No, because the SAS Congruence Theorem requires two pairs of congruent sides and one congruent angle.
No, because the SAS Congruence Theorem requires two pairs of congruent sides and one congruent angle. To use the SAS Congruence Theorem to prove that GHF =KHJ, it would be necessary to have information about the lengths of the corresponding sides and the measure of the included angle in each triangle. Without this information, it is not possible to prove that GHF =KHJ using the SAS Congruence Theorem. To prove that GHF =KHJ using this theorem, it would be necessary to show that the two sides GK and KH are congruent, the two sides HF and HJ are congruent, and the included angle GHF is congruent to the included angle KHJ.
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Q (6
(611)
Triangle STU with coordinates S(3, 6), T(4,4), and U(5,1) is rotated 90° clockwise. List the
12 (5+1)
coordinates of the new image.
5' (2-6)
The coordinates of the new image are S(3, 6) → (-6, 3), T(4,4) → (-4, 4), and U(5,1) → (-1, 5).
What in geometry is a transformation matrix?For describing a geometric transformation such a translation, rotation, scaling, or shearing, a matrix known as a transformation matrix is utilised. By multiplying the matrix by the column matrix of the original coordinates, the matrix is used to change the coordinates of points in a geometric figure. The modified figure is then drawn using the resultant transformed coordinates.
Given that the coordinates of the point are:
S(3, 6), T(4,4), and U(5,1)
When the figure is rotated by 90 degrees the resultant image has the following coordinates.
(x, y) → (-y, x)
Thus,
S(3, 6) → (-6, 3)
T(4,4) → (-4, 4), and
U(5,1) → (-1, 5)
Hence, the coordinates of the new image are S(3, 6) → (-6, 3), T(4,4) → (-4, 4), and U(5,1) → (-1, 5).
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In a math class with 23 students, a test was given the same day that an assignment was due. There were 15 students who passed the test and 18 students who completed the assignment. There were 13 students who passed the test and also completed the assignment. What is the probability that a student chosen randomly from the class failed the test and did not complete the homework?
Answer: To find the probability that a student chosen randomly failed the test and did not complete the homework, we need to subtract the number of students who passed the test and/or completed the homework from the total number of students in the class. Then, we can divide that number by the total number of students in the class to get the probability.
To start, we can use the information given in the problem to create a Venn diagram:
```
Test
|------|------|
| | |
Fail | | |
| | |
--------|------|------|
| | |
| | |
Pass | | |
Assignment|------|------|
| | |
| | |
```
From the diagram, we can see that the number of students who failed the test and did not complete the homework is the number of students outside the intersection of the two circles. To find this number, we can add the number of students who passed the test but did not complete the homework to the number of students who completed the homework but did not pass the test, and then subtract the number of students who passed the test and completed the homework:
Number of students who failed the test and did not complete the homework = (Number of students who passed the test but did not complete the homework) + (Number of students who completed the homework but did not pass the test) - (Number of students who passed the test and completed the homework)
Number of students who failed the test and did not complete the homework = (15 - 13) + (18 - 13) - 13
Number of students who failed the test and did not complete the homework = 4
Therefore, there are 4 students who failed the test and did not complete the homework.
To find the probability of choosing one of these students at random, we can divide the number of students who meet both conditions by the total number of students:
Probability of choosing a student who failed the test and did not complete the homework = Number of students who failed the test and did not complete the homework / Total number of students
Probability of choosing a student who failed the test and did not complete the homework = 4 / 23
Probability of choosing a student who failed the test and did not complete the homework ≈ 0.17
Therefore, the probability that a student chosen randomly from the class failed the test and did not complete the homework is approximately 0.17, or 17% (rounded to two decimal places).
46. Evaluate \( (1+i)^{k}-(1-i)^{k} \) for \( k=4,8 \), and 12 . Predict the value for \( k=16 \). 48. Show that a solution of \( x^{8}-1=0 \) is \( \frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2} i \).
46. k=4 we have -4, k= 8 we have -64, k=12 we have -64, k=16 we have 256
48. (sqrt(2)/2) + (sqrt(2)/2)i is a valid solution of the given equation
46. Evaluate (1 + i)k - (1 - i)k for k = 4, 8, and 12. Predict the value for k = 16.
The given expression can be expanded using the binomial theorem as follows:
(1 + i)k - (1 - i)k = [(1 + i)2]k/2 - [(1 - i)2]k/2 = (2i)k/2 = 2k/2 × ik/2 = 2k/2 × eiπk/4
For k = 4, we have:
(1 + i)4 - (1 - i)4 = 2^2 × e^iπ = -4
For k = 8, we have:
(1 + i)8 - (1 - i)8 = 2^4 × e^2iπ = 16
For k = 12, we have:
(1 + i)12 - (1 - i)12 = 2^6 × e^3iπ = -64
For k = 16, we can predict the value using the same formula:
(1 + i)16 - (1 - i)16 = 2^8 × e^4iπ = 256 × 1 = 256
Thus, the predicted value is 256.
48. Show that a solution of x8 - 1 = 0 is (sqrt(2)/2) + (sqrt(2)/2)i.
Given: x^8 - 1 = 0
Let z = x^4
z^2 - 1 = 0
z^2 = 1
z = ±1
Thus, x^4 = ±1
Let a = x^2
a^2 - 1 = 0
a^2 = 1
a = ±1
Thus, x^2 = ±1
Let b = x
b^2 - 1 = 0
b^2 = 1
b = ±1
Thus, x = ±1 or x^2 = -1
Let x^2 = -1
x^2 + 1 = 0
(x + i)(x - i) = 0
x = ±i
Thus, the solutions of x^8 - 1 = 0 are x = 1, -1, i, -i, (sqrt(2)/2) + (sqrt(2)/2)i, (sqrt(2)/2) - (sqrt(2)/2)i, (-sqrt(2)/2) + (sqrt(2)/2)i, and (-sqrt(2)/2) - (sqrt(2)/2)i.
Therefore, the solution (sqrt(2)/2) + (sqrt(2)/2)i is a valid solution of the given equation.
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i need answers ASAP Chau wants to earn more than $62 trimming trees. He charges $6 per hour and pays $4 in equipment fees. What are the possible numbers of hours Chau could trim trees?
Answer:
he could work 11 hours
Step-by-step explanation:
if he worked 11 hours he would have earned 66 dollars and had to to take out 4 dollars for an equipment fee therefore leaving him with 62 dollars.
An engineer is using a polynomial function to model the height of a roller coaster over time x, as shown.
On a coordinate plane, a curve increases from quadrant 3 and crosses the y-axis at (0, 4). It then decreases and crosses the x-axis at (5, 0). It continues to decrease and then starts to increase and crosses the x-axis at (8, 0).
The engineer wants to modify the roller coaster design by transforming the function. Which represents 2 f (0.3 x minus 1) + 10, the modified design of the roller coaster?
On a coordinate plane, a curve increases from quadrant 3 and crosses the y-axis at (0, 10). It then decreases and goes through (20, 10). It continues to decrease and then starts to increase and goes through (30, 10).
On a coordinate plane, a curve increases from quadrant 3 and crosses the y-axis at (0, negative 10). It then decreases and goes through (20, negative 10). It continues to decrease and then starts to increase and goes through (30, negative 10).
On a coordinate plane, a curve increases from quadrant 3 and crosses the y-axis at (0, 20). It then decreases and then increases again.
On a coordinate plane, a curve increases from quadrant 3 and crosses the y-axis at (0, 10). It then decreases and goes through (20, negative 10). It continues to decrease and then starts to increase and goes through (30, negative 10).
The polynomial function is therefore a quadratic function with the formula (3x - 10)²/25 + 10.
What is the rollercoaster polynomial equation?Unlike the graph that depicts the stock market, the functions for roller coasters need to be smooth curves. The polynomial function[tex]f(x)= -0.000833^{(x3 + 12x2 -580x -1200)[/tex] can be used to depict a simple rollercoaster.
According to the information provided, the original function was as follows: vertical stretch by a factor of 2 horizontal compression by a factor of 1/0.3 = 10/3 horizontal shift right by one unit.
Starting with a common function like f(x) = x², we can perform the following transformations:
Replace x with 3x/10 for the horizontal compression factor, and with 3x/10 for the horizontal shift to the right. Replace x with 3x/10 - 1 for the vertical stretch factor. Vertically move up 10 units by replacing y with 2y: y = 2y + 10.
When you combine everything, you get:
2 f(0.3x - 1) + 10
= 2 (2(3x/10 - 1)² + 10)
= (3x - 10)²/25 + 10
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What is m∠1
m
∠
1
, in degrees, in the figure below?
Two intersecting lines that form 4 angles. Angle one is adjacent to angle two and together form a straight angle. Angle two is vertical to the angle labeled X minus 30 degrees, which is adjacent to the angle labeled 2 X plus 15 degrees. Together, these two angles also form a straight angle.
The value οf m∠1 is 145 degrees is adjacent to the angle labelled 2 X plus 15 degrees..
What are linear pair angles?Pairs οf angles that adds uptο 180 degrees . when a segment is intersected then the angle fοrmed are knοwn as angles in linear pair. the angles add uptο 180 degrees
We are given twο angle in linear pair
And we knοw that there additiοn is 180 degrees.
we have,
x- 30 + 2x+15= 180
3x-15= 180
3x =195
x=65 degrees
2x +15 and m∠1 are vertically οppοsite angle.
Hence they are οf equal measure
Hence
m∠1 = 2x+15
m∠1 = 2(65)+15
m∠1 = 145 degrees
Hence, The value οf m∠1 is 145 degrees.
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Type the correct answer in each box. Use numerals instead of words.
What are the x-intercept and vertex of this quadratic function?
g(x) = -5(x − 3)²
-
Write each feature as an ordered pair: (a,b).
The x-intercept of function g is
The x-intercept of g(x) is (3,0) and the vertex of g(x) is (3,0).
What is the x-intercept of the function?
To find the x-intercept of the quadratic function g(x), we need to set g(x) equal to zero and solve for x:
0 = -5(x - 3)²
Dividing both sides by -5, we get:
0 = (x - 3)²
Taking the square root of both sides, we get:
x - 3 = 0
x = 3
So the x-intercept of the function g(x) is (3,0).
To find the vertex of the function g(x), we can use the formula:
vertex = (h, k)
where;
h is the x-coordinate of the vertex and k is the y-coordinate of the vertex.For a quadratic function in the form:
f(x) = a(x - h)² + k
the vertex is located at the point (h, k).
In the given function g(x), we can see that a = -5, h = 3, and k = 0.
So the vertex of the function g(x) is:
vertex = (h, k) = (3, 0)
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This trapezoid has been divided into two right triangles and a rectangle.
How can the area of the trapezoid be determined using the area of each shape?
Enter your answers in the boxes.
The area of the rectangle is in², the area of the triangle on the left is in², and the area of the triangle on the right is in².
The area of the trapezoid is the sum of these areas, which is in².
Trapezoid ABCD with parallel sides DC and AB. Points F and E are between D and C. FEBA form a rectangle with 4 right angles. D F is 2 inches, F E is 14 inches, E C is 2 inches, A B is 14 inches., and E B is 12 inches.
Answer:
here it is
Step-by-step explanation:
This trapezoid has been divided into two right triangles and a rectangle.
How can the area of the trapezoid be determined using the area of each shape?
Enter your answers in the boxes.
The area of the rectangle is in², the area of the triangle on the left is in², and the area of the triangle on the right is in².
The area of the trapezoid is the sum of these areas, which is in².
Trapezoid ABCD with parallel sides DC and AB. Points F and E are between D and C. FEBA form a rectangle with 4 right angles. D F is 2 inches, F E is 14 inches, E C is 2 inches, A B is 14 inches., and E B is 12 inches.
Geet sells televisions. He earns a fixed amount for each television and an additional $30 if the buyer gets an extended warranty. If Geet sells 18 televisions with extended warranties, He earns $1,710. How much is the fixed amount Geet earns for each television?
Answer:
understand
Step-by-step explanation:
The fixed amount Geet earns for each television is $60.
Match the letter with the transformation that it controls in the graph of an exponential.
f(x) = ab-h + k
h
[Choose ]
[Choose ]
horizontal shift
vertical shift
negative shift
reflection over asymptote
reflection over y axis
In the equatiοn [tex]f(x) = ab^{(x-h)}+ k:[/tex]
The letter h cοntrοls the hοrizοntal shift οf the graph.
What is hοrizοntal shift ?The hοrizοntal shift highlights hοw the input value οf the functiοn affects its graph. When dealing with hοrizοntal shifts, the fοcus is sοlely οn hοw the graph and functiοn behave alοng the x-axis. Understanding hοw hοrizοntal shifts wοrk is impοrtant, especially when graphing cοmplex functiοns.
The hοrizοntal shift οccurs when a graph is shifted alοng the x -axis by h- units — either tο the left οr tο the right. Alοng with οther transfοrmatiοns, it is impοrtant tο knοw hοw tο identify and apply hοrizοntals οn different functiοns — including trigοnοmetric functiοns.
What is an equatiοn?A mathematical equatiοn is a fοrmula that uses the equals sign (=) tο express the equality οf twο expressiοns. The meanings οf the wοrds "equatiοn" and its cοgnates in οther languages can differ slightly. Fοr example, in French, an equatiοn is defined as having οne οr mοre variables, whereas in English, an equatiοn is any prοperly fοrmed fοrmula that cοnsists οf twο expressiοns cοnnected by the equals sign.
The first step in sοlving an equatiοn with variables is tο identify the values οf the variables that make the equality hοld true. The variables fοr which the equatiοn must be sοlved are alsο referred tο as unknοwns, and the values οf the unknοwns that satisfy the equality are referred tο as the equatiοn's sοlutiοns.
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What is the area of a sector with a central angle of 180° and a diameter of 21.2 cm?
Use 3.14 for πand round your final answer to the nearest hundredth.
Enter your answer as a decimal in the box.
cm²
The area of the sector with a central angle of 180° as required to be determined in the task content is; 176.41 cm².
What is the area of the sector described?It follows from the task content that the sector in discuss has a central angle of 180° and a diameter of 21.2 cm.
Recall the area of a sector is;
Area, A = (theta/360) × πr²
where r = diameter / 2
r = 21.2/2
r = 10.6 cm.
A = (180/360) × 3.14 × 10.6²
Area, A = 176.41 cm².
Ultimately, the area of the sector is; 176.41 cm².
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Please specify whether each of the following items would be counted as part of investment in the c i g (x - m) equation. And why?
In response to the given question, we can state that An increase in firm expressions inventories: This would be considered investment because it indicates an increase in items created but not yet sold.
what is expression ?In mathematics, you can multiply, divide, add, or subtract. An expression is formed as follows: Expression, number, and math operator Numbers, parameters, and functions make up a mathematical expression. It is possible to contrast phrases and expressions. Every mathematical statement that comprises variables, numbers, and a mathematical action between them is referred to as an expression. For example, the phrase 4m + 5 is made up of the phrases 4m and 5, as well as the variable m from the provided equation, all separated by the mathematical symbol +.
A firm constructs a new factory: Indeed, because it reflects an increase in actual capital goods utilised for manufacturing, this would be considered investment.
A family buying a new refrigerator: No, because it is a consumer expenditure rather than a capital good utilised for production, this would not be considered investment.
Indeed, a government building a new roadway would be considered an investment since it increases the physical infrastructure needed for manufacturing.
An increase in firm inventories: This would be considered investment because it indicates an increase in items created but not yet sold.
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(Please answer quickly! Giving brainliest!!!)Which expression is equivalent to the expression quantity negative 8 over 7 times t plus 4 over 12 end quantity minus expression quantity negative 3 over 14 times t plus 7 over 4 end quantity?
13 over 14 times t plus negative 25 over 14
5 over 7 times t plus 5 over 14
negative 13 over 14 times t plus 17 over 12
negative 13 over 14 times t minus 17 over 12
The equivalent expressiοn in the given οptiοns is -13/14t - 17/12.
What are expressiοns?In mathematics, an expressiοn that incοrpοrates variables, cοnstants, and algebraic οperatiοns is knοwn as an algebraic expressiοn (additiοn, subtractiοn, etc.). Terms cοmprise expressiοns.
The cοncept οf algebraic expressiοns is the use οf letters οr alphabets tο represent numbers withοut prοviding their precise values. We learned hοw tο express an unknοwn value using letters like x, y, and z in the fundamentals οf algebra. Here, we refer tο these letters as variables. Variables and cοnstants can bοth be used in an algebraic expressiοn. A cοefficient is any value that is added befοre a variable and then multiplied by it.
frοm the questiοn:
We can simplify the given expressiοn as fοllοws:
-8/7t + 4/12 - (-3/14t + 7/4)
= -8/7t + 1/3 - (-3/14t + 7/4) (4/12 = 1/3)
= -8/7t + 1/3 + 3/14t - 7/4 (dοuble negative becοmes pοsitive)
= (-16/14)t + (2/6) + (3/14)t - (49/14)
= (-24/14)t - (47/14) (cοmbining like terms)
= (-12/7)t - (47/14) (simplifying)
The equivalent expressiοn in the given οptiοns is -13/14t - 17/12.
Thus, the apprοpriate chοice is:
negative 13 οver 14 times t minus 17 οver 12
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AC method factoring requires the polynomial to be
A cylinder has a height of 23 m and a volume of 18,488 m³. what is the radius of the cylinder? round your answer to the nearest whole number. responses 256 m 256 m 50 m 50 m 32 m 32 m 16 m
Answer:
Step-by-step explanation:
The volume for a right cylinder is
[tex]V=\pi r^2h[/tex]
We are given all the values except the radius, so we plug them in as follows:
[tex]18488=\pi r^2(23)[/tex]
Begin by dividing by 23π to get
255.8657603 = r²
and then take the square root of both sides to find that
r = 15.995 or 16 m
Omar has 7 2/5 yards of ribbon to make bows. Each bow is made from a piece of ribbon that is 3/5 yard long. What is the maximum number of complete bows Omar can make?
Omar can make a maximum of 12 complete bows from the given length of ribbon.
How To find the maximum number of complete bows?
To find the maximum number of complete bows Omar can make, we need to divide the total length of ribbon he has by the length of ribbon needed for each bow, and then round down to the nearest whole number since we can only make complete bows.
First, we need to convert 7 2/5 yards to an improper fraction so that we can work with it more easily. To do this, we multiply the whole number (7) by the denominator of the fraction (5), and then add the numerator (2):
7 2/5 = (7 x 5) + 2/5 = 35/5 + 2/5 = 37/5 yards
Now we can divide the total length of the ribbon by the length needed for each bow:
37/5 ÷ 3/5 = 37/5 x 5/3 = 37/3
This gives us a fraction, but we want a whole number, so we round down to the nearest integer:
37/3 ≈ 12.33
Since we can only make complete bows, the maximum number of bows Omar can make is 12.
Therefore, Omar can make a maximum of 12 complete bows from the given length of ribbon.
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Answer:
12
Step-by-step explanation:
The maximum number of complete bows omar can make is 12
Please ASAP Help
Will mark brainlest due at 12:00
Answer:
-2b+12
Step-by-step explanation:
Answer:
-2b+12
Step-by-step explanation:
-2b-4(b+3)-4b
-2b+4b+12-4b
-2b+12
could anyone help :(
cos(x)=0.6
find two numerical solutions ?
The two numerical solutions of the given trigonometric functions are: 53.13° or 306.87°
How to solve trigonometric ratios?In the first quadrant, where the value of x and y coordinates are all positive, it is well known that all the six trigonometric functions possess positive values. In the second quadrant, we see that only sine and cosecant (which is the reciprocal of sine) possess positive values. In the third quadrant, we see that only tangent and cotangent possess positive positive values.
The cosine function is positive in the first and fourth quadrants.
Now, we are told that;
cos(x) = 0.6
Thus;
x = cos⁻¹(0.6)
x = 53.13° or 306.87°
These are the numerical solutions required.
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If 5 pineapples and 8 apples cost $42, and 7 pineapples and 4 apples cost $48, then how much do two apples cost?
The cost of two apples is 2A = 2(9.95) = $19.90.
What is an equation system, and how can it be utilised to solve issues?A system of equations is a collection of equations that must all be solved concurrently in order to determine the values of the variables that satisfy every equation at once. In order to solve a problem, a system of equations can be employed, where each equation represents a distinct connection or constraint. The variables' values that fulfil all of the relationships or restrictions in the circumstance can be discovered by solving the system of equations. Several strategies, including substitution, elimination, and matrix approaches, can be used to solve a system of equations.
Let us suppose the cost of pineapples = P.
The cost of apples = A.
Thus, from the given statement we have the equation as:
5P + 8A = 42 (equation 1)
7P + 4A = 48 (equation 2)
Rearranging the equation 2 we have:
7P = 48 - 4A
P = (48 - 4A) / 7
Substitute this expression for P into equation 1:
5[(48 - 4A) / 7] + 8A = 42
240/7 - 20A/7 + 8A = 42
44A/7 = 438/7
A = 9.95
Therefore, the cost of two apples is 2A = 2(9.95) = $19.90.
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The orange spinner is spun and then the aqua spinner is spun. What is the probability that the numbers will add to 4 or less?
50%
25%
3/8
7/16
Answer:
n
Step-by-step explanation:
less
Triangle ABC has vertices A(1, 3), B(−2, −1), and C(3,−2).
After going through the following glide reflection, find the coordinates for A′′, B′′, and C′′.
Translation: along <0, −2>
Reflection: across x-axis
The Coordinates of A′′, B′′, and C′′ are (1, -1),(-2, 3) and (3, 4).
What is Coordinate system ?
A coordinate system is a system that defines how points in space or on a plane can be located and labeled using a set of numbers or coordinates. In a two-dimensional coordinate system, the points are located on a plane, while in a three-dimensional coordinate system, the points are located in space.
First, we apply the translation of moving all points down by 2 units.
A(1, 3) is transformed to A'(1, 1) by subtracting 2 from the y-coordinate.
B(−2, −1) is transformed to B'(-2, −3) by subtracting 2 from the y-coordinate.
C(3,−2) is transformed to C'(3, −4) by subtracting 2 from the y-coordinate.
Next, we apply the reflection across the x-axis.
A'(1, 1) is transformed to A''(1, -1) by negating the y-coordinate.
B'(-2, −3) is transformed to B''(-2, 3) by negating the y-coordinate.
C'(3, −4) is transformed to C''(3, 4) by negating the y-coordinate.
Therefore, the coordinates for A'', B'', and C'' are:
A''(1, -1)
B''(-2, 3)
C''(3, 4)
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Compute each sum or differences
11/12 - 2/3
[tex]1/4\\[/tex]
Explanation:
To subtract 2/3 from 11/12, we need to find a common denominator for the two fractions. The least common multiple (LCM) of 3 and 12 is 12. We can rewrite each fraction with a denominator of 12:
11/12 - 2/3 = (11/12) - (2/3) * (4/4) (Multiplying the denominator and numerator of 2/3 by 4 to get a denominator of 12)
11/12 - 8/12 = 3/12
Now that both fractions have a common denominator of 12, we can subtract the numerators:
11/12 - 2/3 = (11 - 8)/12 = 3/12
Simplifying this fraction by dividing both the numerator and denominator by 3, we get:
3/12 = 1/4
Therefore, 11/12 - 2/3 = 1/4.
A cone has base area 25 mm². A parallel slice 6 mm from the vertex has area 36 mm². Find the height of
the cone.
Therefore , the solution of the given problem of area comes out to be the cone has a 5 millimetre height.
What exactly is area?Calculating how much space would be needed to fully cover the outside will reveal its overall size. When calculating a trapezoidal form's surface, the environs were also taken into account. The surface area of something determines its overall measurements. The amount of edges connecting each of a cuboid's four parallelogram ends reveals how much underground water it can hold.
Here,
Let's name the cone using the details provided:
Its base measures 25 mm2.
A parallel slice 6 mm from the vertex has a 36 mm2 surface.
We can use the fact that the area of a circular slice of a cone is proportional to the square of its distance from the vertex to build up a proportion:
(area of slice) / (base area) Equals (distance from vertex) / (height) 2/ (area from slice)
When we enter the numbers we are aware of, we obtain:
=> 36 / 25 = 6² / h²
If we simplify, we get:
=> h² = (25 * 6²) / 36 = 25
When we square the two edges, we obtain:
=> h = 5
As a result, the cone has a 5 millimetre height.
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A veterinarian weighs a client's dog on a scale. If the dog weighs 35. 16 pounds, what level of accuracy does the scale measure?
The veterinarian can accurately measure the dog's weight up to two decimal places (i.e., 35.16 pounds).
What is Precision?
Precision refers to the level of detail or the smallest increment that a measurement instrument can measure. It is the degree to which repeated measurements under the same conditions show the same results.
To determine the level of accuracy of the scale, we need to know the precision of the measurement. Precision refers to the smallest increment that the scale can measure.
If the scale measures in whole pounds, then the precision is 1 pound. If the scale measures in half-pound increments, then the precision is 0.5 pounds. If the scale measures in quarter-pound increments, then the precision is 0.25 pounds.
Assuming the scale measures in hundredths of a pound, we can say that the precision of the scale is 0.01 pounds. Therefore, the level of accuracy of the scale is 0.01 pounds.
So, the veterinarian can accurately measure the dog's weight up to two decimal places (i.e., 35.16 pounds).
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If √x-3a+√x-3b=√x-3c then prove that x = (a+b+c) ±2√√a² + b² + c²-ab-bc-ca
The required expression has been proved to [tex]$$x = (a+b+c) \pm 2\sqrt{a^2+b^2+c^2-ab-bc-ac}$$[/tex]
How to Solve to prove the problem?Starting with the given equation:
[tex]$$\sqrt{x-3a}+\sqrt{x-3b}=\sqrt{x-3c}$$[/tex]
Squaring both sides, we get:
[tex]$$(x-3a)+(x-3b)+2\sqrt{(x-3a)(x-3b)}=x-3c$$[/tex]
Simplifying and rearranging terms:
[tex]$$2x-3a-3b-3c+2\sqrt{(x-3a)(x-3b)}=0$$[/tex]
Dividing both sides by 2 and rearranging:
[tex]$$\sqrt{(x-3a)(x-3b)}= \frac{3a+3b+3c-2x}{2}$$[/tex]
Squaring both sides again:
[tex]$$(x-3a)(x-3b)=\left(\frac{3a+3b+3c-2x}{2}\right)^2$$[/tex]
Expanding the right side:
[tex]$(x-3a)(x-3b)=\frac{9a^2+9b^2+9c^2+2(3ab+3ac+3bc)-4(3a+3b+3c)x+4x^2}{4}$$[/tex]
Simplifying:
[tex]$$4(x-3a)(x-3b)=9a^2+9b^2+9c^2+2(3ab+3ac+3bc)-12(a+b+c)x+16x^2$$[/tex]
Expanding:
[tex]$$4x^2-12(a+b+c)x+9(a^2+b^2+c^2+2ab+2bc+2ac)-36ax-36bx+36ab-36cx+36bc=0$$[/tex]
Rearranging:
[tex]$$4x^2-8(a+b+c)x+9(a+b+c)^2-12(ab+bc+ac)=0$$[/tex]
Using the quadratic formula:
[tex]$x = \frac{8(a+b+c) \pm 2\sqrt{16(a+b+c)^2-4\cdot4\cdot(9(a^2+b^2+c^2-ab-bc-ac))}}{8}$$[/tex]
Simplifying:
[tex]$$x = (a+b+c) \pm 2\sqrt{a^2+b^2+c^2-ab-bc-ac}$$[/tex]
Therefore, we have proven that:
[tex]$$x = (a+b+c) \pm 2\sqrt{a^2+b^2+c^2-ab-bc-ac}$$[/tex]
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suppose that a factory produces light bulbs and the percentage of defective lightbulbs is 3.5%. if a sample of 550 light bulbs is selected at random, what is the probability that the number of defective bulbs in the sample is greater than 15?
The probability that the number of defective bulbs in the sample is greater than 15 is 0.401, or 40.1%.
This is a binomial distribution problem with n=550 and p=0.035. We want to find the probability that the number of defective bulbs in the sample is greater than 15, which can be written as P(X > 15), where X is the number of defective bulbs in the sample.
Using the binomial probability formula, we have:
P(X > 15) = 1 - P(X ≤ 15)
P(X ≤ 15) = Σi=0¹⁵ (550 chooseᵃ) * 0.035ᵃ * (1-0.035)⁵⁵⁰⁻ᵃ
We can use software or a calculator with a binomial probability distribution function to find this sum, which is approximately 0.599.
Therefore, the probability that the number of defective bulbs in the sample is greater than 15 is:
P(X > 15) = 1 - P(X ≤ 15) ≈ 1 - 0.599 = 0.401
So the probability that more than 15 bulbs in the sample are defective is approximately 0.401, or 40.1%.
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Examples of associative law of addition in matrix form
The associative law of addition states that (A + B) + C = A + (B + C). This can be expressed in matrix form as the addition of three matrices to give the same result.Let A, B, and C be 3x3 matrices.
The associative law of addition states that (A + B) + C = A + (B + C).
This can be expressed in matrix form as:
[tex]\begin{bmatrix}a_{11} & a_{12} & a_{13} \\a_{21} & a_{22} & a_{23} \\a_{31} & a_{32} & a_{33}\end{bmatrix}[/tex]
+
[tex]\begin{bmatrix}b_{11} & b_{12} & b_{13} \\b_{21} & b_{22} & b_{23} \\b_{31} & b_{32} & b_{33}\end{bmatrix}[/tex]
+
[tex]\begin{bmatrix}c_{11} & c_{12} & c_{13} \\c_{21} & c_{22} & c_{23} \\c_{31} & c_{32} & c_{33}\end{bmatrix}[/tex]
[tex]\begin{bmatrix}a_{11} + b_{11} + c_{11} & a_{12} + b_{12} + c_{12} & a_{13} + b_{13} + c_{13} \\a_{21} + b_{21} + c_{21} & a_{22} + b_{22} + c_{22} & a_{23} + b_{23} + c_{23} \\a_{31} + b_{31} + c_{31} & a_{32} + b_{32} + c_{32} & a_{33} + b_{33} + c_{33}\end{bmatrix}[/tex]
=
[tex]\begin{bmatrix}a_{11} + (b_{11} + c_{11}) & a_{12} + (b_{12} + c_{12}) & a_{13} + (b_{13} + c_{13}) \\a_{21} + (b_{21} + c_{21}) & a_{22} + (b_{22} + c_{22}) & a_{23} + (b_{23} + c_{23}) \\a_{31} + (b_{31} + c_{31}) & a_{32} + (b_{32} + c_{32}) & a_{33} + (b_{33} + c_{33})\end{bmatrix}[/tex]
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Find the amplitude, phase shift, and period of the function.
y = 2 – (1/2) cos (3x+π)
Give the exact values, not decimal approximations. Amplitude: ___
Phase shift: ___
Period: ____
The amplitude οf the functiοn is 1/2, the phase shift is (-π)/3, and the periοd is 2π/3.
What is Phase Shift?Phase shift simply means that the twο signals are at different pοints οf their cycle at a given time.
The given functiοn is y = 2 – (1/2) cοs (3x+π).
We can see that the general fοrm οf this functiοn is y = A cοs (Bx - C) + D, where A is the amplitude, B is the frequency, C is the phase shift, and D is the verticaI shift.
Cοmparing the given functiοn with the general fοrm, we can see that:
A = 1/2
B = 3
C = -π
D = 2
Therefοre, the amplitude is |A| = 1/2.
The phase shift is given by C/B = (-π)/3.
The periοd οf the functiοn is given by T = 2π/B = 2π/3.
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Triangle A″B″C″ is formed by a reflection over x = −1 and dilation by a scale factor of 4 from the origin. Which equation shows the correct relationship between ΔABC and ΔA″B″C″?
segment A double prime B double prime equals four segment BC
segment BC equals 4 segment A double prime B double prime
segment AB over segment A double prime B double prime equals one fourth
segment C double prime A double prime over segment CA equals one fourth
Triangle A″B″C″ is formed by a reflection over x = −1 and dilation by a scale factor of 4 from the origin. segment A double prime B double prime equals four segment BC ,equation shows the correct relationship between ΔABC and ΔA″B″C″
The equation that correctly shows the relationship between ΔABC and ΔA″B″C″ is C″A″/CA = 1/4. Triangle A″B″C″ is formed by reflecting triangle ABC over the line x = -1 and dilating it by a scale factor of 4. The reflection of a triangle preserves its angles and its sides are reversed, while the dilatation stretches the triangle out by a factor of 4. Therefore, the ratio between C″A″ and CA will be 1/4.
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Do only number 4 please
Answer:
baby formulaa for sure (wut ur school I got same question)
Step-by-step explanation:
add sum purple to yo nails