From the problem, the minimum height of the tunnel that Jamie's van must be able to pass through is 12.5 m.
How to get the Height?We can approach this problem by determining the minimum width and height of the tunnel that Jamie's van must be able to pass through. If her van is able to fit through these minimum dimensions, then it should be able to pass through the entire tunnel.
Let's start with the width of the tunnel. Since Jamie cannot cross the middle line due to heavy oncoming traffic, her van must fit entirely within her own lane. Therefore, the width of the tunnel must be at least equal to the width of her van, which is 2.5 m.
Next, let's consider the height of the tunnel. At its highest point, the tunnel is 8 m tall. However, Jamie's van is 5 m tall. To pass through the tunnel, the van must fit under the lowest point of the tunnel that is at least 5 m above the ground. We can use the shape of the parabolic tunnel to determine the minimum height that Jamie's van can pass through.
The shape of a parabolic curve is given by the equation y = ax^2, where y is the height, x is the distance from the center of the curve, and a is a constant that determines the steepness of the curve. In this case, we can use the fact that the tunnel is 8 m wide at its base to determine the value of a.
At the center of the tunnel (x = 0), the height is 8 m. Therefore, we have:
8 = a(0)^2
a = 8
Substituting this value of a into the equation for the parabolic curve, we have:
y = 8x^2
To determine the minimum height that Jamie's van can pass through, we need to find the value of x that corresponds to the edge of her van. Since her van is 2.5 m wide, this corresponds to a distance of 1.25 m from the center of the lane.
Substituting x = 1.25 into the equation for the parabolic curve, we have:
y = 8(1.25)^2
y = 12.5
Therefore, the minimum height of the tunnel that Jamie's van must be able to pass through is 12.5 m.
Since the height of the tunnel is greater than the height of Jamie's van, she should be able to pass through without any problems. However, she should still exercise caution and be mindful of the height and width of her vehicle when driving through narrow spaces.
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PQR is a right angled triangle at P nad ahs PQ
The length QR of the right angle triangle is 26 cm.
How to find the side of a right triangle?A right triangle is a triangle that has one of its angles as 90 degrees. The sum of angles in a triangle is 180 degrees.
Therefore, the side of a right angle triangle can be found using Pythagoras's theorem as follows:
Hence,
c² = a² + b²
where
c = hypotenusea and b are the other legsTherefore,
24² + 10² = QR²
576 + 100 = QR²
QR² = 676
QR = √676
QR = 26 cm
Therefore,
length of QR = 26 cm
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given f(x)=x^3-x^2-5x-3 and the factor x-3, find the zeros of the function f(x).
0.062 in standard form
Answer:
6.2 × 10-2
Step-by-step explanation:
HELP. (worth 35 points and will crown brainliest !)
Answer:
Theoretical probability for each color is 1/4, or 25%.
Experimental probability of blue is 42/200, or 21%.
Experimental probability of purple is 55/200, or 27.5%.
Experimental probability of green is 71/200, or 35.5%.
Experimental probability of red is 32/200, or 16%.
Correct statements:
Experimental property of purple (27.5%) is more than theoretical property of blue (25%).
Theoretical property of blue (25%) is more than experimental property of red (16%).
hw06-MoreProbability: Problem 11 (1 point) Suppose that you roll two 6 sided dice. a) What is the size of the sample space?
b) What is the probability that the sum of the dice is a 7 ? c) What is the probability that the sum of the dice is at least a 7?
a) Sample space = {36}
b) Probability of the sum of the dice is a 7 = P(E) = 6/36 = 1/6
c) Probability of the sum of the dice is at least a 7 = P(F) = 21/36 = 7/12.
We need to find, What is the size of the sample space? Probability of the sum of the dice is a 7 ?Probability of the sum of the dice is at least a 7? Solution a)Sample space is defined as the set of all possible outcomes. Suppose that you roll two 6 sided dice. So, The possible outcomes of each die is {1,2,3,4,5,6}.The total outcomes for rolling two dice are {1,1}, {1,2}, {1,3}, {1,4}, {1,5}, {1,6}, {2,1}, {2,2}, {2,3}, {2,4}, {2,5}, {2,6}, {3,1}, {3,2}, {3,3}, {3,4}, {3,5}, {3,6}, {4,1}, {4,2}, {4,3}, {4,4}, {4,5}, {4,6}, {5,1}, {5,2}, {5,3}, {5,4}, {5,5}, {5,6}, {6,1}, {6,2}, {6,3}, {6,4}, {6,5}, and {6,6}.Therefore, Sample space = {36}.b)Let E be the event that the sum of the dice is a 7.The events where the sum of the dice is a 7 are {1,6}, {2,5}, {3,4}, {4,3}, {5,2}, and {6,1}.The number of events where the sum of the dice is a 7 is 6.Therefore, Probability of the sum of the dice is a 7 = P(E) = 6/36 = 1/6.c)Let F be the event that the sum of the dice is at least a 7.Therefore, F = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1), (2,6), (3,5), (4,4), (5,3), (6,2), (3,6), (4,5), (5,4), (6,3), (4,6), (5,5), (6,4), (5,6), and (6,5)}The number of events where the sum of the dice is at least a 7 is 21.Therefore, Probability of the sum of the dice is at least a 7 = P(F) = 21/36 = 7/12.a) Sample space = {36}.b) Probability of the sum of the dice is a 7 = P(E) = 6/36 = 1/6.c) Probability of the sum of the dice is at least a 7 = P(F) = 21/36 = 7/12.
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13 Convert 20 to a percentage.
Answer:
13/20 written as a decimal is 0.65 and as a percent is 65%
1) Make the denominator 100 (20 x 5)
2) Multiply by five from the numerator too (13 x 5 = 65)
Alex is a single taxpayer with $80,000 in taxable income. His investment income consists of $500 of qualified dividends and short-term capital gains of $2,000. Use the tables to complete the statement
Due to Alex's salary falling inside the 22% tax bracket, his short-term capital gains would be subject to the same rate of taxation as his income.
What is short-term capital?A profit realized from the sale of a capital asset, such as a piece of personal or investment property, that has been possessed for one year or less is referred to as a short-term gain.
These profits are classified as ordinary income subject to tax at your personal income tax rate. Gain earned by selling assets that are held for a year or less are called short-term capital gains.
Alex is a single taxpayer who has taxable income of $80,000.
His investment income is made up of $2,000 in short-term capital gains and $500 in qualifying dividends.
As a result of his tax rate income falling between 38,601 and 425,800, which is below 15%, his qualifying dividends would be subject to a 15% tax.
Hence, we must deduct 15% of 500 and 22% of 2000 before combining them.
15% x 500
= 15 x 5
= 75
22% x 2000
= 22 x 20
= 440.
The total is = 75 + 440 = 515.
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A
What is an equation of the line that passes through the point (-2,5) and is perpendicular
to the line whose equation is y=-x+ 5?
O y = 2x+9
Oy=-2x+1
Oy= 2x+1
Oy=-2x-9
Answer: The given line has a slope of -1, since its equation is y = -x + 5. The line that is perpendicular to this line will have a slope that is the negative reciprocal of -1, which is 1. So, we know that the equation of the line we're looking for will have a slope of 1.
To find the equation of this line, we need to use the point-slope form of the equation of a line:
y - y1 = m(x - x1)
where m is the slope of the line, and (x1, y1) is a point on the line.
We know that the point (-2, 5) is on the line we're looking for, and we know that the slope of the line is 1. So we can substitute these values into the point-slope form:
y - 5 = 1(x - (-2))
Simplifying, we get:
y - 5 = x + 2
Adding 5 to both sides, we get:
y = x + 7
Therefore, the equation of the line that passes through the point (-2, 5) and is perpendicular to the line y = -x + 5 is y = x + 7.
Step-by-step explanation:
Find the first three terms of the sequence Tn = n2 - 2n - 6
The first three terms of the sequence Tₙ = n^2 - 2n - 6 are -7, -8, and 0, and the sequence is a quadratic sequence with a parabolic graph that opens upward.
To find the first three terms of the sequence Tₙ = n^2 - 2n - 6, we simply need to substitute the first three positive integers for n, which gives us:
T₁ = 1^2 - 2(1) - 6 = -7
T₂ = 2^2 - 2(2) - 6 = -8
T₃ = 3^2 - 2(3) - 6 = 0
Therefore, the first three terms of the sequence are -7, -8, and 0.
The sequence Tₙ is a quadratic sequence, which means that it has a second-order difference. In other words, the differences between the terms of the sequence form a linear sequence.
Specifically, the first differences are 2, 4, 6, 8, and so on, which form an arithmetic sequence with a common difference of 2. The second differences are all equal to 2, which confirms that the sequence is quadratic.
The graph of the sequence Tₙ is a parabola that opens upward, with a vertex at (1, -7). This means that the sequence starts with a negative term, then decreases until it reaches a minimum at n = 1, and then increases indefinitely.
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harrison St thomas St, and Denny Way are parallel. on broad St, the distance between mercer St and Denny way is 0.7 miles. the distance between those same streets on aurora ave is 0.45 miles
The distance between Thomas St and Denny Way on Broad St is 0.1 miles.
How do we calculate?0.45 miles on Aurora Ave is equivalent to the distance between Mercer St and Denny Way on Broad St.
0.2 miles on Aurora Ave is equivalent to the distance between Thomas St and Denny Way on Aurora Ave.
We say X be the distance between Thomas St and Denny Way on Broad St,
and have the following proportion:
0.45 miles / (Mercer St to Denny Way on Broad St) = 0.2 miles / (Thomas St to Denny Way on Broad St)
Solving for x, we get:
x = 0.45 miles x (Thomas St to Denny Way on Broad St) / (Mercer St to Denny Way on Broad St) = 0.45 * 0.2 / 0.7 = 0.1286 miles
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Complete question:
Use the following information and the map of downtown Seattle to answer questions one and two. Harrison St, Thomas St, and Denny Way are parallel. On Broad St, the distance between Mercer St and Denny Way is 0.7 miles. The distance between those same streets on Aurora Ave is 0.45 miles.
a) On Aurora Ave the distance between Thomas St to Denny Way is 0.2 miles. What is the distance
between these two streets on Broad St? Round your answer to the nearest tenth of a mile.
Below, there is a pattern with its first 5 terms listed. Describe a way to produce each tern from the previous term.
1/2, 1, 2, 4, 8, ...
The formula that describes a way to produce each term from the previous term in the given geometric sequence is: aₙ = ¹/₂(2)ⁿ⁻¹
How to solve geometric sequence?In mathematics, a geometric sequence, is defined as a sequence that consists of non-zero numbers whereby each of the terms after the first is found by multiplying the previous one by a fixed, non-zero number that is referred to as the common ratio.
The formula that is usually utilized in finding the nth term of a geometric sequence is expressed as:
aₙ = arⁿ⁻¹
where:
a is first term
r is common ratio
Thus:
a = 1/2
r = 2/1 = 2
Thus:
aₙ = ¹/₂(2)ⁿ⁻¹
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A road race is 6 kilometers long. There is a water station at the halfway mark. How many meters away from from the start line is the water station
Answer: 3000m
Step-by-step explanation:
Half of 6 km is 3 km
To convert to meters multiply 3 times 1000
That will give you 3000m=3km
Each day for the next 4 days, there is a 40% chance of a thunderstorm. Use the simulation shown, where the digits 1 through 4 represent days with a thunderstorm, to estimate the probability of a thunderstorm on at least 3 of the next 4 days. Round your anwser to the newrest tenth percent if necessary
Therefore , the solution of the given problem of probability comes out to be there is a 37.5% chance of thunderstorms occurring on at least three of the next four days.
What is probability, exactly?The primary goal of the form of patterns defined as hyper parameters is to calculate the likelihood that a remark is accurate or a specific event will occur. Any number between 0 but instead 1, where 1 usually denotes assurance and range 0 typically connotes possibility, can be used to represent chance. A probability diagram shows the chance that a specific event will occur.
Here,
We must count the number of outcomes in which there are 3 or 4 thunderstorms in order to calculate the chance that a thunderstorm will occur on at least 3 of the following 4 days using the simulation.
We can see from the programme that there are 6 scenarios where there are at least 3 thunderstorms:
=> 1-2-3-4
=> 1-2-4-3
=> 1-3-2-4
=> 1-3-4-2
=> 1-4-2-3
=> 1-4-3-2
Since there are a total of 16 potential outcomes (since a thunderstorm can occur every day or not), the likelihood of at least 3 thunderstorms is:
=> 6/16 = 0.375
This means that there is a 37.5% chance of thunderstorms occurring on at least three of the next four days.
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please please help its geometry
In response to the given question, we can state that we know that sum of all angles in a triangle is 180. m∠C = 4*11.67+43 = 89.68 = =90
What precisely is a triangle?A triangle is a polygon because it contains four or more parts. It features a simple rectangular shape. A triangle ABC is a rectangle with the edges A, B, and C. When the sides are not collinear, Euclidean geometry produces a single plane and cube. If a triangle contains three components and three angles, it is a polygon. The corners are the points where the three edges of a triangle meet. The sides of a triangle sum up to 180 degrees.
we know that sum of all angles in a triangle is 180.
2x - 12 + 4x + 43 + 9x - 26 = 180
15x + 5 = 180
15x = 175
x = 11.67
m∠C = 4*11.67+43 = 89.68 = =90
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Answer:
m∠C = 119°
Step-by-step explanation:
According to the Exterior Angle Theorem, the exterior angle of a triangle is equal to the sum of the two non-adjacent interior angles of the triangle.
From inspection of the given triangle, the exterior angle is (9x - 26)° and the two non-adjacent interior angles are ∠B and ∠C.
Equate the sum of the two non-adjacent angles to the exterior angle and solve for x:
⇒ (2x - 12)° + (4x + 43)° = (9x - 26)°
⇒ 2x - 12 + 4x + 43 = 9x - 26
⇒ 6x + 31 = 9x - 26
⇒ 57 = 3x
⇒ x = 19
To calculate the measure of angle C, substitute the found value of x into the expression for the angle:
⇒ m∠C = (4x + 43)°
⇒ m∠C = (4(19) + 43)°
⇒ m∠C = (76 + 43)°
⇒ m∠C = 119°
Unit 8: Right Triangles & Trigonometry
Homework 4: Trigonometric Ratios &
Finding Missing Sides
In the right-angled triangle ABC the value of line segment BD is obtained as x = 21.91.
What is a right-angled triangle?
Any two sides of a triangle's three sides must always add up to more than the third side since a triangle is a regular polygon with three sides. This distinguishing characteristic of a triangle. A right-angle triangle is one that has angles between its two sides that equal 90 degrees.
A right-angled triangle ABC with drawn with angle B = 90°.
A line BD is drawn which is perpendicular to AC.
The angle BDC is also 90 degrees.
The measure for line segment AD = 12 and CD = 40.
The measure for line segment BD is x.
The side BD is common for triangle ABC and BDC.
So, by the formula of indirect measurement we have -
DC / BD = BD / AD
Substitute the values in the equation -
40 / x = x / 12
x² = 480
x = 21.908
x = 21.91
Therefore, the value of x is obtained as 21.91.
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Answer:
Sin Q
7/25
Cos Q
24/25
Tan Q
7/24
Sin R
24/25
Cos R
7/25
Tan24/7
Step-by-step explanation:
12. Describe the graph of a quadratic function that has its vertex and a zero
at the same point.
The dot represents the vertex, and the x represents the point where the parabola touches the x-axis. The parabola is symmetric about the vertical line x = h and does not cross the x-axis anywhere else.
What is parabola?A parabola is a type of curve that is defined by a specific mathematical equation, namely, the quadratic equation. It is a symmetrical curve that can be described as the shape of the graph of a quadratic function.
by the question.
If (h, k) is a zero of the function, then. [tex]f(h) = 0[/tex]. Substituting this into the equation for f(x), we get:
[tex]0 = a(h - h)^2[/tex]
[tex]0 = 0[/tex]
This is a true statement, which tells us that (h, k) is indeed a zero of the function.
Now, let's consider the graph of this function. Since the coefficient a is non-zero, the parabola will be facing either upwards or downwards. If a > 0, then the parabola will be facing upwards, and if a < 0, then the parabola will be facing downwards.
Since the vertex of the parabola is at (h, k), the axis of symmetry is the vertical line x = h. Therefore, the parabola is symmetric about this line.
Finally, since (h, k) is also a zero of the function, the parabola must cross the x-axis at x = h with a single point of tangency. This means that the parabola just touches the x-axis at this point and does not cross it.
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Divide round your answer to the nearest set $40. 90 divided by 66
If $40.90 divided by 66, the rounded answer to the nearest set of 40 is given as $0.
To round the answer of $40.90 divided by 66 to the nearest set of 40, we need to perform the division and then round the quotient to the nearest multiple of 40.
First, let's perform the division:
$40.90 / 66 = 0.6206...
The quotient is a decimal, but we need to round it to the nearest multiple of 40. To do this, we need to find out how close the quotient is to each of the multiples of 40 and then round to the nearest one.
The nearest multiples of 40 are 0, 40, 80, 120, etc.
To determine how close the quotient is to each of these multiples, we can subtract the quotient from each multiple and take the absolute value of the result:
|0 - 0.6206| = 0.6206
|40 - 0.6206| = 39.3794
|80 - 0.6206| = 79.3794
The smallest absolute difference is between the quotient and 0, so we round down to 0.
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The measures of the angles of a triangle are shown in the figure below. Solve for x.
According to the conditions, in right angled triangle, the value of x is 6.
What is angle ?
In mathematics, an angle is a geometric figure formed by two rays (or line segments) that share a common endpoint, known as the vertex of the angle.
In a right-angled triangle, the sum of the two acute angles is always 90 degrees. Therefore, we can use this fact to find the value of x.
We are given that one of the acute angles is 60 degrees, and the other angle is 7x - 12 degrees. So we can write:
60 + (7x - 12) = 90
Simplifying this equation, we get:
7x + 48 = 90
Subtracting 48 from both sides, we get:
7x = 42
Dividing both sides by 7, we get:
x = 6
Therefore, in right angled triangle, the value of x is 6.
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Please it’s argent
What amount would you have in a retirement account if you made annual deposits of $375 for years earning 12% compounded annually?
Answer:%40.50
Step-by-step explanation: i tired
Solve the quadratics attached using the quadratic formula or completing the square
[tex]p^2-6p+8[/tex]
The value of p is 2 and 4.
What is a quadratic equation?
Any equation that can be written in the standard form where x is an unknown value, a, b, and c are known quantities, and a 0 is a quadratic equation. Any equation containing one term in which the unknown is squared and no term in which it is raised to a higher power.
Here, we have
Given: p² - 6p + 8
we have to solve the quadratic formula or complete the square.
= p² - 6p + 8
= p² -4p - 2p + 8
= p(p-4) -2(p-4)
= (p-4)(p-2)
(p-4)(p-2) = 0
p-4 = 0,
p-2 = 0
p = 4, 2
Hence, the value of p is 2 and 4,
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Help,i need help please
a. The inequality required is 2x-y≤3 b. We can graph the inequality of x+2y<4. c. it is not common solution point.
Describe Inequality?An inequality is a mathematical statement that compares two quantities and indicates whether one is greater than, less than, or equal to the other. Inequalities use special symbols, such as "<" (less than), ">" (greater than), "≤" (less than or equal to), and "≥" (greater than or equal to), to represent the relationship between the two quantities.
For example, the inequality 2x + 3 < 7 means that the quantity 2x + 3 is less than 7. To solve this inequality, we can subtract 3 from both sides to get 2x < 4, and then divide both sides by 2 to get x < 2.
Inequalities can also involve variables, such as x or y, and they can be used to represent real-world situations, such as the amount of money in a bank account, the temperature of a room, or the speed of a car.
Inequalities are important in mathematics and other fields because they allow us to compare quantities and make decisions based on those comparisons. They are used in a variety of applications, including economics, physics, engineering, and statistics.
a. Here the inequality, represented by graph
Take two points lying in the line
(x1,y1)=(0,-3) and (x2,y2)= (2,1)
So,
equation of line is
y+3= [tex]\frac{1-(-3)}{2} (x-0)=[/tex] 2x-y-3=0
Thus, the inequality required is 2x-y≤3.
b. We can graph the inequality of x+2y<4
c. Here, we are not agree with Oscar
Reason:- Since (2,1) point lies on inequality 2x-y≤3 but it did not lie on inequality x+2y<4
So it is not common solution point.
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Help,
The Density of
Some Steel is 7.84g/cm³.
What is the mass of 70cm³ of this Steel?
Give your answer to 1 d.p.
Step-by-step explanation:
*change density to kg per cubic meter
*change volume to cubic meter
*rearrange the formula to solve for mass
How many whole numbers are in the interval between -5 and 23/6
A:0
B:3
C:4
D:5
Im actually stuck
Answer: i believe its 5
Step-by-step explanation:
when predicted errors have a kurtosis of 5, which ols assumption is violated? a. no clustering b. homoskedasticity c. no autocorrelation d. normality e. random sampling f. mean of estimated errors has to be 0
The OLS assumption that is violated when predicted errors have a kurtosis of 5 is normality. The correct option is (d). Kurtosis is a statistical measure of the peak of a probability distribution curve. It measures how the tails of the distribution compare to a normal distribution.
Oridinary Least Squares (OLS) is a regression technique that assumes that the response variable has a linear relationship with the explanatory variable(s) and that the response variable has normal distribution error terms. However, in some cases, such as when the predicted errors have a kurtosis of 5, this assumption of normality is violated. If the distribution has more of its observations in the tails than a normal distribution, it is said to be leptokurtic. If it has fewer of its observations in the tails than a normal distribution, it is said to be platykurtic.
Kurtosis of 5 means that the distribution is leptokurtic and has fatter tails than the normal distribution.Assuming normality of the errors means that the residuals or errors are normally distributed. If the errors are not normally distributed, then the residuals will not be normally distributed either. This will affect the accuracy of the confidence intervals and hypothesis tests. The coefficient estimates may be biased and the confidence intervals may be too wide or too narrow. Therefore, normality of the errors is an important assumption of OLS regression and in this case it has been violated.
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Find the distance between the two points.(-6,8) (6,3)
The distance between the two points (-6, 8) and (6, 3) is equal to 13 units.
How to calculate the distance between the two points?Mathematically, the distance between two (2) points that are on a coordinate plane can be calculated by using this formula:
Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]
Where:
x and y represents the data points (coordinates) on a cartesian coordinate.
Substituting the given points into the distance formula, we have the following;
Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]
Distance = √[(6 - (-6))² + (3 - 8)²]
Distance = √[(12)² + (-5)²]
Distance = √(144 + 25)
Distance = √169 units.
Distance = 13 units.
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An open box (no lid) with a square base has a volume of 4 cubic feet. What dimensions will minimize the surface area?
If a square base has a volume of 4 cubic feet, the dimensions that minimize the surface area are: x = 2√2 and h = 4/x^2 = 1/2.
Let x be the side length of the square base and h be the height of the box. Since the volume is 4 cubic feet, we have:
V = x^2h = 4
Solving for h, we get:
h = 4/x^2
The surface area of the box, A, is given by:
A = x^2 + 4xh
Substituting h in terms of x, we get:
A = x^2 + 4x(4/x^2) = x^2 + 16/x
To minimize A, we take the derivative with respect to x and set it equal to zero:
dA/dx = 2x - 16/x^2 = 0
Solving for x, we get:
x = 2√2
To ensure that this is a minimum, we take the second derivative:
d^2A/dx^2 = 2 + 32/x^3
At x = 2√2, this is positive, indicating a minimum.
The box has a square base with side length 2√2 feet and height 1/2 feet.
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Please Help!
A plane is located at C on the diagram. There are two towers located at A and B.
The distance between the towers is 7,600 feet, and the angles of elevation are given.
a. Find BC, the distance from Tower 2 to the plane, to the nearest foot.
b. Find CD, the height of the plane from the ground, to the nearest foot.
This is 6/6 problems finish them all each is 10 points 60 total.
The angle R is 53.1° by the use of the cosine which is one of the trigonometric ratios that we have.
What is trigonometry?In trigonometry, the three most important trigonometric functions are sine (sin), cosine (cos), and tangent (tan). These functions relate the angles of a triangle to the ratios of its sides. For example, the sine of an angle is the ratio of the length of the side opposite the angle to the length of the hypotenuse (the longest side of the right-angled triangle).
Cos R = 3/5
R = Cos-1(3/5)
R = 53.1°
Hence, we can see that the required angle R is obtained as 53.1°
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Rock and Bowl charges $2.75 per game plus $3 for shoe rental. Super Bowling charges $2.25 per game and $3.50 for shoe rental. For how many games will the cost to bowl be approximately the same at both places? What is that cost?
Answer:
1 game, for $5.75
Step-by-step explanation:
To find this answer, all you need to do is create an equation for both Rock and Bowl and the Super Bowling and then set them equal to each other to find out and solve which value of x games makes them equal.
The first equation is 2.75x +3
The second one is 2.25x + 3.5
2.75x + 3 = 2.25x + 3.5
2.75x = 2.25x + .5
From here, you can either solve for x or realize that x being equal to 1 makes both values equal.
So, the answer is 1 game now to plug it into one of our equations, we get
2.75(1) + 3 which we know is equal to the other equation too which is $5.75 dollars
Each number in the table below represents the number of employees at different stores in
two nearby malls.Part A
Determine the interquartile range for numbers of employees at each mall. Show your work or
explain your reasoning.
Part B
Which mall would you expect to have greater variability in regard to numbers of employees?
Show your work or explain your reasoning.
(A) The interquartile range for numbers of employees at Mall A is 65 and at Mall B is 7.5. (B) Mall B would we expect to have greater variability in regard to numbers of employees.
Part A: To determine the interquartile range (IQR) for numbers of employees at each mall, we first need to find the median for each mall. The median is the middle value of a set of data when arranged in order.
For Mall A:
Arrange the numbers in ascending order: 18, 20, 21, 22, 25, 26, 27, 28, 28, 29
The median is the average of the two middle numbers, which are 25 and 26.
Median = (25 + 26) / 2
= 25.5
Next, we need to find the first quartile (Q1) and the third quartile (Q3). The first quartile is the median of the lower half of the data, and the third quartile is the median of the upper half of the data.
For Mall A:
Lower half: 18, 20, 21, 22, 25
Upper half: 26, 27, 28, 28, 29
Q₁ = median of the lower half
= (21 + 22) / 2
= 21.5
Q₃ = median of the upper half
= (28 + 28) / 2
= 28
The interquartile range for Mall A is:
IQR = Q3 - Q1
= 28 - 21.5
= 6.5
For Mall B:
Arrange the numbers in ascending order: 19, 21, 23, 24, 25, 26, 27, 29, 30, 33
The median is the average of the two middle numbers, which are 25 and 26.
Median = (25 + 26) / 2
= 25.5
Lower half: 19, 21, 23, 24, 25
Upper half: 26, 27, 29, 30, 33
Q₁ = median of the lower half
= (21 + 23) / 2
= 22
Q3 = median of the upper half
= (29 + 30) / 2
= 29.5
The interquartile range for Mall B is:
IQR = Q3 - Q1
= 29.5 - 22
= 7.5
Part B: To determine which mall would have greater variability in regard to numbers of employees, we can compare the interquartile ranges for each mall. The interquartile range measures the spread of the middle 50% of the data. The larger the interquartile range, the greater the variability.
In this case, Mall B has a larger interquartile range than Mall A (7.5 vs. 6.5). This suggests that there is greater variability in the number of employees at Mall B.
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