
100 Points!!!
1.) What does the image of an object look like through a convex lens when the object is further from the lens than the focal point?
A. It looks the same as the actual object.
B. It is right side up and larger than the object.
C. It is upside down and larger than the object.
D. It is upside down and smaller than the object.
2.) What happens when light rays reflect?
A. They are partially absorbed.
B. They bounce back.
C. They are all absorbed
D. They pass through an object.
3.) Based on how it refracts light, what would you expect images formed by a concave lens to look like?
A. Smaller
B. The same as the objects that they are images of
C. Magnified
D. Reversed
4.) What happens to light rays when they enter a different medium?
A. They reflect
B. They Bend
C. They Curve
D. They Stop
(1) The image of an object placed further from the lens than the focal point will be upside down and smaller than the object.
(2) When light rays reflect, they bounce back.
(3) Images formed by a concave lens will look magnified.
(4) When light rays enter a different medium, they bend.
1.0 Object placed further from the lens than the focal pointThe image of an object placed further from the lens than the focal point will be diminished and inverted.
Thus, the correct answer will be "upside down and smaller than the object".
2.0 What is reflection of light?The ability of light to bounce back when it strike a hard surface is known as refection.
3.0 Image formed by concave lensA concave lens is diverging lens is usually virtual, erect and magnified.
4.0 Refraction of lightThe change in speed of light when it travels from medium to another medium is known as refraction. Refraction is also, the ability of light to bend around obstacles.
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Answer:
It is upside down and larger than the object
They bounce back
Magnified
They bend
Explanation:
What is one time constant of a 4. 7 μf capacitor in series with a 22 kω resistor?
Hi there!
We can solve for the time constant using the following:
[tex]\tau = RC[/tex]
τ = Time Constant (s)
R = Resistance (Ω)
C = Capacitance (F)
Simply plug in the values. Remember that:
4.7 μF = 4.7 * 10⁻ ⁶ F = 0.0000047 F
22kΩ = 22 * 10³ Ω= 22000Ω
Solve:
[tex]\tau = 0.0000047 * 22000 = \boxed{0.1034 s}[/tex]
Martha wants to calculate an object's velocity. What will she need to do?
Answer:
you divide the distance by the time it takes to travel that same distance, then you add your direction to it.
Imagine a situation : If people could not see colours, then how would traffic lights work ? Design a traffic system that does not rely on colors.
Answer:
position
Explanation:
Okay, so this already exists
Colorblind people use the position of the light
Red on top, yellow in middle, green on bottom
If a fast-moving car making a loud noise approaches and moves past a person, which of the following will happen as the distance between the two increases?
A) The pitch and frequency of the sound waves reaching the person's ear will remain unchanged.
B) The pitch of the sound being heard by the person will appear to be lower than the pitch of the source.
C) The frequency of the sound waves reaching the person's ear will be greater than the frequency of the waves leaving the car.
D) The pitch of the sound being heard by the person will appear to be higher than the pitch of the source.
Answer:
(B) Probably - Pitch will appear to be lower than the source
Pitch differences occur because of relative motions between the source and observer - it does not depend on distance measurements
Answer:
(B) Probably - Pitch will appear to be lower than the source
Pitch differences occur because of relative motions between the source and observer - it does not depend on distance measurements
Explanation:
List the elements mentioned from hydrogen to iron in the order of their fusing temperature.
Explanation:
H
Hydrogen
-259.14 -252.87 0.00008988 (gas, 273K)
2
He
Helium
-272.20 (under pressure) -268.934 0.0001785 (gas, 273K)
3
Li
Lithium
180.54 1347 0.534
4
Be
Beryllium
1278 2970 1.8477
5
B
Boron
2300 3658 2.34
6
C
Carbon
3527 4827
(sublimes) 2.260 (graphite)
3.513 (diamond)
7
N
Nitrogen
-209.86 -195.8 0.0012506 (gas, 273K)
8
O
Oxygen
-218.4 -182.96 0.001429 (gas, 273K)
9
F
Fluorine
-219.62 -188.14 0.001696 (gas, 273K)
10
Ne
Neon
-248.67 -246.05 0.00089994 (gas, 273K)
11
Na
Sodium
97.81 882.9 0.971
12
Mg
Magnesium
648.8 1090 1.738
13
Al
Aluminum
660.37 2467 2.698
14
Si
Silicon
1410 2355 2.329
15
P
Phosphorus
44.1 (white)
410 (red, under pressure) 280 (white) 1.82 (white)
16
S
Sulfur
113 (α)
119 (b)
106.8 (g) 444.67 2.070 (α)
1.957 (b)
17
Cl
Chlorine
-100.98 -33.97 0.003214 (gas, 273K)
18
Ar
Argon
-189.37 -185.86 0.001784 (gas, 273K)
19
K
Potassium
63.65 774 0.862
20
Ca
Calcium
839 1484 1.55
21
Sc
Scandium
1541 2831 2.989
22
Ti
Titanium
1660 3287 4.54
23
V
Vanadium
1887 3377 6.11 (292 K)
24
Cr
Chromium
1857 2672 7.19
25
Mn
Manganese
1244 1962 7.44
26
Fe
Iron
1535 2750 7.874
27
Co
Cobalt
1495 2870 8.90
28
Ni
Nickel
1453 2732 8.902 (298 K)
29
Cu
Copper
1083.4 2567 8.96
30
Zn
Zinc
419.58 907 7.133
31
Ga
Gallium
How many electrons will it take to give a hot wired fence a charge of 3.5 X 10^6 C?
Answer:
Q = N e where N e is the number of electrons required to produce charge Q
N = Q / e = 3.5E6 C / 1.6E-19C = 2.2E25 = 2.2 X 10^25 electrons
Answer:
3.5 million C
Explanation:
If all of the resistors in the circuit were decreased in value by a factor of 1,000, would the current in each resistor simply increase by a factor of 1,000? explain your answer
In a circuit, if the resistors were decreased by a factor of 1,000, it is true that the current would increase by a factor of 1,000, according to Ohm's Law.
What is Ohm's Law?It is a law in electricity that posits that the voltage that goes through a conductor is directly proportional to the current.
How does Ohm'slaw explain the change in current?One formula in Ohm's law is:
Voltage = Current x Resistance
If the resistance were to decrease by a factor of 1,000, the current would have to increase by a factor of 1,000 as well in order to give the same voltage.
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30. (a) What is the effect on the period of a pendulum if you double its length?
(b) What is the effect on the period of a pendulum if you decrease its length by 5.00%?
The answers are "(a) Period increases by a factor of 1.41 (2–√)(b) Period decreases to 97.5% of old period" but please include all of your work.
Let's know the formula
[tex]\\ \rm\rightarrowtail T=2\pi \sqrt{\dfrac{l}{g}}[/tex]
So
[tex]\\ \rm\rightarrowtail T\propto \sqrt{l}[/tex]
Hence if length is doubled time period will be √2 times
√2=1.41 (Approximately)#2
Decrease by 5% will decrease the time period 5/2=2.5%
So
It's
100-2.5=97.5% of old period12. Tom has two pendulums with him. Pendulum 1 has a ball of mass 0.1 kg attached to it and has a length of 5 m. Pendulum 2 has a ball of mass 0.5 kg attached to a string of length 1 m. How does mass of the ball affect the frequency of the pendulum? Which pendulum will have a higher frequency and why?
Show all of your work.
According to Hooke 's law
[tex]\\ \rm\rightarrowtail \nu=k\sqrt{\dfrac{\ell}{m}}[/tex]
[tex]\\ \rm\rightarrowtail \nu\propto \dfrac{1}{\sqrt{m}}[/tex]
Hence lower the mass higher the frequency
First ball will have a higher frequencyA bicycle wheel of radius 40. 0 cm and angular velocity of 10. 0 rad/s starts accelerating at 80. 0 rad/s2. What is the centripetal acceleration of the wheel at this time point?
The magnitude of the centripetal acceleration of the bicycle wheel is 40 m/s².
Centripetal acceleration of the wheel
The centripetal acceleration of the bicycle wheel is the inward or radial acceleration of the bicycle on the circular path.
The magnitude of the centripetal acceleration of the bicycle wheel is calculated as follows;
a = ω²r
where;
ω is angular speed
r is the radius of the circular path
a = (10)² x 0.4
a = 40 m/s²
Thus, the magnitude of the centripetal acceleration of the bicycle wheel is 40 m/s².
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The acceleration of a body travelling in a circular route is known as centripetal acceleration. The centripetal acceleration of the wheel at this time point is 40 m/sec².
What is centripetal acceleration?The acceleration of a body travelling in a circular route is known as centripetal acceleration. It is given by the formula,
[tex]a_c = \dfrac{v^2}{r} = \omega^2 r[/tex]
The centripetal acceleration of the wheel with angular velocity 10 rad/sec and velocity 40cm (0.4 m) can be written as,
[tex]a_c = \omega ^2\times r\\\\a_c = (10)^2\times 0.4\\\\a_c = 40\rm\ m/sec^2[/tex]
Hence, the centripetal acceleration of the wheel at this time point is 40 m/sec².
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The top speed of a car is determined by several factors including:
*Power of the motor
*Weight of the car
*Aerodynamics of the car
*Grip of the tires on the road
1) How would you go about determining which of these has the strongest effect?
Helppp!!
Answer:
Power of the motor.
Explanation:
If it didn't have grip, it would still move. If it was barely aerodynamic (pretty sure nothing can be not aerodynamic at all) it would still move. If it weighed more that the sun (and you had a strong enough motor) it would still move but without a motor, it won't move. Therefore, the motor is the most effective.
A boy of mass 50kg runs a set of steps of total height of 10cm. Calculate the work done (g =10)
Answer:
Explanation:
w=F×S
F=mg
F =50×110
F=500N
S=0.1 m
W=500×0.1
W=50j
Henri becquerel shared a nobel prize for his work in discovering what?.
What increases the transfer of the wind's energy to the water?
Question 4 options:
A. flat water
B. large waves
C. large rocks
PLEAS HELP ME FAST
Answer:
A, flat water
Explanation:
After hearing about an accident on his normal route, mr. gujral checks for alternate routes to get to work. what type of circuit does this traffic situation model? a series circuit because there is more than one path a series circuit because there is only one path a parallel circuit because there is more than one path a parallel circuit because there is only one path
The type of circuit does this traffic situation model will be a parallel circuit because there is more than one path.
What is a parallel circuit?A parallel circuit has branches that split the current such that just a portion of it passes through each branch.
The voltage or potential difference between each branch of a parallel circuit is the same, but the currents might differ.
A parallel circuit is having more than one path in order to reach it on time he has to take a different path.
Hence the type of circuit does this traffic situation model will be a parallel circuit because there is more than one path.
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Answer:
C) a parallel circuit because there is more than one path
Explanation: edge
Which statement correctly describes the relationship between frequency and wavelength?
A :As the frequency of a wave increases, the longer its wavelength is
B: As the frequency of a wave increases, the shorter its wavelength is.
C: As the frequency of a wave increases, its wavelength remains the same.
Answer:
Answer:
Option B
Explanation:
Option B talks about how the frequency of the wave increases the shorter it's wavelengths
Answer:
b
Explanation
B: As the frequency of a wave increases, the shorter its wavelength is.
A 100-cm long dipole is excited by a sinusoidally varying current with an amplitude i0=2 a. Determine the time average power radiated by the dipole if the oscillating frequency is 150 mhz
For A 100-cm long dipole is excited by a sinusoidally varying current with an amplitude i0=2 , the time average power radiated is mathematically given as
P=0.1577w
What is the time average power radiated by the dipole if the oscillating frequency is 150 mhz?Generally, the equation for the is mathematically given as
[tex]\lambda =\frac{c}{f}[/tex]
Therefore
[tex]\lambda=\frac{3\times 10^{8}}{10^{6}}[/tex]
lambda=300m
In conclusion, for the power
[tex]P=40\pi^{2}(I_{0})^{2}(\frac{l}{\lambda})^{2}\\\\P=40* (3.14)^{2}\times6^{2} (\frac{1}{300})^{2}[/tex]
P=0.1577w
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The time-averaged power radiated by the dipole if the oscillating frequency is 150 MHz is 0.1577 w.
What is wavelength?The distance between identical points (adjacent crests) in adjacent cycles of a waveform signal carried in space or down a wire is defined as the wavelength.
Given that the current is 2 amp, while the frequency is 150 MHz. Therefore, the wavelength can be written as,
[tex]\lambda = \dfrac cf = \dfrac{3 \times 10^8}{10^6} = 300\rm\ m[/tex]
Now, the power can be written as,
[tex]P=40 \pi^2 \times (I_o)^2 \times (\dfrac{l}{\lambda})^2\\\\P = 40 \times \pi ^2 \times 6^2 \times (\dfrac{1}{300})^2\\\\P = 0.1577\rm\ w[/tex]
Hence, the time-average power radiated by the dipole if the oscillating frequency is 150 MHz is 0.1577 w.
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Two horses pull horizontally on ropes attached to a tree stump each horse pulls with a force of F if the angle between the two ropes is 126° what's resultant force?
Answer:
126 / 2 = 63 = angle between one rope and the direction of the resultant force
t = F cos 73 = .45 F force on stump due to one horse
T = 2 t = .90 F force on stump due to both horses - T would be the resultant of the two horses each pulling with force F
If you travel for three hours at a speed of 30 km/h, how far will you go?
Distance = (speed) x (time) <== This is important. You should memorize it.
Distance = (30 km/hr) x (3 hr)
Distance = (30 x 3) (km/hr x hr)
Distance = 90 km
Define resistance of a conductor. State the factors on which resistance of a conductor depends.
Name the device which is often used to change the resistance without changing the voltage source in an electric circuit.
Calculate the resistance of 50 m length of wire of cross-sectional area 0.01 square mm and of resistivity 5 ×10 ^-8 ohm m
1. Resistance is the opposition offered in a path of flow of current by the atoms or molecules of the conductor.
Factors on which resistance of a conductor depends are:
Length [tex]R \propto l[/tex]Area of cross section [tex]R \propto \dfrac{1}{A}[/tex]Nature of the material2. Rheostat is used to change the resistance without changing the voltage source in an electric circuit.
3.
Given :
[tex]\dashrightarrow l = 50 m[/tex]
[tex]\dashrightarrow A = 0.01 {mm}^{2} [/tex]
[tex]\dashrightarrow A = 0.01 \times {10}^{ - 6} \: {m}^{2} [/tex]
[tex]\dashrightarrow \rho = 5 \times {10}^{ - 8} \: \Omega \: m[/tex]
We know that,
[tex] \dashrightarrow R = \rho \dfrac{l}{A}[/tex]
[tex] \dashrightarrow R = 5 \times {10}^{ - 8} \bigg(\dfrac{50}{0.01 \times {10}^{ - 6} } \bigg)[/tex]
[tex] \dashrightarrow { \pink{ \underline{ R = 250 \: \Omega }}}[/tex]
The resistance of a conductor is the opposition to the flow of current and depends on the length and area of the material
What is resistance of a conductor?Resistance is the opposition to the flow of current by the atoms or molecules of the conductor.
The factors on which resistance of a conductor depends are:
Length of materialcross-sectional area of the materialNature of the materialA Rheostat is the device used to change the resistance without changing the voltage source in an electric circuit.
The resistanceis given as:
R = resistivity × length/ areaArea = 0.01 square mm = 1.0 × 10^-8 square m
R = (50 × 5 ×10 ^-8 ohm m)/1.0 × 10^-8 square m
Resistance = 250 ohm
Therefore, resistance of a conductor is the opposition to the flow of current.
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