I'm not sure if you can exactly give me the answers, but I need help solving these types of questions, I will attach them below. they are about tangent lines.

I'm Not Sure If You Can Exactly Give Me The Answers, But I Need Help Solving These Types Of Questions,
I'm Not Sure If You Can Exactly Give Me The Answers, But I Need Help Solving These Types Of Questions,
I'm Not Sure If You Can Exactly Give Me The Answers, But I Need Help Solving These Types Of Questions,

Answers

Answer 1

Question 1

Explanation

To solve these types of questions, we will use the Tangent radius theorem

Tangent to a Circle Theorem

The tangent theorem states that a line is a tangent to a circle if and only if the line is perpendicular to the radius drawn to the point of tangency.

The figure below helps give a pictorial view

The principle to be used here for question 1 will be

[tex]x^2+8^2=17^2[/tex]

Simplifying further

[tex]\begin{gathered} x^2+64=289 \\ x^2=289-64 \\ x^2=225 \\ x=\sqrt{225} \\ x=15 \end{gathered}[/tex]

Thus, the value of x is 15 units

I'm Not Sure If You Can Exactly Give Me The Answers, But I Need Help Solving These Types Of Questions,

Related Questions

Referring to the figure, find the unknown measure of ABC.

Answers

According to the Inscribed Angle Theorem, the measure of an angle inscribed in a circle equals half the arc that it intercepts.

Then:

[tex]m\angle ABC=\frac{1}{2}m\overset{\frown}{AC}[/tex]

Since the measure of the arc AC is equal to 84º, then:

[tex]m\angle ABC=\frac{1}{2}(84º)=42º[/tex]

Therefore, the answer is:

The measure of ABC is 42º.

Find the output, f, when the input, t, is 7 f = 2t - 3 f = Stuck? Watch a video or use a hint.

Answers

Answer:

f=11

Explanation:

Given the function:

[tex]f=2t-3[/tex]

When the input, t=7

The value of the output, f will be gotten by substituting 7 for t.

[tex]\begin{gathered} f=2t-3 \\ =2(7)-3 \\ =14-3 \\ f=11 \end{gathered}[/tex]

The output, f is 11.

Not sure on how to do this. Could really use some help.

Answers

We will have the following:

We will recall that the surface area of a sphere is given by:

[tex]A_s=4\pi r^2[/tex]

So, the surface area of the given sphere will be:

[tex]\begin{gathered} A_s=4\pi(\sqrt{\frac{7}{3.14}})^2\Rightarrow A_s=4(3.14)\ast\frac{7}{3.14} \\ \\ \Rightarrow A_s=4\ast7\Rightarrow A=28 \end{gathered}[/tex]

So, the surface area of the sphere will be 28 yd^2.

*The reason we can use "mental math" is that we are using an approximation of pi, which makes it so it cancels with the 3.14 in the denominator after a point; leaving a simple multiplication at the very end.

when his bus arrives Calvin is 40 ft east of the corner the door of the bus is 30 feet north of the corner how far will Calvin run directly across the field to the bus

Answers

Since this situation can be represented by a right triangle, we can use the pythagorean theorem. Doing so, we have:

[tex]\begin{gathered} a^2+b^2=c^2\text{ } \\ (30)^2+(40)^2=c^2\text{ (Replacing)} \\ 900+1600=c^2\text{ (Raising both numbers to the power of 2)} \\ 2500=c^2\text{ (Adding)} \\ \sqrt[]{2500}=\sqrt[]{c^2} \\ 50=c\text{ (Taking the square root of both sides)} \\ \text{The answer is 50 ft} \end{gathered}[/tex]

Sketch the graph of a function that has a local maximum value at x = a where f'(a) is undefined.

Answers

Derivative and Maximum Value of a Function

The critical points of a function are those where the first derivative is zero or does not exist.

Out of those points, we may find local maxima or minima or none of them.

One example of a function with a derivative that does not exist is:

[tex]y=-x^{\frac{2}{3}}[/tex]

This function has a local maximum at x=0 where the derivative does not exist.

The graph of this function is shown below:

the prompt is in the photo

Answers

By using the given box and whisker plot, the number of students that earned a score from 77 and 90 is: N. 13.

What is a box and whisker plot?

A box and whisker plot is also referred to as boxplot and it can be defined as a type of chart that can be used to graphically represent the five-number summary of a data set with respect to locality, skewness, and spread.

In Mathematics, the five-number summary of any box and whisker plot include the following:

MinimumFirst quartileMedianThird quartileMaximum

What is an interquartile range?

IQR is an abbreviation for interquartile range and it can be defined as a measure of the middle 50% of data values when they are ordered from lowest to highest.

Mathematically, interquartile range (IQR) is the difference between first quartile (Q₁) and third quartile (Q₃):

IQR = Q₃ - Q₁

Based on the given box and whisker plot, we can logically deduce the following quartile ranges:

Third quartile, Q₃ = 90

First quartile, Q₁ = 77

Now, we can calculate the interquartile range (IQR) is given by:

Interquartile range, IQR = Q₃ - Q₁

Interquartile range, IQR = 90 - 17

Interquartile range, IQR = 13

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A middle school football game has four 12-minute quarters. Jason plays 8 minutes in each quarter.Which ratio represents Jason's playing time compared to the total number of minutes of playing time possible?1 to 3 2 to 33 to 24 to 1I’m

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The total minutes in the game is 48. The total playing game for Jason is 32. The ratio is

[tex]\frac{32}{48}[/tex]

Simplifying it, we have

[tex]\frac{32}{48}=\frac{16}{24}=\frac{8}{12}=\frac{4}{6}=\frac{2}{3}[/tex]

So, the playing ratio is 2 to 3 for Jason.

In △ABC, m∠A=45°. The altitude divides side AB into two parts of 20 and 21 units. Find BC.

Answers

Answer:

29 units

Step-by-step explanation:

BC is a side of ACB, which is a 45 45 90 triangle. BC = AB/sqrt2

If In △ABC, m∠A=45°. The altitude divides side AB into two parts of 20 and 21 units. Then BC is 29 units

What is Trigonometry?

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

Given,

In △ABC, m∠A=45°. The altitude divides side AB into two parts of 20 and 21 units.

We need to find BC

In triangle ACD,

tan 45° = CD/AD

CD = tan 45° x AD

= 1 x 20= 20 units

In triangle CDB,

tanФ = CD/BD

Ф = tan⁻¹(CD/BD)

= tan⁻¹(20/21)

= 43.6°

so, sin 43.6° = CD/BC

BC = CD/sin 43.6°

= 20/0.689

= 29 units

Hence the length of BC will be 29 units.

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Estimate the time it would take you to drive 278 miles at38 miles per hour. Round to the nearest hour

Answers

Speed formula:

[tex]s=\frac{d}{t}[/tex]

d is the distance

t is the time

As you need to find a time having the distance and speed, solve the equation above for t:

[tex]\begin{gathered} t\cdot s=d \\ t=\frac{d}{s} \end{gathered}[/tex]

Use the given data to find the time:

[tex]\begin{gathered} t=\frac{278mi}{38mi/h} \\ \\ t=7.31h \\ \\ t=7h \end{gathered}[/tex]Then, it would take you 7 hours to drive 278 mi at 38mi/h

Picture of question linked. The choices for the answer are -infinity, infinity, and 0

Answers

[tex]f(x)=-x^9-3x^5-5x^3+1[/tex]

The behavior of any polynomial function is determined by the exponent and the signal of the first term of the function.

In the case of f(x), the leading term is negative, and its expoent is odd. Therefore, when x is negative, the leading term will be positive and, when x is positive, the leading term is negative.

Therefore, we have:

[tex]\begin{gathered} As\text{ }x\rightarrow-\infty,\text{ }f(x)\rightarrow\infty \\ As\text{ }x\rightarrow\infty,\text{ }f(x)\rightarrow-\infty \end{gathered}[/tex]

What is 16.02+8.5+14 ?? i want to know for a home work

Answers

Given:

[tex]16.02\text{ + 8.5 + 14}[/tex]

To solve,

Step 1:

Express each value to a common decimal place.

We can express each value to two decimal places.

Thus, we have

[tex]16.02+8.50+14.00[/tex]

Step 2:

Sum up the values.

Hence, 16.02 + 8.5 + 14 gives 38.52.

Can you please help with 44For the following exercise, sketch a graph of the hyperbola, labeling vertices and foci

Answers

We have the following equation of a hyperbola:

[tex]4x^2+16x-4y^2+16y+16=0[/tex]

Let's divide all the equations by 4, just to simplify it

[tex]x^2+4x-y^2+4y+4=0[/tex]

Just to make it easier, let's put the term if "x" isolated

[tex]x^2+4x=y^2-4y-4[/tex]

Now we can complete squares on both sides, just remember that

[tex]\begin{gathered} (a+b)^2=a^2+2ab+b^2 \\ \\ (a-b)^2=a^2-2ab+b^2 \end{gathered}[/tex]

Now let's complete it!

[tex]\begin{gathered} x^2+4x=y^2-4y-4\text{ complete adding 4 on both sides} \\ \\ x^2+4x+4=y^2-4y-4+4 \\ \\ (x+2)^2=y^2-4y \\ \end{gathered}[/tex]

We already completed one side, now let's complete the side with y^2, see that we will add 4 again, then

[tex]\begin{gathered} (x+2)^2=y^2-4y \\ \\ (x+2)^2+4=y^2-4y+4 \\ \\ (x+2)^2+4=(y-2)^2 \end{gathered}[/tex]

And now we can write it using the standard equation!

[tex]\begin{gathered} (y-2)^2-(x+2)^2=4 \\ \\ (y-2)^2-(x+2)^2=4 \\ \\ \frac{(y-2)^2}{4}-\frac{(x+2)^2}{4}=1 \end{gathered}[/tex]

And now we can graph it like all other hyperbolas, the vertices will be:

[tex](-2,4)\text{ and }(-2,0)[/tex]

And the foci

[tex]\begin{gathered} c^2=a^2+b^2 \\ \\ c^2=2^2+2^2 \\ \\ c^2=2\cdot2^2 \\ \\ c^{}=2\, \sqrt[]{2} \end{gathered}[/tex]

Then the foci are

[tex](-2,2+2\, \sqrt[]{2})\text{ and }(-2,2-2\, \sqrt[]{2})[/tex]

Now we can plot the hyperbola!

I need help with question 4-8, can you please help me?Use f(X) as g(X) for question 5 and 6

Answers

Question 4

The x values for which g(x) = 3

From the graph, we have this value to be:

[tex]0\text{ }\leq\text{ x }\leq\text{ 2}[/tex]

Question 5

f(x) = 6, What is x?

From the graph, we can determine the value of x corresponding to f(x)= 6:

[tex]x\text{ = }4[/tex]

Question 6:

f(x)= 0, What is x?

From the graph, we can determine the value of x corresponding to f(x) = 0

[tex]x\text{ = 7}[/tex]

Question 7

The domain of the function:

The domain is the set of allowable inputs.

[tex]\lbrack0,\text{ 12\rbrack}[/tex]

Question 8

The range is the set outputs

[tex]\lbrack0,\text{ 6\rbrack}[/tex]

Factoring

64v^4-225w^10


I come up with

(8v^2+15w^2)(8v^2-15w^5) can I simplify it?

Answers

Your answer can't be simplified but it's also slightly incorrect. No worries!

You can simplify (64v^4 - 225w^10) by applying the difference of squares --> a^2 - b^2 = (a + b)(a - b)

Here, (64v^4) is a^2, and (225w^10) is b^2.

[tex]\sqrt{64v^4 }[/tex] = a = 8v^2

[tex]\sqrt{225w^{10} }[/tex] = b = 15w^5

Substitute the values:

(8v^2 + 15w^5)(8v^2 - 15w^5)

Therefore, the factorization of [tex]64x^{4} -225w^{10}[/tex] is:

[tex](8v^{2} + 15w^5)(8v^2-15w^5)[/tex]

The factorization is already the simplest. It can't be simplified further.

Hello, I need help with this practice problem. Thank you so much.

Answers

Answer:

5 units

Explanation:

Given the points:

[tex]\begin{gathered} \mleft(x_1,y_1\mright)=K(-2,-1) \\ \mleft(x_2,y_2\mright)=N(2,2) \end{gathered}[/tex]

We use the distance formula below:

[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Substitute the given values:

[tex]\begin{gathered} KN=\sqrt[]{(2-(-2))^2+(2-(-1))^2} \\ =\sqrt[]{(2+2)^2+(2+1)^2} \\ =\sqrt[]{(4)^2+(3)^2} \\ =\sqrt[]{16+9} \\ =\sqrt[]{25} \\ =5\text{ units} \end{gathered}[/tex]

The distance between the two points is 5 units.

Solve the exponential equation. Express irrational solutions as decimals correct to the nearest thousandth.5x -5.e-2x = 2eSelect the correct choice below and, if necessary, fill in the answer box to complete your choice.A. The solution set is(Round to the nearest thousandth as needed. Use a comma to separate answers as needed.)OB. The solution is the empty set.

Answers

We are asked to solve the exponential equation given below:

e^5x - 5 * e^-2x = 2e

First let's apply the exponent rules:

5x - 5 - 2x = In(2e)

Solving 5x - 5 - 2x = In(2e)

3x - 5 = In(2e)

Add 5 to both sides:

3x = In(2e) + 5

Divide both sides by 3

x = In(2e) + 5

3

x = 2.23104

x = 2.231 (To the nearest thousand)

Therefore, the correct option is A, which is The solution set is 2.231 (Round to the nearest thousand).

Choose which function is represented by the graph.111032-11-10 9 8 7 6 5 4-3-2-102 3 4 5 6 7 8 9 10 1110O A. 1(x) = (x − 1)(x +2)(x+4)(x+8)B. f(x) - (x-8)(x-4)(x-2)(x+1)C. f(x)=(x-1)(x+2)(x+4)D. f(x)=(x-4)(x-2)(x+1)876544 4 4 & & To-2X

Answers

The factors of a polynomial tell us the points where the graph intersects the x-axis.

From the graph provided in the question, the graph cuts the x-axis at the points:

[tex]x=-4,x=-2,x=1[/tex]

Therefore, the factors will be:

[tex]\begin{gathered} x=-4,x+4=0 \\ x=-2,x+2=0 \\ x=1,x-1=0 \\ \therefore \\ factors\Rightarrow(x+4),(x+2),(x-1) \end{gathered}[/tex]

Therefore, the polynomial will be:

[tex]f(x)=(x+4)(x+2)(x-1)[/tex]

OPTION C is the correct option.

Find the measures in the parallelogram4. Find AB and AC

Answers

Okay, here we have this:

Considering that in a parallelogram the opposite sides are congruent, we obtain the following:

AB=CD

AB=9 units

AC=BD

AC=4 units

The height of the Empire State Building is 1250 feet tall. Your friend, who is 75 inches tall, is standing nearby and casts a shadow that is 33 inches long. What is the length of the shadow of the Empire State Building? Please help me draw triangles

Answers

Answer:

The length of the building's shadow = 550.66 ft

Explanations:

The height of the Empie State Building = 1250 feet

The friend's height = 75 inches

The length of the friend's shadow = 33 inches

[tex]\frac{Actual\text{ height of the friend}}{\text{Length of the friend's shadow}}=\text{ }\frac{Height\text{ of the building}}{\text{Length of the building's shadow}}[/tex][tex]\begin{gathered} \frac{75}{33}=\text{ }\frac{1250}{\text{Length of the building's shadow}} \\ 2.27\text{ = }\frac{1250}{\text{Length of the building's shadow}} \\ \text{Length of the building's shadow = }\frac{1250}{2.27} \\ \text{Length of the building's shadow = }550.66\text{ f}et \end{gathered}[/tex]

Angles A and B are adjacent on a straight line. Angle A has a measure of (2r +20) and angle B has a measure of 130.. What is the measure of r?

Answers

When two angles are adjacent on a straight line, then the sum of the two angles equals 180 (that is sum of angles on a straight line). Therefore;

[tex]\begin{gathered} (2r+20)+130=180 \\ \text{Subtract 130 from both sides and you'll have} \\ 2r+20=50 \\ \text{Subtract 20 from both sides and you'll have} \\ 2r=30 \\ \text{Divide both sides by 2 and you'll have} \\ r=15 \end{gathered}[/tex]

The measure of r is 15

Abby scored 88, 91, 95, and 89 on her first four history quizzes. What score does Abby need to get on her fifth quiz to have an average of exactly 90 on her history quizzes? a.85b.86c.87a.88

Answers

Solution

For this case we can use the definition of average given by:

[tex]\text{Mean}=\frac{x_1+x_2+x_3+x_4+x_5}{5}[/tex]

The final score needs to be 90 so we can do this:

[tex]90=\frac{88+91+95+89+x_5}{5}[/tex]

And solving for x5 we got:

5*90 = 88+91+95+89+ x5

x5= 450 - 88- 91- 95 -89 = 87

Final answer:

c.87

Hello everybody! I would really appreciate it if Somebody could give me the answer for this question and give a brief explanation on how they got it. Look at the photo for instructions!

Answers

Recall that the constant of variation of a straight line is the slope of the line.

To compute the slope we will use the following formula for the slope of a line:

[tex]s=\frac{y_2-y_1}{x_2-x_1}\text{.}[/tex]

Now, notice that points (-1,3) and (1,-3) are on the line, then substituting these points in the above formula we get:

[tex]s=\frac{3-(-3)}{-1-1}=\frac{6}{-2}=-3.[/tex]

Answer: -3.

I need help with a 8th-grade math assignment:China has a population of approximately 1,382,323,332 people. The United States has a population of about 324,118,787 people.Part AUsing scientific notation, give the approximation for each population. Round the first factor to the nearest tenth.China: United States: Part BAbout how many more people live in China than in the United States? Express your answer using scientific notation. Round the first factor to the nearest hundredth.

Answers

We have the next given information:

China has a population of approximately 1,382,323,332 people.

The United States has a population of about 324,118,787 people.

a) We need to use scientific notation which is given by the next form:

[tex]ax10^n[/tex]

Where a is the coefficient rounded to the nearest tenth.

and a is the terms moved to the decimal point.

For China:

1382323332.0, we moved the decimal point nine spaces to the right.

then

1.382323332

Expressed in scientific notation and rounded to the nearest tenth:

[tex]1.4x10^9[/tex]

For the United States:

324,118,787 with the decimal point 324,118,787.0

then

324118787.0

Move the decimal point 8 spaces to the right, then:

3.24118787

Expressed in scientific notation and rounded to the nearest tenth:

[tex]3.2x10^8[/tex]

Part b:

To find how many more people live in China than in the United States, we need to subtract between China and the United States:

Then:

1,382,323,332 - 324,118,787 = 1,058,204,545

Now

1,058,204,545 equal to 1058204545.0

We need to move the decimal point 9 spaces:

1.058204545

Expressed as scientific notation and rounded to the nearest hundredth:

[tex]1.06x10^9[/tex]

Create an equation that models the table below. Use the variables in the table for your equation. Write your equation with 'S' isolated.

Answers

The table show piszzas (P) on the left column and the slices of Pepperonin (S) on the right column.

To determine the equation models first check the ratio S/P to determine whether they are proportinal or not.

[tex]\begin{gathered} \frac{36}{3}=12 \\ \frac{96}{8}=12 \\ \frac{228}{19}=12 \end{gathered}[/tex]

Now as the ratios are constant it mean the variation is linear and the relationship is proportional.

Thus the model equation can be determine as,

[tex]\begin{gathered} \frac{S}{P}=12 \\ S=12P \end{gathered}[/tex]

Thus, the above equation gives the required model equation.

A 6000-seat theater has tickets for sale at $24 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue
of $168,000?
The number of tickets for sale at $24 should be ?

Answers

The number of tickets which should be sold to $24 and $40 are 4500 and 1500 respectively.

Given, A 6000-seat theater has tickets for sale at $24 and $40.

How many tickets should be sold at each price for a sellout performance to generate a total revenue of $168,000 = ?

first, assign variables:

X = # of $24 tickets,  Y = # or $40 tickets

write equations based on the data presented:

"6000 seat theater..."

   X + Y = 6000 ...equation 1

"total revenue of 168,000"

The revenue from each type of ticket is the cost times the number sold, so:

  24X + 40Y = 168,000 .....equation 2

from equation 1:

   X = 6000 - Y

substitute this into equation 2:   (replace X with 6000-Y)

   24 (6000 - Y) + 40Y = 168,000

expand:

144,000 -24Y + 40Y = 168,000

rearrange and simplify:

    16Y = 168,000 - 144,000

    y = 24000/16

     Y = 1500

from equation 1:

     X = 6000 - 1500

     X = 4500

hence the number of tickets for sale at $24 should be 4500.

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I absolutely dont understand Division Property of Equality please help

Answers

We have the following equation.

[tex]20,000-1.8939m=10,000[/tex]

Where m is the number of feet in a mile.

Let us subtract 20,000 from both sides of the equation then simplify

[tex]\begin{gathered} -20,000+20,000-1.8939m=10,000-20,000 \\ -1.8939m=-10,000 \end{gathered}[/tex]

The negative sign cancels out and the equation becomes

[tex]\text{1}.8939m=10,000[/tex]

Finally, we can apply the Division Property of Equality which states that when we divide both sides of the equation with same number then the equation remains valid.

Let us divide both sides of the equation by 1.8939 then simplify

[tex]\begin{gathered} \frac{1.8939m}{1.8939}=\frac{10,000}{1.8939} \\ m=\frac{10,000}{1.8939} \\ m\approx5280 \end{gathered}[/tex]

Therefore, there are 5280 feet in a mile (rounded to nearest whole number)

Please help me with this word problem quickly, work is needed thank you!

Answers

Given:

Sheila can wash her car in 15 minutes. Bob takes time twice as long to wash the same car.

Required:

Find the time they take both together.

Explanation:

Sheila can wash her car in 15 minutes.

Work done by sheila in a minute =

[tex]\frac{1}{15}\text{ }[/tex]

Bob takes time twice as long to wash the same car. He washes the car in 30 minutes.

Work done by Bob in a minute

[tex]=\frac{1}{30}[/tex]

If they work together let them take time x per minute.

[tex]\frac{1}{15}+\frac{1}{30}=\frac{1}{x}[/tex]

Solve by taking L.C. M.

[tex]\begin{gathered} \frac{2+1}{30}=\frac{1}{x} \\ \frac{3}{30}=\frac{1}{x} \\ \frac{1}{10}=\frac{1}{x} \\ x=10\text{ minutes.} \end{gathered}[/tex]

If they work together they will take 10 minutes.

Final Answer:

Sheila and Bob wash the car together in 10 minutes.

What is the image point of (-12, —8) after the transformation R270 oD ?

Answers

Answer

(-12, -8) after R270°.D¼ becomes (-2, 3)

Explanation

The first operation represented by R270° indicates a rotation of 270° counterclockwise about the origin.

When a rotation of 270° counterclockwise about the origin is done on some coordinate, A (x, y), it transforms this coordinates into A' (y, -x). That is, we switch y and x, then add negative sign to x.

Then, the second operation, represents a dilation of the coordinate about the origin by a scale factor of ¼ given.

The coordinates to start with is (-12, -8)

R270° changes A (x, y) into A' (y, -x)

So,

(-12, -8) = (-8, 12)

Then, the second operation dilates the new coordinates obtained after the first operation by ¼

changes A (x, y) into A' (¼x, ¼y)

So,

(-8, 12) = [¼(-8), ¼(12)] = (-2, 3)

Hope this Helps!!!

Can 37° 111° and 32° be measurements of a triangle?

Answers

Answer

The angles given can easily be the measurements of one triangle because they sum up to give 180°.

Explanation

The sum of angles in a triangle is known to be 180°

So, for the given angles to be to belong to one triangle, the sum of all the angles must be equal to 180°

So, we check by adding them

37° + 111° + 32° = 180°

Hope this Helps!!!

My name is Nika and I need help in math I’m 73 and done with school but still don’t under algebra

Answers

The given equation is

[tex]2x-3=9[/tex]

To solve this equation we have to isolate x on one side and put the numbers on the other side

To do that we will add 3 to each side to move 3 from the left side to the right side

[tex]2x-3+3=9+3[/tex]

Simplify it

[tex]\begin{gathered} 2x+0=12 \\ 2x=12 \end{gathered}[/tex]

Now we need to move 2 from the left side to the right side, then

Divide both sides by 2

[tex]\begin{gathered} \frac{2x}{2}=\frac{12}{2} \\ x=6 \end{gathered}[/tex]

Then the solution of the equation is

x = 6

Other Questions
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