Mickey is classifying a quadrilateral with vertices at Q1,1, U(-1,-3), A(1,-4), D(3,0). What type of quadrilateral is it? Also why?
Please Help!

Answer: 11 in the 5th picture

Step-by-step explanation:

or if you add 5 more then it would be 17

add 2

Based on the information, the only prediction that is justified is that the speed of the fish will be greater than 40 mph, and the speed of the mammal will be less than 50 mph.

Therefore option B  is  correct.

Based on the given information above, we were able to deduct that about 75% of the fish were faster than 40 mph and about 75% of the mammals were slower than 50 mph.

We can go ahead and use this information to make predictions about the speeds of one additional fish and one additional mammal.

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In response to the stated question, we can state that As a result, there coordinates are 7 units between the points (1, 0) and (8, 0).

When locating points or other geometrical objects precisely on a manifold, such as Euclidean space, a coordinate system is a technique that uses one or more integers or coordinates. Locating a point or item on a two-dimensional plane requires the use of coordinates, which are pairs of integers. Two numbers called the x and y coordinates are used to describe a point's location on a 2D plane. a collection of integers that indicate exact locations. The figure often has two numbers. The first number denotes the front-to-back measurement, while the second number denotes the top-to-bottom measurement. For example, in (12.5), there are 12 units below and 5 above.

The distance formula can be used to determine the separation between two points in a two-dimensional Cartesian coordinate system:

[tex]\sqrt[(x2 - x1)2 + (y2 - y1)2] = d[/tex]

and d .

As both of the points in this instance have y-coordinates of 0, we may condense the expression to:

[tex]d = \sqrt[(8 - 1)^² + (0 - 0)^²]\\d = \sqrt[(7)^² + (0)^²]\\d = \sqrt[49]\\ d= 7[/tex]

As a result, there are 7 units between the points (1, 0) and (8, 0).

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The solution set of the given system of linear equations can be expressed as a line in R^3 vector as r = (6, -2) + x_3(3, -5).

To express the solution set of the given system of linear equations as a line in R^3, we first need to express the solution set as a vector equation. We can do this by expressing the equations in terms of x_3 as follows:

x_1 = 6 + 3x_3,

x_2 = -2 - 5x_3

Therefore, the solution set of the given system of linear equations can be expressed as a line in R^3 as follows:

r = (6, -2) + x_3(3, -5).

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Each piece of the rope is 247.76 meters long, approximately.

To find the length of each piece, we need to divide the total length of the rope by the number of pieces it is cut into:

Length of each piece = Total length of the rope / Number of pieces

Length of each piece = 4212 meters / 17

Length of each piece = 247.76 meters (rounded to two decimal places)

The method used to find the length of each piece of rope is division. We divided the total length of the rope by the number of pieces it was cut into, which gives us the length of each piece. This method is based on the fact that the length of each piece is the same, so we can divide the total length equally among the pieces.

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Answer:

40Km

Step-by-step explanation:

Total Distance of Journey  = 140KM

5/7 of the journey:
[tex]\frac{5}{7 } * 140 = 100km[/tex]

Distance travelled before stopping: Total Distance - 5/7 of Total Distance

= 140 - 100KM = 40KM

Claude will use 1197 square centimeters of labeling material to cover the lateral surface of 5 cylindrical bug spray cans.

A three-dimensional object's lateral surface area is its total surface area minus its top and bottom surfaces. The lateral surface area of a cylinder, for instance, would be the area of the curved side of the cylinder. In geometry and engineering, the lateral surface area is frequently used to determine how much material is required to cover or build an object's sides. Depending on the geometry of the item, many formulae may be used to compute the lateral surface area, which is often expressed in square units (such as square centimetres or square feet).

Given the dimensions of the cylindrical can we have the lateral surface area of cylinder as:

Lateral surface area = 2πrh

Substituting the value r = 3 and h = 12.7 we have:

Lateral surface area = 2π(3)(12.7) = 239.4 square centimeters

A total of 5 cans need to be covered thus,

Total labeling material = 5 x 239.4 = 1197 square centimeters

Hence, Claude will use 1197 square centimeters of labeling material to cover the lateral surface of 5 bug spray cans.

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By evaluating and simplifying f(x)=3x2 +3x+8, we get  f(x + h) = 3x² + 6xh + 3h² + 3x + 3h + 8 and  (f(x + h) - f(x))/h = 6x + 3h + 3.

Given function is, f(x) = 3x² + 3x + 8

Evaluate f(x + h)

Expanding f(x + h) => f(x) + hf′(x) + h²/2f″(x)

Applying formulae in the given function f(x + h) = 3(x + h)² + 3(x + h) + 8=> 3x² + 6xh + 3h² + 3x + 3h + 8Now, f(x + h) = 3x² + 6xh + 3h² + 3x + 3h + 8

Evaluate (f(x + h) - f(x))/h

Expanding both the terms f(x + h) and f(x) and simplifying, (f(x + h) - f(x))/h = [3x² + 6xh + 3h² + 3x + 3h + 8 - (3x² + 3x + 8)]/h=> [3x² + 6xh + 3h² + 3x + 3h + 8 - 3x² - 3x - 8]/h=> [6xh + 3h² + 3h]/h=> 6x + 3h + 3

Therefore, the required value is f(x + h) = 3x² + 6xh + 3h² + 3x + 3h + 8and (f(x + h) - f(x))/h = 6x + 3h + 3.

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[tex]\qquad \qquad \textit{combined proportional variation} \\\\ \begin{array}{llll} \textit{\underline{y} varies directly with \underline{x}}\\ \textit{and inversely with }\underline{z^5} \end{array} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}x}{z^5}~\hfill } \\\\[-0.35em] ~\dotfill[/tex]

[tex]\begin{array}{llll} \textit{"y" varies}\\ \textit{directly with "x"}\\ \textit{inversely with "z"} \end{array}\qquad y=\cfrac{kx}{z}\hspace{5em}\textit{we also know that} \begin{cases} x=10\\ z=4\\ y=15 \end{cases} \\\\\\ 15=\cfrac{k(10)}{4}\implies \cfrac{4}{10}\cdot 15=k\implies 6=k\hspace{8em}\boxed{y=\cfrac{6x}{z}} \\\\\\ \textit{when x = 20 and z = 6, what's "y"?}\qquad y=\cfrac{6(20)}{6}\implies y=20[/tex]

Answer:

I think is 500 hope it helps

If locked out of an account due to forgotten password and invalid email, try password recovery options or contact customer support, or create a new account.

If you've been locked out of your account. If you've forgotten your password and the email you used to sign up is not valid, it can be difficult to regain access to your account. Few steps you can try to recover your account:

It's important to note that in some cases, it may not be possible to regain access to your account. Always be cautious about the information you provide when signing up for online services and make sure to keep your login credentials in a safe and secure location.

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Answer:

2

Step-by-step explanation:

John had 10 and he gave Janet 8, which means that he remained with 2

The ordered pairs from the table are (22, 152), (28, 94), (35, 134), and (46, 110). Plotting them on a coordinate plane would produce a scatterplot.

The form of the scatterplot is a line of negative slope that is decreasing from left to right. The direction of the scatterplot is downward.

The relationship between the average price of jeans and number of jeans sold appears to be negative, which means that as the average price of jeans increases, the number of jeans sold decreases. In other words, there is an inverse relationship between the price and quantity demanded of jeans. This relationship is consistent with the law of demand in economics, which states that as the price of a good or service increases, the quantity demanded of that good or service will decrease, ceteris paribus (all else being equal).

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Answer:

Binomial

Step-by-step explanation:

A binomial is a polynomial expression which contains exactly two terms. A binomial can be considered as a sum or difference between two or more monomials.

Answer:

Step-by-step explanation:

we should do multiplications first:

1)

[tex]1)12a^{2}*3ba=12a^{3}b\\2)2ab*3ab^{2}=6a^{2}b^{3}\\3)11aba=11a^{2}b\\4)12a^{3}b+6a^{2}b^{3}+11a^{2}b=a^{2}b(12a+6ab^{2}+11)[/tex]

2)

[tex]1)1.5xy^{2}*(-4)xyz=-6x^{2}y^{3}z\\2)-4mnk*5m^{2}n^{3}k=-20m^{3}n^{4}k^{2}\\3)-6x^{2}y^{3}z-20m^{3}n^{4}k^{2}[/tex]

Answer:

The answer to your problem is, Area = 104.1 square feet.

Step-by-step explanation:

Area of semicircle = 1/2 the area of a circle:

[tex]A_{sc} = \frac{1}{2} tt r^{2}[/tex]

Radius is half the diameter of 6ft.

[tex]A_{sc} = \frac{1}{2} tt ( 3^{2} ) = 14.13ft^{2}[/tex]

Area of the rectangle:

[tex]A_{r} = lw = 15 * 6 = 90ft^{2}[/tex]

Add them:

[tex]90 + 14.13 = 104.13[/tex]

Round to the nearest tenth (one decimal place)

Which is 104.1

Thus the answer to your problem is 104.1 of 104.13

Answer:

  996,250,626,076

Step-by-step explanation:

You want the value of the numerical expression 251^5+8-(9×20+3).

Your calculator will evaluate this properly if you enter it as shown. See the attachment.

If you're doing this in parts, the Order of Operations tells you to start with the parentheses, then do the exponentiation.

  251^5 +8 -(9·20 +3)

  = 251^5 +8 -183

  = 996,250,626,251 +8 -183 = 996,250,626,076

__

Additional comment

You can use a spreadsheet (or an on-line calculator) if your calculator only displays 10 digits.

Tom and Gwen have an adjusted annual gross income of $111,480. Their front end ratio, which measures how much of their income is dedicated to housing costs, is 5.19%. Their back end ratio, which measures how much of their income is dedicated to all debt obligations, is 11.72%.

The front end ratio is a measure of how much of an individual’s gross income is dedicated to housing costs. It is calculated by taking the total housing costs, which includes mortgage payments, property taxes, and homeowners insurance premiums, and dividing it by the annual gross income. For Tom and Gwen, this would be:

Front End Ratio = (Mortgage Payment + Property Taxes + Homeowner’s Insurance Premium) / Annual Gross Income

Front End Ratio = (1,725 + 3,660 + 685) / 111,480

Front End Ratio = 5.19%

The back end ratio is a measure of how much of an individual’s gross income is dedicated to all debt obligations, including housing costs and other debts. It is calculated by taking all debt obligations, which includes mortgage payments, property taxes, homeowner’s insurance premiums, car payments, and credit card payments, and dividing it by the annual gross income. For Tom and Gwen, this would be:

Back End Ratio = (Mortgage Payment + Property Taxes + Homeowner’s Insurance Premium + Car Payment + Credit Card Payment) / Annual Gross Income

Back End Ratio = (1,725 + 3,660 + 685 + 154 + 2,021) / 111,480

Back End Ratio = 11.72%

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Answer:

3069 windows on the side of the apartment building if it has 10 columns.

Step-by-step explanation:

We can notice that the number of windows in each column is double the number of windows in the previous column. So, we can write down the number of windows in each column as a sequence of powers of 2:

3, 6, 12, 24, 48, 96, 192, 384, 768, 1536

We can see that this is a geometric sequence with a common ratio of 2. We can use the formula for the sum of a geometric sequence to find the total number of windows:

Sn = a(1 - r^n)/(1 - r)

where

a = 3 (the first term)

r = 2 (the common ratio)

n = 10 (the number of terms we want to sum)

Substituting these values into the formula, we get:

Sn = 3(1 - 2^10)/(1 - 2)

= 3(1 - 1024)/(-1)

= 3(1023)

= 3069

Therefore, there are 3069 windows on the side of the apartment building if it has 10 columns.

Gloria traveled a distance of 7.5 miles on the bus.

The process of translating a measurement from one unit to another is known as unit conversion. Since multiple units are frequently used to measure the same quantity and because unit conversion is required to carry out calculations and solve issues, it is significant in problem solving. Moreover, unit conversion is crucial since it enables us to compare measurements and present them in a uniform manner. For instance, measurements in science and engineering are frequently stated in SI units.

Given that, Gloria traveled a total of 8 miles.

8 x 1760 = 14080 yards.

The distance walked is 880 yards.

So the distance she traveled on the bus is:

14080 - 880 = 13200 yards

13200 / 1760 = 7.5 miles

Hence, Gloria traveled 7.5 miles on the bus.

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The complete question is:

The probability of picking a medal won by Sam in the years 2009 or 2012 is 5/6.

The probability of picking a medal won by Sam in the years 2009 or 2012 can be calculated using the formula P(A∪B) = P(A) + P(B) - P(A∩B). In this case, P(A) equals the probability of picking a medal won by Sam in 2009, which is 1/3, and P(B) equals the probability of picking a medal won by Sam in 2012, which is 1/2. P(A∩B) would be the probability of picking a medal won by Sam in both years, which is 0, since he did not win a medal in both years. Therefore, the probability of picking a medal won by Sam in the years 2009 or 2012 is P(A∪B) = P(A) + P(B) - P(A∩B) = 1/3 + 1/2 - 0 = 5/6.

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Accοrding tο given cοnditiοns, 250 hamburgers were sοld οn Tuesday.

Algebra is a branch οf mathematics that deals with symbοls and the rules fοr manipulating thοse symbοls. It invοlves sοlving equatiοns and manipulating variables tο find unknοwn values.

Let's use algebra tο sοlve the prοblem.

Let x be the number οf hamburgers sοld.

Then the number οf cheeseburgers sοld is x - 59.

The tοtal number οf hamburgers and cheeseburgers sοld is 441, sο we can write an equatiοn:

x + (x - 59) = 441

Simplifying the left side, we get:

2x - 59 = 441

Adding 59 tο bοth sides, we get:

2x = 500

Dividing by 2, we get:

x = 250

Therefοre, accοrding tο given cοnditiοns, 250 hamburgers were sοld οn Tuesday.

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The work required to move q from the other vertex to the center of the line joining the fixed charges is (1/4π ε0) x 2 x q 2/a.

To solve this problem, we can use the principle of superposition to calculate the potential at the center of the equilateral triangle due to each of the two fixed charges, and then add them up to get the total potential.

Let's first find the potential due to one of the fixed charges at the center of the triangle. We can use the formula for the electric potential due to a point charge q at a distance r from it, which is given by:

V = k x q/r

In this case, the distance from one of the fixed charges to the center of the triangle is: r = a/2

So the potential due to one fixed charge at the center of the triangle is:

V1 = kq/r = kq/(a/2)

Next, let's find the potential due to the other fixed charge at the center of the triangle. Since the triangle is equilateral, the distance from the other fixed charge to the center of the triangle is also a/2. So the potential due to the other fixed charge at the center of the triangle is:

V2 = k x q/(a/2)

Now, the total potential at the center of the triangle due to the two fixed charges is simply the sum of the individual potentials:

V_total = V1 + V2 = kq/(a/2) + kq/(a/2) = 2kq/a

The work required to move a charge q from infinity to the center of the triangle is equal to the change in potential energy of the charge, which is given by:

W = q x (V_final - V_initial)

In this case, the initial potential is zero (since the charge is at infinity), and the final potential is 2kq/a (which we just calculated). So the work required is:

W = q x (2kq/a - 0) = 2kq 2/a

Substituting the given value of k, we get:

W = (1/4π ε0) x 2 x q2/a

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Translate: Knowing that sen alpha = 0. 6 and that a is an acute angle, calculates the rest of trigonometric ratios

Rest of the trigonometric ratios for the acute angle alpha are cos(alpha) = 0.8 and tan(alpha) = 0.75.

If we know that sin(alpha) = 0.6, we can use the Pythagorean identity to find cos(alpha) and tan(alpha). Here's how:

Since sin(alpha) = opposite/hypotenuse, we can represent sin(alpha) as the ratio of the length of the side opposite the acute angle alpha to the length of the hypotenuse of the right triangle. Let's assume that the length of the opposite side is a and the length of the hypotenuse is h. Then we have:

sin(alpha) = a/h = 0.6

Solving for a, we get:

a = 0.6h

Using the Pythagorean theorem:

[tex]a^2 + b^2 = h^2[/tex]

Since a and h are related by a = 0.6h, put 0.6h for a to get:

[tex](0.6h)^2 + b^2 = h^2[/tex]

Simplifying:

[tex]0.36h^2 + b^2 = h^2[/tex]

[tex]b^2 = h^2 - 0.36h^2 = 0.64h^2[/tex]

[tex]b = \sqrt{0.64h^2} = 0.8h[/tex]

So now we know that b = 0.8h and a = 0.6h. Using these values, we can find cos(alpha) and tan(alpha) as follows:

[tex]cos(alpha) = adjacent/hypotenuse = b/h = 0.8h/h = 0.8tan(alpha) = opposite/adjacent = a/b = 0.6h/0.8h = 0.75[/tex]

Therefore, the rest of the trigonometric ratios for the acute angle alpha are cos(alpha) = 0.8 and tan(alpha) = 0.75.

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Answer:15

Step-by-step explanation:

Dividing by a fraction is equivalent to multiplying by its reciprocal. Therefore, 6 divided by 2/5 is the same as multiplying 6 by 5/2, which equals 15.

The expression 6 divided by 2/5 is equivalent to 6 multiplied by 5/2. This is because dividing by a fraction is the same as multiplying by its reciprocal. The reciprocal of 2/5 is 5/2. Therefore, 6 divided by 2/5 is the same as 6 multiplied by 5/2, which gives you the result 15.

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The position of a car driving along a straight road at time t in minutes is given by the function y = f(t).

The function y represents the position of the car in thousands of feet, while the variable t represents the time in minutes.

To find the position of the car at any given time, you simply need to plug in the value of t into the function and solve for y. For example, if you wanted to find the position of the car at 2 minutes, you would plug in 2 for t and solve for y:

y = f(2)

Once you have solved for y, you will have the position of the car in thousands of feet at 2 minutes. You can repeat this process for any value of t to find the position of the car at any given time.

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The values of x make the quadratic equation (x-2)² =2 is 2 + √2.

To find the values of x that make the quadratic equation (x-2)² = 2 true, we need to solve for x.

First, we can take the square root of both sides of the equation:

x - 2 = ±√2

Next, we can add 2 to both sides of the equation:

x = 2 ± √2

Therefore, the two solutions for x are:

x = 2 + √2

x = 2 - √2

These are the two values of x that make the quadratic equation (x-2)^2 = 2 true.

To check these solutions, we can substitute each value back into the original equation:

[(2 + √2) - 2]² = 2

Simplifying:

√2² = 2

2 = 2

This solution works. Now let's check the other solution:

[(2 - √2) - 2]² = 2

Simplifying:

-√2² = 2

-2 = 2

This solution does not work, so we discard it. Therefore, the only value of x that makes the quadratic equation (x-2)² = 2 true is: x = 2 + √2.

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The nearest whole number, the maximum value of S is equivalent to approximately 323 m², which is the area of the lawn.

We are given that the perimeter of the lawn is 90 m. Therefore, we can write:

2y + 4x + 2πx = 90

where π is the constant pi. Simplifying this equation gives:

y = 22.5 - 2x - πx

The area of the lawn is given by:

S = y(2x) + πx²

Substituting y in terms of x gives:

S = (22.5 - 2x - πx)(2x) + πx²

Simplifying this expression gives:

S = 45x - 2πx² - 4x²

We are asked to find the maximum value of S. To do this, we can differentiate S with respect to x and set the derivative equal to zero:

dS/dx

= 45 - 4πx - 8x = 0

Solving for x gives:

x = (45 - 4π)/8

Substituting this value of x into the expression for S gives:

S ≈ 323 m²

Rounding this value to the nearest whole number gives:

S ≈ 323 m².

Therefore, the maximum value of S is approximately 323 m².

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Complete question is:

Figure 2 shows the lawn ABCDEF, where ABDE is a rectangle of length y meters and width 2x meters. (Refer the image)

Each end of the lawn is a semi-circle of radius x meters.

The lawn has perimeter 90 m and area S m ²

dS/ dx= 90 - 2

Given S = 90x-x², then

The value x = 14. 32 gives a maximum value of S

Find, to the nearest whole number, the maximum value of S

2 kilometers per hour

The value of x from the given expression (3^1/2 ) ( 3^1/2 ) = 3^6 can be expressed as 6.

A formula that expresses the connection between two expressions on each side of a sign. Typically, it has a single variable and an equal sign. Like this: 2x - 4 Equals 2. In the above example, the variable x exists.

Given that (3^1/2 ) ( 3^1/2 ) = 3^6

then 3^(x/2+ x/2) = 3 ^6

x/2+ x/2 = 6

Then the lcm , we have

x+x/2 = 6

2x/2 = 6

2x = 12

x = 12/2 = 6

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