Jefferson Elementary School is sending 8 of its students to a drumming contest in Orlando, Florida. The cost will be $588 per person. How much will it cost for the entire group of 8 students to attend?

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

[tex]33.55 <  \mu < 35.5[/tex]

b

[tex]34.03 <  \mu < 34.969 [/tex]

c

Generally the width at  n =  49 is mathematically represented as

   [tex]w =  2 *  E[/tex]

    [tex]w =  2 *  0.952 [/tex]

     [tex]w =  1.904 [/tex]

Generally the width at  n =  196 is mathematically represented as

   [tex]w =  2 *  E[/tex]

    [tex]w =  2 *  0.4687 [/tex]

     [tex]w =  0.9374  [/tex]

d

The correct option is E

Step-by-step explanation:

From the question we are told  that

   The sample mean is  [tex]\= x  =  34.5[/tex]

    The standard deviation is  [tex]s =  3.4[/tex]

Generally given that the confidence level is 95% then the level of significance is  

       [tex]\alpha = (100 -  95)\%[/tex]

=>     [tex]\alpha = 0.05 [/tex]

Generally from the normal distribution table the critical value  of  [tex]\frac{\alpha }{2}[/tex] is  

   [tex]Z_{\frac{\alpha }{2} } =  1.96[/tex]

Considering question a

From the question  n  =  49

Generally the margin of error is mathematically represented as  

      [tex]E = Z_{\frac{\alpha }{2} } *  \frac{s }{\sqrt{n} }[/tex]

=>   [tex]E = 1.96*  \frac{ 3.4 }{\sqrt{49} }[/tex]

=>   [tex]E =  0.952 [/tex]

Generally 95% confidence interval is mathematically represented as  

      [tex]\= x -E <  p <  \=x  +E[/tex]

      [tex]34.5 -0.952 <  p < 34.5 + 0.952[/tex]

=>    [tex]33.55 <  \mu < 35.5[/tex]

Considering question b

From the question  n  =  196

Generally the margin of error is mathematically represented as  

      [tex]E = Z_{\frac{\alpha }{2} } *  \frac{s }{\sqrt{n} }[/tex]

=>   [tex]E = 1.96*  \frac{ 3.4 }{\sqrt{196} }[/tex]

=>   [tex]E =  0.4687 [/tex]

Generally 95% confidence interval is mathematically represented as  

      [tex]\= x -E <  p <  \=x  +E[/tex]

      [tex]34.5 -0.4687 <  p < 34.5 +0.4687[/tex]

=>   [tex]34.03 <  \mu < 34.969 [/tex]

Considering question c

Generally the width at  n =  49 is mathematically represented as

   [tex]w =  2 *  E[/tex]

    [tex]w =  2 *  0.952 [/tex]

     [tex]w =  1.904 [/tex]

Generally the width at  n =  196 is mathematically represented as

   [tex]w =  2 *  E[/tex]

    [tex]w =  2 *  0.4687 [/tex]

     [tex]w =  0.9374  [/tex]

Now when the sample size is quadrupled i.e from n = 49 to  n =  196  

The width of the  confidence interval  decrease by 2 from 1.904 to  0.9374  

Answer:

d. less costly

Step-by-step explanation:

Statistical significance level is the probability of rejecting the null hypothesis. Statistical significance at the 0.05 level is the standard level for rejecting the null hypothesis.

A significance of 0.01 shows that there is strong evidence to conclude that the null hypothesis is not true. A 0.05 significance is the most used level while 0.01 is used when multiple tests are conducted or when the researcher is not so sure if the null hypothesis should be rejected. It increases the amount of evidence required to prove the null hypothesis and it also reduces the possibility of obtaining a false positive.

Answer:

50 leaves, 15 turkeys

Step-by-step explanation:

set up an equation

l = leaves

t = turkeys

l = 2t+20

l = 4t-10

2t+20=4t-10

30=2t

15=t (so that means that there would be 15 turkey decorations, but we're not            done yet)

substitute (either equation):

l = 2(15)+20

l = 30+20

l = 50 (so this means there would be 50 leaves)

hope this helps!

Answer:

I think its 1430 miles

Step-by-step explanation:

Answer:

173 days

Step-by-step explanation:

The formula for substantial presence test is;

SBT = (Total of number of days present in the current tax year) + (1/3)(number of days in the year that was before the tax year) + (1/6)(number of days in the year that was two years before the tax year)

From the question, present tax year is 2019 and number of days is 96 days.

Year before tax year is 2018 and number of days is 198 days

2 years before tax year is 2017 and number of days is 66 days.

Thus;

SBT = 96 + ((1/3)198) + ((1/6)66)

SBT = 173 days

18 + 7/9

14 + 7/8

First, rewrite each fraction in terms of a common denominator. 8 and 9 don't share a common multiple until 8 * 9 = 72, so we have

7/9 = (7/9) • (8/8) = (7 • 8)/(9 • 8) = 56/72

7/8 = (7/8) • (9/9) = (7 • 9)/(8 • 9) = 63/72

Next, write each whole number in terms of fractions with the same denominator. We have

18 • 72 = 1296  ==>  18 = 1296/72

14 • 72 = 1008  ==>  14 = 1008/72

Write each mixed number as an improper fraction:

18 + 7/9 = 1296/72 + 56/72 = (1296 + 56)/72 = 1352/72

14 + 7/8 = 1008/72 + 63/72 = (1008 + 63)/72 = 1071/72

If the backpack and book together weigh 18 + 7/9 pounds, and the backpack without the book weighs 14 + 7/8 pounds, then the book alone weighs the difference, call it b :

b = (18 + 7/9) - (14 + 7/8)

b = 1352/72 - 1071/72

b = (1352 - 1071)/72

b = 281/72

Convert this to a mixed number. 72 • 4 = 288, so 72 • 4 - 7 = 281:

b = (72 • 4 - 7)/72

b = (72 • 4)/72 - 7/72

b = 4 - 7/72

b = (3 + 1) - 7/72

b = 3 + (1 - 7/72)

b = 3 + 65/72

Answer:

the stretch or compression of a quadratic, and if it's opening up to down.

Step-by-step explanation:

Answer:

B. 63.4 yards.

Step-by-step explanation:

Answer:

the answer should be B:12/5

Answer:

See the graph

Step-by-step explanation:

Graph the line using the slope and y-intercept, or two points.

Slope:  − 1

x-intercept: (-5,0)

y-intercept:  ( 0 , − 5 )

Answer:

Step-by-step explanation:

A larger set that a particular set can be a subset of is a Universal set. A universal set is parent where all other sets are derived from.

For example, given a universal set U = {1,2,3,4,5}, a set A = {1, 3, 5} is said to be a subset of the set U because the elements of set B are contained in the Universal set U.

Also, sets like {1, 4,5} and {3,4,5} can also be regarded as the subset of U since all the elements of the sets can be found in the Universal set U. Hence the correct name of the set is a UNIVERSAL SET

So, the number of maximum subsets we can create from the given set is 8.

The subsets of any set consists of all possible sets including its elements and the null set. Let us understand with the help of an example.

Example: Find all the subsets of set A = {1,2,3,4}

Solution: Given, A = {1,2,3,4}

Subsets =

The subsets of any set consisting of all possible sets including its elements and the null set. Let us understand with the help of an example.

Example: Find all the subsets of set A = {1,2,3,4}

{}

{1}, {2}, {3}, {4},

{1,2}, {1,3}, {1,4}, {2,3},{2,4}, {3,4},

{1,2,3}, {2,3,4}, {1,3,4}, {1,2,4}

{1,2,3,4}

So, the formula is [tex]2^n[/tex].

The given set is,

[tex]A = \{1, 3, 5\}[/tex]

Here the number of an element is 3.

So, the maximum number of subsets we can create is,

[tex]2^n=2^3=8[/tex]

Learn more about the topic Subsets:

https://brainly.com/question/17514113

Answer:

-1.4

Step-by-step explanation:

opposite of -1.4 = 1.4

opposite of the opposite of -1.4 = the opposite of 1.4 = -1.4

Answer:

97

Step-by-step explanation:

Given that:

Low = 43bpm

High = 115 bpm

Error = 3

α = 90%

To find the range estimate :

Standard destviation = (high - low) / 4

Standard deviation = (115 - 43) / 4

Standard deviation = 72/4 = 18

The sample size,(n) :

n = [(Zα/2 * sd)/E] ²

2 - tail = (Zα/2) = 1.645

[(Zα/2 * sd)/E] ² = [(1.645 * 18) / 3]² = (29.61/3)²

= 97.41

Sample size = 97

Answer:

157

Step-by-step explanation:

Answer:    15 tens and 7 ones in standard form would be 157. If you have 15 tens this means that you are adding 10, 15 times or multiplying 10 by 15, which gives you 150.

Step-by-step explanation: Hopefully this helped!

Answer:0.6666664

Step-by-step explanation:

You take 5 and divide by 60. Then multiply by 8.

2/3 of a mile.

If he can walk 5 MILES a hour, lets use 5/60.

Multiply 5/60 by 8 since each minute he travels 5/60 of a MILE.

You get 0.66(repeating) OR 2/3

Answer:

+12 degrees

Step-by-step explanation:

You never showed a picture, but im pretty sure this is correct

I hope this helped, please mark Brainliest, thank you!

Answer:

a

Step-by-step explanation:

because there are over half girls and half of 120 is 60 and 75 is over half

Answer:

1 a  [tex]p -value = 0.030054[/tex]

1b   [tex]p -value = 0.0029798[/tex]

1c  [tex]p -value = 0.0039768[/tex]  

2a  [tex]p-value = 0.00099966[/tex]

2b  [tex]p-value = 0.00999706[/tex]

2c  [tex]p-value = 0.0654412[/tex]

Step-by-step explanation:

Considering question a

  The alternative hypothesis is H1:μ>μ0

   The test statistics is  z =1.88

Generally from the z-table  the  probability of   z =1.88 for a right tailed test is

    [tex]p -value = P(Z > 1.88) = 0.030054[/tex]

Considering question b

  The alternative hypothesis is H1:μ<μ0

   The test statistics is  z=−2.75

Generally from the z-table  the  probability of   z=−2.75 for a left tailed test is

    [tex]p -value = P(Z < -2.75) = 0.0029798[/tex]

Considering question c

  The alternative hypothesis is H1:μ≠μ0

   The test statistics is  z=2.88

Generally from the z-table  the  probability of  z=2.88 for a right  tailed test is

    [tex]p -value = P(Z >2.88) = 0.0019884[/tex]    

Generally the p-value for the two-tailed test is

    [tex]p -value = 2 * P(Z >2.88) = 2 * 0.0019884[/tex]    

=> [tex]p -value = 0.0039768[/tex]  

Considering question 2a

    The alternative hypothesis is H1:μ>μ0

     The sample size is  n=16

     The  test statistic is  t =  3.733

Generally the degree of freedom is mathematically represented as

        [tex]df = n - 1[/tex]

=>     [tex]df = 16 - 1[/tex]

=>     [tex]df = 15[/tex]

Generally from the t distribution table  the probability of   t =  3.733 at a degree of freedom of  [tex]df = 15[/tex] for a right tailed test is  

       [tex]p-value = t_{3.733 , 15} = 0.00099966[/tex]

Considering question 2b

    The alternative hypothesis is H1:μ<μ0

     The degree of freedom is df=23

     The  test statistic is ,t= −2.500

Generally from the t distribution table  the probability of   t= −2.500 at a degree of freedom of  df=23 for a left  tailed test is  

       [tex]p-value = t_{-2.500 , 23} = 0.00999706[/tex]

Considering question 2c

    The alternative hypothesis is H1:μ≠μ0

     The sample size is  n= 7

     The  test statistic is ,t= −2.2500

Generally the degree of freedom is mathematically represented as

        [tex]df = n - 1[/tex]

=>     [tex]df = 7 - 1[/tex]

=>     [tex]df = 6[/tex]

Generally from the t distribution table  the probability of   t= −2.2500 at a degree of freedom of  [tex]df = 6[/tex] for a left   tailed test is  

       [tex]t_{-2.2500 , 6} = 0.03272060[/tex]

Generally the p-value  for t= −2.2500 for a two tailed test is

     [tex]p-value = 2 * 0.03272060 = 0.0654412[/tex]

- 3 x₂ + 7 x₃ = 3

x₁ + 2 x₂ - x₃ = 0

5 x₁ - 2 x₂ = 3

(a) I suppose this is asking for the determinant of the coefficient matrix.

[tex]\begin{vmatrix}0&-3&7\\1&2&-1\\5&-2&0\end{vmatrix}[/tex]

Using a cofactor expansion along the first row, this reduces to

[tex]0\begin{vmatrix}2&-1\\-2&0\end{vmatrix}-(-3)\begin{vmatrix}1&-1\\5&0\end{vmatrix}+7\begin{vmatrix}1&2\\5&-2\end{vmatrix}= 3(0 - (-5))+7(-2-10)=\boxed{-69}[/tex]

(b) Using Cramer's rule, we have

[tex]x_1=\dfrac{\begin{vmatrix}\mathbf 3&-3&7\\\mathbf 0&2&-1\\\mathbf 3&-2&0\end{vmatrix}}{\begin{vmatrix}0&-3&7\\1&2&-1\\5&-2&0\end{vmatrix}}[/tex]

[tex]x_2=\dfrac{\begin{vmatrix}0&\mathbf 3&7\\1&\mathbf 0&-1\\5&\mathbf 3&0\end{vmatrix}}{\begin{vmatrix}0&-3&7\\1&2&-1\\5&-2&0\end{vmatrix}}[/tex]

[tex]x_3=\dfrac{\begin{vmatrix}0&-3&\mathbf 3\\1&2&\mathbf 0\\5&-2&\mathbf 3\end{vmatrix}}{\begin{vmatrix}0&-3&7\\1&2&-1\\5&-2&0\end{vmatrix}}[/tex]

That is, solving for n-th variable consists of dividing [the determinant of the coefficient matrix with its n-th column replaced with the right side of the system, the numbers in boldface,] by [the determinant of the coefficient matrix].

Compute each determinant:

[tex]\begin{vmatrix}\mathbf 3&-3&7\\\mathbf 0&2&-1\\\mathbf 3&-2&0\end{vmatrix}=3\begin{vmatrix}2&-1\\-2&0\end{vmatrix}+3\begin{vmatrix}-3&7\\2&-1\end{vmatrix}=3(0-2)+3(3-14)=-39[/tex]

(expanding along the first column)

[tex]\begin{vmatrix}0&\mathbf 3&7\\1&\mathbf 0&-1\\5&\mathbf 3&0\end{vmatrix}=-1\begin{vmatrix}3&7\\3&0\end{vmatrix}+5\begin{vmatrix}3&7\\0&-1\end{vmatrix}=-1(0-21)+5(-3-0)=6[/tex]

(again, along the first column)

[tex]\begin{vmatrix}0&-3&\mathbf 3\\1&2&\mathbf 0\\5&-2&\mathbf 3\end{vmatrix}=-1\begin{vmatrix}-3&3\\-2&3\end{vmatrix}+5\begin{vmatrix}-3&3\\2&0\end{vmatrix}=-1(-9-(-6))+5(0-6)=-27[/tex]

(first column)

So, we get the solution

[tex]x_1=\dfrac{-39}{-69}=\boxed{\dfrac{13}{23}},x_2=\dfrac6{-69}=\boxed{-\dfrac2{23}},x_3=\dfrac{-27}{-69}=\boxed{\dfrac9{23}}[/tex]

(c) Using elimination:

- 3 x₂ + 7 x₃ = 3

x₁ + 2 x₂ - x₃ = 0

5 x₁ - 2 x₂ = 3

Swap the first two equations:

x₁ + 2 x₂ - x₃ = 0

- 3 x₂ + 7 x₃ = 3

5 x₁ - 2 x₂ = 3

Add -5(equation 1) to equation 3:

x₁ + 2 x₂ - x₃ = 0

- 3 x₂ + 7 x₃ = 3

- 12 x₂ + 5 x₃ = 3

Add -4(equation 2) to equation 3:

x₁ + 2 x₂ - x₃ = 0

- 3 x₂ + 7 x₃ = 3

- 23 x₃ = -9

Multiply through equation 3 by -1/23:

x₁ + 2 x₂ - x₃ = 0

- 3 x₂ + 7 x₃ = 3

x₃ = 9/23

Add -7(equation 3) to equation 2:

x₁ + 2 x₂ - x₃ = 0

- 3 x₂ = 6/23

x₃ = 9/23

Multiply through equation 2 by -1/3:

x₁ + 2 x₂ - x₃ = 0

x₂ = -2/23

x₃ = 9/23

Add -2(equation 2) and equation 3 to equation 1:

x₁ = 13/23

x₂ = -2/23

x₃ = 9/23

Answer:

D) x=√10

Step-by-step explanation:

√(10)=3.16(approximately )

Answer:

Simple to help us improve our lives

Answer:

To do good in school

Step-by-step explanation:

the thing is teachers want us to study so we remember whatever is on the test for an example and that is good but not alt of people always study.

Answer: x=-19

Step-by-step explanation:

Answer:

The probability is [tex]P(X  \le 2 ) = 0.9072[/tex]

The company will accept 90.72% of the shipment and will reject [tex](100 -90.72) =  9.2\%[/tex] of the shipment , so many of the shipment are rejected

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  36

   The  proportion that did not meet the requirement is  [tex]p =  0.03[/tex]

Generally the probability that the whole shipment is accepted is equivalent to the probability that there is at most 2 batteries that do not meet the requirement , this is mathematically represented as

     [tex]P(X  \le 2 ) = [ P(X =  0 ) +  P(X =  1 ) + P(X = 0)][/tex]

=>   [tex]P(X  \le 2 ) = [ [^{n}C_0 * (p)^{0} *(1-p)^{n-0} ] +  [^{n}C_1 * (p)^{1} *(1-p)^{n-1} ] +  [^{n}C_2 * (p)^{2} *(1-p)^{n-2} ]][/tex]

Here C stands for Combination (so we will be making the combination function in our  calculators )

So

=> [tex]P(X  \le 2 ) = [ [^{36}C_0 * (0.03)^{0} *(1-0.03)^{36-0} ] +  [^{36}C_1 * (0.03)^{1} *(1-0.03)^{36-1} ] +  [^{36}C_2 * (0.03)^{2} *(1-0.03)^{36-2} ]][/tex]

=> [tex]P(X  \le 2 ) = [ [1 * 1 * 0.3340  ] +  [36* 0.03 *0.3444 ] +  [630 * 0.0009 *(0.355 ]][/tex]

=>[tex]P(X  \le 2 ) = 0.9072[/tex]

The company will accept 90.72% of the shipment and will reject [tex](100 -90.72) =  9.2\%[/tex] of the shipment , so many of the shipment are rejected

Answer:

a=16

Step-by-step explanation:

Answer:

A=4

Step-by-step explanation:

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

[tex]A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years[/tex]

First, let us calculate the decay constant (k)

[tex]75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036[/tex]

Next, let us calculate the half-life as follows:

[tex]\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years[/tex]

Therefore the half-life is between 600 and 700 years

Answer:

Second quadrant

Step-by-step explanation:

[tex] \because \: \frac{ \pi}{2} < \theta < \pi \: bounds \: second \: quadrant \\ \\ \therefore \: \sin \theta = \frac{4}{5 } \: lies \: in \: second \: quadrant.[/tex]