Let's recall one of the properties of exponents:
[tex]x^4\ast x^5=x^{4\text{ + 5}}=x^9[/tex]Therefore, in our exercise we have:
[tex]4y\text{ }\ast2y^3=8y^{4\text{ }}andv^2\ast4v^7=4v^9[/tex][tex]8y^4\ast4v^9=32y^4v^9[/tex]the sign shown below is posted in front of a roller coaster ride at the Wadsworth country fairgrounds.if h represents the height of a rider in inches,what is the correct translation of the statement on this sign?h<48h>58h≤48h≥48
Answer:
h≥48
Explanation:
If all riders must be at least 48 inches tall, it can mean the following.
0. The height of the riders can be ,exactly 48 inches, tall (h=48)
,1. The height of the riders can be, greater than 48 inches,, (h>48).
Combining the two, we have:
h≥48
mark has a bag containing a mixture of 30 green and white marbles.
SOLUTION:
From the experiment performed;
Mark got 10 green marbles and 5 white marbles after 15 trials. Since the number of green marbles gotten in the experiment is more than the white, the conclusion best supported by the experiment is ;
The bag contains more green than white marbles.
3. Suppose an investment of $5000 doubles every 12 years. How much is the investment worth after: 24 years?
Money = $5000
time = 12 years
investment after 24 years
If the investment doubles every 12 years after 24 years the total amount of money will be $10000.0
What is the difference between the inverse function of quadratic and exponential
Answer:
Quadratic functions are those where their rate of change changes at a constant rate. Exponential functions are those where their rate of change is proportional to itself.
Step-by-step explanation:
An example of a quadratic function would be the shape that a ball makes when you throw it. Gravity causes a constant acceleration, the ball slows down as it is moving up, and then it speeds up as it comes down.
An example of an exponential function would be the population of a bacterium as long as there is enough space and nutrients or how your money grows with compound interest in a bank.
The bank requires that customers select a PIN (personal identification number) so ATM’s can be accessed. The PIN must be 3 digits followed by one letter. How many different PIN numbers can be selected if the first digit cannot be zero?
Answer:
A lot
Step-by-step explanation:
use random numbers from 1 to 9 and or 0, after the first natural number. And different letters, so there is no specific amount to say that can be used.
To make banana berry smoothies, Just Juice mixes water and juice in a ratio of 5 to 3. How much water should Just Juice mix with 23 gallons of juice to make banana berry smoothies?
Answer:
38 1/3 gallons.
Step-by-step explanation:
[tex]\frac{w}{j}[/tex] = [tex]\frac{w}{j}[/tex] set up a ratio of the ratio of water to juice to the actual amount of water in juice. Fill in the numbers that you know and solve for the actual amount of water.
[tex]\frac{5}{3}[/tex] = [tex]\frac{w}{23}[/tex] Cross multiply and solve
3w = 5(23)
3w = 115 Divide both side by 3
w = 38 1/3 Gallons
proportional relationships, math
The answer is yes, the equation represents a proportional relationship.
The reason is that a proportional relationship is best described as that in which the value of one variable depends on what happens to the other variable. Just like having one more child every year would mean spending more money on education, etc.
In a proportiona; relationship as shown in this question, y is the total cost of a pizza and each x (each topping) would determine how much is y. So requesting for 5 more toppings would result in 1.5 multiplied by 5, and requesting 10 more would result in 1.5 multiplied by 10. So as the amount of toppings (x variable) increases, the total cost (y variable) likewise would increase.
As x increases or decreases, the value of y would likewise increase or decrease. That makes this equation a proportional relationship
What is the equation of the line that is parallel to the graph of y = 2x - 5 and passes through the point (8, 10)?
We know that the equation of a line is given by
[tex]y-y_1=m(x-x_1)[/tex]To find it we need the slope m and a point that the line passes thorugh. In this case we have the point (8,10) but we don't know the slope. What we know is that the line we are looking for is parallel to the line
[tex]y=2x-5[/tex]We also know that for two lines to be parallel they have the same slope. Then, if we fin the slope of the line y=2x-5, we have the slope of the line we are looking for. To find the slope of the line y=2x-5 we note that it is written in the slope-intercept form
[tex]y=mx+b[/tex]From this we know that the slope is multiplying the x variable when it is written in that form. Hence m=2.
Then the line we are looking for has an slope of 2 and passes through the point (8,10). Pluggin the values in the equation of a line we have.
[tex]y-10=2(x-8)[/tex]Writting it in the slope intercept form we have
[tex]\begin{gathered} y-10=2(x-8) \\ y-10=2x-16 \\ y=2x-16+10 \\ y=2x-6 \end{gathered}[/tex]Then the line parallel to y=2x-5 and passes through the point (8,10) is
[tex]y=2x-6[/tex]The post office offers flat-rate mailing of packages: $1.50 for a package weighing less than 4 oz, $2.50 for a package weighing 4 oz to less than 8 oz, and $3.50 for a package weighing 8 oz to 12 oz. write an equation that would represent the situation.
To solve the problem, we will define a function that given the weight of the package, will determine the cost of the mailing. Let x be the weigth of the package in oz and let f(x) be the cost of mailing the package. We are told that if the weight is less than 4, then the rate is 1.50. So, in math notation that would be f(x) = 1.50 if x<4. Now, we are told that if the package weights between 4 and less than 8, then the rate is 2.50. So, that is f(x) = 2.50 if 4<=x<8. Finally, we are told that if the package weights between 8 and 12, the cost is 3.50. So f(x) = 3.50 if 8<=x<=12. So the final math expression for f(x) is
1.50 if x<4
f(x) = 2.50 if 4<=x<8
3.50 if 8<=x<=12.
i have already graphed the problem, please help me fill in the following.
ANSWER
There are 3 major points to prove that a quadrilateral is a rhombus
1. Indicate that the diagonals of the shape are bisectors that are perpendicular to each other
2. Indicate that the diagonal of the shape bisects both pair of opposite angles
3. Indicate that the shape is a parallelogram with sides of the same length
Complete the square for each expression. Write the resulting expression as a binomial. x^2+14x+____
To complete the square is take the second term in the expression, divided it by 2 and then squared it. This will be the number that we have to add to the original expression.
(14/2)^2=49
so, completing the expression:
x^2+14x+49
Then, the new expression can be factored into a single term squared:
x^2+14x+49= (x+7)^2
The question is which of these statements are true about radicals exponents and rational exponents
We have the following:
I)
[tex]\sqrt[n]{a}=a^{\frac{1}{n}}[/tex]It´s true
II)
[tex]a^{\frac{1}{2}}=\sqrt[]{a}[/tex]It´s true
III)
[tex]\begin{gathered} a^{\frac{p}{q}}=\sqrt[p]{a^q}=(\sqrt[p]{a})^q \\ (\sqrt[p]{a})^q=(a^{\frac{1}{p}})^q=a^{\frac{q}{p}} \end{gathered}[/tex]It´s false
IV)
[tex]\sqrt[]{a}[/tex]It´s true
V)
[tex]\begin{gathered} a^{\frac{1}{n}}=\sqrt[]{a^n} \\ \sqrt[]{a^n}=a^{\frac{n}{2}} \end{gathered}[/tex]It´s false
Topic 8.2: Solving Using Linear/HELP RN!!!!!Area Scale Factor3. Examine the two similar shapes below. What is the linear scale factor? What is the area scalefactor? What is the area of the smaller shape?3a. Linear scale factor =3b. Area scale factor =Area =99 un.2=3c. Area of small shape =
Solution
Question 3:
- Let the dimension of a shape be x and the dimension of its enlarged or reduced image be y.
- The linear scale factor will be:
[tex]sf_L=\frac{y}{x}[/tex]- If the area of the original shape is Ax and the Area of the enlarged or reduced image is Ay, then, the Area scale factor is:
[tex]sf_A=\frac{A_y}{A_x}=\frac{y^2}{x^2}[/tex]- We have been given the area of the big shape to be 99un² and the dimensions of the big and small shapes are 6 and 2 respectively.
- Based on the explanation given above, we can conclude that:
[tex]\begin{gathered} \text{ If we choose }x\text{ to be 6, then }y\text{ will be 2. And if we choose }x\text{ to be 2, then }y\text{ will be 6} \\ \text{ So we can choose any one.} \\ \\ \text{ For this solution, we will use }x=6,y=2 \end{gathered}[/tex]- Now, solve the question as follows:
[tex]\begin{gathered} \text{ Linear Scale factor:} \\ sf_L=\frac{y}{x}=\frac{2}{6}=\frac{1}{3} \\ \\ \text{ Area Scale factor:} \\ sf_A=\frac{y^2}{x^2}=\frac{2^2}{6^2}=\frac{1}{9} \\ \\ \text{ Also, we know that:} \\ sf_A=\frac{A_y}{A_x}=\frac{y^2}{x^2} \\ \\ \text{ We already know that }\frac{y^2}{x^2}=\frac{1}{9} \\ \\ \therefore\frac{A_y}{A_x}=\frac{1}{9} \\ \\ A_x=99 \\ \\ \frac{A_y}{99}=\frac{1}{9} \\ \\ \therefore A_y=\frac{99}{9} \\ \\ A_y=11un^2 \end{gathered}[/tex]Final Answer
The answers are:
[tex]\begin{gathered} \text{ Linear Scale Factor:} \\ \frac{1}{3} \\ \\ \text{ Area Scale Factor:} \\ \frac{1}{9} \\ \\ \text{ Area of smaller shape:} \\ 11un^2 \end{gathered}[/tex]-2(k - 5) + 2K = 5k +5A)k=0B)k=4C)k1D)k=2
The equation we have is:
[tex]-2(k-5)+2k=5k+5[/tex]Now we can simply the equation by multiply the -2 into the parenthesis
[tex]\begin{gathered} -2k+10+2k=5k+5 \\ 10=5k+5 \end{gathered}[/tex]now we can solve for k
[tex]\begin{gathered} 10-5=5k \\ 5=5k \\ \frac{5}{5}=k \\ 1=k \end{gathered}[/tex]Completely factor the expression by grouping if possible 2xy+3x+10y+15
The required factor of the given expression is given as (2y + 3)(x + 3).
Given that,
The factor of the given expression 2xy+3x+10y+15 is to be determined.
The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.
Here
= 2xy+3x+10y+15
Simplifying through factorization,
= x(2y + 3) + 5(2y + 3)
= (2y + 3)(x + 3)
Thus, the required factor of the given expression is given as (2y + 3)(x + 3).
Learn more about simplification here: https://brainly.com/question/12501526
#SPJ1
suppose g(x) = f(x - 3) - 4. I need the graph of g(x) with the graph of f(x)
In order to graph g(x) with the graph of f(x), first we need a translation of 3 units to the right, because of the term f(x - 3)
Then, we need a translation of 4 units down, because of the term -4.
So the movements are: translations of 3 units right and 4 units down.
The Hernandez family and the Cox family each used their sprinklers last summer. The Hernandez family’s sprinkler was used for 15 hours. The fox familys sprinkler was used for 30 hours. There was a combined total output of 1275 L of water. What was the water output rate for each sprinkler if the sum of the two rates was 50 L per hour?
ANSWER
The output rate for the Hernandez family was 15 L/hr and for the Fox family was 35 L/hr.
EXPLANATION
To solve this problem, we have to create a system of two simultaneous equations.
Let the output rate of the Hernandez family sprinkler be h.
Let the output rate of the Fox family sprinkler be f.
The product of the rate and the time used is equal to the output:
[tex]\text{Rate}\cdot\text{time}=\text{output}[/tex]We have that the combined total output for both sprinklers is 1275 L, which means that:
[tex]\begin{gathered} (15\cdot h)+(30\cdot f)=1275 \\ \Rightarrow15h+30f=1275 \end{gathered}[/tex]The sum of the two rates is 50 L/hr, which means that:
[tex]h+f=50[/tex]Now, we have a system of two simultaneous equations:
[tex]\begin{gathered} 15h+30f=1275 \\ h+f=50 \end{gathered}[/tex]Solve the equations by substitution.
Make h the subject of the formula in the second equation:
[tex]h=50-f[/tex]Substitute that into the first equation:
[tex]\begin{gathered} 15(50-f)+30f=1275 \\ 750-15f+30f=1275 \\ 750+15f=1275 \\ \Rightarrow15f=1275-750=525 \\ f=\frac{525}{15} \\ f=35\text{ L/hr} \end{gathered}[/tex]Recall that:
[tex]h=50-f[/tex]Therefore, we have that:
[tex]\begin{gathered} h=50-35 \\ h=15\text{ L/hr} \end{gathered}[/tex]Hence, the output rate for the Hernandez family was 15 L/hr and for the Fox family was 35 L/hr.
15. Find m<1.
Observing the given figure n< 1 can be found using the Vertical angel theorem to be 132.75 degrees
What is vertical angle theorem?The vertical angle theorem is used when two straight lines intersect, at their point of intersection four angles are formed. The angles opposite to each other are equal
How to find m< 1 using vertical angle theoremThe figure shows
(x² - 6x)⁰
(x/2 + 42)°
From vertical angle theorem
(x² - 6x)⁰ = (x/2 + 42)°
solving for x by multiplying out by 2
2x² - 12x = x + 84
2x² - 12x - x - 84 = 0
2x² - 13x - 84 = 0
factorizing the parabolic equation gives
(x + 4)(2x-21)
using the positive value of x
x = 21/2
substituting x = 21/2 into (x/2 + 42) gives
= 47.25
sum of angles at a point = 360 degrees
2 * 47.25 + 2 * m< 1 = 360
2 * m< 1 = 360 - 94.5
m< 1 = 265.5/2
m< 1 = 132.75
Learn more on vertical angles here: https://brainly.com/question/68367
#SPJ1
the bearing from S to R is 160° what is the bearing of S from R
.
The bearing of S from R is given as;
[tex]90+90+90+70=340\degree[/tex]Which set of ordered pairs does not show y as a function of x? A. {(3,-2); (5,-3); (7,-4); (9,-5)} B. O {(3,-2); (6,-2); (9,-2); (12,-2)} c.{(4, -2); (5,-3); (6,-4); (7,-5)} D.O{(4, -2); (5,-3); (4,-8); (5,-9)}
Rain equation for the line that is parallel to the given line and that passes through the given point
From the properties of line
If two lines are parallel, then thier slope are equal.
The general equation of line with slope m is; y = mx + b
The given equation of line us y = -5x + 3, slope of the given line is (-5)
The line is passes through the point (-6,3) and slope (-5)
The general equation of line is;
[tex]y-y_1=m(x-x_1)[/tex]Substitute the coordinates as;
[tex]x_1=-6,y_1=3[/tex]Thus;
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-3=-5(x+6) \\ y-3=-5x-30 \\ y+5x-3+30=0 \\ 5x+y+27=0 \\ y=-5x-27 \end{gathered}[/tex]Answer : y = -5x - 27
,,,
I need help on question number 1 I have been stuck on it for a long time
Explanation
Step 1
Vertical angles are formed when two lines intersect each other. Out of the 4 angles that are formed, the angles that are opposite to each other are vertical angles. vertical angles are congruent so
[tex]\begin{gathered} m\angle5=m\angle7\rightarrow reason\text{ vertical angles} \\ \end{gathered}[/tex]Step 1
replace the given values
[tex]\begin{gathered} m\angle5=m\angle7\rightarrow reason\text{ vertical angles} \\ -2(3x-4)=3(x-3)-1 \end{gathered}[/tex]now, we need to solve for x
a)
[tex]\begin{gathered} -2(3x-4)=3(x-3)-1 \\ \text{apply distributive property} \\ -6x+8=3x-9-1 \\ \text{add like terms} \\ -6x+8=3x-10\rightarrow reason\text{ distributive property} \end{gathered}[/tex]b)subtract 3x in both sides( additioin or subtraction property of equality)
[tex]\begin{gathered} -6x+8=3x-10 \\ subtract\text{ 3x in both sides} \\ -6x+8-3x=3x-10-3x \\ -9x+8=-10 \\ \text{subtract 8 in both sides} \\ -9x+8-8=-10-8 \\ -9x=-18 \\ -9x=-18\rightarrow reason\colon\text{ addition and subtraction property of equality} \end{gathered}[/tex]c) finally, divide both sides by (-9) division property of equality
[tex]\begin{gathered} -9x=-18 \\ \text{divide both side by -9} \\ \frac{-9x}{-9}=\frac{-18}{-9} \\ x=2\rightarrow\text{prove} \end{gathered}[/tex]i hope this helps you
A $300,000 property appreciated in value by 3%. What is its new value?
Answer:
The word "Appreciated" means "Increase" in value of something.
Here, The value of property is Appreciated by 3%
Therefore,
New price = Old price + 3% of Old price
New price = $300000 + 3% of $300000
New price = $300000 + $( 3/100 × 300000)
New price = $300000 + $9000
New price = $309000
I hope it's helpful
Answer:
$309 000.
Step-by-step explanation:
It is now worth 3% more than its original 100%
So 103% ( in decimal 1.03)
1.03 * 300 000 = 309 000 dollars
In a probability experiment, Craig rolled a six-sided die 62 times. The die landed on a number greater than three 36 times. What is the ratio of rolls greater than three to rolls less than or equal to three?
Answer:
31/55
Step-by-step explanation:
А.Translate the triangle.Then enter the new coordinates.A'([?], []).(4,-1) B'([ ], [])C'([],[ ](1,-3)(5,-4)<-2,3)B.
Given the triangle shown in the picture, you know its vertices:
[tex]A\mleft(4,-1\mright);B\mleft(5,-4\mright);C\mleft(1,-3\mright)[/tex]You have the following translation vector:
[tex]\langle-2,3\rangle[/tex]Therefore, you can identify that to find the Image (the figure translated) of the Pre-Image (the original figure) ABC, you have to translate each vertex 2 units left and 3 units up. Then, you get:
[tex]\begin{gathered} A^{\prime}(4-2,-1+3)=A^{\prime}(2,2) \\ \\ B^{\prime}(5-2,-4+3)=B^{\prime}(3,-1) \\ \\ C^{\prime}(1-2,-3+3)=C^{\prime}(-1,0) \end{gathered}[/tex]Then, the answer is:
[tex]undefined[/tex]Given:• UZ | VW• UV ZUZ306Nw4511Which is closest to mZW?26.630°60°63.49
From the image, given that UZ is parallel to VW, UV is congruent to UZ. We can redraw the image to include some extra details.
The image is below;
With the image above, we can the find the angle W, using tangent function of trigonometry.
This is seen below;
[tex]\begin{gathered} \tan w=\frac{opposite}{\text{Adjacent}} \\ \text{opposite =30ft} \\ \text{Adjacent}=15ft \\ \therefore\tan w=\frac{30}{15} \\ \tan w=2 \\ w=\tan ^{-1}2 \\ w=63.4^0 \end{gathered}[/tex]The angle closest to m
Answer: 63.4
Open the image attached belowProve that:sec n/(tan n + cot n) = sin n
Given:
We are required to prove:
[tex]\frac{\sec\text{ }\theta\text{ }}{\tan\text{ }\theta\text{ + cot}\theta}\text{ = sin}\theta[/tex]From the left-hand side:
[tex]\begin{gathered} =\frac{\sec\text{ }\theta\text{ }}{\tan\text{ }\theta\text{ + cot}\theta}\text{ } \\ =\text{ }\frac{\frac{1}{\cos\theta}}{\frac{\sin\theta}{\cos\theta}\text{ + }\frac{\cos \theta}{\sin \theta}} \\ =\text{ }\frac{\frac{1}{\cos\theta}}{\frac{\sin ^2\theta+cos^2\theta}{\sin \theta\cos \theta}} \\ \end{gathered}[/tex]From standard trigonometric identity, we have:
[tex]\sin ^2\theta+cos^2\theta\text{ = 1}[/tex]Substituting we have:
[tex]\begin{gathered} =\text{ }\frac{\frac{1}{\cos\theta}}{\frac{1}{\sin \theta\cos \theta}} \\ =\text{ }\frac{\sin \theta\cos \theta}{\cos \theta} \\ =\text{ sin }\theta\text{ (Right-hand side)} \end{gathered}[/tex]the circle below has center E. Suppose that m
Notice that the triangle △GEF is an isosceles triangle, since GE=EF (both sides are radii of the circle).
Since △GEF is an isosceles triangle with GE=EF, then the measure of the angles opposed to those sides is the same:
[tex]m\angle GFE=m\angle EGF[/tex]Since the line FH is tangent to the circle, the angle ∠HFE is a right angle.
Since ∠HFG and ∠GFE are adjacent angles, then:
[tex]m\angle\text{HFG}+m\angle\text{GFE}=m\angle\text{HFE}[/tex]Substitute m∠HFG=62 and m∠HFE=90 to find m∠GFE:
[tex]\begin{gathered} 62+m\angle\text{GFE}=90 \\ \Rightarrow m\angle GFE=28 \end{gathered}[/tex]Since the sum of the internal angles of any triangle is 180 degrees, then:
[tex]m\angle\text{GFE}+m\angle\text{EGF}+m\angle\text{FEG}=180[/tex]Substitute the values of m∠GFE and m∠EGF:
[tex]\begin{gathered} 28+28+m\angle\text{FEG}=180 \\ \Rightarrow\angle FEG=124 \end{gathered}[/tex]Therefore:
[tex]\begin{gathered} \text{m}\angle\text{FGE}=28 \\ m\angle FEG=124 \end{gathered}[/tex]Rabbit's run: distance (meters) time (minutes) way 800 1 900 5 1107.5 20 1524 32.5
Answer:
Notice that:
[tex]\begin{gathered} \frac{800}{1}=800, \\ \frac{900}{5}=180, \\ \frac{1107.5}{20}=\frac{443}{8}, \\ \frac{1524}{32.5}=\frac{3048}{65}. \end{gathered}[/tex]Since all reduced fractions are different, the distance traveled by the rabbit and the time are not proportional.
Simplify 2+^3 ÷ 2- ^3
We want to simplify the following expression:
[tex]\frac{2+\sqrt[]{3}}{2-\sqrt[]{3}}[/tex]This means that we want to "remove" the denominator".
STEP 1If we observe the denominator:
[tex](2-\sqrt[]{3})[/tex]If we multiply it by
2 + √3, then
[tex]\begin{gathered} (2-\sqrt[]{3})(2+\sqrt[]{3}) \\ =4-\sqrt[]{3}^2=4-3=1 \end{gathered}[/tex]STEP 2We know that if we multiply both sides of a fraction by the same number or expression, the fraction will remain the same, then we multiply both sides by 2 + √3:
[tex]\frac{2+\sqrt[]{3}}{2-\sqrt[]{3}}=\frac{(2+\sqrt[]{3})(2+\sqrt[]{3})}{(2-\sqrt[]{3})(2+\sqrt[]{3})}[/tex]For the denominator, as we analyzed before
[tex](2-\sqrt[]{3})(2+\sqrt[]{3})=1[/tex]For the denominator:
[tex](2+\sqrt[]{3})(2+\sqrt[]{3})=(2+\sqrt[]{3})^2[/tex]Then,
[tex]\frac{2+\sqrt[]{3}}{2-\sqrt[]{3}}=\frac{(2+\sqrt[]{3})(2+\sqrt[]{3})}{(2-\sqrt[]{3})(2+\sqrt[]{3})}=\frac{(2+\sqrt[]{3})^2}{1}=(2+\sqrt[]{3})^2[/tex]STEP 3Now, we can simplify the result:
[tex]\begin{gathered} (2+\sqrt[]{3})^2=(2+\sqrt[]{3})(2+\sqrt[]{3}) \\ =2^2+2\sqrt[]{3}+(\sqrt[]{3})^2+2\sqrt[]{3} \\ =4+4\sqrt[]{3}+3 \\ =7+4\sqrt[]{3} \end{gathered}[/tex]Answer: 7+4√3