The concentration of the solution is 7.02 × 10⁻⁴ mol/L.
The Beer-Lambert law or Beer's law states that the amount of light absorbed by a solution is directly proportional to the concentration of the absorbing material in the solution, the path length, and the absorption coefficient.
According to Beer's law,
A = εcl
where A is the absorbance, ε is the molar absorptivity, c is the concentration, and l is the path length.
Let's find the concentration of the solution from the given data using Beer's law.
A = εcl
0.929 = ε × c × l
Let's find the molar absorptivity (ε) from the data given.
Experimental beer's law for copper(ii) ions in solution at 814 nm was determined to be
ε = 1.32 × 10³ mol⁻¹ L cm⁻¹
From the data given, the path length is not mentioned.
Let's consider the path length as 1 cm.
So, l = 1 cm.
0.929 = (1.32 × 10³ mol⁻¹ L cm⁻¹) × c × 1 cmc
= 0.929/1.32 × 10³ mol/L
= 7.02 × 10⁻⁴ mol/L
The concentration of the solution is 7.02 × 10⁻⁴ mol/L.
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What chemical reactions are taking place inside the mouse?
Answer:
the heart and blood
Explanation:
the blood jus move threw heart or sum
What are the name and relative atomic mass of the element with which the relative atomic masses of all other elements are compared?
Answer:
Relative atomic mass is the average mass of an atom of an element, compared to 1/12th the mass of carbon 12 atom. Relative molecular mass is the ratio of the average mass of one molecular of an element or compound to1/2 of the mass of an atom of carbon 12.
During which step in "Steps to Solve a Problem" should students pick a strategy to use? Step 1 Step 2 Step 3 Step 4
Students should pick a strategy to use during Step 2 of "Steps to Solve a Problem."
In Step 1, students should read the problem and try to understand what is being asked of them. In Step 2, they should analyze the problem and identify what type of problem it is and what strategies could be used to solve it. This is where they should pick a strategy or method to solve the problem.
In Step 3, students should develop a plan for solving the problem using the strategy they have chosen. In Step 4, they should execute the plan and check their work to make sure it is correct.
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Answer:
Step 2
Explanation:
Which of the following is a fission reaction?
hydrogen-2 and hydrogen-3 combining to form a helium-4 atom and a neutron
carbon-12 and hydrogen-1 combining to form a nitrogen-13 atom
uranium-235 absorbing a neutron and breaking into barium-141, krypton-92, and three neutrons
a glucose molecule being metabolized with oxygen to form carbon dioxide and water
Please helpppp meeee!!!!!!!
a) A gas was produced
b) Reaction 1 does not takes place in a beaker
c) The reactions are balanced
d) The law of conservation of mass can be used to show that a reaction is balanced.
Why does reaction 1 not occur in a beaker?A combustion reaction, for instance, might not be able to continue if there isn't enough fuel or oxygen in the beaker to support it.
Moreover, a beaker is unlikely to contain an ignition source, like as a spark or flame, which is typically required to start the reaction.
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silver sulfide (ag2s) is the common tarnish on silver objects. what mass of silver sulfide can be made from 1.53 x 10-3g of hydrogen sulfide (h2s) obtained from a rotten egg?\
Silver sulfide (Ag2S) is the common tarnish on silver objects. The mass of silver sulfide that can be made from 1.53 x 10^-3g of hydrogen sulfide (H2S) obtained from a rotten egg is 3.67 g.
Let's understand this in detail:
The balanced chemical equation for the reaction is:
2 AgNO3 + H2S → Ag2S + 2 HNO3
The molar mass of H2S is 34.08 g/mol.
1.53 x 10^-3g of H2S = (1 mol / 34.08 g) * (1.53 x 10^-3g) = 4.49 x 10^-5 mol H2S.
From the balanced equation, it is clear that one mole of Ag2S is formed from one mole of H2S.
Therefore, the number of moles of Ag2S formed from 1.53 x 10^-3g of H2S is 4.49 x 10^-5 mol.
The molar mass of Ag2S is 247.8 g/mol. Therefore, the mass of Ag2S formed from 1.53 x 10^-3g of H2S is
(247.8 g/mol) * (4.49 x 10^-5 mol) = 0.0111 g or 11.1 mg.
To convert to grams, divide by 1000:11.1 mg ÷ 1000 = 0.0111 g or 11.1 mg = 1.11 x 10^-2
Therefore, the mass of silver sulfide that can be made from 1.53 x 10^-3g of hydrogen sulfide obtained from a rotten egg is 3.67 g (approx).
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Please Help. Complete the number of bonds and the total energy for each. Don't forget to state whether this is on the product or reactant side by highlighting the correct one. CEC # of bonds single bond O=O # of bonds C-H # of bonds C-O # of bonds H-O # of bonds (product/reactant) side (product / reactant) side (product/reactant) side (product/reactant) side (product / reactant) side Energy: Energy: Energy: Energy: Energy:
CEC-C-H: 9 bοnds (reactant) / 0 bοnds (prοduct)
C-O: 0 bοnds (reactant) / 2 bοnds (prοduct)
H-O: 0 bοnds (reactant) / 1 bοnd (prοduct)
What are the number οf bοnds fοr each element invοlved in the reactiοn?
CEC: The reactant side has 9 C-H bοnds, while the prοduct side has 0 C-H bοndsCEC: The reactant side has 0 C-O bοnds, while the prοduct side has 2 C-O bοnds.CEC: The reactant side has 0 H-O bοnds, while the prοduct side has 1 H-O bοnd.Single bοnd O=O: The reactant side has 0 O=O bοnds, while the prοduct side has 2 O=O bοnds.The tοtal energy fοr each bοnd is nοt prοvided, but the number οf bοnds and whether they are οn the reactant οr prοduct side is given.
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An energy level diagram is shown below. What is the overall energy change in this reaction?
Using the reaction profile that we can see from the question that has been given, the overall energy change is -250 kJ/mol
What is enthalpy of reaction?Enthalpy of reaction is the amount of heat absorbed or released during a chemical reaction, at a constant pressure. It is a measure of the energy change that occurs when reactants are transformed into products in a chemical reaction.
Enthalpy of reaction is denoted as ΔHrxn, where ΔH is the symbol for the change in enthalpy, and rxn is the abbreviation for "reaction". It is expressed in units of energy per amount of substance, such as joules per mole (J/mol).
Using;
Energy of Products - Energy of reactants
100 - 350 = -250 kJ/mol
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consider a salt that has a solubility of 551 g/l. you add 123 g of this salt to 421 ml of water. how much (in g) salt will remain undissolved?
The answer is 0 g.
In order to determine how much salt will remain undissolved after adding 123 g of a salt with solubility of 551 g/L to 421 mL of water, we need to first convert the volume of water to liters.421 mL of water = 0.421 L of water
The maximum amount of salt that can dissolve in 1 L of water with a solubility of 551 g/L can be calculated using the formula:
Max amount of salt that can dissolve = Solubility × Volume of solvent Max amount of salt that can dissolve = 551 g/L × 1 L
Max amount of salt that can dissolve = 551 g
Therefore, the maximum amount of salt that can dissolve in 0.421 L of water is:
Max amount of salt that can dissolve = 551 g/L × 0.421 L
Max amount of salt that can dissolve = 231.671 g
Since only 123 g of salt was added to 0.421 L of water, this is less than the maximum amount of salt that can dissolve. Hence, all of the salt will dissolve and there will be no salt left undissolved. Therefore, the answer is 0 g.
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draw and label the diagram of parts of the battery and illustrate the flow of electric current.
The specific components and design of a battery can vary depending on the type of battery and its intended use.
What are the parts of a battery?The basic components of a battery include:
Anode: This is the negative electrode of the battery where the oxidation reaction takes place.
Cathode: This is the positive electrode of the battery where the reduction reaction takes place.
Electrolyte: This is the medium that allows ions to flow between the anode and cathode, completing the circuit and generating the electrical energy.
Separator: This is a porous material that separates the anode and cathode, preventing direct contact between the electrodes while still allowing ions to flow between them.
Terminal: These are the points on the battery where the electrical energy is transferred out of the battery to power a device or charge another battery.
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HELP ME I DONT KNOW WHAT TO DO
Glass Because wood and other materials can be electrified through induction, but glass can't.
Is specific heat capacity C or Q?
The equation q = mcT may be used to compute the amount of heat acquired or lost by a sample (q), where m is the sample's mass, c is the specific heat, and T is the temperature change.
The quantity of heat required to raise the temperature of a given amount of stuff by one degree Celsius is referred to as heat capacity. The heat capacity of one gram of a material is known as its specific heat capacity (or specific heat), whereas the heat capacity of one mole is known as its molar heat capacity.
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Calculate each of the following quantities.
(a) Total number of ions in 47. 8 g of SrF2
(b) Mass (kg) of 4. 90 mol of CuCl2 · 2 H2O
(c) Mass (mg) of 2. 67 1022 formula units of Bi(NO3)3 · 5 H2O
a. Total number of ions in 47. 8 g of SrF2 = 1.635 ions.
b. Mass (kg) of 4. 90 mol of CuCl2 · 2 H2O = 0.833 kg
c. Mass (mg) of 2. 67 1022 units of Bi(NO3)3 · 5 H2O = 21,700 mg
a. Total number of ions in 47. 8 g of SrF2
The molar mass of SrF2 per gram = 87.62 g/mol
The number of moles of SrF2 in 47.8 g is calculated by using the formula,
The number of moles = n = (m/M) = 47.8 g / 87.62 g/mol
The number of moles = 0.545 mol
Total number of ions present in the molecule SrF2 = (1 Sr2+ ion/mol) x (0.545 mol) + (2 F- ions/mol) x (0.545 mol)
The Total number of ions = 0.545 + 2(0.545)
The total number of ions = 1.635 ions.
b. Mass (kg) of 4. 90 mol of CuCl2 · 2 H2O
Total number of ions in CuCl2 · 2 H2O = (63.55 g/mol Cu + 2 x 35.45 g/mol Cl + 2 x 18.02 g/mol H + 16.00 g/mol O) + 2 x 18.02 g/mol H + 2 x 16.00 g/mol O
Total number of ions = 170.48 g/mol
The mass of 4.90 mol of CuCl2 · 2 H2O is:
Molar mass (m) = nM = 4.90 mol x 170.48 g/mol
Molar mass (m) = 833.8 g = 0.833 kg
c. Mass (mg) of 2.67 10^22 units of Bi(NO3)3 · 5 H2O
Total number of ions in Bi(NO3)3 · 5 H2O = (208.98 g/mol Bi + 3 x 62.01 g/mol N + 9 x 16.00 g/mol O) + 5 x 18.02 g/mol H + 5 x 16.00 g/mol O
Total number of ions = 485.09 g/mo
Total number of moles (n) = N/NA = (2.67 × 10^22)/6.022 × 10^23
Total number of moles = 0.0444 mol
The mass of 0.0444 mol of Bi(NO3)3 · 5 H2O is:
Molar mass (m) = nM = 0.0444 mol x 485.09 g/mol
Molar mass = 21.7 g = 21,700 mg
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In a terrarium, the pincushion moss, the echeveria, and the moon cactus make up which of the following? A population community or ecosystem
Answer: The pincushion moss, the echeveria, and the moon cactus in a terrarium make up a community.
:)
I think this is the answer btw Sorry if i'm wrong I have no clue.
In a terrarium, the pincushion moss, the echeveria, and the moon cactus make up the community.
Moon cactus, also known as Gymnocalycium mihanovichii or Hibotan cactus, is native to South American deserts in places like Brazil and Argentina.
Leucobryum glaucum, commonly known as leucobryum moss or pin cushion moss, is a species of haplolepideous mosses with a wide distribution in eastern North America and Europe.
Echeveria is a large genus of flowering plants in the family Crassulaceae, native to semi-desert areas of Central America, Mexico and northwestern South America.
Therefore, In a terrarium, the pincushion moss, the echeveria, and the moon cactus make up the community.
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What is ionization energy?
Answer:
b) The amount of energy required to eject an electron from an atom.
The balanced equation below represents the reaction of glucose, C6H12O6, with oxygen at 298 K and 101.3 kPa.
C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(ℓ)
Determine the mass of CO2 produced when 9.0 grams of glucose completely reacts with 9.6 grams of oxygen to produce 5.4 grams of water. [1]
Compare the entropy of the reactants to the entropy of the products. [1]
Write the empirical formula for glucose. [1]
Answer:
1. 79.2 g of CO2
2. the reaction is spontaneous and favors the formation of products
3. CH2O
Explanation:
To solve the problem, we first need to calculate the limiting reagent by comparing the amount of glucose and oxygen available for the reaction. We will assume that the reaction goes to completion.
The balanced equation shows that for every 1 mole of glucose, 6 moles of oxygen are required. Therefore, the moles of oxygen required for 9.0 grams of glucose is:
moles of glucose = mass/molar mass = 9.0/180.16 = 0.0499 mol
moles of oxygen = 6 x moles of glucose = 6 x 0.0499 = 0.2994 mol
Since we have 0.2994 moles of oxygen available, and only 0.2000 moles of oxygen are required to react with 0.0499 moles of glucose to produce 0.0270 moles of water (according to the balanced equation), oxygen is the limiting reagent.
Using the balanced equation, we can now calculate the moles of CO2 produced:
moles of water produced = mass/molar mass = 5.4/18.02 = 0.2997 mol
moles of CO2 produced = 6 x moles of water produced = 6 x 0.2997 = 1.7982 mol
Finally, we can calculate the mass of CO2 produced:
mass of CO2 produced = moles x molar mass = 1.7982 x 44.01 = 79.2 g
Therefore, the mass of CO2 produced when 9.0 grams of glucose completely reacts with 9.6 grams of oxygen to produce 5.4 grams of water is 79.2 g.
To compare the entropy of the reactants to the entropy of the products, we can use the equation:
ΔS = ΣS(products) - ΣS(reactants)
The entropy of a substance depends on its state and temperature, and can be looked up in tables. At standard conditions (298 K and 101.3 kPa), the molar entropy of glucose, oxygen, CO2, and liquid water are:
S(C6H12O6) = 212.8 J/(mol K)
S(O2) = 205.0 J/(mol K)
S(CO2) = 214.8 J/(mol K)
S(H2O) = 69.9 J/(mol K)
Using the above values and the balanced equation, we can calculate the entropy change:
ΔS = (6 x S(CO2) + 6 x S(H2O)) - (S(C6H12O6) + 6 x S(O2))
ΔS = (6 x 214.8 + 6 x 69.9) - (212.8 + 6 x 205.0)
ΔS = 287.4 J/(mol K)
Since ΔS is positive, the entropy of the products is greater than the entropy of the reactants. This means that the reaction is spontaneous and favors the formation of products.
The empirical formula for glucose can be determined by dividing the subscripts by their greatest common factor. In this case, the empirical formula is:
C6H12O6 ÷ 6 = CH2O
Therefore, the empirical formula for glucose is CH2O.
Which conditions in Northern Europe encouraged emigration between 1845 and 1860?
A. war and famine
B. disease and slavery
C. natural disasters and climate change
D. religious persecution and poor education
How many moles of NaBr are there in 0. 50 liters of a 2. 1M NaBr solution?
Answer:
Explanation:
mOLARITY IS moles/L
moles = M X L
2.1 X 0.50 = 1.05 moles NaBr or 1.1 moles NaBr to correct sig figs
AgNO 3 + NaCI - AgCI + NaNO 3
Answer:
Correct
pls mrk me brainliest
Can someone please help with this chemistry question
24.9 g of oxygen gas would be required to completely burn 7.33 g of propane.
What is oxygen?Oxygen is an element found in air. It is a colorless, odorless gas that makes up about 21% of the Earth's atmosphere. Oxygen is essential for humans and animals to survive, as it is used to produce energy in the cells of living organisms, and to help maintain the balance of other elements in the body.
To answer this question, you need to balance the chemical equation first. The balanced equation is:
[tex]C_3H_8 + 5O_2 - > 3CO_2 + 4H_2O[/tex]
Now that the equation is balanced, you can calculate the mass of oxygen required to burn 7.33 g of propane.
To calculate the mass of oxygen, you need to use the mole ratio of the reactants in the balanced equation. The mole ratio of propane to oxygen is 1:5. Therefore, for every 1 mole of propane, 5 moles of oxygen are required.
Using the mole ratio and the given mass of propane, you can calculate the mass of oxygen required.
7.33 g of propane x (1 mole propane / 44.096 g propane) x (5 moles oxygen / 1 mole propane) x (32.00 g oxygen / 1 mole oxygen) = 24.9 g of oxygen
Therefore, 24.9 g of oxygen gas would be required to completely burn 7.33 g of propane.
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What is the amount of pure substance in 10. 7 g of aluminum? Assume the molar mass of aluminum is 26. 98 g/mol
This is calculated by dividing the mass of aluminum (10.7 g) by its molar mass (26.98 g/mol), resulting in 0.395 mol.
To find the amount of pure substance (in moles) in 10.7 g of aluminum, we need to divide the given mass by the molar mass of aluminum.
The molar mass of aluminum is given as 26.98 g/mol.
Therefore, the amount of pure substance (in moles) in 10.7 g of aluminum can be calculated as:
moles = mass/molar mass
moles = 10.7 g/26.98 g/mol
moles = 0.396 moles (rounded to three significant figures)
So, there are approximately 0.395 moles of pure substance (aluminum) in 10.7 g of aluminum.
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How many Oxygen atoms in the formula 4H3O2
Answer:
There are 8 oxygen atoms in the formula 4H3O2.
Explanation:
Answer:
There are 6 oxygen atoms in 4H3O2
Explanation:
There are 3 oxygens but since oxygen is a diatomic atom you multiply it by 2 and you get 6.
Un estudiante tiene 6 galletas Graham, 3 piezas de chocolate y 4 malvaviscos. Para hacer un s'more, un estudiante necesita usar dos galletas Graham, una pieza de chocolate y dos malvaviscos. ¿Cuál de los siguientes describe con precisión los reactivos limitantes y en exceso dados estos materiales? Pregunta 1 opciones: Los malvaviscos serían el reactivo limitante y las galletas graham y el chocolate serían el exceso. Se pueden hacer dos s'mores. El chocolate sería el reactivo limitante y las galletas graham y los malvaviscos serían el exceso. Se pueden hacer tres s'mores. El chocolate sería el reactivo limitante y las galletas graham y los malvaviscos serían el exceso. Se pueden hacer dos s'mores.
Answer:
Dado que los malvaviscos solo pueden hacer 2 s'mores, son el reactivo limitante. Esto significa que el número máximo de s'mores que se pueden hacer es 2.
Por lo tanto, la respuesta correcta es: los malvaviscos serían el reactivo limitante y las galletas graham y el chocolate serían el exceso. Puedes hacer dos s'mores.
Explanation:
The particles in.......... can be separated from
heterogeneous mixtures by passing the mixture through a filter.
-suspension
-solution
-colloid
-pure substance
The particles in a suspension can be separated from heterogeneous mixtures by passing the mixture through a filter.
What is a suspension?Suspensions are heterogeneous mixtures that contain particles of a larger size that are suspended in a liquid medium. These particles are large enough to be visible to the ordinary eye and can be separated from the mixture through the use of a filter.
When a suspension is passed through a filter, the particles in the mixture are trapped in the filter medium, and the liquid passes through, leaving the solid particles behind.
This is due to the physical properties of the particles in suspension, which are large enough to be filtered out. In contrast, the particles in solutions and colloids are much smaller, and cannot be separated through filtration.
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Grove School had a play. The graph shows how many people came to the play each night. Look at the data.
Which of the following is true?
A.
More people came to the play on Tuesday than on Friday.
B.
More people came to the play on Tuesday than on Monday.
C.
Everyone liked the play.
D.
Tickets cost less on Thursday.
The true statement on the data on the graph about the attendance for the play made by Grove Street is B. More people came to the play on Tuesday than on Monday.
What does the graph show ?The graph shows the number of people who attended a school play by Grove School from Monday to Saturday in a certain week. We see that Monday had the lowest attendance and was followed by Tuesday.
Attendance continued to rise and was higher on Wednesday than Tuesday but then dropped for Thurdsady and Frifay. It was then highest on the Saturday as more parents probably had time to attend.
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Can someone please help with this chemistry question
N2 (g) + 3H2 (g) 2NH3 is the balanced chemical equation of N2 + H2 NH3 (g). Based on the rule of conservation of mass, it is possible to make the atoms on both the reactant and product sides equal.
How do you find the balanced chemical equation?In a balanced chemical equation, the total number of atoms of an element present in a species is equal to the product of the stoichiometric coefficient and the number of atoms of the element in one molecule of the species.
The total number of oxygen atoms in the reactive species '2O2', for example, is four. Use these easy principles to balance equations on your own: Verify that all of the equation's formulas are valid. Just deal with one ingredient at a time. Balancing adds up to a lot of money.
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YooooooOOO!! Help!
Which of the following statements is incorrect concerning BaF2?
Question 2 options:
The total number of fluoride ions present in one formula unit is 2(6.022 x 1023).
The total number of fluoride ions present in three moles of BaF2 is equal to 6 x (6.022 x 1023).
The mass of 0.600 moles of BaF2 is 105 grams.
0.600 moles of BaF2 is equivalent to 3.61 x 1023 formula units of BaF2.
Explanation:
The total number of fluoride ions present in three moles of BaF2 is equal to 6 x (6.022 x 1023).How many moles of NaOH are needed to create a 2 M solution in 8 liters of solution? Please help, I’m really stuck on this one.
Answer:
To calculate the number of moles of NaOH needed to create a 2 M solution in 8 liters of solution, we need to use the formula:
moles = molarity x volume (in liters)
Here, the molarity (M) is given as 2 M, and the volume (V) is given as 8 liters.
So,
moles = 2 M x 8 L
= 16 moles
Therefore, 16 moles of NaOH are needed to create a 2 M solution in 8 liters of solution.
Explanation:
What is the mass of each element in 100. 0 g vinegar ? (Enter your answers to two decimal places. ) Percent Mass Mass in 100. 0 40. 01 ? 6. 70 % 53. 29 %
G C
G H
G O
the mass of carbon in 100.0 g of vinegar is 40.01 g, the mass of hydrogen is 6.70 g, and the mass of oxygen is 53.29 g.
To calculate the mass of each element in 100.0 g of vinegar, we need to use the percent composition of the compound. The percent composition tells us the percentage of each element in the compound by mass.
The percent composition of vinegar is:
Carbon (C): 40.01%
Hydrogen (H): 6.70%
Oxygen (O): 53.29%
To calculate the mass of each element, we need to multiply the percent composition by the total mass of the compound (100.0 g).
Mass of carbon (C) = 40.01% x 100.0 g = 40.01 g
Mass of hydrogen (H) = 6.70% x 100.0 g = 6.70 g
Mass of oxygen (O) = 53.29% x 100.0 g = 53.29 g
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Calculate the molar/formula mass for each compound. NO2
C6H12O6
C₆H₁₂O₆ has a molar mass of 180.18 g/mol.
The molar mass of a compound is the mass of one mole of the compound and is expressed in grams per mole (g/mol). To calculate the molar mass of a compound, we sum the atomic masses of all the atoms in the compound.
For NO₂, we have:
Molar mass of N = 14.01 g/mol
Molar mass of O = 16.00 g/mol
Therefore, the molar mass of NO₂ = 14.01 g/mol + 2(16.00 g/mol) = 46.01 g/mol.
For C₆H₁₂O₆ (glucose), we have:
Molar mass of C = 12.01 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of O = 16.00 g/mol
Therefore, the molar mass of C₆H₁₂O₆ = 6(12.01 g/mol) + 12(1.01 g/mol) + 6(16.00 g/mol) = 180.18 g/mol.
Knowing the molar mass is useful in calculating various other properties of the compound, such as the number of moles present in a given mass or the mass of a given number of moles.
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The molar mass of NO2 is 46 g/mol.
The molar mass of C6H12O6 is 180 g/mol.
The atomic masses of all the atoms in a compound's formula are added to determine its molar mass. In order to compute the molar mass of NO2, the atomic masses of one nitrogen atom (14.01 g/mol) and two oxygen atoms (2 x 16.00 g/mol) are added together, yielding a result of 46.01 g/mol.
Glucose is a typical monosaccharide and has the chemical formula C6H12O6. The atomic masses of every atom in the molecule must be added in order to determine the molar mass. Hydrogen, oxygen, and carbon all have atomic masses of 1.01 g/mol, 12.01 g/mol, and 16.00 g/mol, respectively. dividing the atomic mass of each element by the number of atoms in that element.
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How many elements and atoms are in these equations?
H2F5BLi
2He2PSO4
3He2O4PH
The only one I know is NaC2HO4. 1 atom in sodium, 2 atoms in carbon, 1 atom in hydrogen and 4 atoms in oxygen completeting the total of 8 atoms in this element.
How do you find the number of atoms in a formula?The first stage in calculating the number of atoms is to determine the number of molecules. To determine the number of moles in an element or compound, reduce the specified mass by the element or compound's molar mass. The number of atoms in 1 mole of a material is or. 023 10 23 atoms.
An element is a particle. Since the two terms are identical, the answer is always one, and only one, if you're searching for the number of atoms in an element.
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Full Question: What’s the elements found in these formulas?
NaC2HO4
H2F5BLi
2He2PSO4
3He2O4PH