Answer:
Apparently the curve is not banked.
The maximum frictional force is -
Ff = m g * .5
Fc = m v^2 / R where Fc is the centripetal force that must be present in
order for the car not to slip.
.5 g = v^2 / R equating forces
v^2 = .5 R g = .5 ^ 1000 * 9.80
v = (500 * 9.80)^1/2 = 70 m/s
(about 230 ft/sec = 230/88 * 60 = 157 mph
PE:
Write T in the blank if the statement is true and E if it is false.
_____1. A basketball game starts with a jump ball.
_____2. Basketball is a cardiovascular work-out.
_____3. The middle of the basketball court is called the sideline.
_____4. Unlimited substitutions are allowed during a regular basketball game.
_____5. If the ball crosses the sideline, it is considered out of bounds and goes to the other team.
_____6. A turnover is any loss of the ball without a shot being taken.
_____7. A player may intentionally kick the ball for the team's benefit.
_____8. When dribbling a ball, a basketball you want to keep the ball below your waist and off to the side of your body.
_____9. If your opponent shoots at the wrong hoop your team receives the points.
_____10. After a player stops dribbling the ball in basketball, he or she is allowed 4 steps to pass or shoot.
Answer:
The answers are:
T, T, F, F, T, T, F, F, T, T, F
Good luck!
The solar mass of the Sun is 1. The orbital period of Jupiter is 11. 9 Earth years. What is the distance between Jupiter and the Sun? 5. 2 AU 41 AU 52 AU 410 AU.
The distance between Jupiter and the sun is 5.2 AU.
According to Kepler's third law, the square of the period of revolution of planets is proportional to the cube of their mean distances from the sun. From this; T^2 = r^3.
Now, we are told that the orbital period (T) is 11. 9 Earth years. We have to make the distance the subject of the formula.
r =T^2/3
r = (11.9)^2/3
r = 5.2 AU
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Answer:
The answer is A. 5.2 AU
Explanation:
in jus dat ni ni fr
Calculate the force of gravity of a 25kg block resting on the earth (M=5.97x10^24kg). The radius of the earth is 6.38x10^6m.
I already know...
[tex](6.67*10^{-11})(25)(5.97*10^{24} )/(6.38*10^6)^2[/tex]
But I don't understand what steps I have to take to solve that equation
From Newton's law of gravity, the force of gravity is 245 Newtons
To calculate the force of gravity of a 25kg block resting on the earth of mass M = 5.97x10^24kg with the radius r of the earth is 6.38x10^6m, let us first list out all the given parameters
Mass m = 25 kg
Mass of the earth M = 5.97x10^24kg
Radius r = 6.38x10^6m
Force F = ?
The formula to calculate the force of gravity is
F = (GMm)/[tex]r^{2}[/tex]
Where G = 6.67 x [tex]10^{-11}[/tex]
Substitute all the parameters
F = (6.67 x [tex]10^{-11}[/tex] x 5.97x10^24 x 25) / (6.38x10^6)^2
F = 9.9 x [tex]10^{15}[/tex] / 4.07 x [tex]10^{13}[/tex]
F = 244.56 N
F = 245 Newtons (approximately)
Therefore, the force of gravity is 245 Newtons
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An object is moving with a constant velocity of 311 m/s. How long will it take it to travel 9000 m?
[tex]\text{Given that,}\\\\\text{Velocity, v= 311 m s}^{-1}\\\\\text{Displacement, s = 9000 m}\\\\\text{Since velocity is constant,}\\\\s=vt\\\\\implies t =\dfrac{s}v = \dfrac{9000}{311} = 28.94 ~ \text{sec}.[/tex]
hlo anyone help
a stone is thrown upward with the kinetic energy of 10 joule if it goes up to a maximum height of 5 M find the initial velocity and mass of the stone??
Ty no spam plz help rn
Explanation:
Here, kinetic energy of the body, K.E=10 J
Height attained by the body, h=5 m
h=5m
When the body attains maximum height, its kinetic energy is converted into potential energy.
P.E=K.E
⟹mgh=10
⟹m= 10/gh
= m = 10/(10×5) =0.2 kg (taking the value g as 10m/s²)
Now, ½mv²=10
0.2×v²=20
v²=20/0.2
v²=100
v=√100
v=10m/s.
hope this helps you.
[tex]\huge \bf༆ Answer ༄[/tex]
Let's solve ~
As we know the total energy [P.E + K.E = C] of the system remains constant throughout the motion,
So, When a stone was thrown initially it didn't had any potential energy (P.E = 0) but had kinetic Energy of 10 joules.
So, total energy = P.E + K.E = 0 + 10 = 10 joules
As per the given information, equate it with the formula.
[tex] \sf \dfrac{1}{2}m {v}^{2} = 10[/tex][tex] \sf m {v}^{2} = 20[/tex]Now, As it approaches 5m height it comes to rest, Therefore velocity = 0. And since velocity = 0 then Kinetic Energy = 0
Now, let's find the Potential Energy at that point ~
[tex] \sf mgh[/tex][tex] \sf m \times 10 \times 5[/tex][tex] \sf50m[/tex]And here, the Total energy = P.E + K.E = 10 Joules
So,
[tex] \sf50m + 0 = 10 [/tex][tex] \sf50m = 10[/tex][tex] \sf m = 10 \div 50[/tex][tex] \sf m = 0.2[/tex]Therefore, mass of the object is 0.2 kg = 200 grams
Now, plug the value of mass (m) in the equation of kinetic Energy to find the initial velocity of the stone ~
[tex] \sf m {v}^{2} = 20[/tex][tex] \sf0.2 \times {v}^{2} = 20[/tex][tex] \sf {v}^{2} = 20 \div 0.2[/tex][tex] \sf v = \sqrt{100} [/tex][tex] \sf v = 10 \: \: ms {}^{ - 1} [/tex]Hence, velocity of the particle at the beginning was 10 m/s
Why would poor clusters of galaxies be more likely to have irregular shapes then rich
clusters
These Milky Way companion galaxies are easily visible from dark locations in the Southern Hemisphere. Prime examples of erratic galaxies are the Large and Small Magellanic clouds (left and right, respectively).
What clusters of galaxies likely to have irregular shapes?In comparison to a rich cluster, the poor cluster typically has a slightly more erratic shape. A number of smaller galaxies orbit each major spiral. The Small and Large Magellanic clouds are the two most well-known examples of atypical galaxies.
When two galaxies collide, irregular galaxies frequently result. This unusual Cartwheel Galaxy was created when a tiny galaxy slid through the centre of a massive spiral galaxy.
Therefore, Rich clusters are other clusters that include hundreds to thousands of galaxies. A weak cluster can't cling to its members strongly because of its low bulk.
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A young man heaves a 6.5 kg rock at a velocity of 6.9 m/s. What is the kinetic energy of the rock?
Answer:
Hope it will help you a lot.
An object of length 3.00 cm is inside a plastic block with index of refraction 1.40. If the object is viewed from directly above, what is the length of its image?
Given,
length of object, [tex]h_o = 3 cm[/tex]
We know, for flat refracting surface,
Image distance = object distance
So,
magnification is = [tex]-1[/tex]
length of the image,
[tex]h_i = magnification * h_o\\\\h_i = -1 * 3 \\\\h_i = -3cm[/tex]
Here, negative sign means inverted image.
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A coin of mass 0.0050 kg is placed on a horizontal disk at a distance of 0.14 m from the center, as shown above. The coin doesn’t slip and the time it takes for the coin to make a complete revolution is 1.5 s.
A)The figure below shows the disk and coin as viewed from above. Draw and label vectors on the figure below to show instantaneous acceleration and linear velocity vectors for the pin when it is at the position shown below.
B)Determine the linear speed of the coin
C)The rate of rotation of the disk is gradually increased. The coefficient of stats if friction between the coin and the disk is 0.50. Determine the linear speed of the coin when it just begins to slip.
D)If the experiment in part c were repeated with a second, identical coin glued to the top of the first coin, how would this affect the answer to part c? Explain.
A) Figure attached below
B) The linear speed of the coin = 0.59 m/s
C) Linear speed as coin begins to slip = 0.83 m/s
D) The tangential speed will remain the same as seen in part C
Given data :
mass of coin = 0.0050 kg
Distance of coin from the center of disk = 0.14 m
Time to make a complete revolution = 1.5 s
A) Diagram showing the vectors on the figure is attached below
B) Determine the Linear speed of the coinLinear speed of coin = 2 * π * ( 0.14 ) / 1.5
= 0.59 m/s
C) Determine the linear speed of the coin when it just begins to slipgiven that: friction between coin and disk = 0.50
Friction becomes maximum when coin begins to slip
Maximum frictional force (Fmax) = uV
where V = mg
∴ Fmax = u*mg ---- ( 1 )centripetal force = [tex]\frac{mv^{2} }{r}[/tex] ---- ( 2 )Equating equations ( 1 ) and ( 2 ) to determine the linear speed ( v )
v² = u*r*g
∴ v = √(u*r*g ) = √( 0.5 * 0.14 * 9.8 )
= 0.83 m/s
D) If the experiment is repeated with a second coin glued to the top of the first coin the tangential speed will remain the same
Hence we can conclude that The linear speed of the coin = 0.59 m/s Linear speed as coin begins to slip = 0.83 m/s , The tangential speed will remain the same as seen in part C
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how much brighter is Vega than the Sun? (astronomy)
Answer: 60 times brighter
what prevents the planets in our solar system from floating away?
A. Earth's gravitational pull
B. planets gravitational pull on one another
C. moon's gravitational pull
D. suns gravitational pull
Suns' gravitational pull prevents the planets in our solar system from floating away, therefore the correct answer is option D.
What is a solar system?It is a structure in which the sun's attractive force causes all the planetary systems and celestial bodies to revolve around this.
The Sun is believed to be located in the system's center in the sun-centered concept upon which our Solar System is founded.
The primary factor that causes the planets in the solar system to revolve around the sun is gravity.
The sun's pull of gravity prohibits the planets in our planetary system from moving away, hence option D is the appropriate
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car was moving in a straight road of length 320 km it covered 240 km with an average velocity 75 km/hr then it ran out of fuel and stopped for 0.6 hr until it was refueled and completed its journey with a velocity 100 km/hr so the average velocity during the whole journey
The average velocity of the car for the whole journey is 69.57 km/h.
The given parameters:
Length of the road, L = 320 kmDistance covered = 240 km at 75 km/htime spent refueling, t₂ = 0.6 hrFinal velocity, = 100 km/hrThe time spent by the before refueling is calculated as follows;
[tex]t = \frac{d}{v} \\\\t_1 = \frac{240}{75} \\\\t_1 = 3.2 \ hours[/tex]
The time spent by the car for the remaining journey;
[tex]t_3 = \frac{320 - 240}{100} \\\\t_3 = 0.8 \ hr[/tex]
The total time of the journey is calculated as follows;
[tex]t = t_1 + t_2 + t_3\\\\t = 3.2 \ hr \ + \ 0.6 \ hr \ + \ 0.8 \ hr\\\\t = 4.6 \ hours[/tex]
The average velocity of the car for the whole journey is calculated as follows;
[tex]v = \frac{total \ distance }{total \ time} \\\\v = \frac{320}{4.6} \\\\v = 69.57 \ km/h[/tex]
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A vector consists both?
Answer:
magnitude and a direction
Explanation:
Which statement regarding characteristics of electromagnetic radiation is correct?
Longer wavelengths of light have higher energies.
Lower frequencies of light have higher energies.
Higher frequencies of light have shorter wavelengths.
Shorter wavelengths of light have lower energies.
Answer:
Higher frequencies of light have shorter wavelengths.
Solve the science problem
Answer:
ybuTouch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.
Read this statement: Biotechnology uses primary clarifiers for biological nutrient removal.
Which part of the statement is not true?
Biological nutrients are found in wastewater.
Primary clarifiers remove biological nutrients.
Biological nutrients are part of biotechnology processes.
Biological nutrient removal is part of wastewater management.
Primary clarifiers removing biological nutrients is not true. Primary clarifiers
involves the use of processes such as sedimentation in order to remove
particles floating or other inorganic solids from the waste water.
Biological nutrients such as nitrogen and phosphorus are found in waste
water and removal of these important nutrients for other uses is a part of
waste water management.
The secondary clarifiers are the ones responsible for the removal of
biological nutrients in the waste water through biofiltration etc.
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A swimming pool of width 9.0 m and length 12.0 m is filled with water to a depth of 3.0 m. Calculate pressure on the bottom of the pool due to the water.
Hint: 1 m^3 of water has a mass of 1000 kg.
With the use of the formula, the pressure on the bottom of the pool due to the water is 29400 Pascal
Given that a swimming pool of width 9.0 m and length 12.0 m is filled with water to a depth of 3.0 m.
Volume = Length x Width x Height
Volume = 9 x 12 x 3
Volume = 324 [tex]m^{3}[/tex]
Since 1 m^3 of water has a mass of 1000 kg,
Mass = 324 x 1000
mass = 324000 kg
To calculate the pressure on the bottom of the pool due to the water, let us use the pressure formula below
P = δgh
where
P = pressure
δ = density of the water = 1000 kg/[tex]m^{3}[/tex]
g = Acceleration due to gravity = 9.8 m/[tex]s^{2}[/tex]
h = height = 3m
Substitute all the parameters into the formula
P = 1000 x 9.8 x 3
P = 29400 Pascal
Therefore, the pressure on the bottom of the pool due to the water is 29400 Pascal
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Iron, Nickel, Copper, Zinc... These are all what kind of metals?
Answer:
there very old
Explanation:
how many band is the parametric microphone equalizer?
Answer:
3 bands
Explanation:
Basically, the Parametric EQ divides the audio spectrum into three bands, allowing you to enhance (or suppress) the level in that range.
Ana wonders how light can affect a mystery material. The table below shows what happens when different types of light hit the mystery material.
The light can definitely change the mystery material. This can occur through a change in temperature or color (option C).
A material is affected by light mainly if the material absorbs the light. Based on the chart, we know this mystery material can absorb two types of light:
Red light.Yellow light.Moreover, this phenomenon can lead to two main changes:
Change in temperature: Light affects materials by increasing their temperature of these. A common example is the way the temperature of an object increases if it is exposed to sunlight.Change in color: Some materials react to light by changing their color.Based on this, the material can change its color or temperature.
Note: This question is incomplete; here is the missing part:
A. Yes, but the mystery material can change in only one way, such as by getting warm, because all the light that a material absorbs will affect that material in the same way.
B. No. The mystery material can’t change because the light is not a physical thing. Light cannot change physical things like the mystery material.
C. Yes and the mystery material can change in one or two different ways, such as by getting warm and/or changing color, because different types of light can cause different changes to a material when they are absorbed.
D. There is no way to know whether the mystery material will change or not.
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David delivers meals to elderly people once a week. He uses a cart to move the meals. The cart has four smooth wheels. Which type of friction acts between the cartwheels and the sidewalk?
Answer: rolling friction
Explanation: I think it is the answer
What is the force of gravity?
Answer:
2. 4.63 x 10 to the -11th power
Explanation:
m1 = 3.1, m2= 6.3, d = 5.3, G = 6.67 × 10^-11
m1 · m2 = 3.1 · 6.3 = 19.5
d² = 5.3² = 28.1
19.5/28.1 = 0.694
(6.67 · 10^-11) · 0.694 = 4.63 × 10^-11
Answer:
Natural phenomenon
Explanation:
Gravity, or gravitation, is a natural phenomenon by which all things with mass or energy—including planets, stars, galaxies, and even light—are attracted to one another.
Examples of this can be:
The force that holds the gases in the sun.
The force that causes a ball you throw in the air to come down again.
The force that causes a car to coast downhill even when you aren't stepping on the gas.
The force that causes a glass you drop to fall to the floor.
Write a paragraph explaining how a pressurized garden sprayer works. Make sure todescribe what happens to the air pressure insidethe sprayer as it is pumped by hand.
The principle of operation of a pressurized garden sprayer is as follows;
A pressurized garden sprayer is a chamber which is filled with a liquid which can be a lubricant, paint or chemical, then filled with compressed air to allow the liquid to be sprayed at high pressure.
As it is pumped by hand, the compressed air with which it is filled serves the primary purpose of allowing the liquid to be sprayed at high pressure - an important requirement for performance characteristics of the sprayer.
Flammable liquids must not be used with such equipment.
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A go cart with a mass of 60 kg is moving at a rate of 10 m/s. How much Kinetic Energy does the go cart have?
Answer:
3000 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass in kg
v is the velocity in m/s
From the question
m = 60 kg
v = 10 m/s
We have
[tex]k = \frac{1}{2} \times 60 \times {10}^{2} \\ = 30 \times 100 \\ = 3000[/tex]
We have the final answer as
3000 JHope this helps you
Answer:
[tex]\boxed {\boxed {\sf 3000 \ J}}[/tex]
Explanation:
Kinetic energy is the energy an object has due to motion. It is calculated using the following formula:
[tex]KE=\frac{1}{2} mv^2[/tex]
The mass of the go-cart is 60 kilograms and the velocity is 10 meters per second.
m= 60 kg v= 10 m/sSubstitute the values into the formula.
[tex]KE= \frac{1}{2} (60 \ kg)(10 \ m/s)^2[/tex]
Solve the exponent.
(10 m/s)² = 10 m/s * 10 m/s = 100 m²/s²[tex]KE = \frac{ 1}{2} (60 \ kg)(100 \ m^2/s^2)[/tex]
Multiply the numbers together.
[tex]KE= 30 \ kg * 100 \ m^2/s^2[/tex]
[tex]KE= 3000 \ kg*m^2/s^2[/tex]
Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule, so our answer of 3000 kg*m²/s² equals 3000 Joules.
[tex]KE= 3000 \ J[/tex]
The go-cart has 3000 Joules of kinetic energy.
An open train car rolls along a track while it is being filled with sand. There is negligible friction. As a result of
the accumulating sand, what happens to the speed of the train car? (Assume negligible friction and the cart is
just rolling along, not receiving any additional force to regulate its speed.)
Answer:
Explanation:
that`s a the train car, that you asked the meaning, of that if the train car rolls it`s doing it`s speed, and it`s not ganna fall off the the trail of the train, car.An open train car rolls along a track while it is being filled with sand. There is negligible friction. The speed of the train car will be slowed down.
What is friction?Between two surfaces that are sliding or attempting to slide over one another, there is a force called friction. For instance, friction makes it challenging to push a book down the floor.
Friction always moves an object in a direction that is counter to the direction that it is traveling or attempting to move.
Speed indicates the rate of movement of something or someone. If you know how far something has traveled and how long it took to get there, you can calculate its average speed. Speed is calculated as follows: speed = distance x time.
Therefore, an open railway car is packed with sand and is rolling along a track. Very little friction exists. The railway car's speed will be slowed down.
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4) What is the kinetic energy of o 5 kg object moving at a velocity of 25 m/s?
Ek = 1/2 mv^2
= 1/2 × 5 × (25)^2
= 1562.5 J
how does the age of the universe depend on the hubble constant?
A well chosen lifetime activity is something that should hold a person's interest for a long time.
Please select the best answer from the choices provided.
T
F
Answer:
true
Explanation:
as long as you are interested, you are happy
Since lifetime activities are done for a lifetime, it is true that a well chosen lifetime activity is something that should hold a person's interest for a long time.
What is a lifetime activity?A lifetime activity is an activity which an individual decides to do for a lifetime.
A lifetime activity should be able to hold a person's interest for a long time, else it could lead to frustration.
Some lifetime activities include:
choice of careersmarriage family relationshipsTherefore, it is true that a well chosen lifetime activity is something that should hold a person's interest for a long time.
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in the bohr model, what is the ratio of its kinetic energy to its potential energy?
The centrifugal force C = mv^2/r = kq^2/r^2 = P centripetal force. m is the electron mass, q are the proton and electron charges (opposites), and r is the Bohr radius.
Thus 1/2 mv^2/r = 1/2 kq^2/r^2 and KE = 1/2 mv^2 = 1/2 kq^2/r = 1/2 PE
Therefore KE/PE = 1/2, no matter what state the electron is in.
In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg. After the two balls collide, the final momentum of the cue ball is 0.01 kg. what is the magnitude of the final momentum of the eight ball
This question involves the concepts of the law of conservation of momentum.
The magnitude of the final momentum of the eight ball is "0.22 N.s".
According to the law of conservation of momentum:
[tex]P_{i1}+P_{i2}=P_{f1}+P_{f2}[/tex]
where,
[tex]P_{i1}[/tex] = initial momentum of the cue ball = 0.23 N.s
[tex]P_{i2}[/tex] = initial momentum of the eight ball = 0 N.s (since ball is initially at rest)
[tex]P_{f1}[/tex] = final momentum of the cue ball = 0.01 N.s
[tex]P_{f2}[/tex] = final momentum of the eight ball = ?
Therefore,
[tex]0.23\ N.s + 0\N.s = 0.01\ N.s+P_{f2}\\\\P_{f2} = 0.22\ N.s[/tex]
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