Answer:
a) a= 19 m/s2, b ) F = F = 38 N
c) the correct one is B
Explanation:
1) To solve this exercise, let's use the concept of torque, let's start by looking for the mass of the mass of the head, which is 65 of 65 kg
m= 0.06 65 = 3.9 kg
torque is defined
τ = F x R
the bold indicate vectors
τ = F R sin θ
the force is the weight of the head and the distance R = 0.20 m
τ = mg R sin θ
τ = 3.9 9.8 0.2 sin 50
τ = 5.86 N m
Newton's second law expression for rotational motion is
τ = I α
In general, the head is approximated by a sphere, so the moment of foolishness with respect to the base of the neck (turning point) using the parallel axis theorem is
I = I_sphere + m d²
Neck height data is not indicated, so we will assume that it is zero (d = 0)
I = 2/5 m R²
angular and linear acceleration are related
a = α R
α = a / R
let's replace
τ = 2/5 mR² (a / R)
a = 5/2 τ / mR
let's calculate
a = 5/2 5.86 / (3.9 0.2)
a = 18.8 m / s²
a= 19 m/s²
2) as the neck and the head are related, the forces are action and reaction, therefore the neck force is
F = m g
F = 3.9 9.8 = 38.2 N
F = 38 N
3) He asks us about the efficiency of the headrest, after reviewing the different alternatives, the correct one is B
Yes. A headrest ensures that both the head and the body experience the same forward force at approximately the same time.
What is the main difference between the atoms in a solid versus atoms in a 1 point
liquid?
Answer:
Atoms in a solid are close and tightly packed.They vibrate about fixed positions .They are arranged in a regular LATTICE.They cannot be compressed nor can they change shape.They have strong forces of attraction between them so they cannot move in order to move they have to gain ENERGY. Whereas the atoms in a liquid are not that close compared to the ones in solid.They take the shape of the container but their volume remains fixed.They have weak forces of attraction between atoms and have more energy which enables them to move.
Explanation:
8. In explosives, potential energy is generally
stored in the form of
a thermal energy
b. electromagnetic energy
c. nuclear energy
d. chemical energy
Answer:
In explosives,potential energy is in the stored form of chemical energy.
8. Using Newton's second law, solve the following problems using
GFFS.
a. A force of 35N is applied to a 25kg object, what is its
acceleration??
b. What force is required to accelerate a 14kg object at 4.5
m/s2?
c. Calculate the mass of an object that accelerated at a rate of
2.7 m/s2 by a force of 18N.
Answer:
a) 1.4 m/s2
b) 63N
c) 6.66kg
Which describes the motion of the box based on the resulting free-body diagram?
1. It is moving up with a net force of 20 N.
2. It is moving to the right with a net force of 10 N.
3. It is in dynamic equilibrium with a net force of 0 N.
4. It is in static equilibrium with a net force of 0 N.
Answer:
D. (static equilibrium)
Explanation:
I just took the test and made a 100 with that answer.
Answer:
4. It is in static equilibrium with a net force of 0 N.
Explanation:
Just got it right :)
According to the kinetic theory, what happens when the temperature of water
increases?
The water molecules increase their speed.
The water molecules do not change speed.
The water molecules decrease their speed.
Question 7
(01.01 MC)
What is the difference between a hypothesis and a theory?
the state of matter that has low thermal expansion
Answer:
Matter
Explanation:
Because it is solid
Answer:
Solid
Solid < Liquid < Gas
A force of 1000N is applied to push
a mass of 500kg. How quickly does
it accelerate?
Answer:
Explanation: use f= ma
we get 1000 ÷ 500 = a
∴ a = 2 m/s²
When a mass of 500 Kg with the force 1000N, the acceleration produced is equal to 2m/s².
What is Newton's second law of motion?According to Newton’s second law of motion, the force equals the mass of the object times acceleration when the object has constant mass.
This law states that acceleration depends on two variables. The first variable is the mass and the net force acting on the body. The acceleration is directly proportional to the net force acting and inversely proportional to the mass.
Newton’s second law can be represented in the equation as follows:
[tex]F= ma[/tex]
or, [tex]a =\frac{F}{m}[/tex]
Acceleration or gaining speed happens when a force acts on an object.
Given the mass of the object, m= 500 Kg
The force applied on the object, F = 1000N
The acceleration produced in the mass, a = F/m = 1000/500 = 2m/s².
Therefore, the mass accelerates at a rate of 2m/s².
Learn more about Newton's second law of motion, here:
brainly.com/question/13447525
#SPJ2
15)
The Celsius temperature equal to 86° Fahrenheit is:
T(F) = 9/5T(C) + 32
T(C) = 5/9 ( T(F) - 32)
A)
16°C
B)
30°C
C)
212°C
D)
190°C
Answer:
letter b
Explanation:
30 degrees Celsius equals 86 degrees Fahrenheit add me plesse mark brainiest
PLEASE PLEASE HELP PICTURE INCLUDED
Answer:
a is the answer
Explanation:
when electric and _______ fields both exist, it is called an electromagentic
Answer:
the answer is magnetic
A baseball's resultant velocity is 25.79 m/s, at 68.64° from the level ground.
Determine the vertical component of the baseball's velocity.
Answer:
Vy = 24.01 [m/s]
Explanation:
To solve this problem we must understand that velocity is a vector and therefore has magnitude and direction, in this way we can decompose the velocity in the components x & y, by means of the trigonometric functions of the sine and cosine of the angle.
For the vertical component, the sine of the angle is used.
Vy = 25.79*sin(68.64)
Vy = 24.01 [m/s]
What is the final velocity of a running back that is moving with an initial velocity of 2 m/s and accelerates at a rate of 4 m/s$$ in 5 seconds as he moves toward the defensive line?
Answer:
Final velocity = 22
Explanation:
22-2/5= 4
20/5=4
so add to so it is not 18/5
Then you get your answer.
Answer:
4. A sound wave moves towards a building at 5 m/s for 22 seconds.
Explanation:
what is it called when I sound waves slowed buy a new medium
1.echo
2.transmission
3.absorption
4.reflection
Answer:
3
Explanation:
A series RLC circuit contains a 1,000 resistor, a 240 mH inductor, and a 0.04 uF capacitor. What is the circuit's resonant frequency?
A. 12,684 Hz
B. 48,194 Hz
C.51,393 Hz
D. 16.244 Hz
Which pair of factors affects the force of gravity between objects?
direction and distance
mass and distance
mass and shape
shape and time
Answer:
mass and distance
Explanation:
dont need to summary this
Answer:
B. mass and distance
Explanation:
A trebuchet launches a pumpkin at an angle of 27 degrees at an initial velocity of 32 m/ s from the ground. What is the apogee of the pumpkin?
Answer:
10.77 m
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 32 m/s
Angle of projection (θ) = 27°
Acceleration due to gravity (g) = 9.8 m/s²
Apogee i.e maximum height (H) =?
Thus, the apogee i.e the maximum height of the pumpkin can be obtained as follow:
H = u² Sine² θ /2g
H = 32² × (Sine 27)² / 2 × 9.8
H = 1024 × (0.454)² / 19.6
H = (1024 × 0.206116) / 19.6
H = 10.77 m
Thus, the apogee i.e the maximum height of the pumpkin is 10.77 m.
Question 4 of 10
A 6.2 kg bowling ball that weighs 60.76 N is accelerating at 1.8 m/s2. After 2
seconds, it reaches a speed of 3.6 m/s. What is its momentum at this point?
A. 11.2 kg-m/s
B. 1.7 kg.m/s
C. 22.3 kg-m/s
D. 16.9 kg.m/s
Answer:
22.3 kg•m/s
Explanation:
Apex;)
the graph below represents the relationship between velocity and time for an object moving along a straight line.
What is the magnitude of the object's acceleration?
1. 5.0 m/s^2
2. 8.0 m/s^2
3. 10. m/s^2
4. 20. m/s^2
Answer:
10. m/s^2
Explanation:
40-(-10)= 50
50/5 =10
This question can simply be answered by using the slope of the velocity-time graph.
The correct answer for the magnitude of the acceleration is "3. 10 m/s²".
Since the graph between the velocity and the time is in the form of a straight line. Hence, the acceleration can be calculated as the slope of this line. We will use the first and last point of the line to calculate the slope (acceleration):
[tex]Acceleration = Slope = \frac{v_2 - v_1}{t_2-t_1}[/tex]
where,
v₁ = initial velocity from the graph = - 10 m/s
v₂ = final velocity from the graph = 40 m/s
t₁ = initial time from the graph = 0 s
t₂ = final time from the graph = 5 s
Therefore,
[tex]Acceleration = \frac{40\ m/s\ -\ (-\ 10\ m/s)}{5\ s\ -\ 0\ s}[/tex]
Acceleration = 10 m/s²
The attached picture shows the types of a velocity-time graph.
Learn more about the velocity-time graph here:
https://brainly.com/question/11290682?referrer=searchResults
What is the final velocity if you have an initial velocity of 4 m/s with an acceleration of 2 m/s2 over 5 second interval interval
Answer:
14m/s
Explanation:
a horse was at rest.what was the final velocity of the horse if it covered 200 meters in 16 seconds?
Answer:
12.5m/s
Explanation:
Simplify the proportion.
200/16 = 100/8 = 50/4 = 25/2 = 12.5
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Answer:
mel mel 4 ever
Explanation:
What is the acceleration along the ground of a 18 kg wagon when it is pulled with a force of 91 N at an angle of 35° Above the horizontal?
Answer:
4.1 m/s²
Explanation:
Net force in the x direction equals the mass times the acceleration.
∑F = ma
91 cos 35° = (18 kg) a
a = 4.1 m/s²
Answer:
Explanation:
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Jack is buying a subscription to a magazine club. The function c=45+3.75m
c
=
45
+
3
.
75
m
describes the cost of the yearly subscription, c
c
, in terms of the number of magazines, m
m
, he orders.
What is the appropriate domain for the function?
the set of integers
the set of whole numbers
the set of all real numbers
the set of rational numbers
Answer:
the set of all real numbers
Explanation:
Given the cost of the magazine expressed as:
c=45+3.75m where:
c describes the cost of the yearly subscription.
m is the amount of order.
You must understand that domain are the values of the input variable m that will make the function exist.
The value of m that will produce a positive output since we can only have a positive value of the cost. According to the option, we can say that the domain is on the set of all real numbers (some are negative but all positive real numbers)
What is called mass per unit
volume of a substances? | ककसी पदाथष के
द्रव्यमान प्रतत इकाई आयतन को क्या कहते हैं?
A : Mass | द्रव्यमान
B : Weight | भार
C : Density | घनत्व
D : Volume | आयतन
Ans:
C : Density | घनत्व
Answer:
Density
Explanation:
The definition of density of a substance is the quotient between its mass and its volume. Such results in the mass per unit of volume.
A body is pulling a load of 50N with a string inclined at an angle of 30 degrees to the horizontal.
If the tension is 108N, calculate the force tending to lift the load off the ground.
Answer:
answer: 105 sin 30 = 52.5
Which function has a graph that intersects the y-axis at the point (0-4)?
Plz help por favor
Answer:
I believe B. The picture is not completely clear
Explanation:
A large mining dump truck has a mass of 40,000 kg. If its engine produces
20,000N of force, how fast will the truck accelerate?
Answer:
0.5 m/s²
Explanation:
Net force = mass × acceleration
∑F = ma
20,000 N = (40,000 kg) a
a = 0.5 m/s²
Answer:
which one will not start moving faster
Explanation:
Mass is also described by physics. If you apply the same amount of force to a small sports car and to a big garbage truck.
The student toses a ball into the air and then watches the ball fall back down to earth. When does the ball have the most potential energy
Answer:
when the ball is at its highest in the air.
Explanation:
I don't know for sure, but when the ball is in the air it has potential energy to fall(or something like that).
If the maximum linear velocity her center of mass reaches is 2.3 m/s, what is her maximum angular velocity
Like linear velocity, angular velocity is the relationship between the variation of angular space at a given time.
It was agreed that the trajectory of the movement is clockwise. Thus, the movement that follows this orientation will be positive and the opposite, negative.
For the formula relating the linear velocity, it is necessary to take into consideration the following formula
[tex]v = \omega \times R[/tex]
For example, for a R = 0.738 m
[tex]2.3 m/s = \omega \times R \therefore\\ R = 0.738m \therefore\\\omega = 3.12 \frac{rad}{s}[/tex]