in (x-2)+in(x+1)=2
x = -2.6047
x = 4.2312
x = 3.652
x = 3.6047

The general solution of the given differential equation is:
r cos(y) = -(x+1)^2 + Ax + B, where A and B are constants.

To find the general solution of the given differential equation, we can use the method of separation of variables.
First, we can separate the variables by dividing both sides by (x+1)^2 and multiplying by dx:

r sin(y) dy/(x+1)^2 = dx

Next, we can integrate both sides:

∫ r sin(y) dy/(x+1)^2 = ∫ dx

Using the substitution u = x+1 and du = dx, we get:

∫ r sin(y) dy/u^2 = ∫ du

Integrating both sides again, we get:

- r cos(y)/u + C = u + D

where C and D are constants of integration.

Substituting back u = x+1, we get:

- r cos(y)/(x+1) + C = x+1 + D

Rearranging, we get:

r cos(y) = -(x+1)^2 + Ax + B

where A = C+1 and B = D-C-1 are constants.

Thus, the general solution of the given differential equation is:

r cos(y) = -(x+1)^2 + Ax + B, where A and B are constants.

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There is 95% confidence that the difference of the proportions is in the interval. Conclude that there is insufficient evidence of a significant difference in the proportion of males and females that have at least one tattoo. The 95% confidence interval for p1- p2 is (-0.029, 0.053). So, the correct answer is A).

First, we need to calculate the sample proportions for each group

p1 = 182/1211 = 0.150

p2 = 144/1041 = 0.138

The point estimate for the difference in proportions is p1 - p2 = 0.150 - 0.138 = 0.012

The standard error for the difference in proportions is

SE = √((p1(1-p1)/n1) + (p2(1-p2)/n2))

SE = √((0.150(1-0.150)/1211) + (0.138(1-0.138)/1041))

SE = 0.021

Using a 95% confidence level and a z-score of 1.96 for a two-tailed test, we can calculate the margin of error

ME = 1.96 * 0.021 = 0.041

Therefore, the 95% confidence interval for p1 - p2 is

0.012 - 0.041 < p1 - p2 < 0.012 + 0.041

-0.029 < p1 - p2 < 0.053

The interpretation of the interval is option (a): There is 95% confidence that the difference of the proportions is in the interval. Conclude that there is insufficient evidence of a significant difference in the proportion of males and females that have at least one tattoo.

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Rounding to the nearest cent, Sasha will pay $35.10 in interest this month. Therefore, the correct answer is option A.

To calculate the interest that Sasha will pay, we need to use the following formula:

Interest = (Balance * APR * Days in a billing cycle) / 365

where Balance is the amount owed after the payment, APR is the annual percentage rate, and Days in the billing cycle are the number of days in the billing cycle.

Since we do not know the number of days in the billing cycle, we will assume it to be 30 days for simplicity. Therefore, the balance owed after the payment is:

Balance = $3200 - $300 = $2900

Substituting the values into the formula, we get:

Interest = ($2900 * 0.1875 * 30) / 365

= $35.09

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The matrix 2x2 of A is:

[20  30]
[ 0 -15]

What is the eigenvector?

The eigenvector is a vector that is associated with a set of linear equations. The eigenvector of a matrix is also known as a latent vector, proper vector, or characteristic vector. These are defined in the reference of a square matrix.

To solve this problem, we need to use the fact that a matrix can be diagonalized only if it has a set of linearly independent eigenvectors.

First, we need to find the eigenvectors and eigenvalues of the matrix. Let A be the matrix we want to find.

We know that [2 3] is an eigenvector of A with eigenvalue 10, so we have:

A[2 3] = 10[2 3]

Multiplying out the matrices, we get:

[2 3] [a b] = [20 30]

where a and b are the unknown entries of A. Solving this system of equations, we get a = 5 and b = 10. Therefore, the matrix A is:

[5 10]
[0 3]

Now, we need to check if [0 3] is also an eigenvector of A with eigenvalue -5:

A[0 3] = -5[0 3]

[5 10] [0 3] = [0 -15]

Multiplying out the matrices, we get:

[0 30] = [0 -15]

This is a contradiction since the two matrices are not equal. Therefore, [0 3] is not an eigenvector of A with eigenvalue -5.

In summary, the matrix A that satisfies the given conditions is:

[5 10]
[0 3]

with eigenvectors [2 3] and [0 1] and eigenvalues 10 and 3, respectively.
To find a 2x2 matrix with eigenvectors [2, 3] and [0, 3] and eigenvalues 10 and -5, respectively, follow these steps:

Step 1: Associate the eigenvectors with their respective eigenvalues:
- Eigenvector [2, 3] has eigenvalue 10.
- Eigenvector [0, 3] has eigenvalue -5.

Step 2: Write the eigenvalue-eigenvector equations:
- 10 * [2, 3] = A * [2, 3]
- (-5) * [0, 3] = A * [0, 3]

Step 3: Expand the equations:
- 10 * [2, 3] = [20, 30]
- (-5) * [0, 3] = [0, -15]

Step 4: Create the matrix A using the expanded equations:
A = [20, 30; 0, -15]

So, the 2x2 matrix A is:
[20  30]
[ 0 -15]

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Answer:

  4 ft³

Step-by-step explanation:

Given similar pyramids with heights 12 ft and 4 ft, you want the volume of the smaller when the volume of the larger is 256 ft³.

The scale factor for volume is the cube of the scale factor for linear dimensions. The height of the smaller pyramid is 1/4 the height of the larger, so its volume will be (1/4)³ = 1/64 times that of the larger.

The volume of Pyramid B is (1/64)(256 ft³) = 4 ft³.

The fundamental period of [n] is N=72

(a) z(t) = 0 is a constant signal, which means it does not vary with time. A constant signal is not periodic because it does not repeat over time. Therefore, z(t) = 0 is not periodic.

(b) [n] = 1 sin[n] + 4 cos[-] 72- is a discrete-time signal, which means it is defined only at integer values of n. To determine whether it is periodic, we need to check whether there exists a positive integer N such that [n] = [n+N] for all integer values of n.

Using trigonometric identities, we can simplify [n] as follows:

[n] = 1 sin[n] + 4 cos[-] 72-
   = 2 sin[36-] cos[-] 36- + 2 cos[36-] sin[n]

Next, we can rewrite [n+N] using the same trigonometric identities:

[n+N] = 2 sin[36-] cos[-] 36- + 2 cos[36-] sin[n+N]

For [n] to be periodic with period N, [n] must be equal to [n+N] for all integer values of n. This means that the two expressions above must be equal for all n, which in turn means that sin[n] must be equal to sin[n+N] and cos[n] must be equal to cos[n+N] for all n.

Since sin and cos are periodic with period 2π, this condition is satisfied if and only if N is a multiple of 72, which is the least common multiple of 36 and 72. Therefore, the fundamental period of [n] is N=72.

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The sum of all the three angles of a triangle is 180°.

x + x + 26.35° = 180°

2x = 180° - 26.35°

x = 76.825°.

Therefore, ∠P will be equal to 76.825°.

Answer:

∠P = 76.825°

Step-by-step explanation:

If angles P and Q are congruent, then triangle PQR is an isosceles triangle where ∠P and ∠Q are the base angles and ∠R is the apex angle.

The interior angles of a triangle sum to 180°. Therefore:

⇒ ∠P + ∠Q + ∠R = 180°

As ∠P = ∠Q and ∠R = 26.35°, then:

⇒ ∠P + ∠P + 26.35° = 180°

⇒ 2∠P + 26.35° = 180°

⇒ 2∠P + 26.35° - 26.35° = 180° - 26.35°

⇒ 2∠P = 153.65°

⇒ 2∠P ÷ 2 = 153.65° ÷ 2

⇒ ∠P = 76.825°

Therefore, the measure of angle P is 76.825°.

To use the unit circle to find the exact value of sin(330°), we can follow these steps:

        330° - 300° = 30°

Since the reference angle is 30°, the corresponding point is located on the terminal side of the angle formed by rotating 30° counterclockwise from the positive x-axis. This point has coordinates of (cos(30°), sin(30°)), which are (√3/2, 1/2).

Use the sign of the trig function in the appropriate quadrant to determine the final value of sin(330°). Since 330° is in the fourth quadrant and the sine function is negative in the fourth quadrant, sin(330°) = -sin(30°) = -1/2.

Therefore, the exact value of sin(330°) is -1/2.

The solution is:

A) Deceleration of the car is -6.6667 m/s² while it came to stop.

B) The total distance the car travels is 200 meter during the 10 s period.

Here, we have,

Explanation:

Given Data

Initial velocity of the car () =   20.0 m/s

Final velocity of the car () = 0 m/s

Time (in motion) =7.00 s

Time (in rest) =3 s

To find - A) car's deceleration while it came to a stop

             B) the total distance the car travels in 10 s

A) The formula to find the deceleration is

Deceleration = (( final velocity - initial velocity ) ÷ Time)        (m/s²)

Deceleration = (() - ()) ÷ time     (m/s²)

Deceleration =  ( 0.0 - 20 ) ÷ 3      (m/s²)

Deceleration =   (- 20) ÷ 3  (m/s²)

Deceleration   =  - 6.6667 m/s²

(NOTE : Deceleration is the opposite of acceleration so the final result must have the negative sign)

The car's deceleration is  - 6.6667 m/s² while it came to a stop

B) The formula to find the distance traveled by the car is  

Distance traveled by the car is equals to the product of the speed and time

Distance = Speed × Time  (meter)

Distance = 20.0 × 10

Distance = 200 meters

The total distance the car travels during the period of 10 s is 200 meters.

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complete question:

A car is traveling at a 20.0 m/s for 7.00 s and then suddenly comes to a stop over a 3 s period.

a. What was the car’s deceleration while it came to a stop?

b. What is the total distance the car travels during the 10 s period?

Step-by-step explanation:

See image:

The area of the circle with a circumference of 6pi m is 9π square meters.

A circle is simply a closed 2-dimensional curved shape with no corners or edges.

The area of a circle is expressed mathematically as;

A = πr²

The circumference of a circle is expressed as:

C = 2πr

Where r is radius and π is constant pi.

We are given that the circumference of the circle is 6π m, so we can set up the equation and solve for the radius.

C = 2πr

6π = 2πr

Simplifying, we get:

r = 6π/2π

r = 3

Now that we know the radius of the circle, we can use the formula for the area of a circle:

A = πr²

Substituting the value of r, we get:

A = π(3)²

Simplifying, we get:

A = 9π

Therefore, the area is 9π m.

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1) The statement "When dummy coding qualitative variables, the level with the lowest mean value should always be the base level" is FALSE.

2) we will not divide the p-value by 2.

1. Dummy coding qualitative variables: The statement "When dummy coding qualitative variables, the level with the lowest mean value should always be the base level" is FALSE. The choice of the base level in dummy coding is arbitrary, and it does not have to be the level with the lowest mean value.

2. Testing a quadratic model: Since you are unsure whether the curvature would be negative or positive, the appropriate alternative hypothesis is that the beta for the quadratic term is not equal to zero (i.e., it has an effect). In this case, you will perform a two-tailed test, which means you will not divide the p-value by 2.

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A.Hence proved dy/dx = (2x - 5y)/(5x + 2y). B. The slope of the tangent line at any point on the curve when x=2 is given by (4-5y)/(10+2y). C. The curve has a vertical tangent line at x = 5/√29. D. The x-axis is increasing at a rate of 60 square units per unit time at time t=3. D. The value of da/dt at time t=3 is 60.

A. To show that dy/dx = (2x-5y)/(5x+2y), we differentiate the given equation with respect to x using implicit differentiation:

2x - 2y(dy/dx) - 5y - 5x(dy/dx) = 0. Simplifying and solving for dy/dx, we get:

dy/dx = (2x - 5y)/(5x + 2y)

B. To find the slope of the line tangent to the curve at each point when x=2, we substitute x=2 into the expression we derived in part A:

dy/dx = (2(2) - 5y)/(5(2) + 2y) = (4-5y)/(10+2y)

C. To find the positive value of x at which the curve has a vertical tangent line, we need to find where the slope dy/dx becomes infinite. This occurs when the denominator of dy/dx equals zero, which is when: 5x + 2y = 0

Solving for y in terms of x, we get:

y = (-5/2)x

Substituting this into the equation for the curve, we get:

[tex]x^2 - (-5/2)x^2 - 5x(-5/2)x = 25[/tex]

Simplifying and solving for x, we get:

[tex]x = 5/√29[/tex]

or

[tex]x = -5/√29[/tex]

D. To find the value of da/dt at time t=3, we first use the chain rule to get:

2x(dx/dt) - 2y(dy/dt) - 5y(dx/dt) - 5x(dy/dt) = 0. We are given that x=5, y=0, and dy/dt=-2 when t=3. Substituting these values into the equation above and solving for dx/dt, we get:

dx/dt = (5dy/dt)/(2x-5y) = -10/25 = -2/5 Substituting these values into the expression for da/dt, we get:

[tex]da/dt = 2(5)^2 - 2(0)^2 - 5(0)(-2/5) - 5(5)(-2) = 60[/tex]

So the value of da/dt at time t=3 is 60. This means that the area enclosed by the curve.

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The surface area of the triangular prism is 75 ft squared.

The prism is a triangular base prism. The surface area of the prism can be found as follows:

surface area of the prism = (a + b + c)l + bh

where

Therefore,

a = 2 ft

b = 1.5 ft

c = 2.5 ft

l = 12 ft

Hence,

Surface area of the triangular prism = (2 + 1.5 + 2.5)12 + 2(1.5)

Surface area of the triangular prism = 6(12) + 3

Surface area of the triangular prism = 72 + 3

Surface area of the triangular prism = 75 ft²

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The number of minutes she would practice in 4 weeks is 1288

From the question, we have the following parameters that can be used in our computation:

Practices the piano 1610 minutes in 5 weeks

This means that

Rate = 1610/5

For 4 weeks, we have

Minutes = 1610/5 * 4

Evaluate the product

Minutes = 1288

Hence, the minutes is 1288

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The measure of the missing angle in the right triangle rounded to the nearest 10 or the tens Place is 20°.

The figure in the image is a right triangle.

Measure of missing angle = θ

Opposite to angle θ = 8

Adjacent to angle θ  = 20

To solve for the missing angle, we use the trigonometric ratio.

Note that: tangent = opposite / adjacent

Hence:

tangent θ = opposite / adjacent

tan(θ) = 8/20

tan(θ) = 2/5

Take the tan inverse

θ = tan⁻¹( 2/5 )

θ = 21.8014°

Rounding to the nearest 10 or the tens Place.

θ = 20°

Therefore, the missing angle is 20°.

Option C) 20° is the correct answer.

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The sum of money that will grow to $2,324.61 in two years at a 4% interest rate compounded quarterly is $2,145.00.

Sum of money that will grow to $2,324.61 in two years at a 4% interest rate compounded quarterly, we will use the formula for compound interest:

Future Value = Principal * (1 + (Interest Rate / Number of Compounds))^ (Number of Compounds * Time)

Here, we need to find the Principal amount. The given values are:
- Future Value = $2,324.61
- Interest Rate = 4% = 0.04
- Number of Compounds per year = 4 (quarterly)
- Time = 2 years

Rearranging the formula to find the Principal:

Principal = Future Value / (1 + (Interest Rate / Number of Compounds))^ (Number of Compounds * Time)

Substitute the values into the formula:

Principal = 2324.61 / (1 + (0.04 / 4))^(4 * 2)

Principal = 2324.61 / (1 + 0.01)^8
Principal = 2324.61 / (1.01)^8
Principal = 2324.61 / 1.082857169

Principal = $2,145.00 (rounded to the nearest cent)

The sum of money that will grow to $2,324.61 in two years at a 4% interest rate compounded quarterly is $2,145.00.

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Yes, I do agree that Kelly can't put a right triangle in either of the groups because it does not have two pairs of parallel sides.

In Mathematics and Geometry, a right angle can be defined as a type of angle that is formed in a triangle by the intersection of two (2) straight lines at 90 degrees. This ultimately implies that, a right angled triangle has a measure of 90 degrees.

Based on the Venn diagram shown in the image attached below, we can reasonably infer and logically deduce that Kelly was correct by saying can't put a right triangle or right angled triangle in either of the groups because it does not have two pairs of parallel sides.

However, Kelly can put a square or rectangle in either of the groups because they have two pairs of parallel sides.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The student who cut his time by the greatest percentage is

Student B.

We have,

Students A's time decreased by 0.125

= 0.125 x 100

= 12.5%

Student B's decreased by 1/6 which in decimal is

= 1/6

= 0.16667

= 16.66667%

and, Students C's time decreased by 15%.

= 15/100

= 0.15

Thus, the student who cut his time by the greatest percentage is

Student B.

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The sample data to estimate the population parameter with a certain degree of confidence.

Hypothesis testing is a statistical inference technique used to determine if a hypothesis about a population parameter is supported by the sample data. The hypothesis testing procedure consists of several steps:

State the null hypothesis and the alternative hypothesis: The null hypothesis (H0) is the hypothesis that there is no significant difference between the sample data and the population parameter. The alternative hypothesis (Ha) is the hypothesis that there is a significant difference between the sample data and the population parameter.

Choose a significance level: The significance level (α) is the probability of rejecting the null hypothesis when it is actually true. A commonly used significance level is 0.05.

Collect the sample data: The sample data should be collected randomly and should be representative of the population.

Calculate the test statistic: The test statistic is a numerical value calculated from the sample data that measures how well the sample data support the null hypothesis.

Determine the p-value: The p-value is the probability of obtaining a test statistic as extreme or more extreme than the one calculated from the sample data, assuming the null hypothesis is true.

Make a decision: If the p-value is less than the significance level, reject the null hypothesis and accept the alternative hypothesis. If the p-value is greater than or equal to the significance level, fail to reject the null hypothesis.

To give an example, let's say we want to determine if the mean weight of apples produced by a particular orchard is different from 150 grams. We collect two random samples of apples, each with a sample size of 50. We set up the hypothesis as follows:

H0: μ = 150

Ha: μ ≠ 150

We choose a significance level of 0.05. We calculate the test statistic as follows:

t = (x - μ) / (s / sqrt(n))

where x is the sample mean, μ is the population mean, s is the sample standard deviation, and n is the sample size.

Let's say we get a t-value of 2.5 and a p-value of 0.015. Since the p-value is less than the significance level, we reject the null hypothesis and conclude that there is sufficient evidence to suggest that the mean weight of apples produced by the orchard is different from 150 grams. We can then use the sample data to estimate the population parameter with a certain degree of confidence.

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We can conclude that for all integers a and b, if a|b, then a ≤ b.

To prove that for all m and n, if m ≠ n, then m+n ≠ Q, we will use proof by contradiction.

Assume that for some m and n, m ≠ n, and m+n = Q, where Q is a rational number. By the definition of a rational number, Q can be expressed as the ratio of two integers, p and q, where q ≠ 0.

Thus, we have:

m + n = p/q

Multiplying both sides by q, we get:

mq + nq = p

Rearranging, we get:

mq = p - nq

Since p, n, and q are integers, p - nq is also an integer. Therefore, mq is an integer.

But we know that m and n are integers and m ≠ n, which implies that m and n have different prime factorizations. Therefore, mq cannot be an integer, as it would require m and q to have a common factor, which is not possible.

This contradicts our assumption that m+n = Q, and hence, we can conclude that for all m and n, if m ≠ n, then m+n ≠ Q.

To prove that for all integers a and b, if a|b, then a ≤ b, we will use direct proof.

Assume that a and b are integers such that a|b, i.e., there exists an integer k such that b = ak.

To prove that a ≤ b, we need to show that a is less than or equal to k times a, i.e., a ≤ ka.

Dividing both sides of the equation b = ak by a (which is possible as a ≠ 0 since it is a divisor of b), we get:

b/a = k

Since k is an integer, we know that b/a is also an integer. Therefore, a must be less than or equal to b/a.

Multiplying both sides of the inequality a ≤ b/a by a (which is a positive number since a > 0), we get:

[tex]a^2 ≤ ab[/tex]

Since a and b are both positive integers, we know that [tex]a^2 ≤[/tex] ab implies that [tex]a ≤ b[/tex].

Therefore, we can conclude that for all integers a and b, if a|b, then a ≤ b.

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The median wait time for the speed slide is 2 times longer than the median wait time for the wave machine.

No, There is a lot of overlap between the two data sets.

We have,

Box plots:

Speed side

Median = 11

First quartile = 6

Third quartile = 12

IQR = 12 - 6 = 6

Wave machine

Median = 9

First quartile = 8

Third quartile = 14

IQR = 14 - 8 = 6

Now,

Difference between the median.

= 11 - 9

= 2

Now,

From the box plots, the wait time for the wave machine is longer than the speed side.

Thus,

The median wait time for the speed slide is 2 times longer than the median wait time for the wave machine.

No, There is a lot of overlap between the two data sets.

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The smallest amount of coconuts in the original pile is 19141.

Let N be the original number of coconuts in the pile. We want to find the smallest possible integer of N.

After the first sailor takes his share, there are 4/5N coconuts left in the pile. He throws one coconut to the monkey, leaving 4/5N - 1 coconuts.

The second sailor takes one fifth of the remaining coconuts, which is

(1/5)(4/5N - 1) = 4/25N - 1/5.

After he throws one coconut to the monkey, there are

(4/5)(4/25N - 1) = 16/125N - 4/25 coconuts left.

The third sailor takes one fifth of the remaining coconuts, which is

(1/5)(16/125N - 4/25) = 16/625N - 4/125.

After he throws one coconut to the monkey, there are

(4/5)(16/625N - 4/125) = 64/3125N - 16/625 coconuts left.

The fourth sailor takes one fifth of the remaining coconuts, which is

(1/5)(64/3125N - 16/625) = 64/15625N - 16/3125.

After he throws one coconut to the monkey, there are

(4/5)(64/15625N - 16/3125) = 256/78125N - 64/15625 coconuts left.

The fifth sailor takes one fifth of the remaining coconuts, which is

(1/5)(256/78125N - 64/15625) = 256/390625N - 64/78125.

After he throws one coconut to the monkey, there are

(4/5)(256/390625N - 64/78125) = 1024/1953125N - 256/390625 coconuts left.

Finally, the remaining coconuts are divided into 5 equal piles, so each sailor gets

(1024/1953125N - 256/390625)/5 = 2048/9765625N - 512/1953125 coconuts.

We want this fraction to be a whole number, so we set the denominator equal to the numerator:

2048/9765625N - 512/1953125 = 2048/9765625N

Simplifying, we get 512/9765625N = 512/N

Multiplying both sides by N, we get 512 = 9765625/n

Solving for N, we get N = 9765625/512 = 19140.42969

Since N must be a whole number, we round up to N = 19141.

Therefore, the smallest possible integer of coconuts in the original pile is 19141.

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[tex](Ax^2 + 4Ax + 2B)e^x + (2A + B + Ce^x) - 2((Ax^2 + 2Ax + B)e^x + (B + Ce^x)) - 3(Ax^2e^x + Bxe^x + Ce^[/tex]

We can use the method of undetermined coefficients to find particular solutions to these

differential equations.

For y" - [tex]3y' + 2y = (e^3x (1 + x)[/tex], we assume a particular solution of the form y_p = Ae^3x(1 + x) + Bx^2 + Cx + D. Then, [tex]y_p' = 3Ae^3x(1 + x) + 2Bx + C[/tex]and y_p" [tex]= 9Ae^3x + 2B[/tex]. Substituting these into the differential equation, we get:

[tex]9Ae^3x + 2B - 9Ae^3x - 6Ae^3x - 3Ae^3x + 3Ae^3x(1 + x) + 2Bx + Cx + D = e^3x(1 + x)[/tex]

Simplifying and collecting like terms, we get:

[tex](3A + 2B)x + Cx + D = e^3x(1 + x)[/tex]

Matching coefficients, we have:

3A + 2B = 0

C = 1

D = 0

Solving for A and B, we get:

A = -2/9

B = 3/4

Therefore, a particular solution is [tex]y_p = (-2/9)e^3x(1 + x) + (3/4)x^2 + x[/tex].

For [tex]y" - 6y' + 5y = e^-3[/tex]x([tex]35 - 8x[/tex]), we assume a particular solution of the form [tex]y_p = Ae^-3x + Bx + C[/tex]. Then, [tex]y_p' = -3Ae^-3x + B[/tex] and [tex]y_p" = 9Ae^-3x[/tex]. Substituting these into the differential equation, we get:

[tex](9A + B)x + (-6A - 6B + C) = e^-3x(35 - 8x[/tex]

Simplifying and collecting like terms, we get:

[tex](9A + B)x + (-6A - 6B + C) = e^-3x(35 - 8x[/tex])

Matching coefficients, we have:

9A + B = 0

-6A - 6B + C = 35

Solving for A, B, and C, we get:

A = -5/27

B = 15/27 = 5/9

C = 290/27

Therefore, a particular solution is y_p [tex]= (-5/27)e^-3x + (5/9)x + 290/27.For y" - 2y' - 3y = e^x[/tex] [tex](-8 + 3x)[/tex], we assume a particular solution of the form [tex]y_p = Ax^2e^x + Bxe^x + Ce^x. Then, y_p' = (Ax^2 + 2Ax + B)e^x + (B + Ce^x) and y_p" = (Ax^2 + 4Ax + 2B)e^x + (2A + B + Ce^x)[/tex]. Substituting these into the differential equation, we get:

[tex](Ax^2 + 4Ax + 2B)e^x + (2A + B + Ce^x) - 2((Ax^2 + 2Ax + B)e^x + (B + Ce^x)) - 3(Ax^2e^x + Bxe^x + Ce^[/tex]

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The number of MAD's that represents the difference of the means of each data-set is given as follows:

C. 0.2

The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations, which is also called the cardinality of the data-set.

Hence, for the first period, the mean is obtained as follows:

Mean = (3 x 0 + 4 x 1 + 5 x 2 + 2 x 3 + 1 x 4)/(3 + 4 + 5 + 2 + 1)

Mean = 1.6.

For the second period, the mean is obtained as follows:

Mean = (4 x 0 + 5 x 1 + 4 x 2 + 0 x 3 + 2 x 4)/(4 + 5 + 4 + 0 + 2)

Mean = 1.4.

The difference is then given as follows:

1.6 - 1.4 = 0.2 -> which is 0.2 MADs, as MAD = 1.

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If  number has the digit nine in seven to the nearest 10 the number rounds to 100 then the number is 97.

If rounding the number to the nearest 10 results in 100, it means the original number is between 95 and 105. Also, we know that the number has the digit nine in the tens place, since it rounds up to 100.

To find the number, we can consider the possible values for the units digit. If the units digit is 0, then the number is 90, which does not have a 9 in the tens place.

If the units digit is 1, then the number is 91, which also does not have a 9 in the tens place.

If the units digit is 2, then the number is 92, which also does not have a 9 in the tens place.

If the units digit is 3, then the number is 93, which does not have a 9 in the tens place.

If the units digit is 4, then the number is 94, which does not have a 9 in the tens place.

If the units digit is 5, then the number is 95, which does not have a 9 in the tens place.

If the units digit is 6, then the number is 96, which does not have a 9 in the tens place.

If the units digit is 7, then the number is 97, which does have a 9 in the tens place.

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There are 816 triangles that can be formed using diagonals from a common vertex of a 19-gon.

The number of available vertices that are not adjacent to the vertex in question is 18, and we have the freedom to pick three of them by selecting from a pool of 18C3 options. Nevertheless, as we disregard the order in which these vertices are selected, their sequence must be divided by 3!.

As such, the total count for possible triangles formed using diagonals originating at the same vertex in a 19-gon is:

The triangles that would be formed is given as  816 triangles

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1.The first statement "Let S = {a, v, c, x, y}. Then {v, x} ∈ S." is false.
This is because {v, x} is a subset of S, not an element, so it should be {v, x} ⊆ S, not {v, x} ∈ S.

2. The statement "Let |B| = 6, then the number of all subsets of B is 36." is false.
This is because the number of subsets of a set with |B| elements is 2^|B|. So, in this case, there are 2^6 = 64 subsets, not 36.

3. If the set B = {1, 2, a, b, c}, then the cardinality |B| is :
|B| = 5
This is because the cardinality of a set is the number of elements in the set. B has 5 elements: {1, 2, a, b, c}.

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The value of probability that a customer wins a prize is,

⇒ 12.5%

We have to given that;

A jewelry store has each customer spin a spinner with 8 equal sections numbered 1, 1, 1, 2, 2, 3, 3, 4 to win a free bracelet.

And, Customers who spin a 4 win.

Now, We have;

Total outcomes = 8

And, Possible outcomes for who spin a 4 win is,

⇒ 1

Hence, The value of probability that a customer wins a prize is,

⇒ 1 / 8

⇒ 1/8 x 100%

⇒ 12.5%

Thus, The value of probability that a customer wins a prize is,

⇒ 12.5%

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The hypothesis that the variance in the number of patients seen per day is equal to 10 cannot be rejected  based on the given data and using a level of significance of 0.05.

To determine if the variance in the number of patients seen per day is equal to a specific value, we can conduct a hypothesis test. Let's assume the null hypothesis is that the variance is equal to the specified value, and the alternative hypothesis is that the variance is not equal to the specified value.

We can use a chi-square test to test this hypothesis, where the test statistic is calculated as (n-1)*s²/σ², where n is the sample size, s² is the sample variance, and σ² is the hypothesized population variance. This test statistic follows a chi-square distribution with n-1 degrees of freedom.

Using a level of significance of 0.05, with 9 degrees of freedom (since there were 10 observations), the critical value for the chi-square distribution is 16.92.

Calculating the sample variance from the given data, we get s^2 = 4.44. Assuming the hypothesized population variance is 10, the test statistic is (9)*4.44/10 = 4.00.

Since the test statistic (4.00) is less than the critical value (16.92), we fail to reject the null hypothesis. Therefore, there is not enough evidence to conclude that the variance in the number of patients seen per day is not equal to 10.

In conclusion, based on the given data and using a level of significance of 0.05, we cannot reject the hypothesis that the variance in the number of patients seen per day is equal to 10.

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