Answer:
In traffic, she drove for 3 hours
and After the traffic cleared she drove for 2 hours.
Explanation:
Given that the road trip was 136 miles;
[tex]d=136[/tex]The first part of the trip there was lots of traffic, she only averaged 16 mph;
[tex]v_1=16[/tex]The second part of the trip there was no traffic so she could drive 44 mph;
[tex]v_2=44[/tex]She traveled for a total of 5 hours;
[tex]t=5[/tex]let x represent the time in traffic when she traveled at 16 mph
[tex]t_1=x[/tex]the time the traffic is clear would be;
[tex]t_2=t-t_1=5-x[/tex]Recall that distance equals speed multiply by time;
[tex]d=v_1t_1_{}_{}^{}+v_2t_2[/tex]substituting the values;
[tex]136=16x+44(5-x)[/tex]solving for x;
[tex]\begin{gathered} 136=16x+220-44x \\ 44x-16x=220-136 \\ 28x=84 \\ x=\frac{84}{28} \\ x=3 \end{gathered}[/tex]So;
[tex]\begin{gathered} t_1=3\text{ hours} \\ t_2=5-x=5-3=2 \\ t_2=2\text{ hours} \end{gathered}[/tex]Therefore, In traffic, she drove for 3 hours
and After the traffic cleared she drove for 2 hours.
11) a- 15 > 40-6 +3a) 12) 366b-1) > 18 - 3b a-151-46-67+1-useBay 9-15 124-12a atiza324+15 13a339 ay/9 13) 26 + m 2 5(-6 +3m) 14) 20-2p>-2lp
Answer
11) a > 3
12) b > (2/3)
Explanation
11) a - 15 > -4 (-6 + 3a)
a - 15 > 24 - 12a
a + 12a > 24 + 15
13a > 39
Divide both sides by 13
(13a/13) > (39/13)
a > 3
In graphing inequality equations, the first thing to note is that whenever the equation to be graphed has (< or >), the circle at the beginning of the arrow is usually unshaded.
But whenever the inequality has either (≤ or ≥), the circle at the beginning of the arrow will be shaded.
Then, the direction of the graph depends on the direction of the inequality sign, for example, the answer here says a is greater than 3. So, the graph will start with an unshaded circle and cover the numbers greater than 3.
12) 3 (6b - 2) > (8 - 3b)
18b - 6 > 8 - 3b
18b + 3b > 8 + 6
21b > 14
Divide both sides by 21
(21b/21) > (14/21)
b > (2/3)
This answer is similar to that of number 11. For the graph, it will start with an unshaded circle and move towards the numbers greater than (2/3)
Hope this Helps!!!
Can I get help, the last tutor didn't help me that much.
We know that
• The volume of one ball is 221 cubic centimeters.
Since the ball is spherical, we can find its radius with the following formula.
[tex]\begin{gathered} V=\frac{4}{3}\pi r^3 \\ 221\cdot\frac{3}{4\pi}=r^3 \\ r^3=\frac{663}{4\pi} \\ r=\sqrt[3]{\frac{663}{4\pi}}\approx3.75 \end{gathered}[/tex]The diameter would be double than the radius, by definition.
[tex]d=2(3.75)=7.5[/tex]Since there are three balls in the cylinder, the height would be
[tex]h=3(7.5)=22.5[/tex]Now, we find the volume of the cylindrical package.
[tex]V=\pi r^2h=\pi(3.75)^2(22.5)\approx993.52[/tex]Therefore, the volume of the cylindrical package is 993.52, approximately.Which inequality is represented by the graph?
Answer:
A. x > -1
Step-by-step explanation:
x > -1
-------------->
<----0------------->
-1
x < -1
<-------
<------0------------>
-1
x ≥ -1
---------->
<---------|---------->
-1
x ≤ -1
<----------
<---------|---------->
-1
< and > represent an open circle
≤ and ≥ represent a closed circle
I hope this helps!
In ACDE, m/C= (5x+18), m/D= (3x+2), and m/B= (2+16)°.
Angle (D) = m(D) = 50°, CDE provides the following: 3. angles
m=C=(5x+18), m=D=(3x+2), and m=E=(x+16)°.The total of the angles in a triangle is 180°What are angles?An angle is a figure in Euclidean geometry made up of two rays that share a common terminal and are referred to as the angle's sides and vertices, respectively. Angles created by two rays are in the plane where the rays are located. The meeting of two planes also creates angles. We refer to these as dihedral angles.CDE provides the following: 3. angles
m<C=(5x+18),m<D=(3x+2), andm<E=(x+16)degree.The total of the angles in a triangle is 180 degrees, so:
"mC + mD + mE = 180°"(5x+18)° + (3x+2)° + (x+16)° = 180°5x + 18 + 3x + 2 + x + 16 = 180°5x + 3x + x + 18 + 2 + 16 = 180°9x +36= 180°From both sides, deduct 36 as follows:
9x + 36 - 36 = 180° - 36°9x = 144°x = 144°/9x = 16From the aforementioned query, we are requested to determine:
angular D (m<D)Hence:
m∠D=(3x+2)°m∠D=( 3 × 16 + 2)°m∠D=(48 + 2)°m∠D= 50°Therefore, angle (D) = m(D) = 50°, CDE provides the following: 3. angles
m=C=(5x+18), m=D=(3x+2), and m=E=(x+16)°.The total of the angles in a triangle is 180°To learn more about angles, refer to:
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In a class of 10 boys and 12 girls, a committee of 4 members is to be formed. What is the probability to form a committee consisting of 2 boys and 2 girls?A. 0.3040B. 0.4060C. 0.5060D. 0.2060
Given:
Number of boys=10
Number of girls=12
Out of 22 members, 4 members is need to be selected.
To find probability to form a committee consisting of 2 boys and 2 girls:
So, we get
[tex]\begin{gathered} \frac{^{10}C_2\times^{12}C_2}{^{22}C_4}=\frac{\frac{10\times9}{2\times1}\times\frac{12\times11}{2\times1}}{\frac{22\times21\times20\times19}{4\times3\times2\times1}} \\ =\frac{5\times9\times6\times11}{11\times7\times5\times19} \\ =\frac{9\times6}{7\times19} \\ =\frac{54}{133} \\ =0.4060 \end{gathered}[/tex]Hence, the correct option is B.
Match each piece of the function with its domain.(6, oo)(-00, 1)(1,00)(-oo, -2)(-00, 6)(-2, 6)(3,00)(1, 4)
Explanation
The question wants us to select all the domains in the set of functions graphed.
The domain of a function is the set of all possible inputs for the function.
To do so, we have to be aware that there are 3 pieces of functions
These are shown below
These are
[tex]\begin{gathered} (-\infty,-2) \\ \\ (-2,6) \\ \\ (6,\infty) \end{gathered}[/tex]
RATIONAL FUNCTIONSSynthetic divisiontable buand write your answer in the following form: Quotient *
The given polynomial is:
[tex]\frac{2x^4+4x^3-6x^2+3x+8}{x\text{ + 3}}[/tex]Using the long division method:
The equattion can be written in the form:
Quotient + Remainder / Divisor
[tex](2x^3-2x^2\text{ + 3) +}\frac{-1}{x+3}[/tex]The question is in the picture, couldn’t fit the last graph so sent it in a separate picture
Explanation:
Concept:
To figure out if a graph is a function, we will use the vertical line test below
The vertical line test is a graphical method of determining whether a curve in the plane represents the graph of a function by visually examining the number of intersections of the curve with vertical lines.
From the first graph we can see that the vertical line cuts the points at on intersection
The Second graph is given below as
Its has two intersections on both sides of the graph
The third graph is given below as
It has two intersections on the ride hand side of the graph
The Fourth graph ios given below as
Its has two intersection on the right hand side of the graph
In conclusion,
A graph is said to be a function if one value of x has a separate value of y
Therefore,
The final answer is
The FIRST OPTION is the correct answer
Answer the questions about the figures below. 4 ft Figure A 6 ft 6 ft 4 ft (a) Which figures are parallelograms? Mark all that apply. Figure A O Figure B (b) Which figures are squares? Mark all that apply. Figure A Figure B (c) Which figures are rectangles? Mark all that apply. Figure A Figure B O Figure C Figure C Figure C 6 ft Figure B 4 ft 4 ft 6 ft None of the figures None of the figures None of the figures 6 ft X Figure C 6 ft 6 ft Ś 6 ft ?
A parallelogram is a 4 sided figures that has the opposite sides parallel.
Figure A has right angles so the opposite sides are parallel
Figure B has the opposite sides of equal length, so the opposite sides are parallel
Figure C has right angles so the opposite sides are parallel
For Question A, Figure A, B C are parallelograms
Squares have opposites sides parallel and all 4 sides of equal length and all angles right angles
The only figure with all 4 sides of equal length, all 4 angles right angles is Figure C ( opposites sides are parallel because 4 sides are equal length and all 4 angles are right angles)
The figure that is a square is Figure C
Rectangles are shapes that have opposite sides parallel and all 4 angles are right angles. Squares are special rectangles
Figure A has opposite sides parallel and all 4 angles equal length. Figure C is a square, which is a special rectangle
The rectangles are figures A and C
A. Write an exponential function to model with population Y of bacteria X hours after 2 PM
B. How many bacteria were there at 7 PM that day
In this problem, we have an exponential growth function of the form
[tex]y=a(b)^x[/tex]where
a=10 bacteria (initial value at 2 pm)
b is the base of the exponential function
[tex]y=10(b)^x[/tex]Find out the value of b
we know that
For x=0 (2 pm), y=10 bacteria
At 5 pm
y=33,750 bacteria
x=(5 pm-2 pm)=3 hours
substitute in the exponential equation
[tex]33,750=10(b)^3[/tex]Solve for b
[tex]b^3=\frac{33,750}{10}[/tex][tex]\begin{gathered} b=\sqrt[3]{\frac{33,750}{10}} \\ b=15 \end{gathered}[/tex]the equation is
[tex]y=10(15)^x[/tex]Part B
At 7 pm
x=(7 pm-2 pm)=5 hours
substitute
[tex]\begin{gathered} y=10(15)^5 \\ y=7,593,750\text{ bacteria} \end{gathered}[/tex]may ou solve the system of linear equations by substitution
y= 11 + 4x
3x +2y = 0
Put the first equation into the second one. (replace the value of y)
3x +2 (11 + 4x) = 0
Solve for x:
3x + 22 + 8x = 0
3x+8x = -22
11x = -22
x = -22/11
x = -2
Replace x=-2 in the first equation and solve for y
y= 11 + 4 (-2)
y= 11-8
y= 3
Solution:
x= -2 , y=3
Iq scores were gathered for group of college students at a local university. What is the level of measurement of dataNominal, ordinal, interval, ratio
Nominal data refers to non numerical data, for example categories, colors, etc...
Ordinal data refers to numerical data with a natural order, it comprehends real numbers.
Intervals comprehends data with equal distance between the values and no meaningful zero
Ratios comprehends data with equal distance between the values and a meaningul zero value.
With this in mind, the IQ scores of the college students represent numerical data, with a natural order, and the distance between the values is not equal, so you can classify the data as "ordinal"
Linda's mean speed on her drive home from Cincinnati is 54 mph. If the total trip is 378 miles, how long should she expect the drive to take? Round your answer totwo decimal places, if necessary,
We have that Linda's mean speed is 54 miles per hour. Since the total trip is 378 miles, we have the following rule of three:
[tex]\begin{gathered} 54\text{miles}\rightarrow1h \\ 378\text{miles}\rightarrow x \end{gathered}[/tex]therefore, we have:
[tex]\begin{gathered} x=\frac{378\cdot1}{54}=7 \\ x=7 \end{gathered}[/tex]Finally, we have that Linda should expect to drive 7 hours.
Enter a range of values for x.1416202x+109/15-5
26
Here, we want to write a range of values for x.
The shape we have is not a parallelogram but we have two equal sides
If it was a complete parallelogram, the two marked angles will be equal
But since what we have is not a complete parallelogram,
then;
[tex]\begin{gathered} 2x\text{ + 10 < 62 } \\ 2x\text{ < 62 - 10} \\ \\ 2x\text{ < 52} \\ \\ x\text{ < }\frac{52}{2} \\ \\ x\text{ < 26} \end{gathered}[/tex]3. What is the slope of a line that is parallel to the line that contains these
two points: (-2,5) and (-3,1).
Answer:
4
Step-by-step explanation:
The slope of the line through the points is
[tex]\frac{1-5}{-3-(-2)}=4[/tex]
Parallel lines have the same slope, so the answer is 4.
Translate |f(x)=|x| so the vertex is at (-3,2)
we have the parent function
f(x)=|x| ------> vertex is (0,0)
Translate at (-3,2)
The rule of the translation is given by
(x,y) ----> (x-3,y+2)
that means ----> 3 units at the left and 2 units up
so
Applying the translation
the new function is equal to
h(x)=|x+3|+2Fill in the blank with a number to make the expression of perfect square.x^2-18x t
Answer:
[tex]81[/tex]Explanation:
Here, we want to write a figure that would make the given expression a perfect square
As a perfect square, we mean that:
[tex]ax^2+bx+c=(x+d)(x+d)=(x+d)^2[/tex]In this case, what we have to do is to divide the coefficient of x by 2, square it and write it
The coefficient of x is the number before x (we must consider its sign however)
Thus, we have the coefficient in this case as -18
Dividing this by 2 and squaring, we have:
[tex]\frac{-18}{2}=(-9)^2\text{ = 81}[/tex]Thus, we have:
[tex]x^2-18x+81=(x-9)(x-9)=(x-9)^2[/tex]
The functions f(m) = 18 + 0.4m and g(m) = 11.2 + 0.54m give the lengths of two differentsprings in centimeters, as mass is added in grams, m, to each separately.
STEP - BY - STEP EXPLANATION
What to do?
Graph each equation on the same set of axis.
Determine the mass that makes the spring the same length.
Determine the length of that mass.
Write a sentence comparing the two springs.
Given:
f(m) = 18 + 0.4m and g(m) = 11.2 + 0.54m
Step 1
Find the x and y-intercept of both function.
f(m) = 18 + 0.4m
f(0) = 18+0.4(0) = 18
0 = 18 + 0.4m
0.4m = -18
m=-45
The x and y -intercept of the function f(m) are (0, 18) and (-45, 0) respectively.
g(m) = 11.2 + 0.54m
g(0) = 11.2 + 0.54(0)
g(0) = 11.2
0 = 11.2+ 0.54m
0.54m = -11.2
m=20.7
The x and y - intercepts are (0, 11.2) and (20.7, 0).
Step 2
Graph the function.
Below is the graph of the function.
Observe from the graph that that the mass that makes the spring the same length is approximately 48.5 grams.
The length at that point is 37.4 centimeters.
Comparison between the two strings.
The string with the function f(m) started out longer, but does not stretch as quickly as the other spring with the function g(m).
ANSWER
b) 48.6 grams
c) 37.4 centimeters
d) The string with the function f(m) started out longer, but does not stretch as quickly as the other spring with the function g(m).
if QS in TV are parallel lines and m≤SRP=65°, what is m≤VUR
Angle SRP and Angle VUR are corresponding angles.
When two parallel lines are cut by a transversal, it creates several different pairs of angles that are equal, complements, and supplements.
In case of corresponding angles,
They are equal.
Given,
∠SRP = 65°
∠VUR = 65° also
Answer[tex]\angle\text{VUR}=65\degree[/tex]Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 149 millimeters, and a standard deviation of 8 millimeters.
If a random sample of 50 steel bolts is selected, what is the probability that the sample mean would differ from the population mean by more than 3.3 millimeters? Round your answer to four decimal places.
The probability that the sample mean will differ from the population mean by more than 1.8 mm = 0.9949
Given,
In the question:
According to the given problem the mean diameter μ= 149 mm (population mean) and the standard deviation is σ = 8mm
random sample size, n= 50 steel bolts is selected
Let the random variable that represents the diameter of steel bolts be denoted by x and from the problem we have x = 3.3mm
Let z = (x-μ) / (σ/√n ) ....(1)
using formula (1) and when the sample mean differs from the population mean by more than 1.8mm
z = (3.3 - 149) /(8/√50 )
⇒z = -2.575
The probability that the sample mean will differ from the population mean by more than 1.8 mm
P( z > -2575) = 1 - P(z< -2.575) = 1 - 0.0051 = 0.9949
Hence, The probability that the sample mean will differ from the population mean by more than 1.8 mm = 0.9949.
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Referring to the table in question 14, how would you graph the solution set representing students that do not receive a note sent home to parents?Draw points on the integers to the left of, and including, 0.Draw points on the integers to the right of, and including, 0.Draw points on the integers to the left of 0.Draw points on the integers to the right of 0.
According to the table, the statement "note sent to parents" is represented by the following inequality:
[tex]points\text{ < 0}[/tex]this can be represented as all integers less than zero. That is all integers to the left of 0.
We can conclude that the correct answer is:
Answer:Draw points on the integers to the left of 0.
A body is moving in simple harmonic motion with position function
s(t) =2 + 2 cos t
where s is in meters and t is in seconds. Find the at time t.
The velocity of the body under simple harmonic motion (SHM) at time t is equal to -2sint. (Option D)
A type of self-sustaining periodic motion known as simple harmonic motion.
It is observed by the formula:
y = y' + Δy · cos ωt ....1.
Where,
y' = Initial position
Δy = Amplitude
ω = Angular frequency.
t = Time
To find the equation for the velocity of the body in simple harmonic motion differentiating equation w.r.t time (1),
then we get
v = - ω · Δy · sin ωt ....2.
If we know that ω = 1, t = t and Δt = 2, then the velocity of the body is:
v = - 1 · 2 · sin t
v = -2sint
The velocity is equal to -2sint
The velocity of the body under simple harmonic motion (SHM) at time t is equal to -2sint. (Option D)
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A cone has a base radius of length r, and an perpendicular height length h. If the height remains the same, and the radius is multiplied by 3, then the volume is multiplied by:A. 27B. 2C. 9D. 4/3
ANSWER
C. 9
EXPLANATION
The volume of a cone is:
[tex]undefined[/tex]Applying the product rule to expression \left(3^3\div 3^4\right)^5gives us Answer raised to the power of Answerdivided by Answer raised to the power of AnswerSimplify that into a reduced fraction.The numerator is AnswerThe denominator is Answer
Given the expression
[tex](3^3\div3^4)^5[/tex]Using product rule
[tex]\begin{gathered} (3^3\div3^4)^5=(\frac{3^3}{3^4})^5 \\ =(3^{3-4})^5=(3^{-1})^5 \\ =3^{-1\times5}=3^{-5} \end{gathered}[/tex]Where
[tex]3^{-5}=\frac{1}{3^5}=\frac{1}{243}[/tex]Hence, answer is 1/243
[tex](3^3\div3^4)^5=\frac{1}{243}[/tex]The numerator is 1
The denominator is 243
What is The volume of a cylinder 7 in height and 3 radius and a cone of 7 height and 3 radius together? So what is The volume of both together?
In this case r =3, h= 7
[tex]\Rightarrow V_{cy}=\pi\times3^2\times7=63\pi=197.92unit^3[/tex][tex]\begin{gathered} \text{The Volume V}_{co\text{ }}of\text{ a cone with base radius r and height h is given by:} \\ V_{co}=\frac{1}{3}\times\pi\times r^2\times h \end{gathered}[/tex]In this case,
r=3, h=7
[tex]V_{co}=\frac{1}{3}\times\pi\times(3)^2\times7=21\pi=65.97unit^3[/tex][tex]\begin{gathered} \text{Therefore} \\ V_{cy}+V_{co}=63\pi+21\pi=84\pi=263.89unit^3 \end{gathered}[/tex]Hence
volume of cone + volume of cylinder = 263.89 cube units
If the coordinates of a are (3,4) and the coordinates of b are (-3,3) then the length of an is
The length of the line segment from a to b is 6.08 units or [tex]\sqrt{37}[/tex] units.
What is the length of a line segment and what is the role of coordinates?The length is described as the distance between the two points in a line. The coordinate usually refers to the dimensions of the point with respect to the two dimension graph.
Relation between the coordinates and length: [tex]\sqrt{(x_{1} -x_{2}) ^{2} +(y_{1} -y_{2} )^{2} }[/tex]
Now let point a be ([tex]x_{1},y_{1}[/tex]) and point b be ([tex]x_{2},y_{2}[/tex])
Thus putting values,
length = [tex]\sqrt{(3-(-3))^{2}+(4-3)^{2} }[/tex]
length = [tex]\sqrt{36+1}[/tex]
length = [tex]\sqrt{37}[/tex]
Hence the length of ab is [tex]\sqrt{37}[/tex] or 6.08 units.
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The frequency distribution of blood groups of a sample of patients was found to be as follows:A 14B 6AB 3O 17The relative frequency of AB in this data is:Group of answer choices7.5%30.033%
we have that
the number of patients is (14+6+3+17)=40
patients AB=3
so
40 -----> 100%
applying proportion
100/40=x/3
x=3*100/40
x=7.5%Add or subtract the fractions. Write the answer in simplified form.-2/13+(-1/13)
1) To add or subtract fractions, let's firstly check the denominators
In this case, the denominator is the same.
The plus before the bracket does not change the sign.
[tex]\begin{gathered} -\frac{2}{13}+(-\frac{1}{13}) \\ \frac{-2-1}{13} \\ \\ \frac{-3}{13} \end{gathered}[/tex]That is why we get to -3/13 as a result.
Find the equation of the linear function represented by the table below inslope-intercept form.xy1-3 -723-114-15
To find the linear equation, we use two points from the table (1, -3) and (3, -11). First, we have to find the slope with the following formula.
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Where,
[tex]\begin{gathered} x_1=1 \\ x_2=3 \\ y_1=-3 \\ y_2=-11 \end{gathered}[/tex]Let's those coordinates to find the slope.
[tex]\begin{gathered} m=\frac{-11-(-3)_{}}{3-1}=\frac{-11+3}{2}=\frac{-8}{2}=-4\to m=-4 \\ \end{gathered}[/tex]The slope is -4.
Now, we use the point-slope formula to find the equation.
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-(-3)=-4(x-1) \\ y+3=-4x+4 \end{gathered}[/tex]Now, we solve for y to express it in slope-intercept form.
[tex]\begin{gathered} y+3=-4x+4 \\ y=-4x+4-3 \\ y=-4x+1 \end{gathered}[/tex]Therefore, the equation in slope-intercept form is y = -4x+1.Which number is not a solution to3(x+4)−2≥7?-2-12 1
The inequality is:
[tex]3(x+4)-2\ge7[/tex]now we solve the inequality for x
[tex]\begin{gathered} 3(x+4)\ge7+2 \\ 3(x+4)\ge9 \\ x+4\ge\frac{9}{3} \\ x+4\ge3 \\ x\ge3-4 \\ x\ge-1 \end{gathered}[/tex]This means that all the number, from -1 to infinit are solution of the inequality, and the only option that is not a solution is a) -2