Joan decided to go for a walk, st arting from her house. The diagram below shows the m easurement between places on t he route where he walks. what wil I be his Position when he is at c ar?*

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Complete Question: Which the best example that something has kinetic energy ___________.

A. Car parked on steep hill.

B. Tennis ball rolls across court.

C. Picture hangs on wall.

D. Piece of coal before being burned

The best example of something with kinetic energy is option B) where a tennis ball is rolling across the court. This is because it is in a state of motion.

An object's energy due to its motion is referred to as kinetic energy. You require effort to move a body with mass from rest to a particular velocity. Body has kinetic energy that it got when it was being accelerated until and unless there is a change in speed.

In the option B, the tennis ball is rolling across the court. This means that it has covered a particular distance in some time, due to which it has attained some speed and possesses acceleration. Due to the change in its motion state, some energy will get stored in it, which entirely depends on its mass and velocity.

In option A, a car is parked which means it is in a state of rest and doesn't possess any speed. As it isn't in motion, it doesn't have kinetic energy.

In option C, a picture is hanging on the wall at a particular height from the ground. It is static and doesn't have any motion due to which there is no kinetic energy. But it will have potential energy.

In option D, a piece of coal before is burned is not in a state of motion but in a change of physical state. Therefore, it isn't a perfect example for kinetic energy.

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At the time when the Acceleration of b is 0.5 the acceleration would be 0.25 m/s2 and the velocity would be 0.75 m/s after 3 seconds of falling B.

The relation between the acceleration of 2 bodies in this situation will be as  a1 = 2a2 where a1 is the acceleration of body1 and a2 is the acceleration of body2. So given the acceleration of the body at 3 seconds is 0.5 m/s2 so the acceleration of body1 would be half of the body1.

Similarly for velocity using v= u+ at ....(i). we can find the velocity of body1 as we have acceleration(a), time(t), And Initial Velocity(u).

u= 0  ................ (As the body starts from rest)

a = 0.25m/s2 .........(calculated on the basis of the acceleration of body2)

t = 3 Seconds ---(As given)

So from (i) we can say

v = 0+ 0.25*3 => v = 0.75 m/s

So the velocity of body 1 will be 0.75m/s after 3 seconds of falling down.

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The work function of the metal is found to be 1.13eV and the speed of the ejected electrons is found to be 7.8 x 10⁵ m/s.

The wavelength of the light used for illumination is 437 nm.

The stopping potential is given to be 1.67V.

The required values are also given,

(a) The work function is found as,

Ve + W = E

E is the energy of the light,

V is the stopping potential,

W is the work function,

Putting values,

1.67eV + W = 1240/437eV

W = (2.8- 1.67)eV

W = 1.13eV.

The work function of the metal is 1.3eV.

(b) The maximum speed of the ejected electrons,

Kinetic energy = stopping potential

1/2mv² = 1.67 eV

v² = 1.67 x 1.67 x 10⁻¹⁹ x 2/9.1 x 10⁻³¹

v₂ = 6.1 x 10¹¹ m/s

v = 7.8 x 10₅ m/s.

So, the speed of the electron is 7.8 x 10⁵ m/s.

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This same distance from the Earth's core to a location where the gravitational acceleration is g/16 is roughly 20,000 miles (32,000 kilometers).

The pace at which speed changes is known as acceleration. So because direction of an object's velocity is shifting even while it follows a circular course, it continues to accelerate.

According to the formula a = v/t, kinetic energy (a) is the product of the change in momentum (v) and the shift in time (t).

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The chi-square test indicates that the observed data is statistically significant, as the chi-square value of 29.25 is greater than the critical value of 7.815 at the 0.05 significance level and three degrees of freedom.

The chi-square test is a statistical test used to determine if there is a significant difference between observed frequencies and expected frequencies in one or more categories. It is commonly used in hypothesis testing to compare the observed data to expected data, and to measure how well a particular model fits the data. The chi-square statistic is calculated by subtracting the expected frequencies from the observed frequencies, squaring each of the differences, and then summing them. The result is then compared to a chi-square table to determine the probability that the observed data did not differ from the expected data.

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Answer:

Biogas is one of the types of biofuels that is produced by the decomposition of organic substances. Biogas is an excellent fuel.

Explanation:

Reasons are as follows:

1. It is a type of renewable source of energy that has high calorific value also.

2. It is clean source of fuel that leaves no residue like ash in coal,  wood burning.

Depending on the type of organic matter used for decomposition during waste treatment technology and hence composition of biofuel varies. The main constituent of biogas is Methane (75%).

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The charge with uniform density 15.9 nC/m^2 everywhere on its surface is 4.8nC, on its curved lateral surface only is 582.5nC, throughout the plastic is 1730.6nC, along the length of the plastic is 174.7nC.

Given the radius of cylinder (r) = 2.55cm = 2.55 x 10^-2m

The length of cylinder (h) = 6.24cm = 6.24 x 10^-2m

The total surface area of cylinder is calculated as: (A) = 2πr(r + h)

Then, A = 2 x 3.14 x 2.55 x 10^-2(2.55 x 10^-2 + 6.24 x 10^-2)

A = 188.8 x 10^-4m^2

The charge on cylinder = q

We know that the charge density is calculated as:

charge = charge density x total area of cylinder

(a) Given the charge density on cylinder a is = 15.9NC/m^2

The charge on cylinder = surface area x charge density

charge = 4πr^2 x 15.9 = 4 x 3.14 x (2.55 x 10^-2)^2 x 15.9 = 4.8nC

(b) the charge density on curved lateral surface only = 15.9nC/m^2

charge = 2πrhx15.9 = 2 x 3.14 x 2.55 x 10^-2 x 6.24 x 10^-2 x 15.9

= 582.5 nC

(c) the charge density throughout the plastic is = 475 nC/m^3

charge = πr^2h x 475 =  1730.6 nC

(d) along the length of the plastic is 64.2 nC/m

charge = πrh x 64.2 = 174.7 nC

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complete question: four solid plastic cylinders all have radius 2.55 cm and length 6.24 cm. find the charge of each cylinder given the following additional information about each one.

Cylinder (a) carries charge with uniform density 15.9 nC/m^2 everywhere on its surface.

Cylinder (b) carries charge with uniform density 15.9 nC/m^2 on its curved lateral surface only.

Cylinder (c) carries charge with uniform density 475 nC/m^3 throughout the plastic.

Cylinder (d) carries charge with uniform linear density 64.2 nC/m along the length of the plastic.

The weight of the astronauts and the gravitational force of the space station on the astronauts describes the action-reaction force pair in the space.

According to Newton's law of gravitation, every objects attracts every other object in the universe with a force called gravitational force. This force is directly proportional to the product of the objects' masses and inversely proportional to the square of the distance(d) between them.

F = gMm/d²

Now according to the third law of newton every force has an equal and opposite reaction. So the gravitational force of the space station will be equal to the weight of the astronauts on the space station.

Hence the correct option is C.

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Answer:

  71 J

Explanation:

You want the energy lost to non-conservative forces when a 0.76 kg ball is dropped from a height of 22 m and impacts the ground at 15.6 m/s.

The potential energy of the ball is ...

  PE = mgh

  PE = (0.76 kg)(9.8 m/s²)(22 m) = 163.856 J

The kinetic energy the ball has when it strikes the ground is ...

  KE = 1/2mv²

  KE = 1/2(0.76 kg)(15.6 m/s)² = 92.4768 J

The energy lost during the fall is ...

  PE -KE = lost energy

  163.856 -92.4768 = 71.3792 . . . joules

About 71 joules of mechanical energy is lost.

The capacitive current would be lead by the inductive current. Option A

We know that the current is the flow of electrons in the circuit. The cutrrent and the voltage in the cell can be related by the use of the Ohm's law. When we have the RLC circuit, the voltage and the current may lead or lag each other by a phase angle.

A vector diagram can be used to show the way that the voltage does lead or lag the current in the case of the LC circuit as we can see from the complete question shown in the image attached.

Hence, we can see that the indictive current leads the capacitive current.

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The correct equation for the quantity represented in the centralburg city scenario laid out in a uniform grid of blocks, the grocery store is three blocks east and four blocks north of the post office is tan (θ) = dn/de (option A)

Take a look at the image below (figure 1)

To determine tan (θ) = opposite side/ adjacent side.

Now, according to the figure,

The angle's opposite side is dn and the adjacent sides is de.

A right-angled triangle serves as the foundation for the three primary trigonometric functions: sine, cosine, and tangent.

The opposite side, adjacent side, and hypotenuse of a triangle are denoted by:

The terms "opposite" and "adjacent" refer to the opposing and adjacent angles.

Put these values into the formula now,

Which results in the equation,

tan (θ) = dn/de

Now, it is clear from the options provided that option A is correct.

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Power required= 450 watts

Given,

Force(F)= 300N,

Time(t)= 1.0s,

Distance(d)= 1.5m,

Power(p)=?

Power(p)=work/time,

Work=Force*Distance=F*d

        =300*1.5 =450J

Power(p)= 450/1.0

              =450 Watts

Power required= 450 Watts

As the crew is adding one mile to the road each day, so the length of the road after 27 days is 79 miles.

A collection of skilled workers, including a supervisor, a construction manager, a distinct maintenance staff, and a team of specialist labourers, make up an efficient construction crew. Employees must actively participate in the prevention of hazardous situations as they have a significant role to play.

A road construction crew assists with new road and sidewalk creation, repairs to or improvements to current roads, and the burying of wires underneath the local roads. They are also known as vehicle restraining operators and highway maintenance operators.

The question is incomplete, find the complete question here

A construction crew is lengthening a road that originally measured 52 miles. The crew is adding one mile to the road each day. The length, L (in miles), after d days of construction is given by the following function. L = 52 + d. what is the length of the road after 27 days?

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(a) The acceleration of the object when it travels 5 m is 2 m/s².

(b) The time taken for the object to travel the first 12 m is 3.46 seconds.

(c) The work done in displacing the object 12 m is 48 J.

(d) The speed of the object at a displacement of 12 m is 6.92 m/s.

(e) The speed of the object at a displacement of 12 m is zero.

The acceleration of the object is calculated as follows;

a = F / m

when the object travels 5 m, the force = 4 N

a = 4 N / 2 kg

a = 2 m/s²

The time taken for the object to travel the first 12 m is calculated as follows;

t = √ (2s / a )

where;

t = √ (2 x 12 / 2 )

t = 3.46 seconds

The work done in displacing the object 12 m is calculated as follows;

W = Fd

W = 4 N x 12 m

W = 48 J

The speed of the object at a displacement of 12 m is calculated as;

v = at

v = 2 m/s²  x 3.46 s

v = 6.92 m/s

At a displacement of 20 m, the acceleration of the object is zero, hence the velocity is zero.

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When the ball is released from rest 2.0 m from the ground, it will hit the ground at 0.63 seconds.

Therefore, acceleration owing to gravity is the name given to the acceleration of falling objects in free fall.

The paper ball falls from the rest, so the initial velocity will be 0.

s = ut + 1/2 at²

S is the height

u is the initial velocity

g is the gravity (9.81 m/s²)

t the time

The height will be 2.0 m, u = 0

2 = 0 x t + 1/2 x 10 x t²

2 = 5t²

t² = 2/5

t = 0.63 seconds.

Therefore, the ball will hit the ground after 0.63 seconds of its release.

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The magnitude of the torque about the bolt due to the worker and the weight of the beam is 13,798.4 Nm.

.What is the magnitude of the torque about the bolt due to the worker and the weight of the beam?

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Electric field and electric force are related quantities, but not the same thing.

The strength of the electric field is defined as the electrostatic force experienced by a small test charge [tex]q_{0}[/tex]  placed at that point divided by the charge itself.  The electric field is a vector quantity, and its direction is the same as the direction of the force on a positive test charge.

The strength of the Electric field at a point can also be checked by the density of electric field lines present at that point.

The S.I unit of the Electric field is Newton per columb.

The S.I unit of force is Newton.

[tex]F = E \ q_{0}[/tex]

F= electrostatic force

E= electric field

[tex]q_{0}[/tex] = test charge

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The ionosphere is the home of all charged particles in the earth's atmosphere, as well as some of the satellites that we launch.

The ionosphere of Earth extends from the top of the atmosphere to the very edge of space. The Sun heats the gases until they lose an electron or two, resulting in a sea of electrically charged particles.

The ionosphere extends 50 to 400 miles above the Earth's surface, right on the edge of space. The ionosphere, along with the neutral upper atmosphere, forms the boundary between Earth's lower atmosphere — where we live and breathe — and space.

This space boundary is right where many of our Earth-orbiting satellites, including the International Space Station, are located. This means that these satellites can be affected by the ionosphere's constantly changing conditions, such as sudden swells of charged particles that increase drag on satellites and shorten their orbital lifetimes, or how long they can orbit Earth.

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Steve had a stroke last year that most likely the stroke has damaged his frontal lobes.

Stroke can be explained as a condition that occur when sufficient blood does not flow to the brain or due to insufficient flow of blood to the brain. Stroke should be treated as an immediate emergency case as it can lead to difficult walking, talking or paralysis and many more worst cases.

When a person's frontal lobes is damaged the brain may not function properly again and stroke is one of the cause of damaged frontal lobe.

Therefore if he is unable to remember what he just ate for breakfast. it is most likely that the stroke: damaged his frontal lobes.

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Within a study, the factor that does not change is the Independent variable. It is the variable that is controlled and changed by the experimenter.

The independent variable is the factor that is manipulated or changed in an experiment to observe the effect on the dependent variable. Examples of independent variables include temperature, amount of light, or amount of water. An independent variable is exactly what it sounds like. It is an independent variable that has no bearing on the other factors you are attempting to evaluate. For example, age may be an independent variable. For example, if you were analyzing how the amount of sunlight affected the development of a certain plant type, the amount of sunlight would be the independent variable. Each plant receives a different amount of light, which may be altered. Growth is the dependent variable. It is a result of the amount of sunlight.

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The building contains ceiling apertures that enable viewing of constellations that are prominent in the folklore of the culture, and many other structures constructed by the same civilization also have ceiling holes arranged in the same manner.

Folklore is the collective memory of a group of people and it contains the traditions particular to that culture, subculture, or community. Orally transmitted myths, lore, adages, and jokes are included in this. The group's material culture, which ranges from conventional construction designs, is one of these. Folklore also includes customary beliefs, forms and rituals associated with holidays like Christmas and weddings, folk dances, and initiation rituals.Each of them is regarded as a folklore artifact or a traditional cultural manifestation, either separately or together. Folklore includes the transmission of these artifacts from one place or generation to the next, which is just as important as the form.

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The relationship is given as (E) A force not associated with the electric field moves the electron from point A to point B. The electric field does negative work on the electron in the process.

We know that electric field is directed from positive terminal to negative terminal, if the electron truly effected by electric field, it should have moved towards the positive terminal, as electron is negatively charged particle. So a net force not associated with electric field moves the electron from A to B. The proton and electron have equal and opposite charge and force F=qE. So when they are placed in uniform electric field, the magnitude of forces are equal.

Hence option E is correct.

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Complete question:

An electron is placed at point A in a uniform electric field of magnitude E directed to the right, as shown above. A short time later, the electron is at point B. Which of the following statements describes the relationship between the electric field and the motion of the electron? The electron experiences a force of magnitude F =qE at point A, which accelerates the electron in the direction of the electric field The electric potential energy of the electron-field system at point A is converted into kinetic energy, causing the electron to move along the field lines. The electron moves through the electric field from a higher electric potential at point A to a lower electric potential at point B D) The electron is accelerated by the electric field in a direction perpendicular to the field lines, causing it to move from point A to point B (E) A force not associated with the electric field moves the electron from point A to point B. The electric field does negative work on the electron in the process.

While the penumbra of a sunspot can "grow" and become bigger.The significance is that the area around the sunspot is becoming darker and larger.

Sunspots are cooler, darker areas on the sun's surface that stand out from the sun's brighter surroundings. They are brought on by a blockage in the flow of heat and energy from the interior of the sun caused by intense magnetic activity. Sunspots can be anywhere from a few hundred to many thousands of kilometers in diameter and are most common near the sun's poles. Depending on their size and activity, sunspots can last for days, weeks, or even months.

Sunspots are linked to increased solar activity, which can alter Earth's magnetic fields, so this is significant for us on Earth. Geomagnetic storms and additional radiation that reaches Earth's surface as a result of this could disrupt electronic systems like power grids and radio transmissions.

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F = Gm1m2/r2 is one way to conceptualize it mathematically.where F denotes the gravitational force between two objects, expressed in Newtons (N). The answer is 7.4125x10²⁸ kg .

As a result, the gravitational pull between the earth and the moon is 2 10 20 N.Equation for Gravitational Force F = Gm1m2/r2 is one way to conceptualize it mathematically.

where F denotes the gravitational force between two objects, expressed in Newtons (N).

6.674 10-11 Nm2kg-2 is the value of G, the universal gravitational constant.

Given:

r = 3.8x10⁵ km = 3.8x10⁸ m, the distance between the earth and moon,

F = 20.46x10²⁵ N, the gravitational force between the earth and the moon,

G = 6.674x10⁻¹¹ m³/(kg-s²), gravitational constant

M = 5.972x10²⁴ kg, the mass of the earth.

Let m = mass of the moon.

F = (G*M*m)/r^2

m = [20.46×10²⁵ * (3.8×10⁸)²]/[6.674×10⁻¹¹ * 5.972×10²⁴]

   = 7.4125×10²⁸ kg

7.4125x10²⁸ kg

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The mechanical advantage a simple machine is obtained by dividing the output force by the input force.

option B.

The mechanical advantage of a simple machine is the ratio of output force to input force. It is also the ratio of load overcame by a simple machine to the effort applied by the simple machine.

Mathematically, the formula for mechanical advantage of a simple machine is given as;

M.A = output force / input force

M.A = Load / effort

Thus, the mechanical advantage of a simple machine depends on the output force of the machine and the input force of the machine.

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The electric field in region 1, due to the sphere, can be expressed as:

where Q is the charge of the sphere, r is the distance from the center of the sphere, and ε0 is the permittivity of free space.

An electric field is a force field created by a charged particle that exerts a force on other charged particles in the vicinity. It is measured in units of Volts per meter (V/m). The electric field is a vector quantity, meaning it has both magnitude and direction.

The electric field is defined as the force experienced by a unit charge placed in the field. The magnitude of the electric field is proportional to the charge, and the direction of the field is determined by the direction of the force. Electric fields can exist between two charged objects, or between a charge and the ground. Electric fields can also be generated by electric currents, where they are called magnetic fields.

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Circuit-switched network is the more appropriate for this application that transmits data at a steady rate.

The application would perform best over a circuit-switched network since it requires lengthy sessions with steady, predictable bandwidth needs. Because the transmission rate is steady and known, it is possible to reserve bandwidth for each application session without wasting much of it. In addition, the overhead costs of setting up and tearing down connections are reduced over the lengthy duration of a typical application session.

It makes more sense to use a circuit-switched network rather than a packet-switched network, which is more practical when data shows in bursts, as the data are transmitted at a steady rate (x bits per second, for example), and they are also transmitted over a relatively long period of time rather than in short bursts.

The question is incomplete. The complete question is 'Would a packet-switched network or a circuit-switched network be more appropriate for this application? Why?'

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A single cylinder, double acting compressor with bore and stroke of 45 cm x 45 cm is tested at 150 rpm. The percent clearance is 586.6%

An equation is a mathematical statement that uses the equals sign (=) to show that two expressions are equal. Equations can be used to find solutions to problems with unknown values and to define relationships between various variables. Equations are also used to represent natural laws and describe the behavior of physical systems.

The following equation can be used to determine the percentage of clearance:

C is equal to 100 times (Vd/Vs - 1),

where Vd is the volume displaced per cycle and

Vs is the volume swept per cycle.

The following equation can be used to determine the displaced volume per cycle: (n/n-1) x (V1/P1) x (P2 - P1) is Vd.

The following equation can be used to determine the swept volume per cycle: Vs is equal to /4  × (D2) × L, where D is the cylinder's bore and L is its stroke.

We obtain: by putting the given values into the equations:

Vs = /4 × (452)  × 45 = 10302.5 cm3/cycle = 0.01031 m3/cycle

C = 100 × (6.049/0.01031 - 1) = 586.6%,

which indicates that the clearance percentage is 586.6%.

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In order to solve this, we can use the conservation of mechanical energy. The total mechanical energy of an object is the sum of its kinetic energy (KE) and its potential energy (PE).

The initial mechanical energy of the toy car is the sum of its initial kinetic energy and its initial potential energy, which is zero since it starts at the same level as the track. The final mechanical energy of the toy car is the sum of its final kinetic energy and its final potential energy.

We know the initial speed of the toy car is 2.00 m/s, and it coasts up the frictionless slope, gaining 0.180 m in altitude. We can use these values to find the final mechanical energy of the toy car.

E_initial = KE_initial + PE_initial = (1/2)mv^2_initial + mgh_initial = 0

E_final = KE_final + PE_final = (1/2)mv^2_final + mgh_final

We know the mass of the toy car is 100g and we can convert it to kg by dividing it by 1000.

m = 100/1000 = 0.1 kg

We also know that the acceleration due to gravity is 9.8 m/s^2.

g = 9.8 m/s^2

Substituting these values into the equation for final mechanical energy, we get:

E_final = (1/2)mv^2_final + mgh_final = (1/2) * 0.1 * v^2_final + 0.1 * 9.8 * 0.180 = 0.05v^2_final + 0.018

Since the initial mechanical energy is zero, we can set the final mechanical energy equal to zero and solve for the final velocity of the toy car.

E_initial = E_final = 0

0.05v^2_final + 0.018 = 0

v^2_final = -0.018 / 0.05

v_final = sqrt(-0.018 / 0.05)

The final velocity/speed of the toy car is 0.687 m/s.

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To be safe during a lightning storm, it is best to be to be safe during a lightning storm, it is best to be inside a metal car.

As the car is made up of metal, it acts as a good conductor and conducts energy from the lightning to the grounded rubber tires.

Being inside a wooden building is not good as wood is a bad conductor.

Staying on metal observation tower is bad as the charges on the tower are attracted to the clouds and lightning strikes you.

It is not safe to stay under tall trees as the charge may jump from trees to you as wood is a bad conductor.

In the middle of grassy meadows is bad as you are taller than surrounding and your are a good conductor.

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