[tex]\\ \sf\Rrightarrow Speed=\dfrac{Distance}{Time}[/tex]
[tex]\\ \sf\Rrightarrow Time=\dfrac{Distance}{Speed}[/tex]
[tex]\\ \sf\Rrightarrow Time=\dfrac{5000}{300}[/tex]
[tex]\\ \sf\Rrightarrow Time=16.6min[/tex]
A 2.6 kg mass attached to a light string rotates on a horizontal,
frictionless table. The radius of the circle is 0.525 m, and the
string can support a mass of 17.9 kg before breaking. The
acceleration of gravity is 9.8m/s2. What maximum speed can
the mass have before the string breaks?
The maximum speed the mass can have before it breaks is 2.27 m/s.
The given parameters:
maximum mass the string can support before breaking, m = 17.9 kgradius of the circle, r = 0.525 mThe maximum speed the mass can have before it breaks is calculated as follows;
[tex]T = ma_c\\\\Mg = \frac{Mv^2}{r} \\\\v^2 = rg\\\\v = \sqrt{rg} \\\\v_{max} = \sqrt{0.525 \times 9.8} \\\\v_{max} = 2.27 \ m/s[/tex]
Thus, the maximum speed the mass can have before it breaks is 2.27 m/s.
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What is the average speed of a car that travels 30 m in the 3 secs and 2 m 4 secs and 20 m 5 secs
Answer:
4.3333333
Explanation:
total distance / total time taken
30 + 2 + 20 / 3 + 4 + 5
52 / 12
4.3 recurring
a car travels at a constant speed of 20m/s and yet it does not have a constant velocity. explain how this could be
Answer:
HOPE THIS HELPS!!
Explanation:
Velocity is speed as well as distance mentioned.
The car is traveling at a constant speed of 20m/s but it may not be traveling in any particular direction. It would be taking many turns (left and right) or it would be moving in a circular manner.
So,it is at constant speed but not constant velocity.
8. Placing your vehicle between the pilot/escort vehicle and an oversize/overweight vehicle can be dangerous.A. TrueB. False
Answer:
A because that's the answer
what is a velocity of an object with a momentum of 300 kg m/s and the mass of 100 kg
Answer:
v = 3 m/s
Explanation:
P is the momentum
m is the mass
v is the velocity
P = m•v
300 = 100•v Divide both sides per 100
300/100 = v
v = 3 m/s
[tex]\text{Given that,}\\\\\text{Momentum, p = 300 kg m s}^{-1}\\\\\text{Mass, m = 100 kg}\\\\\text{We know that,}\\\\p = mv\\\\\implies v = \dfrac pm = \dfrac{300}{100} = 3 ~ \text{m s}^{-1}[/tex]
A bullet of mass M1, is fired towards a block
of mass m2 initially at rest at the edge of a
frictionless table of height h as in the figure.
The initial speed of the bullet is vi. Consider
two cases. a соmрlеtеlу inсlаѕtiс one and an
elastic one where the bullet bounces off the block. What is the flight ratio time?
The ratio of time of flight for inelastic collision to elastic collision [tex](t_A :t_B)[/tex] is 1:2
The given parameters;
mass of the bullet, = m₁mass of the block, = m₂initial velocity of the bullet, = u₁initial velocity of the block, = u₂ = 0Considering inelastic collision, the final velocity of the system is calculated as;
[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\[/tex]
The time of motion of the system form top of the table is calculated as;
[tex]v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)[/tex]
Considering elastic collision, the final velocity of the system is calculated as;
[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2[/tex]
Apply one-directional velocity
[tex]u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1[/tex]
Substitute the value of [tex]v_1[/tex] into the above equation;
[tex]m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)[/tex]
where;
[tex]v_2[/tex] is the final velocity of the block after collision
Since the bullet bounces off, we assume that only the block fell to the ground from the table.
The time of motion of the block is calculated as follows;
[tex]v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)[/tex]
The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;
[tex]\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2[/tex]
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A car travels 120 miles in 12 hours. What is
the car's speed?
Select one:
O a. 10 m/s
b. 10 mph
c. 1200 mph
O d. 0.1 m/s
Answer:
I hope it will help you...
#CARRYONLERANING
How long does it take a car traveling at 45km/h to travel 100.0 m?
Answer:
8 seconds
Explanation:
Since the carspeed is in km/h, we need equal units, so we will make 100.0m 0.1000km.
Then we need to find how long it takes the car to travel 0.1km
We can use the formula distance=speed * time and get
0.1=45 * time
Therefore we get .002222... hours
Multiplying this by 3600 (to get seconds, 60x60), we get 8 seconds
Answer:
8m/s
Explanation:
speed = 45km/h
Distance = 100m
we have to find time = ?
Formula for speed is = Distance/ Time
Here Distance is given in 'm' so we need to convert speed value in 'm'
So to convert km/h in m formula is divide 45km/h by 3.6 then the km/h value gets converted in m so now the value is 12.5 m/s
So now,
speed = Distance/Time
we have to find Time
Then,
Time = Distance/ Speed
= 100/12.5
= 8m/s
The body weighs 15N. What is the mass of that body?
Explain the relationship between pitch and frequency.
Answer:
Though pitch and frequency are not equivalent, they are correlated. This means that as one goes up, the other does as well. A higher frequency produces a higher pitch, and a lower frequency produces a lower pitch.
Explanation:
Share your thoughts about this statement by John Wesley
"Electricty is the soul of universe"
Answer:
I think this statement is true at least in modern day times. The world runs on nothing but technology. People use more technology instead of old school textbooks and papers. Imagine living in a world without technology… that means no cars, no trains, no devices, no machines like your stove or printer, no lights and lots more. John Wesley is 100 percent correct with this statement. Electricity is indeed the powerhouse of the universe.
PLZZZ HELPPP ASAP
I really need help as soon as possible
Answer:
Friction
Explanation:
As the toy cars rolls away, more friction is created. The more friction there is, the more friction on surface rubs against another which creates friction which in-term slows it down. Hope this helps.
A Person is carrying 6kg in one hand and 5kg in another.Calculate the resultant force applied by him
Please help someone. A generator consumes 147 joules of energy in fuel and produces 75 joules of energy
in electricity. Engineers are challenged to produce a generator that is 20% more
efficient. Which of the following combinations of input and output energy represents a generator that has met this design challenge?
a. 150 joules of fuel to produce 90 joules of electricity
b. 135 joules of fuel to produce 68 joules of electricity
c. 60 joules of fuel to produce 100 joules of electricity
d. 115 joules of fuel to produce 82 joules of electricity
Answer:
A
Explanation:
Current effiency
= 75/147
= 0.5102
New Efficiency
= 120/100 × 0.5102
= 0.6122
Only option A satisfies this efficiency.
Calculate Kylie’s weight at 3 radii away from the center of the earth. Kylie weighs 565.4N on the earths surface
Answer:
Earth's mass is 5.98 x 1024 kg and has a radius of 6.37 x 106 m. 8.06 N/kg ... what would be the weight of a 70.0-kg student on the surface of Jupiter?Explanation:
What is centripetal force and elastic force
Answer:
centripetal force is a net force that acts on an object to keep it moving along a circular path and elastic force acts to return a spring to its natural length
electromagnetic radiation at its maximum wavelength is:
Answer:
the radio wave. - The frequency ranges between 300 gigahertz (GHz) to 30 hertz (Hz).
Explanation:
The magnitude, M, of an earthquake is represented by the equation M=23logEE0 where E is the amount of energy released by the earthquake in joules and E0=104. 4 is the assigned minimal measure released by an earthquake. In scientific notation rounded to the nearest tenth, what is the amount of energy released by an earthquake with a magnitude of 5. 5?.
An earthquake with a magnitude of 5.5 releases 4.5 × 10¹² J of energy.
What is the magnitude of an earthquake?The magnitude of an earthquake is a number that characterizes the relative size of an earthquake and is based on the measurement of the maximum motion recorded by a seismograph.
If the magnitude of the earthquake is M = 5.5, we can calculate the amount of energy released (E) using the following expression.
[tex]M = \frac{2}{3} log(\frac{E}{E_0} )\\\\E = E_0 \times 10^{\frac{3}{2}M } = 10^{4.4} \times 10^{\frac{3}{2}(5.5) } = 4.5 \times 10^{12} J[/tex]
where,
E₀ is the assigned minimal measure released by an earthquake.An earthquake with a magnitude of 5.5 releases 4.5 × 10¹² J of energy.
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1. How much energy is needed just to melt 0.56kg of ice at 0◦ C?
2. How much energy is needed just to boil 5kg of water at 100◦ C?
3. What is the specific heat of metal if its mass is 27 g and it requires 420 J of heat energy to
increase its temperature from 25°C to 50°C?
please help me out I dont have much time
Answer:
This will require 266.9 of heat energy.
Explanation:
To calculate the energy required to raise the temperature of any given substance, here's what you require:The mass of the material, m The temperature change that occurs, ΔT The specific heat capacity of the material,
c
(which you can look up). This is the amount of heat required to raise 1 gram of that substance by 1°C.
Here is a source of values of
c for different substances:
Once you have all that, this is the equation:
Q=m×c×ΔT(Q is usually used to symbolize that heat required in a case like this.)For water, the value of c is 4.186g°C So, Q=750×4.186×85=266=858=266.858
i do believe that i need help
mrs. knight drops her briefcase. when the briefcase lands on the floor, what is the reaction force to the action force of the briefcase on the floor?
Answer:
The force of the floor on the briefcase
Explanation:
The briefcase hits the floor and stops the falling which is reacting to the briefcase that was falling and hits the floor.
The falling briefcase would be the action force because it is moving downward
and
The reaction force would be the floor because it will react on the briefcase.
Hope this Helps
When the briefcase lands on the floor, the reaction force to the action force of the briefcase on the floor is force of the floor on the briefcase.
What are action force and reaction force?
It might be difficult to distinguish between action and reaction forces. This is due to the fact that both forces are always present.
One might argue that there are an equal number of forces in the universe if one were to count them all. However, the definition of the action force is provided by the perspective of the interaction analysis in order to help the argument.
A force that is applied to an object is known as an action force.
An action force with an opposite direction has an effect called a reaction force.
These two forces—also referred to as action and reaction forces—are covered by Newton's third law of motion.
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Two boats race in the water. One turns around to head back in the other direction to complete the race, but it collides into the boat that was now directly in front. What forces may have been a part of the collision? Describe them in detail.
The two forces involved in this collision are the colliding force and the reaction force which are equal in magnitude but opposite in direction.
According to Newton's third law, action and reaction are equal and opposite. This law is very important in describing head - on collisions between objects and is particularly apt in describing the collision between the two boats.
In this collision, two forces are important these are the action and the reaction. The action is the colliding force which the boat that was hit experiences. The reaction force is the force that this boat experiences as a result of hitting the boat in front of it. The both forces are equal in magnitude but opposite in direction.
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A furniture crate of mass 60 kg is at rest a loading ramp that makes an angle of 25° with the horizontal
The coefficient of kinetic friction between the crate and the ramp is 0.2. What force, applied parallel to the incline, is required to push the crate up the incline at a constant speed?
Answer:
furniture crate of mass 60 kg is at rest a loading ramp that makes an angle of 25° with the horizontal
The coefficient of kinetic friction between the crate and the ramp is 0.2. What force, applied parallel to the incline, is required to push the crate up the incline at a constant speed?
Explanation:
furniture crate of mass 60 kg is at rest a loading ramp that makes an angle of 25° with the horizontal
The coefficient of kinetic friction between the crate and the ramp is 0.2. What force, applied parallel to the incline, is required to push the crate up the incline at a constant speed?
[tex] \huge \boxed{ \sf lol}[/tex]
What is the height of the Golden Bridge?
Answer:
hi your answer to this question is 220'
Explanation:
hope this helped you
A projectile is fired with a velocity of 320 ms at an angle of 30 degree to a horizontal.1 Find the time to reach the maximum height. 2 it's horizontal range.
(a) The time taken for the projectile to reach the maximum height is 32.65 s.
(b) The horizontal range of the projectile is 9,049.1 m.
The given parameters:
Initial velocity of the projectile, u = 320 m/sAngle of projection, = 30 degreesThe time taken for the projectile to reach the maximum height is calculated as follows;
[tex]v_f = u- gt\\\\0 = 320 - 9.8t\\\\9.8t = 320\\\\t = \frac{320}{9.8} \\\\t = 32.65 \ s[/tex]
The horizontal range of the projectile is calculated as follows;
[tex]R = \frac{u^2 sin(2\theta)}{g} \\\\R = \frac{320^2 \times sin(2\times 30)}{9.8} \\\\R = 9,049.1 \ m[/tex]
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In an action-reaction pair
a. action force is exerted first
b. action force and the reaction force are equal in magnitude and act in the same direction.
c. action force and the reaction force are contact forces only.
d. action force and the reaction force act on two different objects.
Answer:
d. action force and the reaction force act on two different objects.
Hope you could understand.
If you have any query, feel free to ask.
In an action-reaction pair, action force and the reaction force act on two different objects.
What is Newton's Third Law of Motion?Newton's Third Law of Motion states that "For every action, there is an equal and opposite reaction, action and reaction act on two different bodies."
It means that equal force are act on reaction force that is it is also known as reciprocal law of motion.
When considering the options,
The first option is incorrect because action and reaction forces act simultaneously.The second option is also false because they act in opposite direction.The third option is wrong because for action-reaction force, physical contact is not necessary.So, In an action-reaction pair, action force and the reaction force act on two different objects. Thus, Option B is the correct answer.
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What is the magnitude of the resultant of
a 3.0-
meter displacement and a 4.0-meter
displacement as shown in the diagram?
A. 1.0 meter
4.0 meters
B. 5.0 meters
3.0 meters
C. 7.0 meters
D. 12 meters
Answer:b. 5.0 meters
Explanation: d² = 3²+4²
d² = 9+16
d² = 25
d = √25
d = 5m
The magnitude of the displacement is 5 m as shown in the diagram. Option B is correct.
What is displacement?
Displacement can be defined as the total change in the position of the object. It is a vector quantity.
From the Pythagorean theorem,
[tex]d =\sqrt { 3^2 +4^2}\\\\d = \sqrt {25}\\\\d = 5[/tex]
Therefore, the magnitude of the displacement is 5 m.
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If the force to stretch a spring is given as k = (100N/m), then what is the potential energy of the spring if it is stretched 1 meters from rest?
Answer:
50 Joules
Explanation:
An object is dropped from a building and strikes the ground with a speed of 52 m/s. How tall is the building?
Answer:
5.3 0 meter is the hight of the building is it
A train starts at rest and ends up with 1500 J of kinetic energy. How much work was done on the train?
Answer:
1500 J
Explanation:
Apparently, we're to assume that no energy is lost to friction or other effects. Then all of the energy the train has is due to work being done on it.
1500 J of work was done on the train