____ is the vertical distance between two or more lines or surfaces (part features) that are in horizontal planes.

Bounded

Bounded function

In mathematics, a function f is referred to as being bounded if the set of its values is bounded and it is defined on a set X with real or complex values. In other words, there is a real number M such that for all x in X, displaystyle |f(x)|leq M|f(x)|le M. Unbounded functions are those that are not bounded. The function is said to be bounded (from) above by A if f is a real-valued function and f(x) A for all x in X. The function is said to be bounded (from) below by B if f(x) B for all x in X. If and only if it is bounded from above and below, a real-valued function is said to be bound.

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The statement of Tamika  is correct.

Recall that we designate an angle as a place where two line meet. The magnitude of the angle could be measured by the use of a compass. A right angle triangle is a triangle that has an angle of ninety degrees as one of the angles.

Let us keep in mind that all the sides of a rectangle must have an angle of ninety degrees. This is because the sum of the angles in a rectangle must sum up to a total of three hundred and sixty degrees.

Having said that; when we consider the statements of the two persons and reason that if we have two right angled triangles, we could be able to make a rectangle because the four right angles that are required could be cut out of the two congruent right angled triangles. This implies that the statement of Tamika  is correct.

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The probability of both owning a dog is 0. 52

Probability can be defined as the chance that a given event occurs.

From the information given, we have that;

The probability of owning a dog is 26%

Let's convert to decimal

Probability of owning a dog = 26 / 100 = 0.26

P(2 people) = 2 × P(owning a dog)

P(2 people) = 2 × 0. 26

Multiply through

P(2 people) = 0. 52

The probability of both owing a dog is 0.52

Thus, the probability of both owning a dog is 0. 52

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The probability of natural states after applying the Bayes theorem to modify the prior probabilities in light of available indicator data is known as the posterior probability.

The posterior probability is a type of conditional probability that is created by applying the Bayes theorem to update the prior probability with information that is summarized by the likelihood. From an epistemological standpoint, the posterior probability, given prior knowledge and a mathematical model describing the observations available at a specific time, contains all that is known about an uncertain proposition (such as a scientific hypothesis, or parameter values).  The present posterior probability may act as the prior in a subsequent round of Bayesian updating following the arrival of new data. The posterior probability distribution often expresses the epistemic uncertainty regarding statistical parameters conditional on a set of observed data in the context of Bayesian statistics.

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The statement 'The mode is the value of the observation that appears most frequently.' is True.

We know that, the mode is the most frequent number.

It is the number that occurs the highest number of times.

The observation occurring the most number of times or which has highest frequency is known as the mode.

For example,  in {6, 3, 9, 6, 6, 5, 9, 3} the Mode is 6 as it occurs most often.

There is no mode when all observed values appear the same number of times in a data set.

Therefore, the statement 'The mode is the value of the observation that appears most frequently.' is True.

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The 150 m³ cone that has a base radius of 5 meters indicates that the height of approximate length 5.73 meters is greater than the radius (length 5 meters)

The given parameters are;

Volume of the cone is V = 150 m³

Base radius of the cone, r = 5 m

The formula for finding the volume of a cone is; [tex]V = \mathbf{\frac{1}{ 3} \cdot \pi \cdot {r}^{2} \cdot h} [/tex]

By plugging in the values for the volume, V and radius, r, of the cone, we have;

[tex]150 = \frac{1}{ 3} \times \: \pi \times {5}^{2} \times h[/tex]

Which gives;

[tex] h = \mathbf{ \frac{150}{ \frac{1}{ 3} \times \: \pi \times {5}^{2} } \approx 5.73} [/tex]

Therefore;

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Lollipops costs $0.15

Petits costs $0.1

let x represent the cost of lollipops

let y represent the cost of petits

6x + 5y = 1.40.........equation 1

5x + 6x= 1.35.........equation 2

From equation 1

6x + 5y= 1.40

6x= 1.40 -5y

x= 1.40-5y/6

Substitute 1.40-5y/6 for x in equation 2

5(1.40-5y/6) + 6y = 1.35

7-25y/6 + 6y= 1.35

7-25y+36y/6= 1.35

cross multiply

7 +11y= 8.1

11y= 8.1-7

11y= 1.1

y= 1.1/11

y= 0.1

Substitute 0.1 for y in equation 1

6x +5y= 1.40

6x + 5(0.1)= 1.40

6x + 0.5= 1.40

6x= 0.9

x= 0.9/6

x= 0.15

Hence the cost of lollipops is $0.15 and cost of petits is $0.1

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The increase in sales after 170% increase with the initial sales 3 million is

5,100,000 (5 million and 1 lakh or 51 lakh).

Percentage means a number or a ratio represented in the form of fractions of 100. It is represented using the percentage sign ‘%’. The abbreviations used to represent the percentage are ‘pct’ or ‘pc’. In other words, the percentage is defined as how much of one quantity is made by another quantity and it is evaluated in terms of 100.

We have to increase the value by 170%.

The value of the percentage increase = 170% × 3,000,000

The new value = 3,000,000 + The value of the percentage increase

The new value = 3,000,000 + The value of the percentage increase

=3,000,000 + (170% × 3,000,000) = 3,000,000 + 170% × 3,000,000

=(1 + 170%) × 3,000,000 = (100% + 170%) × 3,000,000

=270% × 3,000,000 = 270 ÷ 100 × 3,000,000

=270 × 3,000,000 ÷ 100 = 810,000,000 ÷ 100

=8,100,000 million.

The actual change = The new value - 3,000,000

=8,100,000 - 3,000,000

=5,100,000 million or 5.1 million.

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Answer:

Correct options are A) , B) , C) and D)

secA=

8

17

⇒cosA=

17

8

⇒sinA=±

17

15

cscB=

4

5

⇒sinB=

5

4

⇒cosB=±

5

3

Now cos(A+B)=cosAcosB−sinAsinB

⇒cos(A+B)=

17

8

.

4

5

−(±

17

15

.±

5

3

)=±

85

36

or ±

85

84

∴sec(A+B)=±

36

85

,±

84

85

The percent of decrease from 136 days to 85 days to the nearest tenth is 37.5%

Change in number of days = Original days - New days

= 136 days - 85 days

= 51 days

Percentage decease = Change in number of days / Original days × 100

= 51 / 136 × 100

= 0.375 × 100

= 37.5%

Therefore, the percent of decrease from 136 days to 85 days to the nearest tenth is 37.5%

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Answer:

Hello,

Step-by-step explanation:

[tex]P(x)=6x^5-22x^2+11x-126\\\\P(2)= 6*2^5-22*2^2+11*2-126=0\\\\x-2\ is\ well\ a \ factor\ of\ P(x).\\\\\begin{array}{c|ccccccc}&x^5&x^4&x^3&x^2&x&1\\---&---&---&---&---&---&---\\&6&0&0&-22&11&-126\\x=2&&12&24&48&52&126\\---&---&---&---&---&---&---\\&6&12&24&26&63&0\end {array}\\\\P(x)=6x^5-22x^2+11x-126=(x-2)*(6x^4+12x^3+24x^2-26x+63)\\[/tex]

Answer:

14

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

2 x 7 = 14 apples

Answer: 2/23

Step-by-step explanation:

9+14=23

"Correlational" research looks at how variables vary with each other, while "experimental" research looks at how one variable causes a change in another variable.

Research is a form of non-experimental methodology in which a researcher measures 2 factors and analyzes and evaluates the statistical relationship among them without the influence of any other variable.

Some key features regarding the correlational research are-

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Answer:

4

Step-by-step explanation:

The probability of person being a heavy smoker given person died is 0.57 .

Baye's Theorem helps in finding the probability of any event A given that event B has already occurred.

For Example the probability of event A given that event B has already occurred is denoted by

[tex]P(A/B)=\frac{P(B/A)P(A)}{P(B)}[/tex]

In the given question

Let H denoted heavy smokers , L denote Light smokers , N denote Non smokers.

Given the probability of non smokers P(N) = 50%=0.5

the probability of light smokers P(L)=20%=0.2

the probability of heavy smokers P(H)=30%=0.3

let P(D/H) denoted the person died given he was a heavy smoker.

let P(D/L) denoted the person died given he was a light smoker.

let P(D/N) denoted the person died given that he was a non smoker.

According to question

"heavy smokers twice as likely to die as light smokers" means

P(D/H)=2P(D/L)......(1)

and "light smokers twice as likely to die as nonsmokers" means

P(D/L)=2P(D/N)

On simplifying we get

[tex]P(D/N)=\frac{1}{2} P(D/L)\\ \\ P(D/N)=0.5 P(D/L)[/tex].....(2)

According to Baye's Theorem

[tex]P(H/D)=\frac{P(D/H)P(H)}{P(D/N)P(N)+P(D/L)P(L)+P(D/H)P(H)}[/tex]

Substituting values of P(D/H) from ...(1) and values of P(D/N) from ....(2)

we get [tex]P(H/D)=\frac{2*P(D/L)P(H)}{0.5*P(D/L)P(N)+P(D/L)P(L)+2*P(D/L)P(H)}[/tex]

taking P(D/L) common from each term

[tex]P(H/D)=\frac{P(D/L)}{P(D/L)} (\frac{2*P(H)}{0.5*P(N)+P(L)+2*P(H)})[/tex]

[tex]P(H/D)= (\frac{2*P(H)}{0.5*P(N)+P(L)+2*P(H)})[/tex]

Substituting the values of P(N), P(H), P(L) from above we get

[tex]P(H/D)= (\frac{2*(0.3)}{0.5*(0.5)+(0.2)+2*(0.3)})[/tex]

[tex]P(H/D)= (\frac{0.6}{0.25+0.2+0.6})[/tex]

=[tex]\frac{0.6}{1.05}=0.57[/tex]

Therefore , the probability of person being a heavy smoker given person died is 0.57 .

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Answer:

1 significant figure

Step-by-step explanation:

Zero is significant when:

It occurs between two non-zero integers, such as 408; it occurs at the end of a number that contains a decimal point, such as 570. or 1.300

Zero is not significant when:

It is before the first non-zero integer, such as 0.0057 (two significant figures); it is at the end of a number that does not contains a decimal point, such as 253,000 (three significant figures)

(trust me I'm taking chemistry this year and literally that is the 'rule' that is written down in my notebook)

The total number of boxes required for packing the carrots is 40 boxes.

The unitary approach is a strategy for problem-solving that involves first determining the value of a single unit, then multiplying that value to determine the required value. The unitary technique, in essence, determines the value of a unit from the value of a multiple. To put it simply, it determines the value of a single unit from a given multiple. How can you figure out the price of one pen if 100 cost Rs. 400? You can reach the solution using the unitary technique. Additionally, after a single unit's value has been established, the values of the other units can be derived by multiplying the original unit's value.

Janine is carrying carrots because of this. There are 20 2-pound bags of carrots in each huge box.

We must determine how many boxes Janine can fill.

Now, 800/20=40 boxes are equal to the total number of bags/bags each box can contain.

This means that a total of 40 boxes are needed to load the carrots.

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Answer:

There are 60 people in the chior so we will be dividing that number up to see how many women men and children there are. Half of them are women, which mean divide 60 by 2 which equals 30. There are 30 women in the choir. The number of women is 3 times compared to men. Since its 3 times we use the commutative property of division. 30 divided by 3 is 10. There are 10 men in the choir. The rest are children. To find the rest of them we will take how many people in the choir we know so far and then subtract from the total: 60. there are 30 women and 10 men which adds up to 40. 60 minus 40 equals 20. There are 20 children in the choir.

Since n = number of men and children:

n = 30

30 : 1

Step-by-step explanation:

Hope it helps! =D

The explicit rule for the sequence using subscript notation is [tex]a_n=2000\times1.2^{n-1}[/tex] .

It is given that sequence is G.P

In G.P 2nd and 4th is given by

 [tex]a_2=ar[/tex]      ...(1)      and              [tex]a_4=ar^3[/tex]  ...(2)

We have given [tex]a_2=2400 , a_4=3456[/tex]

Putting in equation (1) and (2) , we get

       [tex]2400=ar[/tex]    ...(3)          and           [tex]3456=ar^3[/tex]      ...(4)

On dividing equation (3) by equation (4) , we get

        [tex]\frac{2400}{3456} =\frac{ar}{ar^3} \\\\\\ 0.6944=\frac{1}{r^2}\\\\r^2=1.44 \\r=1.2[/tex]

First term will be given by

       [tex]a_1=a_2 r^{1-2}\\\\a_1=2400r^{-1}\\\\a_1=\frac{2400}{1.2} \\\\a_1=2000[/tex]

Nth term is given by

[tex]a_n=a_1r^{n-1}\\a_n=2000\times1.2^{n-1}[/tex]

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Answer:

7/9

Step-by-step explanation:

Combine the two variables: 9p = 7

Then do 7 / 9

Answer:

the answer is D  (-2 + 4)

Step-by-step explanation:

the lower line shows -2 and the higher one shows +4

A description of the distribution of the values of a random variable and their associated probabilities is called a Probability Distribution.

Understanding the random variable and its probability is necessary for the analysis of complex random occurrences. The numerical result of a random process, which might be discrete or continuous in nature, is known as a random variable.

Now,

Hence, A description of the distribution of the values of a random variable and their associated probabilities is called a Probability Distribution.

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The solution to the given inequality is: F < -9/2.

The inequality is given by:

F + 2 and 1/2 < -2.

First we have to realize the conversion of the mixed number to fraction, as follows:

2 and 1/2 = 2 + 1/2 = 4/2 + 1/2 = 5/2

Hence the inequality is:

F + 5/2 < -2

F < -2 - 5/2

F < -4/2 - 5/2

F < -9/2.

The solution to the given inequality is: F < -9/2.

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Answer: 2fg

Step-by-step explanation:

Rewrite using the commutative property of multiplication = 2fg

Answer: 164 ft^2

Step-by-step explanation:

l=length. w=width. h=height. SA=surface area

SA=2(l*w)+2(l*h)+2(w*h)

SA=2(10*3)+2(10*4)+2(3*4)

SA=2(30)+2(40)+2(12)

SA=60+80+24

SA=140+24

SA=164 ft^2

Answer:

can you put a better pic

Step-by-step explanation:

The number of mandarin oranges one can buy for $9 is 48 oranges. It is calculated using basic arithmetic operations.

What are arithmetic operations?

Arithmetic operations are the basic mathematical operations which deal with simple calculations. It involves addition (+), subtraction (-), multiplication (×), and division (÷). Arithmetic operations can be used to combine two or more expressions in some or the other way.

Calculation of the number of mandarin oranges one can buy for $9

We are given that,

$6 = 4 pounds

Using arithematic operation division,

Dividing by 6 into both sides, we have,

$1 = 4 / 6 pounds

$1 = 2 / 3 pounds

Using arithematic operation multiplication,

Multiplying the above equation with 9 on both sides,

$9 = (2 / 3) * 9 pounds

$9 = 6 pounds              - - - - - (1)

According to the given question,

1 orange  weighs 2 ounces         - - - - -(2)

1 pound = 16 ounces                  

1 pound = 8 × (2 ounces)

Using equation 2,

1 pound = 8 oranges

Using equation 1,

$9 = 6 (8 oranges)

$9 = 48 oranges

Hence, one can buy 48 oranges for 9 dollars i.e. $9.

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Answer: C

Step-by-step explanation:

g(7) = 7/8 (7)  - 1/2

g(7) = 6.125  - 1/2

g(7) = 5.625   OR in fraction form, 45/8

The answer is C

Answer: seventy-eight million

Step-by-step explanation:

seventy eight million four thousand / setenta y ocho million cuatro mil