In the adjoining figure triangle PQR is similar to triangle PMN , PM= 2MQ And PN = 2NR . Determine ratio of MN/QR
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Answer:

hi

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Answer:

72x430/43

Step-by-step explanation:

Answer:

60 cm

Step-by-step explanation:

The perimeter of a polygon means adding up all the side lengths.

In this case, we need to add up 13, 12, 8, 8, and 19

Adding all of these gets us 60

Answer:

Step-by-step explanation:

Since cotangent of angle is:

And

The value of cot λ is:

Correct choice is B

Answer:

7

Step-by-step explanation:

List out possible numbers that would add to the answer choices and see which has most possibilities

7

3 + 4

5 + 2

1 + 6

10

5 + 5

4 + 6

11

5 + 6

12

6 + 6

The function is given by y = 550(0.76)ˣ, after 10 passes, the number of dirts is about 35.36 ml

Let y represent the amount of dirt on the floor after x passes.

The floor initially has 550 ml of dirt, hence a = 550.

During each pass, 24% of the dirt is removed. Hence b = 100% - 24% = 76% = 0.76

The equation is given by:

y = 550(0.76)ˣ

After 10 passes:

y = 550(0.76)¹⁰ = 35.36 ml

The function is given by y = 550(0.76)ˣ, after 10 passes, the number of dirts is about 35.36 ml

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[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: ({4}^{2}) \star ( {2}^{9} ) = {2}^{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \: ({ {2}^{2}) }^{2} \star ( {2}^{9} ) = {2}^{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \: ({ {2}^{}) }^{4} \star ( {2}^{9} ) = {2}^{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \:2 {}^{4 + 9} = {2}^{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 4 + 9[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 13[/tex]

hence, value of x is 13

[tex]➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖[/tex]

Answer:

x = 13

Step-by-step explanation:

[tex]\left(4^2\right)\left(2^9\right)=2^x[/tex]

[tex]\mathrm{multiply}[/tex]

[tex]4^2=16[/tex]

[tex]2^9=512[/tex]

[tex]16*512=8192[/tex]

[tex]8192=2^x[/tex]

[tex]\mathrm{Flip \;the \;equation}[/tex]

[tex]2x=8192[/tex]

[tex]log(2x)=log(8192)(Take \;log \;of\; both \;sides)[/tex]

[tex]x*(log(2))=log(8192)[/tex]

[tex]x=\frac{log(8192)}{log(2)}[/tex]

[tex]x=13[/tex]

[RevyBreeze]

Hi, to begin, the ordered pair value (-3, 15) has an x-value of -3. So, to see if it lies on the line of your equation y = 6x + 11, plug -3 in for x. This gives you y = 6(-3) + 11 = -7 So the ordered pair answer for this would be (-3, -7) and not (-3, 15). So the answer is no.

Hey there!

The average squared distance between the points is their variance

The average squared distance is 8/3

The given parameters are:

R={(x,y): 0<=x<=2, 0<=y<=2}

The point = (2,2).

f(x,y) = (x-2)² + (y-2)²

The squared distance is calculated as:

D² = f(x,y) = (x-2)² + (y-2)²

Where the area (A) is:

A = xy

Substitute the maximum values of x and y in A = xy

A = 2 * 2

A = 4

The minimum values of x and y are 0.

So, the limits for the integrals are 0 to 2

The integral becomes

[tex]D\² = \int \int (x-2)\² + (y-2)\² dx dy[/tex]

Expand

[tex]D\² = \int \int x\² -4x + 4 + (y-2)\² dx dy[/tex]

Evaluate the inner integral with respect to x from 0 to 2

[tex]D\² = \int \frac 13x^3 -2x^2 + 4x + x(y-2)\² |\limits^2_0 dy[/tex]

Expand

[tex]D\² = \int [\frac 13(2)^3 -2(2)^2 + 4(2) + (2)(y-2)\²] dy[/tex]

Simplify

[tex]D\² = \int \frac 83 + (2)(y-2)\² dy[/tex]

Expand

[tex]D\² = \int \frac 83 + 2y^2-8y + 8 \ dy[/tex]

Evaluate the integral with respect to y from 0 to 2

[tex]D\² = [\frac 83y + \frac 23y^3- 4y^2 + 8y ]|\limits^2_0[/tex]

Expand

[tex]D\² = \frac 83*2 + \frac 23*2^3- 4*2^2 + 8*2[/tex]

D² = 32/3

The average squared distance (AD²) is calculated as:

AD² = D²/A

So, we have:

AD² = 32/3 [tex]\div[/tex] 4

Evaluate the quotient

AD² = 32/12

Simplify

AD² = 8/3

Hence, the average squared distance is 8/3

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The average squared distance between the points of R = {(x,y): 0<=x<= h, 0<=y<=k } is 8/3.

How do determine the average squared distance?

From the given parameters R = {(x,y): 0<=x<= h, 0<=y<=k }

The squared distance from point (h, k) is calculated as

D² = f(x,y) = (x-2)² + (y-2)²

Where the area (A) will be

A = xy

Substitute the maximum values of x and y

A = 2 × 2 = 4

The minimum values of x and y are 0.

So, The integral becomes

[tex]D^{2} = \int \int(x-2)^2 +(y-2)^2 dx dy\\\\D^{2} = \int \int\limits^2_0 (x)^2 -4x + 4+(y-2)^2 dx dy\\\\D^{2} = \int1/3(x)^3-2x^{2} +4x + 4+x(y-2)^2 dy\\\\D^{2} = \int8/3+2y^{2} -8y +8 dy[/tex]

[tex]D^2 = {8/3y +2/3y^2 -4y^2+8y[/tex]

By expanding we get,

D^2 = 32/3

The average squared distance (AD²) is calculated as:

AD² = D²/A

AD² = 32/3  4

AD² = 32/12

AD² = 8/3

Hence, the average squared distance is 8/3

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Answer:

4 inches by 2.5 inches

Step-by-step explanation:

The scale factor is 7 feet/1 inch.

This can be written as  7'/1" or as 1"/7'

28 feet converts to (28')*(1"/7') = 4"

17.5 feet converts to (17.5)*(1"/7') = 2.5"

The drawing dimensions are 4 inches by 2.5 inches.

Answer:

Step-by-step explanation:

Answer:

40+20, 50+10, 46+14

Step-by-step explanation:

15+45=60 =   50+10=60 46+14=60

Answer:

The top-left one.

Step-by-step explanation:

The bottom pictures show that Chef B chopped more carrots than Chef A.

So those pictures are incorrect.

The top-right picture shows that Chef A chopped twice as many carrots as Chef B. So, that isn't correct either.

Finally, we get to the top-left picture.

Chef A chopped 3 times as many carrots as Chef B.

Thus the correct answer is the top-left picture.

Also, I would appreciate it if you marked me as brainliest.

Answer: 65/63

Step-by-step explanation:

The cosecant of angle N is the reciprocal of the sine of angle N.

Using SOHCAHTOA, the sine of angle N is 63/65.

This means that the cosecant of angle N is 65/63.

Answer:

[tex]x=43[/tex]

Step-by-step explanation:

Given equation:

[tex]25=5(3x-4)^{\frac13}[/tex]

Divide both sides by 5:

[tex]\implies 5=(3x-4)^{\frac13}[/tex]

Cube both sides:

[tex]\implies 5^3=((3x-4)^{\frac13})^3[/tex]

[tex]\implies 125=(3x-4)^{\frac33}[/tex]

[tex]\implies 125=(3x-4)^1[/tex]

[tex]\implies 125=3x-4[/tex]

Add 4 to both sides:

[tex]\implies 129=3x[/tex]

Divide both sides by 3:

[tex]\implies x=43[/tex]

Answer:

x = 43

Step-by-step explanation:

Answer:  x = -4 + y

Step-by-step explanation:

Subtract y from both sides y- x - y = 4 - y

Simplify -x = 4 - y

Divide by -1

-x ÷ -1,

4 ÷ -1,

y ÷ -1,

Simplify x = -4 + y

Answer:27.712812921102

Step-by-step explanation:

24*32=x*x

√768=√x²

27.712812921102=x

Geometric mean formula

a=24

b=32

Find GM

On rounding

To find the range, interquartile range, and median of the box plot, see the image attached below to use as a guide.

A box plot consists of a rectangular box, a vertical line that divides the box, and two whiskers extending from the box.

The box plots being referred to in the question are missing, however, the diagram attached shows how to determine the values you will need in solving the question.

The median is represented by the vertical line that divides the rectangular box.

The range = max value - min value.

The interquartile range = the range of the rectangular box = Q3 - Q1.

In summary, to find the range, interquartile range, and median of the box plot, see the image attached below to use as a guide.

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Answer:

20 shirts = $445.00

40 shirts = $541.00

60 shirts = $637.00

Step-by-step explanation:

multiply 20, 40 and 60 by 4.8 then add 349.

20*4.8 = 96

96+349 = 445

40*4.8 = 192

192+349 = 551

60*4.8 = 288

288+349 = 637

Answer:

89

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Answer: One if any.

-x = x - 10                  Add x to both sides

-x+x = x + x - 10          Combine

0 = 2x - 10                   Add 10 to both sides

10 = 2x - 10+10            Combine

10 = 2x                         Divide by 2

10/2=2x/2

x = 5

Definite Answer: One Solution

Answer:

the anwer is A cause jobs and industials had 96 percent and corperate profits after taxes doubled

Answer:

a

Step-by-step explanation:

world War 2 did in fact cause the United States to become the richest and most powerful

Answer:

58

Step-by-step explanation:

x=9

3(9) + 1 + 4(9) -8 + (9) - 7 = 58

Answer:

D is the answer because 4 goes into all of them.

Answer:

5

Step-by-step explanation:

5 158/559

= 5 + 158/559

= 5 + 0.28264758

= 5.28264758

= 5 (rounded to nearest whole number)

Answer:

5

Explanation:

[tex]\rightarrow \sf 5\dfrac{158}{559}[/tex]

[tex]\rightarrow \sf 5.282647585[/tex]

The whole number is the quotient in any fraction.

Answer:

a= 50

b=50

c=110

d=20

Answer:

Step-by-step explanation:

This is a kite. So the two triangles formed by the longest diagonal being drawn in form 2 congruent triangles.

Therefore c = 110 degrees.

d = 20 degrees.

a and b are found by noting that every triangle has 180 degrees.

110 + 20 + a = 180           Combine the left.

130 + a = 180                   Subtract 130 from both sides

a = 180 - 130

a = 50 degrees

b also equals 50 degrees.  Congruent triangles

Answer

Answer:

(a) 3x + 4 = 2x + 1

3x - 2x = 1 - 4

x = -3

Step-by-step explanation:

To solve for 'X', you must move all 'x' to the left-hand side, as seen through the working out. To balance it, you move all the lone numbers without (constants) to the right. Remember: when you move values across the 'equals' sign, the sign of the value you are moving becomes switched. For example, if you're moving 3x + 1 = 0 and you wish to move 1 to the other side, it becomes 3x = 0 ( - 1).

The magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T

The magnetic field inside the central area of the solenoid is given by B = μ₀ni where

Since B = μ₀ni

Substituting the values of the variables into the equation, we have

B = μ₀ni

B = 4π × 10⁻⁷ Tm/A × 3,170 turns/m × 6.7 A

B = 4π × 10⁻⁷ Tm/A × 21239 A-turns/m

B = 84956π × 10⁻⁷ T

B = 266897.15 × 10⁻⁷ T

B = 0.026689715 T

B ≅ 0.0267 T

So, the magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T

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The magnitude of the magnetic field in the central area inside the considered solenoid (assuming in vaccum), is approx 2.67 × 10^{-2} T

Magnetic field = permeability constant x relative permeability x turn density x current

B = [tex]k\mu_0nI = \mu nI[/tex]

where turn density is calculated as:

n = N/L

Where N represents the number of turns of the wire and

L represents the length of the solenoid.

Assuming that the solenoid is placed in vaccum, we have:

[tex]\mu = k\mu_0 = \mu_0 = 4\pi \times 10^{-7} \: \rm T m/A[/tex]

And it is given that:

Thus, we get:

[tex]B = \mu n I = 4\pi \times 10^{-7} \times 3170 \times 6.7 \approx 2.67 \times 10^5 \times 10^{-7} \\\\B = 2.67 \times 10^{5 + (-7)}B = 2.67 \times 10^{-2} \: \tm T[/tex]

Thus, the magnitude of the magnetic field in the central area inside the considered solenoid (assuming in vaccum), is approx 2.67 × 10^{-2} T

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Answer:

3= perimeter=44 area=73

4= perimeter=60 area=209

5= perimeter=32 area=55

Step-by-step explanation:

18x4=72

18+18+4+4=44

11+11+19+19=60

11x19=209

5x11=55

5+5+11+11=32

Answer: C

Step-by-step explanation: