Answer:
In America on the west coast
Step-by-step explanation:
me pueden ayudar es urgente!!!!
es de monomios
Answer:
Step-by-step explanation:
4.2) 2z² - 3z² = -z²
8x - x = 7x
4.3) 3x² - 4x² = (3 -4)x² = -x²
4z² - 3z² = (4- 3)z² = z²
z² - 2z² = (1 - 2)z² = -z²
3x - x = 2x
Cannot be subtracted.
3y² - 3y² = 0
4.3) 2xy - x y = xy
x²y² - 4x²y² = -3x²y²
x - y = /
2x²y² - 6x²y² = -4x²y²
4xy - 2xy = 2xy
4.4) 5xy - xy = 4xy
x²y² - 3x²y² = -2x²y²
3x³y - 2yx³ = x³y
help pls . .. a a z z z z . zz
Answer:
the lines are perpendicular
Which must be present in order for factoring by grouping to apply? - The ratios of the first two terms and the second two terms must be positive. - The ratio of the first two terms must be equivalent to the ratio of the last two terms. - There must be at least three terms. - The first and the last terms must be perfect squares.
Answer:
For factoring by grouping to apply, the ratio of the first two terms must be equal to the ratio of the last two terms
Step-by-step explanation:
Here, we want to select which of the options must be present in order for factoring by grouping to apply.
The correct answer is that the ratio of the first two terms must be equivalent to the ratio of the last two terms
What this mean is that we must have an equal ratio two times
This practically plays out each time we are to factorize quadratic expressions
For example, in the case of
x^2 -12x + 20
This can be written as;
x^2 - 10x - 2x + 20
which can then be written as x(x-10) -2(x -10)
= (x-2)(x-10)
The first two terms have a ratio of ;
x^2/-10x while the last two terms have a ratio -2x/20
Thus, we have -x/10 and -x/10
We can see here that the ratios of both sets are equivalent
Answer:
The ratio of the first two terms must be equivalent to the ratio of the last two terms
WILL GIVE BRAINLST FOR WHOEVER ANSWERS FIRST Which of the following equations is equivalent to 6(3p – 2) = 20?
Group of answer choices
9p – 4 = 20
9p – 8 = 20
18p – 12 = 20
18p – 2 = 20
Approximate the value of the positive square root of 110 to the nearest hundredth
Para recortar algumas figuras geométricas, um aluno utilizou uma cartolina com 1mx0,8m. Sabendo que ele recortou 2 triângulos, ambos com 20cm de base e 30 cm de altura, 2 trapézios ambos com bases de 10cm e 20cm e altura de 7cm. Determine em cm² quanto foi a área da cartolina que sobrou. * 1 ponto 7595cm² 0,7595m² 7190cm² 0.719m²
Answer:
7190 cm²
Step-by-step explanation:
Para recortar algumas figuras geométricas, um aluno utilizou uma cartolina de 1 m x 0,8m.
Passo 1
Determine a área de todo o papelão
= Temos dimensões = 1mx0,8m
Área = Comprimento × Largura
= 0,8m²
Nós convertemos para cm²
1 m² = 10.000 cm²
0,8m² = x cm²
Multiplicação cruzada
0,8m² × 10.000 cm² / 1 m²
= 8000 cm²
Passo 2
Sabendo que recortou 2 triângulos, ambos com 20cm de base e 30cm de altura
Encontramos a área de um triângulo
= 1/2 × base × altura
= 1/2 × 20 × 30
= 300cm²
Ele cortou 2 triângulos Portanto, o são dos dois triângulos = 300cm² × 2
= 600cm²
etapa 3
Ele também cortou 2 trapézios ambos com bases de 10cm e 20cm e altura de 7cm.
A área de um trapézio =
1/2 (a + b) h
= 1/2 (10cm + 20cm) × 7cm
= 1/2 × 30 × 7
= 105 cm²
Ele cortou dois trapézios, portanto
A área dos dois trapézios do corte = 105cm² × 2
= 210 cm²
Passo 4
A área total do papelão que foi cortado = 600cm² + 210cm²
= 810 cm²
Etapa 5
Determine em cm² quanto de papelão sobrou.
Isso é calculado como:
Área total do papelão - Área total que foi cortada
= 8000 cm² - 810 cm²
= 7190 cm²
Math I need help 8th grade
Answer:
Part A x=60
Step-by-step explanation:
68+52= 120
180-120=60
So x=60
It takes 140 minutes to finish a 40-question math test. How many minutes does it take, on average, to solve each math problem? * O 2 1/2 minutes 4 1/4 minutes O 3/4 minutes O 32 minutes
Answer:
Step-by-step explanation:
Average = Questions / Time
Average = 140 / 40 = 14/4 = 7/2 = 3 1/2 = 3.5
None of the answers are the same as mine. I'm pretty sure min is correct. Ask your instructor what you should answer.
Marge's plan costs .14 cents per minute plus a monthly fee of $24. Dan's plan costs .12 cents per minute plus a monthly fee of $28. How many minutes (m) are required for both plans to cost the same for the month?
Answer:
6 min for Marge's and 7 for Dan's plan
Step-by-step explanation:
0.14x6=0.84
0.12x7=0.84
GIVING BRAINLIEST!!! A student observes a beaker of room temperature water resting on a table. She states that the beaker of water does not have any energy. Which statement below is accurate regarding her observation?
a. She is correct because the beaker of water is not moving.
b. She is incorrect because the beaker of water has thermal energy.
c. She is incorrect because all water contains hydrogen and oxygen.
d. She is correct because the beaker of water is at room temperature.
Answer:
b
Step-by-step explanation:
12. The table shows the height in feet of a stack of medium sized moving boxes. What is the height of a stack of 14 boxes
height = 2.25 * box.
So, 14 boxes = 2.25 * 14 = 31.5.
Write the proportional equation that represents the table below.
What is faster? 15 meters per minute or 15 kilometers per hour?
Answer:
15 kilometers
Step-by-step explanation:
15 kilometers is in conversion with miles
The number of free spng to download is determined by usomg a ratio. When you purchase 40 songs, you get 24 free song download. How many songs must you purchase in order to get 6 free song downloads?
Answer:
10
Step-by-step explanation:
set up a proportion, 40/24 and x/6, 6 times 40 = 240, divide by 24 to get 10
A school has $15,000 to spend on computer monitors. The school plans to purchase 200 monitors for $89 each. A teacher completes the calculations below and concludes that the school has enough money to buy the monitors. 200 × 89 = (200 × 8) + (200 × 9) = 1,600 + 1,800 = 3,400
Answer:
Since the budget of the school is $15,000, the school does not have enough money to buy the monitors
Step-by-step explanation:
The school plans to purchase 200 monitors for $89 each.
This is the calculation of the teacher
200 × 89 = (200 × 8) + (200 × 9) = 1,600 + 1,800 = 3,400
The teacher's calculation is wrong
The correct calculation using Distributive property is
a(b + c) = ab + ac
200 × 89 = 200(80) + 200(9)
Because 80 + 9 = 89
Hence,
200 × $89 = 16000 + 1800
= $17,800
Since the budget of the school is $15,000, the school does not have enough money to buy the monitors
$17, 800 ≠ $15,000
Guys pls answer this for me in a minute it is really hard
help me!!!!!!! I need help
Answer:
the answer is 8
Step-by-step explanation:
BC
Answer:
8
Step-by-step explanation:
18-inches is 1.5 feet.
Kristy rides 6 miles on her bicycle in 40 minutes. Jax rides 4 miles on his bicycle in 30 minutes. Who is faster? Remember to support your answer with a mathematical statement!
Answer: Kristy
Step-by-step explanation: 6x=40 4x=30, 40/6 is 6.6 repeating which means she travels a mile in 6.6 minutes and 30/4 is 7.5. 6.6 repeating is lower than 7.5 which means it is faster.
solve for x
-30=5(x+1)
Answer:
-7
Step-by-step explanation:
im failing pls help !!!!!
Answer:
ill suck ya wang
Step-by-step explanation:5$ and ill suck yo wang to do your homework
Answer:
It is C.
Step-by-step explanation:
If you multiply 2 times 2 you get 4. Then multiply 4 by 5 and you get 20.
Therefore, it is C.
For an avian research study, scientists wanted to estimate the local robin population. The scientists captured, tagged, and released 55 robins. A week later, they noted 30 tagged robins out of the 300 robins they counted. To the nearest whole number, what is the best estimate for the robin population?
Answer: The estimated number of robins in the population is 550
Step-by-step explanation: To estimate the population of robins, we will use the Mark-Recapture technique:
1) Capture a small number of individuals, mark them (with tags or other harmless identification) and release them;
2) After a period of time, catch another group and count the ones who have the mark;
3) Estimate the population using:
[tex]N=\frac{M*C}{R}[/tex]
where
N is the estimate of individuals in the population
M number of individuals marked
C is the total number of individuals captured the second time
R is the number of individuals with the mark recaptured
For the population of robins:
[tex]N=\frac{55*300}{30}[/tex]
[tex]N=\frac{16500}{30}[/tex]
N = 550
The best estimate for the robin population is 550.
a.What is the length of A’A?
b.What is the length of B’B
Both in units
Answer:
A'A = 18 units, B'B = 9 units
Step-by-step explanation:
Δ ACB and Δ A'CB' are similar triangles, thus the ratios of corresponding sides are equal, that is
[tex]\frac{AC}{A'C}[/tex] = [tex]\frac{AB}{A'B'}[/tex] , substitute values
[tex]\frac{AC}{12}[/tex] = [tex]\frac{20}{8}[/tex] ( cross- multiply )
8AC = 240 ( divide both sides by 8 )
AC = 30
Thus A'A = AC - A'C = 30 - 12 = 18 units
--------------------------------------------------------------------
and
[tex]\frac{CB}{CB'}[/tex] = [tex]\frac{AB}{A'B'}[/tex] , that is
[tex]\frac{CB}{6}[/tex] = [tex]\frac{20}{8}[/tex] ( cross- multiply )
8CB = 120 ( divide both sides by 8 )
CB = 15
Thus
B'B = CB - CB' = 15 - 6 = 9 units
A one year membership at the club costs $10. You pay an additional $1.25 each day you go.
Last year you spent a total of $45. How many days did you go?
Answer:36
Step-by-step explanation:
Miguel completed the division problem below. What is Miguel's error? A.He included a 5 in the quotient, which does not belong. B.He multiplied the divisor by 10 and the dividend by 100. C.He subtracted 208 from 234 incorrectly. D.He multiplied the divisor by 100 and the dividend by 10. 754 divided by 0.52. 52 StartLongDivisionSymbol 7540 EndLongDivisionSymbol minus 52 = 234. 234 minus 208 = 260. 260 minus 260 = a remainder of 0 and a quotient of 145.
Answer:
D. He multiplied the divisor by 100 and the dividend by 10.
Step-by-step explanation:
From the question: The following steps are given:
754 divided by 0.52.
754 = Dividend
0.52 = Divisor
Step 1
7540 ÷ 52
This is where he made his error,
He multiplied the divisor by 100 and the dividend by 10.
The correct step would be
To Multiply both the Divisor and the Dividend by 100
= 75400 ÷ 52
Option D is the correct option
Answer:
The answer is D
Step-by-step explanation:
Hope this helped! :)
The lengths of the sides of a quadrilateral are 4 consecutive even integers.
The perimeter of the quadrilateral is 20 inches.
What is the length of the longest side?
Answer: 8 inches
Step-by-step explanation:
A quadrilateral is a shape with four sides. Since the lengths of the sides of the quadrilateral are 4 consecutive even integers, let them be represented by a, a+2, a+4 and a+6.
We then equate the side to the perimeter. This will be:
a + a+2 + a+4 + a+6 = 20
4a + 12 = 20
4a = 20 - 12
4a = 8
a = 8/4
a = 2 inches
The length of the longest side will be:
= a + 6
= 2 + 6
= 8 inches
What is 13 / 143 as a unit fraction
Answer:1/11
Just got it using some brain cells >:)
Answer:
1/11
Step-by-step explanation:
13/143=1/11
A half of a number added to 7 gives 19. What is the number? *
Answer:
24
Step-by-step explanation:
---------------
24÷2=12
12+7=19
---------------
need these 3 problems answered
1.(2x-3)^2+24=0
2.(3x+1)^2-49=0
3.3x^2-12x=-45
Answer:
ummm ................
Write the equation
“the quotient of a number and 2, increased by 9 is -15”
Use n as a variable and do not put any spaces
Answer:
[tex]\frac{n}{2}+9=-15[/tex]
I hope this helps!
The concentrates were pooled from the blood of about 1000 donors per lot. If the prevalence of HIV in donor blood in the early 1980s was 1 in 3,000, what was the probability that a hemophiliac would contract HIV from a single infusion of clotting factors?
Answer:
The required probability is "0.0003".
Step-by-step explanation:
Throughout the early 1980s, reconstructed coagulation factors concentrate extracted from individual blood was collected by hemophiliacs. The concentrate was obtained from either the blood of approximately 1000 donors every lot. The occurrence of hepatitis C throughout donated blood reached 1 in 3000 throughout the early 1980s.Therefore, the risk though from a single injection of clotting factors, a hemophiliac would contracted hepatitis C seems to be:
= [tex]\frac{1}{3000}[/tex]
= [tex]0.0003[/tex]