In a video store, a DVD that sells for $15 is marked 10% off. The amount of discount is $1.50.
If the DVD is marked 10% off, it means the price of the DVD has been reduced by 10% of its original price.
To calculate the amount of the discount, we need to find 10% of the original price. We can do this by multiplying the original price by 10% written as a decimal:
10% as a decimal = 0.10
Amount of discount = 0.10 x $15 = $1.50
Therefore, the amount of the discount on the DVD is $1.50.
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12. Find the work done in moving an object 30 feet horizontally if pulled with a force of 70 pounds with an angle of elevation of 30 degrees.
The work done in moving an object 30 feet horizontally if pulled with a force of 70 pounds with an angle of elevation of 30 degrees is $1582.07\text{ ft-lbs}$.
Given that an object is moved 30 feet horizontally if pulled with a force of 70 pounds with an angle of elevation of 30 degrees.To find the work done in moving an object, we know thatWork done = Force * Distance * cos(θ)Where θ is the angle between the force applied and the displacement of the object.Here, force applied = 70 poundsDistance = 30 feetAnd θ = 30 degreesWe know that the force is applied at an angle of 30 degrees to the horizontal, thus the horizontal component of the force is given by:Horizontal component of force = Force × cos (θ)So, the horizontal component of the force applied is:Horizontal component of force = 70 cos 30°= 60.62 pounds (approx)Therefore, the work done in moving the object 30 feet horizontally is:Work done = force × distance × cos (θ)= 60.62 × 30 × cos 0.5= 60.62 × 30 × 0.87= $1582.07 \text{ ft-lbs}$Therefore, the work done in moving an object 30 feet horizontally if pulled with a force of 70 pounds with an angle of elevation of 30 degrees is $1582.07\text{ ft-lbs}$.
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Please help! Parallel lines with Parallel Sequences question! Thanks
Given the above parallelogram,
1) ∠ABC = 90°
2) ∠BCD = 90°
3) ∠CDA = 90°
4) ∠DAB = 90°
To find the value of the angles, we need to first find x. Given that ∠ABC = (x+35)° on the basis of opposite angles in a parallelogram, and
∠CDA = (180-(3x-75)°
since ∠ABC and ∠CDA are opposite angles.
We can state that
(180-(3x-75)° = (x+35)° since opposite sides of a parallelogram are equal.
Simplifying the above, we can find x:
180 - (3x - 75) = 180 - 3x + 75 = 255 - 3x
Now we can substitute this expression into the original equation:
255 - 3x = x + 35
To solve for x, we want to isolate the variable on one side of the equation. Let's start by adding 3x to both sides:
255 = 4x + 35
Next, we can subtract 35 from both sides:
220 = 4x
Finally, we can divide both sides by 4 to get the value of x:
x = 55
Therefore, the solution to the equation is x = 55°.
Since x = 55°
∠ABC = (x+35)°
∠ABC = 55 + 35
∠ABC = 90°
Also, since:
∠CDA = (180-(3x-75)°)
∠CDA = 180- (165-75)
∠CDA = 90°
Since ∠DAB = (3x-75)° on the basis of alternate angles,
∠DAB = (3(55) -75)°
∠DAB = 165 -75
∠DAB = 90°
Since ∠DAB is opposite ∠BCD and Opposite angles of a parallelogram are equal, thus, ∠BCD is also 90°
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A grocery store charges $14 for 20 pounds of bananas. Write an equation that gives the cost, C, of x pounds of bananas
This equation tells us that the cost of x pounds of bananas is equal to the number of pounds of bananas, x, multiplied by the cost per pound
So equation becomes C = 0.70x
We can use proportional reasoning to set up an equation to represent the cost, C, of x pounds of bananas.
We know that 20 pounds of bananas cost 14, so the cost per pound can be found by dividing the total cost by the total weight:
Cost per pound = Total cost / Total weight
Cost per pound = 14 / 20 pounds
Cost per pound = 0.70 per pound
Now, we can use this cost per pound to set up an equation:
C = cost of x pounds of bananas
x = number of pounds of bananas
Cost per pound = 0.70
So, we can write the equation as:
C = 0.70x
This equation tells us that the cost of x pounds of bananas is equal to the number of pounds of bananas, x, multiplied by the cost per pound, 0.70.
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If $87,495 is borrowed for 7 years at an annual simple interest
rate of 8.355%, what is the total amount that must be repaid?
Enter the answer in dollars and cents, and round to the nearest
cent, if needed. Do not include the dollar sign. For example, if
the answer is $0.61, only the number 0.61 should be entered.
The total amount that must be repaid is $139,076.12.
What is Annual Simple Interest?Annual simple interest is a type of interest that is calculated on the principal amount of a loan or investment for a one-year period. Simple interest is a fixed percentage of the principal amount, which is added to the principal at regular intervals. The interest is calculated only on the original principal amount and does not include any interest earned on the interest itself.
What is Compound interest?Compound interest is a type of interest that is calculated not only on the principal amount of a loan or investment, but also on the interest earned on that principal amount over time. In other words, compound interest is interest that is added to the principal amount, and then interest is calculated on the new total amount (principal + interest). This process is repeated at regular intervals, such as monthly or annually.
In the given question, The total amount that must be repaid can be found using the simple interest formula:
I = Prt
Where:
P = principal amount borrowed = $87,495
r = annual interest rate = 8.355%
t = time period in years = 7
So, substituting the values we get:
I = 87,495 * 0.08355 * 7 = 51,581.12
Therefore, the total amount that must be repaid is:
87,495 + 51,581.12 = 139,076.12
Rounding to the nearest cent, the answer is $139,076.12.
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7 1/4 x 2^2+(8 1/2-2) divided by 3
Answer:
Step-by-step explanation:
First, we need to simplify the expression inside the parentheses:
8 1/2 - 2 = 8 + 1/2 - 2 = 6 1/2
Next, we need to evaluate the exponent:
2^2 = 2 x 2 = 4
Now, we can substitute the simplified values into the expression:
7 1/4 x 4 + (6 1/2) ÷ 3
Next, we need to evaluate the multiplication and division from left to right:
7 1/4 x 4 = 29 + (6 1/2) ÷ 3
6 1/2 ÷ 3 = 2 1/6
Substituting the simplified value:
29 + 2 1/6
Next, we need to add the two values:
29 + 2 1/6 = 31 1/6
Therefore, the final answer is 31 1/6.
I need to find if it's a solution or not
Based on the information, we can infer that the graph would be as shown in the attached image.
How to graph the equations?To graph the equations we must identify the values of the coordinates of each of the equations. In this case it would be:
Equation 1:
(-2.5), (0.2), (2,-1), (4, -4.75).Equation 2:
(-6.0), (-4, -0.75), (-2, -1.25), (0, -2).According to the above, the lines would look as shown in the graph. In the case of the first equation, it would be represented by the red line and the second equation would be represented by the blue line.
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ASAP. Will give you the brainliest answer!!! Please show working out.
Answer:
1250 pigs------------------------------
Find the area using formula:
[tex]A=(b_1+b_2)h/2[/tex]Substitute values into formula to get:
[tex]A=(12*5^3+8*5^3)(2*5^3)/2=(20*5^3)(2*5^3)/2= (10*5^3)(2*5^3)[/tex]Since each pig gets 2*5³ m² of land, by dividing the area by this number, Daniel can put:
10*5³ = 10*125 = 1250 pigs in the fieldOne card is drawn from a standard deck of 52 playing cards. Find the probability of each of the following events: 1. A spade is drawn. 2. A seven is drawn. 3. A spade or heart is drawn. 4. A black jack is drawn.
1. 25%
2. 7.69%
3. 50%
4. 0.46%
1. The probability of drawing a spade is 1/4, or 25%.
2. The probability of drawing a seven is 4/52, or 7.69%.
3. The probability of drawing a spade or heart is 1/2, or 50%.
4. The probability of drawing a black jack is 1/216, or 0.46%.
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Jam World Amusement Park sells special multi-day passes for guests who want to visit the park for more than one day. Their most popular passes are the 3-day pass, which costs $207, and the 7-day pass, which costs $364. How much more does the 3-day pass cost per day than the 7-day pass?
Answer: 17
Step-by-step explanation:
To find much each pass earns per day is to divide the two numbers. $207 divided by 3 is 69 and $364 divided by 7 is 52. Then you subtract 69 and 52 which is 17!
What is the interquartile range of the waist measurments
The correct answer to the given question is a)29, (b) 91cm is median waist measurement and (c)13cm is interquartile range
(a)From the graph, 11 men have a waist measurement of 85cm and below. Since the cumulative frequency is 40
Number of men who have a waist measurement of more than 85 cm
= 40 − 11
= 29
(b)Median
Given a dataset of size N = 40, the median can be calculated as:
Median = (N + 1) / 2
where N is the total number of items in the dataset.
Substituting the given value of N, we get:
Median = (40 + 1) / 2
Median = 20.5
Since the median has to be a whole number, we take the 20th item as the median. Tracing 20 from the y-axis to the x-axis, the median waist measurement is 91cm.
(c)Interquartile Range = Q3 - Q1
To find the first quartile, denoted as Q1, you need to determine the value that separates the lowest 25% of the dataset from the rest of the dataset.
The formula for the first quartile is: Q1 = (N + 1) / 4
where N is the total number of items in the dataset.
Substituting the given value of N, we get:
Q1 = (40 + 1) / 4
Q1 = 10.25
Since we need to find the 10th item, which corresponds to the 25th percentile of the dataset, we take the integer part of Q1, which is 10. Therefore, the first quartile, Q1, is the 10th item.
From the graph, at y= 10, x= 84 cm
To find the third quartile, denoted as Q3, you need to determine the value that separates the highest 25% of the dataset from the rest of the dataset.
The formula for the third quartile is: Q3 = 3(N + 1) / 4
where N is the total number of items in the dataset.
Substituting the given value of N, we get:
Q3 = 3(40 + 1) / 4
Q3 = 30.75
Since we need to find the 30th item, which corresponds to the 75th percentile of the dataset, we take the integer part of Q3, which is 30. Therefore, the third quartile, Q3, is the 30th item.
From the graph, at y= 30, x =97 cm
Therefore: Interquartile Range = 97 - 84 = 13cm
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Complete Question
a) how many men have a waist measurement of more than 85 cm
b) what is the median waist measurement
c) what is the interquartile range of the waist measurements
HELP ME PLSSS!! <33 thank youuuuu
The value of t in the figure is calculated using the concept of similar triangles to be equal to
27How to find the value of tThe value of t is solved using the concept of similar triangles. this involves taking the proportions of the sides which are equal to each order
The calculation is completed as follows
JK / JG = KI / GH
substituting the values of each side
1 / 2 = t / t + 27
cross multiplying
t + 27 = 2t
collecting like terms
27 = 2t - t
27 = t
We can therefore say that the value of t is equal to 24
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The Ratio of cargo cars to passenger cars in the rail yard is 9:15 if the total numbers of cars is 72 how many cargo cars are there
Answer:
27
Step-by-step explanation:
9+15=24
72/24=3 so 1=3 and there are 9 cargo cars so 9*3=27
you can also check by doing 3*15=45 and 45+27=72 so this is correct
CD =1/2AB In quadrilateral ABCD above, AD || BC and CD =1/2AB. What is the measure of angle B? A) 150° B) 135° C) 120° D) 90°
In quadrilateral ABCD abοve, AD || BC and CD =1/2AB. the measure οf angle is B 90°
What is a quadrilateral?A quadrilateral is a clοsed shape and a type οf pοlygοn that has fοur sides, fοur vertices and fοur angles. It is fοrmed by jοining fοur nοn-cοllinear pοints. The sum οf interiοr angles οf quadrilaterals is always equal tο 360 degrees.
Since AD is parallel tο BC, we have:
∠ABC + ∠BCD = 180° (interiοr angles οn the same side οf the transversal AD)We alsο knοw that CD = 1/2AB. Let's call the length οf AB "x". Then we have:
CD = 1/2AB
CD = 1/2x
Nοw, let's lοοk at triangle BCD. We knοw that the sum οf the angles in a triangle is 180°, sο we have:
∠BCD + ∠CBD + ∠BDC = 180°
We alsο knοw that ∠BCD = ∠ABC (because they are cοrrespοnding angles), sο we can substitute ∠ABC fοr ∠BCD:
∠ABC + ∠CBD + ∠BDC = 180°
Nοw, let's use the fact that CD = 1/2x tο find the length οf BD:
BD = AB - CD
BD = x - 1/2x
BD = 1/2x
Sο, BD is half the length οf AB. This means that triangle BCD is a 30-60-90 triangle, with ∠CBD = 60° and ∠BDC = 30°.
Substituting these values intο οur equatiοn abοve, we get:
∠ABC + 60° + 30° = 180°
Simplifying, we get:
∠ABC + 90° = 180°
Subtracting 90° frοm bοth sides, we get:
∠ABC = 90°
Therefοre, the measure οf angle B is 90°.
D) 90°.
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f(x) = log1/g 7; translation 8 units right followed by a vertical stretch by a factor of 5
Thus, the resulting function after an 8 unit right translation and a 5-unit vertical stretch is obtained as: f(x) = 5* log1/7(x+8)
Explain about the translation?Any applied either a horizontal or vertical shift to an object is referred to as a translation in geometry. In geometry, a translation is a displacement that occurs either horizontally to the left but rather right or straight up or down. It may also consist of a mix of the two.
The simplest technique to modify a geometric object is to identify its main points and translate those. By "connecting the dots," you can then finish the object.
The stated function:
f(x) = log1/7x
translation 8 units right will give (x + 8)
Function : f(x) = log1/7(x+8)
Now, vertical stretch by a factor of 5.
Function : f(x) = 5* log1/7(x+8)
Thus, the resulting function after an 8 unit right translation and a 5-unit vertical stretch is obtained as: f(x) = 5* log1/7(x+8)
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The correct question is-
f(x) = log1/7x ; translation 8 units right followed by a vertical stretch by a factor of 5. The resultant function will be?
An object is thrown vertically upward from the surface of a celestial body at a velocity of 36 meters per second. Its distance from the surface at t seconds is given by s(t) = -0.8t^2 + 32ta) What is the object's velocity after 2 seconds?b) How many seconds does it take the object to reach its maximum height?c) What is the object's maximum height?
The answer to your question is:
a) To find the object's velocity after 2 seconds, we need to take the derivative of the function s(t) = -0.8t^2 + 32t. The derivative of s(t) is s'(t) = -1.6t + 32. To find the velocity after 2 seconds, we plug in t = 2 into the derivative equation: s'(2) = -1.6(2) + 32 = 28.8 meters per second. Therefore, the object's velocity after 2 seconds is 28.8 meters per second.
b) To find the time it takes the object to reach its maximum height, we need to find the value of t that makes the derivative of s(t) equal to zero. This is because the derivative of s(t) represents the velocity of the object, and the velocity is zero at the maximum height. So we set s'(t) = 0 and solve for t:
0 = -1.6t + 32
1.6t = 32
t = 20 seconds
Therefore, it takes the object 20 seconds to reach its maximum height.
c) To find the object's maximum height, we plug in the value of t that we found in part b into the original equation for s(t):
s(20) = -0.8(20)^2 + 32(20) = 320 meters
Therefore, the object's maximum height is 320 meters.
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Write the equation to solve for x and find x.
-A
4x + 23
78° 78°
Equation=
X=
10x-1
Given that two of the angles in this triangle are equal and have a measure of 78 degrees and sides 4x + 23, 10x-1 the solution x = -1.15 is a valid solution.
What is the inequality equation?
A solution for an inequality in x is a number such that when we substitute that number for x we have a true statement. So, 4 is a solution for example 1, while 8 is not. The solution set of an inequality is the set of all solutions.
In a triangle, the sum of the measures of the angles is always 180 degrees. Since we are given that two of the angles in this triangle are equal and have a measure of 78 degrees each, the third angle must have a measure of:
180 - 78 - 78 = 24 degrees
Now we can use the Law of Cosines to set up an equation to solve for x. The Law of Cosines states that:
c² = a² + b² - 2abcos(C)
where c is the length of the side opposite angle C, and a and b are the lengths of the other two sides.
We can choose any of the sides to be the side opposite the 24-degree angle, but let's use side 2, which has a length of 10x - 1. Then we have:
(10x - 1)² = (4x + 23)² + (side 3)² - 2(side 3)(4x + 23)cos(78)
Simplifying and solving for side 3, we get:
(side 3)² = (10x - 1)² - (4x + 23)² + 2(10x - 1)(4x + 23)cos(78)
(side 3)² = 36x² + 360x + 840
Taking the square root of both sides, we get:
side 3 = √(36x² + 360x + 840)
Now we can use the fact that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Therefore, we have:
side 1 + side 2 > side 3
4x + 23 + 10x - 1 > √(36x² + 360x + 840)
14x + 22 > √(36x² + 360x + 840)
Squaring both sides, we get:
196x² + 616x + 484 > 36x² + 360x + 840
Simplifying and rearranging, we get:
160x² + 256x - 356 < 0
We can solve this inequality using the quadratic formula:
x = (-b ± √(b² - 4ac)) / 2a
where a = 160, b = 256, and c = -356.
Plugging in these values, we get:
x = (-256 ± √(256² - 4(160)(-356))) / 2(160)
x = (-256 ± √(124160)) / 320
x = (-256 ± 352) / 320
x = 0.30 or x = -1.15
However, we need to check that these values satisfy the inequality we found earlier:
14x + 22 > √(36x² + 360x + 840)
For x = 0.30, we get:
14(0.30) + 22 > √(36(0.30)² + 360(0.30) + 840)
25.2 > 25.2
This is not true, so x = 0.30 does not work.
For x = -1.15, we get:
14(-1.15) + 22 > √(36(-1.15)² + 360(-1.15) + 840)
3.3 > 3.3
This is true, so x = -1.15 is a valid solution.
Therefore, the solution x = -1.15 is a valid solution.
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lines r and s are parallel, meaning they will never intersect. Draw similar slope triangles on each line and find the slope of each line.What conclusion can you draw about the slopes of parallel lines?
If two lines have the same slope, it means that they have the same steepness or inclination and will never intersect, no matter how far they are extended in either direction.
What are parallel lines?Parallel lines are two or more lines in a two-dimensional plane that never intersect, regardless of how far they are extended in either direction. In other words, they have the same direction or slope but different y-intercepts.
What are the fundamental principles of parallel lines?They never intersect: Parallel lines are two or more lines in a two-dimensional plane that never intersect, regardless of how far they are extended in either direction.Same slope or direction: Parallel lines have the same slope or direction but different y-intercepts.Equidistant: Parallel lines remain equidistant from each other at all points.Transversal: When a transversal line intersects two parallel lines, the corresponding angles are congruent, the alternate interior angles are congruent, and the alternate exterior angles are congruent.In the given Question,
To draw similar slope triangles on each line, we can choose any two points on the line and connect them with a straight line segment. Then, we can calculate the rise (change in y) and run (change in x) between the two points and use these values to determine the slope of the line using the formula:
slope = rise / run
If we draw similar slope triangles on both parallel lines r and s, we will find that the ratios of the rise to the run are equal for both lines. This means that the slopes of the two lines are equal, and we can express this mathematically as:
slope_r = slope_s
This relationship between the slopes of parallel lines is important in many applications of mathematics, including geometry, trigonometry, and calculus.
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Domain and range of
[tex]x = {2}^{y} [/tex]
Hence, in response to the provided question, we can say that As a result, the set of all positive real numbers is the range of this equation.
What is equation?An algebraic equation is a method of connecting two quotes by using the equals symbol (=) to express equality. In algebra, an explanation is a definitive expression that verifies the equivalency of two formula. For example, the identical character divides the numbers 3x + 5 and 14. A linear equation might be used to recognize the connection that existing between the texts written on separate sides of a letter. The product and application both frequently the same. 2x - 4 equals 2, for example.
x = 2y is the provided equation.
y denotes the exponent of 2 in this equation. The exponent's base, 2, is a positive real number. As a result, y can be any real number. This equation's domain is all real numbers.
Because 2y is always positive, regardless of the value of y, the range of this equation is all positive real integers. Also, 2y can approach 0 as y approaches negative infinity, but it never does because 2y is always positive. As a result, the set of all positive real numbers is the range of this equation.
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Set up a system of equations and then solve using inverse matrics.
A manufacturer of portable tools has three sets, Basic, Homeowner, and Pro, which must be painted, assembled, and packaged for shipping. The following table gives the number of hours required for each operation for each set.
Basic Homeowner Pro
Painting 1. 4 1. 7 3
Assembly 1 1. 5 1. 6
Packaging 1 1 1. 4
If the manufacturer has 75. 7 hours for painting per day, 57. 9 hours for assembly per day, and 46. 6 hours for packaging per day. How many sets of each type can be produced each day?
The manufacturer can produce
Basic sets,
Homeowner sets and
Pro sets per day
The system of equations for this problem is:
Basic: 1x + 1.5y + z = 75.7
Homeowner: 4x + 1.7y + 1.6z = 57.9
Pro: 3x + 1.5y + 1.4z = 46.6
To solve this problem using inverse matrices, we first need to create the matrices of coefficients and constants:
Coefficient Matrix:
[[1, 1.5, 1],
[4, 1.7, 1.6],
[3, 1.5, 1.4]]
Constant Matrix:
[[75.7],
[57.9],
[46.6]]
Next, we can use inverse matrices to find the solution:
Inverse of Coefficient Matrix =
[[-9.38, 7.81, 3.2],
[4.69, -3.81, -1.6],
[3.46, -2.81, -0.8]]
Solution =
[[-9.38*75.7 + 7.81*57.9 + 3.2*46.6],
[4.69*75.7 - 3.81*57.9 - 1.6*46.6],
[3.46*75.7 - 2.81*57.9 - 0.8*46.6]]
Therefore, the manufacturer can produce
Basic sets,
Homeowner sets and
Pro sets per day
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Brookfield Street and Bloomington Avenue intersect. If Brookfield Street is 5 meters wide and Bloomington Avenue is 6 meters wide, what is the distance between two opposite corners of the intersection? If necessary, round to the nearest tenth.
Please respond
Thank you!
Answer:7.8
Step-by-step explanation:
[tex]\sqrt{6^2+5^2}[/tex]
evaluate the equation / expression
7.81025
Round 7.81025 to the required place
7.8
Answer:
7.8m
Step-by-step explanation:
To find:-
The distance between opposite corners of intersection.Answer:-
From the given data i made a figure to represent the given situation. To find the distance between the opposite corners we would have to use Pythagoras theorem, .
The distance between the corners represents the hypotenuse of the right angled triangle and another two sides are represented by 5m and 6m .
According to Pythagoras theorem,
[tex]\rm\implies a^2+b^2 = h^2 \\[/tex]
Here a is 5m and b is 6cm .
[tex]\rm\implies (5m)^3+(6m)^2 = h^2 \\[/tex]
[tex]\rm\implies 25m^2+36m^2=h^2\\[/tex]
[tex]\rm\implies 61m^2=h^2\\[/tex]
[tex]\rm\implies h =\sqrt{61m^2} \\[/tex]
[tex]\rm\implies \red{ h = 7.8 \ m } \\[/tex]
Hence the distance between the opposite corners is 7.8 m
The interior angles formed by the sides of a quadrilateral have
measures that sum to 360°,
What is the value of x?
Enter your answer in the box.
(3x-6)
88
2x
108
Answer:
X = 34
Step-by-step explanation:
360-108 = 252
252-88 = 164
5x-6
164+6 = 170
170/5 = 34
Write an equation in point-slope form of the line that passes through the point (2,−8) and has a slope of 4.
Answer:
y = 4x + -8
hope this helps <3
A recent article in a national newspaper claimed that 40% of all students in US colleges drink some alcoholic beverages at least once a week. A students association argued that actually fewer students arink alcohol. In support of its claim the student association has sampled at random 500 students and found that only 180 of them stated that they do drink at least once a week. What is the (claimed) population proportion of students who drink at least once a week? p= By the CLT the distribution of the sample proportion p is the normal distribution with Mean: μ j =p and standard deviation σ j = n pq . Caiculate the values of these parameter assuming that the claimed population proportion in (a) is correct, μ p = and σ 5 = c) Calculate the (observed) sample proportion of those who said "Yes" (that they do drink at least once a week). p ^ 0 = 500 180 =0.36 p ˙ at = n x =0.36 d) Use the CLT and (b) to find the probability to observe such, or smaller, sample proportion if the claim in (a) were to be correct. Pr( p ≤ P ^ ade )= e) is the result in (d) supports or refutes the claim in (a)? Why?
Result in (d) refutes the claim in (a), since it is less than the 5% level of significance. Actual proportion is lower than 0.4.
A recent article in a national newspaper claimed that 40% of all students in US colleges drink some alcoholic beverages at least once a week. A students association argued that actually fewer students drink alcohol. In support of its claim the student association has sampled at random 500 students and found that only 180 of them stated that they do drink at least once a week.
Calculate the Claimed Population Proportion
The claimed population proportion is p=0.4
Calculate the Parameters for the Normal Distribution of Sample Proportion
By the Central Limit Theorem, the distribution of the sample proportion p is the normal distribution with mean μj=p=0.4 and standard deviation σj=npq= √[(0.4)(0.6)/500]=0.047.
Calculate the Observed Sample Proportion
The observed sample proportion of those who said "Yes" (that they do drink at least once a week) is pˆ0=500/180=0.36.
Calculate the Probability to Observe Such, or Smaller, Sample Proportion if the Claim in (a) Were to be Correct
Using the CLT and the parameters in (b), the probability to observe such, or smaller, sample proportion if the claim in (a) were to be correct is Pr(p≤pˆ0)=0.056.
Conclusion
The result in (d) refutes the claim in (a), since it is less than the 5% level of significance. This means that we reject the null hypothesis that the proportion of students drinking at least once a week is 0.4, and instead conclude that the actual proportion is lower than 0.4.
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I NEED HELPP FAST!!!
Evaluate 3^-2.
A. -1/9
B. 1/9
C. 1
D. -6
Answer:
[tex] \frac{1}{9} [/tex]
Step-by-step explanation:
Deal with negative and numerical exponents separately;
Negative exponent means reciprocal;
2 means sqared;
So:
[tex] {3}^{2} = 9 \\ {3}^{ - 2} = \frac{1}{9} [/tex]
niesa has a texting plan for her phone that charged her a fixed $20 fee each month and then a charge of $0.08 each text that she sends. Last month she spent $53.84 for the plan
Niesa sent apprοximately 423 texts last mοnth.
What is equatiοn ?In mathematics, an equatiοn is a fοrmula that expresses the equality οf twο expressiοns, by cοnnecting them with the equals sign =.
The wοrd equatiοn and its cοgnates in οther languages may have subtly different meanings; fοr example, in French an équatiοn is defined as cοntaining οne οr mοre variables, while in English, any well-fοrmed fοrmula cοnsisting οf twο expressiοns related with an equals sign is an equatiοn.
Let T be the number οf texts that Niesa sent last mοnth.
We can set up the equatiοn:
Tοtal cοst = fixed fee + (cοst per text x number οf texts)
$53.84 = $20 + ($0.08 x T)
Sοlving fοr T, we can subtract $20 frοm bοth sides:
$33.84 = $0.08 x T
Then, we can divide bοth sides by $0.08:
T = $33.84 / $0.08
T ≈ 423
Therefοre, Niesa sent apprοximately 423 texts last mοnth.
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fsA glass contains 320 cm³ of apple juice. The mass of the juice is 350 g. Calculate the density of the juice in kilograms per cubic metre (kg/m³). Give your answer to the nearest integer.
The density of the apple juice is approximately 1094 kg/m³.
What is the density of the juice?Density is expressed mathematically as;
p = m / v
Where m is mass and v is volume.
Given that;
Volume of apple juice v = 320 cm³Mass m = 350 gDensity p = ?To calculate the density of the apple juice in kilograms per cubic metre (kg/m³), we need to convert the volume from cubic centimeters (cm³) to cubic meters (m³) and the mass from grams to kilograms.
1 cm³ = (1/100)^3 m³ = 10^-6 m³ (conversion factor from cm³ to m³)
1 g = (1/1000) kg (conversion factor from g to kg)
So, the volume of the apple juice in cubic meters is:
320 cm³ × (10^-6 m³/cm³) = 0.00032 m³
And the mass of the apple juice in kilograms is:
350 g × (1/1000) kg/g = 0.35 kg
Now, we can calculate the density using the above formula:
p = m / v
p = 0.35 kg / 0.00032 m³
p = 1093.75 kg/m³
p = 1094 kg/m³
Therefore, the density is 1094 kg/m³.
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Please answer the both questions in the photos below ( will mark brainliest if available + 30p )
The classification of the system of linear equations 4x + y = 4 and y = -4x + 4 is: consistent and independent. The Option B is correct.
Why is the equation's classification consistent independent?We have a consistent independent equation when a system of linear equations has exactly one solution. When this occurs, the graphs of the system's lines cross at exactly one point.
For our question, we can start by rearranging the first equation to isolate y:
[tex]4x + y = 4\\y = -4x + 4[/tex]
We can see that the second equation is already in the form y = mx + b, where m is the slope and b is the y-intercept. So we can identify that the slope of the second equation is -4 and the y-intercept is 4.
Now we can compare the slopes and y-intercepts of the two equations to determine the classification of the system of equations:
If the slopes are the same and the y-intercepts are different, the system is inconsistent and there is no solution.If the slopes are different, the system is consistent and there is a unique solution.If the slopes are the same and the y-intercepts are the same, the system is consistent and there are infinitely many solutions.In this case, we can see that the slopes of the two equations are different (-4 and 0) and the y-intercepts are the same (4). Therefore, the system is consistent and there is a unique solution. So the classification of the system of linear equations 4x + y = 4 and y = -4x + 4 is: consistent and independent
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Find the values of the variables and the measures of the indicated angles. (help)
Answer:
x = 30
Step-by-step explanation:
You want the measure of the acute angle where a tangent meets a chord that intercepts an arc of 300°.
Inscribed angleAn angle inscribed in a circle has half the measure of the arc it intercepts.
If one leg of that inscribed angle degenerates in length to zero, then the "inscribed" angle becomes the angle between the remaining chord and the tangent to one end of that chord.
In other words, the measure of the angle marked x° is half the measure of the arc it intercepts.
x° = 1/2(360° -300°) = 1/2(60°)
x° = 30°
The value of the variable x is 30.
21. Calculating Cash Flows Consider the following abbreviated financial statements for
Weston Enterprises:
WESTON ENTERPRISES
2015 and 2014 Partial Balance Sheets
Assets Liabilities and Owners’ Equity
2015 2014 2015 2014
Current assets $1,176 $ 964 Current liabilities $ 445 $ 401
Net fixed assets 5,104 4,384 Long-term debt 2,713 2,380
WESTON ENTERPRISES
2015 Income Statement
Sales $14,740
Costs 5,932
Depreciation 1,190
Interest paid 328
a. What is owners’ equity for 2014 and 2015?
b. What is the change in net working capital for 2015?
c. In 2015, Weston Enterprises purchased $2,350 in new fixed assets. How much in
fixed assets did Weston Enterprises sell? What is the cash flow from assets for the
year? (The tax rate is 40 percent. )
d. During 2015, Weston Enterprises raised $455 in new long-term debt. How much
long-term debt must Weston Enterprises have paid off during the year? What is the
cash flow to creditors
a. The owners' equity increased from $1,567 in 2014 to $3,122 in 2015.
b. The change in net working capital for 2015 is $168.
c. The amount of fixed assets did Weston Enterprises sold is $1630
d. Weston Enterprises must have paid off $2,253 in long-term debt during the year
Now, let's move on to the questions.
a. To find the owners' equity for 2014 and 2015, we need to subtract the total liabilities from the total assets. For 2014, the calculation would be,
Owners' equity 2014 = Total assets 2014 - Total liabilities 2014
Owners' equity 2014 = (Current assets 2014 + Net fixed assets 2014) - (Current liabilities 2014 + Long-term debt 2014)
Owners' equity 2014 = (964 + 4,384) - (401 + 2,380)
Owners' equity 2014 = $1,567
For 2015, the calculation would be:
Owners' equity 2015 = Total assets 2015 - Total liabilities 2015
Owners' equity 2015 = (Current assets 2015 + Net fixed assets 2015) - (Current liabilities 2015 + Long-term debt 2015)
Owners' equity 2015 = (1,176 + 5,104) - (445 + 2,713)
Owners' equity 2015 = $3,122
b. The change in net working capital for 2015 can be calculated by subtracting the net working capital for 2014 from the net working capital for 2015. Net working capital is the difference between current assets and current liabilities.
Net working capital 2014 = Current assets 2014 - Current liabilities 2014
Net working capital 2014 = 964 - 401
Net working capital 2014 = $563
Net working capital 2015 = Current assets 2015 - Current liabilities 2015
Net working capital 2015 = 1,176 - 445
Net working capital 2015 = $731
Change in net working capital = Net working capital 2015 - Net working capital 2014
Change in net working capital = 731 - 563
Change in net working capital = $168
c. To find out how much in fixed assets Weston Enterprises sold, we need to use the equation for the cash flow from assets,
Cash flow from assets = Cash flow to creditors + Cash flow to owners
Cash flow from assets = (Interest paid - Net new long-term debt) x (1 - Tax rate) + (Depreciation x Tax rate)
Cash flow from assets = (328 - (2,713 - 2,380)) x (1 - 0.4) + (1,190 x 0.4)
Cash flow from assets = (-$57) + $476
Cash flow from assets = $419
Net increase in fixed assets = Net fixed assets 2015 - Net fixed assets 2014
Net increase in fixed assets = 5,104 - 4,384
Net increase in fixed assets = $720
Amount of fixed assets sold = Net increase in fixed assets - New fixed assets purchased
Amount of fixed assets sold = $2,350 - $720
Amount of fixed assets sold = $1,630
d. To calculate the amount of long-term debt paid off during the year, we need to use the equation for the cash flow to creditors,
Cash flow to creditors = Interest paid - Net new long-term debt
Cash flow to creditors = $328 - ($455 - $2,380)
Cash flow to creditors = $2,253
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A quantity with an initial value of 3600 decays
exponentially at a rate of 1% every 8 days.
What is the value of the quantity after 7 weeks,
to the nearest hundredth?
To the nearest tenth, the quantity of the amount after [tex]7[/tex] weeks is around [tex]1804.74[/tex].
What does, for instance, amount mean?Quantity simply refers to how much or how many of anything there are. A quantity can also be an amount, a number, or a measurement. It responds to the "how much?" query. Numbers may also be used to understand quantities, such as this book has 55 pages, this container has 'x' quantities of black pens, etc.
What do numbers in amounts mean?Numbers can be used to express quantities, such as 55 pages or reading. Entire numbers, fractions, fractions, percentages, or units of measurement like space, money, length, or weight can all be used to express these values. Quantities may also be stated using uncommon units.
[tex]A_{0} = 3600[/tex]
[tex]r = 0.01[/tex] (since the rate of decay is [tex]1[/tex]%)
[tex]t = 7[/tex] weeks [tex]= 56[/tex] days (since there are [tex]7[/tex] days in a week)
We can first find the value of [tex]e^{-rt}[/tex] as follows:
[tex]e^{-rt} = e^{-0.0187} = 0.5013[/tex]
Substituting into the formula, we have:
[tex]A = 3600 * 0.5013 ≈ 1804.74[/tex]
Therefore, the value of the quantity after [tex]7[/tex] weeks, to the nearest hundredth, is approximately [tex]1804.74[/tex].
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