Mei got scores of 76,80, and 78 on her last three history exams. Write an inequality to determine the score, x, she needs on the next exam so that her average is at least 82.

Answer: Jalen wants the post to be perpendicular to the ground, which means the angle between the post and the ground should be 90 degrees. If the protractor showed the angle to be 82 degrees, then the post is leaning towards the ground. To make the post perpendicular, the angle needs to be decreased. Jalen incorrectly concluded that he needed to increase the angle by 12 degrees, which would make the angle 94 degrees, still not perpendicular.

To make the post perpendicular, Jalen needs to decrease the angle by 8 degrees (90 - 82 = 8). Therefore, the correct answer is D: The angle needs to be increased by 8 degrees to get to a 90 degree angle.

Step-by-step explanation:

Podemos utilizar la ley de cosenos para aproximar la distancia entre las cometas. Primero, necesitamos encontrar la longitud de la tercera cuerda, que conecta los puntos donde se cruzan las dos cuerdas que sostienen las cometas. Podemos usar trigonometría para encontrar la altura de este triángulo.

El ángulo opuesto a la altura es de 30°, por lo que podemos calcular la altura como:

Ahora podemos usar la ley de cosenos para encontrar la longitud de la tercera cuerda:

Entonces, la distancia entre las cometas es aproximadamente de 380 pies.

Answer: 6

Step-by-step explanation:

When x=-3, y=6

You can count it, 1,2,3,4,5,6.

Hope you found that helpful!

The prοbability οf chοοsing a number frοm the sample space that cοntains 1 οr 4  is 1/2.

In science, the prοbability οf an event is a number that indicates hοw likely the event is tο οccur. It is expressed as a number in the range frοm 0 and 1, οr, using percentage nοtatiοn, in the range frοm 0% tο 100%. The mοre likely it is that the event will οccur, the higher its prοbability.

space οf twο-digit numbers that can be created using the digits 7,1 ,9 and 4. What is the prοbability οf chοοsing a number frοm the sample space that cοntains 1 οr 4 ?

here are a tοtal οf 16 pοssible οutcοmes in the sample space, as shοwn in the tree diagram. Out οf these 16 pοssible οutcοmes, 8 οf them cοntain the digit 1 οr 4 (i.e., 14, 17, 19, 41, 44, 71, 74, 91).

Therefοre, the prοbability οf chοοsing a number frοm the sample space that cοntains 1 οr 4 is:

P(1 οr 4) = 8/16 = 1/2

Sο the prοbability is 1/2.

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Answer:

The volume of the container is 1872 cubic cm. The volume of the water is 672 cubic cm.

Therefore, 672/1872 = 0.36 or 36%

[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1200\\ r=rate\to 0.2\%\to \frac{0.2}{100}\dotfill &0.002\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{weekly, thus fifty two} \end{array}\dotfill &52\\ t=years\dotfill &10 \end{cases} \\\\\\ A = 1200\left(1+\frac{0.002}{52}\right)^{52\cdot 10}\implies A \approx 1224.24[/tex]

Answer: $1248 in compound interest for 10 years

Step-by-step explanation:

Answer:

-4y-7

Step-by-step explanation:

- 4 y - 4 + ( - 3 )

We keep the -4y as it is since it can not be simplified. Then we try to open the parentheses. we do this by multiplying by 1.

- 4 y - 4 + 1 * ( - 3)

= - 4 y - 4 - 3

Then we combine the - 4 and -3.

= - 4 y - 7

Answer: I can confirm that it is '-4y-7'

Step-by-step explanation:

The gradient of the line is 200, hence that is the answer.

What does the word "point" actually mean?

A point is a dot on a sheet of paper or in a plane. There are no lengths, widths, or heights in a point. It establishes a plane's position or location. To make a point, mark a dot on a piece of paper with an A or another capital letter.

The slope-intercept version of the equations y = 200x + 500 is y = mx + b, wherein m is the line's gradient and b is its y-intercept.

The value of x, which really is 200, acts as the gradient (or gradient) in this equation. As a result, the line's gradient is 200.

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The number of students who passed the examination is 152.

Given: Marks distribution in Mathematics

To Find: Plot an ogive, the median, the number of students who scored distinction marks (75% and above), and the number of students who passed the examination if the pass marks are 35%.

Solution:

Marks Number of students

Less than 10 7

Less than 20 28

Less than 30 54

Less than 40 71

Less than 50 84

Less than 60 105

Less than 70 147

Less than 80 180

Ogive:

An ogive is a graph that represents the cumulative frequency distribution of a set of data. To plot an ogive, we plot the upper limits of each class on the x-axis and the corresponding cumulative frequency on the y-axis. We then join the points with a free-hand smooth curve to obtain the ogive.

Median:

To find the median from the graph, we draw a line from the value of 50 on the y-axis to the ogive curve and then drop it down to the x-axis. The point where the line intersects the x-axis gives us the median. In this case, the approximate median value from the graph is 52.

The number of students who scored distinction marks:

To find the number of students who scored distinction marks (75% and above), we first calculate 75% of the total number of students, which is 0.75 x 180 = 135.

From the ogive graph, we see that the number of students who scored less than 75% marks is 105.

Therefore, the number of students who scored 75% or more marks is 180 - 105 = 75.

The number of students who passed the examination:

To find the number of students who passed the examination if the pass marks are 35%, we first calculate 35% of the total number of students, which is 0.35 x 180 = 63.

From the ogive graph, we see that the number of students who scored less than 35% marks is 28.

Therefore, the number of students who passed the examination is 180 - 28 = 152.

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The correct answer is answer choice- A.

Step-by-step explanation:

Answer:

Option A

Step-by-step explanation:

See the attached worksheet. The use of a filled or unfilled circle on a number indicates whether that actual number is included (solid circle) or not included (empty circle)  A solid bar between two points telss us these points are all included.  

 -3<x<3 does not have an equality ("=") for ether +3 nor -3.  The the line between those points would be solid (all points are allowed).  Either 3 would be an empty circle.  

Option A seems to have these features.

The numerical coefficient of  [tex]\frac{2b}{3}[/tex]   is [tex]\frac{2}{3}[/tex] . So here we know how to find numeric coefficient.

A numerical coefficient is defined as a fixed (stable) number that is multiplied to a variable.

When an algebraic expression consists of several (various) parts, each part that is added called a term. The numerical part of a term is called as its numerical coefficient (or coefficient).

Variable, It is a symbol that represents (means) a mathematical object. A variable may represent(mean) a number, a matrix, a function, a vector, the argument of a set, a function, or an element of a set.

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The lateral surface area of the cube shaped Paco is 45.6 square inches.

In a cube, all six faces are identical squares, so there is no distinction between the lateral surface area and the total surface area. The surface area of a cube can be found by adding up the areas of all six faces.

If s represents the length of each edge of the cube, then the surface area S can be calculated using the formula: S = 6s²

So the lateral surface area of a cube with edge length s is simply 6 times the area of one of its faces, which is just the area of a square with side length s.

The Lateral surface area of a cube = 6s²

or we can say that, Lateral surface area = 6×(area of one face of a cube)

Given that the area of one face of a cube shaped Paco is 7.6 square inches.

Lateral surface area = 6×(7.6) = 45.6 square inches

Therefore, the lateral surface area of the cube shaped Paco is 45.6 square inches.

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"To solve this problem, we can use the Law of Cosines. Let's call the distance the pilot travels before the course correction d1 and the distance she travels after the course correction d2. We want to find the distance between her starting position and ending position, which we can call D.

First, let's find d1:

d1 = (720 mph) * (90 min / 60 min) = 1080 miles

Next, let's find d2:

d2 = (720 mph) * (100 min / 60 min) = 1200 miles

Now we can use the Law of Cosines:

D² = d1² + d2² - 2d1d2*cos(20°)

D² = 1080² + 1200² - 210801200*cos(20°)

D ≈ 1169 miles

Therefore, the pilot is approximately 1169 miles from her starting position." (ChatGPT, 2023)

Answer and Step-by-step explanation:

Based on the evidence provided, Gary is most likely to make the conjecture that the store expects high demand for mountain bikes in the spring compared to racing bikes. Another conjecture that could be made is that mountain bikes will most likely sell better than racing bikes. This is because the manager has ordered 50 mountain bikes, which is five times more than the number of racing bikes ordered. This suggests that the store is anticipating greater demand for mountain bikes than for racing bikes in the spring season.

Answer:

B

Step-by-step explanation:

the metal is a conductor

Answer: Find the square root of 60i-11

Step-by-step explanation:

i is imaginary number

you can't find the square root of i because i is an imaginary number unless you put sqrt(i)

The nurse will have to administer 3 milliliters with each dose.

When the prescriber orders medication f 150 mcg po q.12h, the pharmacy sends a bottle labeled:

medication f 0.05 mg/ml.

Milliliters will the nurse administer with each dose :

The conversion factor from mcg to mg is 1/1000.

Therefore, 150 mcg = 150/1000 = 0.15 mg.

The nurse has to administer 0.15 mg of medication f per dose.

The medication f available with the pharmacy is 0.05 mg/ml.

So, the nurse has to administer 0.15 mg in a single dose, which is equal to three times the quantity of medication f available in the bottle (0.05 mg/ml).

Therefore, the nurse has to administer 3 ml (0.05 mg/ml × 3 ml) of medication f with each dose.

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Answer: SA=5183.62788

Step-by-step explanation:

A=2πrh+2πr2=2·π·15·40+2·π·152≈ 5183.62788

~Find the radius- 30 divided by 2= 15 so radius =15

y varies directly as x means

[tex]y=kx[/tex]

y varies inversely with z means

[tex]y=k\div z[/tex]

therefore

[tex]y=(kx^2)\div z[/tex]

k=constant of variation

[tex]6=(k9^2)\div 27[/tex]

[tex]6=(k81)\div27[/tex]

[tex]6=3k[/tex]

divide both sides by 3

[tex]2=k[/tex]

the constant of variation is 2

If the quantity y varies directly with the square of x and inversely with z, then we can write the following equation:

What is equation ?

A assertion that two mathematical expressions are equal is known as an equation. It typically consists of variables, constants, and mathematical operations, and it may also include functions, exponents, and other mathematical symbols. Equations are used to represent relationships between quantities in mathematics and to solve problems in various fields such as physics, engineering, and economics.

y = k * (x^2) / z

where k is the constant of variation.

We are given that when x is 9, z is 27, and y is 6. Substituting these values into the equation, we get:

6 = k * (9^2) / 27

Simplifying, we get:

6 = k * 3

k = 6 / 3

k = 2

Therefore, the constant of variation is 2.
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Answer:

Step-by-step explanation:

Translate: In a classroom of 60 students, 3 exams were taken to pass a course and

He noted that those who passed a single exam were five times those who passed the

3 exams and those who passed only 2 exams is triple those who failed

the 3 exams. If the number of those who failed the 3 exams is equal to the number

Of those who passed the 3 exams, how many passed the course if to pass it is

Do they need to pass at least 2 exams?

The number of students who passed the course is x + 3y, where x is smallest integer greater than or equal to[tex](180 - 3z)/53[/tex], and y = [tex](60 - 7x)/3[/tex] for equal things.

Let's use some variables to represent the number of students who passed each exam:

Let's call the number of students who passed all 3 exams "x".

Let's call the number of students who passed exactly 2 exams "3y" (since it's given that this number is triple the number who failed all 3 exams).

Let's call the number of students who passed exactly 1 exam "5x" (since it's given that this number is five times the number who passed all 3 exams).

Finally, let's call the number of students who failed all 3 exams "x".

We can use this information to set up a system of equations:

x + 3y + 5x + x = 60 (since there are 60 students in total)

x = x (since the number who failed all 3 exams is equal to itself)

Simplify:

7x + 3y = 60

Now we need to use the fact that passing at least 2 exams is required to pass the course. This means we need to find the number of students who passed at least 2 exams, which is the sum of the number who passed all 3 exams and the number who passed exactly 2 exams:

x + 3y

We know that this number needs to be greater than or equal to the number of students who pass the course. So we set up another equation:

x + 3y >= z (where z is the number of students who pass the course)

Now we can solve for x and y in terms of z. We'll start with y:

7x + 3y = 60

3y = 60 - 7x

y = (60 - 7x)/3

Next, we'll use the fact that the number who failed all 3 exams is equal to the number who passed all 3 exams:

x = x

Finally, we'll use this information to solve for x in terms of z:

x + 3y >= z

x + 3((60 - 7x)/3) >= z

x + (60 - 7x) >= 3z

53x >= 180 - 3z

x >= (180 - 3z)/53

Since x represents the number of students who passed all 3 exams, we want to round it up to the nearest integer (since we can't have a fractional number of students). So the final answer is:

The number of students who passed the course is x + 3y, where x is the smallest integer greater than or equal to (180 - 3z)/53, and y is given by y = (60 - 7x)/3.

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The probability of selecting a black checker from a bag of 6 black and 4 red checkers, replacing it, and selecting another black is 9/25.

To find the probability follow these-

Determine the probability of selecting a black checker on the first draw.

There are 6 black checkers and a total of 10 checkers (6 black + 4 red).

So, the probability of selecting a black checker on the first draw is 6/10,

which can be simplified to 3/5.

Since the black checker is replaced, there are still 6 black checkers and

a total of 10 checkers in the bag. Therefore, the probability of selecting a

black checker on the second draw is also 3/5.

To find the probability of both events occurring, multiply the probabilities together: (3/5) × (3/5) = 9/25.

So, the probability of selecting a black checker from a bag of 6 black and

4 red checkers, replacing it, and selecting another black is 9/25.

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Satoko play the most number of times with her tokens is KOF. The correct answer is A.

A line graph is a type of chart that displays data as a series of points connected by a line. Line graphs show the relationship between two variables. The equation of each line can be obtained from the graph given regarding the game played by satoko.

Let us first derive the equation of first line Claw. This line goes from (0,0) to (5,20) so, the equation is y = 4x. The unit price is 4.

Next, the equation of DDR line. This line is from (0,0) to (5, 10). so, the equation is y = 3x. The unit price is 3.

The equation of line KOF goes from (0,0) to ( 5, 10). The equation of line is y = 2x. So, the unit price is 2.

Here, 4 greater than 3, and 3 is greatter than 2. so the correct answer is choice A, KOF.

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Answer: A

Step-by-step explanation:

i just know because i got it right.

[tex]y^(3)z^(2)[/tex] is the greatest common factor for the given set of monomials.

The highest power of each variable that is shared by all of the given monomials must be identified in order to calculate the greatest common factor (GCF) for the given list of monomials. To put it another way, we must first determine the prime factors of each monomial before determining the factors that are shared by all the monomials.

Prime factorization for each monomial:

[tex]x^(3)y^(5)z^(3) = (x * x * x) * (y * y * y * y * y) * (z * z * z)y^(3)z^(3) = (y * y * y) * (z * z * z)xy^(3)z^(2) = (x) * (y * y * y) * (z * z)[/tex]

Factors are common to all monomials are [tex]y^(3), z^(2)[/tex]. The GCF is [tex]y^(3)z^(2)[/tex].

This is appropriate GCF by dividing each monomial by [tex]y^(3)z^(2)[/tex] and verify that result is whole number. For eg:

[tex]x^(3)y^(5)z^(3) / (y^(3)z^(2)) = x^(3)y^(2)zy^(3)z^(3) / (y^(3)z^(2)) = yzxy^(3)z^(2) / (y^(3)z^(2)) = x/y[/tex]

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The allowed housing expense for the year is $38,582.01.

The minimum realized income per month is $1,774.53.

In mathematics, a percentage is a number or ratio that can be expressed as a fraction of 100. If we have to calculate the percent of a number, divide the number by the whole and multiply by 100. Hence, the percentage means, a part per hundred. The word percent means per 100. It is represented by the symbol “%”.

1 ) p = 7.65 + 11.5 + 9 = 28.15 %

$53,698.00 · ( 1 - 0.2815 ) =

= $53,698.00 · 0.7185 = $38,582.01

The allowed housing expense for the year is $38,582.01.

2 ) $1,275.00 : 0.7185 = $1,774.53

The minimum realized income per month is $1,774.53.

The complete question is-

1.) You (or your parents) earn $53,698.00/yr and you have deductions of FICA (7.65%), federal tax withholding (11.5%), and state tax withholding (9%). How much is the allowed housing expense for the year? (1 point)

$ /year

2.) You (or your parents) plan to pay $1,275.00/month for a mortgage. How much is the minimum realized income per month to the nearest penny

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well, 2 and 1/2 is just 2 + 1/2 or just 2.5, so 2.5%.

[tex]~~~~~~ \stackrel{ \textit{\LARGE 8 years} }{\textit{Simple Interest Earned}} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$250\\ r=rate\to 2.5\%\to \frac{2.5}{100}\dotfill &0.025\\ t=years\dotfill &8 \end{cases} \\\\\\ I = (250)(0.025)(8) \implies I = 50[/tex]

how about after 1 year?  well, we simply set t = 1, so (250)(0.025)(1) = 6.25.

would the interest for t = 2 be the same as for t = 1, if t = 2 is calculated, anyhow, the wording is a bit poor, let me reword it.

after the 1st year, she has an accumulated amount of 250 + 6.25 = 256.25.

now, if for the 2nd year we use the same 2.5% rate BUT we use the accumulated amount of $256.25 to get the interest, instead of the initial $250, will they be the same?

well, hell no, because (250)(0.025)(2) using the inital amount

is not the same as (256.25)(0.025)(2).

bear in mind that simple interest is calculated for each year using the initial amount or deposit, not the accumulated amount thus far.

Option (a) is correct Mr. Reynolds walks 2000 feet per minute for 8 minute. Here it is the condition of speed.

Speed is define as the distance covered by a person in a given interval or time. It is generally denotes in Km/h or m/sec.

[tex]Speed\ (S)= Distance\ (d) * Time\ (t)[/tex]

Distance, It is an area cover by a person to complete his journey.

Distance is generally denoted by km, m etc,

Time, It is an interval in which generally person complete it task.

It is generally denoted by hour (h), Minute (min) or Second (Sec).

The correct is (a) Mr. Reynolds walks 2000 feet per minute for 8 minute. Here it is the condition of speed.

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Answer:

1. The perimeter of a parallelogram is the sum of the lengths of all four sides. If two consecutive sides of a parallelogram measure 4 m and 9 m, respectively, then the other two sides must also measure 4 m and 9 m, respectively (since opposite sides of a parallelogram are equal in length). Therefore, the perimeter of the parallelogram is:

Perimeter = 4 m + 9 m + 4 m + 9 m = 26 m

So the perimeter of the parallelogram is 26 meters.

2. In a square, both diagonals are equal in length. If one diagonal measures (2x + 4) in and the other diagonal measures 16 in, then we can write:

2x + 4 = 16

Solving for x, we get:

x = 6

So the value of x is 6 inches.

3. In a trapezoid, the length of the median is equal to the average of the lengths of the two parallel sides. If QR is parallel to TS and mQR = 12 cm, then mTS must also be equal to 12 cm. Let x be the length of the base of the trapezoid.

Then, we have:

mUV = (mQR + mTS)/2

Substituting the given values, we get:

24 cm = (12 cm + 12 cm + x)/2

Simplifying, we get:

24 cm = (24 cm + x)/2

Multiplying both sides by 2, we get:

48 cm = 24 cm + x

Subtracting 24 cm from both sides, we get:

x = 24 cm

So the length of the base of the trapezoid is 24 cm, and the length of the median UV is 24 cm.

(If this isn't right, I'm sorry!)

4. In an isosceles trapezoid, the diagonals are equal in length. If one diagonal measures 42 cm and one leg measures 23 cm, then we can use the Pythagorean theorem to find the length of the other leg:

d^2 = l^2 + (b/2)^2

where d is the length of the diagonal, l is the length of each leg, and b is the length of the base. Substituting the given values, we get:

42^2 = 23^2 + (b/2)^2

Simplifying, we get:

b^2/4 = 42^2 - 23^2

b^2/4 = 1253

Multiplying both sides by 4, we get:

b^2 = 5012

Taking the square root of both sides, we get:

b = sqrt(5012) ≈ 70.77

So the length of the other diagonal is also 42 cm.

5. The area of a kite is equal to half the product of the lengths of its diagonals. If mHP = 10 cm and mOE = 18 cm, then we can write:

Area = (mHP x mOE)/2

Substituting the given values, we get:

Area = (10 cm x 18 cm)/2 = 90 cm^2

So the area of the kite is 90 square centimeters.

I hope this helps! I'm sorry if this was wrong. If you need more help, ask me! :]

Answer:

Step-by-step explanation:

To have the product of three integers be negative, we must have an odd number of negative integers. This is because when two negative integers are multiplied, the result is positive, and when an odd number of negative integers are multiplied, the result is negative. Therefore, we need at least one negative integer to produce a negative product, and then either one or three negative integers depending on whether the other two integers are positive or negative.

Here are two groups of three integers whose product is negative:

Group 1: {-1, 2, 3}

Product = (-1) x 2 x 3 = -6

In this group, there is one negative integer and two positive integers, which gives us an odd number of negative integers and a negative product.

Group 2: {-2, -3, 4}

Product = (-2) x (-3) x 4 = 24

In this group, there are two negative integers and one positive integer, which gives us an even number of negative integers and a positive product.

Note that there are infinitely many groups of three integers that can produce a negative product, as long as there is an odd number of negative integers in the group.