M is less than angleAOC = 108 degrees m is less than angle AOB = 3x + 4 degrees m is less than angle BOC = 8x - 28 degrees Find m is less than angle AOB

Answer: not very sure but i think that may be 5

Step-by-step explanation:

Answer:

(6, - 3 )

Step-by-step explanation:

Given f(x) then f( x + c) represents a horizontal translation of f(x)

• If c > 0 then a shift to the left of c units

• If c < 0 then a shift to the right of c units, thus

y = f(x - 4) represents a shift to the right of 4 units, so

(2, - 3 ) → (2 + 4, - 3 ) → (6, - 3 )

The maximum point on the graph after translation y = f( x -4) is (6 , -3)

Translation of a graph is the movement of the graph either in horizontal direction or vertical direction .

Horizontal translation to the left is given by f (x+ c) ,c >0

: (x, y) → (x- c , y)

Horizontal translation to the right is given by f (x- c) ,c >0

: (x, y) → (x+ c , y)

Given that the maximum point on the graph of the equation

y = f(x) is (2,-3)

To find the maximum point on the graph of the equation y = f(x-4)

f(x -4) is Horizontal Translation to the right with 4 units , c= 4

then  (x, y) → (x+ c , y)

Thus the maximum point (2,-3) is moved to ( 2 +c , -3)

⇒ (2+ c , -3) = (2+4 , -3) = ( 6 , -3)

Therefore, the maximum point of the graph of the equation  y = f(x-4) becomes (6,-3)

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Answer:

The missing factor is (9s+1)

Step-by-step explanation:

The missing factor is (9s+1) because of the following

(9s^2 + s) + (18s+2)

If we factor out s from 9s^2+s, we get s(9s+1).

If we factor out 2 from 18s+2, we get 2(9s+1)

putting these together, we get s(9s+1) + 2(9s+1). Factoring out the common term of 9s+1, we get (9s+1)(s+2). therefore, the missing factor is 9s+1

Answer:

Correct option: C.

(Both Joey and Nolan)

Step-by-step explanation:

The step Joey did is:

Add 7x to both sides of the equation

Then, he got:

13x - 42 + 7x = 18 - 7x + 7x

20x - 42 = 18

The step Nolan did is:

Add 42 to both sides of the equation

Then, he got:

13x - 42 + 42 = 18 - 7x + 42

13x = 60 - 7x

So both of them used correctly the addition property of equality in the first step of their work.

Correct option: C.

Answer:

The answer to your question is C.

Step-by-step explanation:

Have a nice day :)

Answer:

The area of the rectangle is 880 cm

Step-by-step explanation:

Lenght = 55cm

Breadth/width=16cm

Area of rectangle= lenght×breadth

Area= 55×16

Area= 880

Hence, area of rectangle is 880cm

P.S - Mark me as the brainliest :D

Answer:

Mehmut is 8 years old.

Step-by-step explanation:

From the statement we can get the following information, let M be Mehmut's age and b brother's age:

M = 4 * b

M + 1 = 3 * (b + 1)

We replace the first equation in the second and we are left with:

4 * b + 1 = 3 * b + 3

4 * b - 3 * b = 3 - 1

b = 2

Now, we replace to calculate M:

M = 4 * b

M = 4 * 2

M = 8

Mehmut is 8 years old.

Answer:

1/2

Step-by-step explanation:

The constant of variation is the same as the slope. From the graph, the slope is 1/2.

Answer:

I believe the answer is 2

Answer:

C

Step-by-step explanation:

Option c gives the actual representation of the question

Answer:

B. 32°

Step-by-step explanation:

Since two of the sides are 10 in length, then we can infer that ∠A and ∠C are congruent. So, both equal 74°. You add 74 + 74 + x = 180, x would equal 32°.

Answer:

B

Step-by-step explanation:

sum of angle in triangle is 180

and since its isosceles triangle, it means <C will be same with <A

so we know that A + C = 148.

so the value of B will be like this

B = 180° - (A+C)° = 180 - 148 = 32°

The required explicit formula for the sequence is [tex]a_n = 9+(n+1)(-3)[/tex]. Option B is correct.

Given, an arithmetic sequance is given in the form of [tex]\left \{ {{a_1=9} \atop {a_n =a_{n-1}-3} \right.[/tex] .
Explicit formula for the sequence is to be determined.

Arithmetic progression is the sequence of numbers that have common differences between adjacent values.
Example,  1, 2, 3, 4, 5, 6. this sequence as n = 6 number with a = 1 (1st term)  and common differene d = 2- 1 = 1.

Given arithmetic sequance is in the form of [tex]\left \{ {{a_1=9} \atop {a_n =a_{n-1}-3} \right.[/tex]
From above expression
[tex]a_n-a_{n-1}= -3[/tex]
common difference (d) = -3
with d = -3 and [tex]a_1 = 9[/tex]
The equation for the nth term in an arithmetic sequence is given by
[tex]a_n =a +(n-1)d[/tex]
[tex]a_n = 9 +(n-1)(-3)[/tex]
The above expression is the explicit form of the arithmetic equation.

Thus, the required explicit formula for the sequence is [tex]a_n = 9+(n+1)(-3)[/tex]. Option B is correct.

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Answer:

simplified expression for √x^2+6x+9 if x≥3

is x+3

Step-by-step explanation:

[tex]\sqrt{x^2+6x+9} \\=>\sqrt{x^2+3x+3x+9} \\=>\sqrt{x(x+3)+3(x+3)} \\=>\sqrt{(x+3)(x+3)} \\=>\sqrt{(x+3)^2}\\=>(x+3) \ or -(x+3)[/tex]

but given that x≥3

then we have to negate solution -(x+3)\

Then simplified expression for √x^2+6x+9 if x≥3

is x+3

The answer choice which could be used to make a bow with the least amount remaining is; 1 2/5 yards.

It follows from the task content that the amount of ribbon remaining in each case can be evaluated as follows;

For 1 2/5 yards: 1 2/5 - 1 1/3 = 1/15. renders only 1/15 a yard to waste.

For 1 and 1/6 yards would render a waste of 1 1/6 yards since it is not possible to make a ribbon out of it.

1 2/10 yards would render a waste of 1 and 1/5 yards since it is not possible to make a ribbon out of it.

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Answer:

6.4

Step-by-step explanation:

By the Pythagorean Theorem:

[tex]c=\sqrt{5^2+4^2}= \\\\\sqrt{25+16}= \\\\\sqrt{41}\approx 6.4[/tex]

Hope this helps!

Answer:

To solve we need to use pythogorean theorm. So first we take the square of both giving us 25, 16. Then we add them and get 41. So the answer is squareroot of 41 and if you round you get 6.4

Step-by-step explanation:

position your compass at point A and using the same distance mark arcs on line AB(mark the point it meets the line D)and AC(mark the meeting point of the arc and the line E).Place your compass at D and draw an arc at the middle of the angle,using the same measurements position your compass at point E and draw an arc.Where the two arcs meet label F using a ruler draw a straight line from F to meet point A.

Note;the width of the compass when making the arcs should be the same always