model and solve. 3/5 ÷ 1/2 =
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Solution:
Consider the following diagram
extremes and means are multiplied in the diagram. Then we have that:
[tex]\frac{\frac{3}{5}}{\frac{1}{2}}\text{ = }\frac{3\text{ x 2}}{5\text{ x1}}\text{ = }\frac{6}{5}\text{ = 1.2}[/tex]and this number is represented on the real line as follows:
Related Questions
Given the equations and the table below, what is the first x-value when the y-value of equation 2 is greater than the y-value of equation 1 after the functions first intersect?Equation 1: f(x)=5x^3Equation 2: f(x)=2x+3
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the first x value, when the y-value of the equation is greater than the y value of equation one, is x=15
Because the y-value of equation 2 with x=15 is 32771, while the y-value of equation 1 is 16875
Compare A and B in three ways, where A = 51527 is the number of deaths due to a deadly disease in the United States in 2005 and B = 17241 is the number of deaths due to the same disease in the United States in 2009. a. Find the ratio of A to B. b. Find the ratio of B to A. c. Complete the sentence: A is ____ percent of B.
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ANSWER
Ratio of A to B = 2.99 (to 2 decimal places)
Ratio of B to A = 0.33 (to 2 decimal places)
A is 299% of B (to nearest integer)
STEP BY STEP EXPLANATION
for ratio of A to B:
[tex]\begin{gathered} \frac{A}{B}\text{ = }\frac{51527}{17241}\text{ = }2.98863 \\ \text{ = 2.99 (to 2 decimal places)} \end{gathered}[/tex]for ratio of B to A:
[tex]\begin{gathered} \frac{B}{A}\text{ = }\frac{17241}{51527}\text{ = 0.33460 } \\ \text{ = 0.33 (to 2 decimal places)} \end{gathered}[/tex]A is x % of B:
[tex]\begin{gathered} A\text{ = }\frac{x}{100}\times B \\ x\text{ = }\frac{100\text{ }\times A}{B} \\ x\text{ = }\frac{100\text{ }\times\text{ 51527}}{17241}\text{ = 298.86} \\ x\text{ = 299\% (to nearest integer)} \end{gathered}[/tex]Hence, the ratio of A to B = 2.99 (to 2 decimal places), B to A = 0.33 (to 2 decimal places) and A is 299% of B (to nearest integer).
Complete a triangulation calculation to measure the distance between actual objects in or near your home. include a well-labeled diagram.
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Triangulation means the measuring of distances in surveys with triangles. If the distance of two objects and the angle between is knwon, the distance between these objects can be calculated.
Given the diagram we have:
So, the distance between both objects will be calculated by:
[tex]c=\sqrt{a^2+b^2-2ab\cdot\cos\theta}[/tex]Where:
Distance to the first object a = 6
Distance to the first object b = 6
Angle between both objects θ = 60°
Substitute the values, we have:
[tex]c=\sqrt{6^2+6^2-2(6)(6)\cdot\cos60}[/tex]Simplify:
[tex]c=\sqrt{36+36-72(0.5)}=\sqrt{72-36}=\sqrt{36}=6[/tex]So, the distance between both objects c = 6 inches
The graph of which function has a minimum located at (4,-3)
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We need to obtain the first derivate
[tex]\begin{gathered} f\mleft(x\mright)=-\frac{1}{2}x^2+4x-11 \\ f^{\prime}(x)=-x+4 \end{gathered}[/tex][tex]\begin{gathered} f\mleft(x\mright)=-2x^2+16x-35 \\ f^{\prime}(x)=-4x+16 \end{gathered}[/tex][tex]\begin{gathered} \: f\mleft(x\mright)=\frac{1}{2}x^2-4x+5 \\ f^{\prime}(x)=x^{}-4 \end{gathered}[/tex][tex]\begin{gathered} f(x)=2x^2-16x+5 \\ f^{\prime}(x)=4x-16 \end{gathered}[/tex]Answer: B on edge23
Step-by-step explanation:
f(x) = 1/2^x2–4x + 5
Three commercials are played in a row between songs on the radio. The three commercials fill exactly 3 minutes of time. If the first commercial uses 1 – minutes, and the second uses 3 minute, how long is the third commercial? The third commercial is minutes long.
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3 commercials
3 minutes
3 = 1st commercial + 2nd commercial + 3rd commercial
3 = 1 1/5 + 3/4 + 3rd commercial
3rd commercial = 3 - 6/5 - 3/4
= 60/20 - 24/20 - 15/20
= 21/20
The third commercial last = 21/20 or 1 1/20.
What is 44 over 13 rounded to the nearest 10 tenths
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we have that
44/13=3.38
rounded to the nearest tenths
3.38=3.4
the answer is 3.4under normal conditions, 1.5 feet of snow will melt into 2 inches of water. after a recent snowstorm, there were 4 feet if snow. how many inches of water will there be when the snow MELTS? express your answer as a fraction reduced to lowest terms or decimal rounded correctly to two decimals places. Do not include units with this answer.
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If 1.5 feet of snow melts into 2 inches of water, this implies that:
[tex]undefined[/tex]Please Help!!!!! NOT FOR QUIZ!!!!!!!!
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The graph of the line y [tex]=[/tex] -3x + 4 is a line that shows the set of all solutions to the equation , the correct option is (c) .
In the question ,
it is given that
the equation of the line is y [tex]=[/tex] -3x + 4 ,
we have to plot the line in the coordinate plane .
we plot the line ,w e need at least two points .
for the first point ,
for x = 0 , we have
y = -3(0) + 4
y= 0 + 4
y = 4
the first point is (0,4)
for the second point
for y = 0 , we have
0 = -3x + 4
-3x = -4
x = 4/3
the second point is (4/3 , 0)
so , from the graph plotted below , we can see that the line y [tex]=[/tex] -3x+4 shows the set of all solutions to the equations .
Therefore , The graph of the line y [tex]=[/tex] -3x + 4 is a line that shows the set of all solutions to the equation .
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x+3y=6 2x+6y=-18 solve
Answers
The system of equation x + 3y = 6 and 2x + 6y = -18 has no solution.
What is the solution to the given system of equation?Given the system of equation in the question;
x + 3y = 6
2x + 6y = -18
To find the solution to the system of equation, first solve for x in the first equation.
x + 3y = 6
Subtract 3y from both sides
x + 3y - 3y = 6 - 3y
x = 6 - 3y
Now, replace all occurrence of x in the second equation with 6 - 3y and solve for y
2x + 6y = -18
2( 6 - 3y ) + 6y = -18
Apply distributive property to remove the parenthesis
12 - 6y + 6y = -18
-6y and +6y cancels out
12 = -18
Since 12 equal -18 is not true, there is no solution to the system of equation.
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Solve the system you any method. State the final answer as an ordered pair. DO NOT include spaces or dollar signs in your answer.
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To solve the problem, we notice that both of the equations are written with the y solved then we can equate the expressions of x and solve the resulting equation of x:
[tex]\begin{gathered} x-12=-3x+12 \\ x+3x=12+12 \\ 4x=24 \\ x=\frac{24}{4} \\ x=6 \end{gathered}[/tex]Once we have the value of x we plug it on the first equation to find y:
[tex]\begin{gathered} y=6-12 \\ y=-6 \end{gathered}[/tex]Therefore, the solution of the system of equations is (6,-6)
determine whether the equation is linear to x. 5-3x=0
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By definition a linear equation is an equation in which the highest power of any variable in the equation is always 1. In this case we have the equation:
[tex]5-3x=0[/tex]We notice that this equation only has one variable, x, and that its power is 1. Therefore, the equation is linear.
Julie is 6 feet tall if she stands 15 feet from the flagpole and holds a cardboard square the edges of the square light up with the top and bottom of the flagpole approximate the height of the flagpole
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Using tangent function:
[tex]\begin{gathered} \tan (\theta)=\frac{opposite}{adjacent} \\ \frac{6}{15}=\frac{15}{x-6} \\ solve_{\text{ }}for_{\text{ }}x\colon \\ 6(x-6)=15^2 \\ 6x-36=225 \\ 6x=225+36 \\ 6x=261 \\ x=\frac{261}{6} \\ x=43.5ft \end{gathered}[/tex]Solve for x: 4 open parentheses 2 x minus 1 close parentheses plus 8 minus 14 x equals negative 8 x plus 4 plus 2 x The solution is X = _________
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Answer:
x = 1
Step-by-step explanation:
4(2x-1)+8-14= -8x+ 4+ 2x
Consider the following expression:-27 x (-18)By the laws of signs, this is equivalent to27 x 18 this is equivalent to:27 x 18= 486we can conclude thatthe correct answer is:486I feel like that’s wrong, it’s not algebra can anyone help
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The answer is actually CORRECT.
The correct procedure is when two negatives multiply each other, the answer is always a positive.
Therefore;
[tex]\begin{gathered} -27\times(-18)=27\times18 \\ 27\times18=486 \end{gathered}[/tex]We can conclude that the correct answer is 486
The revenue for a small company is given by the quadratic function r(t) = 5tsquared + 5t + 630 where t is the number of years since 1988 and r(t) is in thousands of dollars. If this trend continues, find the year after 1998 in which the company’s revenue will be $730 thousand. Round to the nearest whole year.
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for:
[tex]\begin{gathered} r(t)=730 \\ 5t^2+5t+630=730 \\ so\colon \\ 5t^2+5t-100=0 \end{gathered}[/tex]Divide both sides by 5:
[tex]t^2+t-20=0[/tex]Factor:
The factors of -20 which sum to 1, are -4 and 5 so:
[tex](t-4)(t+5)=0[/tex]So:
[tex]\begin{gathered} t=4 \\ or \\ t=-5 \end{gathered}[/tex]Since a negative year wouldn't make any sense:
[tex]t=4[/tex]Therefore, the company revenue will be $730 for the year:
[tex]1998+t=1998+4=2002[/tex]Answer:
2002
A factory makes car batteries. The probability that a battery is defective is1/6 If 400 batteries are tested, about how many are expected to be defective?A. 40 B. 25C. 16D. 375
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Since there are 400 batteries are tested
Since the probability of the defective batteries is 1/6
The number of defective batteries =
[tex]\frac{1}{16}\times400=25[/tex]The answer is B
Need help asap !!!!!
Answers
The practical domain is 1 ≤ x ≤ 20 and the practical range is 13.61 ≤ C(x) ≤ 127.61
How to determine the practical domain?From the question, the given parameters are:
Charges = $7.61Reservation = $6Maximum number of windows = 20Total cost = CThe domain is dependent on the number of windows washed
Using the maximum as a guide, the minimum number of windows could be
Minimum = 1
The domain is then represented as
Minimum ≤ x ≤ Maximum
So, we have
1 ≤ x ≤ 20
How to determine the practical range?Using the given parameters in (a), we have
Total cost, C = Charges * Number of windows + Reservation
So, we have
C(x) = 7.61 + 6x
Where x is the number of windows
When x = 0, we have
C(1) = 7.61 + 6(1)
C(1) = 13.61
When x = 20, we have
C(20) = 7.61 + 6(20)
C(20) = 127.61
So, we have the range to be 13.61 ≤ C(x) ≤ 127.61
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Suppose that $16,065 is invested at an interest rate of 6.6% per year, compounded continuously. a) Find the exponential function that describes the amount in the account after time t, in years. b) What is the balance after 1 year? 2 years?5 years? 10 years? c) What is the doubling time?
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Okay, here we have this:
Considering the provided information we obtain the following:
a)
Replacing in the Compound Interest formula we obtain the following:
[tex]\begin{gathered} A(t)=Pe^{rt} \\ A(t)=16065e^{0.066t} \end{gathered}[/tex]b)
After 1 year (t=1):
[tex]\begin{gathered} A(1)=16065e^{0.066(1)} \\ A(1)\approx17,161.06 \end{gathered}[/tex]We obtain that after one year the balance is aproximately $17,161.06.
After 2 years (t=2):
[tex]\begin{gathered} A(2)=16065e^{0.066(2)} \\ A(2)=18331.90 \end{gathered}[/tex]We obtain that after two years the balance is aproximately $18,331.90
After 5 years (t=5):
[tex]\begin{gathered} A(5)=16065e^{0.066(5)} \\ A(5)=$22,345.90$ \end{gathered}[/tex]We obtain that after five years the balance is aproximately $22,345.90.
After 10 years (t=10):
[tex]\begin{gathered} A(10)=16065e^{0.066(10)} \\ A(10)=$31,082.44$ \end{gathered}[/tex]We obtain that after ten years the balance is aproximately $31,082.44.
c)
In this case the doubling time will be when she has double what she initially had, that is: $16,065*2=$32130, replacing in the formula:
[tex]32130=16065e^{0.066t}[/tex]Let's solve for t:
[tex]\begin{gathered} 32130=16065e^{0.066t} \\ 16065e^{\mleft\{0.066t\mright\}}=32130 \\ \frac{16065e^{0.066t}}{16065}=\frac{32130}{16065} \\ e^{\mleft\{0.066t\mright\}}=2 \\ 0.066t=\ln \mleft(2\mright) \\ t=\frac{\ln\left(2\right)}{0.066} \\ t\approx10.502years \end{gathered}[/tex]Finally we obtain that the doubling time is approximately 10.502 years or about 10 years 6 months.
May I please get help with this math problem. I am so lost and confused
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We are given three angles and we are asked to determine if the angles are the angles of a triangle. To do that we need to have into account that the measure of the angles of a triangle always adds up to 180, therefore, if we add up the angles and the result is 180, then these angles can be angles measures of a triangle. If the result is different from 180 the angles can't be the angle measures of a triangle. Taking the first set of three angles we get:
[tex]58+34+42=134[/tex]Since the result is different from 180 then these angles can't be the angle measure of a triangle.
The same procedure is used to determine the other sets of angles.
How many offices are between 41 and 50 meters ?
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Solution
For this case we want to find the number of offices between 41 and 50 m and the answer is:
2 meters
A package of 5 pairs of insulated socks costs 27.95$. What is the unit price of the pairs of ?
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Answer:
$5.59
Step-by-step explanation:
You want the unit price of a pair of socks, given that 5 pairs cost $27.95.
Unit priceThe unit price is found by dividing the price by the number of units.
$27.95/5 = $5.59
The unit price of a pair of socks is $5.59.
express the fuction graphed on the axes below as a piecewise function
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Concept
Find the equation of line for the second line.
x1 = -2 y1 = 1
x2 = -4 y2 = 2
Next, apply equation of a line formula
[tex]\begin{gathered} \frac{y-y_1}{x-x_1\text{ }}\text{ = }\frac{y_2-y_1}{x_2-x_1} \\ \frac{y\text{ - 1}}{x\text{ + 2}}\text{ = }\frac{2\text{ - 1}}{-4\text{ + 2}} \\ \frac{y\text{ - 1}}{x\text{ + 2}}\text{ = }\frac{1}{-2} \\ -2(y\text{ - 1) = 1(x + 2)} \\ -2y\text{ + 2 = x + 2} \\ -2y\text{ = x} \\ y\text{ = }\frac{-1}{2}x \end{gathered}[/tex]Final answer
The graphed as a piecewise function is given below
Triangle ABC lies on the coordinate plane with vertices located at A(7,6), B(-3,5), and C(-4,9). The triangle is transformed using the rule (x,y) -> (2x,y-3) to create triangle A'B'C'. Select all possible answers for the vertices of triangle A'B'C'. Question 1 options: (14,3) (9,3) (-6,10) (-8,6) (-6,2)
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All of the possible answers for the vertices of triangle A'B'C' after using this translation rule (x, y) → (2x, y - 3) include the following:
A. (14, 3)
D. (-8, 6)
What is a translation?In Geometry, a translation can be defined as a type of transformation which moves every point of a geometric figure or object in the same direction, as well as for the same distance.
Next, we would transform triangle ABC by using this translation rule (x, y) → (2x, y - 3) to create the vertices of triangle A'B'C' as follows:
(x, y) → (2x, y - 3)
Coordinate A = (7, 6) → Coordinate A' (2(7), 6 - 3) = (14, 3)
Coordinate B = (-3, 5) → Coordinate B' = (2(-2), 5 - 3) = (-4, 2)
Coordinate C = (-4, 9) → Coordinate C' = (2(-4), 9 - 3) = (-8, 6)
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12x÷4yif x=-8 and y=3
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To solve 12x÷4y, first, let's evaluate the products on both sides of the ÷ symbol, we know that x = -8, then we have:
[tex]12\times(-8)=-96[/tex]We have -96 on the left side of the ÷ symbol.
We know that y = 3, then, on the right side, we have:
[tex]4\times3=12[/tex]Then, we have 12 on the right side of the ÷ symbol, now the expression looks like this:
-96 ÷ 12. what we have to do is to divide -96 by 12, then we get:
[tex]-96\text{ }\div12=\frac{-96}{12}=-8[/tex]Then, the answer is 8
How many rays are in the next two terms in the sequence?
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The sequnce is
2, 3, 5, 9, ....
this sequence follows the next formula:
[tex]a_n=2^{n-1}+1[/tex]where an is the nth term.
[tex]\begin{gathered} a_1=2^{1-1}+1=1 \\ a_2=2^{2-1}+1=3 \\ a_3=2^{3-1}+1=5 \\ a_4=2^{4-1}+1=9 \\ a_5=2^{5-1}+1=17 \\ a_6=2^{6-1}+1=33 \end{gathered}[/tex]The next two terms are 17 and 33
Select all the situations in which a proportional relationship is described.
Jackson saves $10 in the first month and $30 in the next 3 months.
Mia saves $8 in the first 2 months and $4 in the next month.
Piyoli spends $2 in the first 2 days of the week and $5 in the next 5 days.
Robert spends $2 in the first 3 days of the week and $5 in the next 4 days.
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Answer:
Jackson saves $10 in the first month and $30 in the next 3 months.
Mia saves $8 in the first 2 months and $4 in the next month.
Piyoli spends $2 in the first 2 days of the week and $5 in the next 5 days.
Step-by-step explanation:
A proportional relationship is one that has a constant of proportionality.
In this case, the correct options are Mia, Piyoli, and Robert.
linear equation in deletion method2x + y − 3z = 13x − y − 4z = 75x + 2y − 6z = 5
Answers
The given system is:
[tex]\begin{gathered} 2x+y-3z=1\ldots(i) \\ 3x-y-4z=7\ldots(ii) \\ 5x+2y-6z=5\ldots(iii) \end{gathered}[/tex]Add (i) and (ii) to get:
[tex]\begin{gathered} 2x+y-3z=1 \\ + \\ 3x-y-4z=7 \\ 5x-7z=8\ldots(iv) \end{gathered}[/tex]Multiply (ii) by 2 to get:
[tex]6x-2y-8z=14\ldots(v)[/tex]Add (iii) and (v) to get:
[tex]\begin{gathered} 6x-2y-8z=14 \\ + \\ 5x+2y-6z=5 \\ 11x-14z=19\ldots(vi) \end{gathered}[/tex]Multiply (iv) by 2 to get:
[tex]10x-14z=16\ldots(vii)[/tex]Subtract (vii) from (vi) to get:
[tex]\begin{gathered} 11x-14z=19 \\ - \\ 10x-14z=16 \\ x=3 \end{gathered}[/tex]Put x=3 in (iv) to get:
[tex]\begin{gathered} 5\times3-7z=8 \\ -7z=8-15 \\ -7z=-7 \\ z=1 \end{gathered}[/tex]Put x=3 and z=1 in (i) to get:
[tex]\begin{gathered} 2(3)+y-3(1)=1 \\ 6+y-3=1 \\ y+3=1 \\ y=-2 \end{gathered}[/tex]So the values are x=3,y=-2 and z=1.
A salad recipe requires 3 cups of spinach and 1/2 cup of pecans. At this rate, what amount of pecans should be used with 2 cups of spinach?
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We need 3 cups of spinach for each 1/2 cup of pecans.
Then we have:
[tex]\begin{gathered} \frac{2\text{ cups of spinach}}{3\text{ cups of spinach}}=\frac{x\text{ cups of pecans}}{\frac{1}{2}\text{ cups of pecans}} \\ \frac{x}{\frac{1}{2}}=\frac{2}{3} \\ x=\frac{1}{2}\cdot\frac{2}{3} \\ x=\frac{1}{3} \end{gathered}[/tex]Answer: It will be needed 1/3 cup of pecans
Corky writes four equations to show each of the properties of equality. Which of Corky's equation is incorrect? Explainwill send image.
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6 + m = 12
A. This IS equivalent
6 + m - m = 12 - m ==> 6 = 12 - m ==> 6 + m = 12
B. This IS NOT equivalent
6 + m - 6 = 12 - 12 ==> m = 0
C. This IS equivalent
6 + m + 2 = 12 + 2 ==> 6 + m = 12
D. This IS equivalent
6 + m - 6 = 12 - 6 ==> m = 6 ==> 6 + m = 12
Answer:
B is not equivalent
Write the slope-intercept form of the equation. Put your answer in y = mx + b form.Passing through (-4, -8) and (-8, -13)
Answers
Answer:
[tex]y=\frac{5}{4}x-3[/tex]Step-by-step explanation:
Linear functions are represented by the following equation:
[tex]\begin{gathered} y=mx+b \\ \text{where,} \\ m=\text{slope} \\ b=y-\text{intercept} \end{gathered}[/tex]The slope of a line is given as;
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex](-4,-8) and (-8,-13):
[tex]\begin{gathered} m=\frac{-8-(-13)}{-4-(-8)} \\ m=\frac{5}{4} \end{gathered}[/tex]Use the slope-point form of a line, to find the slope-intercept form:
[tex]\begin{gathered} y_{}-y_1=m(x_1-x_{}) \\ y+8=\frac{5}{4}(x+4) \\ y+8=1.25\mleft(x+4\mright) \\ y=\frac{5}{4}x-13 \\ y+8=\frac{5}{4}x+\frac{20}{4} \\ y=\frac{5}{4}x+5-8 \\ y=\frac{5}{4}x-3 \end{gathered}[/tex]