in which of the following cases does a car have a negative velocity and a positive acceleration? a car that is traveling in the

The homeowner has reported that sometimes the electric furnace trips the 240-V, 60-A circuit breaker connected to it. Upon examination, it is found that the furnace contains three 5000-W heating elements designed to turn on in stages.

The power rating of the circuit breaker = volt x current

= 240 x 60

= 14400 W

So, we have 3 units of 5000W each.

When the first unit is turned on, the consumption is 5000W and the circuit breaker does not trip. When two of the 5000W units are turned on, it adds up to a consumption of 10000W.

The circuit breaker is still intact. But when the 3rd 5000W unit is turned on, the consumption reached to 15,000W which is greater than the 14,400W mark, and thus the circuit breaker trips off.

So, switching on all three units at once can cause the circuit breaker to trip off.

So, the recommendation would be that at a particular time maximum of two units can be turned on.

Even such, the two units cannot be turned on in series or they won’t receive 240 V each.

Another recommendation would be to use a circuit breaker of a higher power rating, more than 15,000W so that there will be no tripping.

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Answer:

one in which the motion of a particle not subject to forces is in a straight line at constant speed

Explanation:

I searched this on the internet

Answer: 1.3%

The speed of a bullet train is measured to be 312.0 mph ± 3.9 mph. What is the percent uncertainty in this measurement?(1 point) 1.3%

Kw = 4.36×10^-16 is the value of kw at temperature when the ph of a neutral solution is 7.68.

The formula for Kw is:

Kw= [H]*[OH]

where [H] and [OH] are concentrations

We are given the pH so we can calculate the [H] concentration from the formula:

pH=-log[H]

[tex]P_{H} =-log_{10} [H^{+} (aq)][/tex]

[tex]-P_{H} =log_{10} [H^{+} (aq)][/tex]

[tex][H^{+} (aq)]=10^{-P_{H} }[/tex]

[tex][H^{+} (aq)]=10^{-7.68}[/tex]

[tex][H^{+}(aq) ]=[/tex]2.089×[tex]10^{-8}[/tex]mol [tex]dm^{-3}[/tex]

In neutral solution, [H] = [OH],

therefore: [OH]=2.089×10^-8M

Calculating Kw:

Kw = (2.089×10^-8M) *(2.089×10^-8M)

Kw = 4.36×10^-16

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During this inattentive period, the distance traveled is 73.33 when the speed is 120 km/h and the time taken is 2.2 s.

Every moving object travels a particular distance over time. These two factors enable us to determine the speed. The frequency of displacement is the sole determinant of speed. The complete mobility of an object, regardless of direction, will be its distance. No matter where an object originates or finishes, distance measures how much ground it has travelled. A process, an action, or a condition's duration is the amount of time that can be measured or quantified. Speed is the rate at which an object travels along a path over time, whereas velocity is the speed and direction of an item's motion. In another sense, velocity is a vector, whereas speed is a scalar value. There is a formula that connects these three things. Speed can be thought of as a gauge for a body's rate of motion. The distance covered in a single unit of time is how it is defined.

Speed = Distance/ Time

We are given Average speed, = 120 km/h=(120 * 1000)/3600=33.33 m/s

Time, t=2.2s

Now speed =  Distance/ Time

⇒ Distance = speed * time=33.33*2.2=73.33

Thus distance traveled is 73.33 m

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The differential equation for the concentration of the chemical is given by dc/dt = (3/10⁶)(1 - 100c)

Suppose that a(t) is the amount of chemical in the pond at time t.

So, a'(t) = rate of chemical inflow - the rate of chemical outflow.

So, da/dt = (0.01)300 - (a/10⁶)300

So, da/dt = 3 - 3a/10⁴

Now,

Since, c = a/v

Then, c' = a'/v

So, c' = (3 - 3a/10⁴)/10⁶

Or, c' = 3 (1 - a/10⁴)/10⁶

So, dc/dt = 3/10⁶ (1 - cv/10⁴)

So, dc/dt = (3/10⁶) (1 - 100c)

Therefore the differential equation for the concentration of the chemical is dc/dt = (3/10⁶)(1 - 100c)

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The correct answer is 0.00981 kJ/mol.

Every object we encounter has a binding force, and the energy that holds them together is the binding energy. The binding energy is the least amount of energy necessary to remove an electron, proton, or neutron from the nucleus. A nucleus contains electrons and protons that are strongly bound by energy.

Free energy of binding can be calculated using formula, Gbinding = dE coluombic + dEvdw + dGhyd. -TdS where Evdw+Ecoulombic is protein ligand interaction, dGhyd is change in hydration energy.

dS is entropy. dG hydration is Gpolar+Gnon polar. Inhibition constants are given for CBD and

THC = 4350nm, and 44nM. So,

dG = Ki + Ki' = 44+4350 = 4394 and

in kJ/mol = NahC/4394 = (6.022x10^23x6.626x10^-34x3x10^8)/4394 = 0.00981 kJ/mol

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Reactants are substances that are present at the beginning of a chemical reaction.

Products are the substance(s) to the right of the arrow. A substance that remains after a chemical reaction is complete is known as a product.

Consider the balanced chemical equation:

2H₂O → 2H₂ + O₂

Hydrogen and oxygen are the reactants, and water is the product in the balanced equation.

The reactants and product symbols and formulae are known from the aforementioned equation.

One oxygen molecule and two hydrogen atoms unite to form two water molecules.

The ratio of reactant to product is 2 : 1 : 2.

The total mass of products is equal to the total mass of the reactants according to the law of conservation of mass.

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The thing i observe if  I hold a largest plastic shopping bag square between the light source and the wall is that since the plastic is Translucent, it  allow some measures of light to pass through it.  When light hits the translucent materials, since it is big and little thicker, only some of the light went through them.

As light travels through air as well as into a clear material (such as glass), it speed is altered, and light is said to be reflected and also refracted by the said glass

Note that  Light can pass through some kind of materials, such as glass, water, plastic that is clear and transparent materials.

Therefore, The thing i observe if  I hold a largest plastic shopping bag square between the light source and the wall is that since the plastic is Translucent, it  allow some measures of light to pass through it.  When light hits the translucent materials, since it is big and little thicker, only some of the light went through them.

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From this information, it can be determined that

acceleration of the shot = 56 m/s^2

stoppage time = 0.123s

stoppage path length = 1.37m

The average acceleration while being shot by definition

a = [tex]\frac{\frac{80}{3.6} }{0.4}[/tex] = 56 m/s^2

Assuming that there is a constant acceleration we can determine the path covered during his acceleration as

s = 1/2a (0.4s)^2 = 4.5m

then we can find the stoppage time as

t3 = [tex]\frac{\frac{80}{3.6} }{180}[/tex] = 0.123s

Then the stoppage path length is defined as

s3 = [tex]\frac{(80/3.6)^2}{2a}[/tex] = 1.37m

Then the path length of travel with constant velocity is

s2 = 56.64m -s1 - s2 = 50.77m

Then time of flight

t2 = [tex]\frac{s_{2} }{80/3.6}[/tex] = 2.28s

Then we can determine the total time of flight as

t = t1 + t2 + t3 = 2.8s

Thus, we have

ashot = 56m/s^2

tstop = 0.123s

[tex]\delta x[/tex]stop = 1.37m

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Finding the initial and final values for the quantity that the capacitor or inductor opposes changing—i.e., the quantity that the reactive component is seeking to maintain constant—is the first stage.

This amount is voltage for capacitors and current for inductors. This amount is to be used as the "beginning" value because when the switch in a circuit is closed (or opened), the reactive component will try to keep that quantity at the same level as it was before the switch transition. This quantity's ultimate value is whatever it will be after an infinitely long period of time.

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Two rocket ships approach a space station at 80% of the speed of light. Each pilot observes the other ship approaching at 98% the speed of light.

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Answer:

huhu

chuba bi miayang yo

trip rp rrip trip

Explanation:

how are things going with your family in the car with the family in because or am we supposed for a car to stay at the airport and get a taxi

Finding the common slope of the placement function for the term you're interested by will let you decide the common pace.

the absolute value of velocity is common pace, then again.

average pace and average pace are the same if the arrow constantly actions at a regular tremendous or bad speed. we will first pick out the places of high-quality and negative velocities.

Find the velocity equation first. It is y(derivatives: )'s

y'(t) = v(t) = [tex]66 - 3.72t[/tex]

Next, find the positive and negative values of this:

v(t) = 0 when t = [tex]66/3.72 = 17.74[/tex] seconds.

this means that v(t) is continually fine for all 3-time durations. As a result, all we want to do is calculate the average slope of y(t) during each period.

The average slope equation is made up of the slope between the beginning and finishing points = [tex][f(b) - f(a)]/(b-a)[/tex]:

Therefore, these are the calculations:

(i) vavg = [tex][y(2) - y(1)]/(2-1)[/tex]

(ii) vavg = [tex][y(1.5) - y(1))]/(1.5-1)[/tex]

(iii) vavg = [tex][y(1.1) - y(1)]/(1.1-1)[/tex]

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The moon appears 1.1153 during perigee than at apogee.

Perigee is the point at which the moon is nearest to the Earth each month.

The points of apogee and perigee varies throughout the year.

Apogee is the point at which the moon is farthest to the Earth each month.

from the data given,

perigee= 364000km

Apogee= 407000km

diameter= 3480km

p/a = 406,000/364,000

= 1.1153.

Thus, the moon appears 1.1153 during perigee than at apogee.

In conclusion,  it has been scientifically found that in periods of four years, lunar perigees and apogees fall on the same or nearly the same calendar dates.

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Vector a b = c, and that |al |b| = |cl, vectors a and b oriented with respect to each other because they are perpendicular to each other.

A vector is an object that has both magnitude and a direction. Geometrically, we can picture vector as a directed line segment, whose length is the magnitude of the vector and with an arrow indicating the direction. The direction of vector is from its tail to its head.

Two vectors are the same if they have same magnitude and direction. This means that if we take a vector and translate it to a new position (without rotating it), then vector we obtain at the end of this process is the same vector we had in beginning.

Two examples of vectors are those that represent the force and velocity. Both the force and velocity are in a particular direction. The magnitude of vector would indicate the strength of the force or the speed associated with the velocity.

We denote vectors using the boldface as in a or b. Especially when writing by hand where one cannot easily write in boldface, people will sometimes denote vectors using the arrows , or they use the other markings. We won't need to use the arrows here. We denote magnitude of the vector a by |a|. When we want to refer to a number and stress that it is not a vector, we can call number a scalar. We will denote scalars with the italics, as in a or b.

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Answer:

ambt kaon✌️jhrhriekeieieieiei

Explanation:

iwuejejwiowksj

By unit conversion, the power is 4.023 HP.

We need to know about unit conversion to solve this problem. The unit conversion can be used to convert a unit to another unit. It can be defined as

a = xb

where a is unit a, b is unit b and x is the constant of conversion.

From the question above, we know that

P = 3000 watts

unit conversion

(1 HP = 745.7 watts)

Convert the unit conversion

1 HP = 745.7 watts

divide by 745.7

1/745.7 HP = 1 watts

Convert the aspirin power to horsepower

P = 3000 watts

P = 3000 x 1/745.7 HP

P = 3000/745.7 HP

P = 4.023 HP

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The net magnetic force is 31.4×[tex]10^{-5}[/tex] T.

Data;

a = 1.0cm

b = 3.0cm

i = 30a

B = ?

The magnetic field at point 2 will be

[tex]B_{2}[/tex] = (μI/4[tex]\pi[/tex][tex]R^{2}[/tex]) ×Ф

[tex]B_{2}[/tex] = [tex]47.1[/tex]×[tex]10^{-5}[/tex] T

The magnetic field due at point 4 will be

[tex]B_{4}[/tex] = (μI/4[tex]\pi[/tex][tex]R^{2}[/tex]) ×Ф

[tex]B_{4}[/tex] = [tex]15.7[/tex]×[tex]10^{-5}[/tex] T

The direction of magnetic field due to 2 and 4 are in the opposite direction.

The Net magnetic force is

B =  [tex]47.1[/tex]×[tex]10^{-5}[/tex] - [tex]15.7[/tex]×[tex]10^{-5}[/tex]

B = 31.4×[tex]10^{-5}[/tex] T

One of the four fundamental forces of nature, the electromagnetic force, results in the magnetic force, which is brought about by the motion of charges. When two charge-containing objects move in the same direction, a magnetic attraction pulls them together.

A magnetic field, a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. When a charge moves through a magnetic field, a force that is perpendicular to both its own velocity and the magnetic field operates on it. A permanent magnet's magnetic field pulls on ferromagnetic materials like iron and draws or repels other magnets.

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NO, It is an Right Triangle

p(2 , - 1 0)  Q ( 4,  1, 1)  R( 4, -5, 4)

PQ2  =  ( 2 -4)^2 + (-1-1)^2 +( 0-1)^2

PQ^2= (4 + 4  +1 )=9

PQ = 3  

QR^2 = ( 4 - 4)^2 + ( 1 +5)^2 + ( 1-4 )^2

=  0 + 36 + 9  =45

QR = √45 =3√5

RP^2 =  ( 4-2)^2 + ( -5 +1)^2 + (4-0)^2

 =  4 + 16 + 16 = 36

   RP = 6

 LENGTH  OF  SIDES ARE   3 ,6 ,  3√5

and  ajsoPQ^2 + RP^2  = 9 + 36 = 45 =QR^2

PQR   is a  right  angle  triangle

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4 time constants must elapse if an initially charged capacitor is to discharge 55% of its stored energy through a resistor.

What do you understand by the term capacitor?

What is a capacitor used for?

How many types of capacitors are there?

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Answer:

is an early warning sign of infection

Explanation:

it allows organs and bodily proccess to work effectively

Answer:

increase!!!

M V R        describes the angular momentum of mass M

If R is decreased for a given mass M then the velocity must increase to account for the angular momentum being a constant (conserved).

The first quarter in which half the Moon appears illuminated, occurs when the Moon is at a right angle with respect to the Sun when viewed from the Earth.

The Moon is a non illuminating celestial object and doesn't have its own light but reflects the light of the sun and with change in angle between moon and Sun the different phases of the moon appear as seen from earth.

Given:

The Moon is in the first quarter of illumination.

In the first quarter of the moon the only one-fourth of the sun is illuminated and is observable from earth.

For this to happen only the visibly i.e. one-fourth of the moon should be reflecting back the light of the sun.

For this to happen the moon shouldn't be completely opposite to the sun behind the earth. But rather at right angles with respect to the sun when seen from earth.

Therefore, The first quarter in which half the Moon appears illuminated, occurs when the Moon is at a right angle with respect to the Sun when viewed from the Earth.

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The person that practicing yoga for one hour burns 285 kilocalories (kcal) burned: 1192440 j of energy

To solve this problem the we have to do the conversion of units with the given information.

Information about the problem:

By converting the energy units from kilocalories (kcal) to joules (j) we have:

energy =285  kcal * 4184 j/ 1 kcal

energy = 1192440 j

It is the transformation of a value expressed in one unit of measurement into an equivalent value expressed in another unit of measurement of the same nature.

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To compare the magnitude of flux through the surface wherein the cylinder in 2 has twice the radius and half the length compared to the cylinder in case 1 and this comparison in magnitude is given as ϕ= 2ϕ.

The charge density can be defined as a measurement of the amount of electric charge that is present per unit of surface area, body volume, or field.

The amount of charge that is held in a specific field is determined by the charge density. It is absolutely possible to calculate charge density of an object in terms of length, area, or volume.

If q is taken as the charge and l is the distance that it travels, then q/l is the formula for the linear charge density, and the S.I. Coulombs per meter (cm1) is the unit used to measure linear charge density.

The general response is most conveniently expressed in terms of the linear charge density, which is equal to Q/L for a finite rod of length L and total charge Q.

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The direction of velocity is 81.12°

Given that,

Since it is a right angled triangle,

tan θ = Opposite side / Adjacent side

tan θ = Total vertical velocity/ Total horizontal velocity

tan θ = 7714.9 / 1204.9 = 6.4

θ = [tex]tan^{-1}[/tex] ( 6.4 )

θ = 81.12 °

Therefore, the direction of its velocity is 81.12° with respect to x - axis.

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The width of central maximum increases if the wavelength is increased.

The width of the central maximum is simply the distance between 1st order minima from the center of the screen on both sides. Thus, the central maximum becomes twice as wide if the slit width a becomes half as wide.

For one slit experiment, the size(angular width) of the central maximum is given by a 2 λ a , where a is that the slit width. therefore the width of the central maximum is directly proportional to the wavelength of light and inversely proportional to slit width.

A central maximum is that the brightest central zone of a diffraction pattern on the screen. The central maximum has the utmost intensity and widest of all the other diffraction fringes

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