Match each of the elements below to a possible use for it

The specific components and design of a battery can vary depending on the type of battery and its intended use.

The basic components of a battery include:

Anode: This is the negative electrode of the battery where the oxidation reaction takes place.

Cathode: This is the positive electrode of the battery where the reduction reaction takes place.

Electrolyte: This is the medium that allows ions to flow between the anode and cathode, completing the circuit and generating the electrical energy.

Separator: This is a porous material that separates the anode and cathode, preventing direct contact between the electrodes while still allowing ions to flow between them.

Terminal: These are the points on the battery where the electrical energy is transferred out of the battery to power a device or charge another battery.

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Answer:

157 grams magnesium chloride

Explanation:

1.  We must first find the molar mass (g/mole) of magnesium chloride.  The molecular formula is MgCl2.

Add the elemental atromic weights for one molecule of the material:

1 Mg = 24.3

2 Cl = 2*(35.45) = 70.9

Total = 95.2 grams/mole

We can use this as a conversion factor by multiplying it times the moles we are asked to convert:  (1.65 moles MgCl2)*(95.2 grams/mole MgCl2).

The moles cancel, leaving us with 157 grams of magnesium chloride.

The relative atomic mass is205.976 amu x

Relative atomic mass (also called atomic weight) is the average mass of the atoms in a naturally occurring sample of an element, taking into account the abundance of each isotope of the element. It is a dimensionless quantity, defined as the ratio of the average mass per atom of the element to the unified atomic mass unit (u or Da).

To calculate the relative atomic mass of thallium, we need to take into account the abundance and atomic masses of its two isotopes, thallium-205 and thallium-203.

Let X be the relative atomic mass of thallium.

The atomic mass of thallium-205 is 205.976 amu, and its abundance is 70% or 0.7.

The atomic mass of thallium-203 is 202.972 amu, and its abundance is 30% or 0.3.

Using the formula for calculating relative atomic mass, we have:

X = (205.976 amu x

Overall,  the answer has been rounded to four significant figures, which is the same as the least number of significant figures given in the input data (two significant figures for the isotopic abundances).

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The volume of the gas at 1 atm will be 5.05 L. Option D is correct.

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:

P₁V₁/T₁ = P₂V₂/T₂

where P₁, V₁, and T₁ are the initial pressure, volume, and temperature, respectively, and P₂ and V₂ are the final pressure and volume, respectively.

Assuming the temperature is constant, we can rearrange the equation to solve for V₂:

V₂ = (P₁/P₂) × V₁

Plugging in the given values, we get:

V₂ = (1.16 atm/1 atm) × 4.35 L = 5.046 L

Therefore, the volume of the gas at 1 atm will be approximately 5.05 L (rounded to three significant figures).

Hence, D. 5. 05 L is the correct option.

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--The given question is incomplete, the complete question is

"4. 35 L of a gas is at 1. 16 atm. What will be its volume at 1 atm? k A) 0 0. 267 L B) 0 0. 198 L C) 0. 0185 L D) 5. 05 L E) 3. 75 L"--

Answer:

To calculate the number of moles of NaOH needed to create a 2 M solution in 8 liters of solution, we need to use the formula:

moles = molarity x volume (in liters)

Here, the molarity (M) is given as 2 M, and the volume (V) is given as 8 liters.

So,

moles = 2 M x 8 L

= 16 moles

Therefore, 16 moles of NaOH are needed to create a 2 M solution in 8 liters of solution.

Explanation:

Using the reaction profile that we can see from the question that has been given, the overall energy change is -250 kJ/mol

Enthalpy of reaction is the amount of heat absorbed or released during a chemical reaction, at a constant pressure. It is a measure of the energy change that occurs when reactants are transformed into products in a chemical reaction.

Enthalpy of reaction is denoted as ΔHrxn, where ΔH is the symbol for the change in enthalpy, and rxn is the abbreviation for "reaction". It is expressed in units of energy per amount of substance, such as joules per mole (J/mol).

Using;

Energy of Products - Energy of reactants

100 - 350 = -250 kJ/mol

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the mass of carbon in 100.0 g of vinegar is 40.01 g, the mass of hydrogen is 6.70 g, and the mass of oxygen is 53.29 g.

To calculate the mass of each element in 100.0 g of vinegar, we need to use the percent composition of the compound. The percent composition tells us the percentage of each element in the compound by mass.

The percent composition of vinegar is:

Carbon (C): 40.01%

Hydrogen (H): 6.70%

Oxygen (O): 53.29%

To calculate the mass of each element, we need to multiply the percent composition by the total mass of the compound (100.0 g).

Mass of carbon (C) = 40.01% x 100.0 g = 40.01 g

Mass of hydrogen (H) = 6.70% x 100.0 g = 6.70 g

Mass of oxygen (O) = 53.29% x 100.0 g = 53.29 g

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Answer:

Explanation:

mOLARITY IS moles/L

moles = M X L

2.1 X 0.50 = 1.05 moles NaBr or 1.1 moles NaBr to correct sig figs

The answer is 0 g.

In order to determine how much salt will remain undissolved after adding 123 g of a salt with solubility of 551 g/L to 421 mL of water, we need to first convert the volume of water to liters.421 mL of water = 0.421 L of water

The maximum amount of salt that can dissolve in 1 L of water with a solubility of 551 g/L can be calculated using the formula:

Max amount of salt that can dissolve = Solubility × Volume of solvent Max amount of salt that can dissolve = 551 g/L × 1 L

Max amount of salt that can dissolve = 551 g

Therefore, the maximum amount of salt that can dissolve in 0.421 L of water is:

Max amount of salt that can dissolve = 551 g/L × 0.421 L

Max amount of salt that can dissolve = 231.671 g

Since only 123 g of salt was added to 0.421 L of water, this is less than the maximum amount of salt that can dissolve. Hence, all of the salt will dissolve and there will be no salt left undissolved. Therefore, the answer is 0 g.

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The other main reason that radiocarbon (14C based) age is offset from calendar (true) age is because of variations in the concentration of 14C in the atmosphere over time.

Radiocarbon dating is a technique for determining the age of an object by measuring the quantity of the radioactive isotopes of carbon contained within it. It relies on a specific natural decay process of the radioactive isotope carbon-14 (14C) into stable carbon isotopes.

Carbon-14 (14C) is a radioactive isotope that is created in the Earth's upper atmosphere when cosmic rays collide with nitrogen atoms. This is followed by the decay of 14C into stable nitrogen, with a half-life of 5,700 years.

As a result, living organisms absorb 14C as they consume carbon-containing food. When an organism dies, it no longer consumes carbon, and the 14C in its tissues starts to decay.

By measuring the ratio of 14C to stable carbon isotopes in the remains, scientists can determine the age of the organism or object.

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The name of the ionic compound formed by Ion X and Ion Y would be written as Ion X₃Y.

Ion X with a charge of 1+ means that it has lost one electron, while Ion Y with a charge of 3- means that it has gained three electrons.

To form an ionic compound, the ions must combine in such a way that the overall charge of the compound is neutral. This is achieved by combining one Ion X ion with three Ion Y ions, since 1+ charge of Ion X can be balanced by the combined 3- charge of three Ion Y ions.

The chemical formula of the ionic compound formed by Ion X and Ion Y would be written as X⁺¹(Y)³⁻

where;

So, the name of the ionic compound formed by Ion X and Ion Y would be written as Ion X₃Y.

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The mass of the Silicon Carbide is  33.3 g using the data that has been presented in the question before us.

In a balanced chemical equation, the coefficients in front of the chemical formulas represent the number of moles of each substance that participate in the reaction.

We can see that;

Number of moles of silicon dioxide =  50.0 grams/60 g/mol

= 0.833 moles

Number of moles of Carbon = 79.1 g/12 g/mol = 6.6 moles

Now silicon dioxide is the limiting reactant.

Thus;

The theoretical yield of the silicon carbide is;

0.833 moles * 40 g/mol

= 33.3 g

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Answer: a= 7  

Explanation:

Answer:

Dado que los malvaviscos solo pueden hacer 2 s'mores, son el reactivo limitante. Esto significa que el número máximo de s'mores que se pueden hacer es 2.

Por lo tanto, la respuesta correcta es: los malvaviscos serían el reactivo limitante y las galletas graham y el chocolate serían el exceso. Puedes hacer dos s'mores.

Explanation:

The heat absorbed by 30 g of ice absorbs heat with an enthalpy of fusion of 334 J/g in a calorimeter is 10.02kJ.

Given the mass of ice (m) = 30g

The enthalpy of fusion (L) = 334J/g

Let the heat absorbed = Q

We know that in calorimetry, the heat absorbed is equal to the product of mass of substance and its enthalpy of fusion.

According to the above given details,

Q = m * L

Q = 30 * 334 = 10,020J = 10.02kJ

Enthalpy of fusion is the amount of energy required to convert a substance from its solid state to its liquid state at a constant pressure.

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The theoretical yield of H2O from 68.75 g of C4H10 is 106.6 g.

We now know that the theoretical yield of CO2 C O 2 is 2.56 mol since the limiting reactant dictates it.

For the combustion of C4H10, the balanced equation is:

2C4H10 + 13O2 → 8CO2 + 10H2O

First, let's calculate the number of moles of C4H10:

molar mass of C4H10 = 4(12.01) + 10(1.01) = 58.12 g/mol

C4H10 mass is equal to its molar mass in C4H10 moles.

moles of C4H10 = 68.75 g / 58.12 g/mol

moles of C4H10 = 1.183 mol

According to the balanced equation, 2 moles of C4H10 produce 10 moles of H2O. As a result, the amount of water generated is:

moles of H2O = (moles of C4H10) x (10 moles H2O / 2 moles C4H10)

moles of H2O = 1.183 mol x 5

moles of H2O = 5.915 mol

The amount of moles of water can finally be converted to grams:

molar mass of H2O = moles of H2O x

mass of H2O = 5.915 mol x 18.02 g/mol

mass of H2O = 106.6 g.

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The actual score on an exam refers to the number of points earned by a student on the test, while the theoretical score is the maximum possible score that a student could have earned if they answered every question correctly.

In chemistry, concentration refers to the amount of solute that is dissolved in a given amount of solvent or solution. It is typically expressed in units such as molarity (moles of solute per liter of solution), molality (moles of solute per kilogram of solvent), or percent concentration (the percentage of solute in a solution by mass or volume). Concentration plays an important role in determining the properties and behavior of a solution, including its reactivity, solubility, and osmotic pressure. It also affects the rate of chemical reactions, as the frequency of collisions between molecules or ions is related to their concentration in the reaction mixture.

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Answer:

the heart and blood

Explanation:

the blood jus move threw heart or sum

The molecular formula for Adenine with molecular mass of 135.1 and consist of 44. 45% C, 3. 73% H, and 52. 82% N by mass is C₃H₃₆N₂.

The molecular formula expresses the number of atoms of each element in one chemical molecule.

The definition of a molecular formula is the formula that shows the exact number of atoms in a molecule.

The empirical formula is used to derive the Molecular Formula when the molar mass value is known.

n=empirical formula molar mass/mass

The molecular formula is frequently the same as or an exact multiple of an empirical formula.

We have molecular formula = 135.14

so we need to find each atoms contribution so,

C = 135.14 /44.45 = 3.03

H = 135.14 /3.73 = 36.21

N = 135.14 / 52.82 = 2.55

So we have molecular formula as,

C₃H₃₆N₂.

Adenine is a nucleic acid component, specifically the nitrogenous base in the structure. Adenine is a nitrogenous base present on both DNA and RNA molecules (examples of nucleic acids). Adenine is a compound of Carbon, Hydrogen, and Nitrogen atoms, and elemental analysis can assist in determining the chemical formula.

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CEC-C-H: 9 bοnds (reactant) / 0 bοnds (prοduct)

C-O: 0 bοnds (reactant) / 2 bοnds (prοduct)

H-O: 0 bοnds (reactant) / 1 bοnd (prοduct)

What are the number οf bοnds fοr each element invοlved in the reactiοn?

The tοtal energy fοr each bοnd is nοt prοvided, but the number οf bοnds and whether they are οn the reactant οr prοduct side is given.

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Students should pick a strategy to use during Step 2 of "Steps to Solve a Problem."

In Step 1, students should read the problem and try to understand what is being asked of them. In Step 2, they should analyze the problem and identify what type of problem it is and what strategies could be used to solve it. This is where they should pick a strategy or method to solve the problem.

In Step 3, students should develop a plan for solving the problem using the strategy they have chosen. In Step 4, they should execute the plan and check their work to make sure it is correct.

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Answer:

Step 2

Explanation:

The percentage of abundance of zinc is 20.16 % whose density is 7.13 g/cm3.

Density of the mixture is 7.039 g/ml.

Density of Cu is 8.96 g/ cm3.

Density of Zn is 7.13 g/cm3.

The fractional abundance of copper is 0.946.  

Density is defined as the substance's mass per unit of volume. The symbol of density is ρ. Mass is defined as the quantity of matter while volume is the measure of space occupied by the object. The ratio of the mass and volume of the matter is known as density.

Mass of the mixture is equals to the mass of the copper and the mass of the zinc.

Mass of mixture = Mass of copper + mass of Zinc

We know that, Density = Mass * Volume

Putting the values in this we can find the percentage of abundance of zinc.

Volume of zinc / volume of mixture = 0.20156

Percentage abundance is defined as the quantitative measurement of the percentage of a specific isotope present on earth. This gives the abundance of that particular isotope.

So percentage of abundance of zinc in the mixture is,

                = 0.20156 * 100 %

                = 20.16 %

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The question is incomplete.

What is the percent abundance (in units of percent) of zinc in a sample whose density is 7.039 g/mL and the only other component is copper with a fractional abundance of 0.946? The density for pure copper is 8.96 g/cm3 and the density of pure zinc is 7.13 g/cm3. Report your answer to one decimal place.

Answer:

Explanation:

Electron clouds are the portion that is found around the nucleus where the probability of electrons getting found is the most. The theory that describes about the electron cloud is quantum mechanical model (Schrodinger atomic model). Schrodinger suggested that the electrons are observed around the nucleus.

Explanation:

The question deals with the process of qualitative analysis and the salt we are to identify is D which is ZnCl2.

Qualitative analysis of metal ions in chemistry is the process of identifying the presence or absence of various metal ions in a given sample through the use of chemical tests. Qualitative analysis is important because it helps to identify the chemical composition of a substance.

We can see that the time that the NaOH(aq) in drops, then in excess was added, there was the appearance of a ppt which is Zn(OH)2. This is going to dissolve in excess.

Addition of  dil. HNO3 + AgNO3(aq) + NH3(aq) would confirm the presence of the chloride anion.

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Hydrocid and oxacid acids (formation, nomenclature, properties and application):

Formation: binary compounds formed by HYDROGEN and a NON-METAL (from groups 6A and 7A of the periodic table).

Properties: they are found naturally in a gaseous state. They are called hydrocids because when they dissolve in water and dissociate, they generate acidic solutions.

Applications : In the industry they are mostly used for organic synthesis and for the leather tanning industry.

Formula: HX, H is hydrogen and X is the chemical symbol for halogen.

Systematic: name of the acid + suffix -ide + hydrogen. Example: Hydrogen chloride → HCl

Traditional: acid + non-metal + suffix "-hydric". Example: Hydrogen telluric acid → H₂Te

Formation: Acid compounds formed by HYDROGEN, a NON-METAL and OXYGEN. They are obtained by reaction between an anhydride (acid oxide) and water . Hydrogen acts with oxidation number +1 and oxygen with -2.

Properties: They are ternary compounds (formed by three chemical elements), formed by a non-metallic chemical element, oxygen together with hydrogen.

Applications: In the industry it is used to obtain fertilizers for agriculture . As well as it is used for the synthesis of other acids, sulfates and in the petrochemical industry .

Nomenclature

Formula: HaXbOc, H is hydrogen, X is a non-metal element and O is oxygen

Stock : Acid + prefix indicating the number of oxygens + oxo + prefix for the number of non-metallic atoms + root of that atom ending in "-ico" + valence in Roman numerals (in brackets). Example: Dioxochloric acid (III) → HClO₂

Systematic : prefix that indicates the number of oxygens + oxo + prefix for the number of non-metallic atoms + root of that atom ending in "-ate" + valence in Roman numerals (in parentheses) + hydrogen. Example: Hydrogen tetraoxochlorate (VII) → HIO₄

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Translated Question: Prepare, in your notebook, a graphic organizer in which you synthesize the information obtained in the text. Provides information on the formation of hydroacid and oxacid acids, their nomenclature, their properties and their application in industry. help me

The electron's starting energy level was 1.73.

We can use the energy formula E=hc/λ, where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

First, let's convert the given wavelength to meters:

λ = 410 nm = 410 × 10⁻⁹ m

Next, we can substitute the given values into the energy formula to find the energy of the emitted photon:

E = (6.626×10⁻³⁴ J s) × (2.998×10⁸ m/s) / (410×10⁻⁹ m) = 4.846×10⁻¹⁹ J

The energy of the emitted photon corresponds to the difference in energy levels between the initial and final states of the electron in the hydrogen atom. We can use the formula for the energy levels of a hydrogen atom: E = -R[infinity] / n², where R[infinity] is the Rydberg constant for hydrogen and n is the principal quantum number.

If the electron transitioned from an initial energy level with principal quantum number n1 to a final energy level with n2 = 2, then we can set up an equation to solve for n1:

E = -R[infinity] × (1/n₂² - 1/n₁²)

Substituting the given values into the equation and solving for n1, we get:

n₁² = (R[infinity] × (1/n₂² - E / R[infinity]))⁻¹ = 3.00

Therefore, the initial energy level of the electron was n1 = √(3) ≈ 1.73 (rounded to the nearest whole number).

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For AABC AQPR to be true, the measures of angles A, C, and D must all be equal; in this case, they must all be equal to 81°. Therefore, conditions A, C, and D are sufficient to show that AABC AQPR.

Angles are points in a plane that are formed when two lines intersect. They can also be formed when one line rotates around a fixed point. Angles are measured in degrees and can be equal to, greater than, or less than a right angle (90°). The four main types of angles are acute (less than 90°), right (90°), obtuse (greater than 90°), and straight (180°). Angles can also be classified as complementary, supplementary, vertical, alternate, and adjacent.

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Answer:

The identity of the element can be determined by comparing the atomic masses of the known isotopes with the atomic masses of the elements listed in the answer choices.

The weighted average atomic mass of the element can be calculated as follows:

(0.51839 × 106.91 amu) + (0.48161 × 108.90 amu) = 107.87 amu

The closest match to this atomic mass is option 1, Silver. The atomic number of silver is 47, which means it has 47 protons in its nucleus. The two stable isotopes of silver are ^107Ag and ^109Ag, which have atomic masses of 106.905 amu and 108.905 amu, respectively. The given atomic masses of the isotopes in the question are not exact matches to the known isotopes of silver, but they are close enough to identify the element as silver.

Therefore, the answer is 1. Silver.

The quantity of electricity that deposit 10.8g of silver is equal to 9,650 coulombs and the the mass of aluminum which will be deposited by the same quantity of electricity is equal to 2.7g.

During the electrolysis process, the amount of substance deposited on an electrode is directly proportional to the amount of electricity passed through the electrolyte solution. This constant of proportionality is called as Faraday's constant. It is equal to 96,500 coulombs per mole of electrons.

In 108g, the number of moles of Aluminum is 1 mole.

In 10.8g, the number of moles of Aluminum is equal to 0.1 moles.

Since 96.500 coulombs of energy is used to transfer 1 mole of substance, So, 9650 coulombs of energy will be required to transfer 0.1 moles of the substance.

Since 27g of Aluminum will be transferred by 96500 coulombs of energy, so in 9650 coulombs of energy, 2.7g of Aluminum will be deposited.

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