If an airplane is running low on fuel, the pilot may decide to dump unneededweight. As the airplane gets lighter, the engines need less fuel to generate thesame amount of acceleration for flight. The pilot has taken advantage ofNewton's law of motion.A. fourthB. thirdO C. firstD. second

ANSWER

75.65 km/h

EXPLANATION

Given:

• The student's mass, m = 77 kg

• The kinetic energy of the student in the car, KE = 1.7 x 10⁴ J

Find:

• The speed read in the speedometer of the car, which is the speed of the student, v (in km/h)

The kinetic energy of an object with mass m, traveling at a speed v, is,

Solving for v,

Replace the known values and solve,

Note that because the kinetic energy is given in Joules - which is equivalent to kg*m²/s², the speed we found is in m/s. Now, knowing that there are 3600 seconds in 1 hour and that 1 km is equivalent to 1000 m, we can convert this to km/s,

Hence, the speedometer reading of the car is 75.65 km/h, rounded to the nearest hundredth.

Correct answer is option B.

Answer:

3:1

Explanation:

Given:

The currents, I₁=20 A

I₂=10 A

The length of the wires, L=5 m

The distance between two wires, d=1.0 cm=0.01 m

To find:

The magnetic force between the wires.

Explanation:

As the wires are conducting the current in opposite directions, the nature of the force between the wires is repulsive.

The magnitude of the force between two wires is given by,

Where μ₀=4π×10⁻⁷ H/m is the permeability of free space.

On substituting the known values,

Final answer:

The magnetic force between wires is 0.020 N, repulsive.

Answer:  45 A

Explanation:

Primary only protection 3-phase

I =  3 phase kVA / ( 1.723 * V)

I = 30000 / ( 1.732 * 480 ) = 36.085 A

Table 450.3(B)

Currents of 9A or more column

primary only protection  = 125%

Max OCPD pri = 125% of I = 1.25 * 36.085 = 45.11 A

 Table 450.3(B) Note 1   does not apply, use next smaller Table 240.6(A)

Next smaller = 45 A

According to the Euclidean Postulates, a straight line segment can be drawn joining any two points.

Therefore, the answer is:

The eletromagnetic wave that has the highest frequency is the gamma rays. It also has the highest energy and shortest wavelengths.

On the other hand, the type of eletromagnetic wave that has the lowest frequency, lowest energy and longest wavelength is radio waves.

In order to calculate the kinetic energy, we can use the formula:

Where m is the mass in kg and v is the speed in m/s.

So, for the bullet, we have:

And for the liner, we have:

So the ocean liner has greater kinetic energy.

ANSWER

4 meters

EXPLANATION

Given:

• Work = 8.0 J

• Force = 2.0 N

• Mass of the box = 3.0 kg

Unknown:

• Distance the box moves

Work is the product of the applied force in the direction of motion and the distance an object moves,

In this case, a box is pushed horizontally with a force of 2N producing a work of 8J. Solve the equation above for d,

Hence, the horizontal distance the box moves is 4 meters.

The distance between the two charges is 134,164.1 m.

The distance between the two identical charges is determined by applying Coulomb's law as shown below.

F = kq²/r²

where;

r = √(kq²/F)

r = √(9 x 10⁹ x 2²) / 2)

r = 134,164.1 m

Thus, the distance between the two charges is determined by applying Coulomb's law.

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The orbital time period of the Saturn is 29.6 years

We are given that,

Distance from Sun to Saturn is = a = 1.43 × 10¹²

The mass of the Sun is = M =1.99 × 10³⁰kg

The Gravitational constant = G = 6.67 × 10⁻¹¹N-m²kg⁻²

To find the orbital period of Saturn we can use the equation ,

[tex]T^{2} = \frac{4\pi }{GM}a^{3}[/tex]

Where, T is the orbital time period of the of the Saturn , M is the mass of the sun , G is the gravitational constant.

Therefore, after putting the value in above equation we can get,

[tex]T^{2} = \frac{4(\(3.14)^{2} }{(6.67*10)^{-11} )N-m^{2} kg^{-2}}(1.43*10^{12}) ^{3}m[/tex]

[tex]T^{2} = \sqrt{8.688*10^{17} } s[/tex]

[tex]T = 932094415.818s[/tex]

So that , from above to convert the orbital time period of Saturn from second into year i.e. above seconds divided by seconds (1 sec = 3.154 ×10⁷ Earth years)

Thus, the orbital time period can be ,

[tex]T = 29.6 years[/tex]

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Answer: h = 14 m

Explanation:

From the information given,

weight of rocket = 10N

Recall, weight = mg

Thus, mg = 10

where

m = mass of object

g = acceleration due to gravity and its values is 9.8 m/s^2

At the exact top of the trajectory, the total mechanical energy = 140 J

Recall,

total mechanical energy = kinetic energy + potential energy

At the exact top, kinetic energy = 0

Thus,

140 = potential energy

Recall, potential energy = mgh

where h is the height of the object(in this case, h is the height at the exact top and its value is 140J). Thus,

140 = mgh

Substituting mg = 10, we have

140 = 10h

h = 140/10

h = 14 m

The maximum efficiency that a heat engine could have when operating between the normal boiling and freezing temperatures of water is 26.8 %

η = ( [tex]T_{H}[/tex] - [tex]T_{C}[/tex] ) / [tex]T_{H}[/tex] * 100

η = Efficiency

[tex]T_{H}[/tex] = Hottest temperature

[tex]T_{C}[/tex] = Coldest temperature

Hottest temperature = Boiling point

Coldest temperature = Freezing point

[tex]T_{H}[/tex] = 100 °C = 373 K

[tex]T_{C}[/tex] = 0 °C = 272 K

η = ( 373 - 273 ) / 373 * 100

η = 100 / 373 * 100

η = 26.8 %

In a heat engine, the heat energy is converted into mechanical energy which will be used to do mechanical work like pushing a piston out from the cylinder.

Therefore, the maximum efficiency that a heat engine could have when operating between the normal boiling and freezing temperatures of water is 26.8 %

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Given data,

The initial velocity of the body is zero.

The distance travelled by the rescuer upto the height of 30 m from the water surface is,

The final velocity of the rescuer at the height 30 m is,

where g is the acceleration due to gravity.

Substituting the known values,

Thus, the kinetic energy of the rescuer is,

Substituting the known values,

Thus, the kinetic energy of the rescuer is 42.3 KJ and speed of the rescuer is 37.6 meter per second square.

Answer:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

The height of the well is 30m

We are given that ,

The initial velocity of the stone = u = 5m/s

The stone fall into well in time = t = 3s

The acceleration due to gravity = g = 10 m/s²

To get the height of the stone which is thrown from the surface of the water in the well by equation,

h = ut + 1/2 gt²

Where, u is initial velocity in m/s, h is height in m, t is time in secs, g is acceleration due to gravity which is vertically upward direction i.e. (-10m/s²)

h = (5m/s) (3s) + 1/2 (-10m/s²)(3s)²

h = (15m) - (5m/s²)(9s²)

h = -30 m

Therefore, the height of the stone which is thrown upward is 30 m . And here, we can neglect the negative sign due to height is never be in negative.

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The pitch of a note is the same as its frequency.

Remember that te timbre depends on the shape and other properties of the vibrating object. The loudness is related to the amplitude of the wave, and the wavelength of sound is inversely proportional to the frequency.

On the other hand, the frequency of the sound of a string is proportional to the square root of the tension in the string. Then, if the tension increases (if the string is tightened), the frequency will also increase (and if the frequency increases, the wavelength decreases).

Therefore, the parameter that increases when a string of a stringed instrument is tightened, is the pitch.

Therefore, the answer is:

The kinematic equation which relates velocity and time is

As when the acceleratio

Static energy is the energy due to motionless state of a particle. If a particle is at rest it possess static energy also known as potential energy. When some force is applied to the particle then the static energy gets converted into kinetic energy of the particle.

A. The two  trials that demonstrate the effect of a doubling of force upon the acceleration of a cart of constant mass are Trials 2 and 4.

The force applied on object is obtained by multiplying the mass and acceleration of the object.

According to Newton's second law of motion, the force exerted on an object is directly proportional to the product of mass and acceleration of the object.

Also, the applied force is directly proportional to the change in the momentum of the object.

Mathematically, the force acting on object is given as;

F = ma

a = F/m

where;

At a constant mass;

F₁/a₁ = F₂/a₂

When the force is doubled, the acceleration of the object is given as;

a₂ = F₂a₁/F₁

a₂ = (2F₁ x a₁) / F₁

a₂ = 2a₁

From the trials,

acceleration of trial 2 = 0.51 m/s²

acceleration of trial 4 = 1 m/s²

Thus, the two  trials that demonstrate the effect of a doubling of force upon the acceleration of a cart of constant mass are Trials 2 and 4.

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Answer: It should be the answer beginning like this

The linear spread is that

The radial acceleration of locations along the blade's outer edge is approximately 17580 [tex]m/s^2[/tex].

Radial acceleration describes the acceleration of an object travelling on a circular path towards the circle's center. It can be defined as the rate of change of tangential velocity with regard to time and is also known as centripetal acceleration.

Given:

We know that the motor is rotating at 3450 rev/min. One revolution is equal to 2π radians, so we can convert the motor speed to radians per minute:

ω₁ = (3450 rev/min) x (2π rad/rev) = 21675π rad/min

The second pulley is half the diameter of the first pulley, so its angular speed, ω₂, is twice that of ω₁:

ω₂ = 2ω₁ = 43350π rad/min

The circular saw blade is mounted on the same shaft as the second pulley, so it also rotates at the same angular speed:

ω = ω₂ = 43350π rad/min

We can now calculate the linear speed of the small piece of wood moving at the same rate as the rim of the circular saw blade, indicated by v. The circumference of the circle is supplied by the rim of the circular saw blade:

C = πd = π(0.208 m) = 0.6548 m

The linear speed of the little piece of wood is equal to the tangential speed of the circular saw blade's rim:

v = ωr

where r is the circular saw blade's radius, given by half its diameter:

r = d/2 = 0.208/2 = 0.104 m

By substituting the values, we obtain:

v = r = (43350 rad/min) x (0.104 m) x (1/60) = approx. 23.0 m/s

As a result, the linear speed of the little piece of wood moving at the same rate as the rim of the circular saw blade is about 23.0 m/s.

Next, compute the radial acceleration of locations on the blade's outer edge, represented by. The radial acceleration is calculated as follows:

α = rω²

By substituting the values, we obtain:

r2 = (0.104 m) x (43350 rad/min)2 x (1/602) = 17580 m/s2 (approximate)

Therefore, the radial acceleration of points on the outer edge of the blade is approximately 17580 m/s². This high radial acceleration explains why sawdust doesn't stick to the teeth of the saw blade.

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Your question is incomplete, most probably the complete question is:

The motor of a table saw is rotating at 3450{\rm rev/min}. A pulley attached to the motor shaft drives a second pulley of half the diameter by means of a V-belt. A circular saw blade of diameter 0.208{\rm m}is mounted on the same rotating shaft as the second pulley.

The operator is careless and the blade catches and throws back a small piece of wood. This piece of wood moves with linear speed equal to the tangential speed of the rim of the blade. What is this speed?

v =_______________________ m/s

Calculate the radial acceleration of points on the outer edge of the blade to see why sawdust doesn't stick to its teeth.

\alpha=______________________m/s2

We are given the following information

Energy of bulb = 100 W = 100 Joules/second

Area of fingertip = 1 cm² = 0.0001 m²

Wavelength of light = 588×10⁻⁹ m

Number of photons per second = ?

Let us first convert the wavelength into energy

Where h is the plank's constant (6.626x10⁻³⁴J.s), c is the speed of light (3×10⁸ m/s) and λ is the wavelength.

1. A ceiling fan plugged into the wall socket.

The input is the electrical energy and the output is the mechanical energy from the rotation of the fan blades.

So, the energy transfer must be electrical to mechanical.

2. A stove heating a pot of water for pasta

The input is the light energy from the stove and the output is the thermal energy to heat the water.

So, the energy transfer must be light to thermal.

3. A wind turbine generating power

The input is the mechanical energy from the rotation of the turbine blades and the output is the electrical energy that is being generated.

So, the energy transfer must be mechanical to electrical.

4. A person eats a snack when they are hungry and has the energy to take a walk.

The input is the chemical energy that the person gets from eating food and the output is the mechanical energy (doing physical work).

So, the energy transfer must be chemical to mechanical.

5. A solar panel is used to create power

The input is the light energy from the Sun and it is being converted into electrical energy to generate power.

So, the energy transfer must be light to electrical.

6. A microwave is used to heat up a burrito.

The input to the microwave is the electrical energy and the output is the thermal energy to heat up the burrito.

So, the energy transfer must be electrical to thermal.

7. A lamp is plugged into the wall and shines down on a room

The input to the lamp is electrical energy which is being converted into light energy.

So, the energy transfer must be electrical to light.

8. A plant grows by absorbing the sun's rays

The input to the plant is the nuclear energy from the sun and the output is the chemical energy.

So, the energy transfer must be nuclear to chemical.

9. A game controller uses batteries to power it.

The batteries provide chemical energy as input and the output is the electrical energy to power the controller.

So, the energy transfer must be chemical to electrical.

10. The sun heats up a person sunbathing at the beach.

The input is the nuclear energy from the sun and output is the thermal energy by absorbing the heat.

So, the energy transfer must be nuclear to thermal.

Considering the average velocity can be written as:

We can isolate the distance, and we get:

Then, the distance the plane flew is 3600km

Energy effectiveness would be a term that refers to the proportion of input power over output. Power generation, as well as simply energy utilization, is the process of reducing the amount of energy used to produce goods and services.

Considering that,

A cookie contains 54.0 kcal of energy. An athlete utilizes the 54.0 kcal inside this cookie from input energy.

The following diagram illustrates the relationship among input as well as output energy:

Efficiency = output energy / input energy...(i)

Output energy = efficiency × input energy

By using equation (i)

⇒ output energy = 0.25 × 54 kcal = 13.5 kcal.

The lifting exercise has been performed n times for the output energy.

In terms of potential energy, such output energy could be written as follows:

Mass × gravity ×height.

So, energy per repetition = mgh = 103 kg × 9.8 m/ × (2.45 × 0.1m) = 247.303 J =  0.059 kcal.

So, Count of repetitions = sim of output energy / energy per repetition..(ii)

By using equation (ii)

Count of repetitions = 13.5 kcal / 0.059 kcal =229 repetitions.  

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By equating the two forces, acceleration due to gravity g is obtained which is independent of mass

The law state that the rate of change of momentum is directly proportional to the force applied.

From Newton’s Second Law, Force F = mg. And from Newton’s Law of Universal Gravitation, Force F = GMm/r²

Where m is the mass of the satellite or the body revolving round the earth.

Equate the two forces.

mg = GMm/r²

The two m cancelled out leaving

g = GM/r²

Where

Therefore, since the mass of the satellite m has cancelled out, acceleration due to gravity g is independent of mass.

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According to the image A vector points in the direction of the centripetal acceleration of the plane.

The correct option is C.

Centripetal acceleration is a property of an object's motion along a circular path. Centripetal force refers to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.

A person is seen in the image swinging a toy plane on a string in a smooth, circular motion. The velocity direction is tangent to the circular orbit and perpendicular to the direction of the position.

The direction of the velocity and the speed may both vary as an object travels in a circular orbit. The velocity's direction is continually shifting. While acceleration is constantly moving uniformly in a circular path toward the recent, tangent at each point indicates the direction of velocity at that place.

As a result, vector A is pointed in the plane's centripetal acceleration's direction.

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The complete question is -

The picture below shows a person swinging a toy plane attached to a string in uniform circular motion.

Which vector points in the direction of the centripetal acceleration of the

plane?

A-B

B-D

C-A

D-C

Explanation:

The third law of Newton says that when an object exerts a force on a second object, the first object experiences an equal and opposite force that is exerted by the second object.

So, the example that shows this law is:

C. A cannon recoils backward when it is fired.

Because the cannon e

Answer: D

Explanation:

Larger objects require greater amounts of force to move.

As he stacks books from the trolley on shelves, it gets easier to push or pull the trolley because the trolley gets lighter when the books are shifted from the trolley to the shelves. So, larger objects require greater amounts of force to move. Hence, option D is correct.

Inertia is a property of bodies that prevents them from moving or, if they are already moving, causes them to change the speed or direction of their motion. The inertia of a body is a passive quality that prohibits it from acting in any way besides opposing active agents like forces and torques.

A moving body continues to move not because of its inertia but rather because no force exists to stop it, alter its direction, or accelerate it.

According to the question, when there are books on the trolley they require a greater amount of force to move but when the books are shifted on the shelves it's easier to move the trolley. So inertia is proportional to mass.

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Metals are good conductor of electricity while plastics are bad conductors of electricity.

Thus, the statement D Metals and plastic are poor conductors is false.

Hence the correct option is D.