In which number is the value of the 7 ten times the value of the 7 in the number 17,862

Answer:

B

Step-by-step explanation:

A) 1 + 1 + 1 + 1 = 4

4 / 4 = 1

B) 4 + 4 = 8

8 / 2 = 4

Answer: B

Step-by-step explanation:

[tex]\textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=30\pi \end{cases}\implies 30\pi =2\pi r\implies \cfrac{30\pi }{2\pi }=r\implies \boxed{15=r} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\textit{arc's length}\\\\ s = \cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=15\\ \theta =225 \end{cases}\implies \widehat{XY}=\cfrac{(225)\pi (15)}{180}\implies \boxed{\widehat{XY}\approx 58.90} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \qquad A=\pi (15)^2\implies A=225\pi \implies \boxed{A\approx 706.86}[/tex]

Answer:

See below ↓

Step-by-step explanation:

Let's find the x and y values.

Step 1 : Equate the y expressions.

Step 2 : Convert fractions in the equation to whole numbers.

Step 3 : Bring x terms to one side and constant terms to the other.

Step 4 : Solve for y by plugging the value of x into one of the given equations.

Answer: B

Step-by-step explanation:

Multiply U and V:

[tex]\begin{pmatrix}-9&1&0\\ \:4&0&2\\ \:0&1&5\end{pmatrix}\begin{pmatrix}2\\ \:-2\\ \:1\end{pmatrix}[/tex]

[tex]\mathrm{Multiply \ the \ rows \ of \ the \ first \ matrix \ by \ the \ columns \ of \ the \ second \ matrix:}[/tex]

[tex]\begin{aligned}&\left(\begin{array}{ccc}-9 & 1 & 0\end{array}\right)\left(\begin{array}{c}2 \\-2 \\1\end{array}\right)=(-9) \cdot 2+1 \cdot(-2)+0 \cdot 1 \\&\left(\begin{array}{ccc}4 & 0 & 2\end{array}\right)\left(\begin{array}{c}2 \\-2 \\1\end{array}\right)=4 \cdot 2+0 \cdot(-2)+2 \cdot 1 \\&\left(\begin{array}{lll}0 & 1 & 5\end{array}\right)\left(\begin{array}{c}2 \\-2 \\1\end{array}\right)=0 \cdot 2+1 \cdot(-2)+5 \cdot 1\end{aligned}[/tex]

[tex]=\begin{pmatrix}\left(-9\right)\cdot \:2+1\cdot \left(-2\right)+0\cdot \:1\\ 4\cdot \:2+0\cdot \left(-2\right)+2\cdot \:1\\ 0\cdot \:2+1\cdot \left(-2\right)+5\cdot \:1\end{pmatrix}[/tex]

[tex]\mathrm{Simplify\:each\:part:}[/tex]

[tex]=\begin{pmatrix}-20\\ 10\\ 3\end{pmatrix}[/tex]

Therefore, the correct answer is B

Answer:

140cm³

Step-by-step explanation:

Credit: yaretzigutierrez50

Answer:

140cm

Step-by-step explanation:

Answer:

-9 3/4a+10 2/5

Step-by-step explanation:

-12 * 5/6a = -10a

-12 * -7/8 =  10 1/2

1/14 * 3 1/2a = 1/4 a

1/14 * -1 2/5 = -1/10

Put it together: -10a + 10 1/2 + 1/4a - 1/10

-10a+1/4a = -9 3/4a

10 1/2-1/10= 10 2/5

-9 3/4a + 10 2/5

Answer:

an = 9(⅔)^(n-1)

Step-by-step explanation:

The formula for explicit is: An = a1(r)^(n-1)

Answer:

Step-by-step explanation:

Answer:

y=2x-1

Step-by-step explanation:

(1)

If there are three times as many males as females, the ratio of males to females would be 3:1.

To make this more clearer. Suppose you have 100 students. for each 4 students, 3 of them are male and 1 is a female.

We can then say there are 75 males and 25 females.

Expressing this as a ratio(fraction) is easy 3 out of 4 are males and 1 out of 4 are females. So the ratio of males would be;

[tex]r(m) = \frac{3}{4} [/tex]

(2)

Let x be the number of cola bottles

Let y be the number of smarties

Let z be the number of marshmallows

x=3y (since there are 3 times more x than y)

y=2z (since there are 2 times more y than z)

we know that marshmallows are twice as less as smarties. so for 1 marshmallow you'd have 2 smarties. But we also know that cola bottles should be 2×3=6 since we have 3 times more cola bottles than smarties.

Adding up our total sweets we get;

1+2+6=9

But how many of those are cola bottles? 6!

So the ratio of cola bottles can be expressed as,

[tex]r(c) = \frac{6}{9} = \frac{2}{3} [/tex]

You can simplify the numerator and denominator by 3 to get 2 over 3.

Answer:

17 or 7

Step-by-step explanation:

if im right brainliest pls
?

function :  y = (-x) - 6

Find x-intercept :

Find y-intercept :

mark these two points on both the axis and draw a straight linear graph.

passes coordinates : (0, -6), (-6, 0)

[tex]\\ \rm\rightarrowtail y=-x-6[/tex]

Take some point s

Graph it

Answer:

  parry

Step-by-step explanation:

You are looking for a 5-letter word that has two letters R in it. One such is ...

  parry

If the value of |A| is 48 the possible values for x in the matrix is 4 or -2.

The determinant of the matrix A is as follows:

|A| = 48

Therefore,

48 = (3x × 2x) - (4x × 3)

48 = 6x² - 12x

6x² - 12x - 48 = 0

3x² - 6x - 24 = 0

x² - 2x - 8 = 0

x² + 2x - 4x - 8 = 0

x(x + 2 -4(x + 2) = 0

(x - 4)(x +2) = 0

Therefore,

x = 4 or -2

learn more on determinant here: https://brainly.com/question/19206601

The only interval with a negative rate of change is the last one:

[1, 2.5]

For an interval (a, b) and a function f(x), the rate of change is defined as:

[tex]r = \frac{f(b) - f(a)}{b - a}[/tex]

So the rate of change is only negative when the function evaluated on the first value of the interval is larger than the function evaluated in the second one.

For example, on the interval [1, 2.5} we can see that:

f(1) = 3

f(2.5) = -1

Then on this interval, the rate of change will be negative, meaning that this is the correct option.

If you want to learn more about rates of change, you can read:

https://brainly.com/question/8728504

Answer:

It's D: 1 to 2.5

Step-by-step explanation:

It's D: 1 to 2.5

Answer:

The answer is 18.2 OR 18 1/5

Step-by-step explanation:

Hope it helps

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's check I the given pairs of triangles are congruent or not ~

[tex]\qquad \sf  \dashrightarrow \:ABC \cong FED[/tex]

These triangles are congruent by SSS congruency, as it's three sides are equal.

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \:LMN \not \cong PQO[/tex]

・ ．━━━━━━━†━━━━━━━━━．・

These triangles are not congruent because they don't fulfill any congruency criteria.

[tex]\qquad \sf  \dashrightarrow \: XVW \cong YZA [/tex]

These triangles are congruent by AAS congruency criteria, since two angles and one of the side is common.

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \: GHI \not \cong IJG [/tex]

These triangles are not congruent because they don't fulfill any criteria.

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \: PQR\cong QPO[/tex]

These triangles are congruent by SSS congruency, as it's two sides are equal and one side is common.

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \: JIK \cong HIG [/tex]

These triangles are congruent by SAS congruency, since two sides and Angle between them are equal.

・ ．━━━━━━━†━━━━━━━━━．・

These given triangles are congruent by SSS congruency, because they have two equal sides and one common side in there.

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \: BCD \cong FED [/tex]

These triangles are congruent by ASA congruency, because they have one pair equal angles, one pair of vertical opposite angles (they are equal) and a side between them equal.

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \: LKM \cong LNM [/tex]

These given triangles are congruent by SSS congruency, because they have two equal sides and one common side in there.

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

Answer:

$35.

Step-by-step explanation:

SP = 25 + 0.40*25

= 25 + 10

= $35.

well, hmmm to check for polar symmetry, hmmm say we simply replace the value for either "r" or "θ" or both in the original equation, if the equation rendered is the same as the original, there you have it, symmetry, so let's do that.

[tex]\underline{\textit{testing for symmetry to the }\frac{\pi }{2}~line\qquad \qquad r=-r~~,~~\theta =-\theta } \\\\\\ r=-7+2cos(3\theta )\implies (-r)=-7+2cos[3(-\theta )]\implies -r=-7+2cos(-3\theta ) \\\\\\ \stackrel{symmetry~identity}{-r=-7+2\stackrel{\downarrow }{cos(3\theta )}}\implies r=7-2cos(3\theta )\impliedby \textit{woopsie, no dice} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\underline{\textit{testing for symmetry to the polar axis}\qquad \qquad \theta =-\theta} \\\\\\ r=-7+2cos(3\theta )\implies r=-7+2cos[3(-\theta )]\implies r=-7+2cos(-3\theta ) \\\\\\ \stackrel{symmetry~identity}{r=-7+2\stackrel{\downarrow }{cos(3\theta )}}\impliedby \textit{low and behold\qquad \Large \checkmark}[/tex]

now, we could run a test for "the pole" or namely the origin by simply changin r = -r, however we already know where the symmetry is, so no need.

Check the picture below.

Answer:

▲ Base and height. This is the basic volume equation of a triangular prism: Volume = 0.5 * Base * Height * Length. ...

◣ Right triangle. Probably the most popular type of prism! ...

▲ 3 sides. Volume = 0.25 * √( (a+b+c) * (-a+b+c) * (a-b+c) * (a+b-c) ) * Length.

Step-by-step explanation:

Answer:

One bucket of popcorn:  6$

One box of candy: $3.75

2 buckets of popcorn:  $12

3 boxes of candy:  $11.25

2 buckets of popcorn and 3 boxes of candy:  $23.25

Step-by-step explanation:

We can find the cost of one bucket of popcorn and one box of candy using a system of equations

[tex]4P + 6C=46.50\\P + C =9.75[/tex]

We can use the elimination method and thus multiply the second equation by -4:  

[tex]4P + 6C = 46.50\\-4(P+C=9.75)\\\\4P + 6C = 46.50\\-4P -4C=-39\\\\2C = 7.5\\\\C = 3.75[/tex]

We can plug C into the second equation to find P:

[tex]P + 3.75 = 9.75\\P = 6[/tex]

Thus, the cost of two buckets of popcorn is 6 * 2 = $12

And the cost of three boxes of candy is 3.75 * 3 = $11.25

And the cost of both two buckets of popcorn and three boxes of candy is (6*2) + (3*3.75) = 12 + 11.25 = $23.25

Answer:

2/20 chance that they get both the prizes

[tex]\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=10\\ h=18 \end{cases}\implies V=\cfrac{\pi (10)^2(18)}{3}\implies \stackrel{using~\pi =3.14}{V=1884}[/tex]

Answer:

Step-by-step explanation: Your answer will be -10 because even though -10 is much lower than 15 it’s still closer to sea level.

Answer:

given ,

two points A ( -1 , 2 ) and B ( 0 , -14 )

______________________________________

[tex]\fbox\pink{Solution -}[/tex]

let the midpoint be P ( x , y )

using midpoint formula ,

[tex]P(x,y) = ( \frac{ x_{1} + x_{2} }{2} , \frac{ y_{1} + y_{2} }{2} ) \\ \\ P(x,y) = ( \frac{ - 1 + 0}{2} , \frac{2 + ( - 14)}{2} ) \\ \\ (x,y) = ( \frac{ - 1}{2} , \frac{ - 12}{2} ) \\ \\ x = \frac{ - 1}{2} \\ \\ y = \frac{ - 12}{2} => - 6[/tex]

thus ,

the coordinates of the midpoint are

[tex]\red{P( \frac{ - 1}{2} , - 6)} \\ \\ or \\ \\ \red{P( -0.5 , - 6 )} [/tex]

hope helpful :D

Answer:

Step-by-step explanation:

A(-1,2)  x₁ = -1  &  y₁ = 2

B(0 ,-14)   x₂ = 0  & y₂ = -14

[tex]\text{ \sf Midpoint = $\left(\dfrac{x_{1}+x_{2}}{2} ,\dfrac{y_{1}+y_{2}}{2}\right)$ }[/tex]

              [tex]= \left (\dfrac{-1+0}{2} ,\dfrac{2+[-14]}{2} \right) \\\\\\=\left(\dfrac{-1}{2}, \dfrac{-12}{2}\right)\\\\\\=\left( -0.5 , -6 \right)[/tex]

Step-by-step explanation:

y = -x/2 - 1

the y-intercept is right there : -1.

it is the y-value when x = 0

the point of y-intercept is therefore (0, -1).

the x-intercept is the other way around. it is the x- value when y = 0.

0 = -x/2 - 1

1 = -x/2

-2 = x

the point of x-intercept is therefore (-2, 0)

Using proportions, it is found that the error was treating the 100% value as a percent(100) instead of a decimal 1, hence the correct value is of 96.

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In this problem, we have that 100% = 1 of the number is w, while 6 is equals to 6.25% = 0.0625. Hence the rule of three is given by:

1 - w

0.0625 - 6

Applying cross multiplication:

0.0625w = 6.

w = 6/0.0625

w = 96.

The error was treating the 100% value as a percent(100) instead of a decimal 1, hence the correct value is of 96.

More can be learned about proportions at https://brainly.com/question/24372153

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♫[/tex]

Let's see ~

Remember : value of 1 meter = 100 centimeters

[tex]\qquad \sf  \dashrightarrow \:1 \: m = 100 \: cm[/tex]

[tex]\qquad \sf  \dashrightarrow \:1 \: cm = \frac{1}{100} \: m[/tex]

[tex]\qquad \sf  \dashrightarrow \:1 \: cm = 0.01 \: m[/tex]

・ ．━━━━━━━†━━━━━━━━━．・

As we know

So

turn down to fraction

[tex]\\ \rm\rightarrowtail \dfrac{1}{100}[/tex]

Turn to decimal

[tex]\\ \rm\rightarrowtail 0.01m[/tex]