If I take a 45 min. break at 2:15pm what time do I come back?

Answers

Answer 1

The break time is 2:15 pm.

The time interval for break is 45 min.

Determine the time at which interval ends.

[tex]\begin{gathered} 2\colon15+00.45=2\colon60 \\ =3\colon00 \end{gathered}[/tex]

So break ends (individual come back) at 3:00.


Related Questions

Carla has a music box that has a base area of 9 1/2 in² and a height of 3 1/5 inches.What is the volume of the music box?

Answers

Given in the question:

a.) Base area of music box = 9 1/2 in²

b.) Height of music box = 3 1/5 in.

Let's recall the formula for getting the volume of a rectangular prism:

[tex]\text{ Volume = Length x Width x Height or Base Area x Height}[/tex]

Before we plug in the values, let's first transform the mixed numbers into improper fractions.

[tex]\text{ 9 }\frac{1}{2}\text{ = }\frac{1\text{ + (2 x 9)}}{2}\text{ = }\frac{1\text{ + 18}}{2}\text{ = }\frac{19}{2}[/tex][tex]\text{ 3 }\frac{1}{5}\text{ = }\frac{1\text{ + (3 x 5)}}{5}\text{ = }\frac{1\text{ + 15}}{5}\text{ = }\frac{16}{5}[/tex]

Let's now plug in the values to get the volume of the music box.

[tex]\text{ Volume = Base Area x Height}[/tex][tex]=\text{ 9 }\frac{1}{2}\text{ x 3 }\frac{1}{5}\text{ = }\frac{19}{2}\text{ x }\frac{16}{5}\text{ = }\frac{304}{10}\text{ }[/tex][tex]\frac{304}{10}\text{ = }\frac{\frac{304}{2}}{\frac{10}{2}}=\frac{152}{5}\text{ or 30 }\frac{2}{5\text{ }}in.^3[/tex]

Therefore, the volume of the music box is 30 2/5 in.^3.

What are the solutions to the equation (x − 21)2 = 25?x= x=

Answers

SOLUTION:

Case: Quadratics equation

Method:

[tex]\begin{gathered} (x-21)^2=25 \\ TakeSquarerootsOfBothSides \\ x-21=\sqrt{25} \\ x-21=\pm5 \\ x=21\pm5 \\ x=21+5\text{ }or\text{ }x=21-5 \\ x=26\text{ }or\text{ }x=16 \end{gathered}[/tex]

Final answer:

x= 16

x= 26

Use the given rounded values, the properties of logsand your knowledge of logarithmic functions to find thevalue of each log expression. Show your work.

Answers

We want to find the value for

[tex]\log _425[/tex]

To do that, first let's rewrite this expression as

[tex]\log _425=\log _45^2[/tex]

Using the following property

[tex]\log _ab^c=c\log _ab[/tex]

We can rewrite our expression as

[tex]\log _45^2=2\log _45[/tex]

Using the given value on the text, we get our answer

[tex]\log _425=2\log _45=2\cdot1.2=2.4[/tex]

20g of radioactive substance decays by 1/2 of it's original
amount every 30 days. How much is left after 10 days.

Answers

The amount of radioactive after 10 days with the same rate of change of decay will be 16.67 g.

What is the rate of change?

The rate of change is the change of a quantity over 1 unit of another quantity.

Most of the time the rate of change is the change with respect to time.

For example the speed 3meter/second.

As per the given,

Radioactive decays by 1/2 of its original in 30 days.

1/2 of original → 30 days.

Divide both sides by 3

1/6 of original → 10 days

Therefore, in 10 days amount of decays will be,

1/6 of 20 ⇒ 20/6 = 3.33

The amount left = 20 - 3.33 = 16.67.

Hence "The amount of radioactive after 10 days with the same rate of change of decay will be 16.67 g".

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Question 5The table below shows the coordinates of a figure that was transformed.Pre-ImageImageA(5,2)B(6, 1)A'(0,0)B'(1, -1)C'(-1,3)C(4,5)Which is a correct description of the transformation?

Answers

You have the following A, B and C points, which are transformed to the points A', B' and C', jus

A number between 280 and 380 when rounded to the nearest hundred is 45 less than the original number what number is the original number

Answers

If the unknown number is an integer between 280 and 349;

When rounded to the nearest hundred, the unknown number is 300.

If the unknown number is an integer from 350-380;

When rounded to the nearest hundred, the unknown number is 400.

If the approximation is 45 less than the original number, thus it cant be in the range of 350-380.

But;

[tex]300+45=345[/tex]

When 345 is rounded to the nearest hundred, it is 300.

And the difference between the approximated value and the original value is 45.

Hence, 345 is the original number.

CORRECT ANSWER: 345

When water flows across farmland, some of the soil is washed away, resulting in erosion. Researchers released water
across a test bed at different flow rates and measured the amount of soil washed away. The following table gives the
flow (in liters per second) and the weight (in kilograms) of eroded soil:

Answers

The correlation coefficient between flow rate and amount of eroded soil is:

0.967.

Correlation coefficients

The correlation coefficient is an index that measures correlation between two variables, assuming values between -1 and 1.

If it is positive, the relation is positive, meaning that the variables are direct proportional. If it is negative, the variables are inverse proportional.

If the absolute value of the correlation coefficient is greater than 0.6, the relationship between the variables is strong.

Given a data-set of two points, the correlation coefficient is found inserting points of the data-set into the calculator. In this problem, the points in the data-set are given as follows:

(0.31, 0.82), (0.85, 1.95), (1.26, 2.18), (2.47, 3.01), (3.75, 6.07).

Using a calculator, the coefficient is given as follows:

0.967.

Hence the last option gives the correct coefficient.

Missing information

The complete problem is given by the image at the end of the answer.

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Determine the angle of rotation of the conic section given by: 32x2 +50xy + 7y2 = 100 (round your answer to the nearest tenth of adegree).

Answers

The formula to obtain the angle of rotation is as follows:

[tex]\cot 2\theta=\frac{A-C}{B}[/tex]

Compare the given equation to the general equation of a conic.

[tex]Ax^2+Bxy+Cy^2+Dx+Ey+F=0[/tex]

Thus, the values of A, B, and C are as follows.

[tex]\begin{gathered} A=32 \\ B=50 \\ C=7 \end{gathered}[/tex]

Substitute the values into the equation.

[tex]\begin{gathered} \cot 2\theta=\frac{32-7}{50} \\ \cot 2\theta=\frac{25}{50} \\ \cot 2\theta=\frac{1}{2} \end{gathered}[/tex]

Find the value of the θ.

[tex]\begin{gathered} \frac{1}{\tan 2\theta}=\frac{1}{2} \\ \tan 2\theta=2 \\ 2\theta=\tan ^{-1}(2) \\ 2\theta\approx63.4349 \\ \theta\approx31.7 \end{gathered}[/tex]

consider the function f(x) = x^1/2 and the function G, shown below. g(x)= f(1/4 • x) = (1/4 •x)^1/2how will the graph of the function g differ from the graph of the function f?

Answers

ANSWER

The graph of function g is the graph of function f stretched horizontally by a factor of 4.

EXPLANATION

Function g(x) is a transformation of function f(x), obtained by multiplying the variable, x, by 1/4. This is described as a horizontal stretch by a factor of 4.

Hence, the graph of function g is the graph of function f stretched horizontally by a factor of 4.

Swine Flu is attacking Springfield. The function below determines how many people have swine where t=time in days and S=the number of people in thousands.

Answers

[tex]s(t)=9t-4[/tex]

A.find s(4)

[tex]\begin{gathered} s(4)=9(4)-4 \\ s(4)=36-4 \\ s(4)=32 \end{gathered}[/tex]

B. means that in 4 days there will be 32000 infected people

C. find t to S(t)=23

[tex]\begin{gathered} 23=9t-4 \\ 9t=23+4 \\ t=\frac{27}{9} \\ t=3 \end{gathered}[/tex]

D. means there will be 23,000 infected people after 3 days

E. Graph

to draw the line we need two points which we already have but we will add another to make a table of 3 values the new value is t=1

[tex]\begin{gathered} s(1)=9(1)-4 \\ s(1)=5 \end{gathered}[/tex]

table

graph

kindly asking for help to clarify this question and mathematical problem .

Answers

As you can see the options A and B are decreasing, D is constant, therefore, the only increasing relationship is the option C

10. If you invest $2000 at 6% compounded monthly, how long will it take the account to double in
value?

Answers

If I invest $2000 at 6% interest compounded monthly, it will take 11.58 years by the account to double in value.

What is compound interest?

The practice of adding interest to the principal amount of a loan or deposit is known as compound interest, sometimes known as interest on principal and interest. It happens when interest is reinvested, added to the lent capital rather than paid out, or required to be paid by the borrower, resulting in interest being created the next period on the principal amount plus any accrued interest. Compound interest is a prominent concept in finance and economics.

The initial investment of $2000 at 6% compounded monthly.

Since, the interest rate of 6% is compounding monthly, then the effective annual interest rate will be

= (1+)−1i = (1+rm)m−1

Here, r = interest rate in decimals

= (1+0.0612)12−1i = (1+0.0612)12−1

= 0.061678i = 0.061678

= ×100 = 6.1678%

Now, we are using Rule 72 to calculate the doubling time

Time to double the initial amount = 72 /effective annual interest rate

Time to double the initial amount = 11.58 years

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rewrite 2x+5y=10 in slope intercept form then graph them

Answers

The slope intercept of a line is:

[tex]y=mx+b[/tex]

We re-write the equation given:

[tex]\begin{gathered} 2x+5y=10 \\ 5y=-2x+10 \\ y=\frac{-2x+10}{5} \\ y=\frac{-2x}{5}+\frac{10}{5} \\ y=-\frac{2}{5}x+2 \end{gathered}[/tex]

The graph of this line is shown below:

divide the sum of z and 3 by 7

Answers

Answer:

4 divide the sum of z and 3 by 7

Step-by-step explanation:

z+3=7

or,z=7-3

or,z=4

How to graph this and how to solve the equation

Answers

SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

The details of the solution are as follows:

The graphs of the two equations:

[tex]\begin{gathered} y=\text{ }\frac{-1}{5}x\text{ - 6} \\ y=\text{ }\frac{3x}{5}-\text{ 2} \end{gathered}[/tex]

is as follows:

CONCLUSION:

From the graphs above, we can see that the solution to the graphs is:

[tex](x,\text{ y \rparen = \lparen - 5, - 5\rparen}[/tex]

#8 help with algebra 2 question. That’s the only picture I have. I tried writing it out.

Answers

Solution:

Given a cosine function graph;

The general cosine function is

[tex]y=A\cos(Bx-C)+D[/tex]

Where

[tex]\begin{gathered} A\text{ is the amplitude} \\ Period=\frac{2\pi}{B} \\ C\text{ is the phase shift} \\ D\text{ is the vertical shift} \end{gathered}[/tex]

From the graph,

The midline is y = 1

The amplitude, A, is

[tex]\begin{gathered} A=4-1=3 \\ A=3 \end{gathered}[/tex]

The amplitude, A is 3

Where,

[tex]\begin{gathered} Period=12 \\ Period=\frac{2\pi}{B} \\ 12=\frac{2\pi}{B} \\ Crossmultiply \\ 12B=2\pi \\ Duvide\text{ both sides by 12} \\ \frac{12B}{12}=\frac{2\pi}{12} \\ B=\frac{\pi}{6} \end{gathered}[/tex]

The phase shift, C = 0, and the vertical, D, is 1

Thus, the equation of the graph is

[tex]\begin{gathered} y=A\cos(Bx-C)+D \\ Where \\ A=3 \\ B=\frac{\pi}{6} \\ C=0 \\ D=1 \\ y=3\cos(\frac{\pi}{6}x)+1 \end{gathered}[/tex]

The graph is shown below

Hence, the equation is

[tex]y=3\cos(\frac{\pi}{6}x)+1[/tex]

Which statement explains whether x=5 is the solution to 5x + 2 = 27? a. Yes, because 5x means x=5.b. No, because 5x doesn't mean x=5.c. No, because when x is replaced by 5 the equation is false. d. Yes, because when x is replaced by 5 the equation is true.

Answers

Given

x = 5

5x + 2 = 27

Procedure

d. Yes, because when x is replaced by 5 the equation is true. ​

covert 6\10 into decimal number and then see if it's a repeating or terminating

Answers

We are asked to determine wheater 6/10 in decimal form is repeating or terminating. To do that we need to divide 6 over 10. To do that, we proceed as follows:

We need to find a number that when multiplied by 10 gives 6. That number is 0.6, because:

[tex]0.6\times10=6[/tex]

Therefore 6/10=0.6 Since the numbers after the radix point do not repeat, this is a terminating decimal.

The Adventure Club has scheduled a trip to hike a nearby mountain. Since the group started hiking, they gained 456 feet in altitude from their start position. The current altitude is 437 feet, but there is no record of their starting altitude.write a equation to represent this situation Explain what your variable representssolve your equation please someone help me ill give you a star anything please ♡

Answers

Let h be the altitude of the starting position.

Since the group has gained 456 feet from the start position, then the current altitude is:

Find the measures of an interior angle and an exterior angle of the indicated regular polygon. Regular 20-gon interior angle exterior angle

Answers

[tex]\begin{gathered} \text{Please one interior angle =}\frac{180(n-2)}{20},\text{ n =20} \\ \text{Interior angle = }\frac{180(20-2)}{20}=\frac{180\times18}{20}=162 \\ \end{gathered}[/tex][tex]\begin{gathered} \text{One exterior angle = }\frac{360}{n} \\ =\frac{360}{20}=\text{ 18} \end{gathered}[/tex]

A survey was given asking whether they watch movies at home from Netflix, Redbox, or a video store.Use the results to determine how many people use Redbox.60 only use Netflix64 only use Redbox24 only use a video store 8 use only a video store or Redbox38 use only Netflix or Redbox 35 use only a video store or Netflix5 use all three24 use none of these

Answers

SOLUTION

We will use a Venn Diagram for this problem.

Let N represent those that use Netflix, R represent those that use Redbox and V represent those that use video store. The Venn Diagram is shown below

From the Venn Diagram above, the number in each part of a circle, represents the information

Now, how many people use Redbox?

The number of those that use Redbox is represented by the circle R, so we add all the numbers in this circle, we have

[tex]n(R)=38+64+5+8=115[/tex]

Hence the answer is 115

Becky borrowed $580.00 from the bank. The loan had a 13.5% simple
annual interest rate, and she paid off the bill over 18 months. What was
the total amount, including interest, Becky paid for the loan?

Answers

Answer:  $697.45

Work Shown:

P = 580

r = 0.135

t = 18 months = 18/12 = 1.5 years

A = P*(1+r*t)

A = 580*(1+0.135*1.5)

A = 697.45

what is the volume of a cube with sides 3 cm.be sure to include correct units with your answer

Answers

Answer:

27 cubic feet

Explanation:

The volume of a cube with side length L is given by

[tex]V=L^3[/tex]

Now in our case, L = 3 ft; therefore, the volume is

[tex]V=3^3[/tex]

which simplifies to give

[tex]\boxed{V=27\text{ ft}^3.}[/tex]

which is our answer!

Hence, the volume of the cube with the side length of 3 cm is 27 cubic cm.

Megan's text messaging plan cost $15 for the first 600 messages and 5¢ for each additional text message. If she owes $24.60 for text messaging in the month of October, how many text messages did she send that month

Answers

Megan sent  792 text messages in the month of October .

In the question ,

it is given that

Cost for first 600 messages = $15

additional text message charge = $0.05

Amount owed by Megan for the month of October = $24.60

Let the number of Additional messages be x.

So, according to the question

15 + 0.05x = 24.60

0.05x = 24.60-15

0.05x = 9.6

x = 9.6/0.05

x = 192

number of extra messages = 192

total messages = first 600 messages + extra messages

= 600+192

= 792

Therefore , Megan sent 792 text messages in the month of October .

The given question is incomplete , the complete question is

Megan's text messaging plan cost $15 for the first 600 messages and 5¢ for each additional text message. If she owes $24.60 for text messaging in the month of October, how many text messages did she send that month ?

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At which of the following points do the two equations f(x)=3x^2+5 and g(x)=4x+4 intersect?A. (0,5)B. (1,8)C. (0,4) D. (8,1)

Answers

Given the equations:

[tex]\begin{gathered} f(x)=3x^2+5 \\ \\ g(x)=4x+4 \end{gathered}[/tex]

Let's find the point where both equations intersect.

To find the point let's first find the value of x by equation both expression:

[tex]3x^2+5=4x+4[/tex]

Now, equate to zero:

[tex]\begin{gathered} 3x^2+5-4x-4=0 \\ \\ 3x^2-4x+5-4=0 \\ \\ 3x^2-4x+1=0 \end{gathered}[/tex]

Now let's factor by grouping

[tex]\begin{gathered} 3x^2-1x-3x+1=0 \\ (3x^2-1x)(-3x+1)=0 \\ \\ x(3x-1)-1(3x-1)=0 \\ \\ \text{ Now, we have the factors:} \\ (x-1)(3x-1)=0 \end{gathered}[/tex]

Solve each factor for x:

[tex]\begin{gathered} x-1=0 \\ Add\text{ 1 to both sides:} \\ x-1+1=0+1 \\ x=1 \\ \\ \\ \\ 3x-1=0 \\ \text{ Add 1 to both sides:} \\ 3x-1+1=0+1 \\ 3x=1 \\ Divide\text{ both sides by 3:} \\ \frac{3x}{3}=\frac{1}{3} \\ x=\frac{1}{3} \end{gathered}[/tex]

We can see from the given options, we have a point where the x-coordinate is 1 and the y-coordinate is 8.

Since we have a solution of x = 1.

Let's plug in 1 in both function and check if the result with be 8.

[tex]\begin{gathered} f(1)=3(1)^2+5=8 \\ \\ g(1)=4(1)+4=8 \end{gathered}[/tex]

We can see the results are the same.

Therefore, the point where the two equations meet is:

(1, 8)

ANSWER:

B. (1, 8)

i need help solving this and also what does the 2 that's on the top of some letters mean

Answers

given the expression :

[tex]a-bc^2[/tex]

We need to evaluate the expression when :

[tex]\begin{gathered} a=3 \\ b=2 \\ c=-1 \end{gathered}[/tex]

So, substitute with a , b and c at the expression

The result will be :

[tex]\begin{gathered} a-bc^2 \\ =3-2\cdot(-1)^2 \\ =3-2\cdot1 \\ =3-2 \\ \\ =1 \end{gathered}[/tex]

There is another expression :

[tex]c^2+a^2b[/tex]

By substitute with the values of a, b and c

so, the result will be :

[tex]\begin{gathered} c^2=(-1)^2=1 \\ a^2=3^2=9 \\ \\ c^2+a^2b=1+9\cdot2=1+18=19 \end{gathered}[/tex]

Pizza House offers 4 different salads, 5 different kinds of pizza, and 3 different desserts. How many different three course meals can be ordered?...Question content area rightPart 1How many different meals can be ordered?enter your response here

Answers

A three-course meal will contain 1 pizza, 1 salad, and 1 dessert.

The question tells us that there are 4 different salads, 5 different pizzas, and 3 different desserts.

Therefore, the total number of possible ways a three-course meal can be served is calculated as the product of all the numbers. This is shown below:

[tex]\Rightarrow4\times5\times3=60[/tex]

60 different meals can be ordered.

Is P(A and B) ≠ 0? Explain.
A.) No. P(A and B) = 0.

B.) Yes. Even if P(A) = 0 or P(B) = 0, P(A and B) will always be non-zero.

C.) No. Because both P(A) and P(B) are not equal to 0, P(A and B) = 0.

D.) Yes. Because both P(A) and P(B) are not equal to 0, P(A and B) ≠ 0. (b)

Answers

The right option is D as P(A and B) ≠ 0 only for the independent probability events for A and B.

What is an independent event in probability?

Two events say A and B are said to be independent if the probability of the intersection of A and B is equal to the product of their respective probability, But same events are said to be mutually exclusive if the probability of the intersection of A and B is equal to zero(0).

In the given question, P(A and B) ≠ 0 can only be true if A and B are independent event and P(A) and P(B) are not equal to zero such that

P(A and B)=P(A)× P(B)≠ 0.

Hence, we can deduce from the axiom of independent events of probability that because both P(A) and P(B) are not equal to 0, P(A and B) ≠ 0.

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Refer to the diagram below to prove that the exterior angle equals the

Answers

To prove that the sum of the remote interior angles and the exterior angle have the same value, we recall 2 things:

1.- the inner angles of a triangle add up 180 degrees

2.- angle 3 and angle 4 are supplementary which means that they add up 180 degrees.

[tex]\begin{gathered} \measuredangle1+\measuredangle2+\measuredangle3=180^{\circ} \\ \measuredangle3+\measuredangle4=180^{\circ} \\ \Rightarrow \\ \measuredangle1+\measuredangle2+\measuredangle3=\measuredangle3+\measuredangle4 \\ \Rightarrow \\ \measuredangle1+\measuredangle2=\measuredangle4 \end{gathered}[/tex]

Answer:

They are linear pair and therefore supplementary.

Triangle sum theorem.

Substitution.

Subtraction property of equality.

How come my answer is wrong? It says it’s equal to the correct answer but it’s not the right answer.

Answers

[tex]\begin{gathered} (2.7x^3-5.5x^2-2)-(5.5x^3-7.9x^2+\text{ 2) }\ldots..\text{remove parenthesis } \\ =\text{ 2.7}x^{3\text{ }}-5.5x^2-2-5.5x^3+7.9x^2\text{ -2} \\ =\text{ (2}.7x^{3\text{ }}-5.5x^3)-5.5x^2+7.9x^2-2-2^{} \\ =\text{ }-2.8x^3+2.4x^2-4^{} \end{gathered}[/tex]

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