Answer:
1.glass
2.tungstan is going to expire
3.bulb is fuse
4.led
. We __________ fossil fuels, which releases carbon into the atmosphere.
Answer:
burn
Explanation:
we burn fossil fuels, which releases carbon into the atmosphere
Answer:
polution
Explanation:
if the global of earth all polution in earth so,use electric bike
Please help and write full solution
The pH of the solution is 1.8. Option C is the right answer
How The answer was obtainedFirst, we need to calculate the moles of LiOH and HNO3:
Moles of LiOH = 0.1 mol/L × 0.025 L = 0.0025 mol
Moles of HNO3 = 0.1 mol/L × 0.035 L = 0.0035 mol
Next, we need to determine which of the reactants will be limiting. LiOH and HNO3 react in a 1:1 stoichiometric ratio, so whichever reactant is present in the smaller amount will be limiting. In this case, LiOH is limiting because it has fewer moles than HNO3.
The balanced chemical equation for the reaction between LiOH and HNO3 is:
LiOH + HNO3 → LiNO3 + H2O
Since LiOH is limiting, all of it will react with HNO3. This means that all of the moles of HNO3 will be consumed, and there will be some excess LiOH remaining.
Moles of LiOH remaining = Moles of LiOH - Moles of HNO3 = 0.0025 mol - 0.0035 mol = -0.0010 mol
Note that the result is negative, which means that all of the HNO3 has been consumed, and there is still some LiOH remaining.
The concentration of LiOH in the final solution is:
[LiOH] = Moles of LiOH remaining / Total volume of solution = -0.0010 mol / (0.025 L + 0.035 L) = -0.010 mol/L
Again, the result is negative, which is not physically meaningful. This indicates that our assumption that LiOH is limiting is incorrect.
To correct this, we can assume that HNO3 is limiting and repeat the calculations. In this case, all of the HNO3 will react with LiOH, and there will be some excess HNO3 remaining.
Moles of HNO3 remaining = Moles of HNO3 - Moles of LiOH = 0.0035 mol - 0.0025 mol = 0.0010 mol
The concentration of HNO3 in the final solution is:
[HNO3] = Moles of HNO3 remaining / Total volume of solution = 0.0010 mol / (0.025 L + 0.035 L) = 0.01 mol/L
The balanced chemical equation for the reaction between HNO3 and LiOH is:
HNO3 + LiOH → LiNO3 + H2O
The stoichiometry of this reaction tells us that one mole of HNO3 reacts with one mole of LiOH to produce one mole of water. Therefore, the moles of water produced in the reaction are equal to the moles of HNO3 remaining:
Moles of water = 0.0010 mol
The volume of the final solution is:
Volume = 0.025 L + 0.035 L = 0.06 L
The molarity of the water in the final solution is:
Molarity of water = Moles of water / Volume of solution = 0.0010 mol / 0.06 L = 0.0167 mol/L
The pH of water is 7.0, and the pH of a solution is related to the concentration of H+ ions in the solution. Since water is neutral and does not contribute any H+ ions, the pH of the final solution is:
pH = 7.0 - log[H+] = 7.0 - log(0.0167) ≈ 1.8
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Determine the pH of the solution when 25ml of 0.1mLiOH is added to 35ml of 0.1m nitric acid
(A) 0.23
(B) 0.47
(C) 1.8
(D) 7.0
Please answer all questions <3
10) If Reaction B (above) was at equilibrium and then was heated ____________ CH3OH would be present after the reaction adjusts to the new temperature.
more
less
the same amount of
11) If Reaction B (above) was at equilibrium and then the pressure in its container was increased, ____________ CH3OH would be present after the reaction adjusts to the new pressure.
more
less
the same amount of
12) If Reaction B (above) was at equilibrium and then H2 was added, ____________ CH3OH would be present after the reaction adjusts.
more
less
the same amount of
13) If Reaction B (above) was at equilibrium and then H2 was added, ____________ CO would be present after the reaction adjusts.
more
less
the same amount of
Answer:
10. methanol would be more.
11. methanol would be more.
12. methanol would remain the same.
13. CO would be less.
Explanation:
10. Methanol increases because the forward reaction is favoured with increase in temperature and thus it is endothermic.
11. Methanol increases because the forward reaction is favoured with decrease in volume thus increasing pressure decreases the volume of the vessel.
12.Methanol remains the same because the hydrogen added is its raw material but the CO is acting as a limiting reactant for the formation of methanol.
13. Carbon monoxide becomes less because it will rapidly combine with hydrogen added to form methanol and then later be a limiting reactant when hydrogen is still present
60cm3 of carbon (||) oxide,(co) are sparked with 30cm3 of oxygen if all the volumed of the gases are measured at s.t.p. calculate the volume of the residual gases after sparking
Answer:
We can begin by using the balanced chemical equation for the reaction between carbon monoxide and oxygen:
2CO + O2 -> 2CO2
This tells us that 2 volumes of CO react with 1 volume of O2 to produce 2 volumes of CO2. Since we have equal volumes of CO and O2, the limiting reactant will be the one that requires more volume, which is the CO:
2 volumes of CO + 1 volume of O2 -> 2 volumes of CO2
Using the ideal gas law, we can convert the volumes of CO and O2 at STP (standard temperature and pressure, which is 0°C and 1 atm) to moles:
n(CO) = V(CO) / Vm = 60 cm3 / 22.4 L/mol = 0.00268 mol
n(O2) = V(O2) / Vm = 30 cm3 / 22.4 L/mol = 0.00134 mol
Since 2 volumes of CO react with 1 volume of O2, we can say that the reaction will use up 2 x 0.00134 = 0.00268 mol of O2. Since we have 0.00134 mol of O2 initially, this means that all of the O2 will be used up in the reaction, leaving none in the residual gases. The reaction will also produce 2 x 0.00268 = 0.00536 mol of CO2.
Using the ideal gas law again, we can convert the volume of CO2 produced to a volume at STP:
V(CO2) = n(CO2) x Vm = 0.00536 mol x 22.4 L/mol = 0.120 cm3
Therefore, the volume of residual gases after the reaction is:
V(residual) = V(total) - V(CO) - V(O2) - V(CO2) = 90 cm3 - 60 cm3 - 30 cm3 - 0.120 cm3 = 0.880 cm3
The carboxylic acid contains six carbons and the starting material should be an alkyl halide of five carbons or less, so you should look for a method of generating carboxylic acids by adding a carbon. One method of synthesizing carboxylic acids is from the hydrolysis of nitriles, which can be formed by substitution of alkyl halides. Identify the structure that contains a nitrile. RCH=CHNH, OCH,CEN OCH,CH=NH OCH,CH, NH
The synthesis of carboxylic acid can be done by hydrolysing the nitrile which is substituted in place of halide by using cyanide ion. The structure that contains a nitrile is OCH2C≡N.
A nitrile is an organic compound that contains a carbon triple bonded to a nitrogen atom.
The general formula for a nitrile is R–C≡N, where R is an alkyl or aryl group. In the structure OCH2C≡N, the OCH2 group is the alkyl group and the C≡N is the nitrile functional group. Therefore, this structure contains a nitrile.
To synthesize a carboxylic acid from an alkyl halide, you can first convert the alkyl halide to a nitrile through a substitution reaction with a cyanide ion. The nitrile can then be hydrolyzed to form a carboxylic acid. The overall reaction is:
R–X + CN– → R–C≡N → R–COOH
Where R is an alkyl or aryl group, X is a halogen, and CN– is a cyanide ion.
In conclusion, the structure that contains a nitrile is OCH2C≡N and it can be used to synthesize a carboxylic acid from an alkyl halide through a substitution reaction followed by hydrolysis.
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what is the mass of 29.3 L of carbon monoxide at STP?
hey guys.. show. work.. i have no idea whats going on
Answer:
33.67g
Explanation:
To calculate the mass of carbon monoxide, we can use the ideal gas law, which relates the pressure, volume, number of moles, and temperature of a gas:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
At STP (standard temperature and pressure), the pressure is 1 atm and the temperature is 273.15 K. The ideal gas constant is R = 0.08206 L atm/(mol K).
To find the number of moles of carbon monoxide in 29.3 L at STP, we can rearrange the ideal gas law to solve for n:
n = PV/(RT)
n = (1 atm)(29.3 L)/(0.08206 L atm/(mol K) * 273.15 K)
n = 1.203 mol
The molar mass of carbon monoxide (CO) is 28.01 g/mol. Therefore, the mass of 1.203 mol of CO is:
mass = n * molar mass
mass = 1.203 mol * 28.01 g/mol
mass = 33.67 g
Therefore, the mass of 29.3 L of carbon monoxide at STP is approximately 33.67 grams.
Can someone please help with this chemistry question
If 9.7 mol of CO₂ are produced, 14.55 moles of O₂ were reacted.
In chemistry, a mole is a unit of measurement that represents an amount of substance. This number of entities is known as Avogadro's number, which is approximately equal to 6.02 x 10^23.
The mole is a convenient unit for measuring the amount of substance in chemical reactions, because it allows chemists to predict and calculate the quantities of reactants and products involved in a chemical reaction. For example, if we know the balanced chemical equation for a reaction, we can use the stoichiometry of the reaction to determine the amount of reactants needed to produce a given amount of product, or the amount of product that can be produced from a given amount of reactants.
The balanced chemical equation for the combustion of ethylene (C2H4) in oxygen is:
C₂H₄ + 3O₂ → 2CO₂ + 2H₂O
From the balanced equation, we can see that 3 moles of O₂ react with 1 mole of C₂H₄ to produce 2 moles of CO₂. Therefore, the number of moles of O₂ that reacted can be calculated as:
moles of O₂ = (moles of CO₂ produced) × (3/2)
moles of O₂ = 9.7 mol × (3/2)
moles of O₂ = 14.55 mol
Therefore, 14.55 moles of O₂ were reacted.
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which process could result in the net movement of a substance into a cell, if the substance is more concentrated in the cell than in the surroundings? group of answer choices
The process that could result in the net movement of a substance into a cell, if the substance is more concentrated in the cell than in the surroundings is called osmosis.
Osmosis is a passive transport process where water molecules move from an area of high concentration to an area of low concentration through a selectively permeable membrane. In this process, a solute moves from a region of high concentration to a region of low concentration. A selectively permeable membrane is a type of biological membrane that allows certain molecules or ions to pass through it by diffusion and occasionally specialized "facilitated diffusion" and passive or active transport processes, while preventing other molecules or ions from passing through it. Therefore, the correct answer is the option C - Osmosis.
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predict what happens to the temperature in the cooler bag containing dry ice
and ice cream. Explain your answer.
Hint : Look at the transfer of thermal energy when dry ice sublimes.
It stays much colder than traditional ice packs with the added bonus of no condesation building up on the inside of the travel box, like no water to make everything soggy &wet? However never take a huge breath of the contents as you open the box or container because inhaling trapped dry ice gas can be very harmful to your lungs! Simply let it mix with the air then carefully use gloves to move any dry ice away from your product and it should still be very frozen. We do this for long distance wedding cake delivery and I've never had one melt, 2 hours or more of driving to the events! Hope this helps!
What is the molar equilibrium constant for a chemical reaction, and how is it calculated. What differs it from the regular equilibrium constant (Keq)
Show how to carry out the following transformation in the highest yield possible. Select the appropriate reagents and/or draw the correct organic product at each step. Use an expanded octet on sulfur to minimize formal charges
Factors that make the higher yield of crop possible are as follows: enough water for irrigation. access of organic manure of high quality . Fertilizers are a factor in the higher yields of high-cost farming.
Fertilizer is used to ensure good vegetative growth (leaves, branches and flowers), giving rise to healthy plants. They are artificially made but have a rapid response. Overuse of fertilisers can cause negative effects like loose soil fertility. There's a risk with any bond that the issuing company might not be able to meet its obligations.
However, the risks of default are typically higher for companies that issue high-yield bonds. Interest rate . If the octet is expanded with preferred number of bonds, formal charge = 0. The S-atom will gain two electrons in order to complete its octet.
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HELP MEEE I will give good stuff hahahahhaha, okay help
Answer: Its the bottom one
-) How many moles of water will be produced by the complete combustion of 3
moles of propane (C₂H₂)?
Answer:
6 moles of H2O
Explanation:
We need the balanced equation for this reaction.
C2H2 + O2 = CO2 + H2O
2C2H2 + 5O2 = 2CO2 + 4H2O [Balanced reaction]
The balanced reaction tells us that we should expect to obtain 4 moles of water, H2), for every 2 moles of C2H2 (ethylene).
That is a ratio: (4 moles H2O)/(2 moles C2H2) or (2/1)(moles H2O/moles C2H4)
If we start with 3 moles of C2H4:
(3 moles C2H4)*((2 moles H2O)/(1 moles C2H2)) = (2*3/1) moles H2O [the moles C2H2 cancel]
(2*3/1) moles H2O = 6 moles of H2O
What do the red-colored blocks indicate?
The red-colored blocks indicate non metals in the periodic table. Nonmetals are located on the right side of the periodic table, in the p-block.
Non-metals are composed of a variety of elements, such as carbon, nitrogen, oxygen, sulfur, phosphorus, and selenium. These elements are generally non-reactive, but some of them can form compounds with other elements. They are also used in various industries, such as the production of plastics, fertilizers, and explosives. Non-metals are divided into two categories: metalloids and non-metalloids. Nonmetals are characterized by their lack of luster and their low thermal conductivity.
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When an antacid tablet dissolves in water, the fizz is due to a reaction between sodium hydrogen carbonate (sodium bicarbonate, NaHCO3) and citric acid (H₂CH₂O7).
3 NaHCO3(aq) + H₂C6H₂O7(aq) →3 CO₂(g) + 3 H₂O(l) + Na3CH₂O₂(aq)
How many moles of Na3C6H5O7 can be produced if one tablet containing 0.0217 mol of NaHCO3 is dissolved?
Therefore, 0.00723 moles of Na3C6H5O7 can be produced if one tablet containing 0.0217 mol of NaHCO3 is dissolved.
What is balanced chemical reaction?The balanced chemical equation shows that 3 moles of NaHCO3 react with 1 mole of H2C6H6O7 to produce 1 mole of Na3C6H5O7. Therefore, the number of moles of Na3C6H5O7 produced is directly proportional to the number of moles of NaHCO3.
If one tablet containing 0.0217 mol of NaHCO3 is dissolved, then according to the balanced chemical equation, the number of moles of Na3C6H5O7 produced is:
(0.0217 mol NaHCO3) x (1 mol Na3C6H5O7 / 3 mol NaHCO3) = 0.00723 mol Na3C6H5O7
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How many molecules are contained in
1357 mL of O2 gas at −14◦C and 1437 torr?
Answer in units of molec.
There are approximately 6.031 x 10^23 molecules of O2 gas contained in 1357 mL of O2 gas at −14°C and 1437 torr.
we can use the ideal gas law:
PV = nRT
where, P = pressure of the gas in torr,
V = volume of the gas in liters,
n = number of moles of gas,
R = ideal gas constant (0.08206 L·atm/mol·K),
T = temperature of the gas in Kelvin.
the volume of the gas from milliliters (mL) to liters (L):
V = 1357 mL / 1000 mL/L
V = 1.357 L
Now to convert the temperature of the gas from Celsius (°C) to Kelvin (K):
T = -14°C + 273.15
T = 259.15 K
Substituting the given values:
(1437 torr) (1.357 L) = n (0.08206 L·atm/mol·K) (259.15 K)
n = (1437 torr x 1.357 L) / (0.08206 L·atm/mol·K x 259.15 K)
n = 1.0008 mol
the number of moles of O2 gas contained in 1357 mL of O2 gas at −14°C and 1437 torr is 1.0008 mol. To find the number of molecules,
we can use Avogadro's number:
1 mol of O2 gas contains 6.022 x 10^23 molecules
So, the number of molecules in 1.0008 mol of O2 gas is:
(1.0008 mol) x (6.022 x 10^23 molecules/mol) = 6.031 x 10^23 molecules
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what does the NaBr + CI2 in the reaction?
NaBr + CI2 -> NaCI + Br2
A. Reactants
B. States of matter
C. Products
D. Yields
Answer:- NaBr and Cl2 are reactants .
The atoms/molecules/ions on RHS of the reaction which react to give products are called reactants.
So here Sodium bromide and chlorine are the reactants.
Option A is the correct choice.
Additional information:-
Law of conservation of Mass :-
According to this law , the mass of reactants is equal to the mass of the products . Take a chemical reaction ,
C + O2 ==> CO2
Now suppose that if 12g of carbon reacts with 16g of oxygen to form carbon dioxide, then what will be the mass of carbon dioxide? So by law of conservation of Mass we can say that mass of carbon dioxide will be equal to mass of the reactants that will be 12g + 16g = 28g
With this I am leaving a sample problem for you to solve,
Question: Consider the following reaction .
2C + O2 ==> 2CO
If the mass of carbon taken is 24g and the amount of carbon monoxide formed is 56g , find the amount of oxygen used in the reaction.
Answer:D. Yields
Explanation:
Which set of reactants is correct for
this double replacement reaction?
Al₂(SO4)3(aq) + 6NH₂OH(aq) →
I am mixing vinegar and baking soda in a bottle. If I want to be sure that Conservation of Mass is followed, what should I make sure to do?
Law of conservation of mass was crucial to progression of chemistry, as it helped scientists understand that substances did not disappear as result of reaction.
What is conservation of mass?Law of conservation of mass explains that in chemical reaction mass is neither created nor destroyed.
To ensure Conservation of Mass is followed when mixing vinegar and baking soda in a bottle, you should make sure to do the following:
Weigh the bottle and its contents before adding vinegar and baking soda. This will give the initial mass of system.
Carefully measure the amounts of vinegar and baking soda you add to bottle.
Quickly and securely cap the bottle after adding baking soda to avoid any gas from escaping.
Weigh the bottle and its contents again after reaction has completed and the gas has stopped escaping. This will give the final mass of the system.
Compare the initial and final masses of system. They should be equal within experimental error.
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If a 100.0g sample of water at 27.8 degrees Celsius is added to a 100.0g sample of water at 73.7 degrees Celsius determine the final temperature of the water assume no heat is lost to the surroundings
The final temperature of the water is 32.3°C.
If 500.0 g of water at 80.0°C is mixed with 300.0 g of water at 20.0°C, what is the final temperature of the mixture assuming no heat is lost to the surroundings?The final temperature of the mixture is 53.3°C.
How much heat is lost by a 50.0 g piece of copper initially at 200.0°C when it is placed in 100.0 g of water initially at 25.0°C? The final temperature of the copper and water is 50.0°C.The heat lost by the copper is 4.19 kJ.
To determine the final temperature of the water, we can use the principle of conservation of energy. The total heat gained by the cooler water is equal to the total heat lost by the hotter water. The heat gained or lost by a substance can be calculated using the formula:
Q = mcΔT
where Q is the heat gained or lost, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
Let's assume that the final temperature of the water is T. Then, the heat lost by the hotter water is:
Q1 = mcΔT = (100.0 g) x (4.184 J/g°C) x (73.7°C - T)
The heat gained by the cooler water is:
Q2 = mcΔT = (100.0 g) x (4.184 J/g°C) x (T - 27.8°C)
Since the total heat gained is equal to the total heat lost, we can equate Q1 and Q2:
(100.0 g) x (4.184 J/g°C) x (73.7°C - T) = (100.0 g) x (4.184 J/g°C) x (T - 27.8°C)
Simplifying the equation:
3134.4 - 41.84T = 418.4T - 11702.72
459.24T = 14837.12
T = 32.3°C
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When 22.0 g of Mg reacts, what volume, in liters, of H2 gas is produced at 26 ∘C and 800 mmHg ?
T = 23 C + 273 = 296 K V(H2) = (1.7 mol*62360 mmHg/mol*K*296 /850 mmHg) = 36917.1 ml = 36.9 L if volume, per liters, of H2 gas is created at 26 C and 800 mmHg.
Is H2 hazardous gas?For instance, hydrogen is not harmful. Also, as hydrogen is that much lighter than the atmosphere, it evaporates quickly when it is discharged, enabling the fuel to disperse relatively quickly in the event of a leak. To ensure its safe use, some of hydrogen's features necessitate additional technical restrictions.
Is hydrogen gas H2 a gas?When two atoms of hydrogen join forces to form a hydrogen molecule, the result is a gas known as H2. Molecular hydrogen is another name for H2. There are two protons & two electrons in it. Hence, it has a neutral charge and is stable, making it the most prevalent type of hydrogen.
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At the carnival, a baby was given a helium balloon whose pressure equaled the
atmospheric pressure at the carnival which was 102. 7 kPa. However, the baby wasn't
paying attention and the balloon floated away into the troposphere where the
atmospheric pressure is 97. 8 kPa. What is the positive difference between the
pressure in the balloon and the pressure of the troposphere in atm?
atm
The positive difference between the
pressure in the balloon and the pressure of the troposphere is 0.048 kPa .
The balloon is being compressed by atmospheric force. The balloon is trying to inflate owing to gas pressure. The atmospheric pressure (outside pressure) in a fully inflated balloon is lower than the internal gas pressure.
An inflated balloon has a higher internal pressure than its surrounding air. Because the contracting force produced by the rubber's surface tension balances the expanding force caused by the pressure differential, the balloon remains stable.
Because to the air pressure on the walls, a balloon's surface feels tighter when it is inflated. The internal air pressure gives the balloon its shape. The balloon will therefore be more pressurized after being inflated.
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C) Write the formulas and predict the products. Name and Balance the equation Aluminum Phosphite + Copper (ii) Chromate ---→
The balanced equation for the reaction would be 2AlPO4 + 3CuCrO4 → Al2(CrO4)3 + 3Cu3(PO4)2.
Equation of a reactionThe formulas of the reactants are:
Aluminum Phosphite: AlPO4Copper (II) Chromate: CuCrO4The formulas of the products are:
Aluminum Chromate: Al2(CrO4)3Copper (II) Phosphate: Cu3(PO4)2The balanced equation indicates that 2 moles of Aluminum Phosphite react with 3 moles of Copper (II) Chromate to produce 1 mole of Aluminum Chromate and 3 moles of Copper (II) Phosphate.
Thus: 2AlPO4 + 3CuCrO4 → Al2(CrO4)3 + 3Cu3(PO4)2
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How many g of water are needed to create a 4 molal solution with 9 moles of NaOH?
The grams of water needed to create a 4 molal solution with 9 moles of NaOH is 2250 grams.
How to calculate grams of water?Molality is defined as moles of solute per kilogram of solvent. Changing the values of moles and molality in the equation will provide the kg of solvent. 4=9/kg of solvent2.25 kilograms per kilogram of solventThe term "total moles of a solute contained in a kilogram of a solvent" is used to define molality. Molality is often referred to as molal concentration. It gauges the amount of solutes in a solution. Solute and solvent are the two parts that make up the solution. which is equivalent to 2250 grams of water.Molality, often known as molal concentration, is the product of the solute's mass and the solvent's mass: Molality = nsolute / msolvent = msolute / (Wsolute msolvent), where: nsolute is the quantity of the solute (in moles)For more information on molality kindly visit to
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If 25 g of NH, and 96 g of H₂S react according to the following reaction, what is the maximum mass of ammonium sulfide that can be formed?
2 NH, + H₂S → (NH4)₂S
Name the following formula: BF2 (hint: treat boron like a nonmetal)
A. Boron fluoride
B. Monoboron difluoride
C. Boron difluoride
D. Boron (II) fluoride
E. Best Friends Forever
The name of the formula BF2 is : C.) Boron difluoride. The number of atoms of each element in a compound is known by chemical formula.
What is meant by chemical formula?Chemical formula is an expression that shows elements in a compound and relative proportions of those elements. If only one atom of specific type is present, then no subscript is used. For atoms that have two or more of a specific type of atom present, then a subscript is written after the symbol for that atom.
Chemical formula contains the symbols of atoms of the elements present in the compound and also how many there are for each element in the form of subscripts.
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how can enzymes speed up chemical reactions? a.they raise the activation energy needed for the reaction. b.they increase the ph of the reaction. c.they increase the amount of substrate in the reaction. d.they lower the activation energy needed for the reaction.
Enzymes speed up chemical reactions by lowering the activation energy needed for the reaction. The correct option is d.
Enzymes are biological molecules, typically proteins, that act as catalysts for chemical reactions. Catalysts are substances that can speed up a chemical reaction without being consumed in the process.
Enzymes work by lowering the activation energy needed for a chemical reaction to occur. Activation energy is the energy required to break the bonds of the reactants and initiate the chemical reaction. By lowering the activation energy, enzymes make it easier for reactants to come together and form products.
Enzymes achieve this by binding to the reactants, or substrates, and bringing them into close proximity to each other. This allows the substrates to interact more easily and lowers the energy barrier for the reaction to occur. Enzymes also stabilize the transition state of the reaction, further reducing the activation energy needed for the reaction to proceed.
Therefore, the correct answer is d) they lower the activation energy needed for the reaction.
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A cat stands on a scale and finds its weight to be 4. 0 kilograms. If the weight exerted by all four of its paws on the scale is. 25 kilograms per square centimeter, what is the area of one of its paws in square centimeters?
the area of one of the cat's paws is 4 square centimeters.
The weight of the cat is 4.0 kilograms, which is the force exerted on the scale by the cat's body. The weight per unit area on the scale due to the cat's paws is 0.25 kilograms per square centimeter.
Let A be the area of one of the cat's paws in square centimeters. The weight of the cat is supported by all four paws, so the total force exerted by the paws on the scale is:
force = weight = 4.0 kg
The force exerted by one paw is one-fourth of the total force:
force per paw = force / 4 = 4.0 kg / 4 = 1.0 kg
This force is distributed over the area of one paw, so we can write:
pressure = force per paw / A
where pressure is the weight per unit area, which is given as 0.25 kg/cm
Substituting the values and solving for A, we get:
0.25 kg/cm = 1.0 kg / A
A = 1.0 kg / 0.25 kg/cm = 4 cm
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How many moles are there in 5.6x1015 particles of hydrogen peroxide?
Answer:
0.9299 x [tex]10^-7[/tex] moles of [tex]OH^-[/tex]
Explanation:
[tex]OH^-[/tex]: 5.6 x 10^(15) (brainly doesn't allow exponents greater than 9)
This number of particles can also be represented as 5.6e15.
'e' in this case means 'times 10 to the n' where n is the number that follows e.
Use stoichiometry to convert between different units.
[tex]\frac{5.6e15 particles}{1 sample} *\frac{1 mole}{6.022 e22 particles}= 0.9299 e -7 moles[/tex]
So in that sample of particles, there are 0.9299 x [tex]10^-7[/tex] moles of [tex]OH^-[/tex].
What is the new pressure of gas with a solubility of 24 g/ L if 48 g/L is soluble at 444 kPa
The new pressure of the gas with a solubility of 24 g/L will be222 kPa.
The solubility of the gas in the liquid is directly proportional to the partial pressure of a gas above the liquid. This relationship is described by Henry's Law, which states that the solubility of a gas is proportional to its partial pressure:
C = kP
where C is the concentration of the gas in the liquid (in units of g/L), P is the partial pressure of the gas above the liquid (in units of kPa), and k is the proportionality constant.
If we know the solubility of the gas at one pressure, we can use Henry's Law to calculate the solubility at a different pressure. For example, if the solubility of the gas is 48 g/L at 444 kPa, and we want to know the solubility at a new pressure, we can use the following formula:
P₁ / P₂ = C₁ / C₂
where P₁ is the initial pressure, P₂ is the new pressure, C₁ is the initial concentration (solubility) at P₁, and C₂ is the new concentration (solubility) at P₂.
Rearranging this formula, we get:
C₂ = C₁ x (P₂ / P₁)
Substituting the given values, we have:
C₁ = 48 g/L (solubility at 444 kPa)
P₁ = 444 kPa
C₂ = 24 g/L (desired solubility at new pressure)
P₂ = ?
Solving for P₂, we get:
P₂ = (C₂ x P₁) / C₁
P₂ = (24 g/L x 444 kPa) / 48 g/L
P₂ = 222 kPa
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