Answer:
270 nsec
Explanation:
Ripple-carry adder is a combination of multiple full-adders. It is relatively slow as each full-adder waits for the output of a previous full-adder for its input.
Formula to calculate the delay of a ripple-carry adder is;
= 2( n + 1 ) x D
delay in a full-adder = 150 nsec.
number of full-adders = number of ripple-carry bits = 8
= 2 ( 8 + 1 ) x 150
= 18 x 150
= 270 nsec
On what date was jschlatt originally added to the dreamsmp server, and on which date was his second appearance on the server?
since this has already been answered, who is your favorite SMP character?
mines Wilbur/ Ghostbur
some people will disagree with me but jshlatt is one of my favorite characters on the dream smp . But my all time favorite characters is ALL of Wilbur's characters
5-5. Design an Ethernet network to connect a single client P C to a single server. Both the client and the server will connect to their workgroup switches via U T P. The two devices are 900 meters apart. They need to communicate at 800 M b p s. Your design will specify the locations of any switches and the transmission link between the switches.
5-6. Add to your design in the previous question. Add another client next to the first client. Both connect to the same switch. This second client will also communicate with the server and will also need 800 M b p s in transmission speed. Again, your design will specify the locations of switches and the transmission link between the switches.
Answer:
ok so u have take the 5 and put 6
Explanation:
5-5. Ethernet network design: UTP connections from client PC and server to workgroup switches, 900m fiber optic link between switches, 800 Mbps communication.
5-6. Additional client connects to the same switch, UTP connection, maintains existing fiber optic link, 800 Mbps communication with the server.
What is the explanation for this?5-5. For connecting a single client PC to a single server, both located 900 meters apart and requiring communication at 800 Mbps, the following Ethernet network design can be implemented:
- Client PC and server connect to their respective workgroup switches via UTP.
- Use fiber optic cables for the 900-meter transmission link between the switches.
- Install switches at the client PC and server locations.
- Ensure that the switches support at least 1 Gbps Ethernet speeds to accommodate the required transmission speed.
5-6. In addition to the previous design, for adding another client next to the first client:
- Connect both clients to the same switch.
- Use UTP cables to connect the second client to the switch.
- Ensure the switch supports 1 Gbps Ethernet speeds.
- Maintain the existing fiber optic transmission link between the switches.
- The second client can also communicate with the server at the required 800 Mbps transmission speed.
Learn more about Network Design at:
https://brainly.com/question/7181203
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(1) Prompt the user to enter a string of their choosing. Output the string.
Ex: Enter a sentence or phrase: The only thing we have to fear is fear itself. You entered: The only thing we have to fear is fear itself.
(2) Complete the GetNumOfCharacters() function, which returns the number of characters in the user's string. Use a for loop in this function for practice. (2 pts)
(3) In main(), call the GetNumOfCharacters() function and then output the returned result. (1 pt) (4) Implement the OutputWithoutWhitespace() function. OutputWithoutWhitespace() outputs the string's characters except for whitespace (spaces, tabs). Note: A tab is '\t'. Call the OutputWithoutWhitespace() function in main(). (2 pts)
Ex: Enter a sentence or phrase: The only thing we have to fear is fear itself. You entered: The only thing we have to fear is fear itself. Number of characters: 46 String with no whitespace: The only thing we have to fear is fear itself.
Answer:
See solution below
See comments for explanations
Explanation:
import java.util.*;
class Main {
public static void main(String[] args) {
//PrompT the User to enter a String
System.out.println("Enter a sentence or phrase: ");
//Receiving the string entered with the Scanner Object
Scanner input = new Scanner (System.in);
String string_input = input.nextLine();
//Print out string entered by user
System.out.println("You entered: "+string_input);
//Call the first method (GetNumOfCharacters)
System.out.println("Number of characters: "+ GetNumOfCharacters(string_input));
//Call the second method (OutputWithoutWhitespace)
System.out.println("String with no whitespace: "+OutputWithoutWhitespace(string_input));
}
//Create the method GetNumOfCharacters
public static int GetNumOfCharacters (String word) {
//Variable to hold number of characters
int noOfCharactersCount = 0;
//Use a for loop to iterate the entire string
for(int i = 0; i< word.length(); i++){
//Increase th number of characters each time
noOfCharactersCount++;
}
return noOfCharactersCount;
}
//Creating the OutputWithoutWhitespace() method
//This method will remove all tabs and spaces from the original string
public static String OutputWithoutWhitespace(String word){
//Use the replaceAll all method of strings to replace all whitespaces
String stringWithoutWhiteSpace = word.replaceAll(" ","");
return stringWithoutWhiteSpace;
}
}