Answers
In the given equations, the value of variables are:
(A) a = -10(B) b = -0.2(C) c = 0.25What exactly are equations?When two expressions are equal in a mathematical equation, the equals sign is used to show it.A mathematical statement is called an equation if it uses the word "equal to" in between two expressions with the same value.Using the example of 3x + 5, the result is 15.There are many different types of equations, such as cubic, quadratic, and linear.The three primary categories of linear equations are point-slope, standard, and slope-intercept equations.So, solving for variables:
(A) 1/5a = -2:
1/5a = -2a = -2 × 5a = -10(B) 8 + b = 7.8:
8 + b = 7.8b = 7.8 - 8b = -0.2(C) -0.5 = -2c:
-0.5 = -2cc = -0.5/-2c = 0.25Therefore, in the given equations, the value of variables are:
(A) a = -10(B) b = -0.2(C) c = 0.25Know more about equations here:
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Related Questions
Solve by factoring. Be sure to look for a GCF first in case there is one-2x²-4x+70=0
Answers
ANSWER
x = 5 and x = -7
EXPLANATION
We want to solve the equation by factoring.
The equation is:
[tex]-2x^2\text{ - 4x + 70 = 0}[/tex]First, there is a greatest common factor that we can use to simplify the equation. That is -2, so, first we divide through by -2.
It becomes:
[tex]x^2\text{ + 2x - 35 = 0}[/tex]Now, factorise:
[tex]\begin{gathered} x^2\text{ + 2x - 35 = 0} \\ x^2\text{ + 7x - 5x - 35 = 0} \\ x(x\text{ + 7) - 5(x + 7) = 0} \\ (x\text{ - 5)(x + 7) = 0} \\ x\text{ = 5 and x = -7} \end{gathered}[/tex]Solve each system of the equation by elimination. y=-4x+14y=10x-28
Answers
Explanation:
The elimination method consists in substracting one equation from the other, so you eliminate one of the variables and you have only one equation to solve for one variable.
In this case, y has the same coefficient in both equations, so this is the variable we will eliminate.
Substract the first equation from the second:
[tex]\begin{gathered} y=10x-28 \\ - \\ y=-4x+14 \\ \text{ ---------------------} \\ y-y=10x+4x-28-14 \\ 0=14x-42 \end{gathered}[/tex]And solve for x:
[tex]\begin{gathered} 14x=42 \\ x=\frac{42}{14} \\ x=3 \end{gathered}[/tex]Now, we replace x = 3 into one of the equations and solve for y:
[tex]y=-4\cdot3+14=-12+14=2[/tex]Answer:
• x = 3
,• y = 2
The top-selling Red and Voss tire is rated 60000 miles, which means nothing. In fact, the distance the tires can run until wear-out is a normally distributed random variable with a mean of 72000 miles and a standard deviation of 7000 miles.A. What is the probability that the tire wears out before 60000 miles?Probability = What is the probability that a tire lasts more than 80000 miles? Probability=
Answers
a. 0.0436
b. 0.1271
We are given the following:
Distance (x) = 60,000
Mean (u) = 72,000
Standard Deviation(s) = 7,000
We are also told that it is a normal disribution relationship. The formula for ND is as follows:
z = (x - u) / s
Now we can continue with part a and b as follows:
a) P (x < 60,000)
= P (z < (60000 - 72000) / 7000)
= P (z < -1.714)
We can find the corresponding z score by looking at a z score table, and we find th probability to be 0.0436
b) P ( x > 80,000)
= P(z > (80000 - 72000) / 7000)
= P( z > 1.143)
We find the corresponding z score to be 0.8729, now we can substract this from 1 sinsce our probability is larger than the given distance (meaning we are trying to find the area to the right of the z score) to find our final answer:
1 - 0.8729 = 0.1271
Lines that are perpendicular have slopes that arethe same or opposite and reciprocal.
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When lines are perpendicular the slopes of both are opposite and reciprocal, that is:
[tex]m\text{ and - }\frac{1}{m}[/tex]In words, if we have a line with slope = m, the perpendicular line to that line will have a slope = - 1/m ( opposite and reciprocal).
Not sure on how to do this. Would really like some help.
Answers
Given:
[tex]\cos60^{\circ}[/tex]To find:
The value
Explanation:
We know that,
[tex]\cos\theta=\sin(90-\theta)[/tex]So, we write,
[tex]\begin{gathered} \cos60^{\circ}=\sin(90-60) \\ =\sin30^{\circ} \\ =\frac{1}{2} \end{gathered}[/tex]Final answer:
[tex]\cos60^{\circ}=\frac{1}{2}[/tex]•is this function linear? •what’s the pattern in the table•what would be a equation that represents the function
Answers
Given data:
The given table.
The given function can be express as,
[tex]\begin{gathered} y-0=\frac{2-0}{1-0}(x-0) \\ y=2x \end{gathered}[/tex]As the equation of the above function is in the form of y=2x, it is linear function because for single value of x we got single value of y.
Thus, the function can be express as y=2x form which is linear function.
I attached the questions as images. The first image is actually the second.You can send in the work on paper like the graphing part.The questions can be typed on the solution tab or messages whichever is easier for you.Thanks again for the help :)
Answers
SOLUTION
Consider the image below,
The lenght of the compass is the radius, using a lenght of 5 unit, we have circle below as the sphere .
Where
[tex]\begin{gathered} r=\text{ radius, O= origin } \\ And \\ r=5\text{unit } \end{gathered}[/tex]Using the formula, we have
[tex]\begin{gathered} \text{Volume of sphere} \\ =\frac{4}{3}\pi r^3 \\ \text{where} \\ \pi=3.14,\text{ r=}5 \end{gathered}[/tex]Substitute into the formula, we have
[tex]\begin{gathered} \text{Volume of the sphere is } \\ =\frac{4}{3}\times3.14\times5^3 \\ \text{Hence } \\ 523.33\text{ cubic unit} \end{gathered}[/tex]Therefore
The volume of the sphere is 523.33 cubic unit
Find the x- and y-intercepts for the following equation. Then use the intercepts to graph the equation.
4x + 2y = 8
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Answer:
Step-by-step explanation:
x int=2
y int=4
graph 2,0 and 0,4 as two points
what is the image of -3 -7 after a reflection over the x-axis
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Given the point (-3, -7)
We need to find the image after a reflection over the x-axis
The rule of reflection over the x-axis is:
[tex](x,y)\rightarrow(x,-y)[/tex]So, the image of the given point will be:
[tex](-3,-7)\rightarrow(-3,7)[/tex]so, the answer is option D. (-3, 7)
What type of number is - Choose all answers that apply:AWhole numberBIntegerRationalDIrratio
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It is whole, integer, rational
When we use function notation, f(x)=# is asking you to find the input when the output is the given number. We can also consider that an ordered pair can be written as (x,#). With this is mind, explain why f(x)=0 is special.
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Notice that f(x)=0 is special because is the intercept of the graph with the x-axis and if f(x) corresponds to a function, the x-intercepts are the roots of the function.
The ordered pair can be written as (x,0), where x is such that f(x)=0.
Drag the correct algebraic representation of the reflection to the white box
Answers
Question 1
When any point (x,y) is reflected over the x-axis, the reflection coordinate is (x,-y).
So, the x coordinate remains the same, and the y coordinate goes negative.
A = ( -6, 6 ) → A' = (-6,-6 )
B = (-2,6 ) → B' = (-2,-6)
C= (-6,1 ) → C' = (-6,- 1)
Algebraic representation: ( x, -y )
Use the drawing tools to the graph the solution to this system of inequalities on the coordinate plane.
y> 2x + 4
x+y≤6
Answers
The solution to the system of inequalities y> 2x + 4 , x+y≤6 on the coordinate plane is shown below .
in the question ,
the system of inequality is given
y> 2x + 4
x+y≤6
to plot these inequalities on the coordinate plane ,we need to find the intercepts of both.
y>2x+4
put x = 0 we get y as 4 , (0,4)
put y = 0 we get x as -2 ,(-2,0)
x+y≤6
put x = 0 , we get y as 6 , (0,6)
put y = 0 , we get x as 6 , (6,0)
the solution of both the inequality is shown below .
Therefore , the solution to the system of inequalities y> 2x + 4 , x+y≤6 on the coordinate plane is shown below .
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create an original function that has at least one asymptote and possibly a removable discontinuity list these features of your function: asymptote(s) (vertical horizontal slant) removable discontinuity(ies) x intercept(s) y intercept and end behavior provide any other details that would enable another student to graph and determine the equation for your function do not state your function
Answers
We have to create a function that has at least one asymptote and one removable discontinuity (a "hole").
We then have to list the type of feature.
We can start with a function like y = 1/x. This function will have a vertical asymptote at x = 0 and a horizontal asymptote at y = 0.
We can translate it one unit up and one unit to the right and write the equation as:
[tex]y=\frac{1}{x-1}+1=\frac{1}{x-1}+\frac{x-1}{x-1}=\frac{x}{x-1}[/tex]Then, the asymptotes will be x = 1 and y = 1. We have at least one asymptote for this function.
We can now add a removable discontinuity. This type of discontinuity is one that is present in the original equation but, when factorizing numerator and denominator, it can be cancelled. This happens when both the numerator and denominator have a common root: the rational function can be simplified, but the root is still present in the original expression.
We than can add a removable discontinuity to the expression by multiplying both the numerator and denominator by a common factor, like (x-2). This will add a removable discontinuity at x = 2.
We can do it as:
[tex]y=\frac{x(x-2)}{(x-1)(x-2)}=\frac{x^2-2x}{x^2-3x+2}[/tex]This will have the same shape as y =x/(x-1) but with a hole at x = 2, as the function can not take a value that makes the denominator become 0, so it is not defined for x = 2.
Finally, we can find the x and y intercepts.
The y-intercepts happens when x = 0, so we can calculate it as:
[tex]\begin{gathered} f(x)=\frac{x^2-2x}{x^2-3x+2} \\ f(0)=\frac{0^2-2\cdot0}{0^2-3\cdot0+2}=\frac{0}{2}=0 \end{gathered}[/tex]The y-intercept is y = 0, with the function passing through the point (0,0).
As the x-intercept is the value of x when y = 0, we already know that the x-intercept is x = 0, as the function pass through (0,0).
Then, we can list the features as:
Asymptotes: Vertical asymptote at x = 1 and horizontal asymptote at y = 1.
Removable discontinuity: x = 2.
y-intercept: y = 0.
End behaviour: the function tends to y = 1 when x approaches infinity or minus infinity.
With that information, the function can be graphed.
A ball is thrown from an initial height of 4 feet with an initial upward velocity of 23 ft/s. The ball's height h (in feet) after 1 seconds is given by the following.h=4+231-167Find all values of 1 for which the ball's height is 12 feet.Round your answer(s) to the nearest hundredth.(If there is more than one answer, use the "or" button.)Please just provide the answer my last tutor lost connection abruptly.
Answers
Answer
t = 0.59 seconds or t = 0.85 seconds
Step-by-step explanation:
[tex]\begin{gathered} Given\text{ the following equation} \\ h=4+23t-16t^2\text{ } \\ h\text{ = 12 f}eet \\ 12=4+23t-16t^2 \\ \text{Collect the like terms} \\ 12-4=23t-16t^2 \\ 8=23t-16t^2 \\ 23t-16t^2\text{ = 8} \\ -16t^2\text{ + 23t - 8 = 0} \\ \text{ Using the general formula} \\ t\text{ }=\text{ }\frac{-b\pm\sqrt[]{b^2\text{ - 4ac}}}{2a} \\ \text{let a = -16, b = 23, c = -8} \\ t\text{ = }\frac{-23\pm\sqrt[]{(23)^2\text{ - 4}\cdot\text{ }}(-16)\text{ x (-8)}}{2(-16)} \\ t\text{ = }\frac{-23\pm\sqrt[]{529\text{ - 512}}}{-32} \\ t\text{ = }\frac{-23\pm\sqrt[]{17}}{-32} \\ \text{t = -23+}\frac{\sqrt[]{17}}{-32}\text{ or -23-}\frac{\sqrt[]{17}}{-32} \\ t\text{ = -23 }+\text{ 4.12/-32 or t = }\frac{-23\text{ - 4.12}}{-32} \\ t\text{ = }0.59\text{ seconds or t =0.85 seconds} \end{gathered}[/tex]Therefore, t = 0.59 seconds or t = 0.85 seconds
Find f(x) • g(x) if f(x) = x2 – 7 and g(x) = x2 + 3x + 7
Answers
Given the functions:
[tex]\begin{gathered} f(x)=x^2-7 \\ g(x)=x^2+3x+7 \end{gathered}[/tex]We will find: f(x) • g(x)
So, we will find the product of the functions
We will use the distributive property to get the result of the multiplications
So,
[tex]\begin{gathered} f\mleft(x\mright)•g\mleft(x\mright)=(x^2-7)\cdot(x^2+3x+7) \\ f\mleft(x\mright)•g\mleft(x\mright)=x^2\cdot(x^2+3x+7)-7\cdot(x^2+3x+7) \\ f\mleft(x\mright)•g\mleft(x\mright)=x^4+3x^3+7x^2-7x^2-21x-49 \\ f\mleft(x\mright)•g\mleft(x\mright)=x^4+3x^3-21x-49 \end{gathered}[/tex]so, the answer will be:
[tex]f\mleft(x\mright)•g\mleft(x\mright)=x^4+3x^3-21x-49[/tex]Evaluate the expression when a=3 and b=6. b2-4a
Answers
b² - 4a
evaluated when a = 3 and b = 6 is:
6² - 4(3) =
= 36 - 12=
= 24
A rectangular field of corn is averaging 125 bu/acre. The field measures 1080 yd by 924 yd. How many bushels of corn will there be?
Answers
Based on the dimensions of the rectangular field, and the corn per acre, the number of bushels of corn can be found to be 25,772 bushels
How to find the number of bushels of corn?First, find the area of the rectangular field:
= 1,080 x 924
= 997,920 yard²
Then convert this to acres with a single acre being 4,840 yards²:
= 997,920 / 4,840 square yards per acre
= 206.18 acres
The number of bushels of corn that can be grown is:
= 206.18 x 125 bushel per acre
= 25,772 bushels
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Determine the frequency of each class and the table shown
Answers
Given:
The dataset and table with class.
Required:
Determine the frequency of each class.
Explanation:
Answer:
Answered the question.
Jerome rolls two six-sided number cubes. What is the probability that he rolls doubles, given the sum of the numbers is 8?
Answers
Answer:
[tex]\frac{1}{6}[/tex]
Step-by-step explanation:
hope you get it thats the last pen that works in my house
Answer: There are five possible outcomes with a sum of 8:
2 and 6,
3 and 5,
4 and 4,
5 and 3,
6 and 2.
There is only one outcome, 4 and 4, that is doubles. Therefore, the probability is 1/5.
Step-by-step explanation: Got it right on Edmentum
2.) On the first night of a concert, Fish Ticket Outlet collected $67,200 on the sale of 1600 lawn
seats and 2400 reserved seats. On the second night, the outlet collected $73,200 by selling
2000 lawn seats and 2400 reserved seats. Solve the system of equations to determine the cost
of each type of seat.
Answers
Answer:
L=$15
R=$18
Step-by-step explanation:
i cant really explain the work
A cashier has 24 bills, all of which are $10 or $20 bills. The total value of the money is $410. How many of each type of bill does the cashier have?
Answers
The cashier has 7 bills of $10 and 17 bills of $20 (found using linear equation).
According to the question,
We have the following information:
A cashier has 24 bills, all of which are $10 or $20 bills. The total value of the money is $410.
Now, let's take the number of $10 bills to be x and the number of $20 bills to be y.
So, we have the following expression:
x+y = 24
x = 24-y .... (1)
10x+20y = 410
Taking 10 as a common factor from the terms on the left hand side:
10(x+2y) = 410
x+2y = 410/10
x+2y = 41
Now, putting the value of x from equation 1:
24-y+2y = 41
24+y = 41
y = 41-24
y = 17
Now, putting this value of y in equation 1:
x = 24-y
x = 24-17
x = 7
Hence, the cashier has 7 bills of $10 and 17 bills of $20 when the total value of the money is $410.
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Which of the following statements are true regarding functions? Check all that apply. A. The horizontal line test may be used to determine whether a function is one-to-one. B. The vertical line test may be used to determine whether a relatio is a function. C. A sequence is a function whose domain is the set of rational numbers. PREVIOUS
Answers
Statement A is true.
In the next example, we can see a function that is not one-to-one with the help of the horizontal line test:
Statement B is true.
In the next example, we can see a relationship that is not a function because it doesn't pass the vertical line test
Statement C is false.
A sequence is a function whose domain is the set of natural numbers
Write an equation of the line passing through the point (8,-3) that is parallel to the line y= -x -1. An equation of the line is
Answers
The equation of the line, in slope-intercept form, that is parallel to the line y = -x - 1 is: y = -x + 5.
How to Write the Equation of Parallel Lines?Parallel lines have equal slope value, "m". In slope-intercept form, the equation y = mx + b represents a line, where the slope is "m" and the y-intercept is "b".
The slope of y= -x -1 is -1. This means the line that is parallel to y= -x -1 will also have a slope that is equal to -1.
Substitute m = -1 and (x, y) = (8, -3) into y = mx + b to find the value of b:
-3 = -1(8) + b
-3 = -8 + b
-3 + 8 = b
5 = b
b = 5
Substitute b = 5 and m = -1 into y = mx + b to wrote the equation of the line that is parallel y = -x -1:
y = -x + 5
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5 ptsIn Ms. Johnson's class a student will get 3 points forhaving their name on their paper and 4 points for eachquestion that is correct. In Mr. Gallegos class, a studentwill get 7 points for having their name on their paper and2 points for each question correct. Which inequalitycould be used to determine x, the number of questionsthat would give you a higher grade in Ms. Johnson'sclass?
Answers
In Ms. Johnson's class a student will get 3 points for
having their name on their paper and 4 points for each
question that is correct. In Mr. Gallegos class, a student
will get 7 points for having their name on their paper and
2 points for each question correct. Which inequality
could be used to determine x, the number of questions
that would give you a higher grade in Ms. Johnson's
class?
we have
Ms. Johnson's class
3+4x
Mr. Gallegos class
7+2x
so
the inequality is given by
3+4x > 7+2x
solve for x
4x-2x > 7-3
2x>4
x> 2
the number of question must be greater than 2
Find the volume of a pyramid with a square base, where the side length of the base is19.3 ft and the height of the pyramid is 16.2 ft. Round your answer to the nearesttenth of a cubic foot.
Answers
Find the volume of a pyramid with a square base, where the side length of the base is
19.3 ft and the height of the pyramid is 16.2 ft. Round your answer to the nearest
tenth of a cubic foo
Remember that
the volume of the pyramid is equal to
[tex]V=\frac{1}{3}\cdot B\cdot h[/tex]where
B is the area of the base
h is the height
step 1
Find out the area of the base
B=19.3^2
B=372.49 ft2
h=16.2 ft
substitute the given values in the formula
[tex]V=\frac{1}{3}\cdot372.49\cdot16.2[/tex]V=2,011.4 ft3How do I find x I know you separate the shapes but I got it wrong…
Answers
Let's find this length first
6√2 is the hypotenuse, then
[tex]\begin{gathered} (6\sqrt{2})^2=6^2+y^2 \\ \\ y^2=(6\sqrt{2})^2-6^2 \\ \\ y^2=36\cdot2-36 \\ \\ y^2=36 \\ \\ y=\sqrt{36}=6 \end{gathered}[/tex]Then we can find x because
[tex]\begin{gathered} x^2=y^2+12^2 \\ \\ x^2=6^2+12^2 \\ \\ x^2=36+144 \\ \\ x^2=180 \\ \\ x=\sqrt{180} \\ \\ x=6\sqrt{5} \end{gathered}[/tex]The length of x is
[tex]x=6\sqrt{5}[/tex]Given a function described by the table below, what is y when x is 5?XY264859612
Answers
Given a function described by the table
We will find the value of (y) when x = 5
As shown in the table
When x = 5, y = 9
so, the answer will be y = 9
Find 8 3/4 ÷ 1 2/7. Write the answer in simplest form.
Answers
Problem: Find 8 3/4 ÷ 1 2/7. Write the answer in the simplest form.
Solution:
[tex](8+\frac{3}{4}\text{ )}\div(1\text{ + }\frac{2}{3})[/tex]this is equivalent to:
[tex](\frac{32+3}{4}\text{ )}\div(\text{ }\frac{3+2}{3})\text{ = }(\frac{35}{4}\text{ )}\div(\text{ }\frac{5}{3})\text{ }[/tex]Now, we do cross multiplication:
[tex]=(\frac{35}{4}\text{ )}\div(\text{ }\frac{5}{3})=\frac{35\text{ x 3}}{5\text{ x 4}}\text{ =}\frac{105}{20}[/tex]then, the correct answer would be:
[tex]=\frac{105}{20}[/tex]May I please get help with this I have tried multiple times to get the correct answer but still could not get them right. I am confused on how I should draw the dilation as I have tried many times as well.
Answers
After performing dilation centered at the origin we get
(a) shortest side of original figure=2 units
shortest side of the final figure=6units
(b) shortest side of the final figure=3×shortest side of the original figure
(c) True
(d) False
What is the dilation of the figure centered at origin?A transformation called a dilatation alters a figure's size without altering its shape. A figure might become larger or smaller due to dilation. For instance.
The image is smaller than the preimage when the scaling factor is between 0 and 1. Reductions are referred to as dilations with scale factors between 0 and 1.
The image is larger than the preimage if the scaling factor is greater than 1. Enlargements are defined as a dilation with a scale factor greater than 1.
To get the size of the edge we multiply the size of original lenght by scale factor.
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