Jim's displacement if Jim leaves his house and begins walking to his car in a straight line and he goes 2.0 m then returns to his house to get his keys, next, he leaves his house and travels 6.0 m to his car is 6 m
Δx = x2 - x1
Δx = Displacement
x2 = Final position
x1 = Initial position
Considering the house as origin,
Final position = 6 m
Initial position = 0
Δx = 6 - 0
Δx = 6 m
Displacement is the vector quantity that describes position change in a motion. Its scalar quantity distance describes the overall distance travelled during the entire motion.
Therefore, Jim's displacement is 6 m
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Two litres of water, initially at 20 °C, is heated to 40 °C. Determine thevolume of water at 40 °C if the coefficient of volumetric expansion ofwater within this range is 30 x 10-9 °C.
Given data
*The given initial volume of water is V_1 = 2 L
*The given initial temperature of the water is T_i = 20 °C
*The given final temperature of the water is T_f = 40 °C
*The coefficient of volumetric expansion of water is
[tex]\alpha=30\times10^{-9}^{}\text{C}[/tex]The formula for the volumetric expansion is given as
[tex]\frac{\Delta V}{V}=\alpha(T_f-T_i)[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} \frac{\Delta V}{V_1}=30\times10^{-9}\times(40^0-20^0) \\ V_2-V_1=6\times10^{-7}V_1 \\ V_2=6\times10^{-7}V_1+V_1^{} \\ =V_1(6\times10^{-7}+1) \\ =2.00\text{ L} \end{gathered}[/tex]in february 1955, a paratrooper fell 370 m from an air- plane without being able to open his chute but happened to land in snow, suffering only minor injuries. assume that his speed at im- pact was 56 m/s (terminal speed), that his mass (including gear) was 85 kg, and that the magnitude of the force on him from the www.engineeringbookspdf problems 249 12.0 m/s and angle u1 35.0. just after, it is traveling directly upward with velocity of magnitude 10.0 m/s. the duration of the collision is 2.00 ms. what are the (a) magni- v : 2 snow was at the survivable limit of 1.2 105 n. what are (a) the minimum depth of snow that would have stopped him safely and (b) the magnitude of the impulse on him from the snow?
(a)1.1 m is the minimum depth of snow that would have stopped him safely. (b)The magnitude of the impulse on him from the snow[tex]|\Delta \overrightarrow{\mathrm{p}}|[/tex] -4.8 * 10³ kg. m/s.
What is magnitude ?A key concept in science is magnitude, which is employed in physics. Magnitude describes a general amount or a distance. We can relate magnitude to size and speed of the object is motion while considering the aspects of movement. The magnitude of the an object is defined by it's own size or quantity.
Briefing:We choose +y upward, which implies a>0 (the acceleration is upward since it represents a deceleration of his downward motion through the snow).
a) The maximum deceleration a[tex]_m_a_x[/tex] of the paratrooper (of mass m and initial speed ν=56m/s ) is found from Newton’s second law
F[tex]_s_n_o_w[/tex]−mg=ma[tex]_m_a_x[/tex]
where we require F[tex]_s_n_o_w[/tex] =1.2×10⁵N . Using Eq. 2 −15ν² =2a max d , we find the minimum depth of snow for the man to survive :
[tex]\mathrm{d}=\frac{v^2}{2 \mathrm{a}_{\text {max }}}=\frac{\mathrm{m} v^2}{2\left(\mathrm{~F}_{\text {snow }}-\mathrm{mg}\right)} \approx \frac{(85 \mathrm{~kg})(56 \mathrm{~m} / \mathrm{s})^2}{2\left(1.2 \times 10^5 \mathrm{~N}\right)}=[/tex]1.1 m.
(a) He experiences a change in momentum during his brief journey through the snow.
[tex]\Delta \overrightarrow{\mathrm{p}}=\overrightarrow{\mathrm{p}}_{\mathrm{f}}-\overrightarrow{\mathrm{p}}_{\mathrm{i}}[/tex] = 0 - (85 kg)(-56m/s)= -4.8 * 10³ kg. m/s.
or[tex]|\Delta \overrightarrow{\mathrm{p}}|[/tex] = -4.8 * 10³ kg. m/s.
Because downward is the negative direction, the starting velocity has a negative value. This equals the impulse caused by the net force F[tex]_s_n_o_w[/tex]−mg according to the impulse-momentum theorem, but since F[tex]_s_n_o_w[/tex] ≫mg we can approximate this as the impulse on him just from the snow.
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The complete question is -
In February 1955, a paratrooper fell 370m from an airplane without being able to open his chute but happened to land in snow, suffering only minor injuries. Assume that his speed at impact was 56m/s (terminal speed), that his mass (including gear) was 85kg, and that the magnitude of the force on him from the snow was at the survivable limit of 1.2×10⁵ N. What are (a) the minimum depth of snow that would have stopped him safely and (b) the magnitude of the impulse on him from the snow?
What is the acceleration of a car that goes from
rest to 25 m/s in 5.0 s?
Answer:
5 m/s^2
Explanation:
Acceleration is change in velocity / change in time
Accel = 25 m/s / 5 s = 5 m/s^2
You are driving at the speed of 29.5 m/s
(66.0037 mph) when suddenly the car in
front of you (previously traveling at the same
speed) brakes and begins to slow down with
the largest deceleration possible without skidding. Considering an average human reaction,
you press your brakes 0.558 s later. You also
brake and decelerate as rapidly as possible
without skidding. Assume that the coefficient
of static friction is 0.708 between both cars’
wheels and the road.
The acceleration of gravity is 9.8 m/s
2
.
Calculate the acceleration of the car in front
of you when it brakes.
Answer in units of m/s
2
.
The acceleration of the car in front before stopping is 6.94 m/s².
What is the acceleration of the car?The acceleration of the car is the rate of change of velocity of the car with time.
The acceleration of the car in front is determined by applying the Newton's second law of motion assuming the car decelerated at a constant rate before stopping.
Ff = F
μmg = ma
μg = a
where;
Ff is the frictional force on the car when it stopsF is the force of the carm is the mass of the cara is the acceleration of the carg is acceleration due to gravityμ is coefficient of static frictionSubstitute the given parameters and solve for the acceleration of the car.
a = (0.708) x (9.8 m/s²)
a = 6.94 m/s²
Thus, the acceleration of the car in front before stopping is 6.94 m/s².
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Johnny rides his bike South from home to school which is 5 km away. It takes him 30 minutes to arrive at school. What is Johnny's velocity in km/hr?
The velocity of Johnny is 10km/hr
The rate at which an object's position changes in relation to a frame of reference and time is the term meant by velocity. Although it may appear sophisticated, velocity is just the act of moving quickly in one direction. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction. Its SI equivalent is (ms-1). A body is considered to be accelerating if the magnitude or direction of its velocity changes.
We are given that,
The distance of the school = d = 5km
The time taken to reach school = t = 30min = 0.5hr
Velocity of Johnny = V = ?
V = d/t
V = (5km)/ (0.5hr)
V = 10km/hr
Therefore , the velocity would be 10km/hr
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the floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.36 with the floor. if the train is initially moving at a speed of 45 km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor?
24.8 m is the shortest braking distance.
On the horizontal axis, we dread the force of friction (fr) that prevents the train from moving and accelerating.
Y axis
N- W = 0
N = W = mg
explanation?
In order to fix this issue, we must apply Newton's second law to the boxes, with the norm vertically up and the weight vertically down.
Write the equation for each axis. On the horizontal axis, we dread the force of friction (fr) that prevents the train from moving and accelerating.
Y axis
N- W = 0
N = W = mg
X axis
-Fr = m a
-μ N = m a
-μ mg = ma
a = μ g
a = - 0.36
a = - 3.14 m/s²
Utilizing the kinematics equations, we determine the distance.
(Vf2 - Vo2) / 2 a = Vf2 = Vo2 + 2 an
The speed of the train is zero (Vf = 0) when it stops.
Vo=45 km/h (1000 m/km) (1 h 3600 s)= 12.5m/s
x = ( 0 - 12.5²) / 2 (-3.14)
x= 24.88.8 m
The shortest braking distance is 24.8 m
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a 0.500 kg basketball is dropped out of a window that is 6.90 m above the ground. the ball is caught by a person whose hands are 1.62m above the ground. how much work is done on the ball by its weight
Work done on the ball by its weight is +25.872 J .
What is work done by gravity ?
Gravity is that force which pulls objects to the ground. There is a force that acts, so basically gravity acts. When you apply a power to an item, that power works for you. For example, if you throw a ball, the force on the ball will cause it to travel far and complete the task. Work is proportional to the applied force and the distance it covers or covers. For example, if you throw a ball with less force, the distance it travels will decrease proportionally to the force applied. Throwing the ball with more force increases the flight distance. Falling particles are forced to face the direction of gravity. The mass, the gravitational constant, and the height at which the falling object falls determine how large the falling object will be.
Work done by gravity is :
W= mg(h2-h1)
= (0.500)(9.80)(6.90-1.62)
= +25.872 J .
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can somebody help me with this?
Answer: (D) thrust has overcome the drag force
Explanation: In order for the plane to move forward, the backward force will have to be overcome. As thrust is a force in the opposite direction of drag so it can cancel out the backward pull of drag and move forward.
Kinetic theory told us that gas particles are moving constantly and bumping into anything in their path. The collisions of these particles in the gas result in ___________ .
a
Energy conversion
b
Pressure
c
Creation of new forms of matter
d
Potential energy
Answer:
a
Explanation:
because if gas particles move they move with speed and that is because they are free,so when they bump into something,they bump into it with force so it converts the energy
What human activities increase the levels of greenhouse gases released?
Answer: There are many human activities that have negative effects on the environment such as the release of greenhouse gas. Some include; transporting, industry and factories, burning of fossil fuels, agriculture, deforestation, and the release of chemicals into the atomsphere.
Explanation:
Transporting and factories emit gasses such as carbon dioxide, which is toxic and can affect the environment. The burning of fossil fuels also releases carbon dioxide into the air, leading to the massive spread of global warming. Deforestation can lead to less oxygen and more carbon dioxide in the air, and can also cause global warming. Animals can also lose their habitats.
Answer:
humans burn fossil fuels to generate electricity, to keep buildings warm, power cars etc. As a result, waste gases are being produced such as carbon dioxide
Human Activities:
- driving cars, carbon dioxide is released
-burning things e.g wood
-small loads of laundry, wasting
-heating
If centripetal force is towards the center and gravitational force is also towards the center how can we be lighter at the equator?
ANSWER and EXPLANATION
We want to determine why a person weighs lighter at the equator.
At the equator, an object will weigh slightly less as a result of the slightly greater centripetal force and the slight increase in distance from the center of gravity of the earth due to the equatorial bulge. This would imply a decrease in the gravitational force that an object experiences.
In other words, the earth is not a perfect sphere, and so, at the equator, an object will be slightly farther from the center.
That is the answer.
Pls help me
I’m stuck I tried searching the internet but it didn’t work
According to the given statement A toy car that initially increases its speed, travels constant speed, and then decreases its speed.
The correct option is B.
Describe speed using an example:Speed, expressed in terms of meters per second, is the rate at which an object's location changes. An item moves one meter in one second, for instance, if it starts at the origin and moves three meters in three seconds. Simple division of time by distance yields the equation for speed.
What is a speed measurement tool?Speedometers are tools that show a car's speed and are frequently paired with odometers, which keep track of the distance driven.
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The complete question is-
A student performs an experiment in which the horizontal position of a toy car is recorded on ticker tape from a device that places dots on the tape in equal time intervals. The series of dots in the figure represents the motion of an object moving from the negative direction to the positive direction along the horizontal direction. The time interval between each recorded dot is 1s. Which of the following experiments could the student have conducted to create the data shown on the ticker tape?
A toy car that initially increases its speed, travels at a constant speed, and then increases its speed again.
B-A toy car that initially increases its speed, travels at a constant speed, and then decreases its speed.
C-A toy car that initially decreases its speed, and then increases its speed.
D-A toy car that initially decreases its speed, travels at a constant speed, and then increases its speed.
a wheel has a constant angular acceleration of 4 rad/s2. starting from rest, it turns through 300 rad. what is its final angular velocity? how much time elapses while it turns through the 300 radians?
If a wheel has a constant angular acceleration of 4 rad/s2. starting from rest, it turns through 300 rad , then the final angular velocity would be 48.96 rad /s and 12.24 seconds elapse while it turns through the 300 radians.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
By using the second equation of motion given by Newton,
S = ut + 1/2at²
300 = 0 + 0.5 × 4 × t²
t² =300 /2
t = 12.24 seconds
The final angular velocity = 0+ 12.24 × 4
= 48.96 rad /s
Thus, 12.24 seconds elapse while it turns through the 300 radians.
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an electron accelerated from rest through a voltage of 790 v enters a region of constant magnetic field. part a if the electron follows a circular path with a radius of 21 cm , what is the magnitude of the magnetic field? express your answer using two significant figures. b
The electron is accelerated through a potential difference of , so the kinetic energy gained by the electron is equal to its variation of electrical potential energy:
1/2mv²=eΔV
where
m is the electron mass
v is the final speed of the electron
e is the electron charge
is the potential difference
Re-arranging this equation, we can find the speed of the electron before entering the magnetic field:
v=√2eΔv/m=√2(1.6-10-19c)(790v)/9.1-10-31=1.66.10 m/s
Now the electron enters the magnetic field. The Lorentz force provides the centripetal force that keeps the electron in circular orbit:
evb=mv²/r
where B is the intensity of the magnetic field and r is the orbital radius. Since the radius is r=25 cm=0.25 m, we can re-arrange this equation to find B:
b=m/er =3.8.10 t
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a car's bumper is designed to withstand a 5.40 km/h (1.5-m/s) collision with an immovable object without damage to the body of the car. the bumper cushions the shock by absorbing the force over a distance. calculate the magnitude of the average force on a bumper that collapses 0.225 m while bringing a 890 kg car to rest from an initial speed of 1.5 m/s.
The average force is F = 2722.5N
This law of interaction states that when one body exerts a force on a second body, the second body exerts an equal and opposite force on the first body. This is the law of action and reaction, which helps explain why you feel the impact when you collide with another bumper car.
When the car hits something at low speed, the foam and fenders absorb the energy, pushing the bumper back and using the crumple zone to cushion the impact. Shattering the bumpers, fenders, and foam limits the damage you can do to the cars and the people inside them. means equal to the sum.
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Calculator A dog has a kinetic energy of 111J and is running at a speed of 10m/s. What is the mass of the dog? Give your answer to 2 decimal places.
Explanation:
MASS=2.22
VELOCITY=10m/s
KINETIC ENERGY=111
PLEASE MARK ME AS BRILLIANT
Look at the diagram. Calculate the Rf value for sample 7. Give your answer to two decimal places.
The Rf value of sample 7 is 0.94.
What are Rf values?Rf (retention factor) values are values that are used to identify compounds in thin-layer chromatography.
Rf values are obtained by taking the ratio of the distance traveled by the solvent (solvent front) and that traveled by the substance or unknown compound.
Rf = distance traveled by compound / distance traveled by the solventThe Rf value of sample 7 is calculated below:
distance traveled by compound = 33 mm
distance traveled by the solvent = 35 mm
Rf value = 33 mm/ 35 mm
Rf value = 0.94
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what is the conversion efficiency (power coefficient) from power in the wind to electrical power output for a modern highly engineered horizontal axis high-tip-speed two blade wind turbine? group of answer choices
The conversion efficiency from the power in the wind to electrical power output for a modern highly engineered two blade wind turbine is 35 % to 45%.
What is power coefficient and how the conversion efficiency from power in wind to turbine is so?Power coefficient is similarity in relation to power just combining the flow coefficient and head coefficient.Power coefficient is denoted by Cp and whose equation is like Cp= f( Vwind) where V is the velocity of the wind.Here in the question is asked the conversion efficiency from power in wind to the power in wind turbine.So the conversion efficiency from the power in the wind to the electrical power output for a modern highly engineered two blade wind turbine is 35% to 45%.To know more about power coefficient visit:
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A radio announcer's voice is transmitted via radio waves a distance of 469.06 km. How much time, in microseconds, will it take to transmit the wave over this distance?
Assuming the wave is being transmitted on the vacuum, we know that the velocity of an electromagnetic wave on vacuum is c. We can use the following relation:
[tex]v=\frac{\lambda}{T}\Rightarrow T=\frac{\lambda}{c}=\frac{469.06*10^3}{3*10^8}=1.5635ms=1563.5\mu s[/tex]Thus, our final answer is T=1563.5us
line spectra from all regions of the electromagnetic spectrum, including the paschen series of infrared lines for hydrogen, are used by astronomers to identify elements present in the atmospheres of stars. calculate the wavelength of the photon emitted whe
The wavelength of the photon emitted when the hydrogen atom undergoes a transition from n = 5 to n = 3 is 1282 nm.
From the Rydberg's formula;
1/λ = R (1/[tex]n^{2} _{final}[/tex] - 1/[tex]n^{2} _{initial}[/tex])
R = 1.097 ×[tex]10^{7} m^{-1}[/tex]
nfinal = 3
ninitial = 5
Calculating the wavelength of the photon by substituting values, in equation 1/λ = R (1/[tex]n^{2} _{final}[/tex] - 1/[tex]n^{2} _{initial}[/tex]) , we get:
1/λ = 1.096776×[tex]10^{7} m^{-1}[/tex] (1/[tex]3^{2}[/tex] - 1/[tex]5^{2}[/tex])
1/λ = 1.096776×[tex]10^{7} m^{-1}[/tex] (1/9 - 1/25)
λ = 1.282 × [tex]10^{-6}[/tex] m
λ = 1282 nm
Therefore, the wavelength of the photon emitted when the hydrogen atom undergoes a transition from n = 5 to n = 3 is 1282 nm.
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An apple is resting on a table. Claire says that there are no forces acting on the apple because it is not moving. Is she right?
Answer:
no
Explanation:
there are forces , even when the apple isnt moving , for example gravity which is keeping the apple on the table
when the pendulum bob is at its maximum height (farthest from the center of the earth), is the gravitational potential energy of the bob-earth system at a maximum, minimum or some value in between? briefly explain.
Both gravitational potential energy (PE) and kinetic energy (KE) are present on a swinging pendulum bob. The KE is at its highest and the PE is zero when the bob is in its lowest position. The KE is zero and the PE is at its highest value when the bob is in its highest position on both sides.
When does the pendulum's speed reach its highest point?The pendulum moves at its fastest while it is passing through the middle position. We could interpret this in terms of energy conservation. Bob is at his shortest height when he is in the average position. When Bob is positioned at an extreme, such as the right, it is slightly higher than when it is in the middle.
What happens to a pendulum's length when it is full?The bob's center of mass serves as the standard for determining the pendulum's "length." The center of gravity of the bob would fluctuate in a convoluted manner as the mercury drained out of a simple spherical bob with a small hole in the bottom. The center of gravity would be in the middle of the bob when it is totally full.
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It takes 10 seconds to accelerate from rest to rate of 8 m/s. If the mass of the car is 1,200kg. Calculate the net force acting on the car .
Answer:
960 N
Explanation:
Find acceleration
Change in velocity / change in time
8 /10 = .8 m/s^2
Then F = ma
= 1200 kg * .8 m/s^2 = 960 N
Ethan slid a glass of OJ for peter across a counter with a speed of 2.1 m/s unfortunately peter missed it if the countertop was 1.1m above the floor how long did it take for the glass to hit the ground
Answer:
It takes 0.47 seconds for the OJ to reach the ground.
Explanation:
d = vi*t + (1/2)at^2
(-1.1) = (0)t + (1/2)(-9.8)t^2
-1.1 = -4.9t^2
0.22445 = t^2
0.47s = t
Kinetic theory told us that gas particles are moving constantly and bumping into anything in their path. The collisions of these particles in the gas result in ___________ .
a
Energy conversion
b
Pressure
c
Creation of new forms of matter
d
Potential energy
According to the research, the correct option is d. Kinetic theory told us that gas particles are constantly moving and bumping into anything in their path. The collisions of these particles in the gas result in Potential energy.
What is Kinetic theory?It is the model of matter that, starting from the definition of an ideal gas from the point of view, explains the behavior of matter at the molecular level when it is subject to certain conditions.
In this sense, it studies the behavior of molecules and their interactions, where the energy that is capable of being developed during the collision of small particles is first converted into potential energy associated with the position of a body.
Therefore, we can conclude that the kinetic theory explains the interactions that occur in gas particles, where kinetic and potential energy can influence their state.
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jumping up before the elevator hits. after the cable snaps and the safety system fails, an elevator cab free-falls from a height of 36 m. during the collision at the bottom of the elevator shaft, a 90 kg passenger is stopped in 5.0 ms. (assume that neither the passenger nor the cab rebounds.) what are the magnitudes of the (a) impulse and (b) average force on the passenger during the collision? if the passenger were to jump upward with a speed of 7.0 m/s relative to the cab floor just before the cab hits the bottom of the shaft,
a) The magnitude of the impulse is 2.39 × [tex]10^{3}[/tex] N. b) Average force on the passenger during the collision is 4.78 × [tex]10^{5}[/tex] N. c) impulse is 1.6 × [tex]10^{3}[/tex] N.s d) The corresponding average force would be 3.52 × [tex]10^{5}[/tex] N.
a) By energy conservation, the speed of the passenger when the elevator hits the floor is
1/2 mv² = mgh
v = √2gh = [tex]\sqrt{2(9.8)(36)}[/tex]
= 26.6 m/s
The magnitude of the impulse is
J = |Δp| = m|Δv| = mv = (90kg) (26.6m/s) ≈ 2.39 × 10³ N.s
b) With duration of Δt = 5.0 × [tex]10^{-3}[/tex] s for the collision, the average force is
[tex]F_{avg}[/tex] = J/ Δt = 2.39×10³ N.s / 5.0 × [tex]10^{-3}[/tex] s
≈ 4.78 × [tex]10^{5}[/tex] N
c) If the passenger were to jump upward with a speed of [tex]v^{'}[/tex]= 7.0 m/s, then the resulting downward velocity would be
[tex]v^{n}[/tex] = v- [tex]v^{'}[/tex]
= 26.6m/s - 7.0 m/s
= 19.6 m/s
The magnitude of the impulse becomes
[tex]J^{n}[/tex] = |Δ[tex]p^{n}[/tex]| = m|Δ[tex]v^{n}[/tex]| = m[tex]v^{n}[/tex] = (90kg) (19.6 m/s)
≈ 1.76 × 10³³N.s
d) The corresponding average force which is
[tex]F_{avg } ^{n}[/tex] = [tex]J^{n}[/tex]/ Δt = 1.76 × 10³ N.s/ 5.0 × [tex]10^{-3}[/tex] s
≈ 3.52 × [tex]10^{5}[/tex]N
Therefore the magnitude of the impulse is 26.6 m/s, average force on the passenger during the collision is 4.78 × [tex]10^{5}[/tex]N, the magnitude of the impulse is 1.76×[tex]10^{3}[/tex]N.s, average force is 3.52 × [tex]10^{5}[/tex].
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A 14 kg boulder is pushed off a cliff with velocity v = ( 14.0 m/s ) + ( 2.0m/s ) y . Will the object experience a larger vertical or horizontal acceleration?
The object will eventually experience a large vertical acceleration since the vertical velocity increases as the object moves downwards.
What is horizontal motion of a projectile?The horizontal motion of a projectile is the motion of the projectile along a horizontal path.
The horizontal distance of a projectile is not affected by gravity and hence the horizontal speed of a projectile remains constant. That is the initial horizontal velocity is equal to the final horizontal velocity of the projectile.
However, the during the vertical motion an object, the vertical velocity decreases as the object moves upwards and eventual becomes zero when the object reaches the maximum height.
As the object begins to move downwards the vertical velocity increase and eventually become maximum before the object hits the ground.
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There is a ball of fresh fruit at the top of a small cliff that is 45 m high. The fresh fruit baskets mass is 10kg's. Identify the energy (PE or KE) and calculate the it.
Given,
The mass of the fruit basket, m=10 kg
The height of the cliff, h=45 m
Kinetic energy is the energy possessed by an object due to its motion. Kinetic energy is directly proportional to the square of the velocity of the object.
Potential energy is the energy possessed by an object due to its position. The gravitational potential energy is directly proportional to the height at which the object is situated.
As the basket is at rest, its velocity is zero and hence it does not have kinetic energy.
Thus the energy possessed by the fruit basket is the potential energy.
The potential energy is given by,
[tex]E_P=\text{mgh}[/tex]Where g is the acceleration due to gravity.
On substituting the known values,
[tex]\begin{gathered} E_P=10\times9.8\times45 \\ =4410\text{ J} \end{gathered}[/tex]The potential energy of the fruit basket is 4410 J
the magnetic field of a long, straight wire has a value b0 at a distance of r0 when the current is i0. at a distance of 3.00 r0. what current is necessary to produce a field having the same strength b0 at this position?
The magnetic field of a long straight wire has a board b0 at a distance r0 when the cutting edge is i0. at a distance of 3.00 r0: B'=2B0.
A magnetic field is a vector domain that describes the magnetic effect on moving electricity costs, currents, and magnetic materials. Transfer fees in magnetic fields are under pressure perpendicular to personal speed and magnetic fields.
The magnetic field is the place around the magnet where the effect of the magnetism is felt. We use magnetic fields as tools to explain how magnetic forces are directed into circular space and are essentially magnetic. This force attracts or repels magnets to each other. Examples of magnetic forces include compasses, motors, magnets that keep things in refrigerators, learning tracks, and new roller coasters. All the carrying charges create a magnetic field, and the charges flowing through that area enjoy the force.
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when the radius of a circular phase space plot changes, what does this mean? a. momentum is conserved. b. momentum is not conserved. c. energy is not conserved. d. energy is conserved.
Answer is b, momentum is not conserved.
Explanation:
L = r × p
So when the radius of a circular phase space plot changes, the Momentum is not conserved because farther the mass is from the center of rotation, the larger the angular momentum.
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