Indicate if the following pairs of compounds could be separated via liquid-liquid extraction.First, draw the structures of the compounds, next determine whether they are acids or bases or neutral. Finally, look up their pKa (or pKb) values and indicate which aqueous solution would separate them or if they are inseparable. Assume that you can utilize aqueous HCl, NaOH, or NaHCO3 for your extractions. For each case that will not work, give the reason.You don't have to draw structure, just explain if they are able to be separated or not and with what and why.1. picric acid and phenol2. salicyclic acid and phenol3. triethylamine and diethylamine4. 3-nitrobenzoic acid and 2-nitrobenzoic acid5. benzylamine and aniline

The equilibrium constant (Kc) is the ratio of the concentration of the products to the reactants at equilibrium. The value of Kc changes with the temperature but is constant at a given temperature.

The expression for the equilibrium constant Kc can be defined as follows:-

Kc = [C]^c[D]^d/[A]^a[B]^b

where [ ] denotes the molar concentration of the respective species. a, b, c, and d are the coefficients of the balanced chemical equation for the species A, B, C, and D.

If a chemical reaction is at equilibrium at a given temperature, the concentration of reactants and products remains constant over time. In other words, the rate of the forward reaction and the rate of the reverse reaction is equal.

The reaction for which we need to find the equilibrium constant is:-

HI(g)  ↔ H(g) + I(g)

Now, assume that initially there were 'x' moles of HI in the reaction mixture. After the dissociation of HI, the concentration of H and I will be equal to 'x - y' moles. The concentration of HI will be equal to 'x - y' moles.

Here, y is the number of moles of HI that dissociated. According to the given statement, HI is 40% dissociated. Therefore, the number of moles of HI that dissociated will be 0.4x. Similarly, the number of moles of H and I that will be formed will also be 0.4x.

The equation for the dissociation of HI can be written as:-

HI(g)  ↔ H(g) + I(g)

The initial number of moles = x Moles dissociated = 0.4x

At equilibrium, the number of moles of HI = x - 0.4x = 0.6x

Number of moles of H = 0.4x

Number of moles of I = 0.4x

Finally, substitute these values in the expression for the equilibrium constant:-

Kc = [H][I]/[HI]

Kc = (0.4x)(0.4x)/(0.6x)²

Kc = 0.16/0.36Kc = 0.4444 (approximately)

Therefore, the equilibrium constant Kc for the given reaction is 0.4444 (approximately).

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The principal organic product formed in the reaction of ethylene oxide with sodium cyanide (NaCN) in aqueous ethanol is ethylene cyanohydrin ([tex]C_{2}H_{5}CN[/tex]). The reaction follows this general reaction scheme:

Ethylene oxide + NaCN     →   Ethylene cyanohydrin + NaOH

The principal organic product formed in the reaction of ethylene oxide with sodium cyanide (NaCN) in aqueous ethanol is ethyl nitrile ([tex]C_{2}H_{5}CN[/tex]).

What is Ethyl nitrile?

Ethyl nitrile is an organic compound with the chemical formula [tex]C_{2}H_{5}CN[/tex]. This colorless liquid is a component of some commonly used solvents and in the manufacture of pharmaceuticals, textiles, and insecticides. It is used to generate pesticides, pharmaceuticals, and synthetic rubber during synthesis. The principal organic product formed in the reaction of ethylene oxide with sodium cyanide (NaCN) in aqueous ethanol is ethyl nitrile ([tex]C_{2}H_{5}CN[/tex]).

Mechanism of Reaction: The reaction between ethylene oxide and sodium cyanide in aqueous ethanol is carried out by the Saponification of Cyanide. Saponification refers to the reaction of a base with a fatty acid to create a soap.

The ethylene oxide undergoes nucleophilic attack by the hydroxide ion to produce a salt. The sodium ethylene oxide salt reacts with NaCN to form an intermediate. This intermediate reacts with [tex]H_{2} O[/tex]to form Ethyl nitrile. Ethylene oxide is a toxic, flammable, and colorless gas. It is used as a sterilant for medical equipment and as a fumigant for spices and foods. It has a sweet odor and can cause eye and respiratory irritation, as well as skin burns. The reaction of ethylene oxide with NaCN in aqueous ethanol generates Ethyl nitrile, which is used in a variety of industries.

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The balanced equation for combustion of C3H8 with O2 is:

C3H8 + 5O2 → 3CO2 + 4H2O. the correct answer is option. d.

From equation, it can be seen that 1 mole of C3H8 reacts with 5 moles of O2. Given that 8 moles of O2 were present, this is in excess of required amount, so all of the C3H8 will react completely.

Therefore, 5 moles of O2 will be used up in the reaction, leaving 3 moles of O2 remaining. The molar percent of O2 remaining can be calculated as follows: Molar percent of O2 remaining = (3 moles O2 / 8 moles total) x 100% = 37.5% . Therefore, answer is closest to option (d) 30 mol %.

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If the value of ΔG° is equal to 0, then the value of K or Kp is equal to 1 and the system is said to be in equilibrium.

A change in temperature occurs when heat flow increases or decreases the temperature. This changes the chemical equilibrium towards the products or the reactants. This can be identified by examining the reaction and determining whether it is an endothermic reaction or an exothermic reaction.

If the temperature is raised, the equilibrium constant decreases. If the forward reaction has an endothermic nature, the equilibrium constant increases. The equilibrium position also changes when the temperature is changed.

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Answer: The balanced chemical equation for the reaction of aqueous solutions of magnesium chloride and potassium phosphate is; MgCl2(aq) + K3PO4(aq) → Mg3(PO4)2(s) + 6KCl(aq)

To balance the given chemical equation, the number of atoms of elements on both sides of the equation must be equal. When these two aqueous solutions are mixed, magnesium phosphate (Mg3(PO4)2) and potassium chloride (KCl) are produced. The two products are both in aqueous solutions.

Potassium chloride exists as ions in aqueous solution. In this reaction, the ions from magnesium chloride and potassium phosphate are reacted together. The reaction results in precipitation.

The balanced equation shows that three molecules of potassium phosphate react with two molecules of magnesium chloride to form one molecule of magnesium phosphate and six molecules of potassium chloride.

Therefore, the number of atoms of each element is equal on both sides.



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An organic solvent is a liquid that has the ability to dissolve, extract, or suspend another substance to make a solution. An important organic solvent is acetone. The correct option is A.

An organic solvent is a liquid that has the ability to dissolve, extract, or suspend another substance to make a solution. Organic solvents are essential in a variety of industries, including pharmaceuticals, agriculture, paints, coatings, cleaning, and printing, among others.

They are used in the formulation of many products that we use in our daily lives. For example, in the paint and coatings industry, organic solvents are used to dissolve and disperse the ingredients of the paint, which then evaporates, leaving behind a solid coating.

Among the options given, acetone is the most important organic solvent. It is a colorless, flammable liquid that has a distinctive sweet odor.

Acetone is a versatile solvent that is used in a wide range of industries, including the production of chemicals, plastics, and fibers. It is also used as a solvent in paint, ink, and varnish, and it is used as a cleaning agent in a variety of applications.

Additionally, acetone is used in the manufacture of pharmaceuticals and cosmetics. It is also used as a fuel additive and a solvent in the production of biodiesel.

Among the other options given, menthone, phenol, and citral are not organic solvents. Menthone is a terpenoid that is used in the flavor and fragrance industry.

Phenol is an aromatic compound that is used as an antiseptic and disinfectant. Citral is a fragrance compound that is used in the production of perfumes and other fragrances.

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Taking into account the reaction stoichiometry, 22.29 grams of Al₂(SO₄)₃ are formed if 3.52 grams of aluminum completely reacted with H₂SO₄.

The balanced reaction is:

2 Al + 3 H₂SO₄ → Al₂(SO₄)₃ + 3 H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 54 grams of Al form 342 grams of Al₂(SO₄)₃, 3.52 grams of Al form how much mass of Al₂(SO₄)₃?

mass of Al₂(SO₄)₃= (3.52 grams of Al× 342 grams of Al₂(SO₄)₃)÷ 54 grams of Al

mass of Al₂(SO₄)₃= 22.29 grams

Finally, 22.29 grams of Al₂(SO₄)₃ are formed.

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8.88 g is the greatest yield of Na2SO4 that may be produced. As a result of using less NaHCO3 than is required to fully react with the H2SO4, the actual number of NaHCO3 used.

The body requires the base chemical bicarbonate to maintain a healthy acid-base balance. Your body's natural pH balance keeps it from becoming overly acidic, which can lead to a variety of health issues. By eliminating extra acid, the kidneys and lungs maintain a normal blood pH.

Metabolic acidosis is indicated by low blood bicarbonate levels. It is an alkali, the antithesis of acid, and it can counteract acid. Our blood's acidity is kept under control by it.

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Yes, you have enough sulfur for three trials. This is because 1.9 g of sulfur is equal to 0.09 mol, which is enough to do three trials of 0.030 mol each. Use the molar mass of sulfur, which is 32 g/mol.

Convert the mass of sulfur given to moles.

1.9 g / 32 g/mol = 0.09 mol

The moles by the number of trials you need to do:

0.09 mol x 3 trials = 0.27 mol

The moles back to grams to make sure you have enough sulfur:

0.27 mol x 32 g/mol = 8.64 g

Since the amount of sulfur given is more than the amount you need for the three trials (1.9 g > 8.64 g), you have enough sulfur.

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The amount of kinetic energy required to strain the chemical bonds in substrates so they can achieve the transition state is the definition of activation energy.

What is Activation Energy?

Activation energy is the amount of energy required for a chemical reaction to occur. The energy that must be provided to molecules in order for them to react with one another is known as activation energy.

This can be accomplished in a variety of ways, such as by increasing the temperature or pressure, adding a catalyst, or irradiating the reactants with light.

Activation energy is defined as the energy required for the reaction to begin. It's the energy that molecules require to overcome the initial barrier so that a reaction may proceed.

When a chemical reaction occurs, the reactants must collide with one another with sufficient force and in the appropriate orientation to form products.

It's critical to note that activation energy is a form of potential energy that isn't included in the overall energy change of a reaction.

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The correct answer is D. Reactants are substances that are combined to form products in a chemical reaction. Products are the result of substances being combined in a chemical reaction.

If two surface water types with the same density but different salinities and temperatures mix, the resulting water will be denser than both the surface water types.

Areas under warm and high salinity surface water with an appreciable depth, the temperature and salinity decreases with depth and internal vertical mixing processes occur despite stability of the water column. Eventually, this phenomenon is caused by the ability of the sea water to lose or gain heat by conduction and loss or gain of salt takes place by diffusion. This causes the density of the moving water to change directions.

Salt water mixes over limited depths and forms homogenous layers.

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The mass % of the solution if the density of the solution is 1.06 g/ml is 10.51%

The mass of NaI = 99.7 g

Volume of the solution = 895 ml

Density of the solution = 1.06 g/ml

To calculate the mass % of the solution, we have to calculate the mass of the solution first.

Step-by-step explanation:

The formula for density is given by:

Density = Mass/Volume

Or,

Mass = Density × Volume

Now, we will calculate the mass of the solution.

Mass = Density × Volume

        = 1.06 × 895= 948.7 g

Now, we will calculate the mass % of the solution.

Mass % = (Mass of solute/Total mass of solution) × 100

Mass of solute = 99.7 g

Total mass of solution = 948.7 g

Mass % = (99.7/948.7) × 100

             = 10.51%

Therefore, the mass % of the solution is 10.51%.

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The overall reaction of the multistep reaction is: 2A + B → C + D

This reaction can be broken down into two individual steps. In the first step, A and B react to form an intermediate product, X. The balanced chemical equation for this step is: A + B → X. In the second step, the intermediate product X is reacted with A to form C and D. The balanced chemical equation for this step is:X + A → C + D

Combining these two equations yields the overall balanced chemical equation:

2A + B → C + D

In summary, the overall balanced chemical equation for the multistep reaction is 2A + B → C + D. This equation shows that two molecules of A and one molecule of B will combine to form one molecule of C and one molecule of D.

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Acetaldehyde (CH3CHO) is a polar molecule due to its asymmetric shape and presence of polar covalent bonds.

The polarity is caused by the oxygen-hydrogen bond dipoles, as oxygen has a greater electronegativity than the hydrogen. This causes the oxygen to attract the electrons from the bond, creating a net dipole.

Acetaldehyde is a polar molecule. The polar character of a molecule is determined by the shape and polarity of its bonds. When the molecule has polar bonds and an asymmetrical shape, it is said to be polar. On the other hand, if it has no polar bonds or symmetrical shape, it is nonpolar.

Acetaldehyde is a polar molecule due to the electronegativity difference between carbon and oxygen, which creates a polar bond. It also has an asymmetrical shape due to the presence of two electronegative oxygen atoms on either side of the central carbon atom. As a result, acetaldehyde is soluble in polar solvents like water, ethanol, and acetone.

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Answer : 50 ml of a 6.00 M solution of sodium hydroxide must be diluted to 200 ml to make a 1.50 M solution of sodium hydroxide.

The volume (in ml) of concentrated sodium hydroxide solution (6.00 M) to be diluted to 200 ml in order to make a 1.50 M sodium hydroxide solution is 25.0 ml. Dilution of the solution is a process of reducing the concentration of a solute in a solution. It is the process of adding solvent or diluent to the solution to obtain a lower concentration of the solute in the solution.

Concentration (C) can be defined as the number of moles of solute (n) per volume of solution (V):C = n/VWe can derive a dilution equation from this definition: C1V1 = C2V2, where C1 is the initial concentration of the solute, V1 is the initial volume of the solution, C2 is the final concentration of the solute, and V2 is the final volume of the solution.

The number of moles of solute in the final solution is:n2 = C2 x V2We can substitute these values in the dilution equation to get: C1V1 = C2V2 Therefore: V1 = (C2V2)/C1 Substituting the given values in the above equation gives: V1 = (1.50 x 200)/6.00 = 50 ml

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Answer: The compound of bromine and fluorine used to make UF6 has an empirical formula of BrF8, which contains 1 atom of bromine and 8 atoms of fluorine. This compound is composed of 58.37 mass percent bromine and 41.63 mass percent fluorine.

The compound of bromine and fluorine used to make UF6 is composed of 58.37 mass percent bromine. To determine its empirical formula, we can use the following equation:

Molecular Mass = Mass Percent Bromine/Atomic Mass Bromine * Number of Bromine Atoms + Mass Percent Fluorine/Atomic Mass Fluorine * Number of Fluorine Atoms

Using this equation, we can determine the empirical formula by rearranging the equation and making it easier to calculate. To do this, we can make all terms on the right side of the equation be a multiple of the smallest mass percent of the elements in the compound. In this case, the smallest mass percent is bromine, so we must make the fluorine mass percent be a multiple of 58.37.

58.37/Atomic Mass Bromine * Number of Bromine Atoms = Mass Percent Fluorine/Atomic Mass Fluorine * Number of Fluorine Atoms

Using this equation, we can calculate the number of bromine atoms and fluorine atoms. The atomic mass of bromine is 79.9 and the atomic mass of fluorine is 19. In this equation, the number of bromine atoms is 1, and the number of fluorine atoms is 8. This results in an empirical formula of BrF8.

In conclusion, the compound of bromine and fluorine used to make UF6 has an empirical formula of BrF8, which contains 1 atom of bromine and 8 atoms of fluorine. This compound is composed of 58.37 mass percent bromine and 41.63 mass percent fluorine.


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In order to make a solution that is 1.5ppm in fluoride ion using sodium fluoride (NaF), 750L of water needs to be added to 0.22g of NaF.

Mass of NaF (g) = Concentration of F (ppm) x Volume of Water (L) / 1,000,000.

NaF mass = 1.5ppm x 750L / 1,000,000.

Since the atomic weight of NaF is 41.99, 0.22g is equivalent to 0.00518mol NaF.

The molarity (M) of the solution,

Molarity (M) = Moles of Solute (mol) / Volume of Solution (L)

Molarity 0.00518mol / 750L = 0.000068M.

Therefore, 0.22g of NaF should be added to 750L of water to make a solution that is 1.5ppm in fluoride ion.

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The objective of measuring the freezing point of a solution of your compound is: to determine its purity or concentration.

When a compound is dissolved in a solvent, the freezing point of the resulting solution is lower than that of the pure solvent. This is because the solute molecules lower the freezing point of the solvent by interfering with the formation of the crystal lattice. The extent of the depression of the freezing point depends on the concentration of the solute and its nature.

To measure the freezing point of a solution of your compound, the solution is cooled until it begins to solidify. The temperature at which this occurs is recorded as the freezing point of the solution. By comparing the freezing point of the solution with the freezing point of the pure solvent, the concentration or purity of the solute can be calculated using the freezing point depression equation:

ΔTf = Kf · m,

where ΔTf is the freezing point depression, Kf is the freezing point depression constant, and m is the molality of the solute in the solution.

The freezing point depression constant is a property of the solvent and is typically provided in reference tables. Once the molality of the solute is determined, the molar mass or weight percent of the solute can be calculated, allowing for the determination of the purity or concentration of the compound.

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To determine the percent yield, we need to first calculate the theoretical yield of the reaction using stoichiometry, and then divide the actual yield by the theoretical yield and multiply by 100%. The percent yield of the reaction is approximately 84.9%.

Percent yield is a measure of the efficiency of a chemical reaction, calculated by dividing the actual yield of a reaction by the theoretical yield and multiplying by 100%. It represents the percentage of the theoretical amount of product that was actually obtained in a reaction.

The balanced chemical equation is:

2Al + Cr₂O₃ → Al₂O₃ + 2Cr

The molar mass of Cr₂O₃ is 152 g/mol, the molar mass of Al is 27 g/mol, and the molar mass of Cr is 52 g/mol.

We need to determine which reactant is limiting, so we can calculate the theoretical yield based on the amount of limiting reactant. We can do this by calculating the number of moles of each reactant using their molar masses and dividing by their stoichiometric coefficients in the balanced equation:

moles of Cr₂O₃= 44.1 g / 152 g/mol = 0.29 mol

moles of Al = 35.0 g / 27 g/mol = 1.30 mol

From the balanced equation, we see that 1 mole of Cr2O3 reacts with 2 moles of Cr. Therefore, the theoretical yield of Cr is:

moles of Cr produced = 0.29 mol Cr₂O₃x (2 mol Cr / 1 mol Cr₂O₃) = 0.58 mol Cr

mass of Cr produced = 0.58 mol Cr x 52 g/mol = 30.16 g Cr

The percent yield is:

% yield = (actual yield / theoretical yield) x 100%

% yield = (25.6 g Cr / 30.16 g Cr) x 100% = 84.9%

Therefore, the percent yield of the reaction is approximately 84.9%.

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The polarity of a molecule is determined by both the type of bonds and the shape of the molecule. Polar bonds result in a molecule being polar, while non-polar bonds result in a molecule being non-polar. The shape of the molecule can also affect the polarity of the molecule. Molecules that are symmetrical are non-polar, while those that are asymmetrical are polar.

Polar bonds occur when two atoms share electrons unequally, leading to a permanent dipole moment. These molecules are said to be polar. On the other hand, non-polar molecules occur when the atoms involved in the bond share electrons equally, resulting in a non-polar molecule.

The shape of the molecule also plays a role in determining the polarity of the molecule. If the shape of the molecule is symmetrical, with an equal distribution of electrons, then it is considered non-polar.  

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Formic acid (HCOOH), the weak organic acid present in red ants that is responsible again for sting in their bite, with a pH of 2.87 in a 1.35 M solution.

The ph is a useful tool for illustrating how basic or acidic a solution is. By using the inverse logarithm of a hydronium content, or pH = -log[H3O+], we may determine the pH of the solution.

Formic acid has a dissociation constant constant of 1.8 10 4. Formic acid (HCOOH) has a concentration of 0.050 M. [HCOOH] = 0.050 - x, where x is the amount of H+ that separates from HCOOH (formic acid). A 0.050 M strong acid solution has a pH of 2.52.

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The Ka of a 0.010m acid solution which is 19% ionized is 4.5x10-4.

The Ka of an acid is the measure of its acidity and is calculated by dividing the concentration of its products by the concentration of its reactants.

To calculate the Ka of a 0.010m acid solution, we need to know the concentration of the products, which is 19% ionized.

To calculate the concentration of the products, we need to multiply the concentration of the acid (0.010M) by the percentage of ionization (19%). This gives us the concentration of the products as 0.0019M.

Now, we can calculate the Ka of the acid by dividing the concentration of the products (0.0019M) by the concentration of the reactants (0.010M). This gives us a Ka value of 4.5x10-4.

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Answer:  Distillation is best used for B) separating two miscible liquids and for separating insoluble solids from liquids.

Distillation is a separation method that is best used for separating two miscible liquids, such as water and alcohol. This process is done by heating the mixture until it reaches its boiling point and collecting the vaporized mixture. As the vapor rises, the different components of the mixture separate based on their boiling points.

The vapor is then cooled and condensed back into liquid form, resulting in the two liquids being separated.

It can also be used for separating insoluble solids from liquids. In this case, the mixture is heated until it reaches its boiling point and is then filtered, with the insoluble solid being retained by the filter while the liquid passes through.

Distillation is not suitable for separating soluble solids from liquids, as the solids will remain dissolved in the liquid even when heated to the boiling point. It also is not suitable for separating two or more solids from a mixture, as distillation does not allow for the separation of solids.

Overall, distillation is best used for separating two miscible liquids and for separating insoluble solids from liquids.


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The theoretical yield in grams for the dehydration reaction of 4.00 ml of 2-methylcyclohexanol is 3.17E-5 g.

The theoretical yield in grams for the dehydration of 4.00 mL of 2-methylcyclohexanol can be calculated using the following steps:

1. 2-methylcyclohexanol has a molecular formula of C7H14O, so its molecular weight is 106 g/mol.

2. Since the question specifies 4.00 mL, we can convert that to 0.004 L. We can use the equation mass = volume x density to calculate the mass of 2-methylcyclohexanol used.

The density of 2-methylcyclohexanol is 0.841 g/mL, so the mass of 2-methylcyclohexanol used is 0.841 g/mL x 0.004 L, or 0.00336 g.

3. Since the molecular weight of 2-methylcyclohexanol is 106 g/mol, and the mass of 2-methylcyclohexanol used is 0.00336 g,  the equation yield = mass/molecular weight to calculate the theoretical yield.

The theoretical yield of the dehydration reaction is 0.00336 g/106 g/mol, or 3.17E-5 g.

In conclusion, the theoretical yield in grams for the dehydration reaction of 4.00 ml of 2-methylcyclohexanol is 3.17E-5 g.

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The blank can be filled with the term "shielding gas."Shielding gas protects the molten weld pool, the filler rod, and the tungsten electrode as they cool to a temperature at which they will not oxidize rapidly.

What is a shielding gas? A shielding gas is a gas that is employed in gas welding processes to safeguard the weld area from contamination. Welding processes that use shielding gases are referred to as gas metal arc welding or gas tungsten arc welding, among other things. What is the purpose of shielding gas in welding? The primary goal of shielding gas in welding is to defend the molten weld pool, the filler rod, and the tungsten electrode from being contaminated. When the shielding gas is utilized, it forms a sort of barrier that protects the weld from the air and other contaminants. In essence, the shielding gas creates a shield for the welding process that protects the molten weld pool from getting contaminated. As a result, the use of shielding gas is critical in ensuring that the welding process results in high-quality welds.

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Answer:

alpha particles have the least penetration power while beta particles have a moderate penetration power and gamma particles have the highest penetration power.

The mass of metallic iron produced in the course of the reduction of 15.0 g of FeO with 3.0 g of Al is: 12.1 g.

To calculate this, we must consider the reaction that occurs:
FeO + Al → Fe + Al2O3

In this reaction, 1 mol of FeO reacts with 1 mol of Al to produce 1 mol of Fe and 1 mol of Al2O3. Since the given mass of FeO is 15.0 g and the given mass of Al is 3.0 g, we can calculate the number of moles of each reactant with the following equation:  n (reactant) = mass (reactant) ÷ molar mass (reactant)

[tex]n (FeO) = 15.0 g ÷ 71.84 g/mol = 0.2092 mol[/tex]
[tex]n (Al) = 3.0 g ÷ 26.98 g/mol = 0.1115 mol[/tex]

Therefore, since 0.2092 mol of FeO reacts with 0.1115 mol of Al, 0.2092 mol of Fe is produced. We can then calculate the mass of Fe produced with the following equation:

mass (Fe) = n (Fe) × molar mass (Fe)
mass (Fe) = 0.2092 mol × 55.85 g/mol = 11.6 g

Therefore, the mass of metallic iron produced in the course of the reduction of 15.0 g of FeO with 3.0 g of Al is 11.6 g.

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