To answer this question we will use the following formulas to compute n arithmetic means between 'a' and 'b':
[tex]\begin{gathered} A_1=a+\frac{b-a}{n+1}, \\ A_2=a+2\cdot\frac{b-a}{n+1}, \\ \ldots \\ A_n=a+n\cdot\frac{b-a}{n+1}\text{.} \end{gathered}[/tex]Substituting n=3, a=-16, and b=4 we get:
[tex]\begin{gathered} A_1=-16+\frac{4-(-16)}{3+1}, \\ A_2=-16+2\cdot\frac{4-(-16)}{3+1}, \\ A_3=-16+3\cdot\frac{4-(-16)}{3+1}\text{.} \end{gathered}[/tex]Simplifying the above results we get:
[tex]\begin{gathered} A_1=-16+\frac{4+16}{4}=-16+\frac{20}{4}=-11, \\ A_2=-16+2\cdot\frac{4+16}{4}=-16+\frac{40}{4}=-6, \\ A_3=-16+3\cdot\frac{4+16}{4}=-16+\frac{60}{4}=-1. \end{gathered}[/tex]Answer: -11, -6, and -1.
Write all the possible integer values of x.
x > 1 and x ≤ 6
Separate answers with commas.
Step-by-step explanation:
college level ? what teacher puts such a question in on college level ? and you can't answer this ?
that is middle school basics.
what is going on ?
x can have in the defined interval the integer values
2, 3, 4, 5, 6
there, that was all to it ...
The Cunninghams are moving across the country. Mr.Cunningham leaves 3 hours before Mrs. Cunningham. If he averages 55 mph and sheaverages 75 mph, how many hours will it take Mrs. Cunningham to catch up to Mr. Cunninham to catch up to mr.cunningham
Solution:
Remember, distance traveled is the rate times the time. (d = rt) Mrs. Cunningham will overtake Mr. Cunningham when they have traveled the same distance.
Mrs. Cunningham's equation will be:
[tex]d=\text{ }75t[/tex]Since he was traveling 3 hours longer, Mr. Cunningham's equation will be:
[tex]d=55(t+3)[/tex]If they travel the same distance, the equations can be set equal to each other:
[tex]\text{ }75t=55(t+3)[/tex]applying the distributive property, this is equivalent to:
[tex]\text{ }75t=55t\text{ +165}[/tex]this is equivalent to:
[tex]75t-55t\text{ = 165}[/tex]this is equivalent to:
[tex]20t\text{ = 165}[/tex]solving for t, we obtain:
[tex]t\text{ =}\frac{165}{20}=8.25[/tex]So that, we can conclude that the correct answer is:
It will take Mrs. Cunningham 8.25 hours to overtake her husband.
4. If line segment AB has coordinates A(-2,4) and B(2,0) and line segment
CD has coordinates C(3,4)and D(-3,-2), how would you describe these two
line segments?
These 2 lines perpendicular to each other on the graph.
What are perpendicular lines?The two different lines that meet at an angle of 90 degrees are called perpendicular lines. Do your walls' connecting corners—or the letter "L"—share any similarities? They are the straight lines, referred to as perpendicular lines, that intersect at the proper angle. An angle of 90 degrees between two straight lines is known as a perpendicular. The illustration depicts a little square in between two perpendicular lines to indicate the 90° angle, which is also known as a right angle. Here, a right angle between the two lines Two lines that cross each other at a 90° angle are referred to as perpendicular lines in mathematics. I
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Question 6 of 1
For f(x)-3x+1 and g(x)=x²-6, find (f-g)(x).
A. -x²+3x+7
OB.x²-3x-7
O C. 3x²-17
OD. -x²+3x-5
-x² + 3x + 7 is value of function .
What is function in math?
An expression, rule, or law in mathematics that specifies the relationship between an independent variable and a dependent variable (the dependent variable). In mathematics and the sciences, functions are fundamental for constructing physical relationships.f(x) = 3x + 1
g(x) = x² - 6
Then,
According to the' question :-
(f - g)(x) = f(x) - g(x)
= 3x + 1 - (x² - 6)
= 3x + 1 - x² + 6
= -x² + 3x + 7
Hence,
Option 1st : -x² + 3x + 7 is Correct.
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if the slope of a line and a point on the line are known the equation of the line can be found using the slope intercept form y=mx+b. to do so substitute the value of the slope and the values of x and y using the coordinates of the given point, then determine the value of b. using the above technique find the equation of the line containing the points (-8,13) and (4,-2).
The general equation of a line is;
[tex]y\text{ = mx + b}[/tex]m is the slope and b is the y-intercept
To find the slope, we use the equation of the slope as follows;
[tex]\begin{gathered} m\text{ = }\frac{y_2-y_1}{x_2-x_1} \\ \\ (x_1,y_1)\text{ = (-8,13)} \\ (x_2,y_2)\text{ = (4,-2)} \\ \\ m\text{ = }\frac{-2-13}{4-(-8)}\text{ = }\frac{-15}{12}\text{ = }\frac{-5}{4} \end{gathered}[/tex]We have the partial equation as;
[tex]\begin{gathered} y\text{ = }\frac{-5}{4}x\text{ + b} \\ \\ \text{Substitute the point (-8,13)} \\ \text{x = -8 and y = 13} \\ \\ 13\text{ = }\frac{-5}{4}(-8)\text{ + b} \\ \\ 13\text{ = 10 + b} \\ b\text{ = 13-10 = 3} \end{gathered}[/tex]We have the complete equation as;
[tex]y\text{ =}\frac{-5}{4}x\text{ + 3}[/tex]which fraction remains in the quotient when 4,028 is divided by 32
We get that
[tex]\frac{4028}{32}=\frac{1007}{8}=\frac{1000}{8}+\frac{7}{8}=125+\frac{7}{8}[/tex]so the fractions that remains is 7/8
Use the definition of the derivative to find the derivative of the function with respect to x. Show steps
Answer: [tex]\frac{5}{2\sqrt{5x+3\\} }[/tex]
Step-by-step explanation:
First, use the chain rule to quickly find the answer so that you can check after you go through the ridiculous process that is the bane of every calculus 1 student's existence.
f(x) = (5x + 3)^(1/2)
(d/dx) (5x + 3)^(1/2) =
(1/2)(5x + 3)^(-1/2) * (5) =
5/[2(5x+3)^(1/2)]
Now, we enter the first gate of hell:
f'(x) = the limit as h approaches 0 of [(f(x+h) - f(x))/h]
lim as h -> 0 of [(5(x+h)+3)^(1/2) - (5x+3)^(1/2)/h]
lim as h -> 0 of [(5x+5h+3)^(1/2) - (5x+3)^(1/2) / h]
Multiply numerator and denominator by the conjugate of the numerator, which is (5x+5h+3)^(1/2) + (5x+3)^(1/2).
lim as h -> 0 of
[√(5x+5h+3) - √(5x+3) ] [√(5x+5h+3) + √(5x+3) ]
______________________________________
h[√(5x+5h+3) - √(5x+3) ]
Simplify the numerator via FOIL:
5x+5h+3 + √(5x+5h+3)√(5x+3) - √(5x+3)√(5x+5h+3) - (5x+3)
The remaining radicals in the numerator cancel each-other, giving us:
5x + 5h + 3 - 5x - 3
Simplify Further:
5h
Now that we have simplified our numerator, let's continue:
lim as h -> 0 of (5)(h)/[(h)((5x+5h+3)^(1/2) + (5x+3)^(1/2))]
The h in the numerator cancels the h in the denominator.
lim as h -> 0 of 5/[(5x+5h+3)^(1/2) + (5x+3)^(1/2)]
Now, we directly substitute h with 0 in the equation.
5/[ (5x+3)^1/2 + (5x+3)^(1/2) ]
In the denominator, both sides of the addition sign are the same, so we can simplify it further to:
5/[ 2(5x+3)^(1/2) ]
This is the same answer we received using the chain rule, so it is correct!
3.) Write the explicit formula for the arithmetic sequence. 50, 47, 44, 41,...
all the terms are 3 less than its preceding term, simple!
So, the formula would be:
[tex]a_n=a+(n-1)d[/tex]Where
a is the first term
d is the common difference (diff in 2 terms)
From the sequnce,
first term (a) is 50
common difference (d) = 47 - 50 = -3
So, we have:
[tex]\begin{gathered} a_n=a+(n-1)d \\ a_n=50+(n-1)(-3_{}) \\ a_n=50-3n+3 \\ a_n=53-3n \end{gathered}[/tex]Explicit Formula:
[tex]a_n=53-3n[/tex]Find the interest and future value of a deposit of $12,000 at 5.5% simple interest for 10 years.
Given:
Principal - $12,000
Annual Interest Rate = 5.5% or 0.055 in decimal form
Time in years = 10 years
Find: simple interest and future value
Solution:
The formula for getting the simple interest is:
[tex]Interest=Principal\times Rate\times Time[/tex]Let's replace the variables in the formula with their corresponding numerical value.
[tex]Interest=12,000\times0.055\times10[/tex][tex]Interest=6,600[/tex]The interest after 10 years is $6, 600.
So, if the interest is 6,600, the future value of the money is:
[tex]FV=Principal+Interest[/tex][tex]FV=12,000+6,600[/tex][tex]FV=18,600[/tex]The future value of the deposited money after 10 years is $18, 600.
[tex]5x + 17 = 82[/tex]simplify as much as possible
To answer this question, we can follow the next steps:
1. Subtract 17 to both sides of the equation (we apply here the subtraction property of equality):
[tex]5x+17-17=82-17\Rightarrow5x+0=65\Rightarrow5x=65[/tex]2. To isolate the variable, x, in the equation, we need to divide by 5 to both sides of the equation, as follows:
[tex]\frac{5x}{5}=\frac{65}{5}\Rightarrow\frac{5}{5}=1\Rightarrow x=\frac{65}{5}\Rightarrow x=13[/tex]We can check this result if we substitute this last value into the original equation:
[tex]5x+17=82\Rightarrow5(13)+17=82\Rightarrow65+17=82\Rightarrow82=82[/tex]The result is always TRUE.
Therefore, the value for the unknown value of x is x = 13.
Evaluate the function for the indicated values of x. (2x + 1, x 5 f(-10) = F(2) = f(-5) = f(-1) = f(8) =
Explanation
[tex]f(x)f(x)=\mleft\{\begin{aligned}2x+1\text{ if x}\leq-5\text{ } \\ x^2\text{ if -5}Step 1you need to select the correct function depending on the number
i)f(-10)
[tex]-10\leq-5,\text{ then you n}eed\text{ apply}\Rightarrow f(x)=2x+1[/tex]Let x= -10, replacing
[tex]\begin{gathered} f(x)=2x+1 \\ f(-10)=(2\cdot-10)+1 \\ f(-10)=-20+1 \\ f(-10)=-19 \end{gathered}[/tex]Step 2
Now
ii) f(2)
[tex]\begin{gathered} 2\text{ is in the interval} \\ -5Letx=2,replacing
[tex]\begin{gathered} f(x)=x^2 \\ f(2)=2^2=4 \\ f(2)=4 \end{gathered}[/tex]Step 3
iii) f(-5)
[tex]\begin{gathered} -5\text{ is smaller or equal than -5} \\ -5\leq5,\text{ then apply}\Rightarrow f(x)=2x+1 \end{gathered}[/tex]Let
x=-5,replace
[tex]\begin{gathered} f(x)=2x+1 \\ f(-5)=(2\cdot-5)+1=-10+1 \\ f(-5)=-9 \end{gathered}[/tex]Step 4
iv)f(-1)
[tex]\begin{gathered} -1\text{ is in the interval} \\ -5<-1<5 \\ \text{then apply}\Rightarrow f(x)=x^2 \end{gathered}[/tex]let
x=-1,replace
[tex]\begin{gathered} f(x)=x^2 \\ f(-1)=(-1)^2 \\ f(-1)=-1\cdot-1=1 \\ f(-1)=1 \end{gathered}[/tex]Step 5
Finally
F(8)
[tex]\begin{gathered} 8\text{ is greater or equal than 5, then apply} \\ 8\ge5\Rightarrow apply\text{ f(x)=3-x} \\ f(x)=3-x \end{gathered}[/tex]Let
x=8,replace
[tex]\begin{gathered} f(x)=3-x \\ f(8)=3-8 \\ f(8)=-5 \end{gathered}[/tex]I hope this helps you
solve using the quadratic formulax^2+2x-17=0
Can u please help me solve? I'm reviewing for finals.
Given:
Consider the given graph as a reference of the solution.
To find:
[tex]-3(u\cdot v)[/tex]Explanation:
By analyzing the graph, we can define the coordinate of vector u and v:
[tex]\[\begin{align} & \vec{u}=(-8,-9)-(0,0)=(-8,-9) \\ & \vec{v}=(3,7)-(0,0)=(3,7)\end{align}\][/tex]Now, let perform the dot product of two vectors,
[tex]\begin{gathered} u\cdot v=(-8,-9)\cdot(3,7) \\ u\cdot v=(-8)(3)+(-9)(7) \\ u\cdot v=-24-63 \\ u\cdot v=-87 \end{gathered}[/tex]Now, perform the required operation,
[tex]\begin{gathered} -3(u\cdot v) \\ =-3(-87) \\ =261 \end{gathered}[/tex]Final answer:
Hence, the required solution is:
[tex]-3(u\cdot v)=261[/tex]A)what height was the basketball thrown from? B)what is the maximum height the basketball went ?C)after how many seconds did the basketball reach its maximum height?D)how many seconds did it take for the basketball to hit the ground ? make sure you look at the exact value in the graph?pleaseeeeeeeeeeeeeeee
We have the following:
The questions can be found thanks to the graph of the statement
A)what height was the basketball thrown from?
The graph starts at the point (0, 6) therefore the basketball was thrown from 6 feet height
B)what is the maximum height the basketball went ?
The highest point of the graph is (2, 10), therefore the maximum height is 10 ft
C)after how many seconds did the basketball reach its maximum height?
The highest point of the graph is (2, 10), therefore the time it reached this height was 2 seconds
D)how many seconds did it take for the basketball to hit the ground ? make sure you look at the exact value in the graph?
The ground would be when the value of y is equal to 0, therefore according to the point (5.162, 0) the time was 5.162 seconds
A theater group made appearances in two cities. The hotel charge before tax in the second city was $500 higher than in the first. The tax in the first city was5%, and the tax in the second city was 6%. The total hotel tax paid for the two cities was $552.50. How much was the hotel charge in each city before tax?Note that the ALEKS graphing calculator can be used to make computations easier.
SOLUTION
Let us represent the hotel charge with different variables x and y:
Let the hotel charge before tax in the first city be x
Let the hotel charge before tax in the second city be y
Now, let us represent the word problem in equation form:
First, we were told that the charge before tax in the second city is $500 more than the charge before tax in the first city, this can be represented thus:
[tex]y=x+500\ldots\text{.eqn 1}[/tex]Going forward in the question, we were told the tax for the first city (x) is 5%(0.05), and the tax for the second city is 6%(0.06). The total tax from both cities is $552.5, this expression can be written mathematically as:
[tex]0.05x+0.06y=552.5\ldots\ldots\text{eqn 2}[/tex]Now, by solving equation 1 and equation 2 simultaneously, we will obtain the hotel charge in each city before tax. (that is the value of x and y).
[tex]\begin{gathered} y=x+500 \\ 0.05x+0.06y=552.5 \\ \end{gathered}[/tex]Using, the substitution method of solving simultaneous equation, we will solve further:
[tex]\begin{gathered} \text{substitute equation 1 into equation 2} \\ 0.05x+0.06(x+500)=552.5 \\ 0.05x+0.06x+30=552.5 \\ 0.11x+30=552.5 \end{gathered}[/tex][tex]\begin{gathered} 0.11x=552.5-30 \\ 0.11x=522.5 \\ x=\frac{522.5}{0.11} \\ x=4750 \end{gathered}[/tex]The hotel charge before tax in the first city is $4750.
Now, substitute the value of x into equation 1 to get the value of y (hotel charge before tax in the second city)
[tex]\begin{gathered} y=x+500 \\ x=4750 \\ y=4750+500 \\ y=5250 \end{gathered}[/tex]The hotel charge before tax in the second city is $5250.
Solve the equation. Select the correct answer below, and, if necessary, fill in the answer box to complete your choice.
Explanation
[tex]\begin{gathered} \frac{4}{y}+\frac{3}{4}=\frac{4}{4y} \\ Multiply\text{ through by the lowest common multiple }\Rightarrow4y \\ 4y\times\frac{4}{y}+\frac{3}{4}\times4y=\frac{4}{4y}\times4y \\ 16+3y=4 \\ 3y=4-16 \\ 3y=-12 \\ y=-\frac{12}{3} \\ y=-4 \end{gathered}[/tex]Answer= y=-4
a number, twice that number, and one-third of that number added. the result is 20. what is the number?
Answer:
6
Step-by-step explanation:
Let x = the number
2x = twice the number
1/3 x = one-third of the number
x + 2x + 1/3 x = 20
Combine like terms.
3 1/3 x = 20
Change 3 1/3 to an improper number.
10/3 x = 20
Times by 3/10 on both sides.
3/10 • 10/3 x = 20•3/10
x = 60/10
x = 6
Check:
6 + 2(6) + 1/3(6)
= 6 + 12 + 2
= 20 check!
Use a graphing utility to graph the function and to approximate any relative minimum or relative maximum values of the function. (Round your answers to the nearest integer. If an answer does notexist, enter DNE.)
Given:
[tex]f(x)=4x-2x^2[/tex]Required:
To find the relative minimum and relative maximum values of the function.
Explanation:
Consider
[tex]f(x)=4x-2x^2[/tex]The graph of the function is
The relative maximum is at (1,2).
There is no relative minimum.
Final Answer:
The relative maximum : (1,2).
The relative minimum : DNE.
i inserted a picture of the question please state whether the answer is a b c or d please don’t ask questions, yes i’m following.
Solution
- We are asked to find the complement of rolling a 5 or 6 given a cube numbered 1 - 6.
- The complement of an event is defined as every other event asides the event in context.
- Other than rolling a 5 or 6, we can also roll a 1, 2, 3, or 4. This constitutes the complement of rolling 5 or 6.
Final Answer
The complement of rolling a 5 or 6 is:
{Rolling a 1, 2, 3, or 4} (OPTION B)
7. Find the perimeter of the rectangle with length 33 yards and width 59 yards.A.92 ydB.1,947 ydC.125 ydD.184 yd
Solution
We are given
Length (l) = 33 yards
Width (w) = 59 yards
To find the perimeter
Note: Perimeter of a Rectangle
[tex]Perimeter=2(l+w)[/tex]The National Oceanic and Atmospheric Administration tracks the amount of oysters harvested from the Chesapeake Bay each year.Years since 1900 2 28 53 67 78 89Oysters (metric tons) 54.2 22.5 7.38 5.28 3.52 2.38Find the exponential regression equation that models this data.Ay=-58(-0.964)OB. y = -58(0.964)Oc.y=58(0.964)*OD.y=58(-0.964)*Reset SelectionPreviouNext
Explanation
We are given the following table:
We are required to determine the exponential regression equation that models the data.
This is achieved thus:
We know that an exponential equation is given as:
[tex]y=ab^x[/tex]Using a graphing calculator, we have:
From the graph, we have:
[tex]\begin{gathered} a=58 \\ b=0.964 \end{gathered}[/tex]Hence, the answer is:
[tex]y=58(0.964)^x[/tex]solve a system of equations to solve the problem question 8
Let x be the cost of each juice and y be the cost of each BBQ.
4x + 2y = 16
4x + 3y = 21
Subtract the second equation from the first
y = 5
Substitute y = 5 into 4x + 2y = 16
4x + 2(5) = 16
4x + 10 = 16
4x = 16 - 10
4x = 6
x=1.5
Therefore, a juice cost $1.5 and a BBQ cost $5
So, if the Emdin family pu rchased 3 juice and 3 BBQ, then
cost of juice = 3 x $1.5 = $4.5
cost of BBQ = 3 x $5 = $15
Total money spent by Emdin family = $4.5 + $15 = $19.5
Let x be the cost of each juice and y be the cost of each BBQ.
4x + 2y = 16
4x + 3y = 21
Subtract the second equation from the first
y = 5
Substitute y = 5 into 4x + 2y = 16
4x + 2(5) = 16
4x + 10 = 16
4x = 16 - 10
4x = 6
x=1.5
Therefore, a juice cost $1.5 and a BBQ cost $5
So, if the Emdin family pu rchased 3 juice and 3 BBQ, then
cost of juice = 3 x $1.5 = $4.5
cost of BBQ = 3 x $5 = $15
Total money spent by Emdin family = $4.5 + $15 = $19.5
4. Which of the following rules is the composition of a dilation of scale factor 2 following (after) a translation of 3 units to the right?
ANSWER
A. (2x + 3, 2y)
EXPLANATION
Let the original coordinates be (x, y)
First, there was a dilation of scale factor 2.
This means that the coordinates become:
2 * (x, y) => (2x, 2y)
Then, there was a translation of 3 units to the right. That is a translation of 3 units on the horizontal (or x axis).
That is:
(2x + 3, 2y)
So, the answer is option A.
Determine m such that the line through points (2m,4) and (m-3,6) has a slope of -5.
We have to use the formula of the slope
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Where,
[tex]x_1=2m,x_2=m-3,y_1=4,y_2=6,m=-5[/tex]Replacing all these values, we have
[tex]-5=\frac{6-4}{m-3-2m}[/tex]Now, we solve for m
[tex]\begin{gathered} -5=\frac{2}{-m-3} \\ -m-3=\frac{2}{-5} \\ -m=-\frac{2}{5}+3 \\ m=\frac{2}{5}-3=\frac{2-15}{5}=\frac{-13}{5} \end{gathered}[/tex]Therefore, m must be equal to -13/5 in order to meet the given characteristics.translate the following verbal statement into an algebraic equation and then solve: demetrius paid 9$ for a matinee movie. this is 1$ less than the price in the evening what is the price of the movie at night?use x for your variable equation ________x=______
Answer:
x = price of the movie at night
x = $9 + $1
Explanation:
We need to find the price of the movie at night, so, let's call x the price of the movie at night.
Then, the price of the matinee movie $9 is $1 less than the price in the evening. Therefore, we can write the following equation:
9 = x - 1
Solving for x, we get:
x = 9 + 1
Dave has a collection of 60 DVDs. One quarter of them are action mc
What is the ratio of the number of action DVDs to all ofner genres?
Answer:
15:45 i think
Step-by-step explanation:
25% of 60 is 15
60-15=45
15:45
Line Graph: This time you will not have the numbers on the x and y axis. You will need to decide which number to use (1, 2, 3... or 2,4,5.... Or 5, 10, 15...) 3: Creating Graphs Create a single line graph using the following table. Time goes on the x axis Rainfall goes on the y axis Make sure to do the following: Label the x and y axis Create a title 10 15 20 Time (minutes) 25 30 35 40 25 55 45 60 50 35 40 Speed (of car) (km/min)
Line Graph:
A line graph is used to show how the data points are changing with respect to time.
For Example:
A line graph may be used to show the average rainfall over the entire month.
For the given scenario we have,
X-axis = Time in minutes
Y-axis = Speed of car in km/min
Title of graph = Speed of Car Vs Time
Data points for time = 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60
Data points for speed = 25, 30, 35, 40, 25, 55, 45, 60 50 35 40
This is how the line graph looks like.
It is showing the speed of the car in km/min over an interval of 60 minutes in steps of 5 minutes.n steps of
Procedure:
• Draw and label the x-axis and y-axis.
,• Label the data points on both axis.
,• Draw the data points.
,• Join the data points with a line.
,• We are done.
,•
T is in seconds and L is the length of the pendulum in centimeters. Find the period of the pendulum of the given lengths. Give your answer to two decimal places using 3.14 for π. Show and explain your work below. a. L = 23 cm b. L = 192 cm
The period of the pendulum in each case is given as follows:
a. L = 23 cm: 0.96 s.
b. L = 192 cm: 2.78 s.
Period of pendulumThe period of a pendulum is defined according to the following equation:
P = 2π sqrt(L/g)
In which the parameters are as follows:
L is the length of the pendulum which we want to find the period.g = 9.8 m/s² is the acceleration of the pendulum due to the gravity.For a length of 23 cm = 0.23m, in item a, considering 3.14 for π, the period is calculated as follows:
P = 6.28 x sqrt(0.23/9.8) = 0.96 s.
In item b, the length is of 192 cm = 1.92 m, as each cm has 100 m, hence the period is given by:
P = 6.28 x sqrt(1.92/9.8) = 2.78 s.
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what is the area of the triangle below with a side length of 4
All angles of triangles is equal means that that triangle is equailateral triangle with side of a = 4 in.
The formula for the area of equilateral triangle is,
[tex]A=\frac{\sqrt[]{3}a^2}{4}[/tex]Substitute 4 for a in the formula to determine the area of the triangle.
[tex]\begin{gathered} A=\frac{\sqrt[]{3}}{4}\cdot(4)^2 \\ =4\sqrt[]{3} \end{gathered}[/tex]So area of triangle is,
[tex]4\sqrt[]{3}[/tex]Which of the following graphs is a polynomial function with intercepts of(-2,0), (1, 0), and (4, 0)711-15 4NO C.O D.
Explanation
We are given the following:
We are required to determine which of the following graphs is a polynomial function with intercepts of
(-2,0), (1, 0), and (4, 0).
This can be achieved by looking for the graph that crosses the x-axis at the points -2, 1 and 4.
Hence, the answer is option C.